User input/Text

User input/Text
You are encouraged to solve this task according to the task description, using any language you may know.

User input/Text is part of Short Circuit's Console Program Basics selection.

Task

Input a string and the integer   75000   from the text console.

See also: User input/Graphical

11l

V string = input(‘Input a string: ’)
V number = Float(input(‘Input a number: ’))

AArch64 Assembly

Works with: as version Raspberry Pi 3B/4 version Buster 64 bits

//Consts
.equ BUFFERSIZE,   100
.equ STDIN,  0                // linux input console
.equ STDOUT, 1                // linux output console
.equ READ,   63 
.equ WRITE,  64 
.equ EXIT,   93 

.data
enterText:		.asciz "Enter text: "
carriageReturn:  	.asciz "\n"

//Read Buffer
.bss 
buffer:    .skip    BUFFERSIZE

.text
.global _start 

quadEnterText:        	.quad  enterText
quadBuffer:          	.quad  buffer
quadCarriageReturn:	.quad  carriageReturn

writeMessage:
    mov x2,0                   // reset size counter to 0

checkSize:                     // get size of input
    ldrb w1,[x0,x2]            // load char with offset of x2
    add x2,x2,#1               // add 1 char read legnth
    cbz w1,output              // if char found
    b checkSize                // loop

output:
    mov x1,x0                  // move string address into system call func parm
    mov x0,STDOUT              
    mov x8,WRITE               
    svc 0                      // trigger system write
    ret                        


_start:
    //Output enter text
    ldr x0,quadEnterText	// load enter message
    bl writeMessage		// output enter message

    //Read User Input
    mov x0,STDIN           	// linux input console
    ldr x1,quadBuffer      	// load buffer address 
    mov x2,BUFFERSIZE      	// load buffer size 
    mov x8,READ            	// request to read data
    svc 0                  	// trigger system read input

    //Output User Message
    mov x2, #0			// prep end of string
    ldr x1,quadBuffer      	// load buffer address 
    strb w2,[x1, x0]        	// store x2 0 byte at the end of input string, offset x0
    ldr x0,quadBuffer      	// load buffer address 
    bl writeMessage
    
    //Output newline
    ldr x0,quadCarriageReturn   
    bl writeMessage

    //End Program
    mov x0, #0             	// return code
    mov x8, #EXIT          	// request to exit program
    svc 0                 	// trigger end of program

Action!

Library: Action! Tool Kit

Library: Action! Real Math

INCLUDE "H6:REALMATH.ACT"

PROC Main()
  CHAR ARRAY sUser(255)
  REAL r75000,rUser

  Put(125) PutE() ;clear the screen
  ValR("75000",r75000)

  Print("Please enter a text: ")
  InputS(sUser)

  DO
    Print("Please enter number ")
    PrintR(r75000) Print(": ")
    InputR(rUser)
  UNTIL RealEqual(rUser,r75000)
  OD

  PutE()
  Print("Text: ") PrintE(sUser)
  Print("Number: ") PrintRE(rUser)
RETURN

Output:

Screenshot from Atari 8-bit computer

Please enter a text: Atari 130XE
Please enter number 75000: 123
Please enter number 75000: 76000
Please enter number 75000: 75000

Text: Atari 130XE
Number: 75000

Ada

Works with: GCC version 4.1.2

function Get_String return String is
  Line : String (1 .. 1_000);
  Last : Natural;
begin
  Get_Line (Line, Last);
  return Line (1 .. Last);
end Get_String;

function Get_Integer return Integer is
  S : constant String := Get_String;
begin
  return Integer'Value (S);
  --  may raise exception Constraint_Error if value entered is not a well-formed integer
end Get_Integer;

The functions above may be called as shown below

My_String  : String  := Get_String;
My_Integer : Integer := Get_Integer;

Another:

with Ada.Text_IO, Ada.Integer_Text_IO;

procedure User_Input is
   I : Integer;
begin
   Ada.Text_IO.Put ("Enter a string: ");
   declare
      S : String := Ada.Text_IO.Get_Line;
   begin
      Ada.Text_IO.Put_Line (S);
   end;
   Ada.Text_IO.Put ("Enter an integer: ");
   Ada.Integer_Text_IO.Get(I);
   Ada.Text_IO.Put_Line (Integer'Image(I));
end User_Input;

Unbounded IO:

with
  Ada.Text_IO,
  Ada.Integer_Text_IO,
  Ada.Strings.Unbounded,
  Ada.Text_IO.Unbounded_IO;

procedure User_Input2 is
   S : Ada.Strings.Unbounded.Unbounded_String;
   I : Integer;
begin
   Ada.Text_IO.Put("Enter a string: ");
   S := Ada.Strings.Unbounded.To_Unbounded_String(Ada.Text_IO.Get_Line);
   Ada.Text_IO.Put_Line(Ada.Strings.Unbounded.To_String(S));
   Ada.Text_IO.Unbounded_IO.Put_Line(S);
   Ada.Text_IO.Put("Enter an integer: ");
   Ada.Integer_Text_IO.Get(I);
   Ada.Text_IO.Put_Line(Integer'Image(I));
end User_Input2;

ALGOL 68

print("Enter a string: ");
STRING s := read string;
print("Enter a number: ");
INT i := read int;
~

ALGOL W

begin
    string(80) s;
    integer    n;
    write( "Enter a string  > " );
    read( s );
    write( "Enter an integer> " );
    read( n )
end.

Amazing Hopper

Version: hopper-FLOW!

#include <flow.h>

#import lib/input.bas.lib
#include include/flow-input.h

DEF-MAIN(argv,argc)
   CLR-SCR
   MSET( número, cadena )
   LOCATE(2,2), PRNL( "Input an string : "), LOC-COL(20), LET( cadena := READ-STRING( cadena ) )
   LOCATE(3,2), PRNL( "Input an integer: "), LOC-COL(20), LET( número := INT( VAL(READ-NUMBER( número )) ) )
   LOCATE(5,2), PRNL( cadena, "\n ",número ) 
END

Output:

 Input an string : Juanita Pérez 
 Input an integer: 75000.789 

 Juanita Pérez
 75000

APL

str←⍞
int←⎕

ARM Assembly

Works with: as version Raspberry Pi

/* ARM assembly Raspberry PI  */
/*  program inputText.s   */

/* Constantes    */
.equ BUFFERSIZE,   100
.equ STDIN,  0     @ Linux input console
.equ STDOUT, 1     @ Linux output console
.equ EXIT,   1     @ Linux syscall
.equ READ,   3     @ Linux syscall
.equ WRITE,  4     @ Linux syscall
/* Initialized data */
.data
szMessDeb: .asciz "Enter text : \n"
szMessNum: .asciz "Enter number : \n"
szCarriageReturn:  .asciz "\n"

/* UnInitialized data */
.bss 
sBuffer:    .skip    BUFFERSIZE

/*  code section */
.text
.global main 
main:                /* entry of program  */
    push {fp,lr}    /* saves 2 registers */
    ldr r0,iAdrszMessDeb
    bl affichageMess
    mov r0,#STDIN         @ Linux input console
    ldr r1,iAdrsBuffer   @ buffer address 
    mov r2,#BUFFERSIZE   @ buffer size 
    mov r7, #READ         @ request to read datas
    swi 0                  @ call system
    ldr r1,iAdrsBuffer    @ buffer address 
    mov r2,#0                @ end of string
    strb r2,[r1,r0]         @ store byte at the end of input string (r0 contains number of characters)

    ldr r0,iAdrsBuffer    @ buffer address 
    bl affichageMess
    ldr r0,iAdrszCarriageReturn   
    bl affichageMess

    ldr r0,iAdrszMessNum
    bl affichageMess
    mov r0,#STDIN         @ Linux input console
    ldr r1,iAdrsBuffer   @ buffer address 
    mov r2,#BUFFERSIZE   @ buffer size 
    mov r7, #READ         @ request to read datas
    swi 0                  @ call system
    ldr r1,iAdrsBuffer    @ buffer address 
    mov r2,#0                @ end of string
    strb r2,[r1,r0]         @ store byte at the end of input string (r0
    @ 
    ldr r0,iAdrsBuffer    @ buffer address
    bl conversionAtoD    @ conversion string in number in r0
    
100:   /* standard end of the program */
    mov r0, #0                  @ return code
    pop {fp,lr}                 @restaur 2 registers
    mov r7, #EXIT              @ request to exit program
    swi 0                       @ perform the system call

iAdrszMessDeb:  .int szMessDeb
iAdrszMessNum: .int  szMessNum
iAdrsBuffer:   .int  sBuffer
iAdrszCarriageReturn:  .int  szCarriageReturn
/******************************************************************/
/*     display text with size calculation                         */ 
/******************************************************************/
/* r0 contains the address of the message */
affichageMess:
    push {fp,lr}    			/* save  registres */ 
    push {r0,r1,r2,r7}    		/* save others registers */
    mov r2,#0   				/* counter length */
1:      	/* loop length calculation */
    ldrb r1,[r0,r2]  			/* read octet start position + index */
    cmp r1,#0       			/* if 0 its over */
    addne r2,r2,#1   			/* else add 1 in the length */
    bne 1b          			/* and loop */
                                /* so here r2 contains the length of the message */
    mov r1,r0        			/* address message in r1 */
    mov r0,#STDOUT      		/* code to write to the standard output Linux */
    mov r7, #WRITE             /* code call system "write" */
    swi #0                      /* call systeme */
    pop {r0,r1,r2,r7}     		/* restaur others registers */
    pop {fp,lr}    				/* restaur des  2 registres */ 
    bx lr	        			/* return  */

/******************************************************************/
/*     Convert a string to a number stored in a registry          */ 
/******************************************************************/
/* r0 contains the address of the area terminated by 0 or 0A */
/* r0 returns a number                           */
conversionAtoD:
    push {fp,lr}         @ save 2 registers 
    push {r1-r7}         @ save others registers 
    mov r1,#0
    mov r2,#10           @ factor 
    mov r3,#0            @ counter 
    mov r4,r0            @ save address string -> r4 
    mov r6,#0            @ positive sign by default 
    mov r0,#0            @ initialization to 0 
1:     /* early space elimination loop */
    ldrb r5,[r4,r3]     @ loading in r5 of the byte located at the beginning + the position 
    cmp r5,#0            @ end of string -> end routine
    beq 100f
    cmp r5,#0x0A        @ end of string -> end routine
    beq 100f
    cmp r5,#' '          @ space ? 
    addeq r3,r3,#1      @ yes we loop by moving one byte 
    beq 1b
    cmp r5,#'-'          @ first character is -    
    moveq r6,#1         @  1 -> r6
    beq 3f              @ then move on to the next position 
2:   /* beginning of digit processing loop */
    cmp r5,#'0'          @ character is not a number 
    blt 3f
    cmp r5,#'9'          @ character is not a number
    bgt 3f
    /* character is a number */
    sub r5,#48
    ldr r1,iMaxi       @ check the overflow of the register    
    cmp r0,r1
    bgt 99f            @ overflow error
    mul r0,r2,r0         @ multiply par factor 10 
    add r0,r5            @ add to  r0 
3:
    add r3,r3,#1         @ advance to the next position 
    ldrb r5,[r4,r3]     @ load byte 
    cmp r5,#0            @ end of string -> end routine
    beq 4f
    cmp r5,#0x0A            @ end of string -> end routine
    beq 4f
    b 2b                 @ loop 
4:
    cmp r6,#1            @ test r6 for sign 
    moveq r1,#-1
    muleq r0,r1,r0       @ if negatif, multiply par -1 
    b 100f
99:  /* overflow error */
    ldr r0,=szMessErrDep
    bl   affichageMess
    mov r0,#0      @ return  zero  if error
100:
    pop {r1-r7}          @ restaur other registers 
    pop {fp,lr}          @ restaur   2 registers 
    bx lr                 @return procedure 
/* constante program */	
iMaxi: .int 1073741824	
szMessErrDep:  .asciz  "Too large: overflow 32 bits.\n"

Arturo

str: input "Enter a string: "
num: to :integer input "Enter an integer: "

print ["Got:" str "," num]

Output:

Enter a string: hello world
Enter an integer: 1986
Got: hello world , 1986

AutoHotkey

Windows console

DllCall("AllocConsole")
FileAppend, please type something`n, CONOUT$
FileReadLine, line, CONIN$, 1
msgbox % line
FileAppend, please type '75000'`n, CONOUT$
FileReadLine, line, CONIN$, 1
msgbox % line

Input Command

this one takes input regardless of which application has focus.

TrayTip, Input:, Type a string:
Input(String)
TrayTip, Input:, Type an int:
Input(Int)
TrayTip, Done!, Input was recieved.
Msgbox, You entered "%String%" and "%Int%"
ExitApp
Return

Input(ByRef Output)
{
  Loop
  {
    Input, Char, L1, {Enter}{Space}
    If ErrorLevel contains Enter 
      Break
    Else If ErrorLevel contains Space
      Output .= " "
    Else 
      Output .= Char
    TrayTip, Input:, %Output%
  }
}

AWK

This demo shows a same-line prompt, and that the integer i becomes 0 if the line did not parse as an integer.

~/src/opt/run $ awk 'BEGIN{printf "enter a string: "}{s=$0;i=$0+0;print "ok,"s"/"i}'
enter a string: hello world
ok,hello world/0
75000
ok,75000/75000

Axe

Since integers in Axe are two bytes, 75000 exceeds the maximum integer limit (65535). The task has been adjusted accordingly so the integer must be 7500 instead.

In this implementation, the number displayed is effectively the number entered modulo 65536.

Also, in the string entry, the data is a string of tokens, not a string of characters. Thankfully, the most common ASCII symbols (A-Z, 0-9, and some symbols) have the same values as their token counterparts. This means that this example will work for those symbols, but other tokens (especially multi-byte tokens) will cause problems. See this table of tokens and their codes for reference.

Disp "String:"
input→A
length(A)→L

.Copy the string to a safe location
Copy(A,L₁,L)

.Display the string
Disp "You entered:",i
For(I,0,L-1)
 Disp {L₁+I}►Char
End
Disp i

Disp "Integer:",i
input→B
length(B)→L

.Parse the string and convert to an integer
0→C
For(I,0,L-1)
 {B+I}-'0'→N
 If N>10
  .Error checking
  Disp "Not a number",i
  Return
 End
 C*10+N→C
End

.Display and check the integer
Disp "You entered:",i,C►Dec,i
If C≠7500
Disp "That isn't 7500"
End

BabyCobol

      * NB: whitespace insignificance and case insensitivity
      * are used in the field name.
       IDENTIFICATION DIVISION.
           PROGRAM-ID. USER INPUT.
       DATA DIVISION.
       01 HUNDRED CHAR STRING PICTURE IS X(100).
       01 FIVE DIGIT NUMBER PICTURE IS 9(5).
       PROCEDURE DIVISION.
           DISPLAY "Enter a string of appropriate length: " WITH NO ADVANCING
           ACCEPT HundredChar String.
           DISPLAY "Enter a number (preferably 75000): " WITH NO ADVANCING
           ACCEPT FiveDigit Number.

BASIC

Many BASICs will automatically append a question mark (?) to the end of the prompt if the prompt is followed by a semicolon (;). (Some of those will skip the question mark if the prompt is followed by a comma (,) instead of a semicolon.)

This isn't a hard-and-fast rule -- for example, Chipmunk Basic never appends a question mark.

INPUT "Enter a string"; s$
INPUT "Enter a number: ", i%

Output (QBasic):

Enter a string? foo
Enter a number: 1

Applesoft BASIC

10 INPUT "ENTER A STRING: "; S$
20 INPUT "ENTER A NUMBER: "; I : I = INT(I)

Commodore BASIC

When using the prompt feature of the INPUT command, the string literal must be followed by a semicolon and then the string variable, or else a ?SYNTAX ERROR will occur. The question mark prompt is always presented with the INPUT command. Any other behavior would have to come from a user-built routine using the GET command.

Also, when a numeric variable is provided for input, the computer will make repeated attempts to obtain valid input from the user until the input can be clearly interpreted as a numeric value.

10 input "what is a word i should remember";a$
20 print "thank you."
30 input "will you please type the number 75000";nn
40 if nn<>75000 then print "i'm sorry, that's not right.":goto 30
50 print "thank you.":print "you provided the following values:"
60 print a$
70 print nn
80 end

Output

READY.
RUN
WHAT IS A WORD I SHOULD REMEMBER? PANCAKE
THANK YOU.
WILL YOU PLEASE TYPE THE NUMBER 75000? NO.
?REDO FROM START
WILL YOU PLEASE TYPE THE NUMBER 75000? 848
I'M SORRY, THAT'S NOT RIGHT.
WILL YOU PLEASE TYPE THE NUMBER 75000? 75000
THANK YOU.
YOU PROVIDED THE FOLLOWING VALUES:
PANCAKE
 75000

READY.
█

IS-BASIC

100 INPUT PROMPT "Enter a number: ":NUM
110 INPUT PROMPT "Enter a string: ":ST$

QB64

The use of a Long int (l&) is required as the Int variable type is only 2 bytes and even if _UNSIGNED can only hold values up to 65535. If no value is entered for either input value, it will continue to hold whatever value it did previously.

Input "Enter text and a number", s$, l&
Print s$
Print l&

BASIC256

input string "Please enter a string: ", s
do
    input "Please enter 75000   : ", i
until i = 75000
print
print s, i

Run BASIC

input "Please enter a string: "; s$
while i <> 75000
    input "Please enter 75000   : "; i
wend
print
print s$; chr$(9); i

True BASIC

Works with: QBasic

PRINT "Please enter a string";
INPUT s$
DO
   PRINT "Please enter 75000   ";
   INPUT i
LOOP Until i = 75000
PRINT
PRINT s$, i
END

Yabasic

input "Please enter a string: " s$
repeat
    input "Please enter 75000   : " i
until i = 75000
print
print s$, chr$(9), i

Sinclair ZX81 BASIC

10 PRINT "ENTER A STRING"
20 INPUT S$
30 PRINT "YOU ENTERED: ";S$
40 PRINT "NOW ENTER THE NUMBER 75000"
50 INPUT N
60 IF N=75000 THEN STOP
70 PRINT "NO, ";
80 GOTO 40

Batch File

@echo off
set /p var=
echo %var% 75000

BBC BASIC

      INPUT LINE "Enter a string: " string$
      INPUT "Enter a number: " number
      
      PRINT "String = """ string$ """"
      PRINT "Number = " ; number

Befunge

This prompts for a string and pushes it to the stack a character at a time (~) until end of input (-1).

<>:v:"Enter a string: "
 ^,_ >~:1+v
     ^    _@

Numeric input is easier, using the & command.

<>:v:"Enter a number: "
 ^,_ & @

Bracmat

( doit
=   out'"Enter a string"
  & get':?mystring
  &   whl
    ' ( out'"Enter a number"
      & get':?mynumber
      & !mynumber:~#
      & out'"I said:\"a number\"!"
      )
  & out$(mystring is !mystring \nmynumber is !mynumber \n)
);

{?} !doit
Enter a string
abacus
Enter a number
75000h
I said:"a number"!
Enter a number
75000
mystring is abacus
mynumber is 75000

C

#include <stdio.h>
#include <stdlib.h>

int main(void)
{
    // Get a string from stdin
    char str[BUFSIZ];
    puts("Enter a string: ");
    fgets(str, sizeof(str), stdin);

    // Get 75000 from stdin
    long num;
    char buf[BUFSIZ];
    do
    {
        puts("Enter 75000: ");
        fgets(buf, sizeof(buf), stdin);
        num = strtol(buf, NULL, 10);
    } while (num != 75000);

    return EXIT_SUCCESS;
}

Library: Gadget

#include <gadget/gadget.h>

LIB_GADGET_START

Main
   Cls;
   
   String text;
   int number=0;
   
   At 5,5;  Print "Enter text   : ";
   Atrow 7; Print "Enter ‘75000’: ";
   Atcol 20;
   
   Atrow 5; Fn_let(text, Input ( text, 30 ) );   
   Free secure text;
   
   Atrow 7; Stack{ 
               while (number!=75000 )
                   /*into stack, Input() not need var*/
                   number = Str2int( Input ( NULL, 6 ) );
            }Stack_off;

   Prnl;
End

Output:

$ ./tests/input_cons




    Enter text   : Juanita la mañosa 

    Enter ‘75000’: 75000 
$ 

C#

using System;

namespace C_Sharp_Console {

    class example {

        static void Main() {
            string word;
            int num;
            
            Console.Write("Enter an integer: ");
            num = Console.Read();
            Console.Write("Enter a String: ");
            word = Console.ReadLine();
        }
    }
}

C++

Works with: g++

#include <iostream>
#include <string>
using namespace std;

int main()
{
     // while probably all current implementations have int wide enough for 75000, the C++ standard
     // only guarantees this for long int.
     long int integer_input;
     string string_input;
     cout << "Enter an integer:  ";
     cin >> integer_input;
     cout << "Enter a string:  ";
     cin >> string_input;
     return 0;
}

Note: The program as written above only reads the string up to the first whitespace character. To get a complete line into the string, replace

 cin >> string_input;

with

 getline(cin, string_input);

Note: if a numeric input operation fails, the value is not stored for that operation, plus the fail bit is set, which causes all future stream operations to be ignored (e.g. if a non-integer is entered for the first input above, then nothing will be stored in either the integer and the string). A more complete program would test for an error in the input (with if (!cin) // handle error) after the first input, and then clear the error (with cin.clear()) if we want to get further input.

Alternatively, we could read the input into a string first, and then parse that into an int later.

Ceylon

shared void run() {
	print("enter any text here");
	value text = process.readLine();
	print(text);
	print("enter the number 75000 here");
	if (is Integer number = Integer.parse(process.readLine() else "")) {
		print("``number == 75k then number else "close enough"``");
	}
	else {
		print("That was not a number per se.");
	}
}

Clojure

(import '(java.util Scanner))
(def scan (Scanner. *in*))
(def s (.nextLine scan))
(def n (.nextInt scan))

COBOL

Works with: OpenCOBOL

       IDENTIFICATION DIVISION.
       PROGRAM-ID. Get-Input.

       DATA DIVISION.
       WORKING-STORAGE SECTION.
       01  Input-String PIC X(30).
       01  Input-Int    PIC 9(5).

       PROCEDURE DIVISION.
       DISPLAY "Enter a string:"
       ACCEPT Input-String

       DISPLAY "Enter a number:"
       ACCEPT Input-Int

       GOBACK
       .

Common Lisp

(format t "Enter some text: ")
(let ((s (read-line)))
    (format t "You entered ~s~%" s))

(format t "Enter a number: ")
(let ((n (read)))
    (if (numberp n)
        (format t "You entered ~d.~%" n)
      (format t "That was not a number.")))

Crystal

puts "You entered: #{gets}"

begin
  puts "You entered: #{gets.not_nil!.chomp.to_i}"
rescue ex
  puts ex
end

Example with valid input:

Hello
You entered: Hello
75000
You entered: 75000

Example with invalid input:

Hello
You entered: Hello
Goodbye
Invalid Int32: Goodbye

D

import std.stdio;
 
void main() {
    long number;
    write("Enter an integer: ");
    readf("%d", &number);
    
    char[] str;
    write("Enter a string: ");
    readf(" %s\n", &str);
 
    writeln("Read in '", number, "' and '", str, "'");
}

Dart

import 'dart:io' show stdout, stdin;

main() {
	stdout.write('Enter a string: ');
	final string_input = stdin.readLineSync();

	int number_input;	

	do {
		stdout.write('Enter the number 75000: ');
		var number_input_string = stdin.readLineSync();

		try {
			number_input = int.parse(number_input_string);
			if (number_input != 75000)
				stdout.writeln('$number_input is not 75000!');
		} on FormatException {
			stdout.writeln('$number_input_string is not a valid number!');
		} catch ( e ) {
			stdout.writeln(e);
		}

	} while ( number_input != 75000 );

	stdout.writeln('input: $string_input\nnumber: $number_input');
}

Delphi

program UserInputText;

{$APPTYPE CONSOLE}

uses SysUtils;

var
  s: string;
  lStringValue: string;
  lIntegerValue: Integer;
begin
  WriteLn('Enter a string:');
  Readln(lStringValue);

  repeat
    WriteLn('Enter the number 75000');
    Readln(s);
    lIntegerValue := StrToIntDef(s, 0);
    if lIntegerValue <> 75000 then
      Writeln('Invalid entry: ' + s);
  until lIntegerValue = 75000;
end.

Déjà Vu

input s:
    !print\ s
    !decode!utf-8 !read-line!stdin
local :astring input "Enter a string: "
true
while:
    try:
        to-num input "Enter the number 75000: "
        /= 75000
    catch value-error:
        true

EasyLang

write "Enter a string: "
a$ = input
print ""
repeat
  write "Enter the number 75000: "
  h = number input
  print ""
  until h = 75000
.
print a$ & " " & h

Elena

ELENA 6.x :

import extensions;
 
public program()
{
    var num := new Integer();
    console.write("Enter an integer: ").loadLineTo(num);
 
    var word := console.write("Enter a String: ").readLine()
}

Elixir

a = IO.gets("Enter a string: ")      |> String.strip 
b = IO.gets("Enter an integer: ")    |> String.strip |> String.to_integer
f = IO.gets("Enter a real number: ") |> String.strip |> String.to_float
IO.puts "String  = #{a}"
IO.puts "Integer = #{b}"
IO.puts "Float   = #{f}"

Erlang

{ok, [String]} = io:fread("Enter a string: ","~s").
{ok, [Number]} = io:fread("Enter a number: ","~d").

Alternatively, you could use io:get_line to get a string:

 String = io:get_line("Enter a string: ").

Euphoria

include get.e

sequence s
atom n

s = prompt_string("Enter a string:")
puts(1, s & '\n')
n = prompt_number("Enter a number:",{})
printf(1, "%d", n)

F#

open System

let ask_for_input s =
    printf "%s (End with Return): " s
    Console.ReadLine()

[<EntryPoint>]
let main argv = 
    ask_for_input "Input a string" |> ignore
    ask_for_input "Enter the number 75000" |> ignore
    0

Factor

"Enter a string: " write
readln
"Enter a number: " write
readln string>number

Falcon

printl("Enter a string:")
str = input()
printl("Enter a number:")
n = int(input())

FALSE

FALSE has neither a string type nor numeric input. Shown instead are routines to parse and echo a word and to parse and interpret a number using the character input command (^).

[[^$' =~][,]#,]w:
[0[^'0-$$9>0@>|~][\10*+]#%]d:
w;! d;!.

Fantom

The 'toInt' method on an input string will throw an exception if the input is not a number.

class Main
{
  public static Void main ()
  {
    Env.cur.out.print ("Enter a string: ").flush
    str := Env.cur.in.readLine
    echo ("Entered :$str:")
    Env.cur.out.print ("Enter 75000: ").flush
    Int n
    try n = Env.cur.in.readLine.toInt
    catch (Err e) 
    {
      echo ("You had to enter a number")
      return
    }
    echo ("Entered :$n: which is " + ((n == 75000) ? "correct" : "wrong"))
  }
}

Forth

Input a string

: INPUT$ ( n -- addr n )
   PAD SWAP ACCEPT
   PAD SWAP ;

Input a number

The only ANS standard number interpretation word is >NUMBER ( ud str len -- ud str len ), which is meant to be the base factor for more convenient (but non-standard) parsing words.

: INPUT# ( -- u true | false )
  0. 16 INPUT$ DUP >R
  >NUMBER NIP NIP 
  R> <> DUP 0= IF NIP THEN ;

Works with: GNU Forth

: INPUT# ( -- n true | d 1 | false )
   16 INPUT$ SNUMBER? ;

Works with: Win32Forth

: INPUT# ( -- n true | false )
   16 INPUT$ NUMBER? NIP
   DUP 0= IF NIP THEN ;

Note that NUMBER? always leaves a double result on the stack. INPUT# returns a single precision number. If you desire a double precision result, remove the NIP.

Works with: 4tH

: input#
  begin
    refill drop bl parse-word          ( a n)
    number error?                      ( n f)
  while                                ( n)
    drop                               ( --)
  repeat                               ( n)
;

Here is an example that puts it all together:

: TEST
  ." Enter your name: " 80 INPUT$ CR
  ." Hello there, " TYPE CR
  ." Enter a number: " INPUT# CR
  IF   ." Your number is " .
  ELSE ." That's not a number!" THEN CR ;

Fortran

Works with: Fortran version 90 and later

character(20) :: s
integer :: i

print*, "Enter a string (max 20 characters)"
read*, s
print*, "Enter the integer 75000"
read*, i

FreeBASIC

' FB 1.05.0 Win64

Dim s As String
Dim i AS Integer
Input "Please enter a string : "; s
Do
  Input "Please enter 75000    : "; i
Loop Until i = 75000
Print
Print s, i
Sleep

Sample input/output

Output:

Please enter a string : ? Rosetta
Please enter 75000    : ? 70000
Please enter 75000    : ? 75000

Rosetta        75000

Frink

s = input["Enter a string: "]
i = parseInt[input["Enter an integer: "]]

GDScript

Works with: Godot version 4.0

Run with godot --headless --script <file>

extends MainLoop

func _process(_delta: float) -> bool:
	printraw("Input a string: ")
	var read_line := OS.read_string_from_stdin() # Mote that this retains the newline.

	printraw("Input an integer: ")
	var read_integer := int(OS.read_string_from_stdin())

	print("read_line = %s" % read_line.trim_suffix("\n"))
	print("read_integer = %d" % read_integer)

	return true # Exit instead of looping

Go

Go has C-like Scan and Scanf functions for quick and dirty input:

package main

import "fmt"

func main() {
    var s string
    var i int
    if _, err := fmt.Scan(&s, &i); err == nil && i == 75000 {
        fmt.Println("good")
    } else {
        fmt.Println("wrong")
    }
}

Code below allows much more control over interaction and error checking.

package main

import (
    "bufio"
    "fmt"
    "os"
    "strconv"
    "strings"
)

func main() {
    in := bufio.NewReader(os.Stdin)

    fmt.Print("Enter string: ")
    s, err := in.ReadString('\n')
    if err != nil {
        fmt.Println(err)
        return
    }
    s = strings.TrimSpace(s)

    fmt.Print("Enter 75000: ")
    s, err = in.ReadString('\n')
    if err != nil {
        fmt.Println(err)
        return
    }
    n, err := strconv.Atoi(strings.TrimSpace(s))
    if err != nil {
        fmt.Println(err)
        return
    }
    if n != 75000 {
        fmt.Println("fail:  not 75000")
        return
    }
    fmt.Println("Good")
}

Groovy

word = System.in.readLine()
num = System.in.readLine().toInteger()

Haskell

import System.IO (hFlush, stdout)
main = do
    putStr "Enter a string: "
    hFlush stdout
    str <- getLine
    putStr "Enter an integer: "
    hFlush stdout
    num <- readLn :: IO Int 
    putStrLn $ str ++ (show num)

Note: :: IO Int is only there to disambiguate what type we wanted from read. If num were used in a numerical context, its type would have been inferred by the interpreter/compiler. Note also: Haskell doesn't automatically flush stdout when doing input, so explicit flushes are necessary.

hexiscript

print "Enter a string: "
let s scan str
print "Enter a number: "
let n scan int

HolyC

U8 *s;
s = GetStr("Enter a string: ");

U32 *n;
do {
  n = GetStr("Enter 75000: ");
} while(Str2I64(n) != 75000);

Print("Your string: %s\n", s);
Print("75000: %d\n", Str2I64(n));

Icon and Unicon

The following works in both Icon and Unicon:

procedure main ()
  writes ("Enter something: ")
  s := read ()
  write ("You entered: " || s)

  writes ("Enter 75000: ")
  if (i := integer (read ())) then 
    write (if (i = 75000) then "correct" else "incorrect")
  else write ("you must enter a number")
end

Io

string := File clone standardInput readLine("Enter a string: ")
integer := File clone standardInput readLine("Enter 75000: ") asNumber

J

Solution

   require 'misc'            NB. load system script
   prompt 'Enter string: '
   0".prompt 'Enter an integer: '

Note that require'misc' is old - efforts to optimize by loading misc utilities in a fine grained fashion mean that currently (J 805) that should be require'general/misc/prompt' and the older form fails with an error to call attention to this issue.

Example Usage

   prompt 'Enter string: '                    NB. output string to session
Enter string: Hello World
Hello World
   0".prompt 'Enter an integer: '             NB. output integer to session
Enter an integer: 75000
75000
   mystring=: prompt 'Enter string: '         NB. store string as noun
Enter string: Hello Rosetta Code
   myinteger=: 0".prompt 'Enter an integer: ' NB. store integer as noun
Enter an integer: 75000
   mystring;myinteger                         NB. show contents of nouns
┌──────────────────┬─────┐
│Hello Rosetta Code│75000│
└──────────────────┴─────┘

Java

import java.util.Scanner;

public class GetInput {
    public static void main(String[] args) throws Exception {
        Scanner s = new Scanner(System.in);
        System.out.print("Enter a string: ");
        String str = s.nextLine();
        System.out.print("Enter an integer: ");
        int i = Integer.parseInt(s.next());
    }
}

or

Works with: Java version 1.5/5.0+

import java.util.Scanner;

public class GetInput {
    public static void main(String[] args) {
        Scanner stdin = new Scanner(System.in);
        String string = stdin.nextLine();
        int number = stdin.nextInt();
    }
}

JavaScript

Works with: JScript

and only with cscript.exe

WScript.Echo("Enter a string");
var str = WScript.StdIn.ReadLine();

var val = 0;
while (val != 75000) {
    WScript.Echo("Enter the integer 75000");
    val = parseInt( WScript.StdIn.ReadLine() );
}

Works with: SpiderMonkey

print("Enter a string");
var str = readline();

var val = 0;
while (val != 75000) {
    print("Enter the integer 75000");
    val = parseInt( readline() );
}

Joy

"Enter a string: " putchars
stdin fgets
"Enter a number: " putchars
stdin fgets 10 strtol.

jq

Works with: jq version 1.4

If the input consists of a JSON string followed by a JSON number, then the jq program consisting of . will read and echo the two values.

Works with: jq version 1.5

If the goal is to continue reading the input until a JSON string is found, and then continue reading the input until the integer value 75000 is encountered, then the following program could be used on the assumption that the inputs are all valid JSON.

def read(int):
  null | until( . == int;  "Expecting \(int)" | stderr | input);
  
def read_string:
  null | until( type == "string";  "Please enter a string" | stderr | input);

(read_string | "I see the string: \(.)"),
(read(75000) | "I see the expected integer: \(.)")

Output:

The following is a transcript showing the prompts (on stderr), responses (on stdin) and output (on stdout):

$ jq -n -r -f User_input.jq
"Please enter a string"
1
"Please enter a string"
"ok"
I see the string: ok
"Expecting 75000"
1
"Expecting 75000"
"ok"
"Expecting 75000"
75000
I see the expected integer: 75000

Julia

Works with: Julia version 0.6

print("String? ")
y = readline()
println("Your input was \"", y, "\".\n")
print("Integer? ")
y = readline()
try
    y = parse(Int, y)
    println("Your input was \"", y, "\".\n")
catch
    println("Sorry, but \"", y, "\" does not compute as an integer.")
end

Output:

String? cheese
Your input was "cheese".

Integer? 75000
Your input was "75000".

mike@harlan:~/rosetta/julia$ julia user_input_text.jl
String? theory
Your input was "theory".

Integer? 75,000
Sorry, but "75,000" does not compute as an integer.

Kite

System.file.stdout|write("Enter a String ");
string = System.file.stdin|readline();

Kotlin

// version 1.1

fun main(args: Array<String>) {
    print("Enter a string : ")
    val s = readLine()!!
    println(s)
    do {
        print("Enter 75000 : ")
        val number = readLine()!!.toInt()
    } while (number != 75000)
}

Lambdatalk

{input
 {@ type="text" 
    placeholder="Please enter a string and dblclick" 
    ondblclick="alert( 'You wrote « ' +
                       this.value +
                       ' » and it is ' +
                       ((isNaN(this.value)) ? 'not' : '') +
                       ' a number.' )"
}}

Please enter a string and dblclick

Input: Hello World
Output: You wrote « Hello World » and it is not a number.

Input: 123
Output: You wrote « 123 » and it is a number.

Lasso

#!/usr/bin/lasso9

define read_input(prompt::string) => {

	local(string)

	// display prompt
	stdout(#prompt)
	// the following bits wait until the terminal gives you back a line of input
	while(not #string or #string -> size == 0) => {
		#string = file_stdin -> readsomebytes(1024, 1000)
	}
	#string -> replace(bytes('\n'), bytes(''))

	return #string -> asstring

}

local(
	string,
	number
)

// get string
#string = read_input('Enter the string: ')

// get number
#number = integer(read_input('Enter the number: '))

// deliver the result
stdoutnl(#string + ' (' + #string -> type + ') | ' + #number + ' (' + #number -> type + ')')

Output:

Enter the string: Hello
Enter the number: 1234
Hello (string) | 1234 (integer)

LDPL

data:
myText is text
myNumber is number

procedure:
display "Enter some text: "
accept myText
display "Enter a number: "
accept myNumber

Liberty BASIC

Input "Enter a string. ";string$
Input "Enter the value 75000.";num

LIL

# User input/text, in LIL
write "Enter a string: "
set text [readline]

set num 0
while {[canread] && $num != 75000} {
    write "Enter the number 75000: "
    set num [readline]
}

print $text
print $num

Logo

Logo literals may be read from a line of input from stdin as either a list or a single word.

make "input readlist   ; in: string 75000
show map "number? :input  ; [false true]

make "input readword   ; in: 75000
show :input + 123       ; 75123 
make "input readword   ; in: string 75000
show :input             ; string 75000

Logtalk

Using an atom representation for strings and type-check failure-driven loops:

:- object(user_input).

    :- public(test/0).
    test :-
        repeat,
            write('Enter an integer: '),
            read(Integer),
        integer(Integer),
        !,
        repeat,
            write('Enter an atom: '),
            read(Atom),
        atom(Atom),
        !.

:- end_object.

Output:

| ?- user_input::test.
Enter an integer: 75000.
Enter an atom: 'Hello world!'.
yes

LOLCODE

HAI 1.4
I HAS A string
GIMMEH string
I HAS A number
GIMMEH number
BTW converts number input to an integer
MAEK number A NUMBR
KTHXBYE

Lua

print('Enter a string: ')
s = io.stdin:read()
print('Enter a number: ')
i = tonumber(io.stdin:read())

M2000 Interpreter

Module CheckIt {
      Keyboard "75000"+chr$(13)
      Input "Integer:", A%
      \\ Input erase keyboard buffer, we can't place in first Keyboard keys for second input
      Keyboard  "Hello World"+Chr$(13)
      Input "String:", A$
      Print A%, A$
}
CheckIt

MACRO-10

        TITLE User Input

COMMENT !
     User Input ** PDP-10 assembly language (kjx, 2022)
      Assembler: MACRO-10   Operating system: TOPS-20

  This program reads a string (maximum of 80 characters) and
  a decimal number. The number is checked to be 75000. Invalid
  input (like entering characters instead of a decimal number)
  is detected, and an error message is printed in that case.
!

        SEARCH MONSYM,MACSYM
        .REQUIRE SYS:MACREL

        STDAC.                          ;Set standard register names.

STRING: BLOCK 20                        ;20 octal words = 80 characters.
NUMBER: BLOCK 1                         ;1 word for number.

        ;;
        ;; Execution starts here:
        ;;

GO::    RESET%                          ;Initialize process.

        ;; Print prompt:

        HRROI T1,[ASCIZ /Please type a string, 80 chars max.: /]
        PSOUT%
        
        ;; Read string from terminal:

        HRROI T1,STRING                 ;Pointer to string-buffer.
        MOVEI T2,^D80                   ;80 characters max.
        SETZ  T3                        ;No special ctrl-r prompt.
        RDTTY%                          ;Read from terminal.
          ERJMP ERROR                   ;  On error, go to ERROR.

        ;; Print second prompt:

NUMI:   HRROI T1,[ASCIZ /Please type the decimal number 75000: /]
        PSOUT%
        
        ;; Input number from terminal:
        
        MOVEI T1,.PRIIN                 ;Read from terminal.
        MOVEI T3,^D10                   ;Decimal input.
        NIN%                            ;Input number.
          ERJMP ERROR                   ;  On error, go to ERROR.
           
        ;; Make sure number is actually 75000.
        
        CAIE  T2,^D75000                ;Compare number...
          JRST [ HRROI T1,[ASCIZ /Number is not 75000! /]
                 PSOUT%                 ;  ...complain and
                 JRST  NUMI ]           ;  try again.
        MOVEM T2,NUMBER                 ;Store number if correct.

        ;; Now print out string and number:

        HRROI T1,STRING                 ;String ptr into T1.
        PSOUT%                          ;Print string.

        MOVEI T1,.PRIOU                 ;Print on standard output.
        MOVE  T2,NUMBER                 ;Load number into T2.
        MOVEI T3,^D10                   ;Decimal output.
        NOUT%                           ;And print the number.
          ERJMP ERROR                   ;  On error, go to ERROR.

        ;; End program:

        HALTF%                          ;Halt program.
        JRST  GO                        ;Allow for 'continue'-command.

        ;;
        ;; The following routine prints out an error message,
        ;; similar to perror() in C:
        ;;

ERROR:  MOVEI T1,.PRIOU                 ;Standard output.
        MOVE  T2,[.FHSLF,,-1]           ;Own program, last error.
        SETZ  T3,                       ;No size-limit on message.
        ERSTR%                          ;Print error-message.
          JFCL                          ;  Ignore errors from ERSTR.
          JFCL                          ;  dito.
        HALTF%                          ;Halt program.
        JRST  GO                        ;Allow for 'continue'-command.

        END GO

Example output:

@ exec uinput
MACRO:  User
LINK:   Loading
[LNKXCT USER execution]
Please type a string, 80 chars max.: This is a test.
Please type the decimal number 75000: 74998
Number is not 75000! Please type the decimal number 75000: 74999
Number is not 75000! Please type the decimal number 75000: 75000
This is a test.
75000
@ _

Maple

printf("String:"); string_value := readline();
printf("Integer: "); int_value := parse(readline());

Mathematica / Wolfram Language

mystring = InputString["give me a string please"];
myinteger = Input["give me an integer please"];

MATLAB

The input() function automatically converts the user input to the correct data type (i.e. string or double). We can force the input to be interpreted as a string by using an optional parameter 's'.

Sample usage:

>> input('Input string: ')
Input string: 'Hello'

ans =

Hello

>> input('Input number: ')
Input number: 75000

ans =

       75000

>> input('Input number, the number will be stored as a string: ','s')
Input number, the number will be stored as a string: 75000

ans =

75000

Maxima

/* String routine */
block(
s:read("enter a string"),
if stringp(s) then print(s,"is an actual string") else "that is not a string")$

/* Number routine */
block(
n:read("enter a number"),
if numberp(n) then print(n,"is an actual number") else "that is not a number")$

Metafont

string s;
message "write a string: ";
s := readstring;
message s;
message "write a number now: ";
b := scantokens readstring;
if b = 750:
  message "You've got it!"
else:
  message "Sorry..."
fi;
end

If we do not provide a number in the second input, Metafont will complain. (The number 75000 was reduced to 750 since Metafont biggest number is near 4096).

min

Works with: min version 0.19.3

"Enter a string" ask
"Enter an integer" ask int

Mirah

s = System.console.readLine()

puts s

mIRC Scripting Language

alias askmesomething {
  echo -a You answered: $input(What's your name?, e)
}

Modula-3

MODULE Input EXPORTS Main;

IMPORT IO, Fmt;

VAR string: TEXT;
    number: INTEGER;

BEGIN
  IO.Put("Enter a string: ");
  string := IO.GetLine();
  IO.Put("Enter a number: ");
  number := IO.GetInt();
  IO.Put("You entered: " & string & " and " & Fmt.Int(number) & "\n");
END Input.

MUMPS

TXTINP
 NEW S,N
 WRITE "Enter a string: "
 READ S,!
 WRITE "Enter the number 75000: "
 READ N,!
 KILL S,N
 QUIT

Nanoquery

string  = str(input("Enter a string: "))
integer = int(input("Enter an integer: "))

Neko

/**
 User input/Text, in Neko
 Tectonics:
   nekoc userinput.neko
   neko userinput
*/

var stdin = $loader.loadprim("std@file_stdin", 0)()
var file_read_char = $loader.loadprim("std@file_read_char", 1)

/* Read a line from file f into string s returning length without any newline */
var NEWLINE = 10
var readline = function(f, s) {
    var len = 0
    var ch
    while true {
        try ch = file_read_char(f) catch a break;
        if ch == NEWLINE break;
        if $sset(s, len, ch) == null break; else len += 1
    }
    return $ssub(s, 0, len)
}

$print("Enter a line of text, then the number 75000\n")

try {
    var RECL = 132
    var str = $smake(RECL)
    var userstring = readline(stdin, str)
    $print(":", userstring, ":\n")

    var num = $int(readline(stdin, str))
    if num == 75000 $print("Rosetta Code 75000, for the win!\n")
    else $print("Sorry, need 75000\n")
} catch problem $print("Exception: ", problem, "\n")

Output:

prompt$ nekoc userinput.neko
prompt$ neko userinput.n
Enter a line of text, then the number 75000
this is a line of text
:this is a line of text:
75000
Rosetta Code 75000, for the win!

Nemerle

using System;
using System.Console;

module Input
{
    Main() : void
    {
        Write("Enter a string:");
        _ = ReadLine()

        mutable entry = 0;
        mutable numeric = false;
        
        do
        {
            Write("Enter 75000:");
            numeric = int.TryParse(ReadLine(), out entry);
        } while ((!numeric) || (entry != 75000)) 
    }
}

NetRexx

/* NetRexx */
options replace format comments java crossref symbols nobinary

checkVal = 75000
say 'Input a string then the number' checkVal
parse ask inString
parse ask inNumber .

say 'Input string:' inString
say 'Input number:' inNumber
if inNumber == checkVal then do
  say 'Success!  Input number is as requested'
  end
else do
  say 'Failure!  Number' inNumber 'is not' checkVal
  end
return

newLISP

Works with: newLISP version 9.0

(print "Enter an integer: ")
(set 'x (read-line))
(print "Enter a string: ")
(set 'y (read-line))

Nim

import rdstdin, strutils

let str = readLineFromStdin "Input a string: "
let num = parseInt(readLineFromStdin "Input an integer: ")

NS-HUBASIC

10 INPUT "ENTER A STRING: ",STRING$
20 PRINT "YOU ENTERED ";STRING$;"."
30 INPUT "ENTER AN INTEGER: ",INTEGER
40 PRINT "YOU ENTERED";INTEGER;"."

Nu

{
	String: (input "Enter a string: ")
	Number: (input "Enter an integer: ")
}

Output:

Enter a string: Hello world!
Enter an integer: 75000
╭────────┬──────────────╮
│ String │ Hello world! │
│ Number │ 75000        │
╰────────┴──────────────╯

Oberon-2

Works with: oo2c

MODULE InputText;
IMPORT 
  In,
  Out;
VAR
  i: INTEGER;
  str: ARRAY 512 OF CHAR;
BEGIN
  Out.String("Enter a integer: ");Out.Flush();In.Int(i);
  Out.String("Enter a string: ");Out.Flush();In.String(str);
END InputText.

Objeck

use IO;

bundle Default {
  class Hello {
    function : Main(args : String[]) ~ Nil {
      string := Console->GetInstance()->ReadString();
      string->PrintLine();

      number := Console->GetInstance()->ReadString()->ToInt();
      number->PrintLine();
    }
  }
}

OCaml

print_string "Enter a string: ";
let str = read_line () in
  print_string "Enter an integer: ";
  let num = read_int () in
    Printf.printf "%s%d\n" str num

Octave

% read a string ("s")
s = input("Enter a string: ", "s");

% read a GNU Octave expression, which is evaluated; e.g.
% 5/7 gives 0.71429
i = input("Enter an expression: ");

% parse the input for an integer
printf("Enter an integer: "); 
ri = scanf("%d");

% show the values
disp(s);
disp(i);
disp(ri);

Oforth

import: console

: testInput{
| s n |
   System.Console askln ->s
   while (System.Console askln asInteger dup ->n isNull) [ "Not an integer" println ]

   System.Out "Received : " << s << " and " << n << cr ;

Oz

declare
  StdIn = {New class $ from Open.file Open.text end init(name:stdin)}
  StringInput
  Num = {NewCell 0}
in
  {System.printInfo "Enter a string: "}
  StringInput = {StdIn getS($)}

  for until:@Num == 75000 do
     {System.printInfo "Enter 75000: "}
     Line = {StdIn getS($)}
  in
     Num := try {String.toInt Line} catch _ then 0 end
  end

PARI/GP

s=input();
n=eval(input());

Pascal

program UserInput(input, output);
var i : Integer;
    s : String;
begin
 write('Enter an integer: ');
 readln(i);
 write('Enter a string: ');
 readln(s)
end.

Perl

print "Enter a string: "; 
my $string = <>;
print "Enter an integer: ";
my $integer = <>;

Phix

?prompt_string("Enter any string:")
?prompt_number("Enter the number 75000:",{75000,75000})

Output:

Enter any string:abc
"abc"
Enter the number 75000:123
A number from 75000 to 75000 is expected here - try again
Enter the number 75000:75000
75000

Phixmonti

/# Rosetta Code problem: https://rosettacode.org/wiki/User_input/Text
by Galileo, 10/2022 #/

"Enter any string: " input nl
true while
    75000 "Enter the number " over tostr chain ": " chain input
    nl tonum over == not
endwhile
drop pstack

Output:

Enter any string: Hello
Enter the number 75000: 1000
Enter the number 75000: 75000

["Hello", 75000]

=== Press any key to exit ===

PHP

Works with: CLI SAPI

#!/usr/bin/php
<?php
$string = fgets(STDIN);
$integer = (int) fgets(STDIN);

Picat

main =>
  print("Enter a string: "),
  String = read_line(),
  print("Enter a number: "),
  Number = read_int(),
  println([string=String,number=Number]).

PicoLisp

(in NIL  # Guarantee reading from standard input
   (let (Str (read)  Num (read))
      (prinl "The string is: \"" Str "\"")
      (prinl "The number is: " Num) ) )

Pike

int main(){
   write("Enter a String: ");
   string str = Stdio.stdin->gets();
   write("Enter 75000: ");
   int num = Stdio.stdin->gets();
}

PL/I

declare s character (100) varying;
declare k fixed decimal (15);

put ('please type a string:');
get edit (s) (L);
put skip list (s);

put skip list ('please type the integer 75000');
get list (k);
put skip list (k);
put skip list ('Thanks');

Plain English

To run:
Start up.
Demonstrate input.
Wait for the escape key.
Shut down.
 
To demonstrate input:
Write "Enter a string: " to the console without advancing.
Read a string from the console.
Write "Enter a number: " to the console without advancing.
Read a number from the console.
\Now show the input values
Write "The string: " then the string to the console.
Write "The number: " then the number to the console.

A sample run of the program:

Output:

Enter a string: abc
Enter a number: 123
The string: abc
The number: 123

Pop11

;;; Setup item reader
lvars itemrep = incharitem(charin);
lvars s, c, j = 0;
;;; read chars up to a newline and put them on the stack
while (charin() ->> c) /= `\n` do j + 1 -> j ; c endwhile;
;;; build the string
consstring(j) -> s;
;;; read the integer
lvars i = itemrep();

PostScript

Works with: PostScript version level-2

%open stdin for reading (and name the channel "kbd"):
/kbd (%stdin) (r) file def
%make ten-char buffer to read string into:
/buf (..........) def
%read string into buffer:
kbd buf readline

At this point there will be two items on the stack: a boolean which is "true" if the read was successful and the string that was read from the kbd (input terminates on a <return>). If the length of the string exceeds the buffer length, an error condition occurs (rangecheck). For the second part, the above could be followed by this:

%if the read was successful, convert the string to integer:
{cvi} if

which will read the conversion operator 'cvi' (convert to integer) and the boolean and execute the former if the latter is true.

PowerShell

$string = Read-Host "Input a string"
[int]$number = Read-Host "Input a number"

PureBasic

If OpenConsole()
  ; Declare a string and a integer to be used
  Define txt.s, num.i

  Print("Enter a string: ")
  txt=Input()

  Repeat
    Print("Enter the number 75000: ")
    num=Val(Input()) ; Converts the Input to a Value with Val()
  Until num=75000
  ; Check that the user really gives us 75000!
  
  Print("You made it!")
  Delay(3000): CloseConsole()
EndIf

Python

Input a string

   string = raw_input("Input a string: ")

In Python 3.0, raw_input will be renamed to input(). The Python 3.0 equivalent would be

   string = input("Input a string: ")

Input a number

While input() gets a string in Python 3.0, in 2.x it is the equivalent of eval(raw_input(...)). Because this runs arbitrary code, and just isn't nice, it is being removed in Python 3.0. raw_input() is being changed to input() because there will be no other kind of input function in Python 3.0.

   number = input("Input a number: ")  # Deprecated, please don't use.

Python 3.0 equivalent:

   number = eval(input("Input a number: ")) # Evil, please don't use.

The preferred way of getting numbers from the user is to take the input as a string, and pass it to any one of the numeric types to create an instance of the appropriate number.

   number = float(raw_input("Input a number: "))

Python 3.0 equivalent:

   number = float(input("Input a number: "))

float may be replaced by any numeric type, such as int, complex, or decimal.Decimal. Each one varies in expected input.

Quackery

The word $->n attempts to convert a string to an integer, and returns an integer and a success flag. Validating the input is not part of the task, but since the flag is there we might as well use it. Similarly, might as well trim leading and trailing spaces, because users, eh.

$ "Please enter a string: " input
say 'You entered: "' echo$ say '"' cr cr
 
$ "Please enter an integer: " input
trim reverse trim reverse
$->n iff 
  [ say "You entered: " echo cr ]
else
  [ say "That was not an integer." cr 
    drop ]

Output:

Please enter a string: 3-ply sisal twine
You entered: "3-ply sisal twine"

Please enter an integer: 75000
You entered: 75000

R

Works with: R version 2.81

stringval <- readline("String: ")
intval <- as.integer(readline("Integer: "))

Racket

#lang racket
(printf "Input a string: ")
(define s (read-line))
(printf "You entered: ~a\n" s)

(printf "Input a number: ")
(define m (or (string->number (read-line))
              (error "I said a number!")))
(printf "You entered: ~a\n" m)

;; alternatively, use the generic `read'
(printf "Input a number: ")
(define n (read))
(unless (number? n) (error "I said a number!"))
(printf "You entered: ~a\n" n)

Raku

(formerly Perl 6)

my $str = prompt("Enter a string: ");
my $int = prompt("Enter a integer: ");

Rascal

It is possible to use the eclipse IDE to create consoles. However, just as with the graphical input, this will always return a string. This string can subsequently be evaluated. A very simple example would be:

import util::IDE;
public void InputConsole(){     
    x = "";                                   
    createConsole("Input Console",                             
                  "Welcome to the Input Console\nInput\> ", 
                  str (str inp) {x = "<inp == "75000" ? "You entered 75000" : "You entered a string">";
                 		 return "<x>\n<inp>\nInput\>";});
}

Which has as output:

This makes it relatively easy to create Domain Specific Languages (or any programming language) and to create a rascal console for this. For examples with Exp, Func and Lisp, see the online Language Examples.

Raven

'Input a string: '   print expect as str
'Input an integer: ' print expect 0 prefer as num

REBOL

REBOL [
	Title: "Textual User Input"
	URL: http://rosettacode.org/wiki/User_Input_-_text
]

s: n: ""

; Because I have several things to check for, I've made a function to
; handle it. Note the question mark in the function name, this convention
; is often used in Forth to indicate test of some sort. 

valid?: func [s n][
	error? try [n: to-integer n] ; Ignore error if conversion fails.
	all [0 < length? s  75000 = n]]

; I don't want to give up until I've gotten something useful, so I
; loop until the user enters valid data. 

while [not valid? s n][
	print "Please enter a string, and the number 75000:"
	s: ask "string: "
	n: ask "number: "
]

; It always pays to be polite...

print rejoin [ "Thank you. Your string was '" s "'."]

Output:

Please enter a string, and the number 75000:
string: This is a test.
number: ksldf
Please enter a string, and the number 75000:
string:
number: 75000
Please enter a string, and the number 75000:
string: Slert...
number: 75000
Thank you. Your string was 'Slert...'.

Red

n: ask "Please enter # 75000: " str: ask "Please enter any string: "

Retro

:example ("-)
  'Enter_a_string:_ s:put s:get s:keep
  [ 'Enter_75000:_ s:put s:get-word s:to-number nl #75000 eq? ] until
  'Your_string_was:_'%s'\n s:format s:put ;

REXX

Note:   all of the following would be accepted as being numerically equal to   75000:

•   7.5E+0004
•   75000.
•   750000e-01
•   000075000.0000
•       75000           (with leading and/or trailing blanks)
•   and others

If the intent was to have the user enter the string exactly as   75000,
then the REXX   do   statement should be replaced with:

 do  until userNumber==75000

/*REXX program prompts & reads/obtains a string, and also the number 75000 from terminal*/
say 'Please enter a string:'                     /*issue a prompt message to the term.  */
parse pull userString                            /*the (char) string can be any length. */
                                                 /* [↑]  the string could be null/empty.*/
  do  until userNumber=75000                     /*repeat this loop until satisfied.    */
  say                                            /*display a blank line to the terminal.*/
  say 'Please enter the number 75000'            /*display a nice prompt message to term*/
  parse pull userNumber                          /*obtain the user text from terminal.  */
  end   /*until*/                                /*check if the response is legitimate. */
                                                 /*stick a fork in it,  we're all done. */

Ring

see "Enter a string : " give s 
see "Enter an integer : " give i 
see "String  = " + s + nl
see "Integer = " + i + nl

Robotic

input string "Enter string:"
set "$str" to "input"
input string "Enter number:"
set "number" to "input"
[ "You entered:"
[ "&$str&"
[ "&number&"
end

To ensure that a specific number must be entered, just create a loop around the second input function:

input string "Enter string:"
set "$str" to "input"
: "incorrect"
input string "Enter number:"
set "number" to "input"
if "number" != "(75000)" then "incorrect"
[ "You entered:"
[ "&$str&"
[ "&number&"
end

RPL

≪ "Enter text" { "" 𝛼 } INPUT    @ Set keyboard alpha mode
   75000 → string n75000
   ≪ DO
        "Enter number " n + "" INPUT
     UNTIL n →STR == END
     string number
≫  ≫ 'TASK' STO 

Ruby

Works with: Ruby version 1.8.4

print "Enter a string: "
s = gets
printf "Enter an integer: "
i = gets.to_i   # If string entered, will return zero
printf "Enter a real number: "
f = Float(gets) rescue nil   # converts a floating point number or returns nil
puts "String  = #{s}"
puts "Integer = #{i}"
puts "Float   = #{f}"

Rust

This program shows all the proper error handling.

use std::io::{self, Write};
use std::fmt::Display;
use std::process;

fn main() {
    let s = grab_input("Give me a string")
        .unwrap_or_else(|e| exit_err(&e, e.raw_os_error().unwrap_or(-1)));

    println!("You entered: {}", s.trim());

    let n: i32 = grab_input("Give me an integer")
        .unwrap_or_else(|e| exit_err(&e, e.raw_os_error().unwrap_or(-1)))
        .trim()
        .parse()
        .unwrap_or_else(|e| exit_err(&e, 2));

    println!("You entered: {}", n);
}

fn grab_input(msg: &str) -> io::Result<String> {
    let mut buf = String::new();
    print!("{}: ", msg);
    try!(io::stdout().flush());

    try!(io::stdin().read_line(&mut buf));
    Ok(buf)
}

fn exit_err<T: Display>(msg: T, code: i32) -> ! {
    let _ = writeln!(&mut io::stderr(), "Error: {}", msg);
    process::exit(code)
}

Scala

print("Enter a number: ")
val i=Console.readLong  // Task says to enter 75000
print("Enter a string: ")
val s=Console.readLine

Scheme

The read procedure is R5RS standard, inputs a scheme representation so, in order to read a string, one must enter "hello world"

(define str (read))
(define num (read))
(display "String = ") (display str)
(display "Integer = ") (display num)

Seed7

$ include "seed7_05.s7i";

const proc: main is func
  local
    var integer: integer_input is 0;
    var string: string_input is "";
  begin
    write("Enter an integer: ");
    readln(integer_input);
    write("Enter a string: ");
    readln(string_input);
  end func;

Sidef

Using the read(Type) built-in function:

var s = read(String);
var i = read(Number);    # auto-conversion to a number

or using the Sys.readln(msg) method:

var s = Sys.readln("Enter a string: ");
var i = Sys.readln("Enter a number: ").to_i;

Slate

print: (query: 'Enter a String: ').
[| n |
  n: (Integer readFrom: (query: 'Enter an Integer: ')).
  (n is: Integer)
    ifTrue: [print: n]
    ifFalse: [inform: 'Not an integer: ' ; n printString]
] do.

Smalltalk

'Enter a number: ' display.
a := stdin nextLine asInteger.

'Enter a string: ' display.
b := stdin nextLine.

smart BASIC

NOTE: The INPUT command uses a colon (:) as opposed to a comma (,) or semi-conlon (;) like other forms of BASIC.

INPUT "Enter a string.":a$
INPUT "Enter the value 75000.":n

SNOBOL4

     output = "Enter a string:"
     str = trim(input)
     output = "Enter an integer:"
     int = trim(input)
     output = "String: " str " Integer: " int
end

SPL

In SPL all console input is text, so number should be converted from text using #.val function.

text = #.input("Input a string")
number = #.val(#.input("Input a number"))

SparForte

As a structured script.

#!/usr/local/bin/spar
  
pragma annotate( summary, "get_string" )
       @( description, "Input a string and the integer 75000 from the text console." )
       @( see_also, "https://rosettacode.org/wiki/User_input/Text" )
       @( author, "Ken O. Burtch" );
pragma license( unrestricted );

pragma restriction( no_external_commands );

procedure get_string is
  s : unbounded_string;
  i : integer;
begin
  s := get_line;
  i := integer( numerics.value( get_line ) );
  ? s @ i;
exception when others =>
  put_line( standard_error, "the value is not valid" );
end get_string;

As a unstructured script and no exception handling.

s := get_line;
i := numerics.value( get_line );
? s @ i;

Standard ML

print "Enter a string: ";
let val str = valOf (TextIO.inputLine TextIO.stdIn) in (* note: this keeps the trailing newline *)
  print "Enter an integer: ";
  let val num = valOf (TextIO.scanStream (Int.scan StringCvt.DEC) TextIO.stdIn) in
    print (str ^ Int.toString num ^ "\n")
  end
end

Swift

Works with: Swift version 2.x+

print("Enter a string: ", terminator: "")
if let str = readLine() {
  print(str)
}

Works with: Swift version 5.x+

print("Enter a string: ", terminator: "")
guard let str = readLine() else {
    fatalError("Nothing read!")
}
print(str)
print("Enter a number: ", terminator: "")
guard let nstr = readLine(), let num = Int(nstr) else {
    fatalError("Not a number!")
}
print(num)

Tcl

Like LISP, there is no concept of a "number" in Tcl - the only real variable type is a string (whether a string might represent a number is a matter of interpretation of the string in a mathematical expression at some later time). Thus the input is the same for both tasks:

set str [gets stdin]
set num [gets stdin]

possibly followed by something like

if {![string is integer -strict $num]} then { ...do something here...}

If the requirement is to prompt until the user enters the integer 75000, then:

set input 0
while {$input != 75000} {
    puts -nonewline "enter the number '75000': "
    flush stdout
    set input [gets stdin]
}

Of course, it's nicer to wrap the primitives in a procedure:

proc question {var message} {
    upvar 1 $var v
    puts -nonewline "$message: "
    flush stdout
    gets stdin $v
}
question name "What is your name"
question task "What is your quest"
question doom "What is the air-speed velocity of an unladen swallow"

TI-83 BASIC

This program leaves the string in String1, and the integer in variable "i".

  :Input "Enter a string:",Str1
  :Prompt i
  :If(i ≠ 75000): Then
  :Disp "That isn't 75000"
  :Else
  :Stop

TI-89 BASIC

This program leaves the requested values in the global variables s and integer.

Prgm
  InputStr "Enter a string", s
  Loop
    Prompt integer
    If integer ≠ 75000 Then
      Disp "That wasn't 75000."
    Else
      Exit
    EndIf
  EndLoop
EndPrgm

Toka

needs readline
." Enter a string: " readline is-data the-string
." Enter a number: " readline >number [ ." Not a number!" drop 0 ] ifFalse is-data the-number

the-string type cr
the-number . cr

TUSCRIPT

$$ MODE TUSCRIPT
LOOP
ASK "Enter a string": str=""
ASK "Enter an integer": int=""
IF (int=='digits') THEN
PRINT "int=",int," str=",str
EXIT
ELSE
PRINT/ERROR int," is not an integer"
CYCLE
ENDIF
ENDLOOP

Output:

Enter a string >a
Enter an integer >a
@@@@@@@@  a is not an integer                                          @@@@@@@@
Enter a string >a
Enter an integer >1
int=1 str=a 

UNIX Shell

Works with: Bourne Shell

#!/bin/sh

read string
read integer
read -p 'Enter a number: ' number
echo "The number is $number"

Ursa

#
# user input
#

# in ursa, the type of data expected must be specified
decl string str
decl int i

out "input a string: " console
set str (in string console)
out "input an int:   " console
set i (in int console)

out "you entered " str " and " i endl console

VBA

Public Sub text()
    Debug.Print InputBox("Input a string")
    Debug.Print InputBox("Input the integer 75000", "Input an integer", 75000, Context = "Long")
End Sub

Vedit macro language

Get_Input(1, "Enter a string: ")
#2 = Get_Num("Enter a number: ")

Visual Basic .NET

Platform: .NET

Works with: Visual Basic .NET version 9.0+

Input an Integer

Dim i As Integer
Console.WriteLine("Enter an Integer")
i = Console.ReadLine()

Input an Integer With Error Handling

Dim i As Integer
Dim iString As String
Console.WriteLine("Enter an Integer")
iString = Console.ReadLine()
Try
    i = Convert.ToInt32(iString)
Catch ex As Exception
    Console.WriteLine("This is not an Integer")
End Try

Input a String

Dim i As String
Console.WriteLine("Enter a String")
i = Console.ReadLine()

V (Vlang)

import os

fn main() {
    s := os.input('Enter string').int()
    if s == 75000 {
        println('good')
    } else {
        println('bad')
    }
}

Input conversion with Error Handling

import os
import strconv

fn main() {
    s := strconv.atoi(os.input('Enter string')) ?
    if s == 75000 {
        println('good')
    } else {
        println('bad $s')
    }
}

Wee Basic

print 1 "Enter a string."
input string$
print 1 "Enter an integer."
input integer

Wren

import "io" for Stdin, Stdout

var string
while (true) {
    System.write("Enter a string : ")
    Stdout.flush()
    string = Stdin.readLine()
    if (string.count == 0) {
        System.print("String cannot be empty, try again.")
    } else {
        break
    }
}

var number
while (true) {
    System.write("Enter a number : ")
    Stdout.flush()
    number = Num.fromString(Stdin.readLine())
    if (!number || !number.isInteger) {
        System.print("Please enter a vaid integer, try again.")
    } else {
        break
    }
}

System.print("\nYou entered:")
System.print("  string: %(string)")
System.print("  number: %(number)")

Output:

Enter a string : Rosetta Code
Enter a number : 75000

You entered:
  string: Rosetta Code
  number: 75000

XLISP

READ-LINE reads a line of input as a string; READ reads an expression, of arbitrary complexity.

(display "Enter a string: ")
(define s (read-line))
(display "Yes, ")
(write s)
(display " is a string.") ;; no need to verify, because READ-LINE has to return a string
(newline)
(display "Now enter the integer 75000: ")
(define n (read))
(display
    (cond
        ((not (integerp n))
            "That's not even an integer." )
        ((/= n 75000)
            "That is not the integer 75000." )
        (t
            "Yes, that is the integer 75000." ) ) )

Output:

Enter a string: Rosetta Code
Yes, "Rosetta Code" is a string.
Now enter the integer 75000: 75000
Yes, that is the integer 75000.

XPL0

When the ChIn(0) intrinsic is first called, it collects characters from the keyboard until the Enter key is struck. It then returns to the XPL0 program where one character is pulled from the buffer each time ChIn(0) is called. When the Enter key (which is the same as a carriage return, $0D) is pulled, the program quits the loop. A zero byte is stored in place of the Enter key to mark the end of the string.

string  0;              \use zero-terminated strings, instead of MSb terminated
include c:\cxpl\codes;
int     I;
char    Name(128);      \the keyboard buffer limits input to 128 characters

[Text(0, "What's your name? ");
I:= 0;
loop    [Name(I):= ChIn(0);                     \buffered keyboard input
        if Name(I) = $0D\CR\ then quit;         \Carriage Return = Enter key
        I:= I+1;
        ];
Name(I):= 0;                                    \terminate string
Text(0, "Howdy "); Text(0, Name); Text(0, "! Now please enter ^"75000^": ");
IntOut(0, IntIn(0));  CrLf(0);                  \echo the number
]

Example output:

What's your name? Loren Blaney
Howdy Loren Blaney! Now please enter "75000": 75000
75000

zkl

str:=ask("Gimmie a string: ");
n:=ask("Type 75000: ").toInt();

ZX Spectrum Basic

10 INPUT "Enter a string:"; s$
20 INPUT "Enter a number: "; n

---