Strip a set of characters from a string
You are encouraged to solve this task according to the task description, using any language you may know.
- Task
Create a function that strips a set of characters from a string.
The function should take two arguments:
- a string to be stripped
- a string containing the set of characters to be stripped
The returned string should contain the first string, stripped of any characters in the second argument:
<lang pseudocode> print stripchars("She was a soul stripper. She took my heart!","aei")
Sh ws soul strppr. Sh took my hrt!</lang>
- Metrics
- Counting
- Word frequency
- Letter frequency
- Jewels and stones
- I before E except after C
- Bioinformatics/base count
- Count occurrences of a substring
- Count how many vowels and consonants occur in a string
- Remove/replace
- XXXX redacted
- Conjugate a Latin verb
- Remove vowels from a string
- String interpolation (included)
- Strip block comments
- Strip comments from a string
- Strip a set of characters from a string
- Strip whitespace from a string -- top and tail
- Strip control codes and extended characters from a string
- Anagrams/Derangements/shuffling
- Word wheel
- ABC problem
- Sattolo cycle
- Knuth shuffle
- Ordered words
- Superpermutation minimisation
- Textonyms (using a phone text pad)
- Anagrams
- Anagrams/Deranged anagrams
- Permutations/Derangements
- Find/Search/Determine
- ABC words
- Odd words
- Word ladder
- Semordnilap
- Word search
- Wordiff (game)
- String matching
- Tea cup rim text
- Alternade words
- Changeable words
- State name puzzle
- String comparison
- Unique characters
- Unique characters in each string
- Extract file extension
- Levenshtein distance
- Palindrome detection
- Common list elements
- Longest common suffix
- Longest common prefix
- Compare a list of strings
- Longest common substring
- Find common directory path
- Words from neighbour ones
- Change e letters to i in words
- Non-continuous subsequences
- Longest common subsequence
- Longest palindromic substrings
- Longest increasing subsequence
- Words containing "the" substring
- Sum of the digits of n is substring of n
- Determine if a string is numeric
- Determine if a string is collapsible
- Determine if a string is squeezable
- Determine if a string has all unique characters
- Determine if a string has all the same characters
- Longest substrings without repeating characters
- Find words which contains all the vowels
- Find words which contains most consonants
- Find words which contains more than 3 vowels
- Find words which first and last three letters are equals
- Find words which odd letters are consonants and even letters are vowels or vice_versa
- Formatting
- Substring
- Rep-string
- Word wrap
- String case
- Align columns
- Literals/String
- Repeat a string
- Brace expansion
- Brace expansion using ranges
- Reverse a string
- Phrase reversals
- Comma quibbling
- Special characters
- String concatenation
- Substring/Top and tail
- Commatizing numbers
- Reverse words in a string
- Suffixation of decimal numbers
- Long literals, with continuations
- Numerical and alphabetical suffixes
- Abbreviations, easy
- Abbreviations, simple
- Abbreviations, automatic
- Song lyrics/poems/Mad Libs/phrases
- Mad Libs
- Magic 8-ball
- 99 Bottles of Beer
- The Name Game (a song)
- The Old lady swallowed a fly
- The Twelve Days of Christmas
- Tokenize
- Text between
- Tokenize a string
- Word break problem
- Tokenize a string with escaping
- Split a character string based on change of character
- Sequences
11l
<lang 11l>F stripchars(s, chars)
R s.filter(c -> c !C @chars).join(‘’)
print(stripchars(‘She was a soul stripper. She took my heart!’, ‘aei’))</lang>
- Output:
Sh ws soul strppr. Sh took my hrt!
360 Assembly
The program uses two ASSIST macro (XDECO,XPRNT) to keep the code as short as possible. <lang 360asm>* Strip a set of characters from a string 07/07/2016 STRIPCH CSECT
USING STRIPCH,R13 base register B 72(R15) skip savearea DC 17F'0' savearea STM R14,R12,12(R13) prolog ST R13,4(R15) " <- ST R15,8(R13) " -> LR R13,R15 " addressability LA R1,PARMLIST parameter list BAL R14,STRIPCHR c3=stripchr(c1,c2) LA R2,PG @pg LH R3,C3 length(c3) LA R4,C3+2 @c3 LR R5,R3 length(c3) MVCL R2,R4 pg=c3 XPRNT PG,80 print buffer L R13,4(0,R13) epilog LM R14,R12,12(R13) " restore XR R15,R15 " rc=0 BR R14 exit
PARMLIST DC A(C3) @c3
DC A(C1) @c1 DC A(C2) @c2
C1 DC H'43',CL62'She was a soul stripper. She took my heart!' C2 DC H'3',CL14'aei' c2 [varchar(14)] C3 DS H,CL62 c3 [varchar(62)] PG DC CL80' ' buffer [char(80)]
- ------- stripchr -----------------------------------------------------
STRIPCHR L R9,0(R1) @parm1
L R2,4(R1) @parm2 L R3,8(R1) @parm3 MVC PHRASE(64),0(R2) phrase=parm2 MVC REMOVE(16),0(R3) remove=parm3 SR R8,R8 k=0 LA R6,1 i=1
LOOPI CH R6,PHRASE do i=1 to length(phrase)
BH ELOOPI " LA R4,PHRASE+1 @phrase AR R4,R6 +i MVC CI(1),0(R4) ci=substr(phrase,i,1) MVI OK,X'01' ok='1'B LA R7,1 j=1
LOOPJ CH R7,REMOVE do j=1 to length(remove)
BH ELOOPJ " LA R4,REMOVE+1 @remove AR R4,R7 +j MVC CJ,0(R4) cj=substr(remove,j,1) CLC CI,CJ if ci=cj BNE CINECJ then MVI OK,X'00' ok='0'B B ELOOPJ leave j
CINECJ LA R7,1(R7) j=j+1
B LOOPJ end do j
ELOOPJ CLI OK,X'01' if ok
BNE NOTOK then LA R8,1(R8) k=k+1 LA R4,RESULT+1 @result AR R4,R8 +k MVC 0(1,R4),CI substr(result,k,1)=ci
NOTOK LA R6,1(R6) i=i+1
B LOOPI end do i
ELOOPI STH R8,RESULT length(result)=k
MVC 0(64,R9),RESULT return(result) BR R14 return to caller
CI DS CL1 ci [char(1)] CJ DS CL1 cj [char(1)] OK DS X ok [boolean] PHRASE DS H,CL62 phrase [varchar(62)] REMOVE DS H,CL14 remove [varchar(14)] RESULT DS H,CL62 result [varchar(62)]
- ---- -------------------------------------------------------
YREGS END STRIPCH</lang>
- Output:
Sh ws soul strppr. Sh took my hrt!
8080 Assembly
<lang 8080asm> org 100h jmp demo ;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;; ;;; Strip a set of chracters from a string, in place. ;;; Input: ;;; DE = $-terminated string to be stripped ;;; HL = $-terminated string containing characters to strip stripchars: push h ; Store characters to strip on stack. mov b,d ; Copy input string pointer to BC. This will be mov c,e ; the target pointer. stripchr: ldax d ; Copy current character from [DE] to [BC] stax b cpi '$' ; Done? jz stripdone pop h ; Get string of characters to strip. push h stripsrch: mvi a,'$' ; At the end? cmp m jz srchdone ldax d ; Does it match the character in the input? cmp m jz srchfound inx h ; Look at next character to strip jmp stripsrch srchfound: dcx b ; Found: copy next character over it later. srchdone: inx b ; Increment both pointers inx d jmp stripchr stripdone: pop h ; Remove temporary variable from stack ret ; Done ;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;; demo: lxi d,string ; Strip from the string, lxi h,remove ; the characters to remove. call stripchars lxi d,string ; Print the result. mvi c,9 jmp 5 string: db 'She was a soul stripper. She took my heart!$' remove: db 'aei$'</lang>
- Output:
Sh ws soul strppr. Sh took my hrt!
8086 Assembly
<lang asm> bits 16 cpu 8086 section .text org 100h jmp demo ;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;; ;;; Strip a set of characters from a string, in place. ;;; Input: ;;; DS:DI = $-terminated string to be stripped. ;;; DS:SI = $-terminated string containing chars to strip stripchars: mov bx,di ; Copy string ptr to use as target ptr mov dx,si ; Copy ptr to characters to strip .char: mov al,[di] ; Copy character mov [bx],al cmp al,'$' ; Done? je .done mov si,dx ; See if character should be stripped .search: mov ah,[si] cmp ah,'$' ; End of characters to strip? je .srchdone cmp ah,al ; Does it match the current character? je .srchfound inc si ; Try next character jmp .search .srchfound: dec bx ; Found - decrement target pointer .srchdone: inc bx ; Increment both pointers inc di jmp .char .done: ret ;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;; demo: mov di,string ; Strip from the string, mov si,remove ; the characters to remove. call stripchars mov dx,string ; Print the result mov ah,9 int 21h ret section .data string: db 'She was a soul stripper. She took my heart!$' remove: db 'aei$'</lang>
- Output:
Sh ws soul strppr. Sh took my hrt!
Action!
<lang Action!>PROC Strip(CHAR ARRAY text,chars,res)
BYTE i,j,size,found CHAR c
size=0 FOR i=1 TO text(0) DO c=text(i) found=0 FOR j=1 TO chars(0) DO IF c=chars(j) THEN found=1 EXIT FI OD IF found=0 THEN size==+1 res(size)=c FI OD res(0)=size
RETURN
PROC Main()
CHAR ARRAY text="She was a soul stripper. She took my heart!", chars="aei", result(255)
Strip(text,chars,result) PrintE("String to be stripped:") PrintF("""%S""%E%E",text) PrintE("Characters to be stripped:") PrintF("""%S""%E%E",chars) PrintE("Stripped string:") PrintF("""%S""%E%E",result)
RETURN</lang>
- Output:
Screenshot from Atari 8-bit computer
String to be stripped: "She was a soul stripper. She took my heart!" Characters to be stripped: "aei" Stripped string: "Sh ws soul strppr. Sh took my hrt!"
Ada
<lang Ada>with Ada.Text_IO;
procedure Strip_Characters_From_String is
function Strip(The_String: String; The_Characters: String) return String is Keep: array (Character) of Boolean := (others => True); Result: String(The_String'Range); Last: Natural := Result'First-1; begin for I in The_Characters'Range loop Keep(The_Characters(I)) := False; end loop; for J in The_String'Range loop if Keep(The_String(J)) then Last := Last+1; Result(Last) := The_String(J); end if; end loop; return Result(Result'First .. Last); end Strip;
S: String := "She was a soul stripper. She took my heart!";
begin -- main
Ada.Text_IO.Put_Line(Strip(S, "aei"));
end Strip_Characters_From_String;</lang>
- Output:
> ./strip_characters_from_string Sh ws soul strppr. Sh took my hrt!
Aime
<lang aime>text stripchars1(data b, text w) {
integer p;
p = b.look(0, w); while (p < ~b) { b.delete(p); p += b.look(p, w); }
b;
}
text stripchars2(data b, text w) {
b.drop(w);
}
integer main(void) {
o_text(stripchars1("She was a soul stripper. She took my heart!", "aei")); o_newline();
o_text(stripchars2("She was a soul stripper. She took my heart!", "aei")); o_newline();
return 0;
}</lang>
ALGOL 68
<lang algol68>#!/usr/local/bin/a68g --script #
PROC strip chars = (STRING mine, ore)STRING: (
STRING out := ""; FOR i FROM LWB mine TO UPB mine DO IF NOT char in string(mine[i], LOC INT, ore) THEN out +:= mine[i] FI OD; out[@LWB mine]
);
printf(($gl$,stripchars("She was a soul stripper. She took my heart!","aei")))</lang>
- Output:
Sh ws soul strppr. Sh took my hrt!
ALGOL W
<lang algolw>begin
% returns s with the characters in remove removed % % as all strings in Algol W are fixed length, the length of remove % % must be specified in removeLength % string(256) procedure stripCharacters( string(256) value s, remove ; integer value removeLength ) ; begin string(256) resultText; integer tPos; resultText := " "; tPos := 0; for sPos := 0 until 255 do begin logical keepCharacter; string(1) c; c := s( sPos // 1 ); keepCharacter := true; for rPos := 0 until removeLength - 1 do begin if remove( rPos // 1 ) = c then begin % have a character that should be removed % keepCharacter := false; goto endSearch end if_have_a_character_to_remove ; end for_rPos ;
endSearch:
if keepCharacter then begin resultText( tPos // 1 ) := c; tPos := tPos + 1 end if_keepCharacter end for_sPos ; resultText end stripCharacters ; % task test case % begin string(256) ex, stripped; ex := "She was a soul stripper. She took my heart!"; stripped := stripCharacters( ex, "aei", 3 ); write( "text: ", ex( 0 // 64 ) ); write( " ->: ", stripped( 0 // 64 ) ) end
end.</lang>
- Output:
text: She was a soul stripper. She took my heart! ->: Sh ws soul strppr. Sh took my hrt!
APL
APL has a built-in function ~ ('without') that removes elements from a vector. Because a string is just a character vector, this can be used to remove characters from a string.
<lang APL>'She was a soul stripper. She took my heart!' ~ 'aei'</lang>
- Output:
Sh ws soul strppr. Sh took my hrt!
AppleScript
Using text item delimiters
<lang AppleScript>stripChar("She was a soul stripper. She took my heart!", "aei")
on stripChar(str, chrs)
tell AppleScript set oldTIDs to text item delimiters set text item delimiters to characters of chrs set TIs to text items of str set text item delimiters to "" set str to TIs as string set text item delimiters to oldTIDs end tell return str
end stripChar</lang>
- Output:
"Sh ws soul strppr. Sh took my hrt!"
By functional composition
Without regex
(Following the Haskell contribution in reversing the argument order to the sequence more probable in a context of potential currying or partial application).
<lang AppleScript>-- stripChars :: String -> String -> String on stripChars(strNeedles, strHaystack)
script notNeedles on |λ|(x) notElem(x, strNeedles) end |λ| end script intercalate("", filter(notNeedles, strHaystack))
end stripChars
-- TEST ---------------------------------------------------------------------------
on run
stripChars("aei", "She was a soul stripper. She took my heart!") --> "Sh ws soul strppr. Sh took my hrt!"
end run
-- GENERIC FUNCTIONS ---------------------------------------------------------------------------
-- filter :: (a -> Bool) -> [a] -> [a] on filter(f, xs)
tell mReturn(f) set lst to {} set lng to length of xs repeat with i from 1 to lng set v to item i of xs if |λ|(v, i, xs) then set end of lst to v end repeat return lst end tell
end filter
-- notElem :: Eq a => a -> [a] -> Bool on notElem(x, xs)
xs does not contain x
end notElem
-- intercalate :: Text -> [Text] -> Text on intercalate(strText, lstText)
set {dlm, my text item delimiters} to {my text item delimiters, strText} set strJoined to lstText as text set my text item delimiters to dlm return strJoined
end intercalate
-- Lift 2nd class handler function into 1st class script wrapper -- mReturn :: Handler -> Script on mReturn(f)
if class of f is script then f else script property |λ| : f end script end if
end mReturn</lang>
- Output:
"Sh ws soul strppr. Sh took my hrt!"
With regex
OS X Yosemite onwards – importing the Foundation classes to use NSRegularExpression
<lang AppleScript>use framework "Foundation"
-- stripChars :: String -> String -> String
on stripChars(strNeedles, strHaystack)
intercalate("", splitRegex("[" & strNeedles & "]", strHaystack))
end stripChars
-- TEST ------------------------------------------------------------------------
on run
stripChars("aei", "She was a soul stripper. She took my heart!") --> "Sh ws soul strppr. Sh took my hrt!"
end run
-- GENERIC FUNCTIONS -----------------------------------------------------------
-- splitRegex :: RegexPattern -> String -> [String] on splitRegex(strRegex, str)
set lstMatches to regexMatches(strRegex, str) if length of lstMatches > 0 then script preceding on |λ|(a, x) set iFrom to start of a set iLocn to (location of x) if iLocn > iFrom then set strPart to text (iFrom + 1) thru iLocn of str else set strPart to "" end if {parts:parts of a & strPart, start:iLocn + (length of x) - 1} end |λ| end script set recLast to foldl(preceding, {parts:[], start:0}, lstMatches) set iFinal to start of recLast if iFinal < length of str then parts of recLast & text (iFinal + 1) thru -1 of str else parts of recLast & "" end if else {str} end if
end splitRegex
-- regexMatches :: RegexPattern -> String -> [{location:Int, length:Int}] on regexMatches(strRegex, str)
set ca to current application set oRgx to ca's NSRegularExpression's regularExpressionWithPattern:strRegex ¬ options:((ca's NSRegularExpressionAnchorsMatchLines as integer)) |error|:(missing value) set oString to ca's NSString's stringWithString:str set oMatches to oRgx's matchesInString:oString options:0 range:{location:0, |length|:oString's |length|()} set lstMatches to {} set lng to count of oMatches repeat with i from 1 to lng set end of lstMatches to range() of item i of oMatches end repeat lstMatches
end regexMatches
-- foldl :: (a -> b -> a) -> a -> [b] -> a on foldl(f, startValue, xs)
tell mReturn(f) set v to startValue set lng to length of xs repeat with i from 1 to lng set v to |λ|(v, item i of xs, i, xs) end repeat return v end tell
end foldl
-- intercalate :: Text -> [Text] -> Text on intercalate(strText, lstText)
set {dlm, my text item delimiters} to {my text item delimiters, strText} set strJoined to lstText as text set my text item delimiters to dlm return strJoined
end intercalate
-- Lift 2nd class handler function into 1st class script wrapper -- mReturn :: Handler -> Script on mReturn(f)
if class of f is script then f else script property |λ| : f end script end if
end mReturn</lang>
- Output:
"Sh ws soul strppr. Sh took my hrt!"
Applesoft BASIC
<lang basic>100 LET S$ = "SHE WAS A SOUL STRIPPER. SHE TOOK MY HEART!" 110 LET RM$ = "AEI" 120 GOSUB 200STRIPCHARS 130 PRINT SC$ 190 END 200 REM 210 REM STRIPCHARS 220 REM 230 LET SC$ = "" 240 LET SL = LEN (S$) 250 IF SL = 0 THEN RETURN 260 FOR SI = 1 TO SL 270 LET SM$ = MID$ (S$,SI,1) 280 FOR SJ = 1 TO LEN (RM$) 290 LET SR$ = MID$ (RM$,SJ,1) 300 LET ST = SR$ < > SM$ 310 IF ST THEN NEXT SJ 320 IF ST THEN SC$ = SC$ + SM$ 330 NEXT SI 340 RETURN </lang>
- Output:
SH WS SOUL STRPPR. SH TOOK MY HRT!
Arturo
<lang rebol>stripChars: function [str, chars]->
join select split str => [not? in? & split chars]
print stripChars "She was a soul stripper. She took my heart!" "aei"</lang>
- Output:
Sh ws soul strppr. Sh took my hrt!
AutoHotkey
<lang AutoHotkey>MsgBox % stripchars("She was a soul stripper. She took my heart!","aei")
StripChars(string, charsToStrip){
Loop Parse, charsToStrip StringReplace, string, string, % A_LoopField, , All return string
}</lang>
- Output:
Sh ws soul strppr. Sh took my hrt!
AWK
<lang AWK>#!/usr/bin/awk -f BEGIN {
x = "She was a soul stripper. She took my heart!"; print x; gsub(/[aei]/,"",x); print x;
}</lang>
- Output:
She was a soul stripper. She took my heart! Sh ws soul strppr. Sh took my hrt!
BaCon
<lang bacon>text$ = "She was a soul stripper. She took my heart!" PRINT text$ PRINT EXTRACT$(text$, "[aei]", TRUE) </lang>
- Output:
She was a soul stripper. She took my heart! Sh ws soul strppr. Sh took my hrt!
BASIC
<lang qbasic>DECLARE FUNCTION stripchars$(src AS STRING, remove AS STRING)
PRINT stripchars$("She was a soul stripper. She took my heart!", "aei")
FUNCTION stripchars$(src AS STRING, remove AS STRING)
DIM l0 AS LONG, t AS LONG, s AS STRING s = src FOR l0 = 1 TO LEN(remove) DO t = INSTR(s, MID$(remove, l0, 1)) IF t THEN s = LEFT$(s, t - 1) + MID$(s, t + 1) ELSE EXIT DO END IF LOOP NEXT stripchars$ = s
END FUNCTION</lang>
- Output:
Sh ws soul strppr. Sh took my hrt!
IS-BASIC
<lang IS-BASIC>100 PROGRAM "Stripchr.bas" 110 PRINT STRIPCHARS$("She was a soul stripper. She took my heart!","aei") 120 DEF STRIPCHARS$(SRC$,REMOVE$) 130 LET T$="" 140 FOR I=1 TO LEN(SRC$) 150 LET L=0 160 FOR J=1 TO LEN(REMOVE$) 170 IF SRC$(I)=REMOVE$(J) THEN LET L=1:EXIT FOR 180 NEXT 190 IF L=0 THEN LET T$=T$&SRC$(I) 200 NEXT 210 LET STRIPCHARS$=T$ 220 END DEF</lang>
Sinclair ZX81 BASIC
Works with 1k of RAM. Since the ZX81 character set includes neither lower case nor !, the test string is not quite identical to the one suggested in the specification. <lang basic> 10 LET A$="SHE WAS A SOUL STRIPPER. SHE TOOK MY HEART."
20 LET B$="AEI" 30 GOSUB 60 40 PRINT C$ 50 STOP 60 LET C$="" 70 FOR I=1 TO LEN A$ 80 LET J=1 90 IF A$(I)=B$(J) THEN GOTO 130
100 LET J=J+1 110 IF J<=LEN B$ THEN GOTO 90 120 LET C$=C$+A$(I) 130 NEXT I 140 RETURN</lang>
- Output:
SH WS SOUL STRPPR. SH TOOK MY HRT.
See also: Liberty BASIC, PureBasic
BBC BASIC
<lang bbcbasic> PRINT FNstripchars("She was a soul stripper. She took my heart!", "aei")
END DEF FNstripchars(A$, S$) LOCAL I%, C%, C$ FOR I% = 1 TO LEN(S$) C$ = MID$(S$, I%, 1) REPEAT C% = INSTR(A$, C$) IF C% A$ = LEFT$(A$, C%-1) + MID$(A$, C%+1) UNTIL C% = 0 NEXT = A$</lang>
Output:
Sh ws soul strppr. Sh took my hrt!
BQN
The key function here is set difference, which is (¬∘∊/⊣)
.
<lang bqn> StripChars ← (¬∘∊/⊣) ¬∘∊/⊣
"She was a soul stripper. She took my heart!" StripChars "aei"
"Sh ws soul strppr. Sh took my hrt!"</lang>
Bracmat
This solution handles Unicode (utf-8) characters. Optimizations are: (1) the chars
string is hard-coded into the pattern before the pattern is used in the match expression, (2) the output characters are stacked (cheap) rather than appended (expensive). The result string is obtained by stringizing the stack and reversing. To make multibyte characters survive, they are reversed before being put onto the stack. A problem is that this code is negligent of diacritical marks.
<lang bracmat>( ( strip
= string chars s pat . !arg:(?string.?chars) & :?s & ' ( ? ( % : [%( utf$!sjt & ( @($chars:? !sjt ?) | rev$!sjt !s:?s ) & ~ ) ) ? ) : (=?pat) & @(!string:!pat) | rev$(str$!s) )
& out
$ (strip$("Аппетит приходит во время еды".веп)
);</lang>
- Output:
Атит риходит о рмя ды
Burlesque
<lang burlesque> blsq ) "She was a soul stripper. She took my heart!"{"aei"\/~[n!}f[ "Sh ws soul strppr. Sh took my hrt!" </lang>
C
<lang c>#include <string.h>
- include <stdio.h>
- include <stdlib.h>
/* removes all chars from string */
char *strip_chars(const char *string, const char *chars) {
char * newstr = malloc(strlen(string) + 1); int counter = 0;
for ( ; *string; string++) { if (!strchr(chars, *string)) { newstr[ counter ] = *string; ++ counter; } }
newstr[counter] = 0; return newstr;
}
int main(void) {
char *new = strip_chars("She was a soul stripper. She took my heart!", "aei"); printf("%s\n", new);
free(new); return 0;
}</lang>
- Result:
Sh ws soul strppr. Sh took my hrt!
With table lookup
<lang C>#include <stdio.h>
- include <stdlib.h>
- include <string.h>
char *strip(const char * str, const char *pat) { /* char replacement is typically done with lookup tables if * the replacement set can be large: it turns O(m n) into * O(m + n). * If same replacement pattern is going to be applied to many * strings, it's better to build a table beforehand and reuse it. * If charset is big like unicode, table needs to be implemented * more efficiently, say using bit field or hash table -- it * all depends on the application. */ int i = 0, tbl[128] = {0}; while (*pat != '\0') tbl[(int)*(pat++)] = 1;
char *ret = malloc(strlen(str) + 1); do { if (!tbl[(int)*str]) ret[i++] = *str; } while (*(str++) != '\0');
/* assuming realloc is efficient and succeeds; if not, we could * do a two-pass, count first, alloc and strip second */ return realloc(ret, i); }
int main() { char * x = strip("She was a soul stripper. She took my heart!", "aei"); printf(x); free(x);
return 0; }</lang>Output same as above.
C#
<lang csharp>using System;
public static string RemoveCharactersFromString(string testString, string removeChars) {
char[] charAry = removeChars.ToCharArray(); string returnString = testString; foreach (char c in charAry) { while (returnString.IndexOf(c) > -1) { returnString = returnString.Remove(returnString.IndexOf(c), 1); } } return returnString;
}</lang> Usage: <lang C sharp> using System;
class Program {
static void Main(string[] args) { string testString = "She was a soul stripper. She took my heart!"; string removeChars = "aei"; Console.WriteLine(RemoveCharactersFromString(testString, removeChars)); }
} </lang>
- Output:
Sh ws soul strppr. Sh took my hrt!
Using Regex
:
<lang C sharp>
using System;
using System.Text.RegularExpressions;
private static string RegexRemoveCharactersFromString(string testString, string removeChars) {
string pattern = "[" + removeChars + "]"; return Regex.Replace(testString, pattern, "");
}</lang>
Alternative version using System.Span<T>
:
<lang csharp>using System;
public static System.ReadOnlySpan<T> RemoveItems<T>(System.Span<T> toStrip, System.ReadOnlySpan<T> toRemove)
where T : System.IEquatable<T>
{
var toIndex = toStrip.Length;
for (var fromIndex = toIndex - 1; fromIndex >= 0; fromIndex--) if (toStrip[fromIndex] is var item && !toRemove.Contains(item)) toStrip[--toIndex] = item;
return toStrip.Slice(toIndex);
}</lang> Usage: <lang csharp>using System;
class Program {
static void Main(string[] args) { var stripString = "She was a soul stripper. She took my heart!"; var removeString = "aei"; System.Console.WriteLine(RemoveItems<char>(stripString.ToCharArray(), removeString).ToString()); }
}</lang>
- Output:
Sh ws soul strppr. Sh took my hrt!
C++
<lang cpp>#include <algorithm>
- include <iostream>
- include <string>
std::string stripchars(std::string str, const std::string &chars) {
str.erase( std::remove_if(str.begin(), str.end(), [&](char c){ return chars.find(c) != std::string::npos; }), str.end() ); return str;
}
int main() {
std::cout << stripchars("She was a soul stripper. She took my heart!", "aei") << '\n'; return 0;
}</lang>
- Output:
Sh ws soul strppr. Sh took my hrt!
Clojure
<lang Clojure>(defn strip [coll chars]
(apply str (remove #((set chars) %) coll)))
(strip "She was a soul stripper. She took my heart!" "aei")
- => "Sh ws soul strppr. Sh took my hrt!"</lang>
COBOL
This function takes the two arguments as specified in the task. However, the result will be returned in the string that had the characters stripped from it, and the string containing the characters to strip must be null-terminated (otherwise, a table would have to be used instead). <lang cobol> IDENTIFICATION DIVISION.
PROGRAM-ID. Strip-Chars.
DATA DIVISION. WORKING-STORAGE SECTION. 01 Str-Size CONSTANT 128.
LOCAL-STORAGE SECTION. 01 I PIC 999. 01 Str-Pos PIC 999.
01 Offset PIC 999. 01 New-Pos PIC 999.
01 Str-End PIC 999.
LINKAGE SECTION. 01 Str PIC X(Str-Size). 01 Chars-To-Replace PIC X(256).
PROCEDURE DIVISION USING Str BY VALUE Chars-To-Replace. Main. PERFORM VARYING I FROM 1 BY 1 UNTIL Chars-To-Replace (I:1) = X"00"
MOVE ZERO TO Offset
- *> Overwrite the characters to remove by left-shifting
- *> following characters over them.
PERFORM VARYING Str-Pos FROM 1 BY 1 UNTIL Str-Size < Str-Pos IF Str (Str-Pos:1) = Chars-To-Replace (I:1) ADD 1 TO Offset ELSE IF Offset NOT = ZERO COMPUTE New-Pos = Str-Pos - Offset MOVE Str (Str-Pos:1) TO Str (New-Pos:1) END-IF END-PERFORM
- *> Move spaces to characters at the end that have been
- *> shifted over.
COMPUTE Str-End = Str-Size - Offset MOVE SPACES TO Str (Str-End:Offset) END-PERFORM
GOBACK .</lang>
ColdFusion
<lang cfm> <Cfset theString = 'She was a soul stripper. She took my heart!'> <Cfset theStrip = 'aei'> <Cfloop from="1" to="#len(theStrip)#" index="i">
<cfset theString = replace(theString, Mid(theStrip, i, 1), , 'all')>
</Cfloop> <Cfoutput>#theString#</Cfoutput> </lang>
Common Lisp
<lang lisp>(defun strip-chars (str chars)
(remove-if (lambda (ch) (find ch chars)) str))
(strip-chars "She was a soul stripper. She took my heart!" "aei")
- => "Sh ws soul strppr. Sh took my hrt!"
- strip whitespace
(string-trim
'(#\Space #\Newline #\Backspace #\Tab #\Linefeed #\Page #\Return #\Rubout) " A string ")
- => "A string"
</lang>
D
<lang d>import std.stdio, std.string;
void main() {
auto s = "She was a soul stripper. She took my heart!"; auto ss = "Sh ws soul strppr. Sh took my hrt!"; assert(s.removechars("aei") == ss);
}</lang>
Delphi
<lang Delphi>program StripCharacters;
{$APPTYPE CONSOLE}
uses SysUtils;
function StripChars(const aSrc, aCharsToStrip: string): string; var
c: Char;
begin
Result := aSrc; for c in aCharsToStrip do Result := StringReplace(Result, c, , [rfReplaceAll, rfIgnoreCase]);
end;
const
TEST_STRING = 'She was a soul stripper. She took my heart!';
begin
Writeln(TEST_STRING); Writeln(StripChars(TEST_STRING, 'aei'));
end.</lang>
EchoLisp
<lang scheme>
- using regexp /[chars]/g
(define (strip-chars string chars)
(string-replace string (string-append "/[" chars "]/g") ""))
(strip-chars "She was a soul stripper. She took my heart!" "aei")
→ "Sh ws soul strppr. Sh took my hrt!"
</lang>
Elena
ELENA 4.x : <lang elena>import extensions; import extensions'text; import system'routines;
public program() {
var testString := "She was a soul stripper. She took my heart!"; var removeChars := "aei"; console.printLine(testString.filterBy:(ch => removeChars.indexOf(0, ch) == -1).summarize(new StringWriter()))
}</lang>
- Output:
Sh ws soul strppr. Sh took my hrt!
Elixir
The easiest solution would be to use replace from the String module, which takes a Regex. <lang elixir>str = "She was a soul stripper. She took my heart!" String.replace(str, ~r/[aei]/, "")
- => Sh ws soul strppr. Sh took my hrt!</lang>
To get the desired interface, we just have to dynamically construct the Regex: <lang elixir>defmodule RC do
def stripchars(str, chars) do String.replace(str, ~r/[#{chars}]/, "") end
end
str = "She was a soul stripper. She took my heart!" RC.stripchars(str, "aei")
- => Sh ws soul strppr. Sh took my hrt!</lang>
Erlang
The function is created in the shell. A module would be over engineering.
- Output:
4> F = fun(To_stripp, Strip_with) -> lists:filter( fun(C) -> not lists:member(C, Strip_with) end, To_stripp ) end. #Fun<erl_eval.12.111823515> 5> F("She was a soul stripper. She took my heart!", "aei"). "Sh ws soul strppr. Sh took my hrt!"
Euphoria
The includes use Euphoria 4 standard library files.
A sequence called originalString holds the text to be converted.
The puts
function is for console output.
The work of this task is done by the transmute
function; this function takes parameters separated by commas. Here it uses 3 parameters, up to 5, the other two are optional and aren't put in this time.
The transmute
function's usage and examples can be searched for in the official Euphoria 4.0.0+ manual. Euphoria object identifiers (names) are case sensitive but don't need to be in a particular case to be recognized as an object type.
<lang euphoria>include std\sequence.e
include std\console.e
sequence originalString = "She was a soul stripper. She took my heart!" puts(1,"Before : " & originalString & "\n") originalString = transmute(originalString, {{} , "a", "e", "i"}, {{} , "", "", ""}) puts(1,"After : " & originalString & "\n") any_key()</lang>
- Output:
Before : She was a soul stripper. She took my heart! After : Sh ws soul strppr. Sh took my hrt! Press Any Key to continue...
Excel
LAMBDA
Binding the name exceptChars to the following lambda expression in the Name Manager of the Excel WorkBook:
(See LAMBDA: The ultimate Excel worksheet function)
<lang lisp>exceptChars =LAMBDA(excluded,
LAMBDA(src, CONCAT( FILTERP( LAMBDA(c, ISERROR( FIND(c, excluded, 1) ) ) )( CHARSROW(src) ) ) )
)</lang>
and also assuming the following generic bindings in the Name Manager for the WorkBook:
<lang lisp>CHARSROW =LAMBDA(s,
MID(s, SEQUENCE(1, LEN(s), 1, 1), 1 )
)
FILTERP
=LAMBDA(p,
LAMBDA(xs, FILTER(xs, p(xs)) )
)</lang>
- Output:
fx | =exceptChars(A2)(B1) | ||
---|---|---|---|
A | B | ||
1 | She was a soul stripper. She took my heart! | ||
2 | aei | Sh ws soul strppr. Sh took my hrt! |
F#
<lang fsharp>let stripChars text (chars:string) =
Array.fold ( fun (s:string) c -> s.Replace(c.ToString(),"") ) text (chars.ToCharArray())
[<EntryPoint>] let main args =
printfn "%s" (stripChars "She was a soul stripper. She took my heart!" "aei") 0</lang>
Output
Sh ws soul strppr. Sh took my hrt!
Factor
<lang factor>without</lang> Example: <lang factor>USE: sets "She was a soul stripper. She took my heart!" "aei" without print</lang>
- Output:
Sh ws soul strppr. Sh took my hrt!
Forth
Forth is a low level language that is extended to solve your problem. Here we add APPEND-CHAR to the language and use it built the new string character by character in a memory buffer called PAD. PAD is a standard Forth word. SCAN is common in most Forth systems and is typically coded in Forth assembler <lang Forth>: append-char ( char str -- ) dup >r count dup 1+ r> c! + c! ; \ append char to a counted string
- strippers ( -- addr len) s" aeiAEI" ; \ a string literal returns addr and length
- stripchars ( addr1 len1 addr2 len2 -- PAD len )
0 PAD c! \ clear the PAD buffer bounds \ calc loop limits for addr2 DO 2dup I C@ ( -- addr1 len1 addr1 len1 char) scan nip 0= \ scan for char in addr1, test for zero IF \ if stack = true (ie. NOT found) I c@ PAD append-char \ fetch addr2 char, append to PAD THEN \ ...then ... continue the loop LOOP 2drop \ we don't need STRIPPERS now PAD count ; \ return PAD address and length
</lang> Test at the forth console
strippers s" She was a soul stripper. She took my heart!" stripchars cr type Sh ws soul strppr. Sh took my hrt! ok
Shorter version, using ]] [[ macros
This shorter version removes creating a new string and prints the "stripped" string immediately. The macro called '?exit' speeds up the '.stripped' print loop by compiling its code inside the loop. <lang Forth>: ?exit ( c1 c2 -- ) ]] = if drop unloop exit then [[ ; immediate
- .stripped ( a u c -- ) -rot bounds ?do dup i c@ ?exit loop emit ;
- stripchars ( a1 u1 a2 u2 -- ) bounds ?do 2dup i c@ .stripped loop 2drop ;
- "aei" s" aei" ;
\ usage: "aei" s" She was a soul stripper. She took my heart!" stripchars</lang>
Fortran
<lang Fortran>elemental subroutine strip(string,set)
character(len=*), intent(inout) :: string character(len=*), intent(in) :: set integer :: old, new, stride old = 1; new = 1 do stride = scan( string( old : ), set ) if ( stride > 0 ) then string( new : new+stride-2 ) = string( old : old+stride-2 ) old = old+stride new = new+stride-1 else string( new : ) = string( old : ) return end if end do
end subroutine strip</lang>Note: Since strip is an elemental subroutine, it can be called with arrays of strings as well.
FreeBASIC
<lang freebasic>' FB 1.05.0 Win64
Function stripChars(s As Const String, chars As Const String) As String
If s = "" Then Return "" Dim count As Integer = 0 Dim strip(0 To Len(s) - 1) As Boolean For i As Integer = 0 To Len(s) - 1 For j As Integer = 0 To Len(chars) - 1 If s[i] = chars[j] Then count += 1 strip(i) = True Exit For End If Next j Next i
Dim buffer As String = Space(Len(s) - count) count = 0 For i As Integer = 0 To Len(s) - 1 If Not Strip(i) Then buffer[count] = s[i] count += 1 End If Next Return buffer
End Function
Dim s As String = "She was a soul stripper. She took my heart!" Dim chars As String = "aei" Print stripChars(s, chars) Print Print "Press any key to quit" Sleep</lang>
- Output:
Sh ws soul strppr. Sh took my hrt!
Frink
<lang frink>stripchars[str, remove] := {
set = toSet[chars[remove]] return char[remove[char[str], {|c, set| set.contains[c]}, set]]
}
println[stripchars["She was a soul stripper. She took my heart!","aei"]] </lang>
- Output:
Sh ws soul strppr. Sh took my hrt!
Fōrmulæ
Fōrmulæ programs are not textual, visualization/edition of programs is done showing/manipulating structures but not text. Moreover, there can be multiple visual representations of the same program. Even though it is possible to have textual representation —i.e. XML, JSON— they are intended for storage and transfer purposes more than visualization and edition.
Programs in Fōrmulæ are created/edited online in its website, However they run on execution servers. By default remote servers are used, but they are limited in memory and processing power, since they are intended for demonstration and casual use. A local server can be downloaded and installed, it has no limitations (it runs in your own computer). Because of that, example programs can be fully visualized and edited, but some of them will not run if they require a moderate or heavy computation/memory resources, and no local server is being used.
In this page you can see the program(s) related to this task and their results.
Gambas
Click this link to run this code <lang gambas>Public Sub Main()
Print StripChars("She was a soul stripper. She took my heart!", "aei")
End '_____________________________________________________________________ Public Sub StripChars(sText As String, sRemove As String) As String Dim siCount As Short
For siCount = 1 To Len(sRemove)
sText = Replace(sText, Mid(sRemove, siCount, 1), "")
Next
Return sText
End</lang> Output:
Sh ws soul strppr. Sh took my hrt!
Go
<lang go>package main
import (
"fmt" "strings"
)
func stripchars(str, chr string) string {
return strings.Map(func(r rune) rune { if strings.IndexRune(chr, r) < 0 { return r } return -1 }, str)
}
func main() {
fmt.Println(stripchars("She was a soul stripper. She took my heart!", "aei"))
}</lang>
- Output:
Sh ws soul strppr. Sh took my hrt!
Groovy
Solution: <lang groovy>def stripChars = { string, stripChars ->
def list = string as List list.removeAll(stripChars as List) list.join()
}</lang> Test: <lang groovy>println (stripChars('She was a soul stripper. She took my heart!', 'aei'))</lang>
- Output:
Sh ws soul strppr. Sh took my hrt!
Haskell
I decided to make the string the second argument and the characters the first argument, because it is more likely for someone to partially apply the characters to be stripped (making a function that strips certain characters), than the string. <lang haskell>stripChars :: String -> String -> String stripChars = filter . flip notElem</lang>
- Testing in GHCI:
> stripChars "aei" "She was a soul stripper. She took my heart!" "Sh ws soul strppr. Sh took my hrt!"
Icon and Unicon
The following works in both languages: <lang unicon>procedure main(A)
cs := \A[1] | 'aei' # argument is set of characters to strip every write(stripChars(!&input, cs)) # strip all input lines
end
procedure stripChars(s,cs)
ns := "" s ? while ns ||:= (not pos(0), tab(upto(cs)|0)) do tab(many(cs)) return ns
end</lang>
- Sample runs:
->strip She was a soul stripper. She took my heart! Sh ws soul strppr. Sh took my hrt! Aardvarks are ant eaters. Ardvrks r nt trs. ->strip AEIOUaeiou Aardvarks are ant eaters. rdvrks r nt trs. ->
J
Solution:
The dyadic primitive -.
(Less) is probably the simplest way to solve this task.
- Example Usage:
<lang j> 'She was a soul stripper. She took my heart!' -. 'aei' Sh ws soul strppr. Sh took my hrt!</lang>
Java
<lang Java>class StripChars {
public static String stripChars(String inString, String toStrip) { return inString.replaceAll("[" + toStrip + "]", ""); }
public static void main(String[] args) { String sentence = "She was a soul stripper. She took my heart!"; String chars = "aei"; System.out.println("sentence: " + sentence); System.out.println("to strip: " + chars); System.out.println("stripped: " + stripChars(sentence, chars)); }
}</lang>
- Output:
sentence: She was a soul stripper. She took my heart! to strip: aei stripped: Sh ws soul strppr. Sh took my hrt!
JavaScript
ES5
<lang JavaScript>function stripchars(string, chars) {
return string.replace(RegExp('['+chars+']','g'), );
}</lang>
ES6
Reversing the order of the arguments, to simplify any currying:
<lang JavaScript>(() => {
'use strict';
// stripChars :: String -> String -> String const stripChars = (strNeedles, strHayStack) => strHayStack.replace(RegExp(`[${strNeedles}]`, 'g'), );
// GENERIC FUNCTION
// curry :: ((a, b) -> c) -> a -> b -> c const curry = f => a => b => f(a, b);
// TEST FUNCTION
const noAEI = curry(stripChars)('aeiAEI');
// TEST return noAEI('She was a soul stripper. She took my heart!');
// 'Sh ws soul strppr. Sh took my hrt!'
})();</lang>
- Output:
'Sh ws soul strppr. Sh took my hrt!'
Alternatively, we could also do this without a regex:
<lang JavaScript>(() => {
'use strict';
// stripChars :: String -> String -> String const stripChars = (strNeedles, strHayStack) => strHayStack.split() .filter(x => !elem(x, strNeedles)) .join();
// GENERIC FUNCTIONS
// elem :: Eq a => a -> [a] -> Bool const elem = (x, xs) => xs.indexOf(x) !== -1;
// curry :: ((a, b) -> c) -> a -> b -> c const curry = f => a => b => f(a, b);
// TEST FUNCTION
const noAEI = curry(stripChars)('aeiAEI');
// TEST return noAEI('She was a soul stripper. She took my heart!');
// 'Sh ws soul strppr. Sh took my hrt!'
})();</lang>
- Output:
'Sh ws soul strppr. Sh took my hrt!'
jq
<lang jq>def stripchars(string; banish):
(string | explode) - (banish | explode) | implode;</lang>
Note: In jq, it would be more idiomatic to define the function as a filter: <lang jq>def stripchars(banish):
explode - (banish | explode) | implode;</lang>
In this case, we would write:
"She was a soul stripper. She took my heart!" | stripchars("aei")
Julia
<lang julia>stripChar = (s, r) -> replace(s, Regex("[$r]") => "")</lang>
- Output:
> stripChar("She was a soul stripper. She took my heart!", "aei") Sh ws soul strppr. Sh took my hrt!
Kotlin
<lang scala>// version 1.0.6
fun stripChars(s: String, r: String) = s.replace(Regex("[$r]"), "")
fun main(args: Array<String>) {
println(stripChars("She was a soul stripper. She took my heart!", "aei"))
}</lang>
- Output:
Sh ws soul strppr. Sh took my hrt!
Lambdatalk
Text substitutions are easy to process directly using regular expressions : <lang scheme> {S.replace (a|e|i)
by // nothing in She was a soul stripper. She took my heart!}
-> Sh ws soul strppr. Sh took my hrt! </lang> and can be wrapped inside a fuction: <lang scheme> {def word2rex
{def word2rex.r {lambda {:w} {if {W.empty? {W.rest :w}} then {W.first :w}) else {W.first :w}|{word2rex.r {W.rest :w}}}}} {lambda {:w :s} {S.replace ({word2rex.r :w} by in :s}}}
-> word2rex
{word2rex aei
She was a soul stripper. She took my heart!}
-> Sh ws soul strppr. Sh took my hrt! </lang>
Lasso
<lang Lasso>define stripper(in::string,destroy::string) => { with toremove in #destroy->values do => { #in->replace(#toremove,) } return #in } stripper('She was a soul stripper. She took my heart!','aei')</lang>
- Output:
Sh ws soul strppr. Sh took my hrt!
Liberty BASIC
<lang lb>Print stripchars$("She was a soul stripper. She took my heart!", "aei", 1) End
Function stripchars$(strip$, chars$, num)
For i = 1 To Len(strip$) If Mid$(strip$, i, 1) <> Mid$(chars$, num, 1) Then stripchars$ = (stripchars$ + Mid$(strip$, i, 1)) End If Next i If (num <= Len(chars$)) Then stripchars$ = stripchars$(stripchars$, chars$, (num + 1))
End Function</lang>
LiveCode
<lang LiveCode>function stripChars str charlist
local strstripped put str into strstripped repeat for each char c in charlist replace c with empty in strstripped end repeat return strstripped
end stripChars</lang> Test<lang LiveCode>command teststripchars
put stripchars("She was a soul stripper. She took my heart!","aei")
end teststripchars</lang>Output
Sh ws soul strppr. Sh took my hrt!
Logo
<lang logo>to strip :string :chars
output filter [not substringp ? :chars] :string
end
print strip "She\ was\ a\ soul\ stripper.\ She\ took\ my\ heart! "aei
bye</lang>
- Output:
Sh ws soul strppr. Sh took my hrt!
Lua
<lang lua> function stripchars(str, chrs)
local s = str:gsub("["..chrs:gsub("%W","%%%1").."]", ) return s
end
print( stripchars( "She was a soul stripper. She took my heart!", "aei" ) ) --> Sh ws soul strppr. Sh took my hrt! print( stripchars( "She was a soul stripper. She took my heart!", "a-z" ) ) --> She ws soul stripper. She took my hert! </lang>
Maple
<lang Maple>with(StringTools):
Remove(c->Has("aei",c), "She was a soul stripper. She took my heart!");</lang> Output:
"Sh ws soul strppr. Sh took my hrt!"
Mathematica/Wolfram Language
<lang Mathematica>stripchars[a_,b_]:=StringReplace[a,(#->"")&/@Characters[b]] stripchars["She was a soul stripper. She took my heart!","aei"] ->Sh ws soul strppr. Sh took my hrt!</lang>
MATLAB / Octave
<lang MATLAB>function str = stripchars(str, charlist)
% MATLAB after 2016b: str = erase(str, charlist); str(ismember(str, charlist)) = ;</lang>
- Output:
>> stripchars('She was a soul stripper. She took my heart!','aei') ans = Sh ws soul strppr. Sh took my hrt!
Nanoquery
<lang Nanoquery>def stripchars(string, chars) for char in chars string = string.replace(char, "") end return string end</lang>
Nemerle
<lang Nemerle>StripChars( text : string, remove : string ) : string {
def chuck = Explode(remove); Concat( "", Split(text, chuck))
}</lang>
NetRexx
<lang NetRexx>/* NetRexx */
options replace format comments java crossref savelog symbols
say stripchars("She was a soul stripper. She took my heart!", "aei")
return
method stripchars(haystack, chs) public static
loop c_ = 1 to chs.length needle = chs.substr(c_, 1) haystack = haystack.changestr(needle, ) end c_
return haystack</lang>
NewLISP
<lang NewLISP>(let (sentence "She was a soul stripper. She took my heart!")
(replace "[aei]" sentence "" 0))</lang>
Nim
<lang nim>import strutils
echo "She was a soul stripper. She took my heart!".split({'a','e','i'}).join()
echo "She was a soul stripper. She took my heart!".multiReplace(
("a", ""), ("e", ""), ("i", "")
)
- And another way using module "sequtils".
import sequtils echo "She was a soul stripper. She took my heart!".filterIt(it notin "aei").join()
</lang>
- Output:
Sh ws soul strppr. Sh took my hrt! Sh ws soul strppr. Sh took my hrt! Sh ws soul strppr. Sh took my hrt!
Objective-C
<lang objc>@interface NSString (StripCharacters) - (NSString *) stripCharactersInSet: (NSCharacterSet *) chars; @end
@implementation NSString (StripCharacters) - (NSString *) stripCharactersInSet: (NSCharacterSet *) chars {
return [[self componentsSeparatedByCharactersInSet:chars] componentsJoinedByString:@""];
} @end</lang>
- To use:
<lang objc> NSString *aString = @"She was a soul stripper. She took my heart!";
NSCharacterSet* chars = [NSCharacterSet characterSetWithCharactersInString:@"aei"];
// Display the NSString. NSLog(@"%@", [aString stripCharactersInSet:chars]);</lang>
OCaml
<lang ocaml>let stripchars s cs =
let len = String.length s in let res = Bytes.create len in let rec aux i j = if i >= len then Bytes.to_string (Bytes.sub res 0 j) else if String.contains cs s.[i] then aux (succ i) (j) else begin Bytes.set res j s.[i]; aux (succ i) (succ j) end in aux 0 0</lang>
- Testing in the toplevel:
# stripchars "She was a soul stripper. She took my heart!" "aei" ;; - : string = "Sh ws soul strppr. Sh took my hrt!"
Oforth
<lang Oforth>String method: stripChars(str) #[ str include not ] self filter ;
"She was a soul stripper. She took my heart!" stripChars("aei") println</lang>
- Output:
Sh ws soul strppr. Sh took my hrt!
PARI/GP
GP should not be used for string manipulation. A good solution to this problem would probably involve system("perl -e
...
<lang parigp>stripchars(s, bad)={
bad=Set(Vec(Vecsmall(bad))); s=Vecsmall(s); my(v=[]); for(i=1,#s,if(!setsearch(bad,s[i]),v=concat(v,s[i]))); Strchr(v)
}; stripchars("She was a soul stripper. She took my heart!","aei")</lang>
Pascal
See Delphi
Perl
Note: this example uses a regular expression character class. Certain characters, like hyphens and brackets, may need to be escaped. <lang perl>sub stripchars {
my ($s, $chars) = @_; $s =~ s/[$chars]//g; return $s;
}
print stripchars("She was a soul stripper. She took my heart!", "aei"), "\n";</lang>
- Output:
Sh ws soul strppr. Sh took my hrt!
Another good option for stripping characters is to use the tr///
operator. This option is very efficient when the set of characters to strip is fixed at compile time, because tr///
is specifically designed for transforming and deleting characters. Note that hyphens also have special meaning in this case.
<lang perl>$str =~ tr/aei//d;</lang>
Since the characters used for tr///
must be fixed at compile time, unfortunately, it requires the use of an eval
to do this generally for any set of characters provided at runtime:
<lang perl>sub stripchars {
my ($s, $chars) = @_; eval("\$s =~ tr/$chars//d;"); return $s;
}</lang>
Phix
?filter("She was a soul stripper. She took my heart!","out","aei")
- Output:
"Sh ws soul strppr. Sh took my hrt!"
PHP
<lang php><?php function stripchars($s, $chars) {
return str_replace(str_split($chars), "", $s);
}
echo stripchars("She was a soul stripper. She took my heart!", "aei"), "\n"; ?></lang>
- Output:
Sh ws soul strppr. Sh took my hrt!
PicoLisp
<lang PicoLisp>(de strDiff (Str1 Str2)
(pack (diff (chop Str1) (chop Str2))) )</lang>
- Output:
: (strDiff "She was a soul stripper. She took my heart!" "aei") -> "Sh ws soul strppr. Sh took my hrt!"
PL/I
<lang PL/I>strip_chars: procedure (text, chars) returns (character (100) varying);
declare text character (*) varying, chars character (*) varying; declare out_text character (100); declare ch character (1); declare (i, j) fixed binary;
j = 0; do i = 1 to length(text); ch = substr(text, i, 1); if index(chars, ch) = 0 then do; j = j + 1; substr(out_text, j, 1) = ch; end; end; return (substr(out_text, 1, j) );
end strip_chars;</lang>
Powershell
Powershell have replace operator that by will replace a regex pattern with a given string:
<lang Powershell>'She was a soul stripper. She took my heart!' -replace '[aei]', Sh ws soul strppr. Sh took my hrt! </lang>
Prolog
Works with SWI-Prolog and module lambda.pl written by Ulrich Neumerkel found there http://www.complang.tuwien.ac.at/ulrich/Prolog-inedit/lambda.pl . <lang Prolog>:- use_module(library(lambda)).
stripchars(String, Exclude, Result) :- exclude(\X^(member(X, Exclude)), String, Result1), string_to_list(Result, Result1). </lang>
- Output:
?- stripchars("She was a soul stripper. She took my heart!","aei", R). R = "Sh ws soul strppr. Sh took my hrt!".
alternative version using DCG strings
<lang prolog>
- - system:set_prolog_flag(double_quotes,chars) .
%! strip_chars(SOURCEz0,SETz0,TARGETz) % % `TARGETz` is `SOURCEz0` but with any of the characters in `SETz0` removed .
strip_chars(SOURCEz0,SETz0,TARGETz)
- -
prolog:phrase(strip_chars(SOURCEz0,SETz0),TARGETz) .
strip_chars([],_SETz0_) --> ! .
strip_chars([SOURCE0|SOURCEz0],SETz0) --> { \+ \+ lists:member(SOURCE0,SETz0) } , ! , strip_chars(SOURCEz0,SETz0) .
strip_chars([SOURCE0|SOURCEz0],SETz0) --> [SOURCE0] , strip_chars(SOURCEz0,SETz0) . </lang>
- Output:
?- strip_chars("She was a soul stripper. She took my heart!","aei",Rs) . Rs = ['S', h, ' ', w, s, ' ', ' ', s, o, u, l, ' ', s, t, r, p, p, r, '.', ' ', 'S', h, ' ', t, o, o, k, ' ', m, y, ' ', h, r, t, !].
PureBasic
PureBasic uses a single (for ASCII) or a two-byte (for Unicode) null to signal the end of a string. Nulls are thus excluded from the allowable characters to strip as they can't be included in a PureBasic string. <lang PureBasic>Procedure.s stripChars(source.s, charsToStrip.s)
Protected i, *ptrChar.Character, length = Len(source), result.s *ptrChar = @source For i = 1 To length If Not FindString(charsToStrip, Chr(*ptrChar\c)) result + Chr(*ptrChar\c) EndIf *ptrChar + SizeOf(Character) Next ProcedureReturn result
EndProcedure
If OpenConsole()
PrintN(stripChars("She was a soul stripper. She took my heart!", "aei")) Print(#CRLF$ + #CRLF$ + "Press ENTER to exit"): Input() CloseConsole()
EndIf</lang>
- Output:
Sh ws soul strppr. Sh took my hrt!
Python
Not using regular expressions
<lang python>>>> def stripchars(s, chars): ... return s.translate(None, chars) ... >>> stripchars("She was a soul stripper. She took my heart!", "aei") 'Sh ws soul strppr. Sh took my hrt!'</lang>
<lang python>>>> import string >>> def stripchars(s, chars): ... return s.translate(string.maketrans("", ""), chars) ... >>> stripchars("She was a soul stripper. She took my heart!", "aei") 'Sh ws soul strppr. Sh took my hrt!'</lang> Implemented manually: <lang python>>>> def stripchars(s, chars): ... return "".join(c for c in s if c not in chars) ... >>> stripchars("She was a soul stripper. She took my heart!", "aei") 'Sh ws soul strppr. Sh took my hrt!'</lang>
Using regular expressions
<lang python>>>> import re >>> def stripchars(s, chars): return re.sub('[%s]+' % re.escape(chars), , s)
>>> stripchars("She was a soul stripper. She took my heart!", "aei") 'Sh ws soul strppr. Sh took my hrt!' >>> </lang>
Quackery
<lang Quackery> [ $ "" swap witheach [ upper join ] ] is upper$ ( $ --> $ )
[ $ "" swap witheach [ lower join ] ] is lower$ ( $ --> $ ) [ 0 swap witheach [ bit | ] ] is ->set ( [ --> s ) [ bit & not ] is !in ( s c --> b ) [ $ "" unrot upper$ dup lower$ join ( omit this line for case-sensitive ) ->set swap witheach [ 2dup !in iff [ swap dip join ] else drop ] drop ] is strip$ ( $ $ --> $ )
$ "One is never alone with a rubber duck." dup echo$ cr $ "EIU" strip$ echo$ cr</lang>
- Output:
One is never alone with a rubber duck. On s nvr alon wth a rbbr dck.
Racket
<lang Racket>
- lang racket
- Using list operations
(define (stripchars1 text chars)
(list->string (remove* (string->list chars) (string->list text))))
- Using a regexp
- => will be broken if chars have "-" or "]" or "\\"
(define (stripchars2 text chars)
(regexp-replace* (~a "[" chars "]+") text ""))
</lang>
Raku
(formerly Perl 6) <lang perl6>sub strip_chars ( $s, $chars ) {
return $s.trans( $chars.comb X=> );
}
say strip_chars( 'She was a soul stripper. She took my heart!', 'aei' );</lang>
- Output:
Sh ws soul strppr. Sh took my hrt!
Red
<lang Red> stripchars: func [str chars] [trim/with str chars] stripchars "She was a soul stripper. She took my heart!" "aei"</lang>
REXX
version 1
In the REXX language, strip usually means to remove leading and/or trailing characters from a string (most often, blanks). <lang rexx>/*REXX program removes a list of characters from a string (the haystack). */ say stripChars('She was a soul stripper. She took my heart!', "iea") /*elide: iea */ exit /*stick a fork in it, we're all done. */ /*──────────────────────────────────────────────────────────────────────────────────────*/ stripChars: procedure; parse arg haystack, remove
do j=1 for length(remove) haystack=changestr( substr( remove, j, 1), haystack, ) end /*j*/ return haystack</lang>
Some older REXXes don't have a changestr BIF, so one is included here ───► CHANGESTR.REX.
- output :
Sh ws soul strppr. Sh took my hrt!
version 2
Using recursion: <lang rexx>/* REXX */ say StripChars('She was a soul stripper. She took my heart!','iea') exit 0
StripChars: procedure parse arg strng,remove removepos=Verify(strng,remove,'MATCH') if removepos=0 then return strng parse value strng with strng =(removepos) +1 rest return strng || StripChars(rest,remove)</lang>
- Output:
Sh ws soul strppr. Sh took my hart!rt!
version 3
This works on all Rexxes.
(Except for R4 and ROO at the least, there may be others.)
<lang rexx>
/* REXX ***************************************************************
- If source and stripchars don't contain a hex 00 character, this works
- 06.07.2012 Walter Pachl
- 19.06.2013 -"- space(result,0) -> space(result,0,' ')
- space(result,0) removes WHITESPACE not only blanks
- /
Say 'Sh ws soul strppr. Sh took my hrt! -- expected' Say stripchars("She was a soul stripper. She took my heart!","aei") Exit stripchars: Parse Arg string,stripchars result=translate(string,'00'x,' ') /* turn blanks into '00'x */ result=translate(result,' ',stripchars) /* turn stripchars into ' ' */ result=space(result,0,' ') /* remove all blanks */ Return translate(result,' ','00'x) /* '00'x back to blanks */ </lang>
version 4
Another neat (?) one No x00 restriction and no changestr
<lang rexx> stripchars: Procedure
Parse Arg i,s /* get input and chars to be removed */ o= /* initialize result */ Do While i\== /* loop through input */ Parse Var i c +1 i /* get one character */ If pos(c,s)=0 Then /* it's not to be removed */ o=o||c /* append it to the result */ End Return o /* return the result */
</lang>
Ring
<lang ring> aList = "She was a soul stripper. She took my heart!" bList = "aei" see aList + nl see stripChars(aList,bList)
func stripChars cList, dList
for n = 1 to len(dList) cList = substr(cList,dList[n],"") + nl next return cList
</lang>
Ruby
<lang ruby>"She was a soul stripper. She took my heart!".delete("aei") # => "Sh ws soul strppr. Sh took my hrt!"</lang>
Rust
Naive Implementation: <lang rust> fn strip_characters(original : &str, to_strip : &str) -> String {
let mut result = String::new(); for c in original.chars() { if !to_strip.contains(c) { result.push(c); } } result
} </lang>
Functional Implementation: <lang rust> fn strip_characters(original : &str, to_strip : &str) -> String {
original.chars().filter(|&c| !to_strip.contains(c)).collect()
} </lang>
Either can be executed thusly: <lang rust> fn main() {
println!("{}", strip_characters("She was a soul stripper. She took my heart!", "aei"));
} </lang>
SAS
This code will write the resulting string to the log: <lang SAS>%let string=She was a soul stripper. She took my heart!; %let chars=aei; %let stripped=%sysfunc(compress("&string","&chars")); %put &stripped;</lang>
Log: <lang SAS>Sh ws soul strppr. Sh took my hrt!</lang>
Scala
<lang scala>def stripChars(s:String, ch:String)= s filterNot (ch contains _)
stripChars("She was a soul stripper. She took my heart!", "aei") // => Sh ws soul strppr. Sh took my hrt!</lang>
Scheme
Two approaches are given here. The first is in plain Scheme, and implements a loop to remove the characters. The second uses the SRFI libraries to create a character set and delete those characters from the string.
<lang scheme> (import (scheme base)
(scheme write) (only (srfi 13) string-delete) (only (srfi 14) ->char-set))
- implementation in plain Scheme
(define (strip-chars str chars)
(let ((char-list (string->list chars))) (define (do-strip str-list result) (cond ((null? str-list) (reverse result)) ((member (car str-list) char-list char=?) (do-strip (cdr str-list) result)) (else (do-strip (cdr str-list) (cons (car str-list) result))))) (list->string (do-strip (string->list str) '()))))
(display (strip-chars "She was a soul stripper. She took my heart!" "aei")) (newline)
- using functions in SRFI 13 and SRFI 14
(define (strip-chars2 str chars)
(string-delete (->char-set chars) str))
(display (strip-chars2 "She was a soul stripper. She took my heart!" "aei")) (newline) </lang>
- Output:
Sh ws soul strppr. Sh took my hrt! Sh ws soul strppr. Sh took my hrt!
ScriptBasic
<lang scriptbasic> str1 = "She was a soul stripper. She took my heart!" rmv = "aei" FOR i = 1 TO LEN(rmv)
str1 = REPLACE(str1, MID(rmv, i, 1), "")
NEXT PRINT str1,"\n" </lang>
Sed
Using echo and piping it through a sed filter: <lang bash>#!/bin/bash
strip_char() {
echo "$1" | sed "s/[$2]//g"
}</lang>
Seed7
<lang seed7>$ include "seed7_05.s7i";
const func string: stripchars (in string: mainStri, in string: charList) is func
result var string: strippedStri is ""; local var char: ch is ' '; begin strippedStri := mainStri; for ch range charList do strippedStri := replace(strippedStri, str(ch), ""); end for; end func;
const proc: main is func
begin writeln(stripchars("She was a soul stripper. She took my heart!", "aei")); end func;</lang>
- Output:
Sh ws soul strppr. Sh took my hrt!
Sidef
<lang ruby>func stripchars(str, char_list) {
str.tr(char_list, "", "d");
}</lang>
or: <lang ruby>func stripchars(str, char_list) {
str.chars.grep {|c| !char_list.contains(c)}.join;
}</lang>
Calling the function: <lang ruby>say stripchars("She was a soul stripper. She took my heart!", "aei");</lang>
- Output:
Sh ws soul strppr. Sh took my hrt!
Smalltalk
<lang smalltalk>| stripChars | stripChars := [ :string :chars | string reject: [ :c | chars includes: c ] ]. stripChars value: 'She was a soul stripper. She took my heart!' value: 'aei'.
"'Sh ws soul strppr. Sh took my hrt!'"</lang>
SNOBOL4
Note: "strip" is a function, its argument, the label of its first executed line, and its returned value.
<lang SNOBOL4> DEFINE("strip(strip,c)") :(strip_end) strip strip ANY(c) = :S(strip)F(RETURN) strip_end
chars = HOST(2, HOST(3)) ;* Get command line argument chars = IDENT(chars) "aei"
again line = INPUT :F(END)
OUTPUT = strip(line, chars) :(again)
END</lang>
- Output:
snobol4 strip.sno aei She was a soul stripper. She took my heart. Sh ws soul strppr. Sh took my hrt.
Standard ML
<lang sml>fun stripchars (string, chars) = let
fun aux c = if String.isSubstring (str c) chars then "" else str c
in
String.translate aux string
end</lang>
- Testing:
- stripchars ("She was a soul stripper. She took my heart!", "aei") ; val it = "Sh ws soul strppr. Sh took my hrt!" : string
Alternately: <lang sml>fun stripchars (string, chars) =
String.concat (String.tokens (fn c => String.isSubstring (str c) chars) string)</lang>
- Testing:
- stripchars ("She was a soul stripper. She took my heart!", "aei") ; val it = "Sh ws soul strppr. Sh took my hrt!" : string
Swift
<lang swift>extension String {
func stripCharactersInSet(chars: [Character]) -> String { return String(seq: filter(self) {find(chars, $0) == nil}) }
}
let aString = "She was a soul stripper. She took my heart!" let chars: [Character] = ["a", "e", "i"]
println(aString.stripCharactersInSet(chars))</lang>
- Output:
Sh ws soul strppr. Sh took my hrt!
Tcl
<lang tcl>proc stripchars {str chars} {
foreach c [split $chars ""] {set str [string map [list $c ""] $str]} return $str
}
set s "She was a soul stripper. She took my heart!" puts [stripchars $s "aei"]</lang>
TorqueScript
This uses a default function.
$string = "She was a soul stripper. She took my heart!"; $chars = "aei"; $newString = stripChars($string, $chars); echo($string); echo($newString);
Output:
She was a soul stripper. She took my heart! Sh ws soul strppr. Sh took my hrt!
TUSCRIPT
<lang tuscript> $$ MODE TUSCRIPT,{} string="She was a soul stripper. She took my heart!" stringstrip=EXCHANGE (string,"_[aei]__") print string print stringstrip </lang> Output:
She was a soul stripper. She took my heart! Sh ws soul strppr. Sh took my hrt!
TXR
This solution builds up a regular expression in a hygienic way from the set of characters given as a string.
The string is broken into a list, which is used to construct a regex abstract syntax tree for a character set match, using a Lisp quasiquote. This is fed to the regex compiler, which produces an executable machine that is then used with regsub
.
On the practical side, some basic structural pattern matching is used to process command line argument list.
Since the partial argument list (the arguments belonging to the TXR script) is a suffix of the full argument list (the complete arguments which include the invoking command and the script name), the classic Lisp function ldiff
comes in handy in obtaining just the prefix, for printing the usage:
<lang txrlisp>(defun strip-chars (str set)
(let* ((regex-ast ^(set ,*(list-str set))) (regex-obj (regex-compile regex-ast))) (regsub regex-obj "" str)))
(defun usage ()
(pprinl `usage: @{(ldiff *full-args* *args*) " "} <string> <set>`) (exit 1))
(tree-case *args*
((str set extra) (usage)) ((str set . junk) (pprinl (strip-chars str set))) (else (usage)))</lang>
- Output:
$ txr strip-chars-2.tl usage: txr strip-chars-2.tl <string> <set> $ txr strip-chars-2.tl "she was a soul stripper. she stole my heart." "aei" sh ws soul strppr. sh stol my hrt.
Now here is a rewrite of strip-chars
which just uses classic Lisp that has been generalized to work over strings, plus the do
syntax (a sibling of the op
operator) that provides syntactic sugar for a lambda function whose body is an operator or macro form.
<lang txr>(defun strip-chars (str set)
(mappend (do if (memq @1 set) (list @1)) str))</lang>
(do if (memq @1 set) (list @1))
is just (lambda (item) (if (memq item set) (list item)))
.
mappend
happily maps over strings and since the leftmost input sequence is a string, and the return values of the lambda are sequence of characters, mappend
produces a string.
UNIX Shell
One would normally do this using the standard tr(1) command:
<lang bash>strip_chars() {
echo "$1" | tr -d "$2"
}</lang> But it can also be accomplished with bash's built-in parameter expansions:
<lang bash>function strip_chars {
echo "${1//[$2]}"
}</lang> Test code: <lang bash> strip_chars "She was a soul stripper. She took my heart!" aei</lang>
- Output:
Sh ws soul strppr. Sh took my hrt!
Ursala
Normally there's no need to define this operation because it's built in. <lang Ursala>strip = ~&j
- cast %s
test = strip('she was a soul stripper. she took my heart','aei')</lang>
- Output:
'sh ws soul strppr. sh took my hrt'
VBA
Pass the optional bSpace parameter True to replace stripped characters with spaces, otherwise replaced with null.
<lang vb>Function StripChars(stString As String, stStripChars As String, Optional bSpace As Boolean) Dim i As Integer, stReplace As String
If bSpace = True Then stReplace = " " Else stReplace = "" End If For i = 1 To Len(stStripChars) stString = Replace(stString, Mid(stStripChars, i, 1), stReplace) Next i StripChars = stString
End Function</lang>
- Output:
' with bSpace = True: Sh w s soul str pp r. Sh took my h rt! 'with bSpace = False / omitted: Sh ws soul strppr. Sh took my hrt!
VBScript
<lang vb> Function stripchars(s1,s2) For i = 1 To Len(s1) If InStr(s2,Mid(s1,i,1)) Then s1 = Replace(s1,Mid(s1,i,1),"") End If Next stripchars = s1 End Function
WScript.StdOut.Write stripchars("She was a soul stripper. She took my heart!","aei") </lang>
- Output:
Sh ws soul strppr. Sh took my hrt!
Wren
<lang javascript>var stripChars = Fn.new { |s, t|
return s.map { |c| return (t.indexOf(c) == -1) ? c : "" }.join()
}
System.print(stripChars.call("She was a soul stripper. She took my heart!", "aei"))</lang>
- Output:
Sh ws soul strppr. Sh took my hrt!
XPL0
<lang XPL0>string 0; \make strings zero-terminated
func In(Char, Chars); \Is Char in the string Chars? char Char, Chars; int I; for I:= 0 to -1>>1 do \for many times...
[if Chars(I) = 0 then return false; if Chars(I) = Char then return true; ];
func StripChars(String, Chars); \Remove Chars from String char String, Chars; int I, O; [O:= 0; for I:= 0 to -1>>1 do \for many times...
[if not In(String(I), Chars) then [String(O):= String(I); O:= O+1]; if String(I)=0 then return String; ];
];
Text(0, StripChars("She was a soul stripper. She took my heart!", "aei"))</lang>
Output:
Sh ws soul strppr. Sh took my hrt!
zkl
<lang zkl>println("She was a soul stripper. She took my heart!" - "aei") //-->Sh ws soul strppr. Sh took my hrt!</lang>
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