Range expansion

Range expansion
You are encouraged to solve this task according to the task description, using any language you may know.

A format for expressing an ordered list of integers is to use a comma separated list of either

• individual integers
• Or a range of integers denoted by the starting integer separated from the end integer in the range by a dash, '-'. (The range includes all integers in the interval including both endpoints)

• The range syntax is to be used only for, and for every range that expands to more than two values.

Example
The list of integers:

-6, -3, -2, -1, 0, 1, 3, 4, 5, 7, 8, 9, 10, 11, 14, 15, 17, 18, 19, 20

Is accurately expressed by the range expression:

-6,-3-1,3-5,7-11,14,15,17-20

(And vice-versa).

The task
Expand the range description:

-6,-3-1,3-5,7-11,14,15,17-20

ALGOL 68

Works with: ALGOL 68 version Revision 1 - no extensions to language used

Works with: ALGOL 68G version Any - tested with release 1.18.0-9h.tiny

Works with: ELLA ALGOL 68 version Any (with appropriate job cards) - tested with release 1.8-8d

<lang algol68>MODE YIELDINT = PROC(INT)VOID;

MODE RANGE = STRUCT(INT lwb, upb); MODE RANGEINT = UNION(RANGE, INT);

OP SIZEOF = ([]RANGEINT list)INT: (

1. determine the length of the output array #

 INT upb := LWB list - 1;
 FOR key FROM LWB list TO UPB list DO
   CASE list[key] IN
     (RANGE value): upb +:= upb OF value - lwb OF value + 1,
     (INT): upb +:= 1
   ESAC
 OD;
 upb

);

PROC gen range expand = ([]RANGEINT list, YIELDINT yield)VOID:

 FOR key FROM LWB list TO UPB list DO
   CASE list[key] IN
     (RANGE range): FOR value FROM lwb OF range TO upb OF range DO yield(value) OD,
     (INT int): yield(int)
   ESAC
 OD;

PROC range expand = ([]RANGEINT list)[]INT: (

1. Finally full the output array with a generator #

 [LWB list: LWB list + SIZEOF list - 1]INT out;
 INT upb := LWB out - 1;

1. FOR INT value IN # gen range expand(list, # ) DO #
   1. (INT value)VOID:

   out[upb +:= 1] := value

1. OD #);

 out

);

test:(

 []RANGEINT list = (-6, RANGE(-3, 1), RANGE(3, 5),  RANGE(7, 11), 14, 15, RANGE(17, 20));
 print((range expand(list), new line))

)</lang> Output:

         -6         -3         -2         -1         +0         +1         +3         +4         +5         +7         +8         +9        +10        +11        +14        +15        +17        +18        +19        +20

J

<lang j>require'strings' to=: (+ i.)/@:(0 1 + -~/\) num=: _&". normaliz=: rplc&(',-';',_';'--';'-_')@,~&',' lumps=:<@(num`([:to num;._1@,~&'-')@.('-'&e.));._1</lang>

Example: <lang j>  ; lumps normaliz '-6,-3-1,3-5,7-11,14,15,17-20' _6 _3 _2 _1 0 1 3 4 5 7 8 9 10 11 14 15 17 18 19 20</lang>

Python

<lang python>def rangeexpand(txt):

   lst = []
   for r in txt.split(','):
       if '-' in r[1:]:
           r0, r1 = r[1:].split('-', 1)
           lst += range(int(r[0] + r0), int(r1) + 1)
       else:
           lst.append(int(r))
   return lst

print(rangeexpand('-6,-3-1,3-5,7-11,14,15,17-20'))</lang>

Sample output

[-6, -3, -2, -1, 0, 1, 3, 4, 5, 7, 8, 9, 10, 11, 14, 15, 17, 18, 19, 20]