Run-length encoding
| This page uses content from Wikipedia. The original article was at Run-length_encoding. The list of authors can be seen in the page history. As with Rosetta Code, the text of Wikipedia is available under the GNU FDL. (See links for details on variance) |
You are encouraged to solve this task according to the task description, using any language you may know.
Given a string containing uppercase characters (A-Z), compress repeated 'runs' of the same character by storing the length of that run, and provide a function to reverse the compression. The output can be anything, as long as you can recreate the input with it.
Example:
- Input:
WWWWWWWWWWWWBWWWWWWWWWWWWBBBWWWWWWWWWWWWWWWWWWWWWWWWBWWWWWWWWWWWWWW - Output:
12W1B12W3B24W1B14W
Note: the encoding step in the above example is the same as a step of the Look-and-say sequence.
Ada
<lang Ada>with Ada.Text_IO; use Ada.Text_IO; with Ada.Strings.Fixed; use Ada.Strings.Fixed; procedure Test_Run_Length_Encoding is
function Encode (Data : String) return String is
begin
if Data'Length = 0 then
return "";
else
declare
Code : constant Character := Data (Data'First);
Index : Integer := Data'First + 1;
begin
while Index <= Data'Last and then Code = Data (Index) loop
Index := Index + 1;
end loop;
declare
Prefix : constant String := Integer'Image (Index - Data'First);
begin
return Prefix (2..Prefix'Last) & Code & Encode (Data (Index..Data'Last));
end;
end;
end if;
end Encode;
function Decode (Data : String) return String is
begin
if Data'Length = 0 then
return "";
else
declare
Index : Integer := Data'First;
Count : Natural := 0;
begin
while Index < Data'Last and then Data (Index) in '0'..'9' loop
Count := Count * 10 + Character'Pos (Data (Index)) - Character'Pos ('0');
Index := Index + 1;
end loop;
if Index > Data'First then
return Count * Data (Index) & Decode (Data (Index + 1..Data'Last));
else
return Data;
end if;
end;
end if;
end Decode;
begin
Put_Line (Encode ("WWWWWWWWWWWWBWWWWWWWWWWWWBBBWWWWWWWWWWWWWWWWWWWWWWWWBWWWWWWWWWWWWWW"));
Put_Line (Decode ("12W1B12W3B24W1B14W"));
end Test_Run_Length_Encoding;</lang> Sample output:
12W1B12W3B24W1B14W WWWWWWWWWWWWBWWWWWWWWWWWWBBBWWWWWWWWWWWWWWWWWWWWWWWWBWWWWWWWWWWWWWW
AWK
It works with "textual" input. Lines containing numbers are skipped, since they can't be represented in a not ambiguous way in this implementation (e.g. "11AA" would be encoded as "212A", which would be decoded as A repeated 212 times!)
Encoding
<lang awk>BEGIN {
FS=""
} /^[^0-9]+$/ {
cp = $1; j = 0
for(i=1; i <= NF; i++) {
if ( $i == cp ) {
j++;
} else {
printf("%d%c", j, cp)
j = 1
}
cp = $i
}
printf("%d%c", j, cp)
}</lang>
Decoding
<lang awk>BEGIN {
RS="[0-9]+[^0-9]" final = "";
} {
match(RT, /([0-9]+)([^0-9])/, r)
for(i=0; i < int(r[1]); i++) {
final = final r[2]
}
} END {
print final
}</lang>
ALGOL 68
Note: The following uses iterators, eliminating the need of declaring arbitrarily large CHAR arrays for caching. <lang algol68>STRING input := "WWWWWWWWWWWWBWWWWWWWWWWWWBBBWWWWWWWWWWWWWWWWWWWWWWWWBWWWWWWWWWWWWWW"; STRING output := "12W1B12W3B24W1B14W";
MODE YIELDCHAR = PROC(CHAR)VOID; MODE GENCHAR = PROC(YIELDCHAR)VOID;
PROC gen char string = (REF STRING s, YIELDCHAR yield)VOID:
FOR i FROM LWB s TO UPB s DO yield(s[i]) OD;
CO
- Note: The following 2 lines use currying. This not supported by ELLA ALGOL 68RS #
GENCHAR input seq = gen char string(input,),
output seq = gen char string(output,);
END CO
GENCHAR
input seq = (YIELDCHAR yield)VOID: gen char string(input, yield), output seq = (YIELDCHAR yield)VOID: gen char string(output, yield);
PROC gen encode = (GENCHAR gen char, YIELDCHAR yield)VOID: (
INT count := 0; CHAR prev;
- FOR CHAR c IN # gen char( # ) DO ( #
- (CHAR c)VOID: (
IF count = 0 THEN
count := 1;
prev := c
ELIF c NE prev THEN
STRING str count := whole(count,0);
gen char string(str count, yield); count := 1;
yield(prev); prev := c
ELSE
count +:=1
FI
- OD # ));
IF count NE 0 THEN STRING str count := whole(count,0); gen char string(str count,yield); yield(prev) FI
);
STRING zero2nine = "0123456789";
PROC gen decode = (GENCHAR gen char, YIELDCHAR yield)VOID: (
INT repeat := 0;
- FOR CHAR c IN # gen char( # ) DO ( #
- (CHAR c)VOID: (
IF char in string(c, LOC INT, zero2nine) THEN
repeat := repeat*10 + ABS c - ABS "0"
ELSE
FOR i TO repeat DO yield(c) OD;
repeat := 0
FI
- OD # ))
);
- iterate through input string #
print("Encode input: ");
- FOR CHAR c IN # gen encode(input seq, # ) DO ( #
- (CHAR c)VOID:
print(c)
- OD # );
print(new line);
- iterate through output string #
print("Decode output: ");
- FOR CHAR c IN # gen decode(output seq, # ) DO ( #
- (CHAR c)VOID:
print(c)
- OD # );
print(new line)</lang> Output:
Encode input: 12W1B12W3B24W1B14W Decode output: WWWWWWWWWWWWBWWWWWWWWWWWWBBBWWWWWWWWWWWWWWWWWWWWWWWWBWWWWWWWWWWWWWW
APL
<lang APL> ∇ ret←RLL rll;count [1] count←∣2-/((1,(2≠/rll),1)×⍳1+⍴rll)~0 [2] ret←(⍕count,¨(1,2≠/rll)/rll)~' '
∇
</lang> Sample Output:
RLL 'WWWWWWWWWWWWBWWWWWWWWWWWWBBBWWWWWWWWWWWWWWWWWWWWWWWWBWWWWWWWWWWWWWW' 12W1B12W3B24W1B14W
AutoHotkey
<lang AutoHotkey>MsgBox % key := rle_encode("WWWWWWWWWWWWBWWWWWWWWWWWWBBBWWWWWWWWWWWWWWWWWWWWWWWWBWWWWWWWWWWWWWW") MsgBox % rle_decode(key)
rle_encode(message) {
StringLeft, previous, message, 1
StringRight, last, message, 1
message .= Asc(Chr(last)+1)
count = 0
Loop, Parse, message
{
If (previous == A_LoopField)
count +=1
Else
{
output .= previous . count
previous := A_LoopField
count = 1
}
}
Return output
}
rle_decode(message) {
pos = 1
While, item := RegExMatch(message, "\D", char, pos)
{
digpos := RegExMatch(message, "\d+", dig, item)
Loop, % dig
output .= char
pos := digpos
}
Return output
}</lang>
BASIC
<lang qbasic>DECLARE FUNCTION RLDecode$ (i AS STRING) DECLARE FUNCTION RLEncode$ (i AS STRING)
DIM initial AS STRING, encoded AS STRING, decoded AS STRING
INPUT "Type something: ", initial encoded = RLEncode(initial) decoded = RLDecode(encoded) PRINT initial PRINT encoded PRINT decoded
FUNCTION RLDecode$ (i AS STRING)
DIM Loop0 AS LONG, rCount AS STRING, outP AS STRING, m AS STRING
FOR Loop0 = 1 TO LEN(i)
m = MID$(i, Loop0, 1)
SELECT CASE m
CASE "0" TO "9"
rCount = rCount + m
CASE ELSE
IF LEN(rCount) THEN
outP = outP + STRING$(VAL(rCount), m)
rCount = ""
ELSE
outP = outP + m
END IF
END SELECT
NEXT
RLDecode$ = outP
END FUNCTION
FUNCTION RLEncode$ (i AS STRING)
DIM tmp1 AS STRING, tmp2 AS STRING, outP AS STRING DIM Loop0 AS LONG, rCount AS LONG
tmp1 = MID$(i, 1, 1) tmp2 = tmp1 rCount = 1
FOR Loop0 = 2 TO LEN(i)
tmp1 = MID$(i, Loop0, 1)
IF tmp1 <> tmp2 THEN
outP = outP + LTRIM$(RTRIM$(STR$(rCount))) + tmp2
tmp2 = tmp1
rCount = 1
ELSE
rCount = rCount + 1
END IF
NEXT
outP = outP + LTRIM$(RTRIM$(STR$(rCount))) outP = outP + tmp2 RLEncode$ = outP
END FUNCTION</lang>
Sample output (last one shows errors from using numbers in input string):
Type something: aaaaeeeeeeiiiioooouuy aaaaeeeeeeiiiioooouuy 4a6e4i4o2u1y aaaaeeeeeeiiiioooouuy Type something: My dog has fleas. My dog has fleas. 1M1y1 1d1o1g1 1h1a1s1 1f1l1e1a1s1. My dog has fleas. Type something: 1r 1r 111r rrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrr
C
C++
<lang cpp>#include <iostream>
- include <string>
- include <sstream>
- include <boost/regex.hpp>
- include <cstdlib>
std::string encode ( const std::string & ) ; std::string decode ( const std::string & ) ;
int main( ) {
std::string to_encode ( "WWWWWWWWWWWWBWWWWWWWWWWWWBBBWWWWWWWWWWWWWWWWWWWWWWWWBWWWWWWWWWWWWWW" ) ;
std::cout << to_encode << " encoded:" << std::endl ;
std::string encoded ( encode ( to_encode ) ) ;
std::cout << encoded << std::endl ;
std::string decoded ( decode( encoded ) ) ;
std::cout << "Decoded again:\n" ;
std::cout << decoded << std::endl ;
if ( to_encode == decoded )
std::cout << "It must have worked!\n" ;
return 0 ;
}
std::string encode( const std::string & to_encode ) {
std::string::size_type found = 0 , nextfound = 0 ;
std::ostringstream oss ;
nextfound = to_encode.find_first_not_of( to_encode[ found ] , found ) ;
while ( nextfound != std::string::npos ) {
oss << nextfound - found ;
oss << to_encode[ found ] ;
found = nextfound ;
nextfound = to_encode.find_first_not_of( to_encode[ found ] , found ) ;
}
//since we must not discard the last characters we add them at the end of the string
std::string rest ( to_encode.substr( found ) ) ;//last run of characters starts at position found
oss << rest.length( ) << to_encode[ found ] ;
return oss.str( ) ;
}
std::string decode ( const std::string & to_decode ) {
boost::regex e ( "(\\d+)(\\w)" ) ;
boost::match_results<std::string::const_iterator> matches ;
std::ostringstream oss ;
std::string::const_iterator start = to_decode.begin( ) , end = to_decode.end( ) ;
while ( boost::regex_search ( start , end , matches , e ) ) {
std::string numberstring ( matches[ 1 ].first , matches[ 1 ].second ) ;
int number = atoi( numberstring.c_str( ) ) ;
std::string character ( matches[ 2 ].first , matches[ 2 ].second ) ;
for ( int i = 0 ; i < number ; i++ )
oss << character ;
start = matches[ 2 ].second ; } return oss.str( ) ;
}</lang>
C#
This example only works if there are no digits in the string to be encoded and then decoded.
<lang csharp>
public static void Main(string[] args)
{
string input = "WWWWWWWWWWWWBWWWWWWWWWWWWBBBWWWWWWWWWWWWWWWWWWWWWWWWBWWWWWWWWWWWWWW";
Console.WriteLine(Encode(input));//Outputs: 12W1B12W3B24W1B14W
Console.WriteLine(Decode(Encode(input)));//Outputs: WWWWWWWWWWWWBWWWWWWWWWWWWBBBWWWWWWWWWWWWWWWWWWWWWWWWBWWWWWWWWWWWWWW
Console.ReadLine();
}
public static string Encode(string s)
{
StringBuilder sb = new StringBuilder();
int count = 1;
char current =s[0];
for(int i = 1; i < s.Length;i++)
{
if (current == s[i])
{
count++;
}
else
{
sb.AppendFormat("{0}{1}", count, current);
count = 1;
current = s[i];
}
}
sb.AppendFormat("{0}{1}", count, current);
return sb.ToString();
}
public static string Decode(string s)
{
string a = "";
int count = 0;
StringBuilder sb = new StringBuilder();
char current = char.MinValue;
for(int i = 0; i < s.Length; i++)
{
current = s[i];
if (char.IsDigit(current))
a += current;
else
{
count = int.Parse(a);
a = "";
for (int j = 0; j < count; j++)
sb.Append(current);
}
}
return sb.ToString();
}
</lang>
Clojure
<lang clojure> (ns compression
(:use clojure.string))
(defn compress [string]
(join (map #(str (count (first %))(second %))
(re-seq #"([A-Z])\1*" string))))
(defn extract [string] (replace string #"\d+[A-Z]"
#(let [c-data (re-seq #"\d+|[A-Z]" %)]
(join (repeat (Integer/parseInt (first c-data)) (second c-data))))))
</lang>
Common Lisp
<lang lisp>(defun group-similar (sequence &key (test 'eql))
(loop for x in (rest sequence)
with temp = (subseq sequence 0 1)
if (funcall test (first temp) x)
do (push x temp)
else
collect temp
and do (setf temp (list x))))
(defun run-length-encode (sequence)
(mapcar (lambda (group) (list (first group) (length group)))
(group-similar (coerce sequence 'list))))
(defun run-length-decode (sequence)
(reduce (lambda (s1 s2) (concatenate 'simple-string s1 s2))
(mapcar (lambda (elem)
(make-string (second elem)
:initial-element
(first elem)))
sequence)))
(run-length-encode "WWWWWWWWWWWWBWWWWWWWWWWWWBBBWWWWWWWWWWWWWWWWWWWWWWWWBWWWWWWWWWWWWWW") (run-length-decode '((#\W 12) (#\B 1) (#\W 12) (#\B 3) (#\W 24) (#\B 1)))</lang>
D
<lang d>import std.stdio; import std.string; void main() {
char[]rle = "WWWWWWWWWWWWBWWWWWWWWWWWWBBBWWWWWWWWWWWWWWWWWWWWWWWWBWWWWWWWWWWWWWW";
char[]encoded = encode(rle);
char[]decoded = decode(encoded);
writefln("\"%s\" == \"%s\", intermediary %s",rle,decoded,encoded);
assert(rle == decoded);
}
// this is essentially an exact copy of the look and say D function char[]encode(char[]input) {
char last = input[$-1];
char[]output;
int count = 0;
foreach_reverse(i;input) {
if (i == last) {
count++;
} else {
output = toString(count)~last~output;
count = 1;
last = i;
}
}
output = toString(count)~last~output;
return output;
}
char[]decode(char[]input) {
char[]i = "";
char[]ret;
foreach(letter;input) {
if (letter <= 'Z' && letter >= 'A') {
// this is the letter to be repeated
if (!i.length) throw new Exception("Can not repeat a letter without a number of repetitions");
ret ~= repeat([letter],atoi(i));
i = null;
} else if (letter <= '9' && letter >= '0') {
// this is a digit to mark the number of repetitions
i ~= letter;
} else {
throw new Exception("'"~letter~"' is not capalphanumeric");
}
}
return ret;
}</lang>
Utf String Version
D's native string is utf-encoded. This version work for utf string. This code use a Variable-length Quantity module.
<lang d>import std.stdio ; import std.conv ; import std.utf ; import std.string ;
import vlq ;
struct RLE { // for utf string
ubyte[] encoded ;
RLE encode(const string s) {
validate(s) ; // check if s is well-formed utf, throw if not
encoded.length = 0 ; // reset
if(s.length == 0) return this ; // empty string
string last ;
VLQ count ; // init value 0
for(int i = 0 ; i < s.length ;) {
auto k = s.stride(i) ;
auto ucode = cast(string)s[i..i+k] ;
if(i == 0) last = ucode ;
if(ucode == last)
count++ ;
else {
encoded ~= count.toVLQ ~ cast(ubyte[]) last ;
last = ucode ;
count = 1 ;
}
i += k ;
}
encoded ~= VLQ(count).toVLQ ~ cast(ubyte[]) last ;
return this ;
}
int opApply(int delegate(ref ulong c, ref string u) dg) {
VLQ count ;
string ucode ;
for(int i = 0 ; i < encoded.length ;) {
auto k = count.extract(encoded[i..$]) ;
i += k ;
if(i >= encoded.length)
throw new Exception("not valid encoded string") ;
k = stride(cast(string) encoded[i..$], 0) ;
if(k == 0xff) // not valid utf code point
throw new Exception("not valid encoded string") ;
ucode = cast(string) encoded[i..i+k].dup ;
dg(count.value, ucode) ;
i += k ;
}
return 0 ;
}
string toString() {
string res ;
foreach(ref i, s ; this)
if(indexOf(`0123456789#`,s) == -1)
res ~= to!string(i) ~ s ;
else
res ~= to!string(i) ~`#` ~ s ;
return res ;
}
string decode() {
string res ;
foreach(ref i, s ; this)
res ~= repeat(s, cast(uint)i) ;
return res ;
}
}
void main() {
RLE r ;
auto s = "尋尋覓覓冷冷清清淒淒慘慘戚戚\nWWWWWWWWWWWWBWWWWWWWWWWW"
"WBBBWWWWWWWWWWWWWWWWWWWWWWWWBWWWWWWWWWWWWWW\n"
"11#222##333" ;
auto f = File("display.txt", "w") ;
f.writeln(s) ;
r.encode(s) ;
f.writefln("-----\n%s\n-----\n%s", r, r.decode) ;
auto sEncoded = RLE.init.encode(s).encoded ;
assert(s == RLE(sEncoded).decode , "Not work") ;
}</lang>
output from "display.txt":
尋尋覓覓冷冷清清淒淒慘慘戚戚 WWWWWWWWWWWWBWWWWWWWWWWWWBBBWWWWWWWWWWWWWWWWWWWWWWWWBWWWWWWWWWWWWWW 11#222##333 ----- 2尋2覓2冷2清2淒2慘2戚1 12W1B12W3B24W1B14W1 2#11##3#22##3#3 ----- 尋尋覓覓冷冷清清淒淒慘慘戚戚 WWWWWWWWWWWWBWWWWWWWWWWWWBBBWWWWWWWWWWWWWWWWWWWWWWWWBWWWWWWWWWWWWWW 11#222##333
NOTE : some characters in this section use Chinese font.
Utf String Version with Regular Expression
regular expression version
This also handles number by escaping digits with #. The code look more complex. <lang d>import std.regexp ; string reEncode(string s) { // assume s valid utf string
return sub(s, `(.|[\n\r\f])\1*`,
delegate string (RegExp m) {
auto c = (search("0123456789#", m[1])) ? "#" ~ m[1] : m[1] ;
return to!string(m[0].length / m[1].length) ~ c ;
},
"g") ;
} string reDecode(string s) { // assume s valid utf string and in encoded format
return sub(s, `(\d+)(#[0123456789#]|[\n\r\f]|[^0123456789#\n\r\f]+)`,
delegate string (RegExp m) {
string c = m[2] ;
if (c.length > 1 && c[0..1] == "#")
c = c[1..$] ;
return repeat(c, to!int(m[1])) ;
},
"g") ;
}</lang>
E
<lang e>def rle(string) {
var seen := null
var count := 0
var result := []
def put() {
if (seen != null) {
result with= [count, seen]
}
}
for ch in string {
if (ch != seen) {
put()
seen := ch
count := 0
}
count += 1
}
put()
return result
}
def unrle(coded) {
var result := ""
for [count, ch] in coded {
result += E.toString(ch) * count
}
return result
}</lang>
<lang e>? rle("WWWWWWWWWWWWBWWWWWWWWWWWWBBBWWWWWWWWWWWWWWWWWWWWWWWWBWWWWWWWWWWWWWW")
- value: [[12, 'W'], [1, 'B'], [12, 'W'], [3, 'B'], [24, 'W'], [1, 'B'], [14, 'W']]
? unrle(rle("WWWWWWWWWWWWBWWWWWWWWWWWWBBBWWWWWWWWWWWWWWWWWWWWWWWWBWWWWWWWWWWWWWW"))
- value: "WWWWWWWWWWWWBWWWWWWWWWWWWBBBWWWWWWWWWWWWWWWWWWWWWWWWBWWWWWWWWWWWWWW"</lang>
Erlang
A single-threaded/process version with a simple set of unit test.
<lang erlang>-module(rle).
-export([encode/1,decode/1]).
-include_lib("eunit/include/eunit.hrl").
encode(S) ->
doEncode(string:substr(S, 2), string:substr(S, 1, 1), 1, []).
doEncode([], CurrChar, Count, R) ->
R ++ integer_to_list(Count) ++ CurrChar;
doEncode(S, CurrChar, Count, R) ->
NextChar = string:substr(S, 1, 1),
if
NextChar == CurrChar ->
doEncode(string:substr(S, 2), CurrChar, Count + 1, R);
true ->
doEncode(string:substr(S, 2), NextChar, 1,
R ++ integer_to_list(Count) ++ CurrChar)
end.
decode(S) ->
doDecode(string:substr(S, 2), string:substr(S, 1, 1), []).
doDecode([], _, R) ->
R;
doDecode(S, CurrString, R) ->
NextChar = string:substr(S, 1, 1),
IsInt = erlang:is_integer(catch(erlang:list_to_integer(NextChar))),
if
IsInt ->
doDecode(string:substr(S, 2), CurrString ++ NextChar, R);
true ->
doDecode(string:substr(S, 2), [],
R ++ string:copies(NextChar, list_to_integer(CurrString)))
end.
rle_test_() ->
PreEncoded =
"WWWWWWWWWWWWBWWWWWWWWWWWWBBBWWWWWWWWWWWWWWWWWWWWWWWWBWWWWWWWWWWWWWW",
Expected = "12W1B12W3B24W1B14W",
[
?_assert(encode(PreEncoded) =:= Expected),
?_assert(decode(Expected) =:= PreEncoded),
?_assert(decode(encode(PreEncoded)) =:= PreEncoded)
].</lang>
FALSE
<lang false>1^[^$~][$@$@=$[%%\1+\$0~]?~[@.,1\$]?%]#%\., {encode}</lang> <lang false>[0[^$$'9>'0@>|~]['0-\10*+]#]n: [n;!$~][[\$][1-\$,]#%%]#%% {decode}</lang>
Fan
<lang Fan>**
- Generates a run-length encoding for a string
class RLE {
Run[] encode(Str s)
{
runs := Run[,]
s.size.times |i|
{
ch := s[i]
if (runs.size==0 || runs.last.char != ch)
runs.add(Run(ch))
runs.last.inc
}
return runs
}
Str decode(Run[] runs)
{
buf := StrBuf()
runs.each |run|
{
run.count.times { buf.add(run.char.toChar) }
}
return buf.toStr
}
Void main()
{
echo(decode(encode(
"WWWWWWWWWWWWBWWWWWWWWWWWWBBBWWWWWWWWWWWWWWWWWWWWWWWWBWWWWWWWWWWWWWW"
))) }
}
internal class Run {
Int char
Int count := 0
new make(Int ch) { char = ch }
Void inc() { ++count }
override Str toStr() { return "${count}${char.toChar}" }
}</lang>
Forth
<lang forth>variable a
- n>a (.) tuck a @ swap move a +! ;
- >a a @ c! 1 a +! ;
- encode ( c-addr +n a -- a n' )
dup a ! -rot over c@ 1 2swap 1 /string bounds ?do over i c@ = if 1+ else n>a >a i c@ 1 then loop n>a >a a @ over - ;
- digit? [char] 0 [ char 9 1+ literal ] within ;
- decode ( c-addr +n a -- a n' )
dup a ! 0 2swap bounds ?do i c@ digit? if 10 * i c@ [char] 0 - + else a @ over i c@ fill a +! 0 then loop drop a @ over - ;</lang>
Example:
<lang forth>s" WWWWWWWWWWWWBWWWWWWWWWWWWBBBWWWWWWWWWWWWWWWWWWWWWWWWBWWWWWWWWWWWWWW" here 1000 + encode here 2000 + decode cr 3 spaces type
WWWWWWWWWWWWBWWWWWWWWWWWWBBBWWWWWWWWWWWWWWWWWWWWWWWWBWWWWWWWWWWWWWW</lang>
Fortran
<lang fortran>program RLE
implicit none
integer, parameter :: bufsize = 100 ! Sets maximum size of coded and decoded strings, adjust as necessary character(bufsize) :: teststr = "WWWWWWWWWWWWBWWWWWWWWWWWWBBBWWWWWWWWWWWWWWWWWWWWWWWWBWWWWWWWWWWWWWW" character(bufsize) :: codedstr = "", decodedstr = "" call Encode(teststr, codedstr) write(*,"(a)") trim(codedstr) call Decode(codedstr, decodedstr) write(*,"(a)") trim(decodedstr)
contains
subroutine Encode(instr, outstr)
character(*), intent(in) :: instr character(*), intent(out) :: outstr character(8) :: tempstr = "" character(26) :: validchars = "ABCDEFGHIJKLMNOPQRSTUVWXYZ" integer :: a, b, c, i
if(verify(trim(instr), validchars) /= 0) then
outstr = "Invalid input"
return
end if
outstr = ""
c = 1
a = iachar(instr(1:1))
do i = 2, len(trim(instr))
b = iachar(instr(i:i))
if(a == b) then
c = c + 1
else
write(tempstr, "(i0)") c
outstr = trim(outstr) // trim(tempstr) // achar(a)
a = b
c = 1
end if
end do
write(tempstr, "(i0)") c
outstr = trim(outstr) // trim(tempstr) // achar(b)
end subroutine
subroutine Decode(instr, outstr)
character(*), intent(in) :: instr character(*), intent(out) :: outstr character(26) :: validchars = "ABCDEFGHIJKLMNOPQRSTUVWXYZ" integer :: startn, endn, n
outstr = "" startn = 1 do while(startn < len(trim(instr))) endn = scan(instr(startn:), validchars) + startn - 1 read(instr(startn:endn-1), "(i8)") n outstr = trim(outstr) // repeat(instr(endn:endn), n) startn = endn + 1 end do
end subroutine end program</lang>
Haskell
<lang haskell>import Data.List (group)
-- Datatypes type Encoded = [(Int, Char)] -- An encoded String with form [(times, char), ...] type Decoded = String
-- Takes a decoded string and returns an encoded list of tuples rlencode :: Decoded -> Encoded rlencode = map (\g -> (length g, head g)) . group
-- Takes an encoded list of tuples and returns the associated decoded String rldecode :: Encoded -> Decoded rldecode = concatMap decodeTuple
where decodeTuple (n,c) = replicate n c
main :: IO () main = do
-- Get input
putStr "String to encode: "
input <- getLine
-- Output encoded and decoded versions of input
let encoded = rlencode input
decoded = rldecode encoded
putStrLn $ "Encoded: " ++ show encoded ++ "\nDecoded: " ++ show decoded</lang>
Icon and Unicon
Icon
<lang Icon>procedure main(arglist)
s := "WWWWWWWWWWWWBWWWWWWWWWWWWBBBWWWWWWWWWWWWWWWWWWWWWWWWBWWWWWWWWWWWWWW"
write(" s=",image(s))
write("s1=",image(s1 := rle_encode(s)))
write("s2=",image(s2 := rle_decode(s1)))
if s ~== s2 then write("Encode/Decode problem.")
else write("Encode/Decode worked.")
end
procedure rle_encode(s)
es := "" s ? while c := move(1) do es ||:= *(move(-1),tab(many(c))) || c return es
end
procedure rle_decode(es)
s := "" es ? while s ||:= Repl(tab(many(&digits)),move(1)) return s
end
procedure Repl(n, c)
return repl(c,n)
end</lang>
Sample output:
s="WWWWWWWWWWWWBWWWWWWWWWWWWBBBWWWWWWWWWWWWWWWWWWWWWWWWBWWWWWWWWWWWWWW" s1="12W1B12W3B24W1B14W" s2="WWWWWWWWWWWWBWWWWWWWWWWWWBBBWWWWWWWWWWWWWWWWWWWWWWWWBWWWWWWWWWWWWWW" Encode/Decode worked.
Unicon
This Icon solution works in Unicon.
J
Solution: <lang j>rle=: ;@(<@(":@#,{.);.1~ 1, 2 ~:/\ ]) rld=: '0123456789'&(-.~ #~ i. ".@:{ ' ' ,~ [)</lang>
Example: <lang j> rle 'WWWWWWWWWWWWBWWWWWWWWWWWWBBBWWWWWWWWWWWWWWWWWWWWWWWWBWWWWWWWWWWWWWW' 12W1B12W3B24W1B14W
rld '12W1B12W3B24W1B14W'
WWWWWWWWWWWWBWWWWWWWWWWWWBBBWWWWWWWWWWWWWWWWWWWWWWWWBWWWWWWWWWWWWWW</lang>
Java
<lang java>import java.util.regex.Matcher; import java.util.regex.Pattern; public class RunLengthEncoding {
public static String encode(String source) {
StringBuffer dest = new StringBuffer();
for (int i = 0; i < source.length(); i++) {
int runLength = 1;
while (i+1 < source.length() && source.charAt(i) == source.charAt(i+1)) {
runLength++;
i++;
}
dest.append(runLength);
dest.append(source.charAt(i));
}
return dest.toString();
}
public static String decode(String source) {
StringBuffer dest = new StringBuffer();
Pattern pattern = Pattern.compile("[0-9]+|[a-zA-Z]");
Matcher matcher = pattern.matcher(source);
while (matcher.find()) {
int number = Integer.parseInt(matcher.group());
matcher.find();
while (number-- != 0) {
dest.append(matcher.group());
}
}
return dest.toString();
}
public static void main(String[] args) {
String example = "WWWWWWWWWWWWBWWWWWWWWWWWWBBBWWWWWWWWWWWWWWWWWWWWWWWWBWWWWWWWWWWWWWW";
System.out.println(encode(example));
System.out.println(decode("1W1B1W1B1W1B1W1B1W1B1W1B1W1B"));
}
}</lang> Tests:
<lang java>import static org.junit.Assert.assertEquals;
import org.junit.Test;
public class RunLengthEncodingTest { private RLE = new RunLengthEncoding();
@Test public void encodingTest() { assertEquals("1W", RLE.encode("W")); assertEquals("4W", RLE.encode("WWWW")); assertEquals("5w4i7k3i6p5e4d2i1a", RLE.encode("wwwwwiiiikkkkkkkiiippppppeeeeeddddiia")); assertEquals("12B1N12B3N24B1N14B", RLE.encode("BBBBBBBBBBBBNBBBBBBBBBBBBNNNBBBBBBBBBBBBBBBBBBBBBBBBNBBBBBBBBBBBBBB")); assertEquals("12W1B12W3B24W1B14W", RLE.encode("WWWWWWWWWWWWBWWWWWWWWWWWWBBBWWWWWWWWWWWWWWWWWWWWWWWWBWWWWWWWWWWWWWW")); assertEquals("1W1B1W1B1W1B1W1B1W1B1W1B1W1B", RLE.encode("WBWBWBWBWBWBWB"));
}
@Test public void decodingTest() { assertEquals("W", RLE.decode("1W")); assertEquals("WWWW", RLE.decode("4W")); assertEquals("WWWWWWWWWWWWBWWWWWWWWWWWWBBBWWWWWWWWWWWWWWWWWWWWWWWWBWWWWWWWWWWWWWW", RLE.decode("12W1B12W3B24W1B14W")); assertEquals("WBWBWBWBWBWBWB", RLE.decode("1W1B1W1B1W1B1W1B1W1B1W1B1W1B")); assertEquals("WBWBWBWBWBWBWB", RLE.decode("1W1B1W1B1W1B1W1B1W1B1W1B1W1B"));
} }</lang>
JavaScript
Here's an encoding method that walks the input string character by character <lang javascript>function encode(input) {
var encoding = [];
var prev, count, i;
for (count = 1, prev = input[0], i = 1; i < input.length; i++) {
if (input[i] != prev) {
encoding.push([count, prev]);
count = 1;
prev = input[i];
}
else
count ++;
}
encoding.push([count, prev]);
return encoding;
}</lang>
Here's an encoding method that uses a regular expression to grab the character runs (
for the forEach method)
<lang javascript>function encode_re(input) {
var encoding = [];
input.match(/(.)\1*/g).forEach(function(substr){ encoding.push([substr.length, substr[0]]) });
return encoding;
}</lang>
And to decode (see Repeating a string) <lang javascript>function decode(encoded) {
var output = "";
encoded.forEach(function(pair){ output += new Array(1+pair[0]).join(pair[1]) })
return output;
}</lang>
Logo
<lang logo>to encode :str [:out "||] [:count 0] [:last first :str]
if empty? :str [output (word :out :count :last)] if equal? first :str :last [output (encode bf :str :out :count+1 :last)] output (encode bf :str (word :out :count :last) 1 first :str)
end
to reps :n :w
output ifelse :n = 0 ["||] [word :w reps :n-1 :w]
end to decode :str [:out "||] [:count 0]
if empty? :str [output :out] if number? first :str [output (decode bf :str :out 10*:count + first :str)] output (decode bf :str word :out reps :count first :str)
end
make "foo "WWWWWWWWWWWWBWWWWWWWWWWWWBBBWWWWWWWWWWWWWWWWWWWWWWWWBWWWWWWWWWWWWWW make "rle encode :foo show equal? :foo decode :rle</lang>
Lua
<lang lua>local C, Ct, R, Cf, Cc = lpeg.C, lpeg.Ct, lpeg.R, lpeg.Cf, lpeg.Cc astable = Ct(C(1)^0)
function compress(t)
local ret = {}
for i, v in ipairs(t) do
if t[i-1] and v == t[i-1] then
ret[#ret - 1] = ret[#ret - 1] + 1
else
ret[#ret + 1] = 1
ret[#ret + 1] = v
end
end
t = ret
return table.concat(ret)
end q = io.read() print(compress(astable:match(q)))
undo = Ct((Cf(Cc"0" * C(R"09")^1, function(a, b) return 10 * a + b end) * C(R"AZ"))^0)
function decompress(s)
t = undo:match(s)
local ret = ""
for i = 1, #t - 1, 2 do
for _ = 1, t[i] do
ret = ret .. t[i+1]
end
end
return ret
end</lang>
Mathematica
Custom functions using Map, Apply, pure functions, replacing using pattern matching, delayed rules and other functions: <lang Mathematica>RunLengthEncode[input_String]:=StringJoin@@Sequence@@@({ToString @Length[#],First[#]}&/@Split[Characters[input]]) RunLengthDecode[input_String]:=StringJoin@@ConstantArray@@@Reverse/@Partition[(Characters[input]/.(ToString[#]->#&/@Range[0,9]))//.{x___,i_Integer,j_Integer,y___}:>{x,10i+j,y},2]</lang> Example: <lang Mathematica>mystring="WWWWWWWWWWWWBWWWWWWWWWWWWBBBWWWWWWWWWWWWWWWWWWWWWWWWBWWWWWWWWWWWWWW"; RunLengthEncode[mystring] RunLengthDecode[%] %==mystring</lang> gives back: <lang Mathematica>12W1B12W3B24W1B14W WWWWWWWWWWWWBWWWWWWWWWWWWBBBWWWWWWWWWWWWWWWWWWWWWWWWBWWWWWWWWWWWWWW True</lang>
MMIX
<lang mmix> LOC Data_Segment GREG @ Buf OCTA 0,0,0,0 integer print buffer Char BYTE 0,0 single char print buffer task BYTE "WWWWWWWWWWWWBWWWWWWWWWWWWBBBWWWWWW" BYTE "WWWWWWWWWWWWWWWWWWBWWWWWWWWWWWWWW",0 len GREG @-1-task
// task should become this tEnc BYTE "12W1B12W3B24W1B14W",0
GREG @ // tuple array for encoding purposes // each tuple is a tetra (4 bytes long or 2 wydes long) // (c,l) in which c is a char and l = number of chars c // high wyde of the tetra contains the char // low wyde .. .. .. contains the length RLE TETRA 0
LOC #100 locate program GREG @ // print number to stdout // destroys input arg $3 ! Prt64 LDA $255,Buf+23 points to LSD // do 2H DIV $3,$3,10 (N,R) = divmod (N,10) GET $13,rR get remainder INCL $13,'0' convert to ascii STBU $13,$255 store ascii digit BZ $3,3F SUB $255,$255,1 move pointer down JMP 2B While N !=0 3H TRAP 0,Fputs,StdOut print number to standard out GO $127,$127,0 return
GREG @ // print char to stdout PChar LDA $255,Char STBU $4,$255 TRAP 0,Fputs,StdOut GO $127,$127,0
GREG @ // encode routine // $0 string pointer // $1 index var // $2 pointer to tuple array // $11 temp var tuple Encode SET $1,0 initialize index = 0 SET $11,0 postion in string = 0 LDBU $3,$0,$1 get first char ADDU $6,$3,0 remember it
do
1H INCL $1,1 repeat incr index LDBU $3,$0,$1 get a char BZ $3,2F if EOS then finish CMP $7,$3,$6 PBZ $7,1B while new == old XOR $4,$4,$4 new tuple ADDU $4,$6,0 SLU $4,$4,16 old char to tuple -> (c,_) SUB $7,$1,$11 length = index - previous position ADDU $11,$1,0 incr position OR $4,$4,$7 length l to tuple -> (c,l) STT $4,$2 put tuple in array ADDU $6,$3,0 remember new char INCL $2,4 incr 'tetra' pointer JMP 1B loop 2H XOR $4,$4,$4 put last tuple in array ADDU $4,$6,0 SLU $4,$4,16 SUB $7,$1,$11 ADDU $11,$1,0 OR $4,$4,$7 STT $4,$2 GO $127,$127,0 return
GREG @ Main LDA $0,task pointer uncompressed string LDA $2,RLE pointer tuple array GO $127,Encode encode string LDA $2,RLE points to start tuples SET $5,#ffff mask for extracting length 1H LDTU $3,$2 while not End of Array BZ $3,2F SRU $4,$3,16 char = (c,_) AND $3,$3,$5 length = (_,l) GO $127,Prt64 print length GO $127,PChar print char INCL $2,4 incr tuple pointer JMP 1B wend 2H SET $4,#a print NL GO $127,PChar
// decode using the RLE tuples LDA $2,RLE pointer tuple array SET $5,#ffff mask 1H LDTU $3,$2 while not End of Array BZ $3,2F SRU $4,$3,16 char = (c,_) AND $3,$3,$5 length = (_,l) // for (i=0;i<length;i++) { 3H GO $127,PChar print a char SUB $3,$3,1 PBNZ $3,3B INCL $2,4 JMP 1B } 2H SET $4,#a print NL GO $127,PChar TRAP 0,Halt,0 EXIT</lang> Example run encode --> decode:
~/MIX/MMIX/Rosetta> mmix rle 12W1B12W3B24W1B14W WWWWWWWWWWWWBWWWWWWWWWWWWBBBWWWWWWWWWWWWWWWWWWWWWWWWBWWWWWWWWWWWWWW
Objective-C
See Run-length encoding/Objective-C
OCaml
<lang ocaml>let encode str =
let len = String.length str in
let rec aux i acc =
if i >= len then List.rev acc
else
let c1 = str.[i] in
let rec aux2 j =
if j >= len then (c1, j-i)
else
let c2 = str.[j] in
if c1 = c2
then aux2 (j+1)
else (c1, j-i)
in
let (c,n) as t = aux2 (i+1) in
aux (i+n) (t::acc)
in
aux 0 []
let decode lst =
let l = List.map (fun (c,n) -> String.make n c) lst in (String.concat "" l)</lang>
<lang ocaml>let () =
let e = encode "aaaaahhhhhhmmmmmmmuiiiiiiiaaaaaa" in
List.iter (fun (c,n) ->
Printf.printf " (%c, %d);\n" c n;
) e;
print_endline (decode [('a', 5); ('h', 6); ('m', 7); ('u', 1); ('i', 7); ('a', 6)]);
- </lang>
- Using regular expressions
<lang ocaml>#load "str.cma";;
open Str
let encode =
global_substitute (Str.regexp "\\(.\\)\\1*")
(fun s -> string_of_int (String.length (matched_string s)) ^
matched_group 1 s)
let decode =
global_substitute (Str.regexp "\\([0-9]+\\)\\([^0-9]\\)")
(fun s -> String.make (int_of_string (matched_group 1 s))
(matched_group 2 s).[0])
let () =
print_endline (encode "WWWWWWWWWWWWBWWWWWWWWWWWWBBBWWWWWWWWWWWWWWWWWWWWWWWWBWWWWWWWWWWWWWW"); print_endline (decode "12W1B12W3B24W1B14W");</lang>
Oz
<lang oz>declare
fun {RLEncode Xs}
for G in {Group Xs} collect:C do
{C {Length G}#G.1}
end end
fun {RLDecode Xs}
for C#Y in Xs append:Ap do
{Ap {Replicate Y C}}
end end
%% Helpers
%% e.g. "1122" -> ["11" "22"]
fun {Group Xs}
case Xs of nil then nil
[] X|Xr then
Ys Zs
{List.takeDropWhile Xr fun {$ W} W==X end ?Ys ?Zs}
in
(X|Ys) | {Group Zs}
end
end
%% e.g. 3,4 -> [3 3 3 3]
fun {Replicate X N}
case N of 0 then nil
else X|{Replicate X N-1}
end
end
Data = "WWWWWWWWWWWWBWWWWWWWWWWWWBBBWWWWWWWWWWWWWWWWWWWWWWWWBWWWWWWWWWWWWWW"
Enc = {RLEncode Data}
in
{System.showInfo Data}
{Show Enc}
{System.showInfo {RLDecode Enc}}</lang>
PARI/GP
This is only a partial solution; decode has not been written yet.
<lang parigp>encode(string)={ my(number=1,string=eval(Vec(Str(string))),Letter=string[1]);
for(x=2,#string,
if(string[x]==Letter,
number+=1,
print1("("number")"Letter);
Letter=string[x];
number=0)
);
}</lang>
Perl
<lang perl>sub encode
{my $str = shift;
$str =~ s {(.)(\1*)} {(length($2) + 1) . $1 . ';'}gse;
return $str;}
sub decode
{my $str = shift;
$str =~ s {(\d+)(.);} {$2 x $1}gse;
return $str;}</lang>
The following modified versions of the previous one, encode/decode a bytes sequence in a way compatible with the functions of the C version.
<lang perl>sub encode
{my $str = shift;
$str =~ s {(.)(\1{0,254})} {pack("C",(length($2) + 1)) . $1 }gse;
return $str;}
sub decode {
my @str = split //, shift;
my $r = "";
foreach my $i (0 .. scalar(@str)/2-1) {
$r .= $str[2*$i + 1] x unpack("C", $str[2*$i]);
}
return $r;
}</lang>
Perl 6
This currently depend on a workaround to pass the match object into the replacement closure as an explicit argument. This is supposed to happen automatically.
Note also that Perl 6 regexes don't care about unquoted whitespace, and that backrefs count from 0, not from 1.
<lang perl6>sub encode($str) { $str.subst(/(.) $0*/, -> $/ { $/.chars ~ $0 ~ ' ' }, :g); }
sub decode($str) { $str.subst(/(\d+) (.) ' '/, -> $/ {$1 x $0}, :g); }
my $e = encode('WWWWWWWWWWWWBWWWWWWWWWWWWBBBWWWWWWWWWWWWWWWWWWWWWWWWBWWWWWWWWWWWWWW'); say $e; say decode($e);</lang>
Output:
12W 1B 12W 3B 24W 1B 14W WWWWWWWWWWWWBWWWWWWWWWWWWBBBWWWWWWWWWWWWWWWWWWWWWWWWBWWWWWWWWWWWWWW
PHP
<lang php><?php function encode($str) {
return preg_replace('/(.)\1*/e', 'strlen($0) . $1', $str);
}
function decode($str) {
return preg_replace('/(\d+)(\D)/e', 'str_repeat($2, $1)', $str);
}
echo encode('WWWWWWWWWWWWBWWWWWWWWWWWWBBBWWWWWWWWWWWWWWWWWWWWWWWWBWWWWWWWWWWWWWW'), "\n"; echo decode('12W1B12W3B24W1B14W'), "\n"; ?></lang>
PicoLisp
<lang PicoLisp>(de encode (Str)
(pack
(make
(for (Lst (chop Str) Lst)
(let (N 1 C)
(while (= (setq C (pop 'Lst)) (car Lst))
(inc 'N) )
(link N C) ) ) ) ) )
(de decode (Str)
(pack
(make
(let N 0
(for C (chop Str)
(if (>= "9" C "0")
(setq N (+ (format C) (* 10 N)))
(do N (link C))
(zero N) ) ) ) ) ) )
(and
(prinl "Data: " "WWWWWWWWWWWWBWWWWWWWWWWWWBBBWWWWWWWWWWWWWWWWWWWWWWWWBWWWWWWWWWWWWWW") (prinl "Encoded: " (encode @)) (prinl "Decoded: " (decode @)) )</lang>
Output:
Data: WWWWWWWWWWWWBWWWWWWWWWWWWBBBWWWWWWWWWWWWWWWWWWWWWWWWBWWWWWWWWWWWWWW Encoded: 12W1B12W3B24W1B14W Decoded: WWWWWWWWWWWWBWWWWWWWWWWWWBBBWWWWWWWWWWWWWWWWWWWWWWWWBWWWWWWWWWWWWWW
PL/I
<lang PL/I> declare (c1, c2) character (1); declare run_length fixed binary; declare input file;
open file (input) title ('/RLE.DAT,type(text),recsize(20000)'); on endfile (input) go to epilog;
get file (input) edit (c1) (a(1)); run_length = 1; do forever;
get file (input) edit (c2) (a(1));
if c1 = c2 then
run_length = run_length + 1;
else
do; put edit (trim(run_length), c1) (a); run_length=1; end;
c1 = c2;
end; epilog:
put edit (trim(run_length), c1) (a); put skip;
/* The reverse of the above operation: */
declare c character (1);
declare i fixed binary;
declare new file;
open file (new) title ('/NEW.DAT,type(text),recsize(20000)'); on endfile (new) stop; do forever;
run_length = 0;
do forever;
get file (new) edit (c) (a(1));
if index('0123456789', c) = 0 then leave;
run_length = run_length*10 + c;
end;
put edit ((c do i = 1 to run_length)) (a);
end; </lang>
PowerBASIC
This version can handle any arbitrary string that doesn't contain numbers (not just letters). (A flag value could be added which would allow the inclusion of any character, but such a flag isn't in this example.)
<lang powerbasic>FUNCTION RLDecode (i AS STRING) AS STRING
DIM Loop0 AS LONG, rCount AS STRING, outP AS STRING, m AS STRING
FOR Loop0 = 1 TO LEN(i)
m = MID$(i, Loop0, 1)
SELECT CASE m
CASE "0" TO "9"
rCount = rCount & m
CASE ELSE
IF LEN(rCount) THEN
outP = outP & STRING$(VAL(rCount), m)
rCount=""
ELSE
outP = outP & m
END IF
END SELECT
NEXT
FUNCTION = outP
END FUNCTION
FUNCTION RLEncode (i AS STRING) AS STRING
DIM tmp1 AS STRING, tmp2 AS STRING, outP AS STRING DIM Loop0 AS LONG, rCount AS LONG
tmp1 = MID$(i, 1, 1) tmp2 = tmp1 rCount = 1
FOR Loop0 = 2 TO LEN(i)
tmp1 = MID$(i, Loop0, 1)
IF tmp1 <> tmp2 THEN
outP = outP & TRIM$(STR$(rCount)) & tmp2
tmp2 = tmp1
rCount = 1
ELSE
INCR rCount
END IF
NEXT
outP = outP & TRIM$(STR$(rCount)) outP = outP & tmp2 FUNCTION = outP
END FUNCTION
FUNCTION PBMAIN () AS LONG
DIM initial AS STRING, encoded AS STRING, decoded AS STRING
initial = INPUTBOX$("Type something.")
encoded = RLEncode(initial)
decoded = RLDecode(encoded)
'in PB/Win, "?" = MSGBOX; in PB/DOS & PB/CC. "?" = PRINT
? initial & $CRLF & encoded & $CRLF & decoded
END FUNCTION</lang>
Outputs are similar to those in BASIC, above.
PowerShell
<lang powershell>function Compress-RLE ($s) {
$re = [regex] '(.)\1*'
$ret = ""
foreach ($m in $re.Matches($s)) {
$ret += $m.Length
$ret += $m.Value[0]
}
return $ret
}
function Expand-RLE ($s) {
$re = [regex] '(\d+)(.)'
$ret = ""
foreach ($m in $re.Matches($s)) {
$ret += [string] $m.Groups[2] * [int] [string] $m.Groups[1]
}
return $ret
}</lang> Output:
PS> Compress-RLE "WWWWWWWWWWWWBWWWWWWWWWWWWBBBWWWWWWWWWWWWWWWWWWWWWWWWBWWWWWWWWWWWWWW" 12W1B12W3B24W1B14W PS> Expand-RLE "12W1B12W3B24W1B14W" WWWWWWWWWWWWBWWWWWWWWWWWWBBBWWWWWWWWWWWWWWWWWWWWWWWWBWWWWWWWWWWWWWW
PureBasic
with some optimations to use pointers instead of string functions. According to the task description it works with uppercase A - Z. In this implementation it also functions with all characters that are non-digits and whose value is non-zero.
<lang PureBasic>Procedure.s RLDecode(toDecode.s)
Protected.s repCount, output, currChar, tmp Protected *c.Character = @toDecode
While *c\c <> #Null
currChar = Chr(*c\c)
Select *c\c
Case '0' To '9'
repCount + currChar
Default
If repCount
tmp = Space(Val(repCount))
ReplaceString(tmp, " ", currChar, #PB_String_InPlace)
output + tmp
repCount = ""
Else
output + currChar
EndIf
EndSelect
*c + SizeOf(Character)
Wend
ProcedureReturn output
EndProcedure
Procedure.s RLEncode(toEncode.s)
Protected.s currChar, prevChar, output Protected repCount Protected *c.Character = @toEncode
prevChar = Chr(*c\c) repCount = 1
*c + SizeOf(Character)
While *c\c <> #Null
currChar = Chr(*c\c)
If currChar <> prevChar
output + Str(repCount) + prevChar
prevChar = currChar
repCount = 1
Else
repCount + 1
EndIf
*c + SizeOf(Character)
Wend
output + Str(repCount) output + prevChar ProcedureReturn output
EndProcedure
If OpenConsole()
Define initial.s, encoded.s, decoded.s
Print("Type something: ")
initial = Input()
encoded = RLEncode(initial)
decoded = RLDecode(encoded)
PrintN(initial)
PrintN(RLEncode(initial))
PrintN(RLDecode(encoded))
Print(#CRLF$ + #CRLF$ + "Press ENTER to exit")
Input()
CloseConsole()
EndIf</lang> Sample output:
Type something: WWWWWWWWWWWWBWWWWWWWWWWWWBBBWWWWWWWWWWWWWWWWWWWWWWWWBWWWWWWWWWWW WWW WWWWWWWWWWWWBWWWWWWWWWWWWBBBWWWWWWWWWWWWWWWWWWWWWWWWBWWWWWWWWWWWWWW 12W1B12W3B24W1B14W WWWWWWWWWWWWBWWWWWWWWWWWWBBBWWWWWWWWWWWWWWWWWWWWWWWWBWWWWWWWWWWWWWW
Python
<lang python>def encode(input_string):
count = 1
prev =
lst = []
for character in input_string:
if character != prev:
if prev:
entry = (prev,count)
lst.append(entry)
#print lst
count = 1
prev = character
else:
count += 1
else:
entry = (character,count)
lst.append(entry)
return lst
def decode(lst):
q = ""
for character, count in lst:
q += character * count
return q
- Method call
encode("aaaaahhhhhhmmmmmmmuiiiiiiiaaaaaa") decode([('a', 5), ('h', 6), ('m', 7), ('u', 1), ('i', 7), ('a', 6)])</lang>
Functional
<lang python>from itertools import groupby def encode(input_string):
return [(len(list(g)), k) for k,g in groupby(input_string)]
def decode(lst):
return .join(c * n for n,c in lst)
encode("aaaaahhhhhhmmmmmmmuiiiiiiiaaaaaa") decode([(5, 'a'), (6, 'h'), (7, 'm'), (1, 'u'), (7, 'i'), (6, 'a')])</lang>
By regular expression
The simplified input range of only uppercase characters allows a simple regular expression to be applied repeatedly for encoding, and another for decoding:
<lang python>from re import sub
def encode(text):
Doctest:
>>> encode('WWWWWWWWWWWWBWWWWWWWWWWWWBBBWWWWWWWWWWWWWWWWWWWWWWWWBWWWWWWWWWWWWWW')
'12W1B12W3B24W1B14W'
return sub(r'(.)\1*', lambda m: str(len(m.group(0))) + m.group(1),
text)
def decode(text):
Doctest:
>>> decode('12W1B12W3B24W1B14W')
'WWWWWWWWWWWWBWWWWWWWWWWWWBBBWWWWWWWWWWWWWWWWWWWWWWWWBWWWWWWWWWWWWWW'
return sub(r'(\d+)(\D)', lambda m: m.group(2) * int(m.group(1)),
text)
textin = "WWWWWWWWWWWWBWWWWWWWWWWWWBBBWWWWWWWWWWWWWWWWWWWWWWWWBWWWWWWWWWWWWWW" assert decode(encode(textin)) == textin</lang>
R
R has a built-in function, rle, for run length encoding. This modification allows input and output in the forms specified above. <lang R>runlengthencoding <- function(x) {
splitx <- unlist(strsplit(input, "")) rlex <- rle(splitx) paste(with(rlex, as.vector(rbind(lengths, values))), collapse="")
}
input <- "WWWWWWWWWWWWBWWWWWWWWWWWWBBBWWWWWWWWWWWWWWWWWWWWWWWWBWWWWWWWWWWWWWW" runlengthencoding(input)</lang> Similarly, inverse.rle provides decompression after a run length encoding. <lang R>inverserunlengthencoding <- function(x) {
lengths <- as.numeric(unlist(strsplit(output, "alpha:"))) values <- unlist(strsplit(output, "digit:")) values <- values[values != ""] uncompressed <- inverse.rle(list(lengths=lengths, values=values)) paste(uncompressed, collapse="")
}
output <- "12W1B12W3B24W1B14W" inverserunlengthencoding(output)</lang>
Ruby
<lang ruby>def encode(string)
string.scan(/(.)(\1*)/).collect do |char, repeat| [char, 1 + repeat.length] end
end
def decode(encoding)
encoding.collect { |char, length| char * length }.join
end
orig = "WWWWWWWWWWWWBWWWWWWWWWWWWBBBWWWWWWWWWWWWWWWWWWWWWWWWBWWWWWWWWWWWWWW" enc = encode(orig) # => [["W", 12], ["B", 1], ["W", 12], ["B", 3], ["W", 24], ["B", 1], ["W", 14]] dec = decode(enc) puts "success!" if dec == orig</lang>
This usage also seems to be idiomatic, and perhaps less cryptic: <lang ruby>def encode(string)
encoding = [] for char, repeat in string.scan(/(.)(\1*)/) encoding << [char, 1 + repeat.length] end encoding
end
def decode(encoding)
decoding = "" for char, length in encoding decoding << char * length end decoding
end</lang>
By regular expression
The simplified input range of only uppercase characters allows a simple regular expression to be applied repeatedly for encoding, and another for decoding:
<lang ruby>def encode(str)
str.gsub(/(.)\1*/) {$&.length.to_s + $1}
end
def decode(str)
str.gsub(/(\d+)(\D)/) {$2 * $1.to_i}
end
encode('WWWWWWWWWWWWBWWWWWWWWWWWWBBBWWWWWWWWWWWWWWWWWWWWWWWWBWWWWWWWWWWWWWW') #=> "12W1B12W3B24W1B14W" decode('12W1B12W3B24W1B14W') #=> "WWWWWWWWWWWWBWWWWWWWWWWWWBBBWWWWWWWWWWWWWWWWWWWWWWWWBWWWWWWWWWWWWWW"</lang>
Scala
Care is taken to use StringBuilder for performance reasons.
<lang scala>def encode(s: String) = (1 until s.size).foldLeft((1, s(0), new StringBuilder)) {
case ((len, c, sb), index) if c != s(index) => sb.append(len); sb.append(c); (1, s(index), sb) case ((len, c, sb), _) => (len + 1, c, sb)
} match {
case (len, c, sb) => sb.append(len); sb.append(c); sb.toString
}
def decode(s: String) = {
val sb = new StringBuilder val Code = """(\d+)([A-Z])""".r for (Code(len, c) <- Code findAllIn s) sb.append(c * len.toInt) sb.toString
}</lang>
A simpler (?) encoder: <lang scala>def encode(s:String) = {
s.foldLeft((0,s(0),""))( (t,c) => t match {case (i,p,s) => if (p==c) (i+1,p,s) else (1,c,s+i+p)})
match {case (i,p,s) => s+i+p}
}</lang>
To make it faster (it's also faster than the longer implementation above) just replace "" with new StringBuilder and s+i+p with {s.append(i);s.append(p)}
Seed7
<lang seed7>$ include "seed7_05.s7i";
include "scanstri.s7i";
const func string: letterRleEncode (in string: data) is func
result
var string: result is "";
local
var char: code is ' ';
var integer: index is 1;
begin
if length(data) <> 0 then
code := data[1];
repeat
incr(index);
until index > length(data) or code <> data[index];
result := str(pred(index)) & str(code) & letterRleEncode(data[index ..]);
end if;
end func;
const func string: letterRleDecode (in var string: data) is func
result
var string: result is "";
local
var integer: count is 0;
begin
if length(data) <> 0 then
count := integer parse getDigits(data);
result := data[1 len 1] mult count & letterRleDecode(data[2 ..]);
end if;
end func;
const proc: main is func
begin
writeln(letterRleEncode("WWWWWWWWWWWWBWWWWWWWWWWWWBBBWWWWWWWWWWWWWWWWWWWWWWWWBWWWWWWWWWWWWWW"));
writeln(letterRleDecode("12W1B12W3B24W1B14W"));
end func;</lang>
Smalltalk
See Run-length encoding/Smalltalk
SNOBOL4
<lang SNOBOL4>* # Encode RLE
define('rle(str)c,n') :(rle_end)
rle str len(1) . c :f(return)
str span(c) @n =
rle = rle n c :(rle)
rle_end
- # Decode RLE
define('elr(str)c,n') :(elr_end)
elr str span('0123456789') . n len(1) . c = :f(return)
elr = elr dupl(c,n) :(elr)
elr_end
- # Test and display
str = 'WWWWWWWWWWWWBWWWWWWWWWWWWBBBWWWWWWWWWWWWWWWWWWWWWWWWBWWWWWWWWWWWWWW'
output = str;
str = rle(str); output = str
str = elr(str); output = str
end</lang>
Output:
WWWWWWWWWWWWBWWWWWWWWWWWWBBBWWWWWWWWWWWWWWWWWWWWWWWWBWWWWWWWWWWWWWW 12W1B12W3B24W1B14W WWWWWWWWWWWWBWWWWWWWWWWWWBBBWWWWWWWWWWWWWWWWWWWWWWWWBWWWWWWWWWWWWWW
Tcl
The encoding is an even-length list with elements {count char ...} <lang tcl>proc encode {string} {
set encoding {}
# use a regular expression to match runs of one character
foreach {run -} [regexp -all -inline {(.)\1+|.} $string] {
lappend encoding [string length $run] [string index $run 0]
}
return $encoding
}
proc decode {encoding} {
foreach {count char} $encoding {
append decoded [string repeat $char $count]
}
return $decoded
}</lang>
<lang tcl>set str "WWWWWWWWWWWWBWWWWWWWWWWWWBBBWWWWWWWWWWWWWWWWWWWWWWWWBWWWWWWWWWWWWWW" set enc [encode $str] ;# ==> {12 W 1 B 12 W 3 B 24 W 1 B 14 W} set dec [decode $enc] if {$str eq $dec} {
puts "success"
}</lang>
Ursala
A standard library function, rlc, does most of the work for this task, which is a second order function taking a binary predicate that decides when consecutive items of an input list belong to the same run. <lang Ursala>#import std
- import nat
encode = (rlc ==); *= ^lhPrNCT\~&h %nP+ length
decode = (rlc ~&l-=digits); *=zyNCXS ^|DlS/~& iota+ %np
test_data = 'WWWWWWWWWWWWBWWWWWWWWWWWWBBBWWWWWWWWWWWWWWWWWWWWWWWWBWWWWWWWWWWWWWW'
- show+
example =
<
encode test_data, decode encode test_data></lang>
The output shows an encoding of the test data, and a decoding of the encoding, which matches the original test data.
12W1B12W3B24W1B14W WWWWWWWWWWWWBWWWWWWWWWWWWBBBWWWWWWWWWWWWWWWWWWWWWWWWBWWWWWWWWWWWWWW
Vedit macro language
The following example encodes/decodes an entire file. Each run is coded with two bytes. The first byte is the run length with high bit set, the second byte is the character code. ASCII characters with run length of 1 are left unchanged. Character codes above 127 are always coded with run length. Newlines are not converted (the regular expression does not count newlines). This methods supports any type of input. <lang vedit>:RL_ENCODE: BOF While (!At_EOF) {
if (At_EOL) { Line(1) Continue } // skip newlines
#1 = Cur_Char // #1 = character
Match("(.)\1*", REGEXP) // count run length
#2 = Chars_Matched // #2 = run length
if (#2 > 127) { #2 = 127 } // can be max 127
if (#2 > 1 || #1 > 127) {
Del_Char(#2)
Ins_Char(#2 | 128) // run length (high bit set)
Ins_Char(#1) // character
} else { // single ASCII char
Char // skip
}
} Return
- RL_DECODE:
BOF While (!At_EOF) {
#2 = Cur_Char
if (#2 > 127) { // is this run length?
#1 = Cur_Char(1) // #1 = character value
Del_Char(2)
Ins_Char(#1, COUNT, #2 & 127)
} else { // single ASCII char
Char
}
} Return</lang>
- WikipediaSourced
- Programming Tasks
- Compression
- Ada
- AWK
- ALGOL 68
- APL
- AutoHotkey
- BASIC
- C
- C++
- Boost
- C sharp
- Clojure
- Common Lisp
- D
- E
- Erlang
- FALSE
- Fan
- Forth
- Fortran
- Haskell
- Icon
- Unicon
- J
- Java
- JUnit
- JavaScript
- Logo
- Lua
- Mathematica
- MMIX
- Objective-C
- OCaml
- Oz
- PARI/GP
- Perl
- Perl 6
- PHP
- PicoLisp
- PL/I
- PowerBASIC
- PowerShell
- PureBasic
- Python
- R
- Ruby
- Scala
- Seed7
- Smalltalk
- SNOBOL4
- Tcl
- Ursala
- Vedit macro language