Tau function
You are encouraged to solve this task according to the task description, using any language you may know.
Given a positive integer, count the number of its positive divisors.
- Task
Show the result for the first 100 positive integers.
- Related task
11l
<lang 11l>F tau(n)
V ans = 0
V i = 1
V j = 1
L i * i <= n
I 0 == n % i
ans++
j = n I/ i
I j != i
ans++
i++
R ans
print((1..100).map(n -> tau(n)))</lang>
- Output:
[1, 2, 2, 3, 2, 4, 2, 4, 3, 4, 2, 6, 2, 4, 4, 5, 2, 6, 2, 6, 4, 4, 2, 8, 3, 4, 4, 6, 2, 8, 2, 6, 4, 4, 4, 9, 2, 4, 4, 8, 2, 8, 2, 6, 6, 4, 2, 10, 3, 6, 4, 6, 2, 8, 4, 8, 4, 4, 2, 12, 2, 4, 6, 7, 4, 8, 2, 6, 4, 8, 2, 12, 2, 4, 6, 6, 4, 8, 2, 10, 5, 4, 2, 12, 4, 4, 4, 8, 2, 12, 4, 6, 4, 4, 4, 12, 2, 6, 6, 9]
Action!
<lang Action!>CARD FUNC DivisorCount(CARD n)
CARD result,p,count result=1 WHILE (n&1)=0 DO result==+1 n=n RSH 1 OD
p=3
WHILE p*p<=n
DO
count=1
WHILE n MOD p=0
DO
count==+1
n==/p
OD
result==*count
p==+2
OD
IF n>1 THEN result==*2 FI
RETURN (result)
PROC Main()
CARD max=[100],n,divCount
PrintF("Tau function for the first %U numbers%E",max)
FOR n=1 TO max
DO
divCount=DivisorCount(n)
PrintC(divCount) Put(32)
OD
RETURN</lang>
- Output:
Screenshot from Atari 8-bit computer
Tau function for the first 100 numbers 1 2 2 3 2 4 2 4 3 4 2 6 2 4 4 5 2 6 2 6 4 4 2 8 3 4 4 6 2 8 2 6 4 4 4 9 2 4 4 8 2 8 2 6 6 4 2 10 3 6 4 6 2 8 4 8 4 4 2 12 2 4 6 7 4 8 2 6 4 8 2 12 2 4 6 6 4 8 2 10 5 4 2 12 4 4 4 8 2 12 4 6 4 4 4 12 2 6 6 9
ALGOL W
<lang algolw>begin % find the count of the divisors of the first 100 positive integers %
% calculates the number of divisors of v %
integer procedure divisor_count( integer value v ) ; begin
integer total, n, p;
total := 1; n := v;
% Deal with powers of 2 first %
while not odd( n ) do begin
total := total + 1;
n := n div 2
end while_not_odd_n ;
% Odd prime factors up to the square root %
p := 3;
while ( p * p ) <= n do begin
integer count;
count := 1;
while n rem p = 0 do begin
count := count + 1;
n := n div p
end while_n_rem_p_eq_0 ;
p := p + 2;
total := total * count
end while_p_x_p_le_n ;
% If n > 1 then it's prime %
if n > 1 then total := total * 2;
total
end divisor_count ;
begin
integer limit;
limit := 100;
write( i_w := 1, s_w := 0, "Count of divisors for the first ", limit, " positive integers:" );
for n := 1 until limit do begin
if n rem 20 = 1 then write();
writeon( i_w := 3, s_w := 1, divisor_count( n ) )
end for_n
end
end.</lang>
- Output:
Count of divisors for the first 100 positive integers: 1 2 2 3 2 4 2 4 3 4 2 6 2 4 4 5 2 6 2 6 4 4 2 8 3 4 4 6 2 8 2 6 4 4 4 9 2 4 4 8 2 8 2 6 6 4 2 10 3 6 4 6 2 8 4 8 4 4 2 12 2 4 6 7 4 8 2 6 4 8 2 12 2 4 6 6 4 8 2 10 5 4 2 12 4 4 4 8 2 12 4 6 4 4 4 12 2 6 6 9
AppleScript
<lang applescript>on factorCount(n)
if (n < 1) then return 0
set counter to 2
set sqrt to n ^ 0.5
if (sqrt mod 1 = 0) then set counter to 1
repeat with i from (sqrt div 1) to 2 by -1
if (n mod i = 0) then set counter to counter + 2
end repeat
return counter
end factorCount
-- Task code: local output, n, astid set output to {"Positive divisor counts for integers 1 to 100:"} repeat with n from 1 to 100
if (n mod 20 = 1) then set end of output to linefeed
set end of output to text -3 thru -1 of (" " & factorCount(n))
end repeat set astid to AppleScript's text item delimiters set AppleScript's text item delimiters to "" set output to output as text set AppleScript's text item delimiters to astid return output</lang>
- Output:
<lang applescript>"Positive divisor counts for integers 1 to 100:
1 2 2 3 2 4 2 4 3 4 2 6 2 4 4 5 2 6 2 6 4 4 2 8 3 4 4 6 2 8 2 6 4 4 4 9 2 4 4 8 2 8 2 6 6 4 2 10 3 6 4 6 2 8 4 8 4 4 2 12 2 4 6 7 4 8 2 6 4 8 2 12 2 4 6 6 4 8 2 10 5 4 2 12 4 4 4 8 2 12 4 6 4 4 4 12 2 6 6 9"</lang>
Arturo
<lang rebol>tau: function [x] -> size factors x
loop split.every:20 1..100 => [
print map & => [pad to :string tau & 3]
]</lang>
- Output:
1 2 2 3 2 4 2 4 3 4 2 6 2 4 4 5 2 6 2 6 4 4 2 8 3 4 4 6 2 8 2 6 4 4 4 9 2 4 4 8 2 8 2 6 6 4 2 10 3 6 4 6 2 8 4 8 4 4 2 12 2 4 6 7 4 8 2 6 4 8 2 12 2 4 6 6 4 8 2 10 5 4 2 12 4 4 4 8 2 12 4 6 4 4 4 12 2 6 6 9
AWK
<lang AWK>
- syntax: GAWK -f TAU_FUNCTION.AWK
BEGIN {
print("The tau functions for the first 100 positive integers:")
for (i=1; i<=100; i++) {
printf("%2d ",count_divisors(i))
if (i % 10 == 0) {
printf("\n")
}
}
exit(0)
} function count_divisors(n, count,i) {
for (i=1; i*i<=n; i++) {
if (n % i == 0) {
count += (i == n / i) ? 1 : 2
}
}
return(count)
} </lang>
- Output:
The tau functions for the first 100 positive integers: 1 2 2 3 2 4 2 4 3 4 2 6 2 4 4 5 2 6 2 6 4 4 2 8 3 4 4 6 2 8 2 6 4 4 4 9 2 4 4 8 2 8 2 6 6 4 2 10 3 6 4 6 2 8 4 8 4 4 2 12 2 4 6 7 4 8 2 6 4 8 2 12 2 4 6 6 4 8 2 10 5 4 2 12 4 4 4 8 2 12 4 6 4 4 4 12 2 6 6 9
BASIC
<lang gwbasic>10 DEFINT A-Z 20 FOR I=1 TO 100 30 N=I: GOSUB 100 40 PRINT USING " ##";T; 50 IF I MOD 20=0 THEN PRINT 60 NEXT 70 END 100 T=1 110 IF (N AND 1)=0 THEN N=N\2: T=T+1: GOTO 110 120 P=3 130 GOTO 180 140 C=1 150 IF N MOD P=0 THEN N=N\P: C=C+1: GOTO 150 160 T=T*C 170 P=P+2 180 IF P*P<=N GOTO 140 190 IF N>1 THEN T=T*2 200 RETURN</lang>
- Output:
1 2 2 3 2 4 2 4 3 4 2 6 2 4 4 5 2 6 2 6 4 4 2 8 3 4 4 6 2 8 2 6 4 4 4 9 2 4 4 8 2 8 2 6 6 4 2 10 3 6 4 6 2 8 4 8 4 4 2 12 2 4 6 7 4 8 2 6 4 8 2 12 2 4 6 6 4 8 2 10 5 4 2 12 4 4 4 8 2 12 4 6 4 4 4 12 2 6 6 9
BCPL
<lang bcpl>get "libhdr"
let tau(n) = valof $( let total = 1 and p = 3
while (n & 1) = 0
$( total := total + 1
n := n >> 1
$)
while p*p <= n
$( let count = 1
while n rem p = 0
$( count := count + 1
n := n / p
$)
total := total * count
p := p + 2
$)
if n>1 then total := total * 2
resultis total
$)
let start() be
for n=1 to 100
$( writed(tau(n), 3)
if n rem 20 = 0 then wrch('*N')
$)</lang>
- Output:
1 2 2 3 2 4 2 4 3 4 2 6 2 4 4 5 2 6 2 6 4 4 2 8 3 4 4 6 2 8 2 6 4 4 4 9 2 4 4 8 2 8 2 6 6 4 2 10 3 6 4 6 2 8 4 8 4 4 2 12 2 4 6 7 4 8 2 6 4 8 2 12 2 4 6 6 4 8 2 10 5 4 2 12 4 4 4 8 2 12 4 6 4 4 4 12 2 6 6 9
C
<lang c>#include <stdio.h>
// See https://en.wikipedia.org/wiki/Divisor_function unsigned int divisor_count(unsigned int n) {
unsigned int total = 1;
// Deal with powers of 2 first
for (; (n & 1) == 0; n >>= 1) {
++total;
}
// Odd prime factors up to the square root
for (unsigned int p = 3; p * p <= n; p += 2) {
unsigned int count = 1;
for (; n % p == 0; n /= p) {
++count;
}
total *= count;
}
// If n > 1 then it's prime
if (n > 1) {
total *= 2;
}
return total;
}
int main() {
const unsigned int limit = 100; unsigned int n;
printf("Count of divisors for the first %d positive integers:\n", limit);
for (n = 1; n <= limit; ++n) {
printf("%3d", divisor_count(n));
if (n % 20 == 0) {
printf("\n");
}
}
return 0;
}</lang>
- Output:
Count of divisors for the first 100 positive integers: 1 2 2 3 2 4 2 4 3 4 2 6 2 4 4 5 2 6 2 6 4 4 2 8 3 4 4 6 2 8 2 6 4 4 4 9 2 4 4 8 2 8 2 6 6 4 2 10 3 6 4 6 2 8 4 8 4 4 2 12 2 4 6 7 4 8 2 6 4 8 2 12 2 4 6 6 4 8 2 10 5 4 2 12 4 4 4 8 2 12 4 6 4 4 4 12 2 6 6 9
C++
<lang cpp>#include <iomanip>
- include <iostream>
// See https://en.wikipedia.org/wiki/Divisor_function unsigned int divisor_count(unsigned int n) {
unsigned int total = 1;
// Deal with powers of 2 first
for (; (n & 1) == 0; n >>= 1)
++total;
// Odd prime factors up to the square root
for (unsigned int p = 3; p * p <= n; p += 2) {
unsigned int count = 1;
for (; n % p == 0; n /= p)
++count;
total *= count;
}
// If n > 1 then it's prime
if (n > 1)
total *= 2;
return total;
}
int main() {
const unsigned int limit = 100;
std::cout << "Count of divisors for the first " << limit << " positive integers:\n";
for (unsigned int n = 1; n <= limit; ++n) {
std::cout << std::setw(3) << divisor_count(n);
if (n % 20 == 0)
std::cout << '\n';
}
}</lang>
- Output:
Count of divisors for the first 100 positive integers: 1 2 2 3 2 4 2 4 3 4 2 6 2 4 4 5 2 6 2 6 4 4 2 8 3 4 4 6 2 8 2 6 4 4 4 9 2 4 4 8 2 8 2 6 6 4 2 10 3 6 4 6 2 8 4 8 4 4 2 12 2 4 6 7 4 8 2 6 4 8 2 12 2 4 6 6 4 8 2 10 5 4 2 12 4 4 4 8 2 12 4 6 4 4 4 12 2 6 6 9
CLU
<lang clu>tau = proc (n: int) returns (int)
total: int := 1
while n//2 = 0 do
total := total + 1
n := n/2
end
p: int := 3
while p*p <= n do
count: int := 1
while n//p = 0 do
count := count + 1
n := n/p
end
total := total * count
p := p+2
end
if n>1 then
total := total * 2
end
return(total)
end tau
start_up = proc ()
po: stream := stream$primary_output()
for n: int in int$from_to(1, 100) do
stream$putright(po, int$unparse(tau(n)), 3)
if n//20=0 then stream$putl(po, "") end
end
end start_up</lang>
- Output:
1 2 2 3 2 4 2 4 3 4 2 6 2 4 4 5 2 6 2 6 4 4 2 8 3 4 4 6 2 8 2 6 4 4 4 9 2 4 4 8 2 8 2 6 6 4 2 10 3 6 4 6 2 8 4 8 4 4 2 12 2 4 6 7 4 8 2 6 4 8 2 12 2 4 6 6 4 8 2 10 5 4 2 12 4 4 4 8 2 12 4 6 4 4 4 12 2 6 6 9
COBOL
<lang cobol> IDENTIFICATION DIVISION.
PROGRAM-ID. TAU-FUNCTION.
DATA DIVISION.
WORKING-STORAGE SECTION.
01 TAU-VARS.
03 TOTAL PIC 999.
03 N PIC 999.
03 FILLER REDEFINES N.
05 FILLER PIC 99.
05 FILLER PIC 9.
88 N-EVEN VALUES 0, 2, 4, 6, 8.
03 P PIC 999.
03 P-SQUARED PIC 999.
03 N-DIV-P PIC 999V999.
03 FILLER REDEFINES N-DIV-P.
05 NEXT-N PIC 999.
05 FILLER PIC 999.
88 DIVISIBLE VALUE ZERO.
03 F-COUNT PIC 999.
01 CONTROL-VARS.
03 I PIC 999.
01 OUT-VARS.
03 OUT-ITM PIC ZZ9.
03 OUT-STR PIC X(80) VALUE SPACES.
03 OUT-PTR PIC 99 VALUE 1.
PROCEDURE DIVISION.
BEGIN.
PERFORM SHOW-TAU VARYING I FROM 1 BY 1
UNTIL I IS GREATER THAN 100.
STOP RUN.
SHOW-TAU.
MOVE I TO N.
PERFORM TAU.
MOVE TOTAL TO OUT-ITM.
STRING OUT-ITM DELIMITED BY SIZE INTO OUT-STR
WITH POINTER OUT-PTR.
IF OUT-PTR IS EQUAL TO 61,
DISPLAY OUT-STR,
MOVE 1 TO OUT-PTR.
TAU.
MOVE 1 TO TOTAL.
PERFORM POWER-OF-2 UNTIL NOT N-EVEN.
MOVE ZERO TO P-SQUARED.
PERFORM ODD-FACTOR THRU ODD-FACTOR-LOOP
VARYING P FROM 3 BY 2
UNTIL P-SQUARED IS GREATER THAN N.
IF N IS GREATER THAN 1,
MULTIPLY 2 BY TOTAL.
POWER-OF-2.
ADD 1 TO TOTAL.
DIVIDE 2 INTO N.
ODD-FACTOR.
MULTIPLY P BY P GIVING P-SQUARED.
MOVE 1 TO F-COUNT.
ODD-FACTOR-LOOP.
DIVIDE N BY P GIVING N-DIV-P.
IF DIVISIBLE,
MOVE NEXT-N TO N,
ADD 1 TO F-COUNT,
GO TO ODD-FACTOR-LOOP.
MULTIPLY F-COUNT BY TOTAL.</lang>
- Output:
1 2 2 3 2 4 2 4 3 4 2 6 2 4 4 5 2 6 2 6 4 4 2 8 3 4 4 6 2 8 2 6 4 4 4 9 2 4 4 8 2 8 2 6 6 4 2 10 3 6 4 6 2 8 4 8 4 4 2 12 2 4 6 7 4 8 2 6 4 8 2 12 2 4 6 6 4 8 2 10 5 4 2 12 4 4 4 8 2 12 4 6 4 4 4 12 2 6 6 9
Cowgol
<lang cowgol>include "cowgol.coh";
typedef N is uint8; sub tau(n: N): (total: N) is
total := 1;
while n & 1 == 0 loop
total := total + 1;
n := n >> 1;
end loop;
var p: N := 3;
while p*p <= n loop
var count: N := 1;
while n%p == 0 loop
count := count + 1;
n := n / p;
end loop;
total := total * count;
p := p + 2;
end loop;
if n>1 then
total := total << 1;
end if;
end sub;
sub print2(n: uint8) is
print_char(' ');
if n<10
then print_char(' ');
else print_i8(n/10);
end if;
print_i8(n%10);
end sub;
var n: N := 1; while n <= 100 loop
print2(tau(n)); if n % 20 == 0 then print_nl(); end if; n := n + 1;
end loop;</lang>
- Output:
1 2 2 3 2 4 2 4 3 4 2 6 2 4 4 5 2 6 2 6 4 4 2 8 3 4 4 6 2 8 2 6 4 4 4 9 2 4 4 8 2 8 2 6 6 4 2 10 3 6 4 6 2 8 4 8 4 4 2 12 2 4 6 7 4 8 2 6 4 8 2 12 2 4 6 6 4 8 2 10 5 4 2 12 4 4 4 8 2 12 4 6 4 4 4 12 2 6 6 9
D
<lang d>import std.stdio;
// See https://en.wikipedia.org/wiki/Divisor_function uint divisor_count(uint n) {
uint total = 1;
// Deal with powers of 2 first
for (; (n & 1) == 0; n >>= 1) {
++total;
}
// Odd prime factors up to the square root
for (uint p = 3; p * p <= n; p += 2) {
uint count = 1;
for (; n % p == 0; n /= p) {
++count;
}
total *= count;
}
// If n > 1 then it's prime
if (n > 1) {
total *= 2;
}
return total;
}
void main() {
immutable limit = 100;
writeln("Count of divisors for the first ", limit, " positive integers:");
for (uint n = 1; n <= limit; ++n) {
writef("%3d", divisor_count(n));
if (n % 20 == 0) {
writeln;
}
}
}</lang>
- Output:
Count of divisors for the first 100 positive integers: 1 2 2 3 2 4 2 4 3 4 2 6 2 4 4 5 2 6 2 6 4 4 2 8 3 4 4 6 2 8 2 6 4 4 4 9 2 4 4 8 2 8 2 6 6 4 2 10 3 6 4 6 2 8 4 8 4 4 2 12 2 4 6 7 4 8 2 6 4 8 2 12 2 4 6 6 4 8 2 10 5 4 2 12 4 4 4 8 2 12 4 6 4 4 4 12 2 6 6 9
Delphi
<lang Delphi> program Tau_function;
{$APPTYPE CONSOLE}
uses
System.SysUtils;
function CountDivisors(n: Integer): Integer; begin
Result := 0; var i := 1; var k := 2; if (n mod 2) = 0 then k := 1;
while i * i <= n do
begin
if (n mod i) = 0 then
begin
inc(Result);
var j := n div i;
if j <> i then
inc(Result);
end;
inc(i, k);
end;
end;
begin
writeln('The tau functions for the first 100 positive integers are:');
for var i := 1 to 100 do
begin
write(CountDivisors(i): 2, ' ');
if (i mod 20) = 0 then
writeln;
end;
readln;
end.</lang>
Dyalect
<lang dyalect>func divisorCount(number) {
var n = number
var total = 1
while (n &&& 1) == 0 {
total += 1
n >>>= 1
}
var p = 3
while p * p <= n {
var count = 1
while n % p == 0 {
count += 1
n /= p
}
total *= count
p += 2
}
if n > 1 {
total *= 2
}
total
}
let limit = 100 print("Count of divisors for the first \(limit) positive integers:") for n in 1..limit {
print(divisorCount(number: n).toString().padLeft(2, ' ') + " ", terminator: "") print() when n % 20 == 0
}</lang>
- Output:
Count of divisors for the first 100 positive integers: 1 2 2 3 2 4 2 4 3 4 2 6 2 4 4 5 2 6 2 6 4 4 2 8 3 4 4 6 2 8 2 6 4 4 4 9 2 4 4 8 2 8 2 6 6 4 2 10 3 6 4 6 2 8 4 8 4 4 2 12 2 4 6 7 4 8 2 6 4 8 2 12 2 4 6 6 4 8 2 10 5 4 2 12 4 4 4 8 2 12 4 6 4 4 4 12 2 6 6 9
F#
This task uses Extensible Prime Generator (F#).
<lang fsharp>
// Tau function. Nigel Galloway: March 10th., 2021
let tau u=let P=primes32()
let rec fN g=match u%g with 0->g |_->fN(Seq.head P)
let rec fG n i g e l=match n=u,u%l with (true,_)->e |(_,0)->fG (n*i) i g (e+g)(l*i) |_->let q=fN(Seq.head P) in fG (n*q) q e (e+e) (q*q)
let n=Seq.head P in fG 1 n 1 1 n
[1..100]|>Seq.iter(tau>>printf "%d "); printfn "" </lang>
- Output:
1 2 2 3 2 4 2 4 3 4 2 6 2 4 4 5 2 6 2 6 4 4 2 8 3 4 4 6 2 8 2 6 4 4 4 9 2 4 4 8 2 8 2 6 6 4 2 10 3 6 4 6 2 8 4 8 4 4 2 12 2 4 6 7 4 8 2 6 4 8 2 12 2 4 6 6 4 8 2 10 5 4 2 12 4 4 4 8 2 12 4 6 4 4 4 12 2 6 6 9
Factor
<lang factor>USING: assocs formatting io kernel math math.primes.factors math.ranges sequences sequences.extras ;
ERROR: nonpositive n ;
- (tau) ( n -- count )
group-factors values [ 1 + ] map-product ; inline
- tau ( n -- count ) dup 0 > [ (tau) ] [ nonpositive ] if ;
"Number of divisors for integers 1-100:" print nl " n | tau(n)" print "-----+-----------------------------------------" print 1 100 10 <range> [
[ "%2d |" printf ] [ dup 10 + [a,b) [ tau "%4d" printf ] each nl ] bi
] each</lang>
- Output:
Number of divisors for integers 1-100: n | tau(n) -----+----------------------------------------- 1 | 1 2 2 3 2 4 2 4 3 4 11 | 2 6 2 4 4 5 2 6 2 6 21 | 4 4 2 8 3 4 4 6 2 8 31 | 2 6 4 4 4 9 2 4 4 8 41 | 2 8 2 6 6 4 2 10 3 6 51 | 4 6 2 8 4 8 4 4 2 12 61 | 2 4 6 7 4 8 2 6 4 8 71 | 2 12 2 4 6 6 4 8 2 10 81 | 5 4 2 12 4 4 4 8 2 12 91 | 4 6 4 4 4 12 2 6 6 9
Fermat
<lang>Func Tau(t) =
if t<3 then Return(t) else
numdiv:=2;
for q = 2 to t\2 do
if Divides(q, t) then numdiv:=numdiv+1 fi;
od;
Return(numdiv);
fi;
.;
for i = 1 to 100 do
!(Tau(i),' ');
od;</lang>
- Output:
1 2 2 3 2 4 2 4 3 4 2 6 2 4 4 5 2 6 2 6 4 4 2 8 3 4 4 6 2 8 2 6 4 4 4 9 2 4 4 8 2 8 2 6 6 4 2 10 3 6 4 6 2 8 4 8 4 4 2 12 2 4 6 7 4 8 2 6 4 8 2 12 2 4 6 6 4 8 2 10 5 4 2 12 4 4 4 8 2 12 4 6 4 4 4 12 2 6 6 9
Forth
<lang forth>: divisor_count ( n -- n )
1 >r
begin
dup 2 mod 0=
while
r> 1+ >r
2/
repeat
3
begin
2dup dup * >=
while
1 >r
begin
2dup mod 0=
while
r> 1+ >r
tuck / swap
repeat
2r> * >r
2 +
repeat
drop 1 > if r> 2* else r> then ;
- print_divisor_counts ( n -- )
." Count of divisors for the first " dup . ." positive integers:" cr 1+ 1 do i divisor_count 2 .r i 20 mod 0= if cr else space then loop ;
100 print_divisor_counts bye</lang>
- Output:
Count of divisors for the first 100 positive integers: 1 2 2 3 2 4 2 4 3 4 2 6 2 4 4 5 2 6 2 6 4 4 2 8 3 4 4 6 2 8 2 6 4 4 4 9 2 4 4 8 2 8 2 6 6 4 2 10 3 6 4 6 2 8 4 8 4 4 2 12 2 4 6 7 4 8 2 6 4 8 2 12 2 4 6 6 4 8 2 10 5 4 2 12 4 4 4 8 2 12 4 6 4 4 4 12 2 6 6 9
FreeBASIC
<lang freebasic>function numdiv( n as uinteger ) as uinteger
dim as uinteger c = 1
for i as uinteger = 1 to (n+1)\2
if n mod i = 0 then c += 1
next i
if n=1 then c-=1
return c
end function
for i as uinteger = 1 to 100
print numdiv(i), if i mod 10 = 0 then print
next i</lang>
- Output:
1 2 2 3 2 4 2 4 3 4 2 6 2 4 4 5 2 6 2 6 4 4 2 8 3 4 4 6 2 8 2 6 4 4 4 9 2 4 4 8 2 8 2 6 6 4 2 10 3 6 4 6 2 8 4 8 4 4 2 12 2 4 6 7 4 8 2 6 4 8 2 12 2 4 6 6 4 8 2 10 5 4 2 12 4 4 4 8 2 12 4 6 4 4 4 12 2 6 6 9
Go
<lang go>package main
import "fmt"
func countDivisors(n int) int {
count := 0
i := 1
k := 2
if n%2 == 0 {
k = 1
}
for i*i <= n {
if n%i == 0 {
count++
j := n / i
if j != i {
count++
}
}
i += k
}
return count
}
func main() {
fmt.Println("The tau functions for the first 100 positive integers are:")
for i := 1; i <= 100; i++ {
fmt.Printf("%2d ", countDivisors(i))
if i%20 == 0 {
fmt.Println()
}
}
}</lang>
- Output:
The tau functions for the first 100 positive integers are: 1 2 2 3 2 4 2 4 3 4 2 6 2 4 4 5 2 6 2 6 4 4 2 8 3 4 4 6 2 8 2 6 4 4 4 9 2 4 4 8 2 8 2 6 6 4 2 10 3 6 4 6 2 8 4 8 4 4 2 12 2 4 6 7 4 8 2 6 4 8 2 12 2 4 6 6 4 8 2 10 5 4 2 12 4 4 4 8 2 12 4 6 4 4 4 12 2 6 6 9
GW-BASIC
<lang gwbasic>10 FOR N = 1 TO 100 20 IF N < 3 THEN T=N: GOTO 70 30 T=2 40 FOR A = 2 TO INT( (N+1)/2 ) 50 IF N MOD A = 0 THEN T = T + 1 60 NEXT A 70 PRINT T; 80 IF N MOD 10 = 0 THEN PRINT 90 NEXT N</lang>
- Output:
1 2 2 3 2 4 2 4 3 4 2 6 2 4 4 5 2 6 2 6 4 4 2 8 3 4 4 6 2 8 2 6 4 4 4 9 2 4 4 8 2 8 2 6 6 4 2 10 3 6 4 6 2 8 4 8 4 4 2 12 2 4 6 7 4 8 2 6 4 8 2 12 2 4 6 6 4 8 2 10 5 4 2 12 4 4 4 8 2 12 4 6 4 4 4 12 2 6 6 9
Haskell
<lang Haskell>tau :: Integral a => a -> a tau n | n <= 0 = error "Not a positive integer" tau n = go 0 (1, 1)
where
yo i = (i, i * i)
go r (i, ii)
| n < ii = r
| n == ii = r + 1
| 0 == mod n i = go (r + 2) (yo $ i + 1)
| otherwise = go r (yo $ i + 1)
main = print $ map tau [1..100]</lang>
- Output:
[1,2,2,3,2,4,2,4,3,4,2,6,2,4,4,5,2,6,2,6,4,4,2,8,3,4,4,6,2,8,2,6,4,4,4,9,2,4,4,8,2,8,2,6,6,4,2,10,3,6,4,6,2,8,4,8,4,4,2,12,2,4,6,7,4,8,2,6,4,8,2,12,2,4,6,6,4,8,2,10,5,4,2,12,4,4,4,8,2,12,4,6,4,4,4,12,2,6,6,9]
Java
<lang java>public class TauFunction {
private static long divisorCount(long n) {
long total = 1;
// Deal with powers of 2 first
for (; (n & 1) == 0; n >>= 1) {
++total;
}
// Odd prime factors up to the square root
for (long p = 3; p * p <= n; p += 2) {
long count = 1;
for (; n % p == 0; n /= p) {
++count;
}
total *= count;
}
// If n > 1 then it's prime
if (n > 1) {
total *= 2;
}
return total;
}
public static void main(String[] args) {
final int limit = 100;
System.out.printf("Count of divisors for the first %d positive integers:\n", limit);
for (long n = 1; n <= limit; ++n) {
System.out.printf("%3d", divisorCount(n));
if (n % 20 == 0) {
System.out.println();
}
}
}
}</lang>
- Output:
Count of divisors for the first 100 positive integers: 1 2 2 3 2 4 2 4 3 4 2 6 2 4 4 5 2 6 2 6 4 4 2 8 3 4 4 6 2 8 2 6 4 4 4 9 2 4 4 8 2 8 2 6 6 4 2 10 3 6 4 6 2 8 4 8 4 4 2 12 2 4 6 7 4 8 2 6 4 8 2 12 2 4 6 6 4 8 2 10 5 4 2 12 4 4 4 8 2 12 4 6 4 4 4 12 2 6 6 9
jq
Works with gojq, the Go implementation of jq
Preliminaries See https://rosettacode.org/wiki/Sum_of_divisors#jq for the definition of `divisors` used here.<lang jq>def count(s): reduce s as $x (0; .+1);
- For pretty-printing
def nwise($n):
def n: if length <= $n then . else .[0:$n] , (.[$n:] | n) end; n;
def lpad($len): tostring | ($len - length) as $l | (" " * $l)[:$l] + .;</lang> The task <lang jq>[range(1;101) | count(divisors)] | nwise(10) | map(lpad(4)) | join("")</lang>
- Output:
1 2 2 3 2 4 2 4 3 4 2 6 2 4 4 5 2 6 2 6 4 4 2 8 3 4 4 6 2 8 2 6 4 4 4 9 2 4 4 8 2 8 2 6 6 4 2 10 3 6 4 6 2 8 4 8 4 4 2 12 2 4 6 7 4 8 2 6 4 8 2 12 2 4 6 6 4 8 2 10 5 4 2 12 4 4 4 8 2 12 4 6 4 4 4 12 2 6 6 9
Julia
Recycles code from http://www.rosettacode.org/wiki/Sequence:_smallest_number_greater_than_previous_term_with_exactly_n_divisors#Julia <lang julia>using Primes
function numfactors(n)
f = [one(n)]
for (p, e) in factor(n)
f = reduce(vcat, [f * p^j for j in 1:e], init = f)
end
length(f)
end
for i in 1:100
print(rpad(numfactors(i), 3), i % 25 == 0 ? " \n" : " ")
end
</lang>
- Output:
1 2 2 3 2 4 2 4 3 4 2 6 2 4 4 5 2 6 2 6 4 4 2 8 3 4 4 6 2 8 2 6 4 4 4 9 2 4 4 8 2 8 2 6 6 4 2 10 3 6 4 6 2 8 4 8 4 4 2 12 2 4 6 7 4 8 2 6 4 8 2 12 2 4 6 6 4 8 2 10 5 4 2 12 4 4 4 8 2 12 4 6 4 4 4 12 2 6 6 9
Lua
<lang lua>function divisorCount(n)
local total = 1
-- Deal with powers of 2 first
while (n & 1) == 0 do
total = total + 1
n = math.floor(n / 2)
end
-- Odd prime factors up tot eh square root
local p = 3
while p * p <= n do
local count = 1
while n % p == 0 do
count = count + 1
n = n / p
end
total = total * count
p = p + 2
end
-- If n > 1 then it's prime
if n > 1 then
total = total * 2
end
return total
end
limit = 100 print("Count of divisors for the first " .. limit .. " positive integers:") for n=1,limit do
io.write(string.format("%3d", divisorCount(n)))
if n % 20 == 0 then
print()
end
end</lang>
- Output:
Count of divisors for the first 100 positive integers: 1 2 2 3 2 4 2 4 3 4 2 6 2 4 4 5 2 6 2 6 4 4 2 8 3 4 4 6 2 8 2 6 4 4 4 9 2 4 4 8 2 8 2 6 6 4 2 10 3 6 4 6 2 8 4 8 4 4 2 12 2 4 6 7 4 8 2 6 4 8 2 12 2 4 6 6 4 8 2 10 5 4 2 12 4 4 4 8 2 12 4 6 4 4 4 12 2 6 6 9
Mathematica/Wolfram Language
<lang Mathematica>DivisorSum[#, 1 &] & /@ Range[100]</lang>
- Output:
{1,2,2,3,2,4,2,4,3,4,2,6,2,4,4,5,2,6,2,6,4,4,2,8,3,4,4,6,2,8,2,6,4,4,4,9,2,4,4,8,2,8,2,6,6,4,2,10,3,6,4,6,2,8,4,8,4,4,2,12,2,4,6,7,4,8,2,6,4,8,2,12,2,4,6,6,4,8,2,10,5,4,2,12,4,4,4,8,2,12,4,6,4,4,4,12,2,6,6,9}
Nim
<lang Nim>import math, strutils
func divcount(n: Natural): Natural =
for i in 1..sqrt(n.toFloat).int:
if n mod i == 0:
inc result
if n div i != i: inc result
echo "Count of divisors for the first 100 positive integers:" for i in 1..100:
stdout.write ($divcount(i)).align(3) if i mod 20 == 0: echo()</lang>
- Output:
Count of divisors for the first 100 positive integers: 1 2 2 3 2 4 2 4 3 4 2 6 2 4 4 5 2 6 2 6 4 4 2 8 3 4 4 6 2 8 2 6 4 4 4 9 2 4 4 8 2 8 2 6 6 4 2 10 3 6 4 6 2 8 4 8 4 4 2 12 2 4 6 7 4 8 2 6 4 8 2 12 2 4 6 6 4 8 2 10 5 4 2 12 4 4 4 8 2 12 4 6 4 4 4 12 2 6 6 9
PARI/GP
<lang parigp>vector(100,X,numdiv(X))</lang>
- Output:
[1, 2, 2, 3, 2, 4, 2, 4, 3, 4, 2, 6, 2, 4, 4, 5, 2, 6, 2, 6, 4, 4, 2, 8, 3, 4, 4, 6, 2, 8, 2, 6, 4, 4, 4, 9, 2, 4, 4, 8, 2, 8, 2, 6, 6, 4, 2, 10, 3, 6, 4, 6, 2, 8, 4, 8, 4, 4, 2, 12, 2, 4, 6, 7, 4, 8, 2, 6, 4, 8, 2, 12, 2, 4, 6, 6, 4, 8, 2, 10, 5, 4, 2, 12, 4, 4, 4, 8, 2, 12, 4, 6, 4, 4, 4, 12, 2, 6, 6, 9]
Pascal
<lang pascal>program tauFunction(output);
type { name starts with `integer…` to facilitate sorting in documentation } integerPositive = 1..maxInt value 1; { the `value …` will initialize all variables to this value }
{ returns Boolean value of the expression divisor ∣ dividend ----------- } function divides( protected divisor: integerPositive; protected dividend: integer ): Boolean; begin { in Pascal, function result variable has the same name as function } divides := dividend mod divisor = 0 end;
{ returns τ(i) --------------------------------------------------------- } function tau(protected i: integerPositive): integerPositive; var count, potentialDivisor: integerPositive; begin { count is initialized to 1 and every number is divisible by one } for potentialDivisor := 2 to i do begin count := count + ord(divides(potentialDivisor, i)) end;
{ in Pascal, there must be exactly one assignment to result variable } tau := count end;
{ === MAIN ============================================================= } var i: integerPositive; f: string(6); begin for i := 1 to 100 do begin writeStr(f, 'τ(', i:1); writeLn(f:8, ') = ', tau(i):5) end end.</lang>
Free Pascal
and on TIO.RUN. Only test 0..99 for a nicer table.
<lang pascal>program Tau_function; {$IFDEF Windows} {$APPTYPE CONSOLE} {$ENDIF}
function CountDivisors(n: NativeUint): integer;
var
q, p, cnt, divcnt: NativeUint;
begin
divCnt := 1;
if n > 1 then
begin
cnt := 1;
while not (Odd(n)) do
begin
n := n shr 1;
divCnt := divCnt+cnt;
end;
p := 3;
while p * p <= n do
begin
cnt := divCnt;
q := n div p;
while q * p = n do
begin
n := q;
q := n div p;
divCnt := divCnt+cnt;
end;
Inc(p, 2);
end;
if n <> 1 then
divCnt := divCnt+divCnt;
end;
CountDivisors := divCnt;
end;
const
UPPERLIMIT = 99; colWidth = trunc(ln(UPPERLIMIT)/ln(10))+1;
var
i: NativeUint;
begin
writeln('The tau functions for the first ',UPPERLIMIT,' positive integers are:');
Write(: colWidth+1);
for i := 0 to 9 do
Write(i: colWidth, ' ');
for i := 0 to UPPERLIMIT do
begin
if i mod 10 = 0 then
begin
writeln;
Write(i div 10: colWidth, '|');
end;
Write(CountDivisors(i): colWidth, ' ');
end;
writeln;
{$Ifdef Windows}readln;{$ENDIF}
end.</lang>
- TIO.RUN:
The tau functions for the first 99 positive integers are:
0 1 2 3 4 5 6 7 8 9
0| 1 1 2 2 3 2 4 2 4 3
1| 4 2 6 2 4 4 5 2 6 2
2| 6 4 4 2 8 3 4 4 6 2
3| 8 2 6 4 4 4 9 2 4 4
4| 8 2 8 2 6 6 4 2 10 3
5| 6 4 6 2 8 4 8 4 4 2
6|12 2 4 6 7 4 8 2 6 4
7| 8 2 12 2 4 6 6 4 8 2
8|10 5 4 2 12 4 4 4 8 2
9|12 4 6 4 4 4 12 2 6 6
Perl
<lang perl>use strict; use warnings; use feature 'say'; use ntheory 'divisors';
my @x; push @x, scalar divisors($_) for 1..100;
say "Tau function - first 100:\n" .
((sprintf "@{['%4d' x 100]}", @x[0..100-1]) =~ s/(.{80})/$1\n/gr);</lang>
- Output:
1 2 2 3 2 4 2 4 3 4 2 6 2 4 4 5 2 6 2 6 4 4 2 8 3 4 4 6 2 8 2 6 4 4 4 9 2 4 4 8 2 8 2 6 6 4 2 10 3 6 4 6 2 8 4 8 4 4 2 12 2 4 6 7 4 8 2 6 4 8 2 12 2 4 6 6 4 8 2 10 5 4 2 12 4 4 4 8 2 12 4 6 4 4 4 12 2 6 6 9
Phix
imperative
for i=1 to 100 do printf(1,"%3d",{length(factors(i,1))}) if remainder(i,20)=0 then puts(1,"\n") end if end for
- Output:
1 2 2 3 2 4 2 4 3 4 2 6 2 4 4 5 2 6 2 6 4 4 2 8 3 4 4 6 2 8 2 6 4 4 4 9 2 4 4 8 2 8 2 6 6 4 2 10 3 6 4 6 2 8 4 8 4 4 2 12 2 4 6 7 4 8 2 6 4 8 2 12 2 4 6 6 4 8 2 10 5 4 2 12 4 4 4 8 2 12 4 6 4 4 4 12 2 6 6 9
functional
same output
sequence r = apply(apply(true,factors,{tagset(100),{1}}),length) puts(1,join_by(apply(true,sprintf,{{"%3d"},r}),1,20,""))
PureBasic
<lang PureBasic>If OpenConsole()
For i=1 To 100
If i<3 : Print(RSet(Str(i),4)) : Continue :EndIf
c=2
For j=2 To i/2+1 : c+Bool(i%j=0) : Next
Print(RSet(Str(c),4))
If i%10=0 : PrintN("") : EndIf
Next
Input()
EndIf End</lang>
- Output:
1 2 2 3 2 4 2 4 3 4 2 6 2 4 4 5 2 6 2 6 4 4 2 8 3 4 4 6 2 8 2 6 4 4 4 9 2 4 4 8 2 8 2 6 6 4 2 10 3 6 4 6 2 8 4 8 4 4 2 12 2 4 6 7 4 8 2 6 4 8 2 12 2 4 6 6 4 8 2 10 5 4 2 12 4 4 4 8 2 12 4 6 4 4 4 12 2 6 6 9
Python
Using prime factorization
<lang Python>def factorize(n):
assert(isinstance(n, int))
if n < 0:
n = -n
if n < 2:
return
k = 0
while 0 == n%2:
k += 1
n //= 2
if 0 < k:
yield (2,k)
p = 3
while p*p <= n:
k = 0
while 0 == n%p:
k += 1
n //= p
if 0 < k:
yield (p,k)
p += 2
if 1 < n:
yield (n,1)
def tau(n):
assert(n != 0)
ans = 1
for (p,k) in factorize(n):
ans *= 1 + k
return ans
if __name__ == "__main__":
print([tau(n) for n in range(1,101)])</lang>
Finding divisors efficiently
<lang Python>def tau(n):
assert(isinstance(n, int) and 0 < n)
ans, i, j = 0, 1, 1
while i*i <= n:
if 0 == n%i:
ans += 1
j = n//i
if j != i:
ans += 1
i += 1
return ans
if __name__ == "__main__":
print([tau(n) for n in range(1,101)])</lang>
- Output:
[1, 2, 2, 3, 2, 4, 2, 4, 3, 4, 2, 6, 2, 4, 4, 5, 2, 6, 2, 6, 4, 4, 2, 8, 3, 4, 4, 6, 2, 8, 2, 6, 4, 4, 4, 9, 2, 4, 4, 8, 2, 8, 2, 6, 6, 4, 2, 10, 3, 6, 4, 6, 2, 8, 4, 8, 4, 4, 2, 12, 2, 4, 6, 7, 4, 8, 2, 6, 4, 8, 2, 12, 2, 4, 6, 6, 4, 8, 2, 10, 5, 4, 2, 12, 4, 4, 4, 8, 2, 12, 4, 6, 4, 4, 4, 12, 2, 6, 6, 9]
Choosing the right abstraction
Yet another exercise in defining a divisors function.
<lang python>The number of divisors of n
from itertools import count, islice from math import floor, sqrt
- oeisA000005 :: [Int]
def oeisA000005():
tau(n) (also called d(n) or sigma_0(n)),
the number of divisors of n.
return map(tau, count(1))
- tau :: Int -> Int
def tau(n):
The number of divisors of n. return len(divisors(n))
- ------------------------- TEST -------------------------
- main :: IO ()
def main():
The first 100 terms of OEIS A000005.
(Shown in rows of 10)
terms = take(100)(
oeisA000005()
)
columnWidth = 1 + len(str(max(terms)))
print(
'\n'.join(
.join(
str(term).rjust(columnWidth)
for term in row
)
for row in chunksOf(10)(terms)
)
)
- ----------------------- GENERIC ------------------------
- chunksOf :: Int -> [a] -> a
def chunksOf(n):
A series of lists of length n, subdividing the
contents of xs. Where the length of xs is not evenly
divible, the final list will be shorter than n.
def go(xs):
return [
xs[i:n + i] for i in range(0, len(xs), n)
] if 0 < n else None
return go
- divisors :: Int -> [Int]
def divisors(n):
List of all divisors of n including n itself.
root = floor(sqrt(n))
lows = [x for x in range(1, 1 + root) if 0 == n % x]
return lows + [n // x for x in reversed(lows)][
(1 if n == (root * root) else 0):
]
- take :: Int -> [a] -> [a]
- take :: Int -> String -> String
def take(n):
The prefix of xs of length n,
or xs itself if n > length xs.
def go(xs):
return (
xs[0:n]
if isinstance(xs, (list, tuple))
else list(islice(xs, n))
)
return go
- MAIN ---
if __name__ == '__main__':
main()</lang>
- Output:
1 2 2 3 2 4 2 4 3 4 2 6 2 4 4 5 2 6 2 6 4 4 2 8 3 4 4 6 2 8 2 6 4 4 4 9 2 4 4 8 2 8 2 6 6 4 2 10 3 6 4 6 2 8 4 8 4 4 2 12 2 4 6 7 4 8 2 6 4 8 2 12 2 4 6 6 4 8 2 10 5 4 2 12 4 4 4 8 2 12 4 6 4 4 4 12 2 6 6 9
Quackery
factors is defined at Factors of an integer#Quackery.
<lang Quackery> [ factors size ] is tau ( n --> n )
[] [] 100 times [ i^ 1+ tau join ] witheach [ number$ nested join ] 70 wrap$
</lang>
- Output:
1 2 2 3 2 4 2 4 3 4 2 6 2 4 4 5 2 6 2 6 4 4 2 8 3 4 4 6 2 8 2 6 4 4 4 9 2 4 4 8 2 8 2 6 6 4 2 10 3 6 4 6 2 8 4 8 4 4 2 12 2 4 6 7 4 8 2 6 4 8 2 12 2 4 6 6 4 8 2 10 5 4 2 12 4 4 4 8 2 12 4 6 4 4 4 12 2 6 6 9
R
This only takes one line. <lang rsplus>lengths(sapply(1:100, function(n) c(Filter(function(x) n %% x == 0, seq_len(n %/% 2)), n)))</lang>
Raku
Yet more tasks that are tiny variations of each other. Tau function, Tau number, Sum of divisors and Product of divisors all use code with minimal changes. What the heck, post 'em all.
<lang perl6>use Prime::Factor:ver<0.3.0+>; use Lingua::EN::Numbers;
say "\nTau function - first 100:\n", # ID (1..*).map({ +.&divisors })[^100]\ # the task .batch(20)».fmt("%3d").join("\n"); # display formatting
say "\nTau numbers - first 100:\n", # ID (1..*).grep({ $_ %% +.&divisors })[^100]\ # the task .batch(10)».&comma».fmt("%5s").join("\n"); # display formatting
say "\nDivisor sums - first 100:\n", # ID (1..*).map({ [+] .&divisors })[^100]\ # the task .batch(20)».fmt("%4d").join("\n"); # display formatting
say "\nDivisor products - first 100:\n", # ID (1..*).map({ [×] .&divisors })[^100]\ # the task .batch(5)».&comma».fmt("%16s").join("\n"); # display formatting</lang>
- Output:
Tau function - first 100:
1 2 2 3 2 4 2 4 3 4 2 6 2 4 4 5 2 6 2 6
4 4 2 8 3 4 4 6 2 8 2 6 4 4 4 9 2 4 4 8
2 8 2 6 6 4 2 10 3 6 4 6 2 8 4 8 4 4 2 12
2 4 6 7 4 8 2 6 4 8 2 12 2 4 6 6 4 8 2 10
5 4 2 12 4 4 4 8 2 12 4 6 4 4 4 12 2 6 6 9
Tau numbers - first 100:
1 2 8 9 12 18 24 36 40 56
60 72 80 84 88 96 104 108 128 132
136 152 156 180 184 204 225 228 232 240
248 252 276 288 296 328 344 348 360 372
376 384 396 424 441 444 448 450 468 472
480 488 492 504 516 536 560 564 568 584
600 612 625 632 636 640 664 672 684 708
712 720 732 776 792 804 808 824 828 852
856 864 872 876 880 882 896 904 936 948
972 996 1,016 1,040 1,044 1,048 1,056 1,068 1,089 1,096
Divisor sums - first 100:
1 3 4 7 6 12 8 15 13 18 12 28 14 24 24 31 18 39 20 42
32 36 24 60 31 42 40 56 30 72 32 63 48 54 48 91 38 60 56 90
42 96 44 84 78 72 48 124 57 93 72 98 54 120 72 120 80 90 60 168
62 96 104 127 84 144 68 126 96 144 72 195 74 114 124 140 96 168 80 186
121 126 84 224 108 132 120 180 90 234 112 168 128 144 120 252 98 171 156 217
Divisor products - first 100:
1 2 3 8 5
36 7 64 27 100
11 1,728 13 196 225
1,024 17 5,832 19 8,000
441 484 23 331,776 125
676 729 21,952 29 810,000
31 32,768 1,089 1,156 1,225
10,077,696 37 1,444 1,521 2,560,000
41 3,111,696 43 85,184 91,125
2,116 47 254,803,968 343 125,000
2,601 140,608 53 8,503,056 3,025
9,834,496 3,249 3,364 59 46,656,000,000
61 3,844 250,047 2,097,152 4,225
18,974,736 67 314,432 4,761 24,010,000
71 139,314,069,504 73 5,476 421,875
438,976 5,929 37,015,056 79 3,276,800,000
59,049 6,724 83 351,298,031,616 7,225
7,396 7,569 59,969,536 89 531,441,000,000
8,281 778,688 8,649 8,836 9,025
782,757,789,696 97 941,192 970,299 1,000,000,000
REXX
<lang rexx>/*REXX program counts the number of divisors (tau, or sigma_0) up to and including N.*/ parse arg LO HI cols . /*obtain optional argument from the CL.*/ if LO== | LO=="," then LO= 1 /*Not specified? Then use the default.*/ if HI== | HI=="," then HI= LO + 100 - 1 /*Not specified? Then use the default.*/ if cols== | cols=="," then cols= 20 /* " " " " " " */ w= 2 + (HI>45359) /*W: used to align the output columns.*/ say 'The number of divisors (tau) for integers up to ' n " (inclusive):"; say say '─index─' center(" tau (number of divisors) ", cols * (w+1) + 1, '─') $=; c= 0 /*$: the output list, shown ROW/line.*/
do j=LO to HI; c= c + 1 /*list # proper divisors (tau) 1 ──► N */
$= $ right( tau(j), w) /*add a tau number to the output list. */
if c//cols \== 0 then iterate /*Not a multiple of ROW? Don't display.*/
idx= j - cols + 1 /*calculate index value (for this row).*/
say center(idx, 7) $; $= /*display partial list to the terminal.*/
end /*j*/
if $\== then say center(idx+cols, 7) $ /*there any residuals left to display ?*/ exit 0 /*stick a fork in it, we're all done. */ /*──────────────────────────────────────────────────────────────────────────────────────*/ tau: procedure; parse arg x 1 y /*X and $ are both set from the arg.*/
if x<6 then return 2 + (x==4) - (x==1) /*some low #s should be handled special*/
odd= x // 2 /*check if X is odd (remainder of 1).*/
if odd then #= 2 /*Odd? Assume divisor count of 2. */
else do; #= 4; y= x % 2; end /*Even? " " " " 4. */
/* [↑] start with known number of divs*/
do j=3 for x%2-3 by 1+odd while j<y /*for odd number, skip even numbers. */
if x//j==0 then do /*if no remainder, then found a divisor*/
#= # + 2; y= x % j /*bump # of divisors; calculate limit.*/
if j>=y then do; #= # - 1; leave; end /*reached limit?*/
end /* ___ */
else if j*j>x then leave /*only divide up to √ x */
end /*j*/; return # /* [↑] this form of DO loop is faster.*/</lang>
- output when using the default input:
The number of divisors (tau) for integers up to 100 (inclusive): ─index─ ──────────────────────────── tau (number of divisors) ──────────────────────────── 1 1 2 2 3 2 4 2 4 3 4 2 6 2 4 4 5 2 6 2 6 21 4 4 2 8 3 4 4 6 2 8 2 6 4 4 4 9 2 4 4 8 41 2 8 2 6 6 4 2 10 3 6 4 6 2 8 4 8 4 4 2 12 61 2 4 6 7 4 8 2 6 4 8 2 12 2 4 6 6 4 8 2 10 81 5 4 2 12 4 4 4 8 2 12 4 6 4 4 4 12 2 6 6 9
Ring
<lang ring> see "The tau functions for the first 100 positive integers are:" + nl
n = 0 num = 0 limit = 100 while num < limit
n = n + 1
tau = 0
for m = 1 to n
if n%m = 0
tau = tau + 1
ok
next
num = num + 1
if num%10 = 1
see nl
ok
tau = string(tau)
if len(tau) = 1
tau = " " + tau
ok
see "" + tau + " "
end </lang> Output:
The tau functions for the first 100 positive integers are: 1 2 2 3 2 4 2 4 3 4 2 6 2 4 4 5 2 6 2 6 4 4 2 8 3 4 4 6 2 8 2 6 4 4 4 9 2 4 4 8 2 8 2 6 6 4 2 10 3 6 4 6 2 8 4 8 4 4 2 12 2 4 6 7 4 8 2 6 4 8 2 12 2 4 6 6 4 8 2 10 5 4 2 12 4 4 4 8 2 12 4 6 4 4 4 12 2 6 6 9
Ruby
<lang ruby>require 'prime'
def tau(n) = n.prime_division.inject(1){|res, (d, exp)| res *= exp + 1}
(1..100).map{|n| tau(n).to_s.rjust(3) }.each_slice(20){|ar| puts ar.join} </lang>
- Output:
1 2 2 3 2 4 2 4 3 4 2 6 2 4 4 5 2 6 2 6 4 4 2 8 3 4 4 6 2 8 2 6 4 4 4 9 2 4 4 8 2 8 2 6 6 4 2 10 3 6 4 6 2 8 4 8 4 4 2 12 2 4 6 7 4 8 2 6 4 8 2 12 2 4 6 6 4 8 2 10 5 4 2 12 4 4 4 8 2 12 4 6 4 4 4 12 2 6 6 9
Rust
<lang rust>// returns the highest power of i that is a factor of n, // and n divided by that power of i fn factor_exponent(n: i32, i: i32) -> (i32, i32) { if n % i == 0 { let (a, b) = factor_exponent(n / i, i); (a + 1, b) } else { (0, n) } }
fn tau(n: i32) -> i32 { for i in 2..(n+1) { if n % i == 0 { let (count, next) = factor_exponent(n, i); return (count + 1) * tau(next); } } return 1; }
fn main() { for i in 1..101 { print!("{} ", tau(i)); } }</lang> Output:
1 2 2 3 2 4 2 4 3 4 2 6 2 4 4 5 2 6 2 6 4 4 2 8 3 4 4 6 2 8 2 6 4 4 4 9 2 4 4 8 2 8 2 6 6 4 2 10 3 6 4 6 2 8 4 8 4 4 2 12 2 4 6 7 4 8 2 6 4 8 2 12 2 4 6 6 4 8 2 10 5 4 2 12 4 4 4 8 2 12 4 6 4 4 4 12 2 6 6 9
Sidef
Built-in: <lang ruby>say { .sigma0 }.map(1..100).join(' ')</lang>
- Output:
1 2 2 3 2 4 2 4 3 4 2 6 2 4 4 5 2 6 2 6 4 4 2 8 3 4 4 6 2 8 2 6 4 4 4 9 2 4 4 8 2 8 2 6 6 4 2 10 3 6 4 6 2 8 4 8 4 4 2 12 2 4 6 7 4 8 2 6 4 8 2 12 2 4 6 6 4 8 2 10 5 4 2 12 4 4 4 8 2 12 4 6 4 4 4 12 2 6 6 9
Swift
<lang swift>import Foundation
// See https://en.wikipedia.org/wiki/Divisor_function func divisorCount(number: Int) -> Int {
var n = number
var total = 1
// Deal with powers of 2 first
while (n & 1) == 0 {
total += 1
n >>= 1
}
// Odd prime factors up to the square root
var p = 3
while p * p <= n {
var count = 1
while n % p == 0 {
count += 1
n /= p
}
total *= count
p += 2
}
// If n > 1 then it's prime
if n > 1 {
total *= 2
}
return total
}
let limit = 100 print("Count of divisors for the first \(limit) positive integers:") for n in 1...limit {
print(String(format: "%3d", divisorCount(number: n)), terminator: "")
if n % 20 == 0 {
print()
}
}</lang>
- Output:
Count of divisors for the first 100 positive integers: 1 2 2 3 2 4 2 4 3 4 2 6 2 4 4 5 2 6 2 6 4 4 2 8 3 4 4 6 2 8 2 6 4 4 4 9 2 4 4 8 2 8 2 6 6 4 2 10 3 6 4 6 2 8 4 8 4 4 2 12 2 4 6 7 4 8 2 6 4 8 2 12 2 4 6 6 4 8 2 10 5 4 2 12 4 4 4 8 2 12 4 6 4 4 4 12 2 6 6 9
Tiny BASIC
<lang tinybasic> LET N = 0
10 LET N = N + 1
IF N < 3 THEN GOTO 100
LET T = 2
LET A = 1
20 LET A = A + 1
IF (N/A)*A = N THEN LET T = T + 1
IF A<(N+1)/2 THEN GOTO 20
30 PRINT "Tau(",N,") = ",T
IF N<100 THEN GOTO 10
END
100 LET T = N
GOTO 30</lang>
Wren
<lang ecmascript>import "/math" for Int import "/fmt" for Fmt
System.print("The tau functions for the first 100 positive integers are:") for (i in 1..100) {
Fmt.write("$2d ", Int.divisors(i).count)
if (i % 20 == 0) System.print()
}</lang>
- Output:
The tau functions for the first 100 positive integers are: 1 2 2 3 2 4 2 4 3 4 2 6 2 4 4 5 2 6 2 6 4 4 2 8 3 4 4 6 2 8 2 6 4 4 4 9 2 4 4 8 2 8 2 6 6 4 2 10 3 6 4 6 2 8 4 8 4 4 2 12 2 4 6 7 4 8 2 6 4 8 2 12 2 4 6 6 4 8 2 10 5 4 2 12 4 4 4 8 2 12 4 6 4 4 4 12 2 6 6 9
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