Anagrams
You are encouraged to solve this task according to the task description, using any language you may know.
Two or more words can be composed of the same characters, but in a different order. Using the word list at http://www.puzzlers.org/pub/wordlists/unixdict.txt, find the sets of words that share the same characters that contain the most words in them.
Ada
<lang ada> with Ada.Text_IO; use Ada.Text_IO;
with Ada.Containers.Indefinite_Ordered_Maps; with Ada.Containers.Indefinite_Ordered_Sets;
procedure Words_Of_Equal_Characters is
package Set_Of_Words is new Ada.Containers.Indefinite_Ordered_Sets (String); use Ada.Containers, Set_Of_Words; package Anagrams is new Ada.Containers.Indefinite_Ordered_Maps (String, Set); use Anagrams;
File : File_Type; Result : Map; Max : Count_Type := 1;
procedure Put (Position : Anagrams.Cursor) is
First : Boolean := True;
List : Set renames Element (Position);
procedure Put (Position : Set_Of_Words.Cursor) is
begin
if First then
First := False;
else
Put (',');
end if;
Put (Element (Position));
end Put;
begin
if List.Length = Max then
Iterate (List, Put'Access);
New_Line;
end if;
end Put;
begin
Open (File, In_File, "unixdict.txt");
loop
declare
Word : constant String := Get_Line (File);
Key : String (Word'Range) := (others => Character'Last);
List : Set;
Position : Anagrams.Cursor;
begin
for I in Word'Range loop
for J in Word'Range loop
if Key (J) > Word (I) then
Key (J + 1..I) := Key (J..I - 1);
Key (J) := Word (I);
exit;
end if;
end loop;
end loop;
Position := Find (Result, Key);
if Has_Element (Position) then
List := Element (Position);
Insert (List, Word);
Replace_Element (Result, Position, List);
else
Insert (List, Word);
Include (Result, Key, List);
end if;
Max := Count_Type'Max (Max, Length (List));
end;
end loop;
exception
when End_Error =>
Iterate (Result, Put'Access);
Close (File);
end Words_Of_Equal_Characters; </lang> Sample output:
abel,able,bale,bela,elba caret,carte,cater,crate,trace angel,angle,galen,glean,lange alger,glare,lager,large,regal elan,lane,lean,lena,neal evil,levi,live,veil,vile
AutoHotkey
contributed by Laszlo on the ahk forum <lang AutoHotkey> MsgBox % anagrams("able")
anagrams(word) {
Static dict
IfEqual dict,, FileRead dict, unixdict.txt ; file in the script directory
w := sort(word)
Loop Parse, dict, `n, `r
If (w = sort(A_LoopField))
t .= A_LoopField "`n"
Return t
}
sort(word) {
a := RegExReplace(word,".","$0`n") Sort a Return a
}</lang>
C++
<lang cpp>#include <iostream>
- include <fstream>
- include <string>
- include <map>
- include <vector>
- include <algorithm>
- include <iterator>
int main() {
std::ifstream in("unixdict.txt");
std::map<std::string, std::vector<std::string> > anagrams;
std::string word;
size_t count = 0;
while (std::getline(in, word)) {
std::string key = word;
std::sort(key.begin(), key.end());
// note: the [] operator automatically inserts a new value if key does not exist
anagrams[key].push_back(word);
count = std::max(count, anagrams[key].size());
}
in.close();
for (std::map<std::string, std::vector<std::string> >::const_iterator it = anagrams.begin();
it != anagrams.end();
it++)
if (it->second.size() >= count) {
std::copy(it->second.begin(), it->second.end(),
std::ostream_iterator<std::string>(std::cout, ", "));
std::cout << std::endl;
}
return 0;
}</lang> Output:
abel, able, bale, bela, elba, caret, carte, cater, crate, trace, angel, angle, galen, glean, lange, alger, glare, lager, large, regal, elan, lane, lean, lena, neal, evil, levi, live, veil, vile,
D
D 1, using Phobos (to download the word list you need the Tango Std Lib). <lang d> import std.stdio, std.stream;
void main() {
string[][string] anags;
foreach (string w; new BufferedFile("unixdict.txt"))
anags[w.dup.sort] ~= w.dup;
int lmax;
foreach (a; anags)
lmax = lmax < a.length ? a.length : lmax;
foreach (a; anags)
if (a.length == lmax)
writefln(a);
} </lang>
E
<lang e>println("Downloading...") when (def wordText := <http://www.puzzlers.org/pub/wordlists/unixdict.txt> <- getText()) -> {
def words := wordText.split("\n")
def storage := [].asMap().diverge()
def anagramTable extends storage {
to get(key) { return storage.fetch(key, fn { storage[key] := [].diverge() }) }
}
println("Grouping...")
var largestGroupSeen := 0
for word in words {
def anagramGroup := anagramTable[word.sort()]
anagramGroup.push(word)
largestGroupSeen max= anagramGroup.size()
}
println("Selecting...")
for _ => anagramGroup ? (anagramGroup.size() == mostSeen) in anagramTable {
println(anagramGroup.snapshot())
}
}</lang>
Factor
"resource:unixdict.txt" utf8 file-lines
[ [ natural-sort >string ] keep ] { } map>assoc sort-keys
[ [ first ] compare +eq+ = ] monotonic-split
dup 0 [ length max ] reduce '[ length _ = ] filter [ values ] map .
{
{ "abel" "able" "bale" "bela" "elba" }
{ "caret" "carte" "cater" "crate" "trace" }
{ "angel" "angle" "galen" "glean" "lange" }
{ "alger" "glare" "lager" "large" "regal" }
{ "elan" "lane" "lean" "lena" "neal" }
{ "evil" "levi" "live" "veil" "vile" }
}
Groovy
This program: <lang groovy> def words = new URL('http://www.puzzlers.org/pub/wordlists/unixdict.txt').text.readLines() def groups = words.groupBy{ it.toList().sort() } def bigGroupSize = groups.collect{ it.value.size() }.max() def isBigAnagram = { it.value.size() == bigGroupSize } println groups.findAll(isBigAnagram).collect{ it.value }.collect{ it.join(' ') }.join('\n') </lang> produces this output:
abel able bale bela elba alger glare lager large regal angel angle galen glean lange caret carte cater crate trace elan lane lean lena neal evil levi live veil vile
Haskell
import Data.List
groupon f x y = f x == f y
main = do
f <- readFile "./../Puzzels/Rosetta/unixdict.txt"
let words = lines f
wix = groupBy (groupon fst) . sort $ zip (map sort words) words
mxl = maximum $ map length wix
mapM_ (print . map snd) . filter ((==mxl).length) $ wix
Sample output:
*Main> main ["abel","able","bale","bela","elba"] ["caret","carte","cater","crate","trace"] ["angel","angle","galen","glean","lange"] ["alger","glare","lager","large","regal"] ["elan","lane","lean","lena","neal"] ["evil","levi","live","veil","vile"]
J
(#~a:~:{:"1)(]/.~/:~&>)<;.2]1!:1<'unixdict.txt'
+-----+-----+-----+-----+-----+
|abel |able |bale |bela |elba |
+-----+-----+-----+-----+-----+
|alger|glare|lager|large|regal|
+-----+-----+-----+-----+-----+
|angel|angle|galen|glean|lange|
+-----+-----+-----+-----+-----+
|caret|carte|cater|crate|trace|
+-----+-----+-----+-----+-----+
|elan |lane |lean |lena |neal |
+-----+-----+-----+-----+-----+
|evil |levi |live |veil |vile |
+-----+-----+-----+-----+-----+
Java
The key to this algorithm is the sorting of the characters in each word from the dictionary. The line Arrays.sort(chars); sorts all of the letters in the word in ascending order using a built-in quicksort, so all of the words in the first group in the result end up under the key "aegln" in the anagrams map. <lang java>import java.net.*; import java.io.*; import java.util.*;
public class WordsOfEqChars {
public static void main(String[] args) throws IOException {
URL url = new URL("http://www.puzzlers.org/pub/wordlists/unixdict.txt");
InputStreamReader isr = new InputStreamReader(url.openStream());
BufferedReader reader = new BufferedReader(isr);
Map<String, Collection<String>> anagrams = new HashMap<String, Collection<String>>();
String word;
int count = 0;
while ((word = reader.readLine()) != null) {
char[] chars = word.toCharArray();
Arrays.sort(chars);
String key = new String(chars);
if (!anagrams.containsKey(key))
anagrams.put(key, new ArrayList<String>());
anagrams.get(key).add(word);
count = Math.max(count, anagrams.get(key).size());
}
reader.close();
for (Collection<String> ana : anagrams.values())
if (ana.size() >= count)
System.out.println(ana);
}
}</lang> Output:
[angel, angle, galen, glean, lange] [elan, lane, lean, lena, neal] [alger, glare, lager, large, regal] [abel, able, bale, bela, elba] [evil, levi, live, veil, vile] [caret, carte, cater, crate, trace]
Mathematica
Download the dictionary, split the lines, split the word in characters and sort them. Now sort by those words, and find sequences of equal 'letter-hashes'. Return the longest sequences: <lang Mathematica>
text={#,StringJoin@@Sort[Characters[#]]}&/@Import["http://www.puzzlers.org/pub/wordlists/unixdict.txt","Lines"];
text=SortBy[text,#2&];
splits=Split[text,#12==#22&]All,All,1;
maxlen=Max[Length/@splits];
Select[splits,Length[#]==maxlen&]
</lang> gives back: <lang Mathematica>
{{abel,able,bale,bela,elba},{caret,carte,cater,crate,trace},{angel,angle,galen,glean,lange},{alger,glare,lager,large,regal},{elan,lane,lean,lena,neal},{evil,levi,live,veil,vile}}
</lang>
Perl
<lang perl>use LWP::Simple; use List::Util qw(max);
my @words = split(' ', get('http://www.puzzlers.org/pub/wordlists/unixdict.txt')); my %anagram; foreach my $word (@words) {
push @{ $anagram{join(, sort(split(//, $word)))} }, $word;
}
my $count = max(map {scalar @$_} values %anagram); foreach my $ana (values %anagram) {
if (@$ana >= $count) {
print "@$ana\n";
}
}</lang> Output:
alger glare lager large regal abel able bale bela elba evil levi live veil vile angel angle galen glean lange elan lane lean lena neal caret carte cater crate trace
PHP
<lang php><?php $words = explode("\n", file_get_contents('http://www.puzzlers.org/pub/wordlists/unixdict.txt')); foreach ($words as $word) {
$chars = str_split($word); sort($chars); $anagram[implode($chars)][] = $word;
}
$best = max(array_map('count', $anagram)); foreach ($anagram as $ana)
if (count($ana) == $best)
print_r($ana);
?></lang>
Python
Python 2.5 shell input (IDLE) <lang python>>>> import urllib >>> from collections import defaultdict >>> words = urllib.urlopen('http://www.puzzlers.org/pub/wordlists/unixdict.txt').read().split() >>> len(words) 25104 >>> anagram = defaultdict(list) # map sorted chars to anagrams >>> for word in words: anagram[tuple(sorted(word))].append( word )
>>> count = max(len(ana) for ana in anagram.itervalues())
>>> for ana in anagram.itervalues():
if len(ana) >= count:
print ana
['angel', 'angle', 'galen', 'glean', 'lange']
['alger', 'glare', 'lager', 'large', 'regal']
['caret', 'carte', 'cater', 'crate', 'trace']
['evil', 'levi', 'live', 'veil', 'vile']
['elan', 'lane', 'lean', 'lena', 'neal']
['abel', 'able', 'bale', 'bela', 'elba']
>>> count
5
>>></lang>
sort and then group using groupby()
<lang python>>>> import urllib, itertools >>> words = urllib.urlopen('http://www.puzzlers.org/pub/wordlists/unixdict.txt').read().split() >>> len(words) 25104 >>> anagrams = [list(g) for k,g in itertools.groupby(sorted(words, key=sorted), key=sorted)]
>>> count = max(len(ana) for ana in anagrams)
>>> for ana in anagrams:
if len(ana) >= count:
print ana
['abel', 'able', 'bale', 'bela', 'elba']
['caret', 'carte', 'cater', 'crate', 'trace']
['angel', 'angle', 'galen', 'glean', 'lange']
['alger', 'glare', 'lager', 'large', 'regal']
['elan', 'lane', 'lean', 'lena', 'neal']
['evil', 'levi', 'live', 'veil', 'vile']
>>> count
5
>>></lang>
Ruby
<lang ruby>require 'open-uri'
anagram = Hash.new {|hash, key| hash[key] = []} # map sorted chars to anagrams
open('http://www.puzzlers.org/pub/wordlists/unixdict.txt') do |f|
words = f.read.split for word in words anagram[word.split().sort] << word end
end
count = anagram.values.map {|ana| ana.length}.max anagram.each_value do |ana|
if ana.length >= count p ana end
end</lang> Output:
["evil", "levi", "live", "veil", "vile"] ["abel", "able", "bale", "bela", "elba"] ["elan", "lane", "lean", "lena", "neal"] ["alger", "glare", "lager", "large", "regal"] ["angel", "angle", "galen", "glean", "lange"] ["caret", "carte", "cater", "crate", "trace"]
sort and then group using group_by
<lang ruby>require 'open-uri'
anagram = nil
open('http://www.puzzlers.org/pub/wordlists/unixdict.txt') do |f|
anagram = f.read \
.split \
.sort_by {|s| s.each_char.sort} \
.group_by {|s| s.each_char.sort}
end
count = anagram.each_value.map {|ana| ana.length}.max anagram.each_value do |ana|
if ana.length >= count p ana end
end</lang>
Tcl
<lang tcl>package require Tcl 8.5 package require http
set url http://www.puzzlers.org/pub/wordlists/unixdict.txt set response [http::geturl $url] set data [http::data $response] http::cleanup $response
set max 0 array set anagrams {}
foreach line [split $data \n] {
foreach word [split $line] {
set anagram [join [lsort [split $word ""]] ""]
lappend anagrams($anagram) $word
set max [::tcl::mathfunc::max $max [llength $anagrams($anagram)]]
}
}
foreach key [array names anagrams] {
if {[llength $anagrams($key)] == $max} {
puts $anagrams($key)
}
}</lang> Outputs:
evil levi live veil vile caret carte cater crate trace abel able bale bela elba elan lane lean lena neal angel angle galen glean lange alger glare lager large regal
Ursala
Supplying the input file on the command line during compilation makes its contents accessible as a pre-declared identifier. The algorithm is to group the words together that are made from the same unordered lists of letters, then collect the groups together that have the same number of words in them, and then show the collection associated with the highest number. <lang Ursala>
- import std
- show+
anagrams = mat` * leql$^&h eql|=@rK2tFlSS ^(~&,-<&)* unixdict_dot_txt</lang> output:
evil levi live veil vile caret carte cater crate trace alger glare lager large regal elan lane lean lena neal angel angle galen glean lange abel able bale bela elba
Vedit macro language
This implementation first sorts characters of each word using Insertion sort in subroutine SORT_LETTERS.
Then the word list is sorted using built-in Sort function.
Finally, groups of words are analyzed and largest groups are recorded.
The word list is expected to be in the same directory as the script.
<lang vedit> File_Open("|(PATH_ONLY)\unixdict.txt")
Repeat(ALL) {
Reg_Copy_Block(10, CP, EOL_Pos) // original word
Call("SORT_LETTERS") // sort letters of the word
EOL
IC(' ') Reg_Ins(10) // add the original word at eol
Line(1, ERRBREAK)
}
Sort(0, File_Size) // sort list according to anagrams
BOF Search("|F") Search(' ') // first word in the list Reg_Copy_Block(10, BOL_Pos, CP+1) // reg 10 = sorted anagram word Reg_Copy_Block(11, CP, EOL_Pos) // reg 11 = list of words in current group Reg_Empty(12) // reg 12 = list of words in largest groups Reg_Set(13, " ")
- 1 = 1 // words in this group
- 2 = 2 // words in largest group found
Repeat(ALL) {
Line(1, ERRBREAK)
if (Match(@10, ADVANCE) == 0) { // same group as previous word?
Reg_Copy_Block(11, CP-1, EOL_Pos, APPEND) // add word to this group
#1++
} else { // different anagram group
Search(" ", ERRBREAK)
if (#1 == #2) { // same size as the largest?
Reg_Set(12, @13, APPEND) // append newline
Reg_Set(12, @11, APPEND) // append word list
}
if (#1 > #2) { // new larger size of group
Reg_Set(12, @11) // replace word list
#2 = #1
}
Reg_Copy_Block(10, BOL_Pos, CP+1)
Reg_Copy_Block(11, CP, EOL_Pos) // first word of new group
#1 = 1
}
}
Buf_Quit(OK) // close word list file Buf_Switch(Buf_Free) // output results in a new edit buffer Reg_Ins(12) // display all groups of longest anagram words Return
//////////////////////////////////////////////////////////////////// // // Sort characters in current line using Insertion sort //
- SORT_LETTERS:
GP(EOL_pos) #9 = Cur_Col-1 for (#1 = 2; #1 <= #9; #1++) {
Goto_Col(#1) #8 = Cur_Char
#2 = #1
while (#2 > 1) {
#7 = Cur_Char(-1)
if (#7 <= #8) { break }
Ins_Char(#7, OVERWRITE)
#2--
Goto_Col(#2)
}
Ins_Char(#8, OVERWRITE)
} return </lang>
Output:
abel able bale bela elba caret carte cater crate trace angel angle galen glean lange alger glare lager large regal elan lane lean lena neal evil levi live veil vile
Scala
Compiler: scala (2.7.5)
<lang scala>
import scala.io.Source import scala.collection.mutable
object Anagrams{
</lang> We can start with a most superficial method - one for printing a list of Strings. This method prints a given list of Strings in a line , each separated by a "|". Each such list represents one set of anagrams <lang scala>
def printList(strLst : List[String]) {
print("|")
strLst.foreach(x => print(x + "|"))
println("")
}
</lang>
Every String has a "root", which is a String which has all the characters in it alphabetically arranged. For example, the root for the string "string" is the string "ginrst". The root for "root" is "oort". <lang scala>
def rootString(str:String):String = new String(str.trim.toCharArray.toList.sort(_<_).toArray)
</lang> We need a method that takes a string and a mutable map between the Strings and List of Strings. Given a String, we compute the root of the String and then check if the root is existing as a key in the map. If it does , we append the given string to the value mapped to that key. Otherwise, we insert the key into the map with the value as a new singleton list containing just the given String <lang scala>
def handleString(str:String,strMap:mutable.Map[String,List[String]]){
val root = rootString(str)
(strMap.get(root)) match{
case Some(lst) => strMap.update(root,str.trim::lst)
case None => strMap.update(root,List(str.trim))
}
}
</lang> Finally, we need the main method that creates an empty map, reads the contents of the file line and by line and appends the map. Then we iterate over the values of the map and prints them <lang scala>
def main(args:Array[String]){
val fileName = "unixdict.txt"
val strmap = new mutable.HashMap[String, List[String]]
Source.fromFile(fileName).getLines.foreach(x => handleString(x,strmap))
strmap.values.foreach(printList)
}
}
</lang> Sample output is given below:
|mental|mantle|mantel|lament|
|vocate|octave|avocet|
|organ|groan|argon|