Dining philosophers
You are encouraged to solve this task according to the task description, using any language you may know.
The dining philosophers problem illustrates non-composability of low-level synchronization primitives like semaphores. It is a modification of a problem posed by Edsger Dijkstra.
Five philosophers, Aristotle, Kant, Spinoza, Marx, and Russel (the tasks) spend their time thinking and eating spaghetti. They eat at a round table with five individual seats. For eating each philosopher needs a fork (resource). There are five forks on the table, one left and one right of each seat. When a philosopher cannot grab both forks it sits and waits. Eating takes random time, then the philosopher puts the forks down and leaves the dining room. After spending some random time thinking about the nature of the universe, he again becomes hungry, and the circle repeats itself.
It can be observed that a straightforward solution, when forks are implemented by semaphores, is exposed to deadlock. There exist two deadlock states when all five philosophers are sitting at the table holding one fork each. One deadlock state is when each philosopher has grabbed the fork left of him, and another is when each has the fork on his right.
There are many solutions of the problem, program at least one, and explain how the deadlock is prevented.
Ada
Array of mutexes
The following solution uses an array of mutexes in order to model the forks. The forks used by a philosopher compose a subset in the array. When the the philosopher seizes his forks from the subset the array object prevents deadlocking since it is an atomic operation. <ada> with Ada.Exceptions; use Ada.Exceptions; with Ada.Numerics.Float_Random; use Ada.Numerics.Float_Random; with Ada.Text_IO; use Ada.Text_IO;
with Synchronization.Generic_Mutexes_Array;
procedure Test_Dining_Philosophers is
type Philosopher is (Aristotle, Kant, Spinoza, Marx, Russel); package Fork_Arrays is new Synchronization.Generic_Mutexes_Array (Philosopher); use Fork_Arrays;
Life_Span : constant := 20; -- In his life a philosopher eats 20 times Forks : aliased Mutexes_Array; -- Forks for hungry philosophers function Left_Of (Fork : Philosopher) return Philosopher is begin if Fork = Philosopher'First then return Philosopher'Last; else return Philosopher'Pred (Fork); end if; end Left_Of;
task type Person (ID : Philosopher); task body Person is Cutlery : aliased Mutexes_Set := ID or Left_Of (ID); Dice : Generator; begin Reset (Dice); for Life_Cycle in 1..Life_Span loop Put_Line (Philosopher'Image (ID) & " is thinking"); delay Duration (Random (Dice) * 0.100); Put_Line (Philosopher'Image (ID) & " is hungry"); declare Lock : Set_Holder (Forks'Access, Cutlery'Access); begin Put_Line (Philosopher'Image (ID) & " is eating"); delay Duration (Random (Dice) * 0.100); end; end loop; Put_Line (Philosopher'Image (ID) & " is leaving"); end Person;
Ph_1 : Person (Aristotle); -- Start philosophers Ph_2 : Person (Kant); Ph_3 : Person (Spinoza); Ph_4 : Person (Marx); Ph_5 : Person (Russel);
begin
null; -- Nothing to do in the main task, just sit and behold
end Test_Dining_Philosophers; </ada>