Text processing/Max licenses in use: Difference between revisions

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(→‎{{header|J}}: use Python's algorithm & assumptions, to make it easier to compare)
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maxouttimes.append(time)
maxouttimes.append(time)
else:
else:
out -=1
out -= 1
return maxout, maxouttimes
return maxout, maxouttimes
if __name__ == '__main__':
if __name__ == '__main__':
log = file('license_example_log.txt')
log = open('license_example_log.txt')
maxout, maxouttimes = max_out(log)
maxout, maxouttimes = max_out(log)
log.close()
log.close()
print "Maximum simultaneous license use is %i at the following times:\n %s" % (
print "Maximum simultaneous license use is %i at the following times:" % maxout
maxout, '\n '.join(maxouttimes))</python>
for x in maxouttimes:
print x</python>
Example output:
Example output:
<pre>Maximum simultaneous license use is 99 at the following times:
<pre>Maximum simultaneous license use is 99 at the following times:

Revision as of 06:15, 4 October 2008

Task
Text processing/Max licenses in use
You are encouraged to solve this task according to the task description, using any language you may know.

A company currently pays a fixed sum for the use of a particular licensed software package. In determining if it has a good deal it decides to calculate its maximum use of the software from its license management log file.

Assume the softwares file faithfully records a checkout event when a copy of the software starts and a checkin event when the software finishes. An example of checkout and checkin events are: 

 License OUT @ 2008/10/03_23:51:05 for job 4974
 ...
 License IN  @ 2008/10/04_00:18:22 for job 4974


Save the 10,000 line log file from here* into a local file then write a program to scan the file extracting both the maximum licenses that were out at any time, and the time(s) at which this occurs.

  • Note: The page uses javascript to display a text file, so it may be best to cut-n-paste from a browser to a text file rather than downloading the URL.

J

   NB.  Parse data, select columns
   'I D' =: (8 ; 14+i.19) { ::]"1 L:0 ];._2 ] 1!:1 ::(''"_) <'licenses.txt'
   
   NB.  Calculate number of licenses used at any given time
   lu    =:  +/\ _1 ^ 'OI' i. I
   
   NB.  Find the maxima
   mx    =:  (I.@:= >./) lu
  
   NB.  Output results
   (mx { D) ,~ 'Maximum simultaneous license use is ' , ' at the following times:' ,~ ": {. ,mx { lu
Maximum simultaneous license use is 99 at the following times:
2008/10/03_08:39:34                                           
2008/10/03_08:40:40

Python

Python 2.6 <python>def max_out(logfile): 

   maxout = 0
   maxouttimes = []
   out = 0
   for line in logfile:
       direction = line[8]
       time = line[14:33]
       if direction == 'O':
           out += 1
           if out > maxout:
               maxout = out
               maxouttimes = [time]
           elif out == maxout:
               maxouttimes.append(time)
       else:
           out -= 1
   return maxout, maxouttimes

if __name__ == '__main__': 

   log = open('license_example_log.txt')
   maxout, maxouttimes = max_out(log)
   log.close()
   print "Maximum simultaneous license use is %i at the following times:" % maxout
   for x in maxouttimes:
       print x</python>

Example output: 

Maximum simultaneous license use is 99 at the following times:
 2008/10/03_08:39:34
 2008/10/03_08:40:40
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