Doubly-linked list/Element insertion
You are encouraged to solve this task according to the task description, using any language you may know.
Use the link structure defined in Doubly-Linked List (element) to define a procedure for inserting a link into a doubly-linked list. Call this procedure to insert element C into a list {A,B}, between elements A and B.
This is much like inserting into a Singly-Linked List, but with added assignments so that the backwards-pointing links remain correct.
Ada
Define the procedure:
procedure Insert (Anchor : Link_Access; New_Link : Link_Access) is begin if Anchor /= Null and New_Link /= Null then New_Link.Next := Anchor.Next; New_Link.Prev := Anchor; if New_Link.Next /= Null then New_Link.Next.Prev := New_Link; end if; Anchor.Next := New_Link; end if; end Insert;
Create links and form the list.
procedure Make_List is Link_Access : A, B, C; begin A := new Link; B := new Link; C := new Link; A.Data := 1; B.Data := 2; C.Data := 2; Insert(Anchor => A, New_Link => B); -- The list is (A, B) Insert(Anchor => B, New_Link => C); -- The list is (A, B, C) end Make_List;
C
Define the function:
void insert(link* anchor, link* newlink) { newlink->next = anchor->next; newlink->prev = anchor; (newlink->next)->prev = newlink; anchor->next = newlink; }
Production code should also include checks that the passed links are valid (e.g. not null pointers). There should also be code to handle special cases, such as when *anchor is the end of the existing list (i.e. anchor->next is a null pointer).
To call the function:
Create links, and form the list:
link a, b, c; a.next = &b; a.prev = null; a.data = 1; b.next = null; b.prev = &a; b.data = 3; c.data = 2;
This list is now {a,b}, and c is separate.
Now call the function:
insert(&a, &c);
This function call changes the list from {a,b} to {a,b,c}.
Ruby
class ListNode def insertAt(ind,newEl) # where ind > 0 if ind==1 ListNode.new(newEl,self,nxt) elsif ind > 1 && nxt nxt.insertAt(ind-1,newEl) else fail "cannot insert at index #{ind}" end end end
a=ListNode.new(:a) b=ListNode.new(:b,a)
a.insertAt(1,:c)