Minimum numbers of three lists

Minimum numbers of three lists is a draft programming task. It is not yet considered ready to be promoted as a complete task, for reasons that should be found in its talk page.

Task

Let given three lists:
Numbers1 = [5,45,23,21,67]
Numbers2 = [43,22,78,46,38]
Numbers3 = [9,98,12,98,53]
Select the minimum of Numbers[n], Numbers2[n] and Numbers3[n], where n <= 5
Add minimum to a new list (Numbers)
Show Numbers on this page.

Go

Library: Go-rcu

<lang go>package main

import (

   "fmt"
   "rcu"

)

func main() {

   numbers1 := [5]int{5, 45, 23, 21, 67}
   numbers2 := [5]int{43, 22, 78, 46, 38}
   numbers3 := [5]int{9, 98, 12, 98, 53}
   minima := [5]int{}
   for n := 0; n < 5; n++ {
       minima[n] = rcu.Min(rcu.Min(numbers1[n], numbers2[n]), numbers3[n])
   }
   fmt.Println(minima)

}</lang>

Output:

[5 22 12 21 38]

Ring

<lang ring> see "working..." + nl

Numbers = [] Numbers1 = [5,45,23,21,67] Numbers2 = [43,22,78,46,38] Numbers3 = [9,98,12,98,53]

for n = 1 to len(Numbers1)

   Temp = []
   add(Temp,Numbers1[n])
   add(Temp,Numbers2[n])
   add(Temp,Numbers3[n])
   min = min(Temp)
   add(Numbers,min)

next

see "The minimum numbers of three lists = " see showArray(Numbers) see nl + "done..." + nl

func showArray(array)

    txt = ""
    see "["
    for n = 1 to len(array)
        txt = txt + array[n] + ","
    next
    txt = left(txt,len(txt)-1)
    txt = txt + "]"
    see txt 

</lang>

Output:

working...
The minimum numbers of three lists = [5,22,12,21,38]
done...

Wren

<lang ecmascript>var numbers1 = [ 5, 45, 23, 21, 67] var numbers2 = [43, 22, 78, 46, 38] var numbers3 = [ 9, 98, 12, 98, 53] var minima = List.filled(5, 0) for (n in 0..4) minima[n] = numbers1[n].min(numbers2[n]).min(numbers3[n]) System.print(minima)</lang>

Output:

[5, 22, 12, 21, 38]