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# Loops/Continue

Loops/Continue
You are encouraged to solve this task according to the task description, using any language you may know.

Show the following output using one loop.

```1, 2, 3, 4, 5
6, 7, 8, 9, 10
```

Try to achieve the result by forcing the next iteration within the loop upon a specific condition, if your language allows it.

## 11l

Translation of: Python
`L(i) 1..10   I i % 5 == 0      print(i)      L.continue   print(i, end' ‘, ’)`
Output:
```1, 2, 3, 4, 5
6, 7, 8, 9, 10
```

## 360 Assembly

`*        Loops/Continue            12/08/2015LOOPCONT CSECT         USING  LOOPCONT,R12         LR     R12,R15BEGIN    LA     R8,0         SR     R5,R5         LA     R6,1         LA     R7,10LOOPI    BXH    R5,R6,ELOOPI       for i=1 to 10         LA     R3,MVC(R8)         XDECO  R5,XDEC         MVC    0(4,R3),XDEC+8         LA     R8,4(R8)         LR     R10,R5         LA     R1,5         SRDA   R10,32         DR     R10,R1         LTR    R10,R10         BNZ    COMMA         XPRNT  MVC,80         LA     R8,0         B      NEXTICOMMA    LA     R3,MVC(R8)         MVC    0(2,R3),=C', '         LA     R8,2(R8)NEXTI    B      LOOPI              next iELOOPI   XR     R15,R15         BR     R14MVC      DC     CL80' 'XDEC     DS     CL16         YREGS           END    LOOPCONT`
Output:
```   1,    2,    3,    4,    5
6,    7,    8,    9,   10```

Ada doesn't have a continue statement, so we have to use a goto statement. The previous submitter said continue is not needed. In this example it is indeed not needed, but that is not always the case. An example is a loop where a number of interdependent conditions are checked before executing the main body of the loop. Without a continue statement (or goto), one ends up with nested statements with the main body to the far right of the page.

B.N. You should always try to avoid using a goto, but if you really must, it's there in Ada.

P.S. it is often simplest to place the label on top of the loop, as in real life the need occurs when reading input, so there is no range condition in the loop and we can forgo the null statement.

`with Ada.Text_IO;use Ada.Text_IO; procedure Loop_Continue isbegin        for I in 1..10 loop                Put (Integer'Image(I));                if I = 5 or I = 10 then                        New_Line;                        goto Continue;                end if;                Put (",");                <<Continue>>  --Ada 2012 no longer requires a statement after the label        end loop;end Loop_Continue;`

N. This is a more true-to-Ada strategy for 'continue' comprising of an outer iteration loop and an inner labeled single-pass loop. This is a safer strategy than using goto which could be problematic when dealing with complex nested loops.

`with Ada.Text_IO;use Ada.Text_IO; procedure Loop_Continue isbegin        Print_All:        for I in 1 .. 10 loop                Print_Element: loop                        Put (Integer'Image(I));                        if I = 5 or I = 10 then                                New_Line;                                exit Print_Element;                        end if;                        Put (",");                exit Print_Element;                end loop Print_Element;        end loop Print_All;end Loop_Continue;`

## Agena

Agena doesn't have a continue statement, conditional statements can be used instead.

`for i to 10 do    write( i );    if i % 5 = 0    then write( "\n" )    else write( ", " )    fiod`

## Aikido

`foreach i 1..10 {    print (i)    if ((i % 5) == 0) {        println()        continue    }     print (", ")}`

## ALGOL 60

``` begin
integer i;
for i:=1 step 1 until 10 do begin
outinteger(i);
if i=(i div 5)*5 then
outimage
else
outstring(", ")
end
end
```
Output:
```         +1  ,          +2  ,          +3  ,          +4  ,          +5
+6  ,          +7  ,          +8  ,          +9  ,         +10
```

## ALGOL 68

Works with: ALGOL 68 version Revision 1 - no extensions to language used
Works with: ALGOL 68G version Any - tested with release 1.18.0-9h.tiny
Works with: ELLA ALGOL 68 version Any (with appropriate job cards) - tested with release 1.8-8d

ALGOL 68 has no continue reserved word, nor does it need one. The continue reserved word is only syntactic sugar for operations that can be achieved without it as in the following example:

`FOR i FROM 1 TO 10 DO  print ((i,     IF i MOD 5 = 0 THEN      new line    ELSE      ","    FI  ))OD`
Output:
```         +1,         +2,         +3,         +4,         +5
+6,         +7,         +8,         +9,        +10
```

## ALGOL W

Algol W doesn't have a continue statement - conditional statements can be used instead.

`begin    i_w := 1; s_w := 0; % set output format %    for i := 1 until 10 do begin        writeon( i );        if i rem 5 = 0        then write()        else writeon( ", " )    end for_iend.`

## AppleScript

` set table to {return}repeat with i from 1 to 10	if i < 5 or (i ≥ 6 and i < 10) then		set end of table to i & ", "	else if i = 5 or i = 10 then		set end of table to i & return	end ifend repeatreturn table as string `
Output:
```"
1, 2, 3, 4, 5
6, 7, 8, 9, 10
"
```

## Arturo

`loop 1..10 'i [    prints i    if 0 = i%5 [        print ""        continue    ]    prints ", "]`
Output:
```1, 2, 3, 4, 5
6, 7, 8, 9, 10```

## AutoHotkey

`Loop, 10 {  Delimiter := (A_Index = 5) || (A_Index = 10) ? "`n":", "  Index .= A_Index . Delimiter}MsgBox %Index%`

## AWK

`BEGIN {  for(i=1; i <= 10; i++) {    printf("%d", i)    if ( i % 5 == 0 ) {      print      continue    }    printf(", ")  }}`

## BASIC

### Applesoft BASIC

` 10  FOR I = 1 TO 10 20  PRINT I; 30  IF I -  INT (I / 5) * 5 = 0 THEN  PRINT : GOTO 50"CONTINUE 40  PRINT ", "; 50  NEXT`

### BASIC256

`for i = 1 to 10	print string(i);	if i mod 5 = 0 then		print		continue for	end if	print ", ";nextprintend`

### BBC BASIC

BBC BASIC doesn't have a 'continue' statement so the remainder of the loop must be made conditional.

`      FOR i% = 1 TO 10        PRINT ; i% ;        IF i% MOD 5 = 0 PRINT ELSE PRINT ", ";      NEXT`

### Commodore BASIC

Commodore BASIC also doesn't have a 'continue' statement. In this example, a GOTO statement is used to simulate 'CONTINUE'. However, Commodore BASIC doesn't have a modulo (remainder) operator, so value of I/5 is check against INT(I/5). If they are the same, the remainder is zero.

`10 FOR I = 1 TO 1020 PRINT I;30 IF INT(I/5) = I/5 THEN PRINT : GOTO 5040 PRINT ", ";50 NEXT`

### FreeBASIC

`' FB 1.05.0 Win64For i As Integer = 1 To 10  Print Str(i);  If i Mod 5 = 0 Then    Print    Continue For  End If  Print ", ";Next PrintSleep`
Output:
```1, 2, 3, 4, 5
6, 7, 8, 9, 10
```

### IS-BASIC

`100 FOR I=1 TO 10110   PRINT STR\$(I);120   IF MOD(I,5)=0 THEN130     PRINT 140   ELSE150     PRINT ", ";160   END IF170 NEXT`

### Liberty BASIC

` for i =1 to 10    if i mod 5 <>0 then print i; ", "; else print inext iend `

### PureBasic

`OpenConsole() For i.i = 1 To 10  Print(Str(i))  If i % 5 = 0    PrintN("")    Continue  EndIf  Print(",")Next Repeat: Until Inkey() <> ""`

### QB64

`Dim i As IntegerFor i = 1 To 10    Print LTrim\$(Str\$(i));    If i Mod 5 = 0 Then        Print        _Continue    End If    Print ", ";Next`

### Run BASIC

Works with: QBasic
`for i = 1 to 10    if i mod 5 <> 0 then print i;", "; else print inext i`

### Sinclair ZX81 BASIC

This probably isn't the most idiomatic way to produce the specified output—but it does illustrate ZX81 BASIC's equivalent of `if <condition> continue`, which is `IF <condition> THEN NEXT <loop-control variable>`.

`10 FOR I=1 TO 1020 PRINT I;30 IF I/5=INT (I/5) THEN PRINT40 IF I/5=INT (I/5) THEN NEXT I50 PRINT ", ";60 NEXT I`

### TI-89 BASIC

`count()Prgm   ""→s  For i,1,10    s&string(i)→s    If mod(i,5)=0 Then      Disp s      ""→s      Cycle    EndIf    s&", "→s  EndForEndPrgm`

Ti-89 lacks support for multi-argument display command or controlling the print position so that one can print several data on the same line. The display command (Disp) only accepts one argument and prints it on a single line (causing a line a feed at the end, so that the next Disp command will print in the next line). The solution is appending data to a string (s), using the concatenator operator (&), by converting numbers to strings, and then printing the string at the end of the line.

### True BASIC

`FOR i = 1 TO 10    PRINT STR\$(i);    IF REMAINDER(i, 5) = 0 THEN       PRINT    ELSE                          !No existe el comando CONTINUE       PRINT ", ";    END IFNEXT iPRINTEND`

### VB-DOS, PDS

` OPTION EXPLICIT DIM i AS INTEGER CLSFOR i = 1 TO 10 PRINT STR\$(i); IF (i MOD 5) THEN PRINT ",";  ELSE PRINTNEXT iEND`

### Visual Basic .NET

`For i = 1 To 10    Console.Write(i)    If i Mod 5 = 0 Then        Console.WriteLine()    Else        Console.Write(", ")    End IfNext`

## bc

Requires a bc with the print and continue statements. POSIX bc has not these statements.

Works with: OpenBSD bc
`for (i = 1; i <= 10; i++) {	print i	if (i % 5) {		print ", "		continue	}	print "\n"}quit`

## Befunge

Befunge outputs numbers with a space after them, so the formatting is slightly off in this version.

` 1>:56+\`#[email protected] +v %5:.:< 1>#v_55+,v ^        <    >" ,",,v ^         < `

This version outputs a 'backspace' ASCII character to try to correct the format, but it may or may not work depending on if the character is accounted for by the output

` 1>:56+\`#[email protected] +v5:,8.:< 1>%#v_55+,v ^         <     >" ,",v ^        ,< `

## Bracmat

Bracmat has no continue statement.

`( 0:?i&   whl  ' ( 1+!i:~>10:?i    &   put      \$ ( str        \$ ( !i            (mod\$(!i.5):0&\n|", ")          )        )    ));`

## C

Translation of: C++
`for(int i = 1;i <= 10; i++){   printf("%d", i);   if(i % 5 == 0){      printf("\n");      continue;   }   printf(", ");}`

## C#

Translation of: Java
`using System; class Program {    static void Main(string[] args) {        for (int i = 1; i <= 10; i++) {            Console.Write(i);             if (i % 5 == 0) {                Console.WriteLine();                continue;            }             Console.Write(", ");        }    }}`

## C++

Translation of: Java
`for(int i = 1;i <= 10; i++){   cout << i;   if(i % 5 == 0){      cout << endl;      continue;   }   cout << ", ";}`

## Chapel

`for i in 1..10 {        write(i);        if i % 5 == 0 then {                writeln();                continue;        }        write(", ");}`

## Clipper

LOOP keyword is used here instead of continue.

Works as is with Harbour 3.0.0 (Rev. 16951)

`FOR i := 1 TO 10   ?? i   IF i % 5 == 0      ?      LOOP   ENDIF   ?? ", "NEXT`

## Clojure

Clojure doesn't have a continue keyword. It has a recur keyword, although I prefer to work with ranges in this case.

`(doseq [n (range 1 11)]  (print n)  (if (zero? (rem n 5))      (println)      (print ", ")))`

`(loop [xs (range 1 11)]  (when-let [x (first xs)]    (print x)    (if (zero? (rem x 5))        (println)        (print ", "))    (recur (rest xs))))`

## COBOL

`       IDENTIFICATION DIVISION.       PROGRAM-ID. loop-continue.        DATA DIVISION.       WORKING-STORAGE SECTION.       01  i PIC 99.        PROCEDURE DIVISION.           PERFORM VARYING i FROM 1 BY 1 UNTIL 10 < i               DISPLAY i WITH NO ADVANCING                IF FUNCTION MOD(i, 5) = 0                   DISPLAY SPACE                   EXIT PERFORM CYCLE               END-IF                DISPLAY ", " WITH NO ADVANCING           END-PERFORM            GOBACK           .`

Note: COBOL does have a `CONTINUE` verb, but this is a no-operation statement used in `IF` and `EVALUATE` statements.

## ColdFusion

Remove the leading space from the line break tag.

`<cfscript>  for( i = 1; i <= 10; i++ )  {    writeOutput( i );    if( 0 == i % 5 )    {      writeOutput( "< br />" );      continue;    }    writeOutput( "," );  }</cfscript>`

## Common Lisp

Common Lisp doesn't have a continue keyword, but the `do` iteration construct does use an implicit `tagbody`, so it's easy to `go` to any label. Four solutions follow. The first pushes the conditional (whether to print a comma and a space or a newline) into the format string. The second uses the implicit `tagbody` and `go`. The third is a do loop with conditionals outside of the output functions.

`(do ((i 1 (1+ i)))    ((> i 10))  (format t "~a~:[, ~;~%~]" i (zerop (mod i 5)))) (do ((i 1 (1+ i)))    ((> i 10))  (write i)  (when (zerop (mod i 5))    (terpri)    (go end))  (write-string ", ")  end) (do ((i 1 (1+ i)))    ((> i 10))  (write i)  (if (zerop (mod i 5))    (terpri)    (write-string ", ")))`

These use the `loop` iteration form, which does not contain an implicit tagbody (though one could be explicitly included). The first uses an explicit condition to omit the rest of the loop; the second uses `block`/`return-from` to obtain the effect of skipping the rest of the code in the `block` which makes up the entire loop body.

`(loop for i from 1 to 10      do (write i)      if (zerop (mod i 5))        do (terpri)      else        do (write-string ", ")) (loop for i from 1 to 10 do  (block continue    (write i)    (when (zerop (mod i 5))      (terpri)      (return-from continue))    (write-string ", ")))`

## D

`import std.stdio; void main() {    foreach (i; 1 .. 11) {        write(i);        if (i % 5 == 0) {            writeln();            continue;        }        write(", ");    }}`
Output:
```1, 2, 3, 4, 5
6, 7, 8, 9, 10```

### Shorter version

` import std.stdio; void main(){  foreach(i; 1..11) i % 5 ? writef("%s, ", i) : writeln(i);} `

## dc

The four commands # n J M are special to OpenBSD dc. The # command starts a comment. The n command prints a number without a newline.

Translation of: bc
Works with: OpenBSD dc
`1 si		# i = 1[2Q]sA		# A = code to break loop[[, ]P 1J]sB	# B = code to print comma, continue loop[ li n		# print i li 5 % 0 !=B	# call B if i % 5 []P              # print newline M		# mark from calling B li 1 + si	# i += 1 li 10!<C	# continue loop if 10 >= i]sC li 10!<C	# enter loop if 10 >= i`

This program uses J and M to force the next iteration of a loop. The nJ command breaks n levels of brackets (like nQ does so), but then skips to the next M command. One can place M at the end of the iteration.

## Delphi

`program DoLoop(output);var  i: integer;begin  for i := 1 to 10 do  begin    write(i);    if i mod 5 = 0 then    begin      writeln;      continue;    end;    write(', ');  end;end.`
Output:
```1, 2, 3, 4, 5
6, 7, 8, 9, 10
```

## DWScript

`var i : Integer; for i := 1 to 10 do begin   Print(i);   if i mod 5 = 0 then begin      PrintLn('');      continue;   end;   Print(', ');end;`

## Dyalect

Translation of: Swift
`for i in 1..10 {    print(i, terminator: "")    if i % 5 == 0 {        print()        continue    }    print(", ", terminator: "")}`
Output:
```1, 2, 3, 4, 5
6, 7, 8, 9, 10```

## Ela

### Direct Approach

`open monad io loop n =   if n > 10 then do      return ()     else do      putStr (show n)      putStr f      loop (n + 1)  where f | n % 5 == 0 = "\r\n"          | else = ", " _ = loop 1 ::: IO`

### Using list

`open monad io loop [] = return ()loop (x::xs) = do      putStr (show x)      putStr f      loop xs  where f | x % 5 == 0 = "\r\n"          | else = ", " _ = loop [1..10] ::: IO`

This version is more generic and can work for any given range of values.

## Elixir

`defmodule Loops do  def continue do    Enum.each(1..10, fn i ->      IO.write i      IO.write if rem(i,5)==0, do: "\n", else: ", "    end)  endend Loops.continue`
Output:
```1, 2, 3, 4, 5
6, 7, 8, 9, 10
```

## Erlang

`%% Implemented by Arjun Sunel-module(continue).-export([main/0, for_loop/1]). main() ->	for_loop(1). for_loop(N)  when N /= 5 , N <10 ->	io:format("~p, ",[N] ),	for_loop(N+1); for_loop(N) when N >=10->	if N=:=10 ->		io:format("~p\n",[N] )	end; for_loop(N) ->	if N=:=5 ->		io:format("~p\n",[N] ),		for_loop(N+1)	end. `
Output:
```1, 2, 3, 4, 5
6, 7, 8, 9, 10
ok```

## ERRE

` FOR I=1 TO 10 DO   PRINT(I;CHR\$(29);)  ! printing a numeric value leaves a blank after it                       ! chr\$(29) delete it.....   IF I MOD 5=0 THEN      PRINT      CONTINUE FOR   END IF   PRINT(",";)END FORPRINT `

## Euphoria

Works with: Euphoria version 4.0.3, 4.0.0 or later
`include std\console.e --only for any_key to make running command window easier on windows for i = 1 to 10 do    if remainder(i,5) = 0 then        printf(1, "%d\n", i)        else            printf(1,"%d, ", i)            continue    end ifend forany_key()`

Version without newline after 10 below.

`include std\console.e --only for any_key to make running command window easier on windows for i = 1 to 10 do    if remainder(i,5) = 0 then        switch i do             case 10 then                printf(1,"%d ",i)                break --new to euphoria 4.0.0+            case else                printf(1,"%d\n", i)        end switch         else            printf(1,"%d, ", i)            continue --new to euphoria 4.0.0+    end ifend forany_key() `

## F#

`continue` is a reserved word, but it has no function. In any case, it is not needed to complete this task.

`for i in 1 .. 10 do  printf "%d" i  if i % 5 = 0 then    printf "\n"  else    printf ", "`

### Using Comma quibbling#The Function

` let fN g=quibble (Seq.initInfinite(fun n ->if (n+1)%5=0 || (n+1)=List.length g then "\n" else ", ")) g  fN [1] |> Seq.iter(fun(n,g)->printf "%d%s" n g)fN [1..9] |> Seq.iter(fun(n,g)->printf "%d%s" n g)fN [1..10] |> Seq.iter(fun(n,g)->printf "%d%s" n g)fN [1..11] |> Seq.iter(fun(n,g)->printf "%d%s" n g) `
Output:
```1
1, 2, 3, 4, 5
6, 7, 8, 9
1, 2, 3, 4, 5
6, 7, 8, 9, 10
1, 2, 3, 4, 5
6, 7, 8, 9, 10
11
```

## Factor

There is no built-in `continue` in Factor.

`1 10 [a,b] [     [ number>string write ]    [ 5 mod 0 = "\n" ", " ? write ] bi] each`

## Fantom

While and for loops support `continue` to jump back to begin the next iteration of the loop.

` class LoopsContinue{  public static Void main ()   {    for (Int i := 1; i <= 10; ++i)    {      Env.cur.out.print (i)      if (i % 5 == 0)       {        Env.cur.out.printLine ("")        continue      }      Env.cur.out.print (", ")    }    Env.cur.out.printLine ("")  }} `

## Forth

Although this code solves the task, there is no portable equivalent to "continue" for either DO-LOOPs or BEGIN loops.

`: main  11 1 do    i dup 1 r.    5 mod 0= if cr else [char] , emit space then  loop ;`

## Fortran

Works with: Fortran version 90 and later
`do i = 1, 10   write(*, '(I0)', advance='no') i   if ( mod(i, 5) == 0 ) then      write(*,*)      cycle   end if   write(*, '(A)', advance='no') ', 'end do`
Works with: Fortran version 77 and later
`C     WARNING: This program is not valid ANSI FORTRAN 77 code. It usesC     one nonstandard character on the line labelled 5001. Many F77C     compilers should be okay with it, but it is *not* standard.CC     It is also worth noting that FORTRAN 77 uses the command CONTINUE,C     but not in the semantic, looping sense of the word. In FORTRAN,C     CONTINUE means "do absolutely nothing." It is a placeholder. IfC     anything, it means "continue to the next line."CC     Python does the same thing with `pass`; C and its family ofC     languages, with `{/* do nothing */}`. Write CONTINUE when you needC     to write something but have nothing to write.CC     This page on Rosetta Code is about a very different "continue"C     statement that tells a loop to go back to the beginning. InC     FORTRAN, we use (you guessed it!) a GOTO to accomplish this.      PROGRAM CONTINUELOOP        INTEGER I         DO 10 I = 1, 10C         Is it five or ten?          IF (MOD(I, 5) .EQ. 0) THENC           If it is, write a newline and no comma.            WRITE (*,5000) I C           Continue the loop; that is, skip to the end of the loop.            GOTO 10          ENDIF C         Write I with a comma and no newline.          WRITE (*,5001) I C       Again, in this case, CONTINUE is completely unrelated to theC       semantic, looping sense of the word.   10   CONTINUE         STOP C       This will print an integer and a newline (no comma). 5000   FORMAT (I3) C       Standard FORTRAN 77 is completely incapable of completing aC       WRITE statement without printing a newline. If you want to printC       five integers in standard code, you have to do something likeC       this:CC           FORMAT (I3, ',', I3, ',', I3, ',', I3, ',', I3)CC       Writing `1, 2, 3, 4, 5` and then `6, 7, 8, 9, 10` to that formatC       would produce the following two lines:CC             1,  2,  3,  4,  5C             6,  7,  8,  9, 10CC       However, this code exists to demonstrate continuing a FORTRAN 77C       loop and not to demonstrate how to get around its rigidity aboutC       newlines.CC       The dollar sign at the end of the format is a nonstandardC       character. It tells the compiler not to print a newline. If youC       are actually using FORTRAN 77, you should figure out what yourC       particular compiler accepts. If you are actually using FortranC       90 or later, you should replace this line with the commentedC       line that follows it. 5001   FORMAT (I3, ',', \$)C5001   FORMAT (I3, ',', ADVANCE='NO')      END`

### Relying instead upon the looping features of FORMAT

For historical reasons, 6 is often the default unit number for standard output.

`       WRITE (6,1) (I,I = 1,10)    1 FORMAT (4(1X,I0,","),1X,I0)      END `

Here the break and continuation comes through the workings of the FORMAT interpreter. The feature 4(etc) means four repetitions of the format items within the brackets, and as each datum from the WRITE statement arrives, it is aligned with the next format item that can receive a datum, the I-format specifier (here I0, which means an integer of only as many digits as are needed for the value) and until such a reciever is encountered, intervening format items are acted upon - 1X means "one space", and the quotes surround a text literal. Accordingly, the first datum generates a space, a one-digit value, and a comma, as does the second and so on. When the sixth datum is received, the end of the format statement has been reached, and the convention is to write the current line and start a new line of output, and further, go back in the FORMAT specification to the first-encountered open-bracket symbol (the rightmost) which in this case is not the beginning of the FORMAT statement but the one that has a repetition count of four in front of it, and, resume interpretation. When the last datum has been accepted, naturally, the line is printed.

An alternative might be FORMAT (4(I2,","),I2) but that would generate

```1, 2, 3, 4, 5
6, 7, 8, 9,10
```

Alternatively, FORMAT (4(I2,","),I2,/,4(I2,","),I3) would do the trick but there would no longer be the loop, break, continue aspect to the interpretation of the FORMAT statement, merely a grinding through a list.

This sort of scheme facilitates a compact way of printing a table with a heading, where the WRITE statement simply pours forth the data and relies on something like FORMAT("heading",/,(complex details for one line)) - thus printing the table line-by-line with only the first line having the heading, a saving on having a write and format statement pair for the heading and a second pair for the table body.

## Gambas

`Public Sub Main()Dim siCount As Short For siCount = 1 To 10  Print siCount;  If siCount <> 5 And siCount <> 10 Then Print ",";  If siCount = 5 Then Print gb.NewLine;Next End`

Output:

```1,2,3,4,5
6,7,8,9,10
```

## GAP

`for i in [1 .. 11] do    if RemInt(i, 5) = 0 then        Print(i, "\n");        continue;    fi;    Print(i, ", ");od; # 1, 2, 3, 4, 5# 6, 7, 8, 9, 10`

## GML

`for(i = 1; i <= 10; i += 1)    {    show_message(string(i))    i += 1    if(i <= 10)        continue    }`

## Go

`package main import "fmt" func main() {    for i := 1; i <= 10; i++ {        fmt.Printf("%d", i)        if i%5 == 0 {            fmt.Printf("\n")            continue        }        fmt.Printf(", ")    }}`
Output:
```1, 2, 3, 4, 5
6, 7, 8, 9, 10
```

## Groovy

`for (i in 1..10) {    print i    if (i % 5 == 0) {        println ()        continue    }    print ', '}`

As a functional language, it is not idiomatic to have true loops - recursion is used instead. Below is one of many possible implementations of the task. The below code uses a guard (| symbol) to compose functions differently for the two alternative output paths, instead of using continue like in an imperative language.

`import Control.Monad (forM)main = forM [1..10] out    where      out x | x `mod` 5 == 0 = print x            | otherwise = (putStr . (++", ") . show) x`

## Haxe

`for (i in 1...11) {  Sys.print(i);  if (i % 5 == 0) {    Sys.print('\n');    continue;  }  Sys.print(', ');}`

## HicEst

`DO i = 1, 10  IF( MOD(i, 5) == 1 ) THEN      WRITE(Format="i3") i    ELSE      WRITE(APPend, Format=" ',', i3 ") i    ENDIFENDDO `

## Icon and Unicon

The following code demonstrates the use of 'next' (the reserved word for 'continue'):

`procedure main()every writes(x := 1 to 10) do {   if x % 5 = 0 then {      write()      next               }   writes(", ")   }end`

However, the output sequence can be written without 'next' and far more succinctly as:

`every writes(x := 1 to 10, if x % 5 = 0 then "\n" else ", ")`

## Io

`for(i,1,10,    write(i)    if(i%5 == 0, writeln() ; continue)    write(" ,"))`

## J

J is array-oriented, so there is very little need for loops. For example, one could satisfy this task this way:

`_2}."1'lq<, >'8!:2>:i.2 5`

J does support loops for those times they can't be avoided (just like many languages support gotos for those time they can't be avoided).

`3 : 0 ] 10         z=.''        for_i. 1 + i.y do.            z =. z , ": i              if. 0 = 5 | i do.                  z 1!:2 ]2                   z =. ''                  continue.              end.               z =. z , ', '        end.     i.0 0   )`

Though it's rare to see J code like this.

## Java

`for(int i = 1;i <= 10; i++){   System.out.print(i);   if(i % 5 == 0){      System.out.println();      continue;   }   System.out.print(", ");}`

## JavaScript

Using the `print()` function from Rhino or SpiderMonkey.

`var output = "";for (var i = 1; i <= 10; i++) {  output += i;   if (i % 5 == 0) {    print(output);    output = "";    continue;  }   output += ", ";}`

Stepping back from any assumption that repetitive patterns of computation necessarily entail 'loops', and using a functional idiom of JavaScript, we can make the value of one or more subexpressions in a reduce() fold conditional on any special cases that we define.

For example:

`function rng(n) {  return n ? rng(n - 1).concat(n) : [];} console.log(  rng(10).reduce(    function (a, x) {      return a + x.toString() + (x % 5 ? ', ' : '\n');    }, ''  ));`

Output:

`1, 2, 3, 4, 56, 7, 8, 9, 10 `

## jq

jq does not have a "continue" statement. In jq 1.4, the simplest way to accomplish the given task is probably as follows:

`reduce range(1;11) as \$i  (""; . + "\(\$i)" + (if \$i % 5 == 0 then "\n" else ", " end))`

## Jsish

`/* Loop/continue in jsish */for (var i = 1; i <= 10; i++) {    printf("%d", i);    if (i % 5 == 0) {        printf("\n");        continue;    }    printf(", ");}`
Output:
```prompt\$ jsish loop-continue.jsi
1, 2, 3, 4, 5
6, 7, 8, 9, 10```

## Julia

` for i in 1:10    print(i)    if i%5 == 0        println()        continue    end    print(", ")end `
Output:
```1, 2, 3, 4, 5
6, 7, 8, 9, 10
```

## Kotlin

`// version 1.1.2 fun main(args: Array<String>) {    for(i in 1 .. 10) {        if (i % 5 == 0) {            println(i)            continue        }        print("\$i, ")    }}`
Output:
```1, 2, 3, 4, 5
6, 7, 8, 9, 10
```

## Lambdatalk

` {def loops_continue {lambda {:i}  {if {> :i 10}   then (end of loop)   else {if {= :i 6} then {br}:i else :i}        {if {= :i 10} then . else ,}        {loops_continue {+ :i 1}}}}}-> loops_continue {loops_continue 0}-> 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10. (end of loop) `

## langur

Works with: langur version 0.8.1
`for .i of 10 {    write .i    if .i div 5 { writeln(); next }    write ", "}`

## Lasso

`loop(10) => {^	loop_count	loop_count % 5 ? ', ' | '\r'	loop_count < 100 ? loop_continue	'Hello, World!' // never gets executed^}`

## Lingo

`str = ""repeat with i = 1 to 10  put i after str  if i mod 5 = 0 then    put RETURN after str    next repeat  end if  put ", " after strend repeatput str`

## Lisaac

`1.to 10 do { i : INTEGER;  i.print;  (i % 5 = 0).if { '\n'.print; } else { ','.print; };};`

## LiveCode

`repeat with n = 1 to 10    put n     if n is 5 then put return    if n < 10 and n is not 5 then put "," end repeat`

## Lua

`for i = 1, 10 do    io.write( i )    if i % 5 == 0 then        io.write( "\n" )    else    	io.write( ", " )     endend`

or

`for i = 1, 10 do    io.write( i )    if i % 5 == 0 then        io.write( "\n" )        goto continue    end    io.write( ", " )     ::continue::end`

## M2000 Interpreter

` Module Checkit {      \\ A For {} loop      For i=1 to 10 {            Print i;            if i mod 5 Else Print : continue            Print ",";      }      Print i=11      \\ A For Next loop      For i=1 to 10            Print i;            if i mod 5 Else Print : continue            Print ",";      Next i      Print i=11      \\ A for loop using  a block and a Loop statement      i=0      {     i++            if i>10  then Exit            loop            Print i;            if i mod 5 Else Print : continue            Print ",";       }      Print i=11      \\ as above but end value for i=10 not 11      i=0      {     i++            if i<10  then loop            Print i;            if i mod 5 Else Print : continue            Print ",";       }      Print i=10  ' not 11 but 10}Checkit `

## Maple

`for i from 1 to 10 do        printf( "%d", i );        if irem( i, 5 ) = 0 then                printf( "\n" );                next        end if;        printf( ", " )end do:`

This can also be done as follows, but without the use of "next".

`for i to 10 do        printf( "%d%s", i, `if`( irem( i, 5 ) = 0, "\n", ", " ) )end do:`

## Mathematica/Wolfram Language

`tmp = "";For[i = 1, i <= 10, i++,  tmp = tmp <> ToString[i];  If[Mod[i, 5] == 0,   tmp = tmp <> "\n";   ,   tmp = tmp <> ", ";   ];  ];Print[tmp]`

## MATLAB / Octave

Loops are considered slow in Matlab and Octave, it is preferable to vectorize the code.

`disp([1:5; 6:10])`

or

`disp(reshape([1:10],5,2)')`

A non-vectorized version of the code is shown below in Octave

`for i = 1:10  printf(' %2d',  i);  if ( mod(i, 5) == 0 )     printf('\n');    continue  endend`

## Maxima

`/* There is no "continue" in Maxima, the easiest is using a "if" instead */block(   [s: ""],   for n thru 10 do (      s: sconcat(s, n),      if mod(n, 5) = 0 then (         ldisp(s),         s: ""      ) else (         s: sconcat(s, ", ")      )   ))\$`

## MAXScript

`for i in 1 to 10 do(    format "%" i    if mod i 5 == 0 then    (        format "\n"        continue    )   continue    format ", ")`

Insert non-formatted text here

## Metafont

Metafont has no a continue (or similar) keyword. As the Ada solution, we can complete the task just with conditional.

`string s; s := "";for i = 1 step 1 until 10:if i mod 5 = 0:  s := s & decimal i & char10;else:  s := s & decimal i & ", "fi; endformessage s;end`

Since message append always a newline at the end, we need to build a string and output it at the end, instead of writing the output step by step.

Note: mod is not a built in; like TeX, "bare Metafont" is rather primitive, and normally a set of basic macros is preloaded to make it more usable; in particular mod is defined as

`primarydef x mod y = (x-y*floor(x/y)) enddef;`

## Modula-3

Modula-3 defines the keyword RETURN as an exception, but when it is used with no arguments it works just like continue in C.

Note, however, that RETURN only works inside a procedure or a function procedure; use EXIT otherwise.

Module code and imports are omitted.

`FOR i := 1 TO 10 DO  IO.PutInt(i);  IF i MOD 5 = 0 THEN    IO.Put("\n");    RETURN;  END;  IO.Put(", ");END;`

## MOO

`s = "";for i in [1..10]  s += tostr(i);  if (i % 5 == 0)    player:tell(s);    s = "";    continue;  endif  s += ", ";endfor`

## Neko

`/** Loops/Continue in Neko Tectonics:   nekoc loops-continue.neko   neko loops-continue*/ var index = 0; while index < 10 {  index += 1;  \$print(index);  if \$not(\$istrue(index % 5)) {    \$print("\n");     continue;   }  \$print(", ");}`
Output:
```prompt\$ nekoc loops-continue.neko
prompt\$ neko loops-continue.n
1, 2, 3, 4, 5
6, 7, 8, 9, 10```

## Nemerle

Translation of: C#
`using System;using System.Console;using Nemerle.Imperative; module Continue{    Main() : void    {        foreach (i in [1 .. 10])        {            Write(i);            when (i % 5 == 0) {WriteLine(); continue;}            Write(", ");        }    }}`

## NetRexx

`/* NetRexx */options replace format comments java crossref savelog symbols nobinary   say  say 'Loops/Continue'   nul = '\-'  loop i_ = 1 to 10    say i_.right(2) || nul    if i_ // 5 = 0 then do      say      iterate i_      end    say ', ' || nul     end i_ `

## NewLISP

`(for (i 1 10)  (print i)  (if (= 0 (% i 5))      (println)    (print ", ")))`

## Nim

Translation of: Python
`for i in 1..10:  if i mod 5 == 0:    echo i    continue  stdout.write i, ", "`

## NS-HUBASIC

`10 FOR I=1 TO 1020 PRINT I;30 IF I-I/5*5=0 THEN PRINT :GOTO 50"CONTINUE40 PRINT ",";50 NEXT`

## Objeck

`class Continue {  function : Main(args : String[]) ~ Nil {    for(i := 1; i <= 10; i += 1;) {      if(i = 5) {        "{\$i}, "->PrintLine();        continue;      };      "{\$i}, "->Print();    };  }}`

## OCaml

There is no continue statement for for loops in OCaml, but it is possible to achieve the same effect with an exception.

`# for i = 1 to 10 do    try      print_int i;      if (i mod 5) = 0 then raise Exit;      print_string ", "    with Exit ->      print_newline()  done  ;;1, 2, 3, 4, 56, 7, 8, 9, 10- : unit = ()`

Though even if the continue statement does not exist, it is possible to add it with camlp4.

## Octave

`v = "";for i = 1:10  v = sprintf("%s%d", v, i);  if ( mod(i, 5) == 0 )     disp(v)    v = "";    continue  endif  v = sprintf("%s, ", v);endfor`

## Oforth

`: loopCont | i |    10 loop: i [       i dup print 5 mod ifZero: [ printcr continue ]      "," .       ] ;`

## Ol

We use continuation to break the execution of the inner body.

` (let loop ((i 1))   (when (less? i 11)      (call/cc (lambda (continue)         (display i)         (when (zero? (mod i 5))            (print)            (continue #f))         (display ", ")))      (loop (+ i 1)))) `
Output:
```1, 2, 3, 4, 5
6, 7, 8, 9, 10
```

## Oz

By using the "continue" feature of the for-loop, we bind C to a nullary procedure which, when invoked, immediately goes on to the next iteration of the loop.

`for I in 1..10 continue:C do   {System.print I}   if I mod 5 == 0 then      {System.printInfo "\n"}      {C}   end   {System.printInfo ", "}end`

## PARI/GP

`for(n=1,10,  print1(n);  if(n%5 == 0, print();continue);  print1(", "))`

See Delphi

## Perl

`foreach (1..10) {    print \$_;    if (\$_ % 5 == 0) {        print "\n";        next;    }    print ', ';}`

It is also possible to use a goto statement to jump over the iterative code section for a particular loop:

`foreach (1..10) {    print \$_;    if (\$_ % 5 == 0) {        print "\n";        goto MYLABEL;    }    print ', ';MYLABEL:}`

## Phix

Library: Phix/basics
```with javascript_semantics
for i=1 to 10 do
printf(1,"%d", i)
if remainder(i,5)=0 then
printf(1, "\n")
continue
end if
printf(1,", ")
end for
```
Output:
```1, 2, 3, 4, 5
6, 7, 8, 9, 10
```

The following works just as well, with identical output

```with javascript_semantics
for i=1 to 10 do
printf(1,"%d", i)
if remainder(i,5)=0 then
printf(1, "\n")
else
printf(1,", ")
end if
end for
```

## PHP

`for (\$i = 1; \$i <= 10; \$i++) {    echo \$i;    if (\$i % 5 == 0) {        echo "\n";        continue;    }    echo ', ';}`

## Picat

Picat doesn't have a continue statement. So I just use a conditional that ends the body of the predicate.

Translation of: Prolog
Works with: Picat
` main =>    foreach (I in 1..10)        printf("%d", I),        if (I mod 5 == 0) then            nl        else            printf(", ")        end,    end. `
Output:
```1, 2, 3, 4, 5
6, 7, 8, 9, 10
```

## PicoLisp

PicoLisp doesn't have an explicit 'continue' functionality. It can always be emulated with a conditional expression.

`(for I 10   (print I)   (if (=0 (% I 5))      (prinl)      (prin ", ") ) )`

## Pike

`int main(){   for(int i = 1; i <= 10; i++){      write(sprintf("%d",i));      if(i % 5 == 0){         write("\n");         continue;      }      write(", ");   }}`

## PL/I

`loop:do i = 1 to 10;   put edit (i) (f(3));   if mod(i,5) = 0 then do; put skip; iterate loop; end;   put edit (', ') (a);end;`

## Plain English

In Plain English, continue is spelled `repeat` and is the only way to specify an end of a loop.

`To run:Start up.Demonstrate continue.Wait for the escape key.Shut down. To demonstrate continue:If a counter is past 10, exit.Convert the counter to a string.Write the string on the console without advancing.If the counter is evenly divisible by 5, write "" on the console; repeat.Write ", " on the console without advancing.Repeat.`

## Pop11

`lvars i;for i from 1 to 10 do   printf(i, '%p');   if i rem 5 = 0 then       printf('\n');       nextloop;   endif;   printf(', ')endfor;`

## PowerShell

Translation of: C
`for (\$i = 1; \$i -le 10; \$i++) {    Write-Host -NoNewline \$i    if (\$i % 5 -eq 0) {        Write-Host        continue    }    Write-Host -NoNewline ", "}`

## Prolog

Prolog doesn't have a continue statement. So I just use a conditional that ends the body of the predicate.

Works with: GNU Prolog
Works with: SWI Prolog
` :- initialization(main). print_list(Min, Max) :-    Min < Max,    write(Min),    Min1 is Min + 1,    (        Min mod 5 =:= 0        -> nl        ; write(',')    ),    print_list(Min1, Max). print_list(Max, Max) :-    write(Max),    nl. main :-    print_list(1, 10). `
Output:
```1,2,3,4,5
6,7,8,9,10
```

## Python

`for i in xrange(1,11):    if i % 5 == 0:        print i        continue    print i, ",",`

## Quackery

`10 times  [ i^ 1+ dup echo    5 mod 0 = iff      cr done    say ", " ]`

## R

Translation of: C++
`for(i in 1:10){   cat(i)   if(i %% 5 == 0)    {      cat("\n")      next   }   cat(", ")}`

## Racket

It is possible to skip loop iterations in Racket, but an explicit continue construct is rarely used:

` #lang racket ;; Idiomatic way(for ([i (in-range 1 11)])  (if (= (remainder i 5) 0)      (printf "~a~n" i)      (printf "~a, " i))) ;; Forces a skip, but not idiomatic because;; the logic is less obvious(for ([i (in-range 1 11)]      #:unless (and (= (remainder i 5) 0)                    (printf "~a~n" i)))  (printf "~a, " i)) `

## Raku

(formerly Perl 6)

Translation of: Perl
Works with: Rakudo Star version 2010.08
`for 1 .. 10 {    .print;    if \$_ %% 5 {        print "\n";        next;    }    print ', ';}`

or without using a loop:

`\$_.join(", ").say for [1..5], [6..10];`

## REBOL

`rebol [	Title: "Loop/Continue"	URL: http://rosettacode.org/wiki/Loop/Continue] ; REBOL does not provide a 'continue' word for loop constructs,; however, you may not even miss it: print "One liner (compare to ALGOL 68 solution):"repeat i 10 [prin rejoin [i  either 0 = mod i 5 [crlf][", "]]] print [crlf "Port of ADA solution:"]for i 1 10 1 [	prin i	either 0 = mod i 5 [		prin newline	][		prin ", "	]]`
Output:
```One liner (compare to ALGOL 68 solution):
1, 2, 3, 4, 5
6, 7, 8, 9, 10

1, 2, 3, 4, 5
6, 7, 8, 9, 10```

## Red

`repeat i 10 [    prin i    if i = 10 [break]    either i = 5 [print ""][prin ","]]1,2,3,4,56,7,8,9,10`

## REXX

### version 1

(This program could be simpler by using a   then/else   construct, but an   iterate   was used to conform to the task.)

`/*REXX program  illustrates  an example of a   DO   loop with an  ITERATE  (continue).  */   do j=1  for 10                                 /*this is equivalent to:  DO J=1 TO 10 */  call charout ,  j                              /*write the integer to the terminal.   */  if j//5\==0  then do                           /*Not a multiple of five?   Then ···   */                    call charout , ", "          /*  write a comma to the terminal, ··· */                    iterate                      /* ··· & then go back for next integer.*/                    end  say                                            /*force REXX to display on next line.  */  end   /*j*/                                                 /*stick a fork in it,  we're all done. */`

Program note:   the comma (,) immediately after the   charout   BIF indicates to use the terminal output stream.

output

```1, 2, 3, 4, 5
6, 7, 8, 9, 10
```

### version 2

`/*REXX program  illustrates  an example of a   DO   loop with an  ITERATE  (continue).  */\$=                                               /*nullify the variable used for display*/    do j=1  for 10                               /*this is equivalent to:  DO J=1 TO 10 */    \$=\$ || j', '                                 /*append the integer to a placeholder. */    if j//5==0  then say left(\$, length(\$) - 2)  /*Is  J  a multiple of five?  Then SAY.*/    if j==5     then \$=                          /*start the display line over again.   */    end   /*j*/                                                 /*stick a fork in it,  we're all done. */`

output   is the same as the 1st REXX version.

## Ring

` for i = 1 TO 10   see i    if i % 5 = 0      see nl      loop   ok   see ", "next `

## Ruby

`for i in 1..10 do   print i   if i % 5 == 0 then      puts      next   end   print ', 'end`

The "for" look could be written like this:

`(1..10).each do |i| ...1.upto(10) do |i| ...10.times do |n| i=n+1; ...`

Without meeting the criteria (showing loop continuation), this task could be written as:

`(1..10).each_slice(5){|ar| puts ar.join(", ")}`

## Rust

`fn main() {    for i in 1..=10 {        print!("{}", i);        if i % 5 == 0 {            println!();            continue;        }        print!(", ");    }}`

## Salmon

`iterate (x; [1...10])  {    print(x);    if (x % 5 == 0)      {        print("\n");        continue;      };    print(", ");  };`

## Sather

There's no `continue!` in Sather. The code solve the task without forcing a new iteration.

`class MAIN is  main is    i:INT;    loop i := 1.upto!(10);      #OUT + i;      if i%5 = 0 then         #OUT + "\n";      else        #OUT + ", ";      end;    end;  end;end;`

## Scala

Scala doesn't have a `continue` keyword. However, you may not even miss it, `if` could be used here.

### The intuitive way

`for (i <- 1 to 10) {  print(i)  if (i % 5 == 0) println() else print(", ")  }`

### Functional solution

Thinking In Scala© says: we avoid for loops and handle it the Functional way:

1. Create a Range 1..10 included
2. Split the range after converting to a List to a pair of List's
3. A List of the elements of pair of will be created: List(List(1,2,3,4,5),List(6,7,8,9,10))
4. The map makes for both elements in the List a conversion to a comma separated String, yielding a List of two Strings.
5. Both comma separated strings will be separated by an EOL
`  val a = (1 to 10 /*1.*/ ).toList.splitAt(5) //2.  println(List(a._1, a._2) /*3.*/ .map(_.mkString(", ") /*4.*/ ).mkString("\n") /*5.*/ )`

## Scheme

 This example is incorrect. It does not accomplish the given task. Please fix the code and remove this message.
`(define (loop i)  (if (> i 10) 'done      (begin       (display i)       (cond ((zero? (modulo i 5))              (newline) (loop (+ 1 i)))             (else (display ", ")                   (loop (+ 1 i)))))))`

## Scilab

Works with: Scilab version 5.5.1
`for i=1:10    printf("%2d ",i)    if modulo(i,5)~=0 then      printf(", ")      continue    end    printf("\n")end `
Output:
``` 1 ,  2 ,  3 ,  4 ,  5
6 ,  7 ,  8 ,  9 , 10 ```

## Sidef

`for i in (1..10) {    print i    if (i %% 5) {        print "\n"        next    }    print ', '}`

## Simula

Works with: SIMULA-67
`! Loops/Continue - simula67 - 07/03/2017;begin    integer i;    for i:=1 step 1 until 10 do begin        outint(i,5);        if mod(i,5)=0 then begin            outimage;            goto loop        end;        outtext(", ");    loop:    end end`
Output:
```    1,     2,     3,     4,     5
6,     7,     8,     9,    10
```

## Smalltalk

Works with: Pharo
Works with: Smalltalk/X
actually works with all dialects ¹
` 1 to: 10 do: [ :i |    [ :continue |        i % 5 = 0 ifTrue: [             Transcript show: i; cr.            continue value ].        Transcript             show: i;            show: ', '.		    ] valueWithExit.] `

¹ if valueWithExit is not present in the Block class, it can be added as:

`valueWithExit    ^ self value:[^ nil]`

## Spin

Works with: BST/BSTC
Works with: FastSpin/FlexSpin
Works with: HomeSpun
Works with: OpenSpin
`con  _clkmode = xtal1 + pll16x  _clkfreq = 80_000_000 obj  ser : "FullDuplexSerial.spin" pub main | i  ser.start(31, 30, 0, 115200)   repeat i from 1 to 10    ser.dec(i)    if i // 5      ser.str(string(", "))      next    ser.str(string(13,10))   waitcnt(_clkfreq + cnt)  ser.stop  cogstop(0)`
Output:
```1, 2, 3, 4, 5
6, 7, 8, 9, 10
```

## SPL

`> n, 1..10  s += n  ? n%5, s += ", "  >> n%5  #.output(s)  s = ""<`
Output:
```1, 2, 3, 4, 5
6, 7, 8, 9, 10
```

## SQL PL

Works with: Db2 LUW
version 9.7 or higher.

With SQL PL:

` --#SET TERMINATOR @ SET SERVEROUTPUT ON @ BEGIN DECLARE I SMALLINT DEFAULT 1;  Loop: WHILE (I <= 10) DO  CALL DBMS_OUTPUT.PUT(I);  SET I = I + 1;  IF (MOD(I - 1, 5) = 0) THEN   CALL DBMS_OUTPUT.PUT_LINE(' ');   ITERATE Loop;  END IF;  CALL DBMS_OUTPUT.PUT(', '); END WHILE Loop;END @ `

Output:

```db2 => BEGIN
...
db2 (cont.) => END @
DB20000I  The SQL command completed successfully.

1, 2, 3, 4, 5
6, 7, 8, 9, 10
```

## Stata

See continue in Stata help. Notice that the _continue option of display has another purpose: it suppresses the automatic newline at the end of the display command.

`forvalues n=1/10 {	display `n' _continue	if mod(`n',5)==0 {		display		continue	}	display ", " _continue}`

## Suneido

`ob = Object()for (i = 1; i <= 10; ++i)    {    ob.Add(i)    if i is 5        {        Print(ob.Join(','))        ob = Object()        }    }Print(ob.Join(','))`
Output:
`1,2,3,4,56,7,8,9,10ok`

## Swift

`for i in 1...10 {    print(i, terminator: "")    if i % 5 == 0 {        print()        continue    }    print(", ", terminator: "")}`
Output:
```1, 2, 3, 4, 5
6, 7, 8, 9, 10
```

## Tcl

`for {set i 1} {\$i <= 10} {incr i} {   puts -nonewline \$i   if {\$i % 5 == 0} {      puts ""      continue   }   puts -nonewline ", "}`

## Transact-SQL

` DECLARE @i INT = 0;DECLARE @str VarChar(40) = '';WHILE @i<10  BEGIN    SET @i = @i + 1;    SET @str = @str + CONVERT(varchar(2),@i);    IF @i % 5 = 0      BEGIN        PRINT @str;        SET @str =''        CONTINUE;      END    SET @str = @str +', ';  END; `

## TUSCRIPT

` \$\$ MODE TUSCRIPTnumbers=""LOOP n=1,10numbers=APPEND (numbers,", ",n)rest=n%5IF (rest!=0) CYCLE PRINT numbers numbers=""ENDLOOP `
Output:
```1, 2, 3, 4, 5
6, 7, 8, 9, 10
```

## UNIX Shell

`Z=1while (( Z<=10 )); do    echo -e "\$Z\c"    if (( Z % 5 != 0 )); then        echo -e ", \c"    else        echo -e ""    fi    (( Z++ ))done`
Works with: Bash
`for ((i=1;i<=10;i++)); do  echo -n \$i  if [ \$((i%5)) -eq 0 ]; then    echo    continue  fi  echo -n ", "done`

## UnixPipes

`yes \ | cat -n | head -n 10 | xargs -n 5 echo | tr ' ' ,`

## Ursa

Translation of: Python
`decl int ifor (set i 1) (< i 11) (inc i)        if (= (mod i 5) 0)                out i endl console                continue        end if        out i ", " consoleend for`

## Vala

`for (int i = 1; i <= 10; i++) {  stdout.printf("%d", i);  if (i % 5 == 0) {    stdout.printf("\n");    continue;  }  stdout.printf(", ");}`

## VBA

`Public Sub LoopContinue()    Dim value As Integer    For value = 1 To 10        Debug.Print value;        If value Mod 5 = 0 Then            'VBA does not have a continue statement            Debug.Print        Else            Debug.Print ",";        End If    Next valueEnd Sub`

## Vedit macro language

`for (#1 = 1; #1 <= 10; #1++) {    Num_Type(#1, LEFT+NOCR)    if (#1 % 5 == 0) {        Type_Newline        Continue    }    Message(", ")}`

## Vlang

`fn main() {    for i in 1..11 {        print(i)        if i%5==0{            println('')            continue        }        print(', ')    }}`
Output:
```1, 2, 3, 4, 5
6, 7, 8, 9, 10
```

## Wren

From v0.4.0 Wren has a continue keyword which works in the expected fashion.

`for (i in 1..10) {    System.write(i)    if (i%5 == 0) {        System.print()                continue    }    System.write(", ")} System.print()`
Output:
```1, 2, 3, 4, 5
6, 7, 8, 9, 10
```

## X86 Assembly

Works with: nasm
Works with: windows

The code got really long, because i manually convert the numbers to ASCII, which gets harder with multiple digits(the number 10). The way you implement continue in X86 Assembly is the same way as how you would create a loop: you just implement a (conditional) jump to another line of code.

` extern _printf section .data    output db 0,0,0,0    reversedOutput db 0,0 section .textglobal _main_main:    mov ecx, 0    looping:        inc ecx        mov eax, ecx        push ecx        cmp ecx, 5        je do5        cmp ecx, 10        je do10    don:        call createOutput        mov [eax+1], byte 0x2c        mov [eax+2], byte 0x20        push eax        call _printf        add esp, 4        pop ecx        jmp looping    do5:        call createOutput        mov [eax+1], byte 0x0a        push eax        call _printf        add esp, 4        pop ecx        jmp looping    do10:        call createOutput        mov [eax+2], byte 0x0a        push eax        call _printf        add esp, 4        pop ecx        xor eax, eax        ret          createOutput: ;parameter in eax    ;eax between 1 and 99    push ebx    mov ecx, 0    clearOutput:        mov [output+ecx], byte 0        cmp ecx, 3        je next        inc ecx        jmp clearOutput    next:        mov ecx, 0        mov ebx, 10    cOlooping:        xor edx, edx        div ebx        mov [reversedOutput+ecx], dl        add [reversedOutput+ecx], byte 0x30        cmp eax, 0        je reverse        cmp ecx, 1        je reverse        inc ecx        jmp cOlooping    reverse:        mov ecx, -1        mov ebx, 0        name:            inc ecx            neg ecx            mov dl, [reversedOutput+ecx+1]            neg ecx            cmp dl, 0            je name            mov [output + ebx], dl            inc ebx            cmp ecx, 1            jl name        mov eax, output        pop ebx        ret `
Output:
```1, 2, 3, 4, 5
6, 7, 8, 9, 10
```

## XBasic

Works with: Windows XBasic
` PROGRAM "loopcontinue" DECLARE FUNCTION Entry() FUNCTION Entry()  FOR i% = 1 TO 10    PRINT i%;    IF i% MOD 5 = 0 THEN      PRINT      DO NEXT ' It looks like DO FOR backs to the FOR with the current value of i%    END IF    PRINT ", ";  NEXT i%END FUNCTIONEND PROGRAM `
Output:
```1, 2, 3, 4, 5
6, 7, 8, 9, 10
```

## XPL0

Like Ada and ALGOL there's no 'continue' command. The task is solved very simply anyway. The commands 'int' and 'rem' are shown spelled out here. Only the first three characters of a command are required.

`code CrLf=9, IntOut=11, Text=12;integer N;for N:= 1 to 10 do        [IntOut(0, N); if remainder(N/5) \#0\ then Text(0, ", ") else CrLf(0)]`
Output:
```1, 2, 3, 4, 5
6, 7, 8, 9, 10
```

## Yabasic

`for i = 1 to 10  print str\$(i);  if mod(i, 5) = 0 then    print     continue  end if  print ", ";nextprintend`

## zkl

`foreach n in ([1..10]){print(n); if(n%5==0){println(); continue;} print(", ")}// or foreach n in ([1..10]){print(n,(n%5) and ", " or "\n")}`

## Zig

`const std = @import("std"); pub fn main() !void {    const stdout_wr = std.io.getStdOut().writer();    var i: i8 = 1;    while (i <= 10) : (i += 1) {        try stdout_wr.print("{d}", .{i});        if (i == 5) {            try stdout_wr.writeAll("\n");            continue;        }        try stdout_wr.writeAll(", ");    }}`