Word frequency
You are encouraged to solve this task according to the task description, using any language you may know.
- Task
Given a text file and an integer n, print/display the n most common words in the file (and the number of their occurrences) in decreasing frequency.
For the purposes of this task:
- A word is a sequence of one or more contiguous letters.
- You are free to define what a letter is.
- Underscores, accented letters, apostrophes, hyphens, and other special characters can be handled at your discretion.
- You may treat a compound word like well-dressed as either one word or two.
- The word it's could also be one or two words as you see fit.
- You may also choose not to support non US-ASCII characters.
- Assume words will not span multiple lines.
- Don't worry about normalization of word spelling differences.
- Treat color and colour as two distinct words.
- Uppercase letters are considered equivalent to their lowercase counterparts.
- Words of equal frequency can be listed in any order.
- Feel free to explicitly state the thoughts behind the program decisions.
Show example output using Les Misérables from Project Gutenberg as the text file input and display the top 10 most used words.
- History
This task was originally taken from programming pearls from Communications of the ACM June 1986 Volume 29 Number 6 where this problem is solved by Donald Knuth using literate programming and then critiqued by Doug McIlroy, demonstrating solving the problem in a 6 line Unix shell script (provided as an example below).
- References
- Metrics
- Counting
- Word frequency
- Letter frequency
- Jewels and stones
- I before E except after C
- Bioinformatics/base count
- Count occurrences of a substring
- Count how many vowels and consonants occur in a string
- Remove/replace
- XXXX redacted
- Conjugate a Latin verb
- Remove vowels from a string
- String interpolation (included)
- Strip block comments
- Strip comments from a string
- Strip a set of characters from a string
- Strip whitespace from a string -- top and tail
- Strip control codes and extended characters from a string
- Anagrams/Derangements/shuffling
- Word wheel
- ABC problem
- Sattolo cycle
- Knuth shuffle
- Ordered words
- Superpermutation minimisation
- Textonyms (using a phone text pad)
- Anagrams
- Anagrams/Deranged anagrams
- Permutations/Derangements
- Find/Search/Determine
- ABC words
- Odd words
- Word ladder
- Semordnilap
- Word search
- Wordiff (game)
- String matching
- Tea cup rim text
- Alternade words
- Changeable words
- State name puzzle
- String comparison
- Unique characters
- Unique characters in each string
- Extract file extension
- Levenshtein distance
- Palindrome detection
- Common list elements
- Longest common suffix
- Longest common prefix
- Compare a list of strings
- Longest common substring
- Find common directory path
- Words from neighbour ones
- Change e letters to i in words
- Non-continuous subsequences
- Longest common subsequence
- Longest palindromic substrings
- Longest increasing subsequence
- Words containing "the" substring
- Sum of the digits of n is substring of n
- Determine if a string is numeric
- Determine if a string is collapsible
- Determine if a string is squeezable
- Determine if a string has all unique characters
- Determine if a string has all the same characters
- Longest substrings without repeating characters
- Find words which contains all the vowels
- Find words which contains most consonants
- Find words which contains more than 3 vowels
- Find words which first and last three letters are equals
- Find words which odd letters are consonants and even letters are vowels or vice_versa
- Formatting
- Substring
- Rep-string
- Word wrap
- String case
- Align columns
- Literals/String
- Repeat a string
- Brace expansion
- Brace expansion using ranges
- Reverse a string
- Phrase reversals
- Comma quibbling
- Special characters
- String concatenation
- Substring/Top and tail
- Commatizing numbers
- Reverse words in a string
- Suffixation of decimal numbers
- Long literals, with continuations
- Numerical and alphabetical suffixes
- Abbreviations, easy
- Abbreviations, simple
- Abbreviations, automatic
- Song lyrics/poems/Mad Libs/phrases
- Mad Libs
- Magic 8-ball
- 99 Bottles of Beer
- The Name Game (a song)
- The Old lady swallowed a fly
- The Twelve Days of Christmas
- Tokenize
- Text between
- Tokenize a string
- Word break problem
- Tokenize a string with escaping
- Split a character string based on change of character
- Sequences
11l
<lang 11l>DefaultDict[String, Int] cnt L(word) re:‘\w+’.find_strings(File(‘135-0.txt’).read().lowercase())
cnt[word]++
print(sorted(cnt.items(), key' wordc -> wordc[1], reverse' 1B)[0.<10])</lang>
- Output:
[(the, 41045), (of, 19953), (and, 14939), (a, 14527), (to, 13942), (in, 11210), (he, 9646), (was, 8620), (that, 7922), (it, 6659)]
Ada
This version uses a character set to match valid characters in a token. Another version could use a pointer to a function returning a boolean to match valid characters (allowing to use functions such as Is_Alphanumeric), but AFAIK there is no "Find_Token" method that uses one.
<lang Ada>with Ada.Command_Line; with Ada.Text_IO; with Ada.Integer_Text_IO; with Ada.Strings.Maps; with Ada.Strings.Fixed; with Ada.Characters.Handling; with Ada.Containers.Indefinite_Ordered_Maps; with Ada.Containers.Indefinite_Ordered_Sets; with Ada.Containers.Ordered_Maps;
procedure Word_Frequency is
package TIO renames Ada.Text_IO;
package String_Counters is new Ada.Containers.Indefinite_Ordered_Maps(String, Natural);
package String_Sets is new Ada.Containers.Indefinite_Ordered_Sets(String);
package Sorted_Counters is new Ada.Containers.Ordered_Maps
(Natural,
String_Sets.Set,
"=" => String_Sets."=",
"<" => ">");
-- for sorting by decreasing number of occurrences and ascending lexical order
procedure Increment(Key : in String; Element : in out Natural) is
begin
Element := Element + 1;
end Increment;
path : constant String := Ada.Command_Line.Argument(1);
how_many : Natural := 10;
set : constant Ada.Strings.Maps.Character_Set := Ada.Strings.Maps.To_Set(ranges => (('a', 'z'), ('0', '9')));
F : TIO.File_Type;
first : Positive;
last : Natural;
from : Positive;
counter : String_Counters.Map;
sorted_counts : Sorted_Counters.Map;
C1 : String_Counters.Cursor;
C2 : Sorted_Counters.Cursor;
tmp_set : String_Sets.Set;
begin
-- read file and count words
TIO.Open(F, name => path, mode => TIO.In_File);
while not TIO.End_Of_File(F) loop
declare
line : constant String := Ada.Characters.Handling.To_Lower(TIO.Get_Line(F));
begin
from := line'First;
loop
Ada.Strings.Fixed.Find_Token(line(from .. line'Last), set, Ada.Strings.Inside, first, last);
exit when last < First;
C1 := counter.Find(line(first .. last));
if String_Counters.Has_Element(C1) then
counter.Update_Element(C1, Increment'Access);
else
counter.Insert(line(first .. last), 1);
end if;
from := last + 1;
end loop;
end;
end loop;
TIO.Close(F);
-- fill Natural -> StringSet Map
C1 := counter.First;
while String_Counters.Has_Element(C1) loop
if sorted_counts.Contains(String_Counters.Element(C1)) then
tmp_set := sorted_counts.Element(String_Counters.Element(C1));
tmp_set.Include(String_Counters.Key(C1));
else
sorted_counts.Include(String_Counters.Element(C1), String_Sets.To_Set(String_Counters.Key(C1)));
end if;
String_Counters.Next(C1);
end loop;
-- output
C2 := sorted_counts.First;
while Sorted_Counters.Has_Element(C2) loop
for Item of Sorted_Counters.Element(C2) loop
Ada.Integer_Text_IO.Put(TIO.Standard_Output, Sorted_Counters.Key(C2), width => 9);
TIO.Put(TIO.Standard_Output, " ");
TIO.Put_Line(Item);
end loop;
Sorted_Counters.Next(C2);
how_many := how_many - 1;
exit when how_many = 0;
end loop;
end Word_Frequency; </lang>
- Output:
$ ./word_frequency 135-0.txt
41093 the
19954 of
14943 and
14558 a
13953 to
11219 in
9649 he
8622 was
7924 that
6661 it
ALGOL 68
Uses the associative array implementations in ALGOL_68/prelude. <lang algol68># find the n most common words in a file #
- use the associative array in the Associate array/iteration task #
- but with integer values #
PR read "aArrayBase.a68" PR MODE AAKEY = STRING; MODE AAVALUE = INT; AAVALUE init element value = 0;
- returns text converted to upper case #
OP TOUPPER = ( STRING text )STRING:
BEGIN
STRING result := text;
FOR ch pos FROM LWB result TO UPB result DO
IF is lower( result[ ch pos ] ) THEN result[ ch pos ] := to upper( result[ ch pos ] ) FI
OD;
result
END # TOUPPER # ;
- returns text converted to an INT or -1 if text is not a number #
OP TOINT = ( STRING text )INT:
BEGIN
INT result := 0;
BOOL is numeric := TRUE;
FOR ch pos FROM UPB text BY -1 TO LWB text WHILE is numeric DO
CHAR c = text[ ch pos ];
is numeric := is numeric AND c >= "0" AND c <= "9";
IF is numeric THEN ( result *:= 10 ) +:= ABS c - ABS "0" FI
OD;
IF is numeric THEN result ELSE -1 FI
END # TOINT # ;
- returns TRUE if c is a letter, FALSE otherwise #
OP ISLETTER = ( CHAR c )BOOL:
IF ( c >= "a" AND c <= "z" )
OR ( c >= "A" AND c <= "Z" )
THEN TRUE
ELSE char in string( c, NIL, "ÇåçêëÆôöÿÖØáóÔ" )
FI # ISLETER # ;
- get the file name and number of words from then commmand line #
STRING file name := "pg-les-misrables.txt"; INT number of words := 10; FOR arg pos TO argc - 1 DO
STRING arg upper = TOUPPER argv( arg pos );
IF arg upper = "FILE" THEN
file name := argv( arg pos + 1 )
ELIF arg upper = "NUMBER" THEN
number of words := TOINT argv( arg pos + 1 )
FI
OD; IF FILE input file;
open( input file, file name, stand in channel ) /= 0
THEN
# failed to open the file # print( ( "Unable to open """ + file name + """", newline ) )
ELSE
# file opened OK #
print( ( "Processing: ", file name, newline ) );
BOOL at eof := FALSE;
BOOL at eol := FALSE;
# set the EOF handler for the file #
on logical file end( input file, ( REF FILE f )BOOL:
BEGIN
# note that we reached EOF on the #
# latest read #
at eof := TRUE;
# return TRUE so processing can continue #
TRUE
END
);
# set the end-of-line handler for the file so get word can see line boundaries #
on line end( input file
, ( REF FILE f )BOOL:
BEGIN
# note we reached end-of-line #
at eol := TRUE;
# return FALSE to use the default eol handling #
# i.e. just get the next charactefr #
FALSE
END
);
# get the words from the file and store the counts in an associative array #
REF AARRAY words := INIT LOC AARRAY;
INT word count := 0;
CHAR c := " ";
WHILE get( input file, ( c ) );
NOT at eof
DO
WHILE NOT ISLETTER c AND NOT at eof DO get( input file, ( c ) ) OD;
STRING word := "";
at eol := FALSE;
WHILE ISLETTER c AND NOT at eol AND NOT at eof DO word +:= c; get( input file, ( c ) ) OD;
word count +:= 1;
words // TOUPPER word +:= 1
OD;
close( input file );
print( ( file name, " contains ", whole( word count, 0 ), " words", newline ) );
# find the most used words #
[ number of words ]STRING top words;
[ number of words ]INT top counts;
FOR i TO number of words DO top words[ i ] := ""; top counts[ i ] := 0 OD;
REF AAELEMENT w := FIRST words;
WHILE w ISNT nil element DO
INT count = value OF w;
STRING word = key OF w;
BOOL found := FALSE;
FOR i TO number of words WHILE NOT found DO
IF count > top counts[ i ] THEN
# found a word that is used nore than a current #
# most used word #
found := TRUE;
# move the other words down one place #
FOR move pos FROM number of words BY - 1 TO i + 1 DO
top counts[ move pos ] := top counts[ move pos - 1 ];
top words [ move pos ] := top words [ move pos - 1 ]
OD;
# install the new word #
top counts[ i ] := count;
top words [ i ] := word
FI
OD;
w := NEXT words
OD;
print( ( whole( number of words, 0 ), " most used words:", newline ) );
print( ( " count word", newline ) );
FOR i TO number of words DO
print( ( whole( top counts[ i ], -6 ), ": ", top words[ i ], newline ) )
OD
FI</lang>
- Output:
Processing: pg-les-misrables.txt pg-les-misrables.txt contains 578381 words 10 most used words: count word 39333: THE 19154: OF 14628: AND 14229: A 13431: TO 11275: HE 10879: IN 8236: WAS 7527: THAT 6491: IT
AppleScript
<lang applescript>(*
For simplicity here, words are considered to be uninterrupted sequences of letters and/or digits. The set text is too messy to warrant faffing around with anything more sophisticated. The first letter in each word is upper-cased and the rest lower-cased for case equivalence and presentation. Where more than n words qualify for the top n or fewer places, all are included in the result.
- )
use AppleScript version "2.4" -- OS X 10.10 (Yosemite) or later use framework "Foundation" use scripting additions
on wordFrequency(filePath, n)
set |⌘| to current application
-- Get the text and "capitalize" it (lower-case except for the first letters in words).
set theText to |⌘|'s class "NSString"'s stringWithContentsOfFile:(filePath) usedEncoding:(missing value) |error|:(missing value)
set theText to theText's capitalizedStringWithLocale:(|⌘|'s class "NSLocale"'s currentLocale()) -- Yosemite compatible.
-- Split it at the non-word characters.
set nonWordCharacters to |⌘|'s class "NSCharacterSet"'s alphanumericCharacterSet()'s invertedSet()
set theWords to theText's componentsSeparatedByCharactersInSet:(nonWordCharacters)
-- Use a counted set to count the individual words' occurrences.
set countedSet to |⌘|'s class "NSCountedSet"'s alloc()'s initWithArray:(theWords)
-- Build a list of word/frequency records, excluding any empty strings left over from the splitting above.
set mutableSet to |⌘|'s class "NSMutableSet"'s setWithSet:(countedSet)
tell mutableSet to removeObject:("")
script o
property discreteWords : mutableSet's allObjects() as list
property wordsAndFrequencies : {}
end script
set discreteWordCount to (count o's discreteWords)
repeat with i from 1 to discreteWordCount
set thisWord to item i of o's discreteWords
set end of o's wordsAndFrequencies to {thisWord:thisWord, frequency:(countedSet's countForObject:(thisWord)) as integer}
end repeat
-- Convert to NSMutableArray, reverse-sort the result on the frequencies, and convert back to list.
set wordsAndFrequencies to |⌘|'s class "NSMutableArray"'s arrayWithArray:(o's wordsAndFrequencies)
set descendingByFrequency to |⌘|'s class "NSSortDescriptor"'s sortDescriptorWithKey:("frequency") ascending:(false)
tell wordsAndFrequencies to sortUsingDescriptors:({descendingByFrequency})
set o's wordsAndFrequencies to wordsAndFrequencies as list
if (discreteWordCount > n) then
-- If there are more than n records, check for any immediately following the nth which may have the same frequency as it.
set nthHighestFrequency to frequency of item n of o's wordsAndFrequencies
set qualifierCount to n
repeat with i from (n + 1) to discreteWordCount
if (frequency of item i of o's wordsAndFrequencies = nthHighestFrequency) then
set qualifierCount to i
else
exit repeat
end if
end repeat
else
-- Otherwise reduce n to the actual number of discrete words.
set n to discreteWordCount
set qualifierCount to discreteWordCount
end if
-- Compose a text report from the qualifying words and frequencies.
if (qualifierCount = n) then
set output to {"The " & n & " most frequently occurring words in the file are:"}
else
set output to {(qualifierCount as text) & " words share the " & ((n as text) & " highest frequencies in the file:")}
end if
repeat with i from 1 to qualifierCount
set {thisWord:thisWord, frequency:frequency} to item i of o's wordsAndFrequencies
set end of output to thisWord & ": " & (tab & frequency)
end repeat
set astid to AppleScript's text item delimiters
set AppleScript's text item delimiters to linefeed
set output to output as text
set AppleScript's text item delimiters to astid
return output
end wordFrequency
-- Test code: set filePath to POSIX path of ((path to desktop as text) & "www.rosettacode.org:Word frequency:135-0.txt") set n to 10 return wordFrequency(filePath, n)</lang>
- Output:
<lang applescript>"The 10 most frequently occurring words in the file are: The: 41092 Of: 19954 And: 14943 A: 14545 To: 13953 In: 11219 He: 9649 Was: 8622 That: 7924 It: 6661"</lang>
AutoHotkey
<lang AutoHotkey>URLDownloadToFile, http://www.gutenberg.org/files/135/135-0.txt, % A_temp "\tempfile.txt" FileRead, H, % A_temp "\tempfile.txt" FileDelete, % A_temp "\tempfile.txt" words := [] while pos := RegExMatch(H, "\balpha:+\b", m, A_Index=1?1:pos+StrLen(m)) words[m] := words[m] ? words[m] + 1 : 1 for word, count in words list .= count "`t" word "`r`n" Sort, list, RN loop, parse, list, `n, `r { result .= A_LoopField "`r`n" if A_Index = 10 break } MsgBox % "Freq`tWord`n" result return</lang>
Outputs:
Freq Word 41036 The 19946 of 14940 and 14589 A 13939 TO 11204 in 9645 HE 8619 WAS 7922 THAT 6659 it
AWK
<lang AWK>
- syntax: GAWK -f WORD_FREQUENCY.AWK [-v show=x] LES_MISERABLES.TXT
- A word is anything separated by white space.
- Therefor "this" and "this." are different.
- But "This" and "this" are identical.
- As I am "free to define what a letter is" I have chosen to allow
- numerics and all special characters as they are usually considered
- parts of words in text processing applications.
{ nbytes += length($0) + 2 # +2 for CR/LF
nfields += NF
$0 = tolower($0)
for (i=1; i<=NF; i++) {
arr[$i]++
}
} END {
show = (show == "") ? 10 : show
width1 = length(show)
PROCINFO["sorted_in"] = "@val_num_desc"
for (i in arr) {
if (width2 == 0) { width2 = length(arr[i]) }
if (n++ >= show) { break }
printf("%*d %*d %s\n",width1,n,width2,arr[i],i)
}
printf("input: %d records, %d bytes, %d words of which %d are unique\n",NR,nbytes,nfields,length(arr))
exit(0)
} </lang>
- Output:
1 40372 the 2 19868 of 3 14472 and 4 14278 a 5 13589 to 6 11024 in 7 9213 he 8 8347 was 9 7250 that 10 6414 his input: 73829 records, 3369772 bytes, 568744 words of which 50394 are unique
BASIC
QB64
This is a rather long code. I fulfilled the requirement with QB64. It "cleans" each word so it takes as a word anything that begins and ends with a letter. It works with arrays. Amazing the speed of QB64 to do this job with such a big file as Les Miserables.txt. <lang QBASIC> OPTION _EXPLICIT
' SUBs and FUNCTIONs DECLARE SUB CountWords (FromString AS STRING) DECLARE SUB QuickSort (lLeftN AS LONG, lRightN AS LONG, iMode AS INTEGER) DECLARE SUB ShowResults () DECLARE SUB ShowCompletion () DECLARE SUB TopCounted () DECLARE FUNCTION InsertWord& (WhichWord AS STRING) DECLARE FUNCTION BinarySearch& (LookFor AS STRING, RetPos AS INTEGER) DECLARE FUNCTION CleanWord$ (WhichWord AS STRING)
' Var DIM iFile AS INTEGER DIM iCol AS INTEGER DIM iFil AS INTEGER DIM iStep AS INTEGER DIM iBar AS INTEGER DIM iBlock AS INTEGER DIM lIni AS LONG DIM lEnd AS LONG DIM lLines AS LONG DIM lLine AS LONG DIM lLenF AS LONG DIM iRuns AS INTEGER DIM lMaxWords AS LONG DIM sTimer AS SINGLE DIM strFile AS STRING DIM strKey AS STRING DIM strText AS STRING DIM strDate AS STRING DIM strTime AS STRING DIM strBar AS STRING DIM lWords AS LONG DIM strWords AS STRING CONST AddWords = 100 CONST TopCount = 10 CONST FALSE = 0, TRUE = NOT FALSE
' Initialize iFile = FREEFILE lIni = 1 strDate = DATE$ strTime = TIME$ lEnd = 0 lMaxWords = 1000 REDIM strWords(lIni TO lMaxWords) AS STRING REDIM lWords(lIni TO lMaxWords) AS LONG REDIM lTopWords(1) AS LONG REDIM strTopWords(1) AS STRING
' ---Main program loop $RESIZE:SMOOTH DO
DO
CLS
PRINT "This program will count how many words are in a text file and shows the 10"
PRINT "most used of them."
PRINT
INPUT "Document to open (TXT file) (f=see files): ", strFile
IF UCASE$(strFile) = "F" THEN
strFile = ""
FILES
DO: LOOP UNTIL INKEY$ <> ""
END IF
LOOP UNTIL strFile <> ""
OPEN strFile FOR BINARY AS #iFile
IF LOF(iFile) > 0 THEN
iRuns = iRuns + 1
CLOSE #iFile
' Opens the document file to analyze it
sTimer = TIMER
ON TIMER(1) GOSUB ShowAdvance
OPEN strFile FOR INPUT AS #iFile
lLenF = LOF(iFile)
PRINT "Looking for words in "; strFile; ". File size:"; STR$(lLenF); ". ";: iCol = POS(0): PRINT "Initializing";
COLOR 23: PRINT "...";: COLOR 7
' Count how many lines has the file
lLines = 0
DO WHILE NOT EOF(iFile)
LINE INPUT #iFile, strText
lLines = lLines + 1
LOOP
CLOSE #iFile
' Shows the bar
LOCATE , iCol: PRINT "Initialization complete."
PRINT
PRINT "Processing"; lLines; "lines";: COLOR 23: PRINT "...": COLOR 7
iFil = CSRLIN
iCol = POS(0)
iBar = 80
iBlock = 80 / lLines
IF iBlock = 0 THEN iBlock = 1
PRINT STRING$(iBar, 176)
lLine = 0
iStep = lLines * iBlock / iBar
IF iStep = 0 THEN iStep = 1
IF iStep > 20 THEN
TIMER ON
END IF
OPEN strFile FOR INPUT AS #iFile
DO WHILE NOT EOF(iFile)
lLine = lLine + 1
IF (lLine MOD iStep) = 0 THEN
strBar = STRING$(iBlock * (lLine / iStep), 219)
LOCATE iFil, 1
PRINT strBar
ShowCompletion
END IF
LINE INPUT #iFile, strText
CountWords strText
strKey = INKEY$
LOOP
ShowCompletion
CLOSE #iFile
TIMER OFF
LOCATE iFil - 1, 1
PRINT "Done!" + SPACE$(70)
strBar = STRING$(iBar, 219)
LOCATE iFil, 1
PRINT strBar
LOCATE iFil + 5, 1
PRINT "Finishing";: COLOR 23: PRINT "...";: COLOR 7
ShowResults
' Frees the RAM
lMaxWords = 1000
lEnd = 0
REDIM strWords(lIni TO lMaxWords) AS STRING
REDIM lWords(lIni TO lMaxWords) AS LONG
ELSE
CLOSE #iFile
KILL strFile
PRINT
PRINT "Document does not exist."
END IF
PRINT
PRINT "Try again? (Y/n)"
DO
strKey = UCASE$(INKEY$)
LOOP UNTIL strKey = "Y" OR strKey = "N" OR strKey = CHR$(13) OR strKey = CHR$(27)
LOOP UNTIL strKey = "N" OR strKey = CHR$(27) OR iRuns >= 99
CLS IF iRuns >= 99 THEN
PRINT "Maximum runs reached for this session."
END IF
PRINT "End of program" PRINT "Start date/time: "; strDate; " "; strTime PRINT "End date/time..: "; DATE$; " "; TIME$ END ' ---End main program
ShowAdvance: ShowCompletion RETURN
FUNCTION BinarySearch& (LookFor AS STRING, RetPos AS INTEGER)
' Var DIM lFound AS LONG DIM lLow AS LONG DIM lHigh AS LONG DIM lMid AS LONG DIM strLookFor AS STRING SHARED lIni AS LONG SHARED lEnd AS LONG SHARED lMaxWords AS LONG SHARED strWords() AS STRING SHARED lWords() AS LONG
' Binary search for stated word in the list
lLow = lIni
lHigh = lEnd
lFound = 0
strLookFor = UCASE$(LookFor)
DO WHILE (lFound < 1) AND (lLow <= lHigh)
lMid = (lHigh + lLow) / 2
IF strWords(lMid) = strLookFor THEN
lFound = lMid
ELSEIF strWords(lMid) > strLookFor THEN
lHigh = lMid - 1
ELSE
lLow = lMid + 1
END IF
LOOP
' Should I return the position if not found?
IF lFound = 0 AND RetPos THEN
IF lEnd < 1 THEN
lFound = 1
ELSEIF strWords(lMid) > strLookFor THEN
lFound = lMid
ELSE
lFound = lMid + 1
END IF
END IF
' Return the value BinarySearch = lFound
END FUNCTION
FUNCTION CleanWord$ (WhichWord AS STRING)
' Var DIM iSeek AS INTEGER DIM iStep AS INTEGER DIM bOK AS INTEGER DIM strWord AS STRING DIM strChar AS STRING
strWord = WhichWord
' Look for trailing wrong characters
strWord = LTRIM$(RTRIM$(strWord))
IF LEN(strWord) > 0 THEN
iStep = 0
DO
' Determines if step will be forward or backwards
IF iStep = 0 THEN
iStep = -1
ELSE
iStep = 1
END IF
' Sets the initial value of iSeek
IF iStep = -1 THEN
iSeek = LEN(strWord)
ELSE
iSeek = 1
END IF
bOK = FALSE
DO
strChar = MID$(strWord, iSeek, 1)
SELECT CASE strChar
CASE "A" TO "Z"
bOK = TRUE
CASE CHR$(129) TO CHR$(154)
bOK = TRUE
CASE CHR$(160) TO CHR$(165)
bOK = TRUE
END SELECT
' If it is not a character valid as a letter, please move one space
IF NOT bOK THEN
iSeek = iSeek + iStep
END IF
' If no letter was recognized, then exit the loop
IF iSeek < 1 OR iSeek > LEN(strWord) THEN
bOK = TRUE
END IF
LOOP UNTIL bOK
IF iStep = -1 THEN
' Reviews if a word was encountered
IF iSeek > 0 THEN
strWord = LEFT$(strWord, iSeek)
ELSE
strWord = ""
END IF
ELSEIF iStep = 1 THEN
IF iSeek <= LEN(strWord) THEN
strWord = MID$(strWord, iSeek)
ELSE
strWord = ""
END IF
END IF
LOOP UNTIL iStep = 1 OR strWord = ""
END IF
' Return the result CleanWord = strWord
END FUNCTION
SUB CountWords (FromString AS STRING)
' Var DIM iStart AS INTEGER DIM iLenW AS INTEGER DIM iLenS AS INTEGER DIM iLenD AS INTEGER DIM strString AS STRING DIM strWord AS STRING DIM lWhichWord AS LONG SHARED lEnd AS LONG SHARED lMaxWords AS LONG SHARED strWords() AS STRING SHARED lWords() AS LONG ' Converts to Upper Case and cleans leading and trailing spaces strString = UCASE$(FromString) strString = LTRIM$(RTRIM$(strString))
' Get words from string
iStart = 1
iLenW = 0
iLenS = LEN(strString)
DO WHILE iStart <= iLenS
iLenW = INSTR(iStart, strString, " ")
IF iLenW = 0 AND iStart <= iLenS THEN
iLenW = iLenS + 1
END IF
strWord = MID$(strString, iStart, iLenW - iStart)
' Will remove mid dashes or apostrophe or "â€"
iLenD = INSTR(strWord, "-")
IF iLenD < 1 THEN
iLenD = INSTR(strWord, "'")
IF iLenD < 1 THEN
iLenD = INSTR(strWord, "â€")
END IF
END IF
IF iLenD >= 2 THEN
strWord = LEFT$(strWord, iLenD - 1)
iLenW = iStart + (iLenD - 1)
END IF
strWord = CleanWord(strWord)
IF strWord <> "" THEN
' Look for the word to be counted
lWhichWord = BinarySearch(strWord, FALSE)
' If the word doesn't exist in the list, add it
IF lWhichWord = 0 THEN
lWhichWord = InsertWord(strWord)
END IF
' Count the word
IF lWhichWord > 0 THEN
lWords(lWhichWord) = lWords(lWhichWord) + 1
END IF
END IF
iStart = iLenW + 1
LOOP
END SUB
' Here a word will be inserted in the list FUNCTION InsertWord& (WhichWord AS STRING)
' Var DIM lFound AS LONG DIM lWord AS LONG DIM strWord AS STRING SHARED lIni AS LONG SHARED lEnd AS LONG SHARED lMaxWords AS LONG SHARED strWords() AS STRING SHARED lWords() AS LONG
' Look for the word in the list
strWord = UCASE$(WhichWord)
lFound = BinarySearch(WhichWord, TRUE)
IF lFound > 0 THEN
' Add one word
lEnd = lEnd + 1
' Verifies if there is still room for a new word
IF lEnd > lMaxWords THEN
lMaxWords = lMaxWords + AddWords ' Other words
IF lMaxWords > 32767 THEN
IF lEnd <= 32767 THEN
lMaxWords = 32767
ELSE
lFound = -1
END IF
END IF
IF lFound > 0 THEN
REDIM _PRESERVE strWords(lIni TO lMaxWords) AS STRING
REDIM _PRESERVE lWords(lIni TO lMaxWords) AS LONG
END IF
END IF
IF lFound > 0 THEN
' Move the words below this
IF lEnd > 1 THEN
FOR lWord = lEnd TO lFound + 1 STEP -1
strWords(lWord) = strWords(lWord - 1)
lWords(lWord) = lWords(lWord - 1)
NEXT lWord
END IF
' Insert the word in the position
strWords(lFound) = strWord
lWords(lFound) = 0
END IF
END IF
InsertWord = lFound
END FUNCTION
SUB QuickSort (lLeftN AS LONG, lRightN AS LONG, iMode AS INTEGER)
' Var DIM lPivot AS LONG DIM lLeftNIdx AS LONG DIM lRightNIdx AS LONG SHARED lWords() AS LONG SHARED strWords() AS STRING
' Clasifies from highest to lowest
lLeftNIdx = lLeftN
lRightNIdx = lRightN
IF (lRightN - lLeftN) > 0 THEN
lPivot = (lLeftN + lRightN) / 2
DO WHILE (lLeftNIdx <= lPivot) AND (lRightNIdx >= lPivot)
IF iMode = 0 THEN ' Ascending
DO WHILE (lWords(lLeftNIdx) < lWords(lPivot)) AND (lLeftNIdx <= lPivot)
lLeftNIdx = lLeftNIdx + 1
LOOP
DO WHILE (lWords(lRightNIdx) > lWords(lPivot)) AND (lRightNIdx >= lPivot)
lRightNIdx = lRightNIdx - 1
LOOP
ELSE ' Descending
DO WHILE (lWords(lLeftNIdx) > lWords(lPivot)) AND (lLeftNIdx <= lPivot)
lLeftNIdx = lLeftNIdx + 1
LOOP
DO WHILE (lWords(lRightNIdx) < lWords(lPivot)) AND (lRightNIdx >= lPivot)
lRightNIdx = lRightNIdx - 1
LOOP
END IF
SWAP lWords(lLeftNIdx), lWords(lRightNIdx)
SWAP strWords(lLeftNIdx), strWords(lRightNIdx)
lLeftNIdx = lLeftNIdx + 1
lRightNIdx = lRightNIdx - 1
IF (lLeftNIdx - 1) = lPivot THEN
lRightNIdx = lRightNIdx + 1
lPivot = lRightNIdx
ELSEIF (lRightNIdx + 1) = lPivot THEN
lLeftNIdx = lLeftNIdx - 1
lPivot = lLeftNIdx
END IF
LOOP
QuickSort lLeftN, lPivot - 1, iMode
QuickSort lPivot + 1, lRightN, iMode
END IF
END SUB
SUB ShowCompletion ()
' Var SHARED iFil AS INTEGER SHARED lLine AS LONG SHARED lLines AS LONG SHARED lEnd AS LONG
LOCATE iFil + 1, 1 PRINT "Lines analyzed :"; lLine PRINT USING "% of completion: ###%"; (lLine / lLines) * 100 PRINT "Words found....:"; lEnd
END SUB
SUB ShowResults ()
' Var DIM iMaxL AS INTEGER DIM iMaxW AS INTEGER DIM lWord AS LONG DIM lHowManyWords AS LONG DIM strString AS STRING DIM strFileR AS STRING SHARED lIni AS LONG SHARED lEnd AS LONG SHARED lLenF AS LONG SHARED lMaxWords AS LONG SHARED sTimer AS SINGLE SHARED strFile AS STRING SHARED strWords() AS STRING SHARED lWords() AS LONG SHARED strTopWords() AS STRING SHARED lTopWords() AS LONG SHARED iRuns AS INTEGER
' Show results
' Creates file name lWord = INSTR(strFile, ".") IF lWord = 0 THEN lWord = LEN(strFile) strFileR = LEFT$(strFile, lWord) IF RIGHT$(strFileR, 1) <> "." THEN strFileR = strFileR + "."
' Retrieves the longest word found and the highest count
FOR lWord = lIni TO lEnd
' Gets the longest word found
IF LEN(strWords(lWord)) > iMaxL THEN
iMaxL = LEN(strWords(lWord))
END IF
lHowManyWords = lHowManyWords + lWords(lWord) NEXT lWord IF iMaxL > 60 THEN iMaxW = 60 ELSE iMaxW = iMaxL
' Gets top counted TopCounted
' Shows the results
CLS
PRINT "File analyzed : "; strFile
PRINT "Length of file:"; lLenF
PRINT "Time lapse....:"; TIMER - sTimer;"seconds"
PRINT "Words found...:"; lHowManyWords; "(Unique:"; STR$(lEnd); ")"
PRINT "Longest word..:"; iMaxL
PRINT
PRINT "The"; TopCount; "most used are:"
PRINT STRING$(iMaxW, "-"); "+"; STRING$(80 - (iMaxW + 1), "-")
PRINT " Word"; SPACE$(iMaxW - 5); "| Count"
PRINT STRING$(iMaxW, "-"); "+"; STRING$(80 - (iMaxW + 1), "-")
strString = "\" + SPACE$(iMaxW - 2) + "\| #########,"
FOR lWord = lIni TO TopCount
PRINT USING strString; strTopWords(lWord); lTopWords(lWord)
NEXT lWord
PRINT STRING$(iMaxW, "-"); "+"; STRING$(80 - (iMaxW + 1), "-")
PRINT "See files "; strFileR + "S" + LTRIM$(STR$(iRuns)); " and "; strFileR + "C" + LTRIM$(STR$(iRuns)); " to see the full list."
END SUB
SUB TopCounted ()
' Var DIM lWord AS LONG DIM strFileR AS STRING DIM iFile AS INTEGER CONST Descending = 1 SHARED lIni AS LONG SHARED lEnd AS LONG SHARED lMaxWords AS LONG SHARED strWords() AS STRING SHARED lWords() AS LONG SHARED strTopWords() AS STRING SHARED lTopWords() AS LONG SHARED iRuns AS INTEGER SHARED strFile AS STRING
' Assigns new dimmentions REDIM strTopWords(lIni TO TopCount) AS STRING REDIM lTopWords(lIni TO TopCount) AS LONG
' Saves the current values
lWord = INSTR(strFile, ".")
IF lWord = 0 THEN lWord = LEN(strFile)
strFileR = LEFT$(strFile, lWord)
IF RIGHT$(strFileR, 1) <> "." THEN strFileR = strFileR + "."
iFile = FREEFILE
OPEN strFileR + "S" + LTRIM$(STR$(iRuns)) FOR OUTPUT AS #iFile
FOR lWord = lIni TO lEnd
WRITE #iFile, strWords(lWord), lWords(lWord)
NEXT lWord
CLOSE #iFile
' Classifies the counted in descending order QuickSort lIni, lEnd, Descending
' Now, saves the required values in the arrays
FOR lWord = lIni TO TopCount
strTopWords(lWord) = strWords(lWord)
lTopWords(lWord) = lWords(lWord)
NEXT lWord
' Now, saves the order from the file
OPEN strFileR + "C" + LTRIM$(STR$(iRuns)) FOR OUTPUT AS #iFile
FOR lWord = lIni TO lEnd
WRITE #iFile, strWords(lWord), lWords(lWord)
NEXT lWord
CLOSE #iFile
END SUB </lang>
- Output:
This program will count how many words are in a text file and shows the 10 most used of them. Document to open (TXT file) (f=see files): miserabl.txt Looking for words in miserabl.txt. File size: 3369775. Initialization complete. Processing... Done! Lines analyzed : 72917 % of completion: 100% Words found....: 23288 Finishing... Lenght of file: 3369775 Time lapse....: 35 seconds Words found...: 578614 (Unique: 23538) Longest word..: 25 The 10 most used are: ---------------------------+------------------------------------------------------------------------ Word | Count ---------------------------+------------------------------------------------------------------------ THE | 40,751 OF | 19,949 AND | 14,891 A | 14,430 TO | 13,923 IN | 11,189 HE | 9,605 WAS | 8,617 THAT | 7,833 IT | 6.579 ---------------------------+------------------------------------------------------------------------ See files miserabl.S1 and miserabl.C1 to see the full list. Try again? (Y/n)
BaCon
Removing all punctuation, digits, tabs and carriage returns. So "This", "this" and "this." are the same. Full support for UTF8 characters in words. The code itself could be smaller, but for sake of clarity all has been written explicitly. <lang bacon>' We do not count superfluous spaces as words OPTION COLLAPSE TRUE
' Optional: use TRE regex library to speed up the program PRAGMA RE tre INCLUDE <tre/regex.h> LDFLAGS -ltre
' We're using associative arrays DECLARE frequency ASSOC NUMBER
' Load the text and remove all punctuation, digits, tabs and cr book$ = EXTRACT$(LOAD$("miserables.txt"), "punct:|digit:|[\t\r]", TRUE)
' Count each word in lowercase FOR word$ IN REPLACE$(book$, NL$, CHR$(32))
INCR frequency(LCASE$(word$))
NEXT
' Sort the associative array and then map the index to a string array LOOKUP frequency TO term$ SIZE x SORT DOWN
' Show results FOR i = 0 TO 9
PRINT term$[i], " : ", frequency(term$[i])
NEXT</lang>
- Output:
the : 40440 of : 19903 and : 14738 a : 14306 to : 13630 in : 11083 he : 9452 was : 8605 that : 7535 his : 6434
Batch File
This takes a very long time per word thus I have chosen to feed it a 200 line sample and go from there.
You could cut the length of this down drastically if you didn't need to be able to recall the word at nth position and wished only to display the top 10 words.
<lang dos> @echo off
call:wordCount 1 2 3 4 5 6 7 8 9 10 42 101
pause>nul exit
- wordCount
setlocal enabledelayedexpansion
set word=100000 set line=0 for /f "delims=" %%i in (input.txt) do ( set /a line+=1 for %%j in (%%i) do ( if not !skip%%j!==true ( echo line !line! ^| word !word:~-5! - "%%~j"
type input.txt | find /i /c "%%~j" > count.tmp set /p tmpvar=<count.tmp
set tmpvar=000000000!tmpvar! set tmpvar=!tmpvar:~-10! set count[!word!]=!tmpvar! %%~j
set "skip%%j=true" set /a word+=1 ) ) ) del count.tmp
set wordcount=0 for /f "tokens=1,2 delims= " %%i in ('set count ^| sort /+14 /r') do ( set /a wordcount+=1 for /f "tokens=2 delims==" %%k in ("%%i") do ( set word[!wordcount!]=!wordcount!. %%j - %%k ) )
cls for %%i in (%*) do echo !word[%%i]! endlocal goto:eof
</lang>
Output
1. - 0000000140 I 2. - 0000000140 a 3. - 0000000118 He 4. - 0000000100 the 5. - 0000000080 an 6. - 0000000075 in 7. - 0000000066 at 8. - 0000000062 is 9. - 0000000058 on 10. - 0000000058 as 42. - 0000000010 with 101. - 0000000004 ears
Bracmat
This solution assumes that words consists of characters that exist in a lowercase and a highercase version. So it won't work with many non-European alphabets.
The built-in vap function can take either two or three arguments. The first argument must be the name of a function or a function definition. The second argument must be a string. The two-argument version maps the function to each character in the string. The three-argument version splits the string at each occurrence of the third argument, which must be a single character, and applies the function to the intervening substrings. The output of vap is a space-separated list of results from the function argument.
The expression !('($arg:?A [($pivot) ?Z)) must be read as follows:
The subexpression '($arg:?A [($pivot) ?Z) is a macro expression. The symbols arg and pivot, which are the right hand sides of $ operators with empty left hand side, are replaced by the actual values of !arg and !pivot. The whole subexpression is made the right hand side of a = operator with empty left hand side, e.g.
=a b c d e:?A [2 ?Z. The = operator protects the subexpression against evaluation. By prefixing the expression with the ! unary operator (which normally is used to obtain the value of a variable), the pattern match operation a b c d e:?A [2 ?Z is executed, assigning a b to A and assigning c d e to Z.
The reason for using a macro expression is that the evaluation of a pattern match operation with pattern variable as in !arg:?A [!pivot ?Z is unecessary slow, since !pivot is evaluated up to !pivot+1 times.
<lang bracmat> ( 10-most-frequent-words
= MergeSort { Local variable declarations. }
types
sorted-words
frequency
type
most-frequent-words
. ( MergeSort { Definition of function MergeSort. }
= A N Z pivot
. !arg:? [?N { [?N is a subpattern that counts the number of preceding elements }
& ( !N:>1 { if N at least 2 ... }
& div$(!N.2):?pivot { divide N by 2 ... }
& !('($arg:?A [($pivot) ?Z)) { split list in two halves A and Z ... }
& MergeSort$!A+MergeSort$!Z { sort each of A and Z and return sum }
| !arg { else just return a single element}
)
)
& MergeSort { Sort }
$ ( vap { Split second argument at each occurrence of third character and apply first argument to each chunk. }
$ ( (=.low$!arg) { Return input, lowercased. }
. str
$ ( vap { Vaporize second argument in UTF-8 or Latin-1 characters and apply first argument to each of them. }
$ ( (
=
. upp$!arg:low$!arg&\n { Return newline instead of non-alphabetic character. }
| !arg { Return (Euro-centric) alphabetic character.}
)
. get$(!arg,NEW STR) { Read input text as a single string. }
)
)
. \n { Split at newlines }
)
)
: ?sorted-words { Assign sum of (frequency*lowercasedword) terms to sorted-words. }
& :?types { Initialize types as an empty list. }
& whl { Loop until right hand side fails. }
' ( !sorted-words:#?frequency*%@?type+?sorted-words { Extract first frequency*type term from sum. }
& (!frequency.!type) !types:?types { Prepend (frequency.type) pair to types list}
)
& MergeSort$!types { Sort the list of (frequency.type) pairs. }
: (?+[-11+?most-frequent-words|?most-frequent-words) { Pick the last 10 terms from the sum returned by MergeSort. }
& !most-frequent-words { Return the last 10 terms. }
)
& out$(10-most-frequent-words$"135-0.txt") { Call 10-most-frequent-words with name of inout file and print result to screen. }</lang> Output
(6661.it) + (7924.that) + (8622.was) + (9649.he) + (11219.in) + (13953.to) + (14546.a) + (14943.and) + (19954.of) + (41092.the)
C
Words are defined by the regular expression "\w+". <lang c>#include <stdbool.h>
- include <stdio.h>
- include <glib.h>
typedef struct word_count_tag {
const char* word; size_t count;
} word_count;
int compare_word_count(const void* p1, const void* p2) {
const word_count* w1 = p1;
const word_count* w2 = p2;
if (w1->count > w2->count)
return -1;
if (w1->count < w2->count)
return 1;
return 0;
}
bool get_top_words(const char* filename, size_t count) {
GError* error = NULL;
GMappedFile* mapped_file = g_mapped_file_new(filename, FALSE, &error);
if (mapped_file == NULL) {
fprintf(stderr, "%s\n", error->message);
g_error_free(error);
return false;
}
const char* text = g_mapped_file_get_contents(mapped_file);
if (text == NULL) {
fprintf(stderr, "File %s is empty\n", filename);
g_mapped_file_unref(mapped_file);
return false;
}
gsize file_size = g_mapped_file_get_length(mapped_file);
// Store word counts in a hash table
GHashTable* ht = g_hash_table_new_full(g_str_hash, g_str_equal,
g_free, g_free);
GRegex* regex = g_regex_new("\\w+", 0, 0, NULL);
GMatchInfo* match_info;
g_regex_match_full(regex, text, file_size, 0, 0, &match_info, NULL);
while (g_match_info_matches(match_info)) {
char* word = g_match_info_fetch(match_info, 0);
char* lower = g_utf8_strdown(word, -1);
g_free(word);
size_t* count = g_hash_table_lookup(ht, lower);
if (count != NULL) {
++*count;
g_free(lower);
} else {
count = g_new(size_t, 1);
*count = 1;
g_hash_table_insert(ht, lower, count);
}
g_match_info_next(match_info, NULL);
}
g_match_info_free(match_info);
g_regex_unref(regex);
g_mapped_file_unref(mapped_file);
// Sort words in decreasing order of frequency
size_t size = g_hash_table_size(ht);
word_count* words = g_new(word_count, size);
GHashTableIter iter;
gpointer key, value;
g_hash_table_iter_init(&iter, ht);
for (size_t i = 0; g_hash_table_iter_next(&iter, &key, &value); ++i) {
words[i].word = key;
words[i].count = *(size_t*)value;
}
qsort(words, size, sizeof(word_count), compare_word_count);
// Print the most common words
if (count > size)
count = size;
printf("Top %lu words\n", count);
printf("Rank\tCount\tWord\n");
for (size_t i = 0; i < count; ++i)
printf("%lu\t%lu\t%s\n", i + 1, words[i].count, words[i].word);
g_free(words);
g_hash_table_destroy(ht);
return true;
}
int main(int argc, char** argv) {
if (argc != 2) {
fprintf(stderr, "usage: %s file\n", argv[0]);
return EXIT_FAILURE;
}
if (!get_top_words(argv[1], 10))
return EXIT_FAILURE;
return EXIT_SUCCESS;
}</lang>
- Output:
Top 10 words Rank Count Word 1 41039 the 2 19951 of 3 14942 and 4 14527 a 5 13941 to 6 11209 in 7 9646 he 8 8620 was 9 7922 that 10 6659 it
C#
<lang csharp>using System; using System.Collections.Generic; using System.IO; using System.Linq; using System.Text.RegularExpressions;
namespace WordCount {
class Program {
static void Main(string[] args) {
var text = File.ReadAllText("135-0.txt").ToLower();
var match = Regex.Match(text, "\\w+");
Dictionary<string, int> freq = new Dictionary<string, int>();
while (match.Success) {
string word = match.Value;
if (freq.ContainsKey(word)) {
freq[word]++;
} else {
freq.Add(word, 1);
}
match = match.NextMatch();
}
Console.WriteLine("Rank Word Frequency");
Console.WriteLine("==== ==== =========");
int rank = 1;
foreach (var elem in freq.OrderByDescending(a => a.Value).Take(10)) {
Console.WriteLine("{0,2} {1,-4} {2,5}", rank++, elem.Key, elem.Value);
}
}
}
}</lang>
- Output:
Rank Word Frequency ==== ==== ========= 1 the 41035 2 of 19946 3 and 14940 4 a 14577 5 to 13939 6 in 11204 7 he 9645 8 was 8619 9 that 7922 10 it 6659
C++
<lang cpp>#include <algorithm>
- include <cstdlib>
- include <fstream>
- include <iostream>
- include <iterator>
- include <string>
- include <unordered_map>
- include <vector>
int main(int ac, char** av) {
std::ios::sync_with_stdio(false);
int head = (ac > 1) ? std::atoi(av[1]) : 10;
std::istreambuf_iterator<char> it(std::cin), eof;
std::filebuf file;
if (ac > 2) {
if (file.open(av[2], std::ios::in), file.is_open()) {
it = std::istreambuf_iterator<char>(&file);
} else return std::cerr << "file " << av[2] << " open failed\n", 1;
}
auto alpha = [](unsigned c) { return c-'A' < 26 || c-'a' < 26; };
auto lower = [](unsigned c) { return c | '\x20'; };
std::unordered_map<std::string, int> counts;
std::string word;
for (; it != eof; ++it) {
if (alpha(*it)) {
word.push_back(lower(*it));
} else if (!word.empty()) {
++counts[word];
word.clear();
}
}
if (!word.empty()) ++counts[word]; // if file ends w/o ws
std::vector<std::pair<const std::string,int> const*> out;
for (auto& count : counts) out.push_back(&count);
std::partial_sort(out.begin(),
out.size() < head ? out.end() : out.begin() + head,
out.end(), [](auto const* a, auto const* b) {
return a->second > b->second;
});
if (out.size() > head) out.resize(head);
for (auto const& count : out) {
std::cout << count->first << ' ' << count->second << '\n';
}
return 0;
} </lang>
- Output:
$ ./a.out 10 135-0.txt the 41093 of 19954 and 14943 a 14558 to 13953 in 11219 he 9649 was 8622 that 7924 it 6661
Alternative
<lang cpp>#include <algorithm>
- include <iostream>
- include <fstream>
- include <map>
- include <regex>
- include <string>
- include <vector>
int main() {
std::regex wordRgx("\\w+");
std::map<std::string, int> freq;
std::string line;
const int top = 10;
std::ifstream in("135-0.txt");
if (!in.is_open()) {
std::cerr << "Failed to open file\n";
return 1;
}
while (std::getline(in, line)) {
auto words_itr = std::sregex_iterator(
line.cbegin(), line.cend(), wordRgx);
auto words_end = std::sregex_iterator();
while (words_itr != words_end) {
auto match = *words_itr;
auto word = match.str();
if (word.size() > 0) {
transform (word.begin(), word.end(), word.begin(), ::tolower);
auto entry = freq.find(word);
if (entry != freq.end()) {
entry->second++;
} else {
freq.insert(std::make_pair(word, 1));
}
}
words_itr = std::next(words_itr);
}
}
in.close();
std::vector<std::pair<std::string, int>> pairs;
for (auto iter = freq.cbegin(); iter != freq.cend(); ++iter) {
pairs.push_back(*iter);
}
std::sort(pairs.begin(), pairs.end(), [](auto& a, auto& b) {
return a.second > b.second;
});
std::cout << "Rank Word Frequency\n"
"==== ==== =========\n";
int rank = 1;
for (auto iter = pairs.cbegin(); iter != pairs.cend() && rank <= top; ++iter) {
std::printf("%2d %4s %5d\n", rank++, iter->first.c_str(), iter->second);
}
return 0;
}</lang>
- Output:
Rank Word Frequency ==== ==== ========= 1 the 36636 2 of 19615 3 and 14079 4 to 13535 5 a 13527 6 in 10256 7 was 8543 8 that 7324 9 he 6814 10 had 6139
Clojure
<lang clojure>(defn count-words [file n]
(->> file slurp clojure.string/lower-case (re-seq #"\w+") frequencies (sort-by val >) (take n)))</lang>
- Output:
user=> (count-words "135-0.txt" 10) (["the" 41036] ["of" 19946] ["and" 14940] ["a" 14589] ["to" 13939] ["in" 11204] ["he" 9645] ["was" 8619] ["that" 7922] ["it" 6659])
COBOL
<lang COBOL>
IDENTIFICATION DIVISION.
PROGRAM-ID. WordFrequency.
AUTHOR. Bill Gunshannon.
DATE-WRITTEN. 30 Jan 2020.
************************************************************
** Program Abstract:
** Given a text file and an integer n, print the n most
** common words in the file (and the number of their
** occurrences) in decreasing frequency.
**
** A file named Parameter.txt provides this information.
** Format is:
** 12345678901234567890123456789012345678901234567890
** |------------------|----|
** ^^^^^^^^^^^^^^^^ ^^^^
** | |
** Source Text File Number of words with count
** 20 Characters 5 digits with leading zeroes
**
**
************************************************************
ENVIRONMENT DIVISION.
INPUT-OUTPUT SECTION.
FILE-CONTROL.
SELECT Parameter-File ASSIGN TO "Parameter.txt"
ORGANIZATION IS LINE SEQUENTIAL.
SELECT Input-File ASSIGN TO Source-Text
ORGANIZATION IS LINE SEQUENTIAL.
SELECT Word-File ASSIGN TO "Word.txt"
ORGANIZATION IS LINE SEQUENTIAL.
SELECT Output-File ASSIGN TO "Output.txt"
ORGANIZATION IS LINE SEQUENTIAL.
SELECT Print-File ASSIGN TO "Printer.txt"
ORGANIZATION IS LINE SEQUENTIAL.
SELECT Sort-File ASSIGN TO DISK.
DATA DIVISION.
FILE SECTION.
FD Parameter-File
DATA RECORD IS Parameter-Record.
01 Parameter-Record.
05 Source-Text PIC X(20).
05 How-Many PIC 99999.
FD Input-File
DATA RECORD IS Input-Record.
01 Input-Record.
05 Input-Line PIC X(80).
FD Word-File
DATA RECORD IS Word-Record.
01 Word-Record.
05 Input-Word PIC X(20).
FD Output-File
DATA RECORD IS Output-Rec.
01 Output-Rec.
05 Output-Rec-Word PIC X(20).
05 Output-Rec-Word-Cnt PIC 9(5).
FD Print-File
DATA RECORD IS Print-Rec.
01 Print-Rec.
05 Print-Rec-Word PIC X(20).
05 Print-Rec-Word-Cnt PIC 9(5).
SD Sort-File.
01 Sort-Rec.
05 Sort-Word PIC X(20).
05 Sort-Word-Cnt PIC 9(5).
WORKING-STORAGE SECTION.
01 Eof PIC X VALUE 'F'.
01 InLine PIC X(80).
01 Word1 PIC X(20).
01 Current-Word PIC X(20).
01 Current-Word-Cnt PIC 9(5).
01 Pos PIC 99
VALUE 1.
01 Cnt PIC 99.
01 Report-Rank.
05 IRank PIC 99999
VALUE 1.
05 Rank PIC ZZZZ9.
PROCEDURE DIVISION.
Main-Program.
**
** Read the Parameters
**
OPEN INPUT Parameter-File.
READ Parameter-File.
CLOSE Parameter-File.
**
** Open Files for first stage
**
OPEN INPUT Input-File.
OPEN OUTPUT Word-File.
**
** Pare\se the Source Text into a file of invidual words
**
PERFORM UNTIL Eof = 'T'
READ Input-File
AT END MOVE 'T' TO Eof
END-READ
PERFORM Parse-a-Words
MOVE SPACES TO Input-Record
MOVE 1 TO Pos
END-PERFORM.
**
** Cleanup from the first stage
**
CLOSE Input-File Word-File
**
** Sort the individual words in alphabetical order
**
SORT Sort-File
ON ASCENDING KEY Sort-Word
USING Word-File
GIVING Word-File.
**
** Count each time a word is used
**
PERFORM Collect-Totals.
**
** Sort data by number of usages per word
**
SORT Sort-File
ON DESCENDING KEY Sort-Word-Cnt
USING Output-File
GIVING Print-File.
**
** Show the work done
**
OPEN INPUT Print-File.
DISPLAY " Rank Word Frequency"
PERFORM How-Many TIMES
READ Print-File
MOVE IRank TO Rank
DISPLAY Rank " " Print-Rec
ADD 1 TO IRank
END-PERFORM.
**
** Cleanup
**
CLOSE Print-File.
CALL "C$DELETE" USING "Word.txt" ,0
CALL "C$DELETE" USING "Output.txt" ,0
STOP RUN.
Parse-a-Words.
INSPECT Input-Record CONVERTING '-.,"();:/[]{}!?|' TO SPACE
PERFORM UNTIL Pos > FUNCTION STORED-CHAR-LENGTH(Input-Record)
UNSTRING Input-Record DELIMITED BY SPACE INTO Word1
WITH POINTER Pos TALLYING IN Cnt
MOVE FUNCTION TRIM(FUNCTION LOWER-CASE(Word1)) TO Word-Record
IF Word-Record NOT EQUAL SPACES AND Word-Record IS ALPHABETIC
THEN WRITE Word-Record
END-IF
END-PERFORM.
Collect-Totals.
MOVE 'F' to Eof
OPEN INPUT Word-File
OPEN OUTPUT Output-File
READ Word-File
MOVE Input-Word TO Current-Word
MOVE 1 to Current-Word-Cnt
PERFORM UNTIL Eof = 'T'
READ Word-File
AT END MOVE 'T' TO Eof
END-READ
IF FUNCTION TRIM(Word-Record)
EQUAL
FUNCTION TRIM(Current-Word)
THEN
ADD 1 to Current-Word-Cnt
ELSE
MOVE Current-Word TO Output-Rec-Word
MOVE Current-Word-Cnt TO Output-Rec-Word-Cnt
WRITE Output-Rec
MOVE 1 to Current-Word-Cnt
MOVE Word-Record TO Current-Word
MOVE SPACES TO Input-Record
END-IF
END-PERFORM.
CLOSE Word-File Output-File.
END-PROGRAM.
</lang>
- Output:
Rank Word Frequency
1 the 40551
2 of 19806
3 and 14730
4 a 14351
5 to 13775
6 in 11074
7 he 09480
8 was 08613
9 that 07632
10 his 06446
11 it 06335
12 had 06181
13 is 06097
14 which 05135
15 with 04469
Common Lisp
<lang lisp> (defun count-word (n pathname)
(with-open-file (s pathname :direction :input)
(loop for line = (read-line s nil nil) while line
nconc (list-symb (drop-noise line)) into words
finally (return (subseq (sort (pair words)
#'> :key #'cdr)
0 n)))))
(defun list-symb (s)
(let ((*read-eval* nil))
(read-from-string (concatenate 'string "(" s ")"))))
(defun drop-noise (s)
(delete-if-not #'(lambda (x) (or (alpha-char-p x)
(equal x #\space)
(equal x #\-))) s))
(defun pair (words &aux (hash (make-hash-table)) ac)
(dolist (word words) (incf (gethash word hash 0))) (maphash #'(lambda (e n) (push `(,e . ,n) ac)) hash) ac)
</lang>
- Output:
> (count-word 10 "c:/temp/135-0.txt") ((THE . 40738) (OF . 19922) (AND . 14878) (A . 14419) (TO . 13702) (IN . 11172) (HE . 9577) (WAS . 8612) (THAT . 7768) (IT . 6467))
Crystal
<lang ruby>require "http/client" require "regex"
- Get the text from the internet
response = HTTP::Client.get "https://www.gutenberg.org/files/135/135-0.txt" text = response.body
text
.downcase
.scan(/[a-zA-ZáéíóúÁÉÍÓÚâêôäüöàèìòùñ']+/)
.reduce({} of String => Int32) { |hash, match|
word = match[0]
hash[word] = hash.fetch(word, 0) + 1 # using fetch to set a default value (1) to the new found word
hash
}
.to_a # convert the returned hash to an array of tuples (String, Int32) -> {word, sum}
.sort { |a, b| b[1] <=> a[1] }[0..9] # sort and get the first 10 elements
.each_with_index(1) { |(word, n), i| puts "#{i} \t #{word} \t #{n}" } # print the result
</lang>
- Output:
1 the 41092 2 of 19954 3 and 14943 4 a 14556 5 to 13953 6 in 11219 7 he 9649 8 was 8622 9 that 7924 10 it 6661
D
<lang D>import std.algorithm : sort; import std.array : appender, split; import std.range : take; import std.stdio : File, writefln, writeln; import std.typecons : Tuple; import std.uni : toLower;
//Container for a word and how many times it has been seen alias Pair = Tuple!(string, "k", int, "v");
void main() {
int[string] wcnt;
//Read the file line by line
foreach (line; File("135-0.txt").byLine) {
//Split the words on whitespace
foreach (word; line.split) {
//Increment the times the word has been seen
wcnt[word.toLower.idup]++;
}
}
//Associative arrays cannot be sort, so put the key/value in an array
auto wb = appender!(Pair[]);
foreach(k,v; wcnt) {
wb.put(Pair(k,v));
}
Pair[] sw = wb.data.dup;
//Sort the array, and display the top ten values
writeln("Rank Word Frequency");
int rank=1;
foreach (word; sw.sort!"a.v>b.v".take(10)) {
writefln("%4s %-10s %9s", rank++, word.k, word.v);
}
}</lang>
- Output:
Rank Word Frequency 1 the 40368 2 of 19863 3 and 14470 4 a 14277 5 to 13587 6 in 11019 7 he 9212 8 was 8346 9 that 7251 10 his 6414
Delphi
<lang Delphi> program Word_frequency;
{$APPTYPE CONSOLE}
uses
System.SysUtils, System.IOUtils, System.Generics.Collections, System.Generics.Defaults, System.RegularExpressions;
type
TWords = TDictionary<string, Integer>;
TFreqPair = TPair<string, Integer>;
TFreq = TArray<TFreqPair>;
function CreateValueCompare: IComparer<TFreqPair>; begin
Result := TComparer<TFreqPair>.Construct(
function(const Left, Right: TFreqPair): Integer
begin
Result := Right.Value - Left.Value;
end);
end;
function WordFrequency(const Text: string): TFreq; var
words: TWords; match: TMatch; w: string;
begin
words := TWords.Create();
match := TRegEx.Match(Text, '\w+');
while match.Success do
begin
w := match.Value;
if words.ContainsKey(w) then
words[w] := words[w] + 1
else
words.Add(w, 1);
match := match.NextMatch();
end;
Result := words.ToArray; words.Free; TArray.Sort<TFreqPair>(Result, CreateValueCompare);
end;
var
Text: string; rank: integer; Freq: TFreq; w: TFreqPair;
begin
Text := TFile.ReadAllText('135-0.txt').ToLower();
Freq := WordFrequency(Text);
Writeln('Rank Word Frequency');
Writeln('==== ==== =========');
for rank := 1 to 10 do
begin
w := Freq[rank - 1];
Writeln(format('%2d %6s %5d', [rank, w.Key, w.Value]));
end;
readln;
end. </lang>
- Output:
Rank Word Frequency ==== ==== ========= 1 the 41040 2 of 19951 3 and 14942 4 a 14539 5 to 13941 6 in 11209 7 he 9646 8 was 8620 9 that 7922 10 it 6659
F#
<lang fsharp> open System.IO open System.Text.RegularExpressions let g=Regex("[A-Za-zÀ-ÿ]+").Matches(File.ReadAllText "135-0.txt") [for n in g do yield n.Value.ToLower()]|>List.countBy(id)|>List.sortBy(fun n->(-(snd n)))|>List.take 10|>List.iter(fun n->printfn "%A" n) </lang>
- Output:
("the", 41088)
("of", 19949)
("and", 14942)
("a", 14596)
("to", 13951)
("in", 11214)
("he", 9648)
("was", 8621)
("that", 7924)
("it", 6661)
Factor
This program expects stdin to read from a file via the command line. ( e.g. invoking the program in Windows: >factor word-count.factor < input.txt ) The definition of a word here is simply any string surrounded by some combination of spaces, punctuation, or newlines. <lang factor> USING: ascii io math.statistics prettyprint sequences splitting ; IN: rosetta-code.word-count
lines " " join " .,?!:;()\"-" split harvest [ >lower ] map sorted-histogram <reversed> 10 head . </lang>
- Output:
{
{ "the" 41021 }
{ "of" 19945 }
{ "and" 14938 }
{ "a" 14522 }
{ "to" 13938 }
{ "in" 11201 }
{ "he" 9600 }
{ "was" 8618 }
{ "that" 7822 }
{ "it" 6532 }
}
FreeBASIC
<lang freebasic>
#Include "file.bi"
type tally
as string s
as long l
end type
Sub quicksort(array() As String,begin As Long,Finish As Long)
Dim As Long i=begin,j=finish Dim As String x =array(((I+J)\2)) While I <= J While array(I) < X :I+=1:Wend While array(J) > X :J-=1:Wend If I<=J Then Swap array(I),array(J): I+=1:J-=1 Wend If J >begin Then quicksort(array(),begin,J) If I <Finish Then quicksort(array(),I,Finish)
End Sub
Sub tallysort(array() As tally,begin As Long,Finish As long)
Dim As Long i=begin,j=finish Dim As tally x =array(((I+J)\2)) While I <= J While array(I).l > X .l:I+=1:Wend While array(J).l < X .l:J-=1:Wend If I<=J Then Swap array(I),array(J): I+=1:J-=1 Wend If J >begin Then tallysort(array(),begin,J) If I <Finish Then tallysort(array(),I,Finish) End Sub
Function loadfile(file As String) As String
If Fileexists(file)=0 Then Print file;" not found":Sleep:End
Dim As Long f=Freefile
Open file For Binary Access Read As #f
Dim As String text
If Lof(f) > 0 Then
text = String(Lof(f), 0)
Get #f, , text
End If
Close #f
Return text
End Function
Function String_Split(s_in As String,chars As String,result() As String) As Long
Dim As Long ctr,ctr2,k,n,LC=Len(chars)
Dim As boolean tally(Len(s_in))
#macro check_instring()
n=0
While n<Lc
If chars[n]=s_in[k] Then
tally(k)=true
If (ctr2-1) Then ctr+=1
ctr2=0
Exit While
End If
n+=1
Wend
#endmacro
#macro splice()
If tally(k) Then
If (ctr2-1) Then ctr+=1:result(ctr)=Mid(s_in,k+2-ctr2,ctr2-1)
ctr2=0
End If
#endmacro
'================== LOOP TWICE =======================
For k =0 To Len(s_in)-1
ctr2+=1:check_instring()
Next k
If ctr=0 Then
If Len(s_in) Andalso Instr(chars,Chr(s_in[0])) Then ctr=1':
End If
If ctr Then Redim result(1 To ctr): ctr=0:ctr2=0 Else Return 0
For k =0 To Len(s_in)-1
ctr2+=1:splice()
Next k
'===================== Last one ========================
If ctr2>0 Then
Redim Preserve result(1 To ctr+1)
result(ctr+1)=Mid(s_in,k+1-ctr2,ctr2)
End If
Return Ubound(result)
End Function
Redim As String s() redim as tally t() dim as string p1,p2,deliminators dim as long count,jmp dim as double tm=timer
Var L=loadfile("rosettalesmiserables.txt") L=lcase(L) 'get deliminators for n as long=1 to 96
p1+=chr(n)
next for n as long=123 to 255
p2+=chr(n)
next
deliminators=p1+p2
string_split(L,deliminators,s())
quicksort(s(),lbound(s),ubound(s))
For n As Long=lbound(s) To ubound(s)-1
if s(n+1)=s(n) then jmp+=1
if s(n+1)<>s(n) then
count+=1
redim preserve t(1 to count)
t(count).s=s(n)
t(count).l=jmp
jmp=0
end if
Next
tallysort(t(),lbound(t),ubound(t))'sort by frequency print "frequency","word" print for n as long=lbound(t) to lbound(t)+9
print t(n).l,t(n).s
next
Print print "time for operation ";timer-tm;" seconds" sleep </lang>
- Output:
I saved and reloaded the file as ascii text. frequency word 41098 the 19955 of 14939 and 14557 a 13953 to 11219 in 9648 he 8621 was 7923 that 6660 it time for operation 1.099869600031525 seconds
Frink
This example shows some of the subtle and non-obvious power of Frink in processing text files in a language-aware and Unicode-aware fashion:
- Frink has a Unicode-aware function,
wordList[str], which intelligently enumerates through the words in a string (and correctly handles compound words, hyphenated words, accented characters, etc.) It returns words, spaces, and punctuation marks separately. For the purposes of this program, "words" that do not contain any alphanumeric characters (as decided by the Unicode standard) are filtered out. These are likely punctuation and spaces.
- The file fetched from Project Gutenberg is supposed to be encoded in UTF-8 character encoding, but their servers incorrectly send either that it is Windows-1252 encoded or send no character encoding at all, so this program fixes that.
- Frink has a Unicode-aware lowercase function,
lc[str]that correctly handles accented characters and may even make a string longer.
- Frink can normalize Unicode characters with its
normalizeUnicodefunction so the same word encoded two different ways in Unicode can be treated consistently. For example, a Unicode string can use various methods to encode what is essentially the same character/glyph. For example, the characterôcan be represented as either"\u00F4"or"\u006F\u0302". The former is a "precomposed" character,"LATIN SMALL LETTER O WITH CIRCUMFLEX", and the latter is two Unicode codepoints, ano(LATIN SMALL LETTER O) followed by"COMBINING CIRCUMFLEX ACCENT". (This is usually referred to as a "decomposed" representation.) Unicode normalization rules can convert these "equivalent" encodings into a canonical representation. This makes two different strings which look equivalent to a human (but are very different in their codepoints) be treated as the same to a computer, and these programs will count them the same. Even if the Project Gutenberg document uses precomposed and decomposed representations for the same words, this program will fix it and count them the same! See the [Unicode Normal Forms] specification for more about these normalization rules. Frink implements all of them (NFC, NFD, NFKC, NFKD). NFC is the default innormalizeUnicode[str, encoding=NFC]. They're interesting!
How many other languages in this page do all or any of this correctly?
There are two sample programs below. First, a simple but powerful method that works in old versions of Frink:
<lang frink>d = new dict for w = select[wordList[read[normalizeUnicode["https://www.gutenberg.org/files/135/135-0.txt", "UTF-8"]]], %r/alnum:/ ]
d.increment[lc[w], 1]
println[join["\n", first[reverse[sort[array[d], {|a,b| a@1 <=> b@1}]], 10]]]</lang>
- Output:
[the, 40802] [of, 19933] [and, 14924] [a, 14450] [to, 13719] [in, 11184] [he, 9636] [was, 8617] [that, 7901] [it, 6641]
Next, a "showing off" one-liner that works in recent versions of Frink that uses the countToArray function which easily creates sorted frequency lists and the formatTable function that formats into a nice table with columns lined up, and still performs full Unicode-aware normalization, capitalization, and word-breaking:
<lang frink>formatTable[first[countToArray[select[wordList[lc[normalizeUnicode[read["https://www.gutenberg.org/files/135/135-0.txt", "UTF-8"]]]], %r/alnum:/ ]], 10], "right"]</lang>
- Output:
the 36629 of 19602 and 14063 a 13447 to 13345 in 10259 was 8541 that 7303 he 6812 had 6133
Go
<lang go>package main
import (
"fmt" "io/ioutil" "log" "regexp" "sort" "strings"
)
type keyval struct {
key string val int
}
func main() {
reg := regexp.MustCompile(`\p{Ll}+`)
bs, err := ioutil.ReadFile("135-0.txt")
if err != nil {
log.Fatal(err)
}
text := strings.ToLower(string(bs))
matches := reg.FindAllString(text, -1)
groups := make(map[string]int)
for _, match := range matches {
groups[match]++
}
var keyvals []keyval
for k, v := range groups {
keyvals = append(keyvals, keyval{k, v})
}
sort.Slice(keyvals, func(i, j int) bool {
return keyvals[i].val > keyvals[j].val
})
fmt.Println("Rank Word Frequency")
fmt.Println("==== ==== =========")
for rank := 1; rank <= 10; rank++ {
word := keyvals[rank-1].key
freq := keyvals[rank-1].val
fmt.Printf("%2d %-4s %5d\n", rank, word, freq)
}
}</lang>
- Output:
Rank Word Frequency ==== ==== ========= 1 the 41088 2 of 19949 3 and 14942 4 a 14596 5 to 13951 6 in 11214 7 he 9648 8 was 8621 9 that 7924 10 it 6661
Groovy
Solution: <lang groovy>def topWordCounts = { String content, int n ->
def mapCounts = [:]
content.toLowerCase().split(/\W+/).each {
mapCounts[it] = (mapCounts[it] ?: 0) + 1
}
def top = (mapCounts.sort { a, b -> b.value <=> a.value }.collect{ it })[0..<n]
println "Rank Word Frequency\n==== ==== ========="
(0..<n).each { printf ("%4d %-4s %9d\n", it+1, top[it].key, top[it].value) }
}</lang>
Test: <lang groovy>def rawText = "http://www.gutenberg.org/files/135/135-0.txt".toURL().text topWordCounts(rawText, 10)</lang>
Output:
Rank Word Frequency ==== ==== ========= 1 the 41036 2 of 19946 3 and 14940 4 a 14589 5 to 13939 6 in 11204 7 he 9645 8 was 8619 9 that 7922 10 it 6659
Haskell
<lang Haskell>module Main where
import Control.Category -- (>>>) import Data.Char -- toLower, isSpace import Data.List -- sortBy, (Foldable(foldl')), filter import Data.Ord -- Down import System.IO -- stdin, ReadMode, openFile, hClose import System.Environment -- getArgs
-- containers import Data.Map.Strict (Map) import qualified Data.Map.Strict as M import qualified Data.IntMap.Strict as IM
-- text import Data.Text (Text) import qualified Data.Text as T import qualified Data.Text.IO as T
frequencies :: Ord a => [a] -> Map a Integer frequencies = foldl' (\m k -> M.insertWith (+) k 1 m) M.empty {-# SPECIALIZE frequencies :: [Text] -> Map Text Integer #-}
main :: IO () main = do
args <- getArgs
(n,hand,filep) <- case length args of
0 -> return (10,stdin,False)
1 -> return (read $ head args,stdin,False)
_ -> let (ns:fp:_) = args
in fmap (\h -> (read ns,h,True)) (openFile fp ReadMode)
T.hGetContents hand >>=
(T.map toLower
>>> T.split isSpace
>>> filter (not <<< T.null)
>>> frequencies
>>> M.toList
>>> sortBy (comparing (Down <<< snd)) -- sort the opposite way
>>> take n
>>> print)
when filep (hClose hand)</lang>
- Output:
$ ./word_count 10 < ~/doc/les_miserables*
[("the",40368),("of",19863),("and",14470),("a",14277),("to",13587),("in",11019),("he",9212),("was",8346),("that",7251),("his",6414)]
Or, perhaps a little more simply:
<lang haskell>import qualified Data.Text.IO as T
import qualified Data.Text as T
import Data.List (group, sort, sortBy) import Data.Ord (comparing)
frequentWords :: T.Text -> [(Int, T.Text)] frequentWords =
sortBy (flip $ comparing fst) . fmap ((,) . length <*> head) . group . sort . T.words . T.toLower
main :: IO () main = T.readFile "miserables.txt" >>= (mapM_ print . take 10 . frequentWords)</lang>
- Output:
(40370,"the") (19863,"of") (14470,"and") (14277,"a") (13587,"to") (11019,"in") (9212,"he") (8346,"was") (7251,"that") (6414,"his")
J
Text acquisition: store the entire text from the web page http://www.gutenberg.org/files/135/135-0.txt (the plain text UTF-8 link) into a file. This linux example uses ~/downloads/books/LesMis.txt .
Program: Reading from left to right, 10 {. "ten take" from an array computed by words to the right. \:~ "sort descending" by items of the array computed by whatever is to the right. (#;{.)/.~ "tally linked with item" key ;: "words" parses the argument to its right as a j sentence. tolower changes to a common case
Hence the remainder of the j sentence must clean after loading the file.
The parenthesized expression (a.-.Alpha_j_,' ') computes to a vector of the j alphabet excluding [a-zA-Z ] ((e.&(a.-.Alpha_j_,' '))`(,:&' '))} substitutes space character for the unwanted characters. 1!:1 reads the file named in the box <
10{.\:~(#;{.)/.~;:tolower((e.&(a.-.Alpha_j_,' '))`(,:&' '))}1!:1<jpath'~/downloads/books/LesMis.txt'
┌─────┬────┐
│41093│the │
├─────┼────┤
│19954│of │
├─────┼────┤
│14943│and │
├─────┼────┤
│14558│a │
├─────┼────┤
│13953│to │
├─────┼────┤
│11219│in │
├─────┼────┤
│9649 │he │
├─────┼────┤
│8622 │was │
├─────┼────┤
│7924 │that│
├─────┼────┤
│6661 │it │
└─────┴────┘
Java
<lang Java>import java.io.IOException; import java.nio.file.Files; import java.nio.file.Path; import java.nio.file.Paths; import java.util.HashMap; import java.util.List; import java.util.Map; import java.util.regex.Matcher; import java.util.regex.Pattern; import java.util.stream.Collectors;
public class WordCount {
public static void main(String[] args) throws IOException {
Path path = Paths.get("135-0.txt");
byte[] bytes = Files.readAllBytes(path);
String text = new String(bytes);
text = text.toLowerCase();
Pattern r = Pattern.compile("\\p{javaLowerCase}+");
Matcher matcher = r.matcher(text);
Map<String, Integer> freq = new HashMap<>();
while (matcher.find()) {
String word = matcher.group();
Integer current = freq.getOrDefault(word, 0);
freq.put(word, current + 1);
}
List<Map.Entry<String, Integer>> entries = freq.entrySet()
.stream()
.sorted((i1, i2) -> Integer.compare(i2.getValue(), i1.getValue()))
.limit(10)
.collect(Collectors.toList());
System.out.println("Rank Word Frequency");
System.out.println("==== ==== =========");
int rank = 1;
for (Map.Entry<String, Integer> entry : entries) {
String word = entry.getKey();
Integer count = entry.getValue();
System.out.printf("%2d %-4s %5d\n", rank++, word, count);
}
}
}</lang>
- Output:
Rank Word Frequency ==== ==== ========= 1 the 41088 2 of 19949 3 and 14942 4 a 14596 5 to 13951 6 in 11214 7 he 9648 8 was 8621 9 that 7924 10 it 6661
jq
The following solution uses the concept of a "bag of words" (bow), here realized as a JSON object with the words as keys and the frequency of a word as the corresponding value.
To avoid issues with case folding, the "letters" here just the alphabet and hyphen, but a "word" may not begin with hyphen. Thus "the-the" would count as one word, and "-the" would be excluded.
<lang jq> < 135-0.txt jq -nR --argjson n 10 ' def bow(stream):
reduce stream as $word ({}; .[($word|tostring)] += 1);
bow(inputs | gsub("[^-a-zA-Z]"; " ") | splits(" *") | ascii_downcase | select(test("^[a-z][-a-z]*$"))) | to_entries | sort_by(.value) | .[- $n :] | reverse | from_entries ' </lang>
Output
<lang jq> {
"the": 41087, "of": 19937, "and": 14932, "a": 14552, "to": 13738, "in": 11209, "he": 9649, "was": 8621, "that": 7923, "it": 6661
} </lang>
Julia
<lang julia> using FreqTables
txt = read("les-mis.txt", String) words = split(replace(txt, r"\P{L}"i => " ")) table = sort(freqtable(words); rev=true) println(table[1:10])</lang>
- Output:
Dim1 │ ───────┼────── "the" │ 36671 "of" │ 19618 "and" │ 14081 "to" │ 13541 "a" │ 13529 "in" │ 10265 "was" │ 8545 "that" │ 7326 "he" │ 6816 "had" │ 6140
Kotlin
The author of the Raku entry has given a good account of the difficulties with this task and, in the absence of any clarification on the various issues, I've followed a similar 'literal' approach.
So, after first converting the text to lower case, I've assumed that a word is any sequence of one or more lower-case Unicode letters and obtained the same results as the Raku version.
There is no change in the results if the numerals 0-9 are also regarded as letters. <lang scala>// version 1.1.3
import java.io.File
fun main(args: Array<String>) {
val text = File("135-0.txt").readText().toLowerCase()
val r = Regex("""\p{javaLowerCase}+""")
val matches = r.findAll(text)
val wordGroups = matches.map { it.value }
.groupBy { it }
.map { Pair(it.key, it.value.size) }
.sortedByDescending { it.second }
.take(10)
println("Rank Word Frequency")
println("==== ==== =========")
var rank = 1
for ((word, freq) in wordGroups)
System.out.printf("%2d %-4s %5d\n", rank++, word, freq)
}</lang>
- Output:
Rank Word Frequency ==== ==== ========= 1 the 41088 2 of 19949 3 and 14942 4 a 14596 5 to 13951 6 in 11214 7 he 9648 8 was 8621 9 that 7924 10 it 6661
Liberty BASIC
<lang lb>dim words$(100000,2)'words$(a,1)=the word, words$(a,2)=the count dim lines$(150000) open "135-0.txt" for input as #txt while EOF(#txt)=0 and total < 150000
input #txt, lines$(total) total=total+1
wend for a = 1 to total
token$ = "?"
index=0
new=0
while token$ <> ""
new=0
index = index + 1
token$ = lower$(word$(lines$(a),index))
token$=replstr$(token$,".","")
token$=replstr$(token$,",","")
token$=replstr$(token$,";","")
token$=replstr$(token$,"!","")
token$=replstr$(token$,"?","")
token$=replstr$(token$,"-","")
token$=replstr$(token$,"_","")
token$=replstr$(token$,"~","")
token$=replstr$(token$,"+","")
token$=replstr$(token$,"0","")
token$=replstr$(token$,"1","")
token$=replstr$(token$,"2","")
token$=replstr$(token$,"3","")
token$=replstr$(token$,"4","")
token$=replstr$(token$,"5","")
token$=replstr$(token$,"6","")
token$=replstr$(token$,"7","")
token$=replstr$(token$,"8","")
token$=replstr$(token$,"9","")
token$=replstr$(token$,"/","")
token$=replstr$(token$,"<","")
token$=replstr$(token$,">","")
token$=replstr$(token$,":","")
for b = 1 to newwordcount
if words$(b,1)=token$ then
num=val(words$(b,2))+1
num$=str$(num)
if len(num$)=1 then num$="0000"+num$
if len(num$)=2 then num$="000"+num$
if len(num$)=3 then num$="00"+num$
if len(num$)=4 then num$="0"+num$
words$(b,2)=num$
new=1
exit for
end if
next b
if new<>1 then newwordcount=newwordcount+1:words$(newwordcount,1)=token$:words$(newwordcount,2)="00001":print newwordcount;" ";token$
wend
next a print sort words$(), 1, newwordcount, 2 print "Count Word" print "===== =================" for a = newwordcount to newwordcount-10 step -1
print words$(a,2);" ";words$(a,1)
next a print "-----------------------" print newwordcount;" unique words found." print "End of program" close #txt end </lang>
- Output:
Count Word ===== ================= 40292 the 19825 of 14703 and 14249 a 13594 to 122613 11061 in 09436 he 08579 was 07530 that 06428 his ----------------------- 29109 unique words found.
Lua
<lang lua> -- This program takes two optional command line arguments. The first (arg[1]) -- specifies the input file, or defaults to standard input. The second -- (arg[2]) specifies the number of results to show, or defaults to 10.
-- in freq, each key is a word and each value is its count local freq = {} for line in io.lines(arg[1]) do -- %a stands for any letter for word in string.gmatch(string.lower(line), "%a+") do if not freq[word] then freq[word] = 1 else freq[word] = freq[word] + 1 end end end
-- in array, each entry is an array whose first value is the count and whose -- second value is the word local array = {} for word, count in pairs(freq) do table.insert(array, {count, word}) end table.sort(array, function (a, b) return a[1] > b[1] end)
for i = 1, arg[2] or 10 do io.write(string.format('%7d %s\n', array[i][1] , array[i][2])) end </lang>
- Output:
❯ ./wordcount.lua 135-0.txt 41093 the 19954 of 14943 and 14558 a 13953 to 11219 in 9649 he 8622 was 7924 that 6661 it
Relevant documentation: io.lines gmatch patterns like %a
Mathematica / Wolfram Language
<lang Mathematica>TakeLargestBy[Tally@StringCases[ToLowerCase@Import["https://www.gutenberg.org/files/135/135-0.txt",CharacterEncoding->"UTF-8"],RegularExpression@"\\w+"],Last,10]</lang>
- Output:
{{the,41045},{of,19953},{and,14939},{a,14527},{to,13942},{in,11210},{he,9646},{was,8620},{that,7922},{it,6659}}
MATLAB / Octave
<lang Matlab> function [result,count] = word_frequency() URL='https://www.gutenberg.org/files/135/135-0.txt'; text=webread(URL); DELIMITER={' ', ',', ';', ':', '.', '/', '*', '!', '?', '<', '>', '(', ')', '[', ']','{', '}', '&','$','§','"','”','“','-','—','‘','\t','\n','\r'}; words = sort(strsplit(lower(text),DELIMITER)); flag = [find(~strcmp(words(1:end-1),words(2:end))),length(words)]; dwords = words(flag); % get distinct words, and ... count = diff([0,flag]); % ... the corresponding occurance frequency [tmp,idx] = sort(-count); % sort according to occurance result = dwords(idx); count = count(idx); for k = 1:10,
fprintf(1,'%d\t%s\n',count(k),result{k})
end </lang>
- Output:
41039 the 19950 of 14942 and 14523 a 13941 to 11208 in 9605 he 8620 was 7824 that 6533 it
Nim
<lang Nim>import tables, strutils, sequtils, httpclient
proc take[T](s: openArray[T], n: int): seq[T] = s[0 ..< min(n, s.len)]
var client = newHttpClient() var text = client.getContent("https://www.gutenberg.org/files/135/135-0.txt")
var wordFrequencies = text.toLowerAscii.splitWhitespace.toCountTable wordFrequencies.sort for (word, count) in toSeq(wordFrequencies.pairs).take(10):
echo alignLeft($count, 8), word</lang>
- Output:
40377 the 19870 of 14469 and 14278 a 13590 to 11025 in 9213 he 8347 was 7249 that 6414 his
Objeck
<lang objeck>use System.IO.File; use Collection; use RegEx;
class Rosetta {
function : Main(args : String[]) ~ Nil {
if(args->Size() <> 1) {
return;
};
input := FileReader->ReadFile(args[0]);
filter := RegEx->New("\\w+");
words := filter->Find(input);
word_counts := StringMap->New();
each(i : words) {
word := words->Get(i)->As(String);
if(word <> Nil & word->Size() > 0) {
word := word->ToLower();
if(word_counts->Has(word)) {
count := word_counts->Find(word)->As(IntHolder);
count->Set(count->Get() + 1);
}
else {
word_counts->Insert(word, IntHolder->New(1));
};
};
};
count_words := IntMap->New();
words := word_counts->GetKeys();
each(i : words) {
word := words->Get(i)->As(String);
count := word_counts->Find(word)->As(IntHolder);
count_words->Insert(count->Get(), word);
};
counts := count_words->GetKeys();
counts->Sort();
index := 1;
"Rank\tWord\tFrequency"->PrintLine();
"====\t====\t===="->PrintLine();
for(i := count_words->Size() - 1; i >= 0; i -= 1;) {
if(count_words->Size() - 10 <= i) {
count := counts->Get(i);
word := count_words->Find(count)->As(String);
"{$index}\t{$word}\t{$count}"->PrintLine();
index += 1;
};
};
}
}</lang>
Output:
Rank Word Frequency ==== ==== ==== 1 the 41036 2 of 19946 3 and 14940 4 a 14589 5 to 13939 6 in 11204 7 he 9645 8 was 8619 9 that 7922 10 it 6659
OCaml
<lang ocaml>let () =
let n =
try int_of_string Sys.argv.(1)
with _ -> 10
in
let ic = open_in "135-0.txt" in
let h = Hashtbl.create 97 in
let w = Str.regexp "[^A-Za-zéèàêâôîûœ]+" in
try
while true do
let line = input_line ic in
let words = Str.split w line in
List.iter (fun word ->
let word = String.lowercase_ascii word in
match Hashtbl.find_opt h word with
| None -> Hashtbl.add h word 1
| Some x -> Hashtbl.replace h word (succ x)
) words
done
with End_of_file ->
close_in ic;
let l = Hashtbl.fold (fun word count acc -> (word, count)::acc) h [] in
let s = List.sort (fun (_, c1) (_, c2) -> compare c2 c1) l in
let r = List.init n (fun i -> List.nth s i) in
List.iter (fun (word, count) ->
Printf.printf "%d %s\n" count word
) r</lang>
- Output:
$ ocaml str.cma word_freq.ml 41092 the 19954 of 14943 and 14554 a 13953 to 11219 in 9649 he 8622 was 7924 that 6661 it
Perl
<lang perl>$top = 10;
open $fh, "<", '135-0.txt'; ($text = join , <$fh>) =~ tr/A-Z/a-z/
or die "Can't open '135-0.txt': $!\n";
@matcher = (
qr/[a-z]+/, # simple 7-bit ASCII qr/\w+/, # word characters with underscore qr/[a-z0-9]+/, # word characters without underscore
);
for $reg (@matcher) {
print "\nTop $top using regex: " . $reg . "\n";
@matches = $text =~ /$reg/g;
my %words;
for $w (@matches) { $words{$w}++ };
$c = 0;
for $w ( sort { $words{$b} <=> $words{$a} } keys %words ) {
printf "%-7s %6d\n", $w, $words{$w};
last if ++$c >= $top;
}
}</lang>
- Output:
Top 10 using regex: (?^:[a-z]+) the 41089 of 19949 and 14942 a 14608 to 13951 in 11214 he 9648 was 8621 that 7924 it 6661 Top 10 using regex: (?^:\w+) the 41036 of 19946 and 14940 a 14589 to 13939 in 11204 he 9645 was 8619 that 7922 it 6659 Top 10 using regex: (?^:[a-z0-9]+) the 41089 of 19949 and 14942 a 14608 to 13951 in 11214 he 9648 was 8621 that 7924 it 6661
Phix
without javascript_semantics ?"loading..." constant subs = '\t'&"\r\n_.,\"\'!;:?][()|=<>#/*{}+@%&$", reps = repeat(' ',length(subs)), fn = open("135-0.txt","r") string text = lower(substitute_all(get_text(fn),subs,reps)) close(fn) sequence words = append(sort(split(text,no_empty:=true)),"") constant wf = new_dict() string last = words[1] integer count = 1 for i=2 to length(words) do if words[i]!=last then setd({count,last},0,wf) count = 0 last = words[i] end if count += 1 end for count = 10 function visitor(object key, object /*data*/, object /*user_data*/) ?key count -= 1 return count>0 end function traverse_dict(routine_id("visitor"),0,wf,true)
- Output:
loading...
{40743,"the"}
{19925,"of"}
{14881,"and"}
{14474,"a"}
{13704,"to"}
{11174,"in"}
{9623,"he"}
{8613,"was"}
{7867,"that"}
{6612,"it"}
Phixmonti
<lang Phixmonti>include ..\Utilitys.pmt
"loading..." ? "135-0.txt" "r" fopen var fn " " true while
fn fgets number? if drop fn fclose false else lower " " chain chain true endif
endwhile
"process..." ? len for
var i i get dup 96 > swap 123 < and not if 32 i set endif
endfor split sort
"count..." ? ( ) var words "" var prev 1 var n len for
var i
i get dup prev ==
if
drop n 1 + var n
else
words ( n prev ) 0 put var words var prev 1 var n
endif
endfor drop words sort 10 for
-1 * get ?
endfor drop</lang>
- Output:
loading... process... count... [41093, "the"] [19954, "of"] [14943, "and"] [14558, "a"] [13953, "to"] [11219, "in"] [9649, "he"] [8622, "was"] [7924, "that"] [6661, "it"] === Press any key to exit ===
PHP
<lang php> <?php
preg_match_all('/\w+/', file_get_contents($argv[1]), $words); $frecuency = array_count_values($words[0]); arsort($frecuency);
echo "Rank\tWord\tFrequency\n====\t====\t=========\n"; $i = 1; foreach ($frecuency as $word => $count) {
echo $i . "\t" . $word . "\t" . $count . "\n";
if ($i >= 10) {
break;
}
$i++;
}</lang>
- Output:
Rank Word Frequency ==== ==== ========= 1 the 36636 2 of 19615 3 and 14079 4 to 13535 5 a 13527 6 in 10256 7 was 8543 8 that 7324 9 he 6814 10 had 6139
PicoLisp
<lang PicoLisp>(setq *Delim " ^I^J^M-_.,\"'*[]?!&@#$%^\(\):;") (setq *Skip (chop *Delim))
(de word+ NIL
(prog1
(lowc (till *Delim T))
(while (member (peek) *Skip) (char)) ) )
(off B) (in "135-0.txt"
(until (eof)
(let W (word+)
(if (idx 'B W T) (inc (car @)) (set W 1)) ) ) )
(for L (head 10 (flip (by val sort (idx 'B))))
(println L (val L)) )</lang>
- Output:
"the" 41088 "of" 19949 "and" 14942 "a" 14545 "to" 13950 "in" 11214 "he" 9647 "was" 8620 "that" 7924 "it" 6661
Prolog
<lang prolog>print_top_words(File, N):-
read_file_to_string(File, String, [encoding(utf8)]),
re_split("\\w+", String, Words),
lower_case(Words, Lower),
sort(1, @=<, Lower, Sorted),
merge_words(Sorted, Counted),
sort(2, @>, Counted, Top_words),
writef("Top %w words:\nRank\tCount\tWord\n", [N]),
print_top_words(Top_words, N, 1).
lower_case([_], []):-!. lower_case([_, Word|Words], [Lower - 1|Rest]):-
string_lower(Word, Lower), lower_case(Words, Rest).
merge_words([], []):-!. merge_words([Word - C1, Word - C2|Words], Result):-
!, C is C1 + C2, merge_words([Word - C|Words], Result).
merge_words([W|Words], [W|Rest]):-
merge_words(Words, Rest).
print_top_words([], _, _):-!. print_top_words(_, 0, _):-!. print_top_words([Word - Count|Rest], N, R):-
writef("%w\t%w\t%w\n", [R, Count, Word]),
N1 is N - 1,
R1 is R + 1,
print_top_words(Rest, N1, R1).
main:-
print_top_words("135-0.txt", 10).</lang>
- Output:
Top 15 words: Rank Count Word 1 41040 the 2 19951 of 3 14942 and 4 14539 a 5 13941 to 6 11209 in 7 9646 he 8 8620 was 9 7922 that 10 6659 it
PureBasic
<lang PureBasic>EnableExplicit
Structure wordcount
wkey$ count.i
EndStructure
Define token.c, word$, idx.i, start.i, arg$ NewMap wordmap.i() NewList wordlist.wordcount()
If OpenConsole("")
arg$ = ProgramParameter(0)
If arg$ = "" : End 1 : EndIf
start = ElapsedMilliseconds()
If ReadFile(0, arg$, #PB_Ascii)
While Not Eof(0)
token = ReadCharacter(0, #PB_Ascii)
Select token
Case 'A' To 'Z', 'a' To 'z'
word$ + LCase(Chr(token))
Default
If word$
wordmap(word$) + 1
word$ = ""
EndIf
EndSelect
Wend
CloseFile(0)
ForEach wordmap()
AddElement(wordlist())
wordlist()\wkey$ = MapKey(wordmap())
wordlist()\count = wordmap()
Next
SortStructuredList(wordlist(), #PB_Sort_Descending, OffsetOf(wordcount\count), TypeOf(wordcount\count))
PrintN("Elapsed milliseconds: " + Str(ElapsedMilliseconds() - start))
PrintN("File: " + GetFilePart(arg$))
PrintN(~"Rank\tCount\t\t Word")
If FirstElement(wordlist())
For idx = 1 To 10
Print(RSet(Str(idx), 2))
Print(~"\t")
Print(wordlist()\wkey$)
Print(~"\t\t")
PrintN(RSet(Str(wordlist()\count), 6))
If NextElement(wordlist()) = 0
Break
EndIf
Next
EndIf
EndIf
Input()
EndIf
End</lang>
- Output:
Elapsed milliseconds: 462 File: 135-0.txt Rank Count Word 1 the 41093 2 of 19954 3 and 14943 4 a 14558 5 to 13953 6 in 11219 7 he 9649 8 was 8622 9 that 7924 10 it 6661
Python
Collections
Python2.7
<lang python>import collections import re import string import sys
def main():
counter = collections.Counter(re.findall(r"\w+",open(sys.argv[1]).read().lower())) print counter.most_common(int(sys.argv[2]))
if __name__ == "__main__":
main()</lang>
- Output:
$ python wordcount.py 135-0.txt 10
[('the', 41036), ('of', 19946), ('and', 14940), ('a', 14589), ('to', 13939),
('in', 11204), ('he', 9645), ('was', 8619), ('that', 7922), ('it', 6659)]
Python3.6
<lang python>from collections import Counter from re import findall
les_mis_file = 'les_mis_135-0.txt'
def _count_words(fname):
with open(fname) as f:
text = f.read()
words = findall(r'\w+', text.lower())
return Counter(words)
def most_common_words_in_file(fname, n):
counts = _count_words(fname) for word, count in 'WORD', 'COUNT' + counts.most_common(n): print(f'{word:>10} {count:>6}')
if __name__ == "__main__":
n = int(input('How many?: '))
most_common_words_in_file(les_mis_file, n)</lang>
- Output:
How many?: 10
WORD COUNT
the 41036
of 19946
and 14940
a 14586
to 13939
in 11204
he 9645
was 8619
that 7922
it 6659
Sorted and groupby
<lang python>""" Word count task from Rosetta Code http://www.rosettacode.org/wiki/Word_count#Python """ from itertools import (groupby,
starmap)
from operator import itemgetter from pathlib import Path from typing import (Iterable,
List,
Tuple)
FILEPATH = Path('lesMiserables.txt')
COUNT = 10
def main():
words_and_counts = most_frequent_words(FILEPATH) print(*words_and_counts[:COUNT], sep='\n')
def most_frequent_words(filepath: Path,
*,
encoding: str = 'utf-8') -> List[Tuple[str, int]]:
"""
A list of word-frequency pairs sorted by their occurrences.
The words are read from the given file.
"""
def word_and_frequency(word: str,
words_group: Iterable[str]) -> Tuple[str, int]:
return word, capacity(words_group)
file_contents = filepath.read_text(encoding=encoding) words = file_contents.lower().split() grouped_words = groupby(sorted(words)) words_and_frequencies = starmap(word_and_frequency, grouped_words) return sorted(words_and_frequencies, key=itemgetter(1), reverse=True)
def capacity(iterable: Iterable) -> int:
"""Returns a number of elements in an iterable""" return sum(1 for _ in iterable)
if __name__ == '__main__':
main()
</lang>
- Output:
('the', 40372)
('of', 19868)
('and', 14472)
('a', 14278)
('to', 13589)
('in', 11024)
('he', 9213)
('was', 8347)
('that', 7250)
('his', 6414)
Collections, Sorted and Lambda
<lang python>
- !/usr/bin/python3
import collections import re
count = 10
with open("135-0.txt") as f:
text = f.read()
word_freq = sorted(
collections.Counter(sorted(re.split(r"\W+", text.lower()))).items(), key=lambda c: c[1], reverse=True,
)
for i in range(len(word_freq)):
print("[{:2d}] {:>10} : {}".format(i + 1, word_freq[i][0], word_freq[i][1]))
if i == count - 1:
break
</lang>
- Output:
[ 1] the : 41039 [ 2] of : 19951 [ 3] and : 14942 [ 4] a : 14527 [ 5] to : 13941 [ 6] in : 11209 [ 7] he : 9646 [ 8] was : 8620 [ 9] that : 7922 [10] it : 6659
R
I chose to remove apostrophes only if they're followed by an s (so "mom" and "mom's" will show up as the same word but "they" and "they're" won't). I also chose not to remove hyphens. <lang R> wordcount<-function(file,n){
punctuation=c("`","~","!","@","#","$","%","^","&","*","(",")","_","+","=","{","[","}","]","|","\\",":",";","\"","<",",",">",".","?","/","'s")
wordlist=scan(file,what=character())
wordlist=tolower(wordlist)
for(i in 1:length(punctuation)){
wordlist=gsub(punctuation[i],"",wordlist,fixed=T)
}
df=data.frame("Word"=sort(unique(wordlist)),"Count"=rep(0,length(unique(wordlist))))
for(i in 1:length(unique(wordlist))){
df[i,2]=length(which(wordlist==df[i,1]))
}
df=df[order(df[,2],decreasing = T),]
row.names(df)=1:nrow(df)
return(df[1:n,])
} </lang>
- Output:
> wordcount("MobyDick.txt",10)
Read 212793 items
Word Count
1 the 14346
2 of 6590
3 and 6340
4 a 4611
5 to 4572
6 in 4130
7 that 2903
8 his 2516
9 it 2308
10 i 1845
Racket
<lang racket>#lang racket
(define (all-words f (case-fold string-downcase))
(map case-fold (regexp-match* #px"\\w+" (file->string f))))
(define (l.|l| l) (cons (car l) (length l)))
(define (counts l (>? >)) (sort (map l.|l| (group-by values l)) >? #:key cdr))
(module+ main
(take (counts (all-words "data/les-mis.txt")) 10))</lang>
- Output:
'(("the" . 41036)
("of" . 19946)
("and" . 14940)
("a" . 14589)
("to" . 13939)
("in" . 11204)
("he" . 9645)
("was" . 8619)
("that" . 7922)
("it" . 6659))
Raku
(formerly Perl 6)
Note: much of the following exposition is no longer critical to the task as the requirements have been updated, but is left here for historical and informational reasons.
This is slightly trickier than it appears initially. The task specifically states: "A word is a sequence of one or more contiguous letters", so contractions and hyphenated words are broken up. Initially we might reach for a regex matcher like /\w+/ , but \w includes underscore, which is not a letter but a punctuation connector; and this text is full of underscores since that is how Project Gutenberg texts denote italicized text. The underscores are not actually parts of the words though, they are markup.
We might try /A-Za-z/ as a matcher but this text is bursting with French words containing various accented glyphs. Those are letters, so words will be incorrectly split up; (Misérables will be counted as 'mis' and 'rables', probably not what we want.)
Actually, in this case /A-Za-z/ returns very nearly the correct answer. Unfortunately, the name "Alèthe" appears once (only once!) in the text, gets incorrectly split into Al & the, and incorrectly reports 41089 occurrences of "the". The text has several words like "Panathenæa", "ça", "aérostiers" and "Keksekça" so the counts for 'a' are off too. The other 8 of the top 10 are "correct" using /A-Za-z/, but it is mostly by accident.
A more accurate regex matcher would be some kind of Unicode aware /\w/ minus underscore. It may also be useful, depending on your requirements, to recognize contractions with embedded apostrophes, hyphenated words, and hyphenated words broken across lines.
Here is a sample that shows the result when using various different matchers. <lang perl6>sub MAIN ($filename, $top = 10) {
my $file = $filename.IO.slurp.lc.subst(/ (<[\w]-[_]>'-')\n(<[\w]-[_]>) /, {$0 ~ $1}, :g );
my @matcher = (
rx/ <[a..z]>+ /, # simple 7-bit ASCII
rx/ \w+ /, # word characters with underscore
rx/ <[\w]-[_]>+ /, # word characters without underscore
rx/ <[\w]-[_]>+[["'"|'-'|"'-"]<[\w]-[_]>+]* / # word characters without underscore but with hyphens and contractions
);
for @matcher -> $reg {
say "\nTop $top using regex: ", $reg.raku;
.put for $file.comb( $reg ).Bag.sort(-*.value)[^$top];
}
}</lang>
- Output:
Passing in the file name and 10:
Top 10 using regex: rx/ <[a..z]>+ / the 41089 of 19949 and 14942 a 14608 to 13951 in 11214 he 9648 was 8621 that 7924 it 6661 Top 10 using regex: rx/ \w+ / the 41035 of 19946 and 14940 a 14577 to 13939 in 11204 he 9645 was 8619 that 7922 it 6659 Top 10 using regex: rx/ <[\w]-[_]>+ / the 41088 of 19949 and 14942 a 14596 to 13951 in 11214 he 9648 was 8621 that 7924 it 6661 Top 10 using regex: rx/ <[\w]-[_]>+[["'"|'-'|"'-"]<[\w]-[_]>+]* / the 41081 of 19930 and 14934 a 14587 to 13735 in 11204 he 9607 was 8620 that 7825 it 6535
It can be difficult to figure out what words the different regexes do or don't match. Here are the three more complex regexes along with a list of "words" that are treated as being different using this regex as opposed to /a..z/. IE: It is lumped in as one of the top 10 word counts using /a..z/ but not with this regex.
Top 10 using regex: rx/ \w+ / the 41035 alèthe _the _the_ of 19946 of_ _of_ and 14940 _and_ paternoster_and a 14577 _ça aïe ça keksekça aérostiers _a poréa panathenæa to 13939 to_ _to in 11204 _in he 9645 _he was 8619 _was that 7922 _that it 6659 _it Top 10 using regex: rx/ <[\w]-[_]>+ / the 41088 alèthe of 19949 and 14942 a 14596 poréa ça aérostiers panathenæa aïe keksekça to 13951 in 11214 he 9648 was 8621 that 7924 it 6661 Top 10 using regex: rx/ <[\w]-[_]>+[["'"|'-'|"'-"]<[\w]-[_]>+]* / the 41081 will-o'-the-wisps alèthe skip-the-gutter police-agent-ja-vert-was-found-drowned-un-der-a-boat-of-the-pont-au-change jean-the-screw will-o'-the-wisp of 19930 chromate-of-lead-colored die-of-hunger die-of-cold-if-you-have-bread police-agent-ja-vert-was-found-drowned-un-der-a-boat-of-the-pont-au-change unheard-of die-of-hunger-if-you-have-a-fire and 14934 come-and-see so-and-so cock-and-bull hide-and-seek sambre-and-meuse a 14587 keksekça l'a ça now-a-days vis-a-vis a-dreaming police-agent-ja-vert-was-found-drowned-un-der-a-boat-of-the-pont-au-change poréa panathenæa aérostiers a-hunting aïe die-of-hunger-if-you-have-a-fire to 13735 to-morrow to-day hand-to-hand to-night well-to-do face-to-face in 11204 in-pace son-in-law father-in-law whippers-in general-in-chief sons-in-law he 9607 he's he'll was 8620 police-agent-ja-vert-was-found-drowned-un-der-a-boat-of-the-pont-au-change that 7825 that's pick-me-down-that it 6535 it's it'll
One nice thing is this isn't special cased. It will work out of the box for any text / language.
Russian? No problem.
$ raku wf 14741-0.txt 5
Top 5 using regex: rx/ <[a..z]>+ / the 176 of 119 gutenberg 93 project 87 to 80 Top 5 using regex: rx/ \w+ / и 860 в 579 не 290 на 222 ты 195 Top 5 using regex: rx/ <[\w]-[_]>+ / и 860 в 579 не 290 на 222 ты 195 Top 5 using regex: rx/ <[\w]-[_]>+[["'"|'-'|"'-"]<[\w]-[_]>+]* / и 860 в 579 не 290 на 222 ты 195
Greek? Sure, why not.
$ raku wf 39963-0.txt 5
Top 5 using regex: rx/ <[a..z]>+ / the 187 of 123 gutenberg 93 project 87 to 82 Top 5 using regex: rx/ \w+ / και 1628 εις 986 δε 982 του 895 των 859 Top 5 using regex: rx/ <[\w]-[_]>+ / και 1628 εις 986 δε 982 του 895 των 859 Top 5 using regex: rx/ <[\w]-[_]>+[["'"|'-'|"'-"]<[\w]-[_]>+]* / και 1628 εις 986 δε 982 του 895 των 859
Of course, for the first matcher, we are asking specifically to match Latin ASCII, so we end up with... well... Latin ASCII; but the other 3 match any Unicode characters.
REXX
version 1
This REXX version doesn't need to sort the list of words.
Extra code was added to handle some foreign letters (non-Latin) and also handle most accented letters.
This version recognizes all the accented letters that are present in the required/specified text (file) (and some other non-Latin letters as well).
This means that the word Alèthe is treated as one word, not as two words Al the (and not thereby adding two separate words).
This version also supports words that contain embedded
apostrophes ( ' )
[that is, within a word, but not those words that start or
end with an apostrophe; for those encapsulated words, the apostrophe is
elided].
Thus, it's is counted separately from it and/or its.
Since REXX doesn't support UTF-8 encodings, code was added to this REXX version to support the accented letters in the mandated input file. <lang rexx>/*REXX pgm displays top 10 words in a file (includes foreign letters), case is ignored.*/ parse arg fID top . /*obtain optional arguments from the CL*/ if fID== | fID=="," then fID= 'les_mes.txt' /*None specified? Then use the default.*/ if top== | top=="," then top= 10 /* " " " " " " */ call init /*initialize varied bunch of variables.*/ call rdr say right('word', 40) " " center(' rank ', 6) " count " /*display title for output*/ say right('════', 40) " " center('══════', 6) " ═══════" /* " title separator.*/
do until otops==tops | tops>top /*process enough words to satisfy TOP.*/
WL=; mk= 0; otops= tops /*initialize the word list (to a NULL).*/
do n=1 for c; z= !.n; k= @.z /*process the list of words in the file*/
if k==mk then WL= WL z /*handle cases of tied number of words.*/
if k> mk then do; mk=k; WL=z; end /*this word count is the current max. */
end /*n*/
wr= max( length(' rank '), length(top) ) /*find the maximum length of the rank #*/
do d=1 for words(WL); y= word(WL, d) /*process all words in the word list. */
if d==1 then w= max(10, length(@.y) ) /*use length of the first number used. */
say right(y, 40) right( commas(tops), wr) right(commas(@.y), w)
@.y= . /*nullify word count for next go 'round*/
end /*d*/ /* [↑] this allows a non-sorted list. */
tops= tops + words(WL) /*correctly handle any tied rankings.*/
end /*until*/
exit /*stick a fork in it, we're all done. */ /*──────────────────────────────────────────────────────────────────────────────────────*/ commas: parse arg ?; do jc=length(?)-3 to 1 by -3; ?=insert(',', ?, jc); end; return ? 16bit: do k=1 for xs; _=word(x,k); $=changestr('├'left(_,1),$,right(_,1)); end; return /*──────────────────────────────────────────────────────────────────────────────────────*/ init: x= 'Çà åÅ çÇ êÉ ëÉ áà óâ ªæ ºç ¿è ⌐é ¬ê ½ë «î »ï ▒ñ ┤ô ╣ù ╗û ╝ü'; xs= words(x)
abcL="abcdefghijklmnopqrstuvwxyz'" /*lowercase letters of Latin alphabet. */
abcU= abcL; upper abcU /*uppercase version of Latin alphabet. */
accL= 'üéâÄàÅÇêëèïîìéæôÖòûùÿáíóúÑ' /*some lowercase accented characters. */
accU= 'ÜéâäàåçêëèïîìÉÆôöòûùÿáíóúñ' /* " uppercase " " */
accG= 'αßΓπΣσµτΦΘΩδφε' /* " upper/lowercase Greek letters. */
ll= abcL || abcL ||accL ||accL || accG /*chars of after letters. */
uu= abcL || abcU ||accL ||accU || accG || xrange() /* " " before " */
@.= 0; q= "'"; totW= 0; !.= @.; c= 0; tops= 1; return
/*──────────────────────────────────────────────────────────────────────────────────────*/ rdr: do #=0 while lines(fID)\==0; $=linein(fID) /*loop whilst there're lines in file.*/
if pos('├', $) \== 0 then call 16bit /*are there any 16-bit characters ?*/
$= translate( $, ll, uu) /*trans. uppercase letters to lower. */
do while $ \= ; parse var $ z $ /*process each word in the $ line. */
parse var z z1 2 zr -1 zL /*obtain: first, middle, & last char.*/
if z1==q then do; z=zr; if z== then iterate; end /*starts with apostrophe?*/
if zL==q then z= strip(left(z, length(z) - 1)) /*ends " " ?*/
if z== then iterate /*if Z is now null, skip.*/
if @.z==0 then do; c=c+1; !.c=z; end /*bump word cnt; assign word to array*/
totW= totW + 1; @.z= @.z + 1 /*bump total words; bump a word count*/
end /*while*/
end /*#*/
say commas(totW) ' words found ('commas(c) "unique) in " commas(#),
' records read from file: ' fID; say; return</lang>
- output when using the default inputs:
574,122 words found (23,414 unique) in 67,663 records read from file: les_mes.txt
word rank count
════ ══════ ═══════
the 1 41,088
of 2 19,949
and 3 14,942
a 4 14,595
to 5 13,950
in 6 11,214
he 7 9,607
was 8 8,620
that 9 7,826
it 10 6,535
To see a list of the top 1,000 words that show (among other things) words like it's and other accented words, see the discussion page for this task.
version 2
Inspired by version 1 and adapted for ooRexx. It ignores all characters other than a-z and A-Z (which are translated to a-z). <lang>/*REXX program reads and displays a count of words a file. Word case is ignored.*/ Call time 'R' abc='abcdefghijklmnopqrstuvwxyz' abcABC=abc||translate(abc) parse arg fID_top /*obtain optional arguments from the CL*/ Parse Var fid_top fid ',' top if fID== then fID= 'mis.TXT' /* Use default if not specified */ if top== then top= 10 /* Use default if not specified */ occ.=0 /* occurrences of word (stem) in file */ wn=0 Do While lines(fid)>0 /*loop whilst there are lines in file. */
line=linein(fID)
line=translate(line,abc||abc,abcABC||xrange('00'x,'ff'x)) /*use only lowercase letters*/
Do While line<>
Parse Var line word line /* take a word */
If occ.word=0 Then Do /* not yet in word list */
wn=wn+1
word.wn=word
End
occ.word=occ.word+1
End
End
Say 'We found' wn 'different words' say right('word',40) ' rank count ' /* header */ say right('----',40) '------ -------' /* separator. */ tops=0 Do Until tops>=top | tops>=wn /*process enough words to satisfy TOP.*/
max_occ=0
tl= /*initialize (possibly) a list of words*/
Do wi=1 To wn /*process the list of words in the file*/
word=word.wi /* take a word from the list */
Select
When occ.word>max_occ Then Do /* most occurrences so far */
tl=word /* candidate for output */
max_occ=occ.word /* current maximum occurrences */
End
When occ.word=max_occ Then Do /* tied */
tl=tl word /* add to output candidate */
End
Otherwise /* no candidate (yet) */
Nop
End
End
do d=1 for words(tl)
word=word(tl,d)
say right(word,40) right(tops+1,4) right(occ.word,8)
occ.word=0 /*nullify this word count for next time*/
End
tops=tops+words(tl) /*correctly handle the tied rankings. */
end
Say time('E') 'seconds elapsed'</lang>
- Output:
We found 22820 different words
word rank count
---- ------ -------
the 1 41089
of 2 19949
and 3 14942
a 4 14608
to 5 13951
in 6 11214
he 7 9648
was 8 8621
that 9 7924
it 10 6661
1.750000 seconds elapsed
Ring
<lang ring>
- project : Word count
fp = fopen("Miserables.txt","r") str = fread(fp, getFileSize(fp)) fclose(fp)
mis =substr(str, " ", nl) mis = lower(mis) mis = str2list(mis) count = list(len(mis)) ready = [] for n = 1 to len(mis)
flag = 0
for m = 1 to len(mis)
if mis[n] = mis[m] and n != m
for p = 1 to len(ready)
if m = ready[p]
flag = 1
ok
next
if flag = 0
count[n] = count[n] + 1
ok
ok
next
if flag = 0
add(ready, n)
ok
next for n = 1 to len(count)
for m = n + 1 to len(count)
if count[m] > count[n]
temp = count[n]
count[n] = count[m]
count[m] = temp
temp = mis[n]
mis[n] = mis[m]
mis[m] = temp
ok
next
next for n = 1 to 10
see mis[n] + " " + (count[n] + 1) + nl
next
func getFileSize fp
c_filestart = 0
c_fileend = 2
fseek(fp,0,c_fileend)
nfilesize = ftell(fp)
fseek(fp,0,c_filestart)
return nfilesize
func swap(a, b)
temp = a
a = b
b = temp
return [a, b]
</lang> Output:
the 41089 of 19949 and 14942 a 14608 to 13951 in 11214 he 9648 was 8621 that 7924 it 6661
Ruby
<lang ruby> class String
def wc
n = Hash.new(0)
downcase.scan(/[A-Za-zÀ-ÿ]+/) { |g| n[g] += 1 }
n.sort{|n,g| n[1]<=>g[1]}
end
end
open('135-0.txt') { |n| n.read.wc[-10,10].each{|n| puts n[0].to_s+"->"+n[1].to_s} } </lang>
- Output:
it->6661 that->7924 was->8621 he->9648 in->11214 to->13951 a->14596 and->14942 of->19949 the->41088
Tally and max_by
<lang ruby>RE = /alpha:+/ count = open("135-0.txt").read.downcase.scan(RE).tally.max_by(10, &:last) count.each{|ar| puts ar.join("->") } </lang>
- Output:
the->41092 of->19954 and->14943 a->14546 to->13953 in->11219 he->9649 was->8622 that->7924 it->6661
Chain of Enumerables
<lang ruby>wf = File.read("135-0.txt", :encoding => "UTF-8")
.downcase
.scan(/\w+/)
.each_with_object(Hash.new(0)) { |word, hash| hash[word] += 1 }
.sort_by { |k, v| v }
.reverse
.take(10)
.each_with_index { |w, i|
printf "[%2d] %10s : %d\n",
i += 1,
w[0],
w[1]
} </lang>
- Output:
[ 1] the : 41040 [ 2] of : 19951 [ 3] and : 14942 [ 4] a : 14539 [ 5] to : 13941 [ 6] in : 11209 [ 7] he : 9646 [ 8] was : 8620 [ 9] that : 7922 [10] it : 6659
Rust
<lang Rust>use std::cmp::Reverse; use std::collections::HashMap; use std::fs::File; use std::io::{BufRead, BufReader};
extern crate regex; use regex::Regex;
fn word_count(file: File, n: usize) {
let word_regex = Regex::new("(?i)[a-z']+").unwrap();
let mut words = HashMap::new();
for line in BufReader::new(file).lines() {
word_regex
.find_iter(&line.expect("Read error"))
.map(|m| m.as_str())
.for_each(|word| {
*words.entry(word.to_lowercase()).or_insert(0) += 1;
});
}
let mut words: Vec<_> = words.iter().collect(); words.sort_unstable_by_key(|&(word, count)| (Reverse(count), word));
for (word, count) in words.iter().take(n) {
println!("{:8} {:>8}", word, count);
}
}
fn main() {
word_count(File::open("135-0.txt").expect("File open error"), 10)
}</lang>
- Output:
the 41083 of 19948 and 14941 a 14604 to 13951 in 11212 he 9604 was 8621 that 7824 it 6534
Scala
Featuring online remote file as input
- Output:
Best seen running in your browser Scastie (remote JVM). <lang Scala>import scala.io.Source
object WordCount extends App {
val url = "http://www.gutenberg.org/files/135/135-0.txt" val header = "Rank Word Frequency\n==== ======== ======"
def wordCnt =
Source.fromURL(url).getLines()
.filter(_.nonEmpty)
.flatMap(_.split("""\W+""")).toSeq
.groupBy(_.toLowerCase())
.mapValues(_.size).toSeq
.sortWith { case ((_, v0), (_, v1)) => v0 > v1 }
.take(10).zipWithIndex
println(header)
wordCnt.foreach {
case ((word, count), rank) => println(f"${rank + 1}%4d $word%-8s $count%6d")
}
println(s"\nSuccessfully completed without errors. [total ${scala.compat.Platform.currentTime - executionStart} ms]")
}</lang>
- Output:
Rank Word Frequency ==== ======== ====== 1 the 41036 2 of 19946 3 and 14940 4 a 14589 5 to 13939 6 in 11204 7 he 9645 8 was 8619 9 that 7922 10 it 6659 Successfully completed without errors. [total 4528 ms]
Seed7
The Seed7 program uses the function getHttp, to get the file 135-0.txt directly from Gutemberg. The library scanfile.s7i provides getSimpleSymbol, to get words from a fle. The words are converted to lower case, to assure that "The" and "the" are considered the same.
<lang seed7>$ include "seed7_05.s7i";
include "gethttp.s7i"; include "strifile.s7i"; include "scanfile.s7i"; include "chartype.s7i"; include "console.s7i";
const type: wordHash is hash [string] integer; const type: countHash is hash [integer] array string;
const proc: main is func
local
var file: inFile is STD_NULL;
var string: aWord is "";
var wordHash: numberOfWords is wordHash.EMPTY_HASH;
var countHash: countWords is countHash.EMPTY_HASH;
var array integer: countKeys is 0 times 0;
var integer: index is 0;
var integer: number is 0;
begin
OUT := STD_CONSOLE;
inFile := openStrifile(getHttp("www.gutenberg.org/files/135/135-0.txt"));
while hasNext(inFile) do
aWord := lower(getSimpleSymbol(inFile));
if aWord <> "" and aWord[1] in letter_char then
if aWord in numberOfWords then
incr(numberOfWords[aWord]);
else
numberOfWords @:= [aWord] 1;
end if;
end if;
end while;
countWords := flip(numberOfWords);
countKeys := sort(keys(countWords));
writeln("Word Frequency");
for index range length(countKeys) downto length(countKeys) - 9 do
number := countKeys[index];
for aWord range sort(countWords[number]) do
writeln(aWord rpad 8 <& number);
end for;
end for;
end func;</lang>
- Output:
Word Frequency the 41036 of 19946 and 14940 a 14589 to 13939 in 11204 he 9645 was 8619 that 7922 it 6659
Sidef
<lang ruby>var count = Hash() var file = File(ARGV[0] \\ '135-0.txt')
file.open_r.each { |line|
line.lc.scan(/[\pL]+/).each { |word|
count{word} := 0 ++
}
}
var top = count.sort_by {|_,v| v }.last(10).flip
top.each { |pair|
say "#{pair.key}\t-> #{pair.value}"
}</lang>
- Output:
the -> 41088 of -> 19949 and -> 14942 a -> 14596 to -> 13951 in -> 11214 he -> 9648 was -> 8621 that -> 7924 it -> 6661
Simula
<lang simula>COMMENT COMPILE WITH $ cim -m64 word-count.sim
BEGIN
COMMENT ----- CLASSES FOR GENERAL USE ;
! ABSTRACT HASH KEY TYPE ;
CLASS HASHKEY;
VIRTUAL:
PROCEDURE HASH IS
INTEGER PROCEDURE HASH;;
PROCEDURE EQUALTO IS
BOOLEAN PROCEDURE EQUALTO(K); REF(HASHKEY) K;;
BEGIN
END HASHKEY;
! ABSTRACT HASH VALUE TYPE ;
CLASS HASHVAL;
BEGIN
! THERE IS NOTHING REQUIRED FOR THE VALUE TYPE ;
END HASHVAL;
CLASS HASHMAP;
BEGIN
CLASS INNERHASHMAP(N); INTEGER N;
BEGIN
INTEGER PROCEDURE INDEX(K); REF(HASHKEY) K;
BEGIN
INTEGER I;
IF K == NONE THEN
ERROR("HASHMAP.INDEX: NONE IS NOT A VALID KEY");
I := MOD(K.HASH,N);
LOOP:
IF KEYTABLE(I) == NONE OR ELSE KEYTABLE(I).EQUALTO(K) THEN
INDEX := I
ELSE BEGIN
I := IF I+1 = N THEN 0 ELSE I+1;
GO TO LOOP;
END;
END INDEX;
! PUT SOMETHING IN ;
PROCEDURE PUT(K,V); REF(HASHKEY) K; REF(HASHVAL) V;
BEGIN
INTEGER I;
IF V == NONE THEN
ERROR("HASHMAP.PUT: NONE IS NOT A VALID VALUE");
I := INDEX(K);
IF KEYTABLE(I) == NONE THEN BEGIN
IF SIZE = N THEN
ERROR("HASHMAP.PUT: TABLE FILLED COMPLETELY");
KEYTABLE(I) :- K;
VALTABLE(I) :- V;
SIZE := SIZE+1;
END ELSE
VALTABLE(I) :- V;
END PUT;
! GET SOMETHING OUT ;
REF(HASHVAL) PROCEDURE GET(K); REF(HASHKEY) K;
BEGIN
INTEGER I;
IF K == NONE THEN
ERROR("HASHMAP.GET: NONE IS NOT A VALID KEY");
I := INDEX(K);
IF KEYTABLE(I) == NONE THEN
GET :- NONE ! ERROR("HASHMAP.GET: KEY NOT FOUND");
ELSE
GET :- VALTABLE(I);
END GET;
PROCEDURE CLEAR;
BEGIN
INTEGER I;
FOR I := 0 STEP 1 UNTIL N-1 DO BEGIN
KEYTABLE(I) :- NONE;
VALTABLE(I) :- NONE;
END;
SIZE := 0;
END CLEAR;
! DATA MEMBERS OF CLASS HASHMAP ;
REF(HASHKEY) ARRAY KEYTABLE(0:N-1);
REF(HASHVAL) ARRAY VALTABLE(0:N-1);
INTEGER SIZE;
END INNERHASHMAP;
PROCEDURE PUT(K,V); REF(HASHKEY) K; REF(HASHVAL) V;
BEGIN
IF IMAP.SIZE >= 0.75 * IMAP.N THEN
BEGIN
COMMENT RESIZE HASHMAP ;
REF(INNERHASHMAP) NEWIMAP;
REF(ITERATOR) IT;
NEWIMAP :- NEW INNERHASHMAP(2 * IMAP.N);
IT :- NEW ITERATOR(THIS HASHMAP);
WHILE IT.MORE DO
BEGIN
REF(HASHKEY) KEY;
KEY :- IT.NEXT;
NEWIMAP.PUT(KEY, IMAP.GET(KEY));
END;
IMAP.CLEAR;
IMAP :- NEWIMAP;
END;
IMAP.PUT(K, V);
END;
REF(HASHVAL) PROCEDURE GET(K); REF(HASHKEY) K;
GET :- IMAP.GET(K);
PROCEDURE CLEAR;
IMAP.CLEAR;
INTEGER PROCEDURE SIZE;
SIZE := IMAP.SIZE;
REF(INNERHASHMAP) IMAP;
IMAP :- NEW INNERHASHMAP(16); END HASHMAP;
CLASS ITERATOR(H); REF(HASHMAP) H;
BEGIN
INTEGER POS,KEYCOUNT;
BOOLEAN PROCEDURE MORE;
MORE := KEYCOUNT < H.SIZE;
REF(HASHKEY) PROCEDURE NEXT;
BEGIN
INSPECT H DO
INSPECT IMAP DO
BEGIN
WHILE KEYTABLE(POS) == NONE DO
POS := POS+1;
NEXT :- KEYTABLE(POS);
KEYCOUNT := KEYCOUNT+1;
POS := POS+1;
END;
END NEXT;
END ITERATOR;
COMMENT ----- PROBLEM SPECIFIC CLASSES ;
HASHKEY CLASS TEXTHASHKEY(T); VALUE T; TEXT T;
BEGIN
INTEGER PROCEDURE HASH;
BEGIN
INTEGER I;
T.SETPOS(1);
WHILE T.MORE DO
I := 31*I+RANK(T.GETCHAR);
HASH := I;
END HASH;
BOOLEAN PROCEDURE EQUALTO(K); REF(HASHKEY) K;
EQUALTO := T = K QUA TEXTHASHKEY.T;
END TEXTHASHKEY;
HASHVAL CLASS COUNTER;
BEGIN
INTEGER COUNT;
END COUNTER;
REF(INFILE) INF; REF(HASHMAP) MAP; REF(TEXTHASHKEY) KEY; REF(COUNTER) VAL; REF(ITERATOR) IT; TEXT LINE, WORD; INTEGER I, J, MAXCOUNT, LINENO; INTEGER ARRAY MAXCOUNTS(1:10); REF(TEXTHASHKEY) ARRAY MAXWORDS(1:10);
WORD :- BLANKS(1000); MAP :- NEW HASHMAP; COMMENT MAP WORDS TO COUNTERS ;
INF :- NEW INFILE("135-0.txt");
INF.OPEN(BLANKS(4096));
WHILE NOT INF.LASTITEM DO
BEGIN
BOOLEAN INWORD;
PROCEDURE SAVE;
BEGIN
IF WORD.POS > 1 THEN
BEGIN
KEY :- NEW TEXTHASHKEY(WORD.SUB(1, WORD.POS - 1));
VAL :- MAP.GET(KEY);
IF VAL == NONE THEN
BEGIN
VAL :- NEW COUNTER;
MAP.PUT(KEY, VAL);
END;
VAL.COUNT := VAL.COUNT + 1;
WORD := " ";
WORD.SETPOS(1);
END;
END SAVE;
LINENO := LINENO + 1;
LINE :- COPY(INF.IMAGE).STRIP; INF.INIMAGE;
COMMENT SEARCH WORDS IN LINE ;
COMMENT A WORD IS ANY SEQUENCE OF LETTERS ;
INWORD := FALSE;
LINE.SETPOS(1);
WHILE LINE.MORE DO
BEGIN
CHARACTER CH;
CH := LINE.GETCHAR;
IF CH >= 'a' AND CH <= 'z' THEN
CH := CHAR(RANK(CH) - RANK('a') + RANK('A'));
IF CH >= 'A' AND CH <= 'Z' THEN
BEGIN
IF NOT INWORD THEN
BEGIN
SAVE;
INWORD := TRUE;
END;
WORD.PUTCHAR(CH);
END ELSE
BEGIN
IF INWORD THEN
BEGIN
SAVE;
INWORD := FALSE;
END;
END;
END;
SAVE; COMMENT LAST WORD ;
END;
INF.CLOSE;
COMMENT FIND 10 MOST COMMON WORDS ;
IT :- NEW ITERATOR(MAP);
WHILE IT.MORE DO
BEGIN
KEY :- IT.NEXT;
VAL :- MAP.GET(KEY);
FOR I := 1 STEP 1 UNTIL 10 DO
BEGIN
IF VAL.COUNT >= MAXCOUNTS(I) THEN
BEGIN
FOR J := 10 STEP -1 UNTIL I + 1 DO
BEGIN
MAXCOUNTS(J) := MAXCOUNTS(J - 1);
MAXWORDS(J) :- MAXWORDS(J - 1);
END;
MAXCOUNTS(I) := VAL.COUNT;
MAXWORDS(I) :- KEY;
GO TO BREAK;
END;
END;
BREAK:
END;
COMMENT OUTPUT 10 MOST COMMON WORDS ;
FOR I := 1 STEP 1 UNTIL 10 DO
BEGIN
IF MAXWORDS(I) =/= NONE THEN
BEGIN
OUTINT(MAXCOUNTS(I), 10);
OUTTEXT(" ");
OUTTEXT(MAXWORDS(I) QUA TEXTHASHKEY.T);
OUTIMAGE;
END;
END;
END </lang>
- Output:
41089 THE
19949 OF
14942 AND
14608 A
13951 TO
11214 IN
9648 HE
8621 WAS
7924 THAT
6661 IT
6 garbage collection(s) in 0.2 seconds.
Swift
<lang swift>import Foundation
func printTopWords(path: String, count: Int) throws {
// load file contents into a string
let text = try String(contentsOfFile: path, encoding: String.Encoding.utf8)
var dict = Dictionary<String, Int>()
// split text into words, convert to lowercase and store word counts in dict
let regex = try NSRegularExpression(pattern: "\\w+")
regex.enumerateMatches(in: text, range: NSRange(text.startIndex..., in: text)) {
(match, _, _) in
guard let match = match else { return }
let word = String(text[Range(match.range, in: text)!]).lowercased()
dict[word, default: 0] += 1
}
// sort words by number of occurrences
let wordCounts = dict.sorted(by: {$0.1 > $1.1})
// print the top count words
print("Rank\tWord\tCount")
for (i, (word, n)) in wordCounts.prefix(count).enumerated() {
print("\(i + 1)\t\(word)\t\(n)")
}
}
do {
try printTopWords(path: "135-0.txt", count: 10)
} catch {
print(error.localizedDescription)
}</lang>
- Output:
Rank Word Count 1 the 41039 2 of 19951 3 and 14942 4 a 14527 5 to 13941 6 in 11209 7 he 9646 8 was 8620 9 that 7922 10 it 6659
Tcl
<lang Tcl>lassign $argv head while { [gets stdin line] >= 0 } {
foreach word [regexp -all -inline {[A-Za-z]+} $line] {
dict incr wordcount [string tolower $word]
}
}
set sorted [lsort -stride 2 -index 1 -int -decr $wordcount] foreach {word count} [lrange $sorted 0 [expr {$head * 2 - 1}]] {
puts "$count\t$word"
}</lang>
./wordcount-di.tcl 10 < 135-0.txt
- Output:
41093 the 19954 of 14943 and 14558 a 13953 to 11219 in 9649 he 8622 was 7924 that 6661 it
TMG
McIlroy's Unix TMG: <lang UnixTMG>/* Input format: N text */ /* Only lowercase letters can constitute a word in text. */ /* (c) 2020, Andrii Makukha, 2-clause BSD licence. */
progrm: readn/error
table(freq) table(chain) [firstword = ~0]
loop: not(!<<>>) output
| [j=777] batch/loop loop; /* Main loop */
/* To use less stack, divide input into batches. */ /* (Avoid interpreting entire input as a single "sentence".) */ batch: [j<=0?] succ
| word/skip [j--] skip batch;
skip: string(other); not: params(1) (any($1) fail | ()); readn: string(!<<0123456789>>) readint(n) skip; error: diag(( ={ <ERROR: input must start with a number> * } ));
/* Process a word */ word: smark any(letter) string(letter) scopy
locate/new
[freq[k]++] newmax;
locate: find(freq, k); new: enter(freq, k)
[freq[k] = 1] newmax
[firstword = firstword==~0 ? k : firstword]
enter(chain, i) [chain[i]=prevword] [prevword=k];
newmax: [max = max<freq[k] ? freq[k] : max];
/* Output logic */ output: [next=max] outmax: [max=next] [next=0] [max>0?] [j = prevword] cycle/outmax; cycle: [i = j] [k = freq[i]] [n>0?]
( [max==freq[i]?] parse(wn)
| [(freq[i]<max) & (next<freq[i])?] [next = freq[i]]
| ())
[i != firstword?] [j = chain[i]] cycle;
wn: getnam(freq, i) [k = freq[i]] decimal(k) [n--]
= { 2 < > 1 * };
/* Reads decimal integer */ readint: proc(n;i) ignore(<<>>) [n=0] inta int1: [n = n*12+i] inta\int1; inta: char(i) [i<72?] [(i =- 60)>=0?];
/* Variables */ prevword: 0; /* Head of the linked list */ firstword: 0; /* First word's index to know where to stop output */ k: 0; i: 0; j: 0; n: 0; /* Number of most frequent words to display */ max: 0; /* Current highest number of occurrences */ next: 0; /* Next highest number of occurrences */
/* Tables */ freq: 0; chain: 0;
/* Character classes */ letter: <<abcdefghijklmnopqrstuvwxyz>>; other: !<<abcdefghijklmnopqrstuvwxyz>>;</lang>
Unix TMG didn't have tolower builtin. Therefore, you would use it together with tr: <lang bash>cat file | tr A-Z a-z > file1; ./a.out file1</lang>
Additionally, because 1972 TMG only understood ASCII characters, you might want to strip down the diacritics (e.g., é → e): <lang bash>cat file | uni2ascii -B | tr A-Z a-z > file1; ./a.out file1</lang>
UNIX Shell
This is derived from Doug McIlroy's original 6-line note in the ACM article cited in the task. <lang bash>#!/bin/sh <"$1" tr -cs A-Za-z '\n' | tr A-Z a-z | LC_ALL=C sort | uniq -c | sort -rn | head -n "$2"</lang>
- Output:
$ ./wordcount.sh 135-0.txt 10 41089 the 19949 of 14942 and 14608 a 13951 to 11214 in 9648 he 8621 was 7924 that 6661 it
VBA
In order to use it, you have to adapt the PATHFILE Const.
<lang vb> Option Explicit
Private Const PATHFILE As String = "C:\HOME\VBA\ROSETTA"
Sub Main() Dim arr Dim Dict As Object Dim Book As String, temp As String Dim T# T = Timer
Book = ExtractTxt(PATHFILE & "\les miserables.txt")
temp = RemovePunctuation(Book)
temp = UCase(temp)
arr = Split(temp, " ")
Set Dict = CreateObject("Scripting.Dictionary")
FillDictionary Dict, arr
Erase arr
SortDictByFreq Dict, arr
DisplayTheTopMostUsedWords arr, 10
Debug.Print "Words different in this book : " & Dict.Count Debug.Print "-------------------------" Debug.Print "" Debug.Print "Optionally : " Debug.Print "Frequency of the word MISERABLE : " & DisplayFrequencyOf("MISERABLE", Dict) Debug.Print "Frequency of the word DISASTER : " & DisplayFrequencyOf("DISASTER", Dict) Debug.Print "Frequency of the word ROSETTA_CODE : " & DisplayFrequencyOf("ROSETTA_CODE", Dict) Debug.Print "-------------------------" Debug.Print "Execution Time : " & Format(Timer - T, "0.000") & " sec." End Sub
Private Function ExtractTxt(strFile As String) As String 'http://rosettacode.org/wiki/File_input/output#VBA Dim i As Integer
i = FreeFile
Open strFile For Input As #i
ExtractTxt = Input(LOF(1), #i)
Close #i
End Function
Private Function RemovePunctuation(strBook As String) As String Dim T, i As Integer, temp As String Const PUNCT As String = """,;:!?."
T = Split(StrConv(PUNCT, vbUnicode), Chr(0))
temp = strBook
For i = LBound(T) To UBound(T) - 1
temp = Replace(temp, T(i), " ")
Next
temp = Replace(temp, "--", " ")
temp = Replace(temp, "...", " ")
temp = Replace(temp, vbCrLf, " ")
RemovePunctuation = Replace(temp, " ", " ")
End Function
Private Sub FillDictionary(d As Object, a As Variant) Dim L As Long
For L = LBound(a) To UBound(a)
If a(L) <> "" Then _
d(a(L)) = d(a(L)) + 1
Next
End Sub
Private Sub SortDictByFreq(d As Object, myArr As Variant) Dim K Dim L As Long
ReDim myArr(1 To d.Count, 1 To 2)
For Each K In d.keys
L = L + 1
myArr(L, 1) = K
myArr(L, 2) = CLng(d(K))
Next
SortArray myArr, LBound(myArr), UBound(myArr), 2
End Sub
Private Sub SortArray(a, Le As Long, Ri As Long, Col As Long) Dim ref As Long, L As Long, r As Long, temp As Variant
ref = a((Le + Ri) \ 2, Col)
L = Le
r = Ri
Do
Do While a(L, Col) < ref
L = L + 1
Loop
Do While ref < a(r, Col)
r = r - 1
Loop
If L <= r Then
temp = a(L, 1)
a(L, 1) = a(r, 1)
a(r, 1) = temp
temp = a(L, 2)
a(L, 2) = a(r, 2)
a(r, 2) = temp
L = L + 1
r = r - 1
End If
Loop While L <= r
If L < Ri Then SortArray a, L, Ri, Col
If Le < r Then SortArray a, Le, r, Col
End Sub
Private Sub DisplayTheTopMostUsedWords(arr As Variant, Nb As Long) Dim L As Long, i As Integer
i = 1
Debug.Print "Rank Word Frequency"
Debug.Print "==== ======= ========="
For L = UBound(arr) To UBound(arr) - Nb + 1 Step -1
Debug.Print Left(CStr(i) & " ", 5) & Left(arr(L, 1) & " ", 8) & " " & Format(arr(L, 2), "0 000")
i = i + 1
Next
End Sub
Private Function DisplayFrequencyOf(Word As String, d As Object) As Long
If d.Exists(Word) Then _
DisplayFrequencyOf = d(Word)
End Function</lang>
- Output:
Words different in this book : 25884 ------------------------- Rank Word Frequency ==== ======= ========= 1 THE 40 831 2 OF 19 807 3 AND 14 860 4 A 14 453 5 TO 13 641 6 IN 11 133 7 HE 9 598 8 WAS 8 617 9 THAT 7 807 10 IT 6 517 Optionally : Frequency of the word MISERABLE : 35 Frequency of the word DISASTER : 12 Frequency of the word ROSETTA_CODE : 0 ------------------------- Execution Time : 7,785 sec.
Wren
I've taken the view that 'letter' means either a letter or digit for Unicode codepoints up to 255. I haven't included underscore, hyphen nor apostrophe as these usually separate compound words.
Not very quick (runs in about 47 seconds on my system) though this is partially due to Wren not having regular expressions and the string pattern matching module being written in Wren itself rather than C.
If the Go example is re-run today (21 October 2020), then the output matches this Wren example precisely though it appears that the text file has changed since the former was written more than 2 years ago. <lang ecmascript>import "io" for File import "/str" for Str import "/sort" for Sort import "/fmt" for Fmt import "/pattern" for Pattern
var fileName = "135-0.txt" var text = File.read(fileName).trimEnd() var groups = {} // match runs of A-z, a-z, 0-9 and any non-ASCII letters with code-points < 256 var p = Pattern.new("+1&w") var lines = text.split("\n") for (line in lines) {
var ms = p.findAll(line)
for (m in ms) {
var t = Str.lower(m.text)
groups[t] = groups.containsKey(t) ? groups[t] + 1 : 1
}
} var keyVals = groups.toList Sort.quick(keyVals, 0, keyVals.count - 1) { |i, j| (j.value - i.value).sign } System.print("Rank Word Frequency") System.print("==== ==== =========") for (rank in 1..10) {
var word = keyVals[rank-1].key
var freq = keyVals[rank-1].value
Fmt.print("$2d $-4s $5d", rank, word, freq)
}</lang>
- Output:
Rank Word Frequency ==== ==== ========= 1 the 41092 2 of 19954 3 and 14943 4 a 14546 5 to 13953 6 in 11219 7 he 9649 8 was 8622 9 that 7924 10 it 6661
XQuery
<lang xquery>let $maxentries := 10,
$uri := 'https://www.gutenberg.org/files/135/135-0.txt'
return <words in="{$uri}" top="{$maxentries}"> { (
let $doc := unparsed-text($uri),
$tokens := (
tokenize($doc, '\W+')[normalize-space()]
! lower-case(.)
! normalize-unicode(., 'NFC')
)
return
for $token in $tokens
let $key := $token
group by $key
let $count := count($token)
order by $count descending
return <word key="{$key}" count="{$count}"/>
)[position()=(1 to $maxentries)] }</words></lang>
- Output:
<lang xml><words in="https://www.gutenberg.org/files/135/135-0.txt" top="10">
<word key="the" count="41092"/> <word key="of" count="19954"/> <word key="and" count="14943"/> <word key="a" count="14545"/> <word key="to" count="13953"/> <word key="in" count="11219"/> <word key="he" count="9649"/> <word key="was" count="8622"/> <word key="that" count="7924"/> <word key="it" count="6661"/>
</words></lang>
zkl
<lang zkl>fname,count := vm.arglist; // grab cammand line args
// words may have leading or trailing "_", ie "the" and "_the"
File(fname).pump(Void,"toLower", // read the file line by line and hash words
RegExp("[a-z]+").pump.fp1(Dictionary().incV)) // line-->(word:count,..)
.toList().copy().sort(fcn(a,b){ b[1]<a[1] })[0,count.toInt()] // hash-->list .pump(String,Void.Xplode,"%s,%s\n".fmt).println();</lang>
- Output:
$ zkl bbb ~/Documents/Les\ Miserables.txt 10 the,41089 of,19949 and,14942 a,14608 to,13951 in,11214 he,9648 was,8621 that,7924 it,6661
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