Text processing/Max licenses in use
You are encouraged to solve this task according to the task description, using any language you may know.
A company currently pays a fixed sum for the use of a particular licensed software package. In determining if it has a good deal it decides to calculate its maximum use of the software from its license management log file.
Assume the softwares file faithfully records a checkout event when a copy of the software starts and a checkin event when the software finishes. An example of checkout and checkin events are:
License OUT @ 2008/10/03_23:51:05 for job 4974 ... License IN @ 2008/10/04_00:18:22 for job 4974
Save the 10,000 line log file from here into a local file then write a program to scan the file extracting both the maximum licenses that were out at any time, and the time(s) at which this occurs.
APL
⍝ Copy/paste file's contents into TXT (easiest), or TXT ← ⎕NREAD
I ← TXT[;8+⎕IO]
D ← TXT[;⎕IO+14+⍳19]
lu ← +\ ¯1 * 'OI' ⍳ I
mx ← (⎕IO+⍳⍴lu)/⍨lu= max ← ⌈/ lu
⎕ ← 'Maximum simultaneous license use is ' , ' at the following times:' ,⍨ ⍕max ⋄ ⎕←D[mx;]
Maximum simultaneous license use is 99 at the following times: 2008/10/03_08:39:34 2008/10/03_08:40:40
AutoHotkey
<lang autohotkey> IfNotExist, mlijobs.txt
UrlDownloadToFile, http://rosettacode.org/mlijobs.txt, mlijobs.txt
out := 0, max_out := -1, max_times := ""
Loop, Read, mlijobs.txt {
If InStr(A_LoopReadLine, "OUT")
out++
Else
out--
If (out > max_out)
max_out := out, max_times := ""
If (out = max_out)
{
StringSplit, lineArr, A_LoopReadLine, %A_Space%
max_times .= lineArr4 . "`n"
}
}
MsgBox Maximum use is %max_out% at:`n`n%max_times% </lang>
Maximum use is 99 at: 2008/10/03_08:39:34 2008/10/03_08:40:40
C
<lang c>#include <stdio.h>
- include <stdlib.h>
- include <string.h>
- include <sys/types.h>
- define INOUT_LEN 4
- define TIME_LEN 20
- define MAX_MAXOUT 1000
char inout[INOUT_LEN]; char time[TIME_LEN]; uint jobnum;
char maxtime[MAX_MAXOUT][TIME_LEN];
int main(int argc, char **argv) {
FILE *in = NULL; int l_out = 0, maxout=-1, maxcount=0;
if ( argc > 1 ) {
in = fopen(argv[1], "r");
if ( in == NULL ) {
fprintf(stderr, "cannot read %s\n", argv[1]);
exit(1);
}
} else {
in = stdin;
}
while( fscanf(in, "License %s @ %s for job %u\n", inout, time, &jobnum) != EOF ) {
if ( strcmp(inout, "OUT") == 0 )
l_out++;
else
l_out--;
if ( l_out > maxout ) {
maxout = l_out;
maxcount=0; maxtime[0][0] = '\0';
}
if ( l_out == maxout ) {
if ( maxcount < MAX_MAXOUT ) {
strncpy(maxtime[maxcount], time, TIME_LEN); maxcount++;
} else {
fprintf(stderr, "increase MAX_MAXOUT (now it is %u)\n", MAX_MAXOUT); exit(1);
} } }
printf("Maximum simultaneous license use is %d at the following times:\n", maxout);
for(l_out=0; l_out < maxcount; l_out++) {
printf("%s\n", maxtime[l_out]);
}
if ( in != stdin ) fclose(in); exit(0);
}</lang>
Common Lisp
<lang lisp>(defun max-licenses (&optional (logfile "mlijobs.txt"))
(with-open-file (log logfile :direction :input)
(do ((current-logs 0) (max-logs 0) (max-log-times '())
(line #1=(read-line log nil nil) #1#))
((null line)
(format t "~&Maximum simultaneous license use is ~w at the ~
following time~p: ~{~% ~a~}."
max-logs (length max-log-times) (nreverse max-log-times)))
(cl-ppcre:register-groups-bind (op time)
("License (\\b.*\\b)[ ]{1,2}@ (\\b.*\\b)" line)
(cond ((string= "OUT" op) (incf current-logs))
((string= "IN" op) (decf current-logs))
(t (cerror "Ignore it." "Malformed entry ~s." line)))
(cond ((> current-logs max-logs)
(setf max-logs current-logs
max-log-times (list time)))
((= current-logs max-logs)
(push time max-log-times)))))))</lang>
> (max-licenses) Maximum simultaneous license use is 99 at the following times: 2008/10/03_08:39:34 2008/10/03_08:40:40. NIL
E
<lang e>var out := 0 var maxOut := 0 var maxTimes := []
def events := ["OUT " => 1, "IN " => -1]
for line in <file:mlijobs.txt> {
def `License @{via (events.fetch) delta}@@ @time for job @num$\n` := line
out += delta
if (out > maxOut) {
maxOut := out
maxTimes := []
}
if (out == maxOut) {
maxTimes with= time
}
}
println(`Maximum simultaneous license use is $maxOut at the following times:`) for time in maxTimes {
println(` $time`)
}</lang>
Fortran
<lang fortran>
PROGRAM MAX_LICENSES
IMPLICIT NONE
INTEGER :: out=0, maxout=0, maxcount=0, err
CHARACTER(50) :: line
CHARACTER(19) :: maxtime(100)
OPEN (UNIT=5, FILE="Licenses.txt", STATUS="OLD", IOSTAT=err)
IF (err > 0) THEN
WRITE(*,*) "Error opening file Licenses.txt"
STOP
END IF
DO
READ(5, "(A)", IOSTAT=err) line
IF (err == -1) EXIT ! EOF detected
IF (line(9:9) == "O") THEN
out = out + 1
ELSE IF (line(9:9) == "I") THEN
out = out - 1
END IF
IF (out > maxout ) THEN
maxout = maxout + 1
maxcount = 1
maxtime(maxcount) = line(15:33)
ELSE IF (out == maxout) THEN
maxcount = maxcount + 1
maxtime(maxcount) = line(15:33)
END IF
END DO
CLOSE(5)
WRITE(*,"(A,I4,A)") "Maximum simultaneous license use is", maxout, " at the following times:"
WRITE(*,"(A)") maxtime(1:maxcount)
END PROGRAM MAX_LICENSES
</lang> Output
Maximum simultaneous license use is 99 at the following times: 2008/10/03_08:39:34 2008/10/03_08:40:40
Haskell
<lang haskell> import Data.List
main = do
f <- readFile "./../Puzzels/Rosetta/inout.txt"
let (ioo,dt) = unzip. map ((\(_:io:_:t:_)-> (io,t)). words) . lines $ f
cio = drop 1 . scanl (\c io -> if io == "IN" then pred c else succ c) 0 $ ioo
mo = maximum cio
putStrLn $ "Maximum simultaneous license use is " ++ show mo ++ " at:"
mapM_ (putStrLn . (dt!!)) . elemIndices mo $ cio
</lang>
J
<lang j>
NB. Parse data, select columns
'I D' =: (8 ; 14+i.19) { ::]"1 L:0 ];._2 ] 1!:1 ::("_) <'licenses.txt'
NB. Calculate number of licenses used at any given time
lu =: +/\ _1 ^ 'OI' i. I
NB. Find the maxima
mx =: (I.@:= >./) lu
NB. Output results
(mx { D) ,~ 'Maximum simultaneous license use is ' , ' at the following times:' ,~ ": {. ,mx { lu
</lang>
Maximum simultaneous license use is 99 at the following times: 2008/10/03_08:39:34 2008/10/03_08:40:40
Java
<lang java5>import java.io.BufferedReader; import java.io.FileNotFoundException; import java.io.FileReader; import java.io.IOException; import java.util.LinkedList;
public class License {
public static void main(String[] args) throws FileNotFoundException, IOException{
BufferedReader in = new BufferedReader(new FileReader(args[0]));
int max = Integer.MIN_VALUE;
LinkedList<String> dates = new LinkedList<String>();
String line;
int count = 0;
while((line = in.readLine()) != null){
if(line.startsWith("License OUT ")) count++;
if(line.startsWith("License IN ")) count--;
if(count > max){
max = count;
String date = line.split(" ")[3];
dates.clear();
dates.add(date);
}else if(count == max){
String date = line.split(" ")[3];
dates.add(date);
}
}
System.out.println("Max licenses out: "+max);
System.out.println("At time(s): "+dates);
}
}</lang>
Max licenses out: 99 At time(s): [2008/10/03_08:39:34, 2008/10/03_08:40:40]
MAXScript
<lang maxscript>fn licencesInUse = (
local logFile = openFile "mlijobs.txt" local out = 0 local maxOut = -1 local maxTimes = #()
while not EOF logFile do
(
line = readLine logFile
if findString line "OUT" != undefined then
(
out += 1
)
else
(
out -= 1
)
if out > maxOut then
(
maxOut = out
maxTimes = #()
)
if out == maxOut then
(
append maxTimes (filterString line " ")[4]
)
)
format "Maximum simultaneous license use is % at the following times:\n" maxOut
for time in maxTimes do
(
format "%\n" time
)
close logFile
)
licencesInUse()</lang> Output
Maximum simultaneous license use is 99 at the following times: 2008/10/03_08:39:34 2008/10/03_08:40:40
OCaml
<lang ocaml>let () =
let out = ref 0 in let max_out = ref(-1) in let max_times = ref [] in
let ic = open_in "mlijobs.txt" in
try while true do
let line = input_line ic in
let io, date, n =
Scanf.sscanf line
"License %3[IN OUT] %_c %19[0-9/:_] for job %d"
(fun io date n -> (io, date, n))
in
if io = "OUT" then incr out else decr out;
if !out > !max_out then
( max_out := !out;
max_times := date :: []; )
else if !out = !max_out then
max_times := date :: !max_times;
done
with End_of_file ->
close_in ic;
Printf.printf
"Maximum simultaneous license use is %d \
at the following times:\n" !max_out;
List.iter print_endline !max_times;
- </lang>
Perl
<lang perl>#!/usr/bin/perl -w use strict;
my $out = 0; my $max_out = -1; my @max_times;
open FH, '<mlijobs.txt' or die "Can't open file: $!"; while (<FH>) {
chomp;
if (/OUT/) {
$out++;
} else {
$out--;
}
if ($out > $max_out) {
$max_out = $out;
@max_times = ();
}
if ($out == $max_out) {
push @max_times, (split)[3];
}
} close FH;
print "Maximum simultaneous license use is $max_out at the following times:\n"; print " $_\n" foreach @max_times;</lang> Example output:
Maximum simultaneous license use is 99 at the following times: 2008/10/03_08:39:34 2008/10/03_08:40:40
Python
<lang python>out = 0 max_out = -1 max_times = []
for job in open('mlijobs.txt'):
if "OUT" in job:
out += 1
else:
out -= 1
if out > max_out:
max_out = out
max_times = []
if out == max_out:
max_times.append(job.split()[3])
print "Maximum simultaneous license use is", max_out, "at the following times:" for time in max_times:
print " ", time</lang>
Example output:
Maximum simultaneous license use is 99 at the following times: 2008/10/03_08:39:34 2008/10/03_08:40:40
R
<lang R>
- Read in data, discard useless bits
dfr <- read.table("mlijobs.txt") dfr <- dfr[,c(2,4)]
- Find most concurrent licences, and when
n.checked.out <- cumsum(ifelse(dfr$V2=="OUT", 1, -1)) times <- strptime(dfr$V4, "%Y/%m/%d_%H:%M:%S") most.checked.out <- max(n.checked.out) when.most.checked.out <- times[which(n.checked.out==most.checked.out)]
- As a bonus, plot license use
plot(times, n.checked.out, type="s") </lang>
Ruby
<lang ruby>out = 0 max_out = -1 max_times = []
open('mlijobs.txt') do |file|
for job in file
if job.include?("OUT")
out += 1
else
out -= 1
end
if out > max_out
max_out = out
max_times = []
end
if out == max_out
max_times << job.split[3]
end
end
end
puts "Maximum simultaneous license use is #{max_out} at the following times:" for time in max_times
puts " #{time}"
end</lang> Example output:
Maximum simultaneous license use is 99 at the following times: 2008/10/03_08:39:34 2008/10/03_08:40:40
Tcl
<lang tcl> set out 0
set max_out -1
set max_times {}
foreach job [split [read [open "mlijobs.txt" "r"]] "\n"] {
if {[lindex $job 1] == "OUT"} {
incr out
} {
incr out -1
}
if {$out > $max_out} {
set max_out $out
set max_times {}
}
if {$out == $max_out} {
lappend max_times [lindex $job 3]
}
}
puts "Maximum simultaneous license use is $max_out at the following times:"
foreach t $max_times {
puts " $t"
}</lang>
Output matches Python
Ursala
Four functions are defined. Log lexes the log file, which can be accessed as a pre-declared constant without explicit I/O by being given as a compile-time command line parameter. Scan accumulates running totals of licenses in use. Search identifies the maxima, and format transforms the results to human readable form.
<lang Ursala>
- import std
- import nat
log = ^(~&hh==`O,~&tth)*FtPS sep` *F mlijobs_dot_txt scan = @NiX ~&ar^& ^C/~&alrhr2X ~&arlh?/~&faNlCrtPXPR ~&fabt2R search = @lSzyCrSPp leql$^&hl@lK2; ^/length@hl ~&rS format = ^|C\~& --' licenses in use at'@h+ %nP
- show+
main = format search scan log</lang> output:
99 licenses in use at 2008/10/03_08:39:34 2008/10/03_08:40:40
Vedit macro language
<lang vedit> File_Open("|(PATH_ONLY)\data\mlijobs.txt", BROWSE)
- 1 = 0 // Number of licenses active
- 2 = 0 // Max number of active licenses found
Repeat(ALL) {
Search("|{OUT,IN}|W@", ADVANCE+ERRBREAK)
if (Match_Item == 1) { // "OUT"
#1++
if (#1 > #2) { // new high value
#2 = #1
Reg_Empty(10) // empty the time list
}
if (#1 == #2) { // same as high value
Reg_Copy(10, 1, APPEND) // store time
}
} else { // "IN"
#1--
}
}
Message("Maximum simultaneous license use is ") Num_Type(#2, LEFT+NOCR) Message(" at the following times:\n") Reg_Type(10)
Buf_Quit(OK) </lang>
Output:
Maximum simultaneous license use is 99 at the following times: 2008/10/03_08:39:34 for job 1833 2008/10/03_08:40:40 for job 1837