Sorting algorithms/Bogosort: Difference between revisions

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=={{header|Oberon-2}}==
=={{header|Oberon-2}}==
Works with Oxford Oberon-2 Compiler.
{{Works with|Oxford Oberon-2 Compiler}}
<pre>MODULE Bogo;

<pre>
MODULE Bogo;


IMPORT Out, Random;
IMPORT Out, Random;
Line 236: Line 234:
PrintArray(a);
PrintArray(a);
Out.Ln;
Out.Ln;
END Bogo.
END Bogo.</pre>
</pre>


Init initializes the array as 1..10, then it is shuffled, and then the while loop continually shuffles until Sorted returns true.
Init initializes the array as 1..10, then it is shuffled, and then the while loop continually shuffles until Sorted returns true.


=={{header|OCaml}}==
=={{header|OCaml}}==

Revision as of 14:02, 23 October 2008

Task
Sorting algorithms/Bogosort
You are encouraged to solve this task according to the task description, using any language you may know.

Bogosort a list of numbers. Bogosort simply shuffles a collection until it is sorted. (read the article on Wikipedia)

Pseudocode:

while not InOrder(list) do Shuffle(list);

C++

The following algorithm actually works for all sequences of comparable types; restricting to lists of integers would not make the code simpler. <cpp>#include <iterator>

  1. include <algorithm>

template<typename ForwardIterator>

void bogosort(ForwardIterator begin, ForwardIterator end)

{

 typedef std::iterator_traits<ForwardIterator>::value_type value_type;
 // if we find two adjacent values where the first is greater than the second, the sequence isn't sorted.
 while (std::adjacent_find(begin, end, std::greater<value_type>()) != end)
   std::random_shuffle(begin, end);

}</cpp> Using the is_sorted function, part of the SGI STL implementation:

Works with: GCC

<cpp>#include <algorithm>

  1. include <ext/algorithm>

template<typename ForwardIterator>

void bogosort(ForwardIterator begin, ForwardIterator end)

{

 while (!__gnu_cxx::is_sorted(begin, end))
   std::random_shuffle(begin, end);

}</cpp>

D

<d>module bogosort ; import std.stdio, std.random ;

bool isSorted(T)(inout T[] a) { // test if a is already sorted

 if(a.length <= 1) return true ; // 1-elemented/empty array is defined as sorted
 for(int i = 1 ; i < a.length ; i++) if(a[i] < a[i-1]) return false ;
 return true ;

}

T[] bogosort(T)(T[] s) {

 while(!isSorted(s)) {
   for(int n = s.length ; n > 1 ; n--) { 
     int i = rand() % n ;        // random shuffling
     T tmp = s[i] ; s[i] = s[n - 1] ; s[n - 1] = tmp ;
   }
 }
 return s ;

}

void main() {

 auto b = [2,7,4,3] ;
 writefln("%s", bogosort(b)) ;
 writefln("%s", b) ;             // sort is in place
 

}</d>

Fortran

Works with: Fortran version 90 and later
MODULE BOGO
IMPLICIT NONE
CONTAINS
  FUNCTION Sorted(a)
    LOGICAL :: Sorted
    INTEGER, INTENT(IN) :: a(:)
    INTEGER :: i

    Sorted = .TRUE.  
    DO i = 1, SIZE(a)-1
      IF(a(i) > a(i+1)) THEN
        Sorted = .FALSE.
        EXIT
      END IF
    END DO
  END FUNCTION Sorted

  SUBROUTINE SHUFFLE(a)
    INTEGER, INTENT(IN OUT) :: a(:)
    INTEGER :: i, rand, temp
    REAL :: x

    DO i = SIZE(a), 1, -1
       CALL RANDOM_NUMBER(x)
       rand = INT(x * i) + 1
       temp = a(rand)
       a(rand) = a(i)
       a(i) = temp
    END DO
  END SUBROUTINE
END MODULE

PROGRAM BOGOSORT

  USE BOGO
  IMPLICIT NONE
  INTEGER :: iter = 0
  INTEGER :: array(8) = (/2, 7, 5, 3, 4, 8, 6, 1/)
  LOGICAL :: s
 
  DO
    s = Sorted(array)
    IF (s) EXIT
    CALL SHUFFLE(array)
    iter = iter + 1
  END DO
  WRITE (*,*) "Array required", iter, " shuffles to sort"
 
END PROGRAM BOGOSORT

Haskell

import System.Random
import Data.Array.IO
import Control.Monad

isSorted :: (Ord a) => [a] -> Bool
isSorted (e1:e2:r) = e1 <= e2 && isSorted (e2:r)
isSorted _         = True

-- Plagiarized from http://www.haskell.org/haskellwiki/Random_shuffle
shuffle :: [a] -> IO [a]
shuffle xs = do
        ar <- newArray n xs
        forM [1..n] $ \i -> do
            j <- randomRIO (i,n)
            vi <- readArray ar i
            vj <- readArray ar j
            writeArray ar j vi
            return vj
  where
    n = length xs
    newArray :: Int -> [a] -> IO (IOArray Int a)
    newArray n xs =  newListArray (1,n) xs

bogosort :: (Ord a) => [a] -> IO [a]
bogosort li | isSorted li = return li
            | otherwise   = shuffle li >>= bogosort

Example:

*Main> bogosort [7,5,12,1,4,2,23,18]
[1,2,4,5,7,12,18,23]

J

bogo=: 3 : 0
whilst. -. *./ 2 </\ Ry  do. Ry=. (A.~ ?@!@#) y  end. Ry
)

Java

Works with: Java version 1.5+

This implementation works for all comparable types (types with compareTo defined). <java>import java.util.Collections; import java.util.List; import java.util.Iterator;

public class Bogosort {

   private static <T extends Comparable<? super T>> boolean isSorted(List<T> list) {
       if (list.isEmpty())
           return true;
       Iterator<T> it = list.iterator();
       T last = it.next();
       while (it.hasNext()) {
           T current = it.next();
           if (last.compareTo(current) > 0)
               return false;
           last = current;
       }
       return true;
   }
   public static <T extends Comparable<? super T>> void bogoSort(List<T> list) {
       while (!isSorted(list))
           Collections.shuffle(list);
   }

}</java>

Oberon-2

MODULE Bogo;

   IMPORT Out, Random;

   VAR a: ARRAY 10 OF INTEGER;

   PROCEDURE Init;
      VAR i: INTEGER;
   BEGIN
      FOR i := 0 TO LEN(a) - 1 DO
         a[i] := i + 1;
      END;
   END Init;

   PROCEDURE Sorted(VAR a: ARRAY OF INTEGER): BOOLEAN;
      VAR i: INTEGER;
   BEGIN 
      IF LEN(a) <= 1 THEN
         RETURN TRUE;
      END;
      FOR i := 1 TO LEN(a) - 1 DO
         IF (a[i] < a[i - 1]) THEN 
            RETURN FALSE;
         END;
      END;
      RETURN TRUE;
   END Sorted;

   PROCEDURE PrintArray(VAR a: ARRAY OF INTEGER);
      VAR i: INTEGER;
   BEGIN
      FOR i := 0 TO LEN(a) - 1 DO
         Out.Int(a[i], 0);
         Out.String(" ");
      END;
   END PrintArray;

   PROCEDURE Shuffle*(VAR a: ARRAY OF INTEGER);
      VAR n, t, r: INTEGER;
   BEGIN
      FOR n := 0 TO LEN(a) - 1 DO
         r := Random.Roll(n);
         t := a[n];
         a[n] := a[r];
         a[r] := t;
      END;
   END Shuffle;

BEGIN
   Init;
   Shuffle(a);
   WHILE ~Sorted(a) DO
      Shuffle(a);
   END;
   PrintArray(a);
   Out.Ln;
END Bogo.

Init initializes the array as 1..10, then it is shuffled, and then the while loop continually shuffles until Sorted returns true.

OCaml

<ocaml> let rec is_sorted comp = function

| e1 :: e2 :: r -> comp e1 e2 <= 0 && is_sorted comp (e2 :: r)
| _             -> true

(* Fisher-Yates shuffle on lists; uses temp array *) let shuffle l =

 let ar = Array.of_list l in
   for n = Array.length ar - 1 downto 1 do
     let k = Random.int (n+1) in
     let temp = ar.(k) in (* swap ar.(k) and ar.(n) *)
       ar.(k) <- ar.(n);
       ar.(n) <- temp
   done;
   Array.to_list ar

let rec bogosort li =

 if is_sorted compare li then
   li
 else
   bogosort (shuffle li)

</ocaml> Example:

# bogosort [7;5;12;1;4;2;23;18] ;;
- : int list = [1; 2; 4; 5; 7; 12; 18; 23]

Perl

<perl>sub bogosort

{my @l = @_;
 shuffle(\@l) until in_order(@l);
 return @l;}

sub in_order

{my $last = shift(@_);
 foreach (@_)
    {$_ >= $last or return 0;
     $last = $_;}
 return 1;}

sub shuffle

  1. This uses the algorithm described at:
  2. http://en.wikipedia.org/wiki/Fisher-Yates_shuffle#The_modern_algorithm
{our @l; local *l = shift;
   # @l is now an alias of the original argument.
 for (my $n = $#l ; $n ; --$n)
    {my $k = int rand($n + 1);
     @l[$k, $n] = @l[$n, $k] if $k != $n;}}</perl>

Python

<python>import random

def bogosort(l):

   while not in_order(l):
       random.shuffle(l)
   return l

def in_order(l):

   if not l:
       return True
   last = l[0]
   for x in l[1:]:
       if x < last:
           return False
       last = x
   return True</python>

Alternative definition for in_order (Python 2.5) <python>def in_order(l):

   return not l or all( l[i] < l[i+1] for i in range(0,len(l)-1))</python>