Sum digits of an integer: Difference between revisions
(→{{header|Kotlin}}: Improved version) |
(→{{header|Ruby}}: Code greatly simplified with v2.4 features) |
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>> sumDigits(0xf0e, 16) |
>> sumDigits(0xf0e, 16) |
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=> 29 |
=> 29 |
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== Since v2.4 == |
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def sumDigits(num, base = 10) |
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num.digits(base).sum |
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end |
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</lang> |
</lang> |
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Revision as of 23:54, 24 May 2017
You are encouraged to solve this task according to the task description, using any language you may know.
- Task
Take a Natural Number in a given base and return the sum of its digits:
- 110 sums to 1
- 123410 sums to 10
- fe16 sums to 29
- f0e16 sums to 29
360 Assembly
The program uses two ASSIST macro (XDECO,XPRNT) to keep the code as short as possible. <lang 360asm>* Sum digits of an integer 08/07/2016 SUMDIGIN CSECT
USING SUMDIGIN,R13 base register B 72(R15) skip savearea DC 17F'0' savearea STM R14,R12,12(R13) prolog ST R13,4(R15) " <- ST R15,8(R13) " -> LR R13,R15 " addressability LA R11,NUMBERS @numbers LA R8,1 k=1
LOOPK CH R8,=H'4' do k=1 to hbound(numbers)
BH ELOOPK " SR R10,R10 sum=0 LA R7,1 j=1
LOOPJ CH R7,=H'8' do j=1 to length(number)
BH ELOOPJ " LR R4,R11 @number BCTR R4,0 -1 AR R4,R7 +j MVC D,0(R4) d=substr(number,j,1) SR R9,R9 ii=0 SR R6,R6 i=0
LOOPI CH R6,=H'15' do i=0 to 15
BH ELOOPI " LA R4,DIGITS @digits AR R4,R6 i MVC C,0(R4) c=substr(digits,i+1,1) CLC D,C if d=c BNE NOTEQ then LR R9,R6 ii=i B ELOOPI leave i
NOTEQ LA R6,1(R6) i=i+1
B LOOPI end do i
ELOOPI AR R10,R9 sum=sum+ii
LA R7,1(R7) j=j+1 B LOOPJ end do j
ELOOPJ MVC PG(8),0(R11) number
XDECO R10,XDEC edit sum MVC PG+8(8),XDEC+4 output sum XPRNT PG,L'PG print buffer LA R11,8(R11) @number=@number+8 LA R8,1(R8) k=k+1 B LOOPK end do k
ELOOPK L R13,4(0,R13) epilog
LM R14,R12,12(R13) " restore XR R15,R15 " rc=0 BR R14 exit
DIGITS DC CL16'0123456789ABCDEF' NUMBERS DC CL8'1',CL8'1234',CL8'FE',CL8'F0E' C DS CL1 D DS CL1 PG DC CL16' ' buffer XDEC DS CL12 temp
YREGS END SUMDIGIN</lang>
- Output:
1 1 1234 10 FE 29 F0E 29
Ada
Numeric constants in Ada are either decimal or written as B#Digits#. Here B is the base, written as a decimal number, and Digits is a base-B number. E.g., 30, 10#30# 2#11110#, and 16#1E# are the same number -- either written in decimal, binary or hexadecimal notation.
<lang Ada>with Ada.Integer_Text_IO;
procedure Sum_Digits is
-- sums the digits of an integer (in whatever base) -- outputs the sum (in base 10)
function Sum_Of_Digits(N: Natural; Base: Natural := 10) return Natural is Sum: Natural := 0; Val: Natural := N; begin while Val > 0 loop Sum := Sum + (Val mod Base); Val := Val / Base; end loop; return Sum; end Sum_Of_Digits;
use Ada.Integer_Text_IO;
begin -- main procedure Sum_Digits
Put(Sum_OF_Digits(1)); -- 1 Put(Sum_OF_Digits(12345)); -- 15 Put(Sum_OF_Digits(123045)); -- 15 Put(Sum_OF_Digits(123045, 50)); -- 104 Put(Sum_OF_Digits(16#fe#, 10)); -- 11 Put(Sum_OF_Digits(16#fe#, 16)); -- 29 Put(Sum_OF_Digits(16#f0e#, 16)); -- 29
end Sum_Digits;</lang>
- Output:
1 15 15 104 11 29 29
ALGOL 68
<lang algol68>
- operator to return the sum of the digits of an integer value in the #
- specified base #
PRIO SUMDIGITS = 1; OP SUMDIGITS = ( INT value, INT base )INT:
IF base < 2 THEN # invalid base # print( ( "Base for digit sum must be at least 2", newline ) ); stop ELSE # the base is OK # INT result := 0; INT rest := ABS value;
WHILE rest /= 0 DO result PLUSAB ( rest MOD base ); rest OVERAB base OD;
result FI; # SUMDIGITS #
- additional operator so we can sum the digits of values expressed in #
- other than base 10, e.g. 16ra is a hex lteral with value 10 #
- (Algol 68 allows bases 2, 4, 8 and 16 for non-base 10 literals) #
- however as such literals are BITS values, not INTs, we need this #
- second operator #
OP SUMDIGITS = ( BITS value, INT base )INT: ABS value SUMDIGITS base;
main:(
# test the SUMDIGITS operator #
print( ( "value\base base digit-sum", newline ) ); print( ( " 1\10 10 ", whole( 1 SUMDIGITS 10, -9 ), newline ) ); print( ( " 1234\10 10 ", whole( 1234 SUMDIGITS 10, -9 ), newline ) ); print( ( " fe\16 16 ", whole( 16rfe SUMDIGITS 16, -9 ), newline ) ); print( ( " f0e\16 16 ", whole( 16rf0e SUMDIGITS 16, -9 ), newline ) );
# of course, we don't have to express the number in the base we sum # # the digits in... # print( ( " 73\10 71 ", whole( 73 SUMDIGITS 71, -9 ), newline ) )
) </lang>
- Output:
value\base base digit-sum 1\10 10 1 1234\10 10 10 fe\16 16 29 f0e\16 16 29 73\10 71 3
AppleScript
<lang AppleScript>-- digitsSummed :: (Int | String) -> Int on digitsSummed(n)
-- digitAdded :: Int -> String -> Int script digitAdded -- Numeric values of known glyphs: 0-9 A-Z a-z -- digitValue :: String -> Int on digitValue(s) set i to id of s if i > 47 and i < 123 then -- 0-z if i < 58 then -- 0-9 i - 48 else if i > 96 then -- a-z i - 87 else if i > 64 and i < 91 then -- A-Z i - 55 else -- unknown glyph 0 end if else -- unknown glyph 0 end if end digitValue on lambda(accumulator, strDigit) accumulator + digitValue(strDigit) end lambda end script foldl(digitAdded, 0, splitOn("", n as string))
end digitsSummed
-- TEST
-- showDigitSum :: Int -> String on showDigitSum(n)
(n as string) & " -> " & digitsSummed(n)
end showDigitSum
on run
intercalate(linefeed, ¬ map(showDigitSum, [1, 12345, "254", "fe", "f0e", "999ABCXYZ"]))
end run
-- GENERIC FUNCTIONS
-- foldl :: (a -> b -> a) -> a -> [b] -> a on foldl(f, startValue, xs)
tell mReturn(f) set v to startValue set lng to length of xs repeat with i from 1 to lng set v to lambda(v, item i of xs, i, xs) end repeat return v end tell
end foldl
-- map :: (a -> b) -> [a] -> [b] on map(f, xs)
tell mReturn(f) set lng to length of xs set lst to {} repeat with i from 1 to lng set end of lst to lambda(item i of xs, i, xs) end repeat return lst end tell
end map
-- Lift 2nd class handler function into 1st class script wrapper -- mReturn :: Handler -> Script on mReturn(f)
if class of f is script then f else script property lambda : f end script end if
end mReturn
-- splitOn :: Text -> Text -> [Text] on splitOn(strDelim, strMain)
set {dlm, my text item delimiters} to {my text item delimiters, strDelim} set xs to text items of strMain set my text item delimiters to dlm return xs
end splitOn
-- intercalate :: Text -> [Text] -> Text on intercalate(strText, lstText)
set {dlm, my text item delimiters} to {my text item delimiters, strText} set strJoined to lstText as text set my text item delimiters to dlm return strJoined
end intercalate </lang>
- Output:
1 -> 1 12345 -> 15 254 -> 11 fe -> 29 f0e -> 29 999ABCXYZ -> 162
ATS
<lang ATS> (* ****** ****** *) // // How to compile: // patscc -DATS_MEMALLOC_LIBC -o SumDigits SumDigits.dats // (* ****** ****** *) //
- include
"share/atspre_staload.hats" // (* ****** ****** *)
extern fun{a:t@ype} SumDigits(n: a, base: int): a
implement {a}(*tmp*) SumDigits(n, base) = let // val base = gnumber_int(base) // fun loop (n: a, res: a): a =
if gisgtz_val<a> (n) then loop (gdiv_val<a>(n, base), gadd_val<a>(res, gmod_val<a>(n, base))) else res
// in
loop (n, gnumber_int(0))
end // end of [SumDigits]
(* ****** ****** *)
val SumDigits_int = SumDigits<int>
(* ****** ****** *)
implement main0 () = { // val n = 1 val () = println! ("SumDigits(1, 10) = ", SumDigits_int(n, 10)) val n = 12345 val () = println! ("SumDigits(12345, 10) = ", SumDigits_int(n, 10)) val n = 123045 val () = println! ("SumDigits(123045, 10) = ", SumDigits_int(n, 10)) val n = 0xfe val () = println! ("SumDigits(0xfe, 16) = ", SumDigits_int(n, 16)) val n = 0xf0e val () = println! ("SumDigits(0xf0e, 16) = ", SumDigits_int(n, 16)) // } (* end of [main0] *) </lang>
- Output:
SumDigits(1, 10) = 1 SumDigits(12345, 10) = 15 SumDigits(123045, 10) = 15 SumDigits(0xfe, 16) = 29 SumDigits(0xf0e, 16) = 29
AutoHotkey
Translated from the C version.
<lang AutoHotkey>MsgBox % sprintf("%d %d %d %d %d`n" ,SumDigits(1, 10) ,SumDigits(12345, 10) ,SumDigits(123045, 10) ,SumDigits(0xfe, 16) ,SumDigits(0xf0e, 16) )
SumDigits(n,base) { sum := 0 while (n) { sum += Mod(n,base) n /= base } return sum }
sprintf(s,fmt*) { for each, f in fmt StringReplace,s,s,`%d, % f return s }</lang>
- Output:
1 15 15 29 29
AWK
MAWK only support base 10 numeric constants, so a conversion function is necessary.
Will sum digits in numbers from base 2 to base 16.
The output is in decimal. Output in other bases would require a function to do the conversion because MAWK's printf() does not support bases other than 10.
Other versions of AWK may not have these limitations.
<lang AWK>#!/usr/bin/awk -f
BEGIN {
print sumDigits("1") print sumDigits("12") print sumDigits("fe") print sumDigits("f0e")
}
function sumDigits(num, nDigs, digits, sum, d, dig, val, sum) {
nDigs = split(num, digits, "") sum = 0 for (d = 1; d <= nDigs; d++) { dig = digits[d] val = digToDec(dig) sum += val } return sum
}
function digToDec(dig) {
return index("0123456789abcdef", tolower(dig)) - 1
} </lang>
- Output:
1 3 29 29
BASIC
Note that in order for this to work with the Windows versions of PowerBASIC,
the test code needs to be with FUNCTION PBMAIN
.
<lang qbasic>FUNCTION sumDigits(num AS STRING, bas AS LONG) AS LONG
'can handle up to base 36 DIM outp AS LONG DIM validNums AS STRING, tmp AS LONG, x AS LONG, lennum AS LONG, L0 AS LONG 'ensure num contains only valid characters validNums = LEFT$("0123456789ABCDEFGHIJKLMNOPQRSTUVWXYZ", bas) lennum = LEN(num) FOR L0 = lennum TO 1 STEP -1 x = INSTR(validNums, MID$(num, L0, 1)) - 1 IF -1 = x THEN EXIT FUNCTION tmp = tmp + (x * (bas ^ (lennum - L0))) NEXT WHILE tmp outp = outp + (tmp MOD bas) tmp = tmp \ bas WEND sumDigits = outp
END FUNCTION
PRINT sumDigits(LTRIM$(STR$(1)), 10) PRINT sumDigits(LTRIM$(STR$(1234)), 10) PRINT sumDigits(LTRIM$(STR$(&HFE)), 16) PRINT sumDigits(LTRIM$(STR$(&HF0E)), 16) PRINT sumDigits("2", 2)</lang>
- Output:
1 10 11 20 0
See also: BBC BASIC, Run BASIC, Visual Basic
Applesoft BASIC
<lang ApplesoftBasic>10 BASE = 10 20 N$ = "1" : GOSUB 100 : PRINT N 30 N$ = "1234" : GOSUB 100 : PRINT N 40 BASE = 16 50 N$ = "FE" : GOSUB 100 : PRINT N 60 N$ = "F0E" : GOSUB 100 : PRINT N 90 END
100 REM SUM DIGITS OF N$, BASE 110 IF BASE = 1 THEN N = LEN(N$) : RETURN 120 IF BASE < 2 THEN BASE = 10 130 N = 0 : V$ = LEFT$("0123456789ABCDEFGHIJKLMNOPQRSTUVWXYZ", BASE) 140 FOR I = 1 TO LEN(N$) : C$ = MID$(N$, I, 1) 150 FOR J = 1 TO LEN(V$) 160 IF C$ <> MID$(V$, J, 1) THEN NEXT J : N = SQR(-1) : STOP 170 N = N + J - 1 180 NEXT I 190 RETURN</lang>
BBC BASIC
This solution deliberately avoids MOD and DIV so it is not restricted to 32-bit integers. <lang bbcbasic> *FLOAT64
PRINT "Digit sum of 1 (base 10) is "; FNdigitsum(1, 10) PRINT "Digit sum of 12345 (base 10) is "; FNdigitsum(12345, 10) PRINT "Digit sum of 9876543210 (base 10) is "; FNdigitsum(9876543210, 10) PRINT "Digit sum of FE (base 16) is "; ~FNdigitsum(&FE, 16) " (base 16)" PRINT "Digit sum of F0E (base 16) is "; ~FNdigitsum(&F0E, 16) " (base 16)" END DEF FNdigitsum(n, b) LOCAL q, s WHILE n <> 0 q = INT(n / b) s += n - q * b n = q ENDWHILE = s</lang>
- Output:
Digit sum of 1 (base 10) is 1 Digit sum of 12345 (base 10) is 15 Digit sum of 9876543210 (base 10) is 45 Digit sum of FE (base 16) is 1D (base 16) Digit sum of F0E (base 16) is 1D (base 16)
bc
<lang bc>define s(n) {
auto i, o, s o = scale scale = 0
for (i = n; i > 0; i /= ibase) { s += i % ibase } scale = o return(s)
}
ibase = 10 s(1) s(1234) ibase = 16 s(FE) s(F0E)</lang>
- Output:
1 10 29 29
C
<lang c>#include <stdio.h>
int SumDigits(unsigned long long n, const int base) {
int sum = 0; for (; n; n /= base) sum += n % base; return sum;
}
int main() {
printf("%d %d %d %d %d\n", SumDigits(1, 10), SumDigits(12345, 10), SumDigits(123045, 10), SumDigits(0xfe, 16), SumDigits(0xf0e, 16) ); return 0;
}</lang>
- Output:
1 15 15 29 29
C#
<lang csharp>namespace RosettaCode.SumDigitsOfAnInteger {
using System; using System.Collections.Generic; using System.Linq;
internal static class Program { /// <summary> /// Enumerates the digits of a number in a given base. /// </summary> /// <param name="number"> The number. </param> /// <param name="base"> The base. </param> /// <returns> The digits of the number in the given base. </returns> /// <remarks> /// The digits are enumerated from least to most significant. /// </remarks> private static IEnumerable<int> Digits(this int number, int @base = 10) { while (number != 0) { int digit; number = Math.DivRem(number, @base, out digit); yield return digit; } }
/// <summary> /// Sums the digits of a number in a given base. /// </summary> /// <param name="number"> The number. </param> /// <param name="base"> The base. </param> /// <returns> The sum of the digits of the number in the given base. </returns> private static int SumOfDigits(this int number, int @base = 10) { return number.Digits(@base).Sum(); }
/// <summary> /// Demonstrates <see cref="SumOfDigits" />. /// </summary> private static void Main() { foreach (var example in new[] { new {Number = 1, Base = 10}, new {Number = 12345, Base = 10}, new {Number = 123045, Base = 10}, new {Number = 0xfe, Base = 0x10}, new {Number = 0xf0e, Base = 0x10} }) { Console.WriteLine(example.Number.SumOfDigits(example.Base)); } } }
}</lang>
- Output:
1 15 15 29 29
C++
<lang cpp>#include <iostream>
- include <cmath>
int SumDigits(const unsigned long long int digits, const int BASE = 10) {
int sum = 0; unsigned long long int x = digits; for (int i = log(digits)/log(BASE); i>0; i--){ const double z = std::pow(BASE,i);
const unsigned long long int t = x/z; sum += t; x -= t*z;
} return x+sum;
}
int main() {
std::cout << SumDigits(1) << ' ' << SumDigits(12345) << ' ' << SumDigits(123045) << ' ' << SumDigits(0xfe, 16) << ' ' << SumDigits(0xf0e, 16) << std::endl; return 0;
}</lang>
- Output:
1 15 15 29 29
Template metaprogramming version
Tested with g++-4.6.3 (Ubuntu). <lang cpp> // Template Metaprogramming version by Martin Ettl
- include <iostream>
- include <cmath>
typedef unsigned long long int T; template <typename T, T i> void For(T &sum, T &x, const T &BASE) {
const double z(std::pow(BASE,i)); const T t = x/z; sum += t; x -= t*z; For<T, i-1>(sum,x,BASE);
} template <> void For<T,0>(T &, T &, const T &){}
template <typename T, T digits, int BASE> T SumDigits()
{ T sum(0); T x(digits); const T end(log(digits)/log(BASE)); For<T,end>(sum,x,BASE); return x+sum;
}
int main() {
std::cout << SumDigits<T, 1 , 10>() << ' ' << SumDigits<T, 12345 , 10>() << ' ' << SumDigits<T, 123045, 10>() << ' ' << SumDigits<T, 0xfe , 16>() << ' ' << SumDigits<T, 0xf0e , 16>() << std::endl; return 0;
} </lang>
- Output:
1 15 15 29 29
Clojure
<lang clojure>(defn sum-digits [n base]
(let [number (if-not (string? n) (Long/toString n base) n)] (reduce + (map #(Long/valueOf (str %) base) number))))</lang>
- Output:
user=> (sum-digits 1 10) 1 user=> (sum-digits 1234 10) 10 user=> (sum-digits "fe" 16) 29 user=> (sum-digits "f0e" 16) 29 user=> (sum-digits 254 16) 29 user=> (sum-digits 3854 16) 29 user=> (sum-digits 16rfe 16) 29 user=> (sum-digits 16rf0e 16) 29 user=> (sum-digits "clojure" 32) 147
Common Lisp
<lang lisp>(defun sum-digits (number base)
(loop for n = number then q for (q r) = (multiple-value-list (truncate n base)) sum r until (zerop q)))</lang>
Example: <lang lisp>(loop for (number base) in '((1 10) (1234 10) (#xfe 16) (#xf0e 16))
do (format t "(~a)_~a = ~a~%" number base (sum-digits number base)))</lang>
- Output:
(1)_10 = 1 (1234)_10 = 10 (254)_16 = 29 (3854)_16 = 29
D
<lang d>import std.stdio, std.bigint;
uint sumDigits(T)(T n, in uint base=10) pure nothrow in {
assert(base > 1);
} body {
typeof(return) total = 0; for ( ; n; n /= base) total += n % base; return total;
}
void main() {
1.sumDigits.writeln; 1_234.sumDigits.writeln; sumDigits(0xfe, 16).writeln; sumDigits(0xf0e, 16).writeln; 1_234.BigInt.sumDigits.writeln;
}</lang>
- Output:
1 10 29 29 10
Elixir
<lang elixir>defmodule RC do
def sumDigits(n, base\\10) def sumDigits(n, base) when is_integer(n) do Integer.digits(n, base) |> Enum.sum end def sumDigits(n, base) when is_binary(n) do String.codepoints(n) |> Enum.map(&String.to_integer(&1, base)) |> Enum.sum end
end
Enum.each([{1, 10}, {1234, 10}, {0xfe, 16}, {0xf0e, 16}], fn {n,base} ->
IO.puts "#{Integer.to_string(n,base)}(#{base}) sums to #{ RC.sumDigits(n,base) }"
end) IO.puts "" Enum.each([{"1", 10}, {"1234", 10}, {"fe", 16}, {"f0e", 16}], fn {n,base} ->
IO.puts "#{n}(#{base}) sums to #{ RC.sumDigits(n,base) }"
end)</lang>
- Output:
1(10) sums to 1 1234(10) sums to 10 FE(16) sums to 29 F0E(16) sums to 29 1(10) sums to 1 1234(10) sums to 10 fe(16) sums to 29 f0e(16) sums to 29
Emacs Lisp
<lang Emacs Lisp> (defun digit-sum (n)
(apply '+ (mapcar 'string-to-number (cdr (butlast (split-string (number-to-string n) "") )))))
(insert (format "%d\n" (digit-sum 1234) )) </lang> Output:
10
Erlang
<lang erlang> -module(sum_digits). -export([sum_digits/2, sum_digits/1]).
sum_digits(N) ->
sum_digits(N,10).
sum_digits(N,B) ->
sum_digits(N,B,0).
sum_digits(0,_,Acc) ->
Acc;
sum_digits(N,B,Acc) when N < B ->
Acc+N;
sum_digits(N,B,Acc) ->
sum_digits(N div B, B, Acc + (N rem B)).
</lang>
Example usage:
2> sum_digits:sum_digits(1). 1 3> sum_digits:sum_digits(1234). 10 4> sum_digits:sum_digits(16#fe,16). 29 5> sum_digits:sum_digits(16#f0e,16). 29
Ezhil
<lang Python>
- இது ஒரு எழில் தமிழ் நிரலாக்க மொழி உதாரணம்
- sum of digits of a number
- எண்ணிக்கையிலான இலக்கங்களின் தொகை
நிரல்பாகம் எண்_கூட்டல்( எண் )
தொகை = 0 @( எண் > 0 ) வரை d = எண்%10; பதிப்பி "digit = ",d எண் = (எண்-d)/10; தொகை = தொகை + d முடி பின்கொடு தொகை
முடி
பதிப்பி எண்_கூட்டல்( 1289)#20
பதிப்பி எண்_கூட்டல்( 123456789)# 45
</lang>
F#
<lang fsharp>open System
let digsum b n =
let rec loop acc = function | n when n > 0 -> let m, r = Math.DivRem(n, b) loop (acc + r) m | _ -> acc loop 0 n
[<EntryPoint>] let main argv =
let rec show = function | n :: b :: r -> printf " %d" (digsum b n); show r | _ -> ()
show [1; 10; 1234; 10; 0xFE; 16; 0xF0E; 16] // -> 1 10 29 29 0</lang>
or Generically
In order to complete the Digital root task I require a function which can handle numbers larger than 32 bit integers. <lang fsharp> //Sum Digits of An Integer - Nigel Galloway: January 31st., 2015 //This code will work with any integer type let inline sumDigits N BASE =
let rec sum(g, n) = if n < BASE then n+g else sum(g+n%BASE, n/BASE) sum(LanguagePrimitives.GenericZero<_>,N)
</lang>
- Output:
> sumDigits 254 2;; val it : int = 7 > sumDigits 254 10;; val it : int = 11 > sumDigits 254 16;; val it : int = 29 > sumDigits 254 23;; val it : int = 12
so let's try it with a big integer
> sumDigits 123456789123456789123456789123456789123456789I 10I;; val it : System.Numerics.BigInteger = 225 {IsEven = false; IsOne = false; IsPowerOfTwo = false; IsZero = false; Sign = 1;}
Factor
<lang factor>: sum-digits ( base n -- sum ) 0 swap [ dup zero? ] [ pick /mod swapd + swap ] until drop nip ;
{ 10 10 16 16 } { 1 1234 0xfe 0xf0e } [ sum-digits ] 2each</lang>
- Output:
--- Data stack: 1 10 29 29
Forth
This is an easy task for Forth, that has built in support for radices up to 36. You set the radix by storing the value in variable BASE. <lang forth>: sum_int 0 begin over while swap base @ /mod swap rot + repeat nip ;
2 base ! 11110 sum_int decimal . cr
10 base ! 12345 sum_int decimal . cr 16 base ! f0e sum_int decimal . cr</lang>
Fortran
Please find GNU/linux compilation instructions along with the sample output within the comments at the start of this FORTRAN 2008 source. Thank you. Review of this page shows a solution to this task with the number input as text. The solution is the sum of index positions in an ordered list of digit characters. (awk). Other solutions ignore the representations of the input, encode digits using the base, then sum the encoding. Both methods appear in this implementation. <lang FORTRAN> !-*- mode: compilation; default-directory: "/tmp/" -*- !Compilation started at Fri Jun 7 21:00:12 ! !a=./f && make $a && $a !gfortran -std=f2008 -Wall -fopenmp -ffree-form -fall-intrinsics -fimplicit-none f.f08 -o f !f.f08:57.29: ! ! subroutine process1(fmt,s,b) ! 1 !Warning: Unused dummy argument 'b' at (1) !digit sum n ! 1 1 ! 10 1234 ! 29 fe ! 29 f0e ! sum of digits of n expressed in base is... ! n base sum ! 1 10 1 ! 1234 10 10 ! 254 16 29 ! 3854 16 29 ! !Compilation finished at Fri Jun 7 21:00:12
module base_mod
private :: reverse
contains
subroutine reverse(a) integer, dimension(:), intent(inout) :: a integer :: i, j, t do i=1,size(a)/2 j = size(a) - i + 1 t = a(i) a(i) = a(j) a(j) = t end do end subroutine reverse
function antibase(b, n) result(a) integer, intent(in) :: b,n integer, dimension(32) :: a integer :: m, i a = 0 m = n i = 1 do while (m .ne. 0) a(i) = mod(m, b) m = m/b i = i+1 end do call reverse(a) end function antibase
end module base_mod
program digit_sum
use base_mod call still call confused
contains
subroutine still character(len=6),parameter :: fmt = '(i9,a)' print'(a9,a8)','digit sum','n' call process1(fmt,'1',10) call process1(fmt,'1234',10) call process1(fmt,'fe',16) call process1(fmt,'f0e',16) end subroutine still
subroutine process1(fmt,s,b) character(len=*), intent(in) :: fmt, s integer, intent(in), optional :: b integer :: i print fmt,sum((/(index('123456789abcdef',s(i:i)),i=1,len(s))/)),' '//s end subroutine process1
subroutine confused character(len=5),parameter :: fmt = '(3i7)' print*,'sum of digits of n expressed in base is...' print'(3a7)','n','base','sum' call process0(10,1,fmt) call process0(10,1234,fmt) call process0(16,254,fmt) call process0(16,3854,fmt) end subroutine confused
subroutine process0(b,n,fmt) integer, intent(in) :: b, n character(len=*), intent(in) :: fmt print fmt,n,b,sum(antibase(b, n)) end subroutine process0
end program digit_sum </lang>
FreeBASIC
<lang freebasic>' FB 1.05.0 Win64
Function SumDigits(number As Integer, nBase As Integer) As Integer
If number < 0 Then number = -number ' convert negative numbers to positive If nBase < 2 Then nBase = 2 ' nBase can't be less than 2 Dim As Integer sum = 0 While number > 0 sum += number Mod nBase number \= nBase Wend Return sum
End Function
Print "The sums of the digits are:" Print Print "1 base 10 :"; SumDigits(1, 10) Print "1234 base 10 :"; SumDigits(1234, 10) Print "fe base 16 :"; SumDigits(&Hfe, 16) Print "f0e base 16 :"; SumDigits(&Hf0e, 16) Print Print "Press any key to quit the program" Sleep</lang>
- Output:
The sums of the digits are: 1 base 10 : 1 1234 base 10 : 10 fe base 16 : 29 f0e base 16 : 29
Go
Handling numbers up to 2^64-1 and bases from 2 to 36 is pretty easy, larger values can be handled using the math/big
package (but it's still limited to base<=36).
<lang go>// File digit.go
package digit
import ( "math/big" "strconv" )
func SumString(n string, base int) (int, error) { i, ok := new(big.Int).SetString(n, base) if !ok { return 0, strconv.ErrSyntax } if i.Sign() < 0 { return 0, strconv.ErrRange } if i.BitLen() <= 64 { return Sum(i.Uint64(), base), nil } return SumBig(i, base), nil }
func Sum(i uint64, base int) (sum int) { b64 := uint64(base) for ; i > 0; i /= b64 { sum += int(i % b64) } return }
func SumBig(n *big.Int, base int) (sum int) { i := new(big.Int).Set(n) b := new(big.Int).SetUint64(uint64(base)) r := new(big.Int) for i.BitLen() > 0 { i.DivMod(i, b, r) sum += int(r.Uint64()) } return }</lang> <lang go>// File digit_test.go
package digit
import "testing"
type testCase struct { n string base int dSum int }
var testData = []testCase{ {"1", 10, 1}, {"1234", 10, 10}, {"fe", 16, 29}, {"f0e", 16, 29}, {"18446744073709551615", 10, 87}, {"abcdefghijklmnopqrstuvwzuz0123456789", 36, 628}, }
func TestSumString(t *testing.T) { for _, tc := range testData { ds, err := SumString(tc.n, tc.base) if err != nil { t.Error("test case", tc, err) continue } if ds != tc.dSum { t.Error("test case", tc, "got", ds, "expected", tc.dSum) } } }
func TestErrors(t *testing.T) { for _, tc := range []struct { n string base int }{ {"1234", 37}, {"0", 1}, {"1234", 4}, {"-123", 10}, } { _, err := SumString(tc.n, tc.base) if err == nil { t.Error("expected error for", tc) } t.Log("got expected error:", err) } }</lang>
Groovy
Solution: <lang groovy>def digitsum = { number, radix = 10 ->
Integer.toString(number, radix).collect { Integer.parseInt(it, radix) }.sum()
}</lang>
Test: <lang groovy>[[30, 2], [30, 10], [1, 10], [12345, 10], [123405, 10], [0xfe, 16], [0xf0e, 16]].each {
println """ Decimal value: ${it[0]} Radix: ${it[1]} Radix value: ${Integer.toString(it[0], it[1])} Decimal Digit Sum: ${digitsum(it[0], it[1])} Radix Digit Sum: ${Integer.toString(digitsum(it[0], it[1]), it[1])} """
}</lang>
- Output:
Decimal value: 30 Radix: 2 Radix value: 11110 Decimal Digit Sum: 4 Radix Digit Sum: 100 Decimal value: 30 Radix: 10 Radix value: 30 Decimal Digit Sum: 3 Radix Digit Sum: 3 Decimal value: 1 Radix: 10 Radix value: 1 Decimal Digit Sum: 1 Radix Digit Sum: 1 Decimal value: 12345 Radix: 10 Radix value: 12345 Decimal Digit Sum: 15 Radix Digit Sum: 15 Decimal value: 123405 Radix: 10 Radix value: 123405 Decimal Digit Sum: 15 Radix Digit Sum: 15 Decimal value: 254 Radix: 16 Radix value: fe Decimal Digit Sum: 29 Radix Digit Sum: 1d Decimal value: 3854 Radix: 16 Radix value: f0e Decimal Digit Sum: 29 Radix Digit Sum: 1d
Haskell
<lang haskell>digsum
:: Integral a => a -> a -> a
digsum base = f 0
where f a 0 = a f a n = f (a + r) q where (q, r) = n `quotRem` base
main :: IO () main = print $ digsum 16 255 -- "FF": 15 + 15 = 30</lang>
- Output:
30
Or, we could write sum . (digitToInt <$>)
<lang haskell>import Data.Char (digitToInt, intToDigit, isHexDigit)
import Data.List (transpose, intersperse)
import Numeric (showIntAtBase, readInt)
-- Function of digit string digitSum :: String -> Int digitSum = sum . (digitToInt <$>)
-- Function of base and integer value intDigitSum :: Int -> Int -> Int intDigitSum base n = digitSum (showIntAtBase base intToDigit n [])
-- TEST main :: IO () main =
mapM_ putStrLn $ unwords <$> transpose (((<$>) =<< flip justifyRight ' ' . succ . maximum . (length <$>)) <$> transpose ([ "Base" , "Digits" , "Value" , "digit string -> sum" , "integer value -> sum" ] : ((\(s, b) -> let v = readBase b s in [ show b -- base , show s -- digits , show v -- value , show (digitSum s) -- sum from digit string , show (intDigitSum b v) -- sum from base and value ]) <$> [("1", 10), ("1234", 10), ("fe", 16), ("f0e", 16)]))) where justifyRight n c s = drop (length s) (replicate n c ++ s) readBase b s = let [(n, _)] = readInt b isHexDigit digitToInt s in n</lang>
- Output:
Base Digits Value digit string -> sum integer value -> sum 10 "1" 1 1 1 10 "1234" 1234 10 10 16 "fe" 254 29 29 16 "f0e" 3854 29 29
Icon and Unicon
This solution works in both languages. This solution assumes the input number is expressed in the indicated base. This assumption differs from that made in some of the other solutions.
<lang unicon>procedure main(a)
write(dsum(a[1]|1234,a[2]|10))
end
procedure dsum(n,b)
n := integer((\b|10)||"r"||n) sum := 0 while sum +:= (0 < n) % b do n /:= b return sum
end</lang>
Sample runs:
->sdi 1 1 ->sdi 1234 10 ->sdi fe 16 29 ->sdi f0e 16 29 ->sdi ff 16 30 ->sdi 255 16 12 ->sdi fffff 16 75 ->sdi 254 16 11 ->
J
<lang j>digsum=: 10&$: : (+/@(#.inv))</lang>
Example use:
<lang J> digsum 1234 10
10 digsum 254
11
16 digsum 254
29</lang>
Illustration of mechanics:
<lang j> 10 #. 1 2 3 4 1234
10 #.inv 1234
1 2 3 4
10 +/ 1 2 3 4
10
10 +/@(#.inv) 1234
10</lang>
So #.inv gives us the digits, +/ gives us the sum, and @ glues them together with +/ being a "post processor" for #.inv or, as we say in the expression: (#.inv). We need the parenthesis or inv will try to look up the inverse of +/@#. and that's not well defined.
The rest of it is about using 10 as the default left argument when no left argument is defined. A J verb has a monadic definition (for use with one argument) and a dyadic definition (for use with two arguments) and : derives a new verb where the monadic definition is used from the verb on the left and the dyadic definition is used from the verb on the right. $: is a self reference to the top-level defined verb.
Full examples:
<lang j> digsum 1 1
digsum 1234
10
16 digsum 16bfe
29
16 digsum 16bf0e
29</lang>
Note that J implements numeric types -- J tries to ensure that the semantics of numbers match their mathematical properties. So it doesn't matter how we originally obtained a number.
<lang j> 200+54 254
254
254
2.54e2
254
16bfe
254
254b10 , 1r254b0.1 NB. 10 in base 254 , 0.1 in base 1/254
254 254</lang>
Java
<lang java>import java.math.BigInteger; public class SumDigits {
public static int sumDigits(long num) {
return sumDigits(num, 10);
} public static int sumDigits(long num, int base) {
String s = Long.toString(num, base); int result = 0; for (int i = 0; i < s.length(); i++) result += Character.digit(s.charAt(i), base); return result;
} public static int sumDigits(BigInteger num) {
return sumDigits(num, 10);
} public static int sumDigits(BigInteger num, int base) {
String s = num.toString(base); int result = 0; for (int i = 0; i < s.length(); i++) result += Character.digit(s.charAt(i), base); return result;
}
public static void main(String[] args) {
System.out.println(sumDigits(1)); System.out.println(sumDigits(12345)); System.out.println(sumDigits(123045)); System.out.println(sumDigits(0xfe, 16)); System.out.println(sumDigits(0xf0e, 16)); System.out.println(sumDigits(new BigInteger("12345678901234567890")));
}
}</lang>
- Output:
1 15 15 29 29 90
JavaScript
Imperative
<lang JavaScript>function sumDigits(n) {
n +=
for (var s=0, i=0, e=n.length; i<e; i+=1) s+=parseInt(n.charAt(i),36)
return s
}
for (var n of [1, 12345, 0xfe, 'fe', 'f0e', '999ABCXYZ']) document.write(n, ' sum to ', sumDigits(n), '
')
</lang>
- Output:
1 sum to 1 12345 sum to 15 254 sum to 11 fe sum to 29 f0e sum to 29 999ABCXYZ sum to 162
Functional (ES 5)
<lang JavaScript>(function () {
'use strict';
// digitsSummed :: (Int | String) -> Int function digitsSummed(number) { // 10 digits + 26 alphabetics // give us glyphs for up to base 36 var intMaxBase = 36; return number .toString() .split() .reduce(function (a, digit) { return a + parseInt(digit, intMaxBase); }, 0); }
// TEST
return [1, 12345, 0xfe, 'fe', 'f0e', '999ABCXYZ'] .map(function (x) { return x + ' -> ' + digitsSummed(x); }) .join('\n');
})(); </lang>
1 -> 1 12345 -> 15 254 -> 11 fe -> 29 f0e -> 29 999ABCXYZ -> 162
jq
The following pipeline will have the desired effect if numbers and/or strings are presented as input: <lang jq>tostring | explode | map(tonumber - 48) | add</lang> For example:<lang sh> $ jq -M 'tostring | explode | map(tonumber - 48) | add' 123 6 "123" 6</lang>
Julia
Using the built-in digits
function:
<lang julia>sumdigits(n, base=10) = sum(digits(n, base))</lang>
Kotlin
<lang scala>// version 1.1.0
const val digits = "0123456789abcdefghijklmnopqrstuvwxyz"
fun sumDigits(ns: String, base: Int): Int {
val n = ns.toLowerCase().trim() if (base !in 2..36) throw IllegalArgumentException("Base must be between 2 and 36") if (n.isEmpty()) throw IllegalArgumentException("Number string can't be blank or empty") var sum = 0 for (digit in n) { val index = digits.indexOf(digit) if (index == -1 || index >= base) throw IllegalArgumentException("Number string contains an invalid digit") sum += index } return sum
}
fun main(args: Array<String>) {
val numbers = mapOf("1" to 10, "1234" to 10, "fe" to 16, "f0e" to 16, "1010" to 2, "777" to 8, "16xyz" to 36) println("The sum of digits is:") for ((number, base) in numbers) println("$number\tbase $base\t-> ${sumDigits(number, base)}")
}</lang>
- Output:
The sum of digits is: 1 base 10 -> 1 1234 base 10 -> 10 fe base 16 -> 29 f0e base 16 -> 29 1010 base 2 -> 2 777 base 8 -> 21 16xyz base 36 -> 109
Lasso
<lang Lasso>define br => '
\n'
define sumdigits(int, base = 10) => { fail_if(#base < 2, -1, 'Base need to be at least 2') local( out = integer, divmod ) while(#int) => { #divmod = #int -> div(#base) #int = #divmod -> first #out += #divmod -> second } return #out }
sumdigits(1) br sumdigits(12345) br sumdigits(123045) br sumdigits(0xfe, 16) br sumdigits(0xf0e, 16)</lang>
- Output:
1 15 15 29 29
Lingo
<lang lingo>on sum_digits (n, base)
sum = 0 repeat while n m = n / base sum = sum + n - m * base n = m end repeat return sum
end</lang>
<lang lingo>put sum_digits(1, 10) -- 1 put sum_digits(1234, 10) -- 10 put sum_digits(254, 16) -- 0xfe -- 29 put sum_digits(3854, 16) -- 0xf0e -- 29</lang>
LiveCode
<lang LiveCode>function sumDigits n, base
local numb if base is empty then put 10 into base repeat for each char d in n add baseConvert(d,base,10) to numb end repeat return numb
end sumDigits</lang> Example <lang LiveCode>put sumdigits(1,10) & comma & \
sumdigits(1234,10) & comma & \ sumdigits(fe,16) & comma & \ sumdigits(f0e,16)</lang>Output<lang LiveCode>1,10,29,29</lang>
Logo
<lang logo>make "digits "0123456789abcdefghijklmnopqrstuvwxyz
to digitvalue :digit
output difference find [equal? :digit item ? :digits] iseq 1 count :digits 1
end
to sumdigits :number [:base 10]
output reduce "sum map.se "digitvalue :number
end
foreach [1 1234 fe f0e] [print (se ? "-> sumdigits ?)]</lang>
- Output:
1 -> 1 1234 -> 10 fe -> 29 f0e -> 29
Lua
<lang lua>function sum_digits(n, base)
sum = 0 while n > 0.5 do m = math.floor(n / base) digit = n - m * base sum = sum + digit n = m end return sum
end
print(sum_digits(1, 10)) print(sum_digits(1234, 10)) print(sum_digits(0xfe, 16)) print(sum_digits(0xf0e, 16))</lang>
- Output:
1 10 29 29
Maple
<lang maple>sumDigits := proc( num ) local digits, number_to_string, i; number_to_string := convert( num, string ); digits := [ seq( convert( h, decimal, hex ), h in seq( parse( i ) , i in number_to_string ) ) ]; return add( digits ); end proc: sumDigits( 1234 ); sumDigits( "fe" );</lang>
- Output:
10 29
Mathematica
<lang Mathematica>Total[IntegerDigits[1234]] Total[IntegerDigits[16^^FE, 16]]</lang>
- Output:
10 29
МК-61/52
<lang>П0 <-> П1 Сx П2 ИП1 ^ ИП0 / [x] П3 ИП0 * - ИП2 + П2 ИП3 П1 x=0 05 ИП2 С/П</lang>
ML
mLite
Left in the to_radix even though not used in the solution. <lang ocaml>exception :radix_out_of_range and :unknown_digit;
fun to_radix (0, radix, result) = implode result
| (n, radix > 36, result) = raise :radix_out_of_range | (n rem radix > 10, radix, result) = to_radix (n div radix, radix, chr (n rem radix + ord #"a" - 10) :: result) | (n, radix, result) = to_radix (n div radix, radix, chr (n rem radix + ord #"0") :: result) | (n, radix) = to_radix (n, radix, [])
fun from_radix (s, radix) =
let val digits = explode "0123456789abcdefghijklmnopqrstuvwxyz"; val len_digits = len digits; fun index (_, n >= radix, c) = raise :unknown_digit | (h :: t, n, c = h) = n | (_ :: t, n, c) = index (t, n + 1, c) | c = index (digits, 0, c) and conv ([], radix, power, n) = n | (h :: t, radix, power, n) = conv (t, radix, power * radix, index h * power + n) | (s, radix) = conv (rev ` explode s, radix, 1, 0) in conv (s, radix) end
fun sumdig ([], base, n) = n | (h :: t, base, n) = sumdig (t, base, from_radix (implode [h], base) + n) | (s, base) = sumdig (explode s, base, 0)
fun shosum (s, b) = (print "sum of digits of "; print s; print " (base "; print b; print ") = "; println ` sumdig (s, b))
shosum ("10fg",17); shosum ("deadbeef",16); shosum ("1101010101010101010101010101010101010101010101010101010101010101010101010101010101010101",2); shosum ("thequickbrownfoxjumpsoverthelazydog",36); </lang> Output
sum of digits of 10fg (base 17) = 32 sum of digits of deadbeef (base 16) = 104 sum of digits of 1101010101010101010101010101010101010101010101010101010101010101010101010101010101010101 (base 2) = 45 sum of digits of thequickbrownfoxjumpsoverthelazydog (base 36) = 788
NetRexx
Strings
Processes data as text from the command line. Provides a representative sample if no input is supplied: <lang NetRexx>/* NetRexx */ options replace format comments java crossref symbols nobinary
parse arg input inputs = ['1234', '01234', '0xfe', '0xf0e', '0', '00', '0,2' '1', '070', '77, 8' '0xf0e, 10', '070, 16', '0xf0e, 36', '000999ABCXYZ, 36', 'ff, 16', 'f, 10', 'z, 37'] -- test data if input.length() > 0 then inputs = [input] -- replace test data with user input loop i_ = 0 to inputs.length - 1
in = inputs[i_] parse in val . ',' base . dSum = sumDigits(val, base) say 'Sum of digits for integer "'val'" for a given base of "'base'":' dSum'\-' -- Carry the exercise to it's logical conclusion and sum the results to give a single digit in range 0-9 loop while dSum.length() > 1 & dSum.datatype('n') dSum = sumDigits(dSum, 10) say ',' dSum'\-' end say end i_
-- Sum digits of an integer method sumDigits(val = Rexx, base = Rexx ) public static returns Rexx
rVal = 0 parse normalizeValue(val, base) val base . loop label digs for val.length() -- loop to extract digits from input and sum them parse val dv +1 val do rVal = rVal + Integer.valueOf(dv.toString(), base).intValue() catch ex = NumberFormatException rVal = 'NumberFormatException:' ex.getMessage() leave digs end end digs return rVal
-- Clean up the input, normalize the data and determine which base to use method normalizeValue(inV = Rexx, base = Rexx ) private static returns Rexx
inV = inV.strip('l') base = base.strip() parse inV xpref +2 . - =0 opref +1 . - =0 . '0x' xval . ',' . - =0 . '0' oval . ',' . - =0 dval .
select when xpref = '0x' & base.length() = 0 then do -- value starts with '0x' and no base supplied. Assign hex as base inval = xval base = 16 end when opref = '0' & base.length() = 0 then do -- value starts with '0' and no base supplied. Assign octal as base inval = oval base = 8 end otherwise do inval = dval end end if base.length() = 0 then base = 10 -- base not set. Assign decimal as base if inval.length() <= 0 then inval = 0 -- boundary condition. Invalid input or a single zero rVal = inval base
return rVal
</lang>
- Output:
Sum of digits for integer "1234" for a given base of "": 10, 1 Sum of digits for integer "01234" for a given base of "": 10, 1 Sum of digits for integer "0xfe" for a given base of "": 29, 11, 2 Sum of digits for integer "0xf0e" for a given base of "": 29, 11, 2 Sum of digits for integer "0" for a given base of "": 0 Sum of digits for integer "00" for a given base of "": 0 Sum of digits for integer "0" for a given base of "2": 0 Sum of digits for integer "070" for a given base of "": 7 Sum of digits for integer "77" for a given base of "8": 14, 5 Sum of digits for integer "070" for a given base of "16": 7 Sum of digits for integer "0xf0e" for a given base of "36": 62, 8 Sum of digits for integer "000999ABCXYZ" for a given base of "36": 162, 9 Sum of digits for integer "ff" for a given base of "16": 30, 3 Sum of digits for integer "f" for a given base of "10": NumberFormatException: For input string: "f" Sum of digits for integer "z" for a given base of "37": NumberFormatException: radix 37 greater than Character.MAX_RADIX
Type int
Processes sample data as int arrays: <lang NetRexx>/* NetRexx */ options replace format comments java crossref symbols binary
inputs = [[int 1234, 10], [octal('01234'), 8], [0xfe, 16], [0xf0e,16], [8b0, 2], [16b10101100, 2], [octal('077'), 8]] -- test data loop i_ = 0 to inputs.length - 1
in = inputs[i_, 0] ib = inputs[i_, 1] dSum = sumDigits(in, ib) say 'Sum of digits for integer "'Integer.toString(in, ib)'" for a given base of "'ib'":' dSum'\-' -- Carry the exercise to it's logical conclusion and sum the results to give a single digit in range 0-9 loop while dSum.length() > 1 & dSum.datatype('n') dSum = sumDigits(dSum, 10) say ',' dSum'\-' end say end i_
-- Sum digits of an integer method sumDigits(val = int, base = int 10) public static returns Rexx
rVal = Rexx 0 sVal = Rexx(Integer.toString(val, base)) loop label digs for sVal.length() -- loop to extract digits from input and sum them parse sVal dv +1 sVal do rVal = rVal + Integer.valueOf(dv.toString(), base).intValue() catch ex = NumberFormatException rVal = 'NumberFormatException:' ex.getMessage() leave digs end end digs return rVal
-- if there's a way to insert octal constants into an int in NetRexx I don't remember it method octal(oVal = String) private constant returns int signals NumberFormatException
iVal = Integer.valueOf(oVal, 8).intValue() return iVal
</lang>
- Output:
Sum of digits for integer "1234" for a given base of "10": 10, 1 Sum of digits for integer "1234" for a given base of "8": 10, 1 Sum of digits for integer "fe" for a given base of "16": 29, 11, 2 Sum of digits for integer "f0e" for a given base of "16": 29, 11, 2 Sum of digits for integer "0" for a given base of "2": 0 Sum of digits for integer "10101100" for a given base of "2": 4 Sum of digits for integer "77" for a given base of "8": 14, 5
Nim
<lang nim>proc sumdigits(n, base: Natural): Natural =
var n = n while n > 0: result += n mod base n = n div base
echo sumDigits(1, 10) echo sumDigits(12345, 10) echo sumDigits(123045, 10) echo sumDigits(0xfe, 16) echo sumDigits(0xf0e, 16)</lang>
- Output:
1 15 15 29 29
Oberon-2
<lang oberon2> MODULE SumDigits; IMPORT Out; PROCEDURE Sum(n: LONGINT;base: INTEGER): LONGINT; VAR sum: LONGINT; BEGIN sum := 0; WHILE (n > 0) DO INC(sum,(n MOD base)); n := n DIV base END; RETURN sum END Sum; BEGIN Out.String("1 : ");Out.LongInt(Sum(1,10),10);Out.Ln; Out.String("1234 : ");Out.LongInt(Sum(1234,10),10);Out.Ln; Out.String("0FEH : ");Out.LongInt(Sum(0FEH,16),10);Out.Ln; Out.String("OF0EH : ");Out.LongInt(Sum(0F0EH,16),10);Out.Ln END SumDigits. </lang>
- Output:
1 : 1 1234 : 10 0FEH : 29 OF0EH : 29
OCaml
<lang ocaml>let sum_digits ~digits ~base =
let rec aux sum x = if x <= 0 then sum else aux (sum + x mod base) (x / base) in aux 0 digits
let () =
Printf.printf "%d %d %d %d %d\n" (sum_digits 1 10) (sum_digits 12345 10) (sum_digits 123045 10) (sum_digits 0xfe 16) (sum_digits 0xf0e 16)</lang>
- Output:
1 15 15 29 29
Oforth
<lang Oforth>: sumDigits(n, base) 0 while( n ) [ n base /mod ->n + ] ;</lang>
Usage : <lang Oforth>sumDigits(1, 10) println sumDigits(1234, 10) println sumDigits(0xfe, 16) println sumDigits(0xf0e, 16) println</lang>
- Output:
1 10 29 29
PARI/GP
<lang parigp>dsum(n,base)=my(s); while(n, s += n%base; n \= base); s</lang>
Also the built-in sumdigits
can be used for base 10.
Pascal
<lang pascal>Program SumOFDigits;
function SumOfDigitBase(n:UInt64;base:LongWord): LongWord; var
tmp: Uint64; digit,sum : LongWord;
Begin
digit := 0; sum := 0; While n > 0 do Begin tmp := n div base; digit := n-base*tmp; n := tmp; inc(sum,digit); end; SumOfDigitBase := sum;
end; Begin
writeln(' 1 sums to ', SumOfDigitBase(1,10)); writeln('1234 sums to ', SumOfDigitBase(1234,10)); writeln(' $FE sums to ', SumOfDigitBase($FE,16)); writeln('$FOE sums to ', SumOfDigitBase($F0E,16)); writeln('18446744073709551615 sums to ', SumOfDigitBase(High(Uint64),10));
end.</lang>
- output
1 sums to 1 1234 sums to 10 $FE sums to 29 $FOE sums to 29 18446744073709551615 sums to 87
Perl
<lang Perl>#!/usr/bin/perl use strict; use warnings;
my %letval = map { $_ => $_ } 0 .. 9; $letval{$_} = ord($_) - ord('a') + 10 for 'a' .. 'z'; $letval{$_} = ord($_) - ord('A') + 10 for 'A' .. 'Z';
sub sumdigits {
my $number = shift; my $sum = 0; $sum += $letval{$_} for (split //, $number); $sum;
}
print "$_ sums to " . sumdigits($_) . "\n"
for (qw/1 1234 1020304 fe f0e DEADBEEF/);</lang>
- Output:
1 sums to 1 1234 sums to 10 1020304 sums to 10 fe sums to 29 f0e sums to 29 DEADBEEF sums to 104
The ntheory module also does this, for a solution similar to Perl 6, with identical output. <lang Perl>use ntheory "sumdigits"; say sumdigits($_,36) for (qw/1 1234 1020304 fe f0e DEADBEEF/);</lang>
Perl 6
This will handle input numbers in any base from 2 to 36. The results are in base 10. <lang perl6>say Σ $_ for <1 1234 1020304 fe f0e DEADBEEF>;
sub Σ { [+] $^n.comb.map: { :36($_) } }</lang>
- Output:
1 10 10 29 29 104
Phix
<lang Phix>function sum_digits(integer n, integer base) integer res = 0
while n do res += remainder(n,base) n = floor(n/base) end while return res
end function
?sum_digits(1,10) ?sum_digits(1234,10) ?sum_digits(#FE,16) ?sum_digits(#F0E,16)</lang>
- Output:
1 10 29 29
PHP
<lang php><?php function sumDigits($num, $base = 10) {
$s = base_convert($num, 10, $base); foreach (str_split($s) as $c) $result += intval($c, $base); return $result;
} echo sumDigits(1), "\n"; echo sumDigits(12345), "\n"; echo sumDigits(123045), "\n"; echo sumDigits(0xfe, 16), "\n"; echo sumDigits(0xf0e, 16), "\n"; ?></lang>
- Output:
1 15 15 29 29
PicoLisp
<lang PicoLisp>(de sumDigits (N Base)
(or (=0 N) (+ (% N Base) (sumDigits (/ N Base) Base)) ) )</lang>
Test: <lang PicoLisp>: (sumDigits 1 10) -> 1
- (sumDigits 1234 10)
-> 10
- (sumDigits (hex "fe") 16)
-> 29
- (sumDigits (hex "f0e") 16)
-> 29</lang>
PL/I
<lang PL/I> sum_digits: procedure options (main); /* 4/9/2012 */
declare ch character (1); declare (k, sd) fixed;
on endfile (sysin) begin; put skip data (sd); stop; end; sd = 0; do forever; get edit (ch) (a(1)); put edit (ch) (a); k = index('abcdef', ch); if k > 0 then /* we have a base above 10 */ sd = sd + 9 + k; else sd = sd + ch; end;
end sum_digits; </lang> results:
5c7e SD= 38; 10111000001 SD= 5;
PowerShell
<lang Powershell> function Get-DigitalSum ([string] $number, $base = 10) {
if ($number.ToCharArray().Length -le 1) { [Convert]::ToInt32($number, $base) } else { $result = 0 foreach ($character in $number.ToCharArray()) { $digit = [Convert]::ToInt32(([string]$character), $base) $result += $digit } return $result }
} </lang>
- Output:
PS C:\> Get-DigitalSum 1 1 PS C:\> Get-DigitalSum 1234 10 PS C:\> Get-DigitalSum fe 16 29 PS C:\> Get-DigitalSum f0e 16 29
PureBasic
<lang PureBasic> EnableExplicit
Procedure.i SumDigits(Number.q, Base)
If Number < 0 : Number = -Number : EndIf; convert negative numbers to positive If Base < 2 : Base = 2 : EndIf ; base can't be less than 2 Protected sum = 0 While Number > 0 sum + Number % Base Number / Base Wend ProcedureReturn sum
EndProcedure
If OpenConsole()
PrintN("The sums of the digits are:") PrintN("") PrintN("1 base 10 : " + SumDigits(1, 10)) PrintN("1234 base 10 : " + SumDigits(1234, 10)) PrintN("fe base 16 : " + SumDigits($fe, 16)) PrintN("f0e base 16 : " + SumDigits($f0e, 16)) PrintN("") PrintN("Press any key to close the console") Repeat: Delay(10) : Until Inkey() <> "" CloseConsole()
EndIf </lang>
- Output:
The sums of the digits are: 1 base 10 : 1 1234 base 10 : 10 fe base 16 : 29 f0e base 16 : 29
Python
<lang python>def toBaseX(num, base):
output = [] while num: num, rem = divmod(num, base) output.append(rem) return output
def sumDigits(num, base=10):
if base < 2: print "Error: Base must be at least 2" return return sum(toBaseX(num, base))
print sumDigits(1) print sumDigits(12345) print sumDigits(123045) print sumDigits(0xfe, 16) print sumDigits(0xf0e, 16)</lang>
- Output:
1 15 15 29 29
The following does no error checking and requires non-base 10 numbers passed as string arguments: <lang python> def sumDigits(num, base=10):
return sum([int(x, base) for x in list(str(num))])
print sumDigits(1) print sumDigits(12345) print sumDigits(123045) print sumDigits('fe', 16) print sumDigits("f0e", 16)</lang> Each digit is base converted as it's summed.
R
<lang rsplus>change.base <- function(n, base) {
ret <- integer(as.integer(logb(x=n, base=base))+1L) for (i in 1:length(ret)) { ret[i] <- n %% base n <- n %/% base } return(ret)
}
sum.digits <- function(n, base=10) {
if (base < 2) stop("base must be at least 2") return(sum(change.base(n=n, base=base)))
}
sum.digits(1) sum.digits(12345) sum.digits(123045) sum.digits(0xfe, 16) sum.digits(0xf0e, 16)</lang>
Racket
<lang Racket>#lang racket (define (sum-of-digits n base (sum 0))
(if (= n 0) sum (sum-of-digits (quotient n base) base (+ (remainder n base) sum))))
(for-each
(lambda (number-base-pair) (define number (car number-base-pair)) (define base (cadr number-base-pair)) (displayln (format "(~a)_~a = ~a" number base (sum-of-digits number base)))) '((1 10) (1234 10) (#xfe 16) (#xf0e 16)))
- outputs
- (1)_10 = 1
- (1234)_10 = 10
- (254)_16 = 29
- (3854)_16 = 29</lang>
REXX
version 1
<lang rexx> /* REXX **************************************************************
- 04.12.2012 Walter Pachl
- /
digits='0123456789ABCDEF' Do i=1 To length(digits)
d=substr(digits,i,1) value.d=i-1 End
Call test '1' Call test '1234' Call test 'FE' Call test 'F0E' Exit test:
Parse Arg number res=right(number,4) dsum=0 Do While number<> Parse Var number d +1 number dsum=dsum+value.d End Say res '->' right(dsum,2) Return</lang>
- Output:
1 -> 1 1234 -> 10 FE -> 29 F0E -> 29
version 2
This REXX version allows:
- leading signs (+ -)
- decimal points
- leading and/or trailing whitespace
- numerals may be in mixed case
- numbers may include commas (,)
- numbers may be expressed up to base 36
- numbers may be any length (size)
<lang rexx>/*REXX program sums the decimal digits of natural numbers in any base up to base 36.*/ parse arg z /*obtain optional argument from the CL.*/ if z= | z="," then z= '1 1234 fe f0e +F0E -666.00 11111112222222333333344444449'
do j=1 for words(z); _=word(z, j) /*obtain a number from the list. */ say right(sumDigs(_), 9) ' is the sum of the digits for the number ' _ end /*j*/
exit /*stick a fork in it, we're all done. */ /*──────────────────────────────────────────────────────────────────────────────────────*/ sumDigs: procedure; arg x; @=123456789ABCDEFGHIJKLMNOPQRSTUVWXYZ; $=0
do k=1 to length(x); $=$ + pos( substr(x, k, 1), @); end /*k*/ return $</lang>
output when using the default input:
1 is the sum of the digits for the number 1 10 is the sum of the digits for the number 1234 29 is the sum of the digits for the number fe 29 is the sum of the digits for the number f0e 29 is the sum of the digits for the number +F0E 18 is the sum of the digits for the number -666.00 79 is the sum of the digits for the number 11111112222222333333344444449
version 3
This REXX version is an optimized version limited to base ten integers only (for fast decomposing of a decimal number's numerals).
The function makes use of REXX's parse statement <lang rexx>/*REXX program sums the decimal digits of integers expressed in base ten. */ parse arg z /*obtain optional argument from the CL.*/ if z= | z="," then z=copies(7, 108) /*let's generate a pretty huge integer.*/ numeric digits 1 + max( length(z) ) /*enable use of gigantic numbers. */
do j=1 for words(z); _=abs(word(z, j)) /*ignore any leading sign, if present.*/ say sumDigs(_) ' is the sum of the digits for the number ' _ end /*j*/
exit /*stick a fork in it, we're all done. */ /*──────────────────────────────────────────────────────────────────────────────────────*/ sumDigs: procedure; parse arg N 1 $ 2 ? /*use first decimal digit for the sum. */
do while ?\==; parse var ? _ 2 ?; $=$+_; end /*while*/ return $</lang>
output when using the default input:
756 is the sum of the digits for the number 777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777
Ring
<lang ring> see "sum digits of 1 = " + sumDigits(1) + nl see "sum digits of 1234 = " + sumDigits(1234) + nl
func sumDigits n
sum = 0 while n > 0.5 m = floor(n / 10) digit = n - m * 10 sum = sum + digit n = m end return sum
</lang>
Ruby
<lang ruby>>> def sumDigits(num, base = 10) >> num.to_s(base).split(//).inject(0) {|z, x| z + x.to_i(base)} >> end => nil >> sumDigits(1) => 1 >> sumDigits(12345) => 15 >> sumDigits(123045) => 15 >> sumDigits(0xfe, 16) => 29 >> sumDigits(0xf0e, 16) => 29
Since v2.4
def sumDigits(num, base = 10)
num.digits(base).sum
end </lang>
Rust
Using an Iterator
This solution creates an iterator which yields the digits of a given number using a given base and then utilizes the `sum` method which is implemented automatically on iterators. <lang rust>struct DigitIter(usize, usize);
impl Iterator for DigitIter {
type Item = usize; fn next(&mut self) -> Option<Self::Item> { if self.0 == 0 { None } else { let ret = self.0 % self.1; self.0 /= self.1; Some(ret) } }
}
fn main() {
println!("{}", DigitIter(1234,10).sum::<usize>());
}</lang>
Scala
<lang scala>def sumDigits(x:BigInt, base:Int=10):BigInt=sumDigits(x.toString(base), base) def sumDigits(x:String, base:Int):BigInt = x map(_.asDigit) sum</lang> Test: <lang scala>sumDigits(0) // => 0 sumDigits(0, 2) // => 0 sumDigits(0, 16) // => 0 sumDigits("00", 2) // => 0 sumDigits("00", 10) // => 0 sumDigits("00", 16) // => 0 sumDigits(1234) // => 10 sumDigits(0xfe) // => 11 sumDigits(0xfe, 16) // => 29 sumDigits(0xf0e, 16) // => 29 sumDigits(077) // => 9 sumDigits(077, 8) // => 14 sumDigits("077", 8) // => 14 sumDigits("077", 10) // => 14 sumDigits("077", 16) // => 14 sumDigits("0xf0e", 36) // => 62 sumDigits("000999ABCXYZ", 36) // => 162 sumDigits(BigInt("12345678901234567890")) // => 90 sumDigits("12345678901234567890", 10) // => 90</lang>
Scheme
This requires taking an input number (which may be input in any supported base), and a required target base to represent the number (as numbers entered in a given base do not preserve that base internally, and we may want to use unsupported bases).
The output is the sum of the digits in the target base, displayed in base 10.
<lang scheme> (import (scheme base)
(scheme write))
- convert number to a list of digits, in desired base
(define (number->list n base)
(let loop ((res '()) (num n)) (if (< num base) (cons num res) (loop (cons (remainder num base) res) (quotient num base)))))
- return the sum of digits of n in given base
(define (sum-digits n base)
(apply + (number->list n base)))
- test cases
- -- this displays each number in its original, given-base, for comparison
- -- target-base is the base in which to consider each number represented, for summing the digits
(define (test-case n given-base target-base)
(display (string-append (number->string n given-base) " base " (number->string given-base) " has decimal value " (number->string n) " => sum of digits in base " (number->string target-base) " is " (number->string (sum-digits n target-base)))) (newline))
(test-case 1 10 10) (test-case 1234 10 10) (test-case #o1234 8 10) (test-case #xFE 16 16) (test-case #xFE 16 10) (test-case #xF0E 16 16) (test-case #b1101010101010101010101010101010101 2 2) (test-case #b1101010101010101010101010101010101 2 10) (test-case #b1101010101010101010101010101010101 2 1000) </lang>
- Output:
The final sum is always in base 10:
1 base 10 has decimal value 1 => sum of digits in base 10 is 1 1234 base 10 has decimal value 1234 => sum of digits in base 10 is 10 1234 base 8 has decimal value 668 => sum of digits in base 10 is 20 fe base 16 has decimal value 254 => sum of digits in base 16 is 29 fe base 16 has decimal value 254 => sum of digits in base 10 is 11 f0e base 16 has decimal value 3854 => sum of digits in base 16 is 29 1101010101010101010101010101010101 base 2 has decimal value 14316557653 => sum of digits in base 2 is 18 1101010101010101010101010101010101 base 2 has decimal value 14316557653 => sum of digits in base 10 is 46 1101010101010101010101010101010101 base 2 has decimal value 14316557653 => sum of digits in base 1000 is 1540
Seed7
<lang seed7>$ include "seed7_05.s7i";
const func integer: sumDigits (in var integer: num, in integer: base) is func
result var integer: sum is 0; begin while num > 0 do sum +:= num rem base; num := num div base; end while; end func;
const proc: main is func
begin writeln(sumDigits(1, 10)); writeln(sumDigits(12345, 10)); writeln(sumDigits(123045, 10)); writeln(sumDigits(123045, 50)); writeln(sumDigits(16#fe, 10)); writeln(sumDigits(16#fe, 16)); writeln(sumDigits(16#f0e, 16)); end func;</lang>
- Output:
1 15 15 104 11 29 29
Sidef
<lang ruby>func Σ(String str, base=36) {
str.chars.map{ Num(_, base) }.sum
}
<1 1234 1020304 fe f0e DEADBEEF>.each { |n|
say "Σ(#{n}) = #{Σ(n)}"
}</lang>
- Output:
Σ(1) = 1 Σ(1234) = 10 Σ(1020304) = 10 Σ(fe) = 29 Σ(f0e) = 29 Σ(DEADBEEF) = 104
Swift
Template:Https://github.com/Ch0c0late/ContestKit
<lang Swift> let number = 1234 let base = 10
println(number.toString(base: base).characters
.map { char in String(char).toInt(base: 10) } .reduce(0, combine: +))
</lang>
- Output:
10
<lang Swift> let number = 0xfe let base = 16
// Except toString which is from ContestKit everything // else used here is defined in Swift Standard Library print(number.toString(base: base).characters
.map { char in Int(String(char), radix: base)! } .reduce(0, combine: +))
</lang>
- Output:
29
Tcl
Supporting arbitrary bases makes this primarily a string operation. <lang tcl>proc sumDigits {num {base 10}} {
set total 0 foreach d [split $num ""] {
if {[string is alpha $d]} { set d [expr {[scan [string tolower $d] %c] - 87}] } elseif {![string is digit $d]} { error "bad digit: $d" } if {$d >= $base} { error "bad digit: $d" } incr total $d
} return $total
}</lang> Demonstrating: <lang tcl>puts [sumDigits 1] puts [sumDigits 12345] puts [sumDigits 123045] puts [sumDigits fe 16] puts [sumDigits f0e 16] puts [sumDigits 000999ABCXYZ 36]</lang>
- Output:
1 15 15 29 29 162
Ursa
The function: <lang ursa>def sumDigits (string val, int base) decl int ret for (decl int i) (< i (size val)) (inc i) set ret (+ ret (int val base)) end for return ret end sumDigits</lang>
Calling the function: (This could be done on a single line, but it's split up for clarity.) <lang ursa>out (sumDigits "1" 10) endl console out (sumDigits "1234" 10) endl console out (sumDigits "fe" 16) endl console out (sumDigits "f0e" 16) endl console</lang>
- Output:
1 10 29 29
Visual Basic
This version checks that only valid digits for the indicated base are passed in, exiting otherwise.
<lang vb>Function sumDigits(num As Variant, base As Long) As Long
'can handle up to base 36 Dim outp As Long Dim validNums As String, tmp As Variant, x As Long, lennum As Long 'ensure num contains only valid characters validNums = Left$("0123456789ABCDEFGHIJKLMNOPQRSTUVWXYZ", base) lennum = Len(num) For L0 = lennum To 1 Step -1 x = InStr(validNums, Mid$(num, L0, 1)) - 1 If -1 = x Then Exit Function tmp = tmp + (x * (base ^ (lennum - L0))) Next While tmp outp = outp + (tmp Mod base) tmp = tmp \ base Wend sumDigits = outp
End Function
Sub tester()
Debug.Print sumDigits(1, 10) Debug.Print sumDigits(1234, 10) Debug.Print sumDigits(&HFE, 16) Debug.Print sumDigits(&HF0E, 16) Debug.Print sumDigits("2", 2)
End Sub</lang>
- Output:
(in the debug window)
1 10 11 20 0
XPL0
<lang XPL0>code ChOut=8, CrLf=9, IntOut=11;
func SumDigits(N, Base); int N, Base, Sum; [Sum:= 0; repeat N:= N/Base;
Sum:= Sum + rem(0);
until N=0; return Sum; ];
[IntOut(0, SumDigits(1, 10)); ChOut(0, ^ );
IntOut(0, SumDigits(12345, 10)); ChOut(0, ^ ); IntOut(0, SumDigits(123045, 10)); ChOut(0, ^ ); IntOut(0, SumDigits($FE, 10)); ChOut(0, ^ ); IntOut(0, SumDigits($FE, 16)); ChOut(0, ^ ); IntOut(0, SumDigits($F0E, 16)); CrLf(0);
]</lang>
- Output:
1 15 15 11 29 29
zkl
<lang zkl>fcn sum(n,b=10){
if(b==10) n.split().sum(0); // digits to list else n.toString(b).split("").apply("toInt",b).sum(0);
}</lang> If not base 10, convert the int into a string (in the proper base, ie 0xfe-->"fe"), blow it apart into a list of digits/characters, convert each character back into a int (from the base, ie ("c"/16-->12) and add them up.
- Output:
sum(1,10); //--> 1 sum(1234,10); //--> 10 sum(0xfe,16); //--> 29 sum(0xf0e,16); //--> 29 sum(0b1101,2); //--> 3
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