N'th
Write a function/method/subroutine/... that when given an integer greater than or equal to zero returns a string of the number followed by an apostrophe then the ordinal suffix.
You are encouraged to solve this task according to the task description, using any language you may know.
- Example
Returns would include 1'st 2'nd 3'rd 11'th 111'th 1001'st 1012'th
- Task
Use your routine to show here the output for at least the following (inclusive) ranges of integer inputs:
0..25, 250..265, 1000..1025
Note: apostrophes are now optional to allow correct apostrophe-less English.
11l
<lang 11l>V _suffix = [‘th’, ‘st’, ‘nd’, ‘rd’, ‘th’, ‘th’, ‘th’, ‘th’, ‘th’, ‘th’]
F nth(n)
R ‘#.'#.’.format(n, I n % 100 <= 10 | n % 100 > 20 {:_suffix[n % 10]} E ‘th’)
L(j) (0..1000).step(250)
print_elements(Array(j.+25).map(i -> nth(i)))</lang>
- Output:
0'th 1'st 2'nd 3'rd 4'th 5'th 6'th 7'th 8'th 9'th 10'th 11'th 12'th 13'th 14'th 15'th 16'th 17'th 18'th 19'th 20'th 21'st 22'nd 23'rd 24'th 250'th 251'st 252'nd 253'rd 254'th 255'th 256'th 257'th 258'th 259'th 260'th 261'st 262'nd 263'rd 264'th 265'th 266'th 267'th 268'th 269'th 270'th 271'st 272'nd 273'rd 274'th 500'th 501'st 502'nd 503'rd 504'th 505'th 506'th 507'th 508'th 509'th 510'th 511'th 512'th 513'th 514'th 515'th 516'th 517'th 518'th 519'th 520'th 521'st 522'nd 523'rd 524'th 750'th 751'st 752'nd 753'rd 754'th 755'th 756'th 757'th 758'th 759'th 760'th 761'st 762'nd 763'rd 764'th 765'th 766'th 767'th 768'th 769'th 770'th 771'st 772'nd 773'rd 774'th 1000'th 1001'st 1002'nd 1003'rd 1004'th 1005'th 1006'th 1007'th 1008'th 1009'th 1010'th 1011'th 1012'th 1013'th 1014'th 1015'th 1016'th 1017'th 1018'th 1019'th 1020'th 1021'st 1022'nd 1023'rd 1024'th
8080 Assembly
<lang asm> org 100h jmp demo ;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;; ;; Given a 16-bit unsigned integer in HL, return a string ;; consisting of its ASCII representation plus an ordinal ;; suffix in HL. nth: lxi b,-10 ; Divisor for digit loop push h ; Push integer to stack lxi h,nthsfx ; Pointer to end of digit area xthl ; Swap digit pointer with integer nthdigit: lxi d,-1 ; Get current digit - DE holds quotient nthdiv10: inx d ; Increment quotient, dad b ; subtract 10 from integer, jc nthdiv10 ; Keep going until HL<0 mvi a,'0'+10 ; Calculate ASCII value for digit add l ; Modulus is in (H)L xthl ; Swap integer with pointer dcx h ; Point to one digit further left mov m,a ; Store the digit xthl ; Swap pointer with integer xchg ; Put quotient in HL mov a,h ; Is it zero? ora l jnz nthdigit ; If not, go calculate next digit mvi e,0 ; Default suffix is 'th'. lxi h,nthnum+3 ; Look at tens digit mov a,m cpi '1' ; Is it '1'? jz nthsetsfx ; Then it is always 'th'. inx h ; Look at zeroes digit mov a,m sui '0' ; Subtract ASCII '0' cpi 4 ; 4 or higher? jnc nthsetsfx ; Then it is always 'th'. rlc ; Otherwise, suffix is at N*2+nthord mov e,a nthsetsfx: mvi d,0 ; Look up suffix in list lxi h,nthord dad d ; Pointer to suffix in HL lxi d,nthsfx ; Pointer to space for suffix in DE mov a,m ; Get first letter of suffix stax d ; Store it in output inx h ; Increment both pointers inx d mov a,m ; Get second letter of suffix stax d ; Store it in output pop h ; Return pointer to leftmost digit ret nthord: db 'thstndrd' ; Ordinal suffixes nthnum: db '*****' ; Room for digits nthsfx: db '**$' ; Room for suffix ;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;; demo: ;; Demo code lxi h,0 ; Starting at 0... mvi b,26 ; ...print 26 numbers [0..25] call printnums lxi h,250 ; Starting at 250... mvi b,16 ; ...print 16 numbers [250..265] call printnums lxi h,1000 ; Starting at 1000... mvi b,26 ; ...print 26 numbers [1000..1025] ;; Print values from HL up to HL+B printnums: push h ; Keep number push b ; Keep counter call nth ; Get string for current HL xchg ; Put it in DE mvi c,9 ; CP/M print string call 5 mvi e,' ' ; Separate numbers with spaces mvi c,2 ; CP/M print character call 5 pop b ; Restore counter pop h ; Restore number inx h ; Increment number dcr b ; Decrement counter jnz printnums ; If not zero, print next number ret</lang>
- Output:
Line breaks added for clarity.
0th 1st 2nd 3rd 4th 5th 6th 7th 8th 9th 10th 11th 12th 13th 14th 15th 16th 17th 18th 19th 20th 21st 22nd 23rd 24th 25th 250th 251st 252nd 253rd 254th 255th 256th 257th 258th 259th 260th 261st 262nd 263rd 264th 265th 1000th 1001st 1002nd 1003rd 1004th 1005th 1006th 1007th 1008th 1009th 1010th 1011th 1012th 1013th 1014th 1015th 1016th 1017th 1018th 1019th 1020th 1021st 1022nd 1023rd 1024th 1025th
8086 Assembly
<lang asm> bits 16 cpu 8086 segment .text org 100h jmp demo ;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;; ;; Given a number in AX, return string with ordinal suffix ;; in DX. nth: mov cx,10 ; Divisor mov bx,.sfx ; Pointer to end of number .digit: xor dx,dx ; Zero DX div cx ; AX = DX:AX/10; DX=remainder add dl,'0' ; Make digit dec bx ; Back up the pointer mov [bx],dl ; Store digit and ax,ax ; Done yet? (AX=0?) jnz .digit ; If not, get next digit mov dx,bx ; Keep string pointer in DX xor bx,bx ; Default suffix is 'th'. cmp byte [.num+3],'1' ; Is the tens digit '1'? je .setsfx ; Then the suffix is 'th'. mov cl,[.num+4] ; Get the ones digit cmp cl,'4' ; Is it '4' or higher? jae .setsfx ; Then the suffix is 'th'. mov bl,cl sub bl,'0' ; Calculate offset. shl bl,1 ; [0..3]*2 + .ord .setsfx: mov ax,[bx+.ordsfx] ; Set suffix mov [.sfx],ax ret .ordsfx: db 'thstndrd' .num: db '*****' .sfx: db '**$' ;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;; ;; Print numbers. demo: mov ax,0 ; Starting at 0... mov bl,26 ; ...print 26 numbers [0..25] call printn mov ax,250 ; Starting at 250... mov bl,16 ; ...print 16 numbers [250..265] call printn mov ax,1000 ; Starting at 1000... mov bl,26 ; ...print 26 numbers [1000..1025] ;; Print BL numbers starting at AX printn: push ax ; Keep number push bx ; Keep counter call nth ; Get string for current AX mov ah,9 ; MS-DOS print string int 21h mov dl,' ' ; Separate numbers by spaces mov ah,2 ; MS-DOS print character int 21h pop bx ; Restore counter pop ax ; Restore number inc ax ; Next number dec bl ; Are we done yet? jnz printn ret</lang>
- Output:
Line breaks added for clarity.
0th 1st 2nd 3rd 4th 5th 6th 7th 8th 9th 10th 11th 12th 13th 14th 15th 16th 17th 18th 19th 20th 21st 22nd 23rd 24th 25th 250th 251st 252nd 253rd 254th 255th 256th 257th 258th 259th 260th 261st 262nd 263rd 264th 265th 1000th 1001st 1002nd 1003rd 1004th 1005th 1006th 1007th 1008th 1009th 1010th 1011th 1012th 1013th 1014th 1015th 1016th 1017th 1018th 1019th 1020th 1021st 1022nd 1023rd 1024th 1025th
Action!
<lang Action!>PROC Nth(CARD val,CHAR ARRAY s)
CHAR ARRAY sfx BYTE d
StrC(val,s) s(0)=s(0)+1 s(s(0))=
d=val MOD 100 IF d>10 AND d<14 THEN sfx="th" ELSE d=val MOD 10 IF d=1 THEN sfx="st" ELSEIF d=2 THEN sfx="nd" ELSEIF d=3 THEN sfx="rd" ELSE sfx="th" FI FI s(0)=s(0)+2 SAssign(s,sfx,s(0)-1,s(0)+1)
RETURN
PROC Main()
CARD ARRAY n=[0 250 1000] CHAR ARRAY s(10) CARD i,j
FOR i=0 TO 2
DO
FOR j=n(i) TO n(i)+25
DO
Nth(j,s)
PrintF("%S ",s)
OD
PutE() PutE()
OD
RETURN</lang>
- Output:
Screenshot from Atari 8-bit computer
0'th 1'st 2'nd 3'rd 4'th 5'th 6'th 7'th 8'th 9'th 10'th 11'th 12'th 13'th 14'th 15'th 16'th 17'th 18'th 19'th 20'th 21'st 22'nd 23'rd 24'th 25'th 250'th 251'st 252'nd 253'rd 254'th 255'th 256'th 257'th 258'th 259'th 260'th 261'st 262'nd 263'rd 264'th 265'th 266'th 267'th 268'th 269'th 270'th 271'st 272'nd 273'rd 274'th 275'th 1000'th 1001'st 1002'nd 1003'rd 1004'th 1005'th 1006'th 1007'th 1008'th 1009'th 1010'th 1011'th 1012'th 1013'th 1014'th 1015'th 1016'th 1017'th 1018'th 1019'th 1020'th 1021'st 1022'nd 1023'rd 1024'th 1025'th
Ada
<lang Ada>with Ada.Text_IO;
procedure Nth is
function Suffix(N: Natural) return String is
begin
if N mod 10 = 1 and then N mod 100 /= 11 then return "st";
elsif N mod 10 = 2 and then N mod 100 /= 12 then return "nd";
elsif N mod 10 = 3 and then N mod 100 /= 13 then return "rd";
else return "th";
end if;
end Suffix;
procedure Print_Images(From, To: Natural) is
begin
for I in From .. To loop
Ada.Text_IO.Put(Natural'Image(I) & Suffix(I));
end loop;
Ada.Text_IO.New_Line;
end Print_Images;
begin
Print_Images( 0, 25); Print_Images( 250, 265); Print_Images(1000, 1025);
end Nth;</lang>
- Output:
0th 1st 2nd 3rd 4th 5th 6th 7th 8th 9th 10th 11th 12th 13th 14th 15th 16th 17th 18th 19th 20th 21st 22nd 23rd 24th 25th 250th 251st 252nd 253rd 254th 255th 256th 257th 258th 259th 260th 261st 262nd 263rd 264th 265th 1000th 1001st 1002nd 1003rd 1004th 1005th 1006th 1007th 1008th 1009th 1010th 1011th 1012th 1013th 1014th 1015th 1016th 1017th 1018th 1019th 1020th 1021st 1022nd 1023rd 1024th 1025th
ALGOL 68
<lang algol68># PROC to suffix a number with st, nd, rd or th as appropriate # PROC nth = ( INT number )STRING: BEGIN
INT number mod 100 = number MOD 100;
- RESULT #
whole( number, 0 )
+ IF number mod 100 >= 10 AND number mod 100 <= 20
THEN
# numbers in the range 10 .. 20 always have "th" #
"th"
ELSE
# not in the range 10 .. 20, suffix is st, nd, rd or th #
# depending on the final digit #
CASE number MOD 10
IN # 1 # "st"
, # 2 # "nd"
, # 3 # "rd"
OUT "th"
ESAC
FI
END; # nth #
- PROC to test nth, displays nth for all numbers in the range from .. to #
PROC test nth = ( INT from, INT to )VOID: BEGIN
INT test count := 0;
FOR test value FROM from TO to
DO
STRING test result = nth( test value );
print( ( " "[ 1 : 8 - UPB test result ], nth( test value ) ) );
test count +:= 1;
IF test count MOD 8 = 0
THEN
print( ( newline ) )
FI
OD;
print( ( newline ) )
END; # test nth #
main: (
test nth( 0, 25 ); test nth( 250, 265 ); test nth( 1000, 1025 )
)</lang>
- Output:
0th 1st 2nd 3rd 4th 5th 6th 7th
8th 9th 10th 11th 12th 13th 14th 15th
16th 17th 18th 19th 20th 21st 22nd 23rd
24th 25th
250th 251st 252nd 253rd 254th 255th 256th 257th
258th 259th 260th 261st 262nd 263rd 264th 265th
1000th 1001st 1002nd 1003rd 1004th 1005th 1006th 1007th
1008th 1009th 1010th 1011th 1012th 1013th 1014th 1015th
1016th 1017th 1018th 1019th 1020th 1021st 1022nd 1023rd
1024th 1025th
APL
<lang APL> nth←{
sfx←4 2⍴'stndrdth' tens←(10<100|⍵)∧20>100|⍵ (⍕⍵),sfx[(4×tens)⌈(⍳3)⍳10|⍵;] }</lang>
- Output:
2 13⍴ nth¨ 0,⍳25
0th 1st 2nd 3rd 4th 5th 6th 7th 8th 9th 10th 11th 12th
13th 14th 15th 16th 17th 18th 19th 20th 21st 22nd 23rd 24th 25th
2 7⍴ nth¨ 250+0,⍳15
250th 251st 252nd 253rd 254th 255th 256th
257th 258th 259th 260th 261st 262nd 263rd
2 13⍴ nth¨ 1000+0,⍳25
1000th 1001st 1002nd 1003rd 1004th 1005th 1006th 1007th 1008th 1009th 1010th 1011th 1012th
1013th 1014th 1015th 1016th 1017th 1018th 1019th 1020th 1021st 1022nd 1023rd 1024th 1025th
AppleScript
<lang AppleScript>-- ORDINAL STRINGS -----------------------------------------------------------
-- ordinalString :: Int -> String on ordinalString(n)
(n as string) & ordinalSuffix(n)
end ordinalString
-- ordinalSuffix :: Int -> String on ordinalSuffix(n)
set modHundred to n mod 100
if (11 ≤ modHundred) and (13 ≥ modHundred) then
"th"
else
item ((n mod 10) + 1) of ¬
{"th", "st", "nd", "rd", "th", "th", "th", "th", "th", "th"}
end if
end ordinalSuffix
-- TEST ---------------------------------------------------------------------- on run
-- showOrdinals :: [Int] -> [String]
script showOrdinals
on |λ|(lstInt)
map(ordinalString, lstInt)
end |λ|
end script
map(showOrdinals, ¬
map(uncurry(enumFromTo), ¬
[[0, 25], [250, 265], [1000, 1025]]))
end run
-- GENERIC FUNCTIONS ---------------------------------------------------------
-- enumFromTo :: Int -> Int -> [Int] on enumFromTo(m, n)
if m > n then
set d to -1
else
set d to 1
end if
set lst to {}
repeat with i from m to n by d
set end of lst to i
end repeat
return lst
end enumFromTo
-- map :: (a -> b) -> [a] -> [b] on map(f, xs)
tell mReturn(f)
set lng to length of xs
set lst to {}
repeat with i from 1 to lng
set end of lst to |λ|(item i of xs, i, xs)
end repeat
return lst
end tell
end map
-- Lift 2nd class handler function into 1st class script wrapper -- mReturn :: Handler -> Script on mReturn(f)
if class of f is script then
f
else
script
property |λ| : f
end script
end if
end mReturn
-- uncurry :: Handler (a -> b -> c) -> Script |λ| ((a, b) -> c) on uncurry(f)
script
on |λ|(xy)
set {x, y} to xy
mReturn(f)'s |λ|(x, y)
end |λ|
end script
end uncurry</lang>
- Output:
{{"0th", "1st", "2nd", "3rd", "4th", "5th", "6th", "7th", "8th", "9th",
"10th", "11th", "12th", "13th", "14th", "15th", "16th", "17th", "18th",
"19th", "20th", "21st", "22nd", "23rd", "24th", "25th"},
{"250th", "251st", "252nd", "253rd", "254th", "255th", "256th", "257th",
"258th", "259th", "260th", "261st", "262nd", "263rd", "264th", "265th"},
{"1000th", "1001st", "1002nd", "1003rd", "1004th", "1005th", "1006th",
"1007th", "1008th", "1009th", "1010th", "1011th", "1012th", "1013th",
"1014th", "1015th", "1016th", "1017th", "1018th", "1019th", "1020th",
"1021st", "1022nd", "1023rd", "1024th", "1025th"}}
Applesoft BASIC
<lang ApplesoftBasic>0 OP = 1 10 FOR N = 0 TO 25 : GOSUB 100 : NEXT 20 FOR N = 250 TO 265 : GOSUB 100 : NEXT 30 FOR N = 1000 TO 1025 : GOSUB 100 : NEXT 40 END
100 GOSUB 200"NTH 110 PRINT NTH$ " "; 120 RETURN
200 M1 = N - INT(N / 10) * 10 210 M2 = N - INT(N / 100) * 100 220 NTH$ = "TH" 230 IF M1 = 1 AND M2 <> 11 THEN NTH$ = "ST" 240 IF M1 = 2 AND M2 <> 12 THEN NTH$ = "ND" 250 IF M1 = 3 AND M2 <> 13 THEN NTH$ = "RD" 260 IF NOT OP THEN NTH$ = "'" + NTH$ 270 NTH$ = STR$(N) + NTH$ 280 RETURN</lang>
- Output:
0'TH 1'ST 2'ND 3'RD 4'TH 5'TH 6'TH 7'TH 8'TH 9'TH 10'TH 11'TH 12'TH 13'TH 14'TH 15'TH 16'TH 17'TH 18'TH 19'TH 20'TH 21'ST 22'ND 23'RD 24'TH 25'TH 250'TH 251'ST 252'ND 253'RD 254'TH 255'TH 256'TH 257'TH 258'TH 259'TH 260'TH 261'ST 262'ND 263'RD 264'TH 265'TH 1000'TH 1001'ST 1002'ND 1003'RD 1004'TH 1005'TH 1006'TH 1007'TH 1008'TH 1009'TH 1010'TH 1011'TH 1012'TH 1013'TH 1014'TH 1015'TH 1016'TH 1017'TH 1018'TH 1019'TH 1020'TH 1021'ST 1022'ND 1023'RD 1024'TH 1025'TH
Arturo
<lang rebol>suffixes: ["th" "st" "nd" "rd" "th" "th" "th" "th" "th" "th"]
nth: function [n][
if? or? 100 >= n%100
20 < n%100
-> (to :string n) ++ "'" ++ suffixes\[n%10]
else -> (to :string n) ++ "'th"
]
loop range.step:250 0 1000 'j [
loop j..j+24 'i ->
prints (nth i)++" "
print ""
]</lang>
- Output:
0'th 1'st 2'nd 3'rd 4'th 5'th 6'th 7'th 8'th 9'th 10'th 11'st 12'nd 13'rd 14'th 15'th 16'th 17'th 18'th 19'th 20'th 21'st 22'nd 23'rd 24'th 250'th 251'st 252'nd 253'rd 254'th 255'th 256'th 257'th 258'th 259'th 260'th 261'st 262'nd 263'rd 264'th 265'th 266'th 267'th 268'th 269'th 270'th 271'st 272'nd 273'rd 274'th 500'th 501'st 502'nd 503'rd 504'th 505'th 506'th 507'th 508'th 509'th 510'th 511'st 512'nd 513'rd 514'th 515'th 516'th 517'th 518'th 519'th 520'th 521'st 522'nd 523'rd 524'th 750'th 751'st 752'nd 753'rd 754'th 755'th 756'th 757'th 758'th 759'th 760'th 761'st 762'nd 763'rd 764'th 765'th 766'th 767'th 768'th 769'th 770'th 771'st 772'nd 773'rd 774'th 1000'th 1001'st 1002'nd 1003'rd 1004'th 1005'th 1006'th 1007'th 1008'th 1009'th 1010'th 1011'st 1012'nd 1013'rd 1014'th 1015'th 1016'th 1017'th 1018'th 1019'th 1020'th 1021'st 1022'nd 1023'rd 1024'th
AutoHotkey
<lang AutoHotkey>for k, v in [[0, 25], [250, 265], [1000, 1025]] { while v[1] <= v[2] { Out .= Ordinal(v[1]) " " v[1]++ } Out .= "`n" } MsgBox, % Out
Ordinal(n) { s2 := Mod(n, 100) if (s2 > 10 && s2 < 14) return n "th" s1 := Mod(n, 10) return n (s1 = 1 ? "st" : s1 = 2 ? "nd" : s1 = 3 ? "rd" : "th") }</lang>
- Output:
0th 1st 2nd 3rd 4th 5th 6th 7th 8th 9th 10th 11th 12th 13th 14th 15th 16th 17th 18th 19th 20th 21st 22nd 23rd 24th 25th 250th 251st 252nd 253rd 254th 255th 256th 257th 258th 259th 260th 261st 262nd 263rd 264th 265th 1000th 1001st 1002nd 1003rd 1004th 1005th 1006th 1007th 1008th 1009th 1010th 1011th 1012th 1013th 1014th 1015th 1016th 1017th 1018th 1019th 1020th 1021st 1022nd 1023rd 1024th 1025th
AWK
<lang AWK>
- syntax: GAWK -f NTH.AWK
BEGIN {
prn(0,25) prn(250,265) prn(1000,1025) exit(0)
} function prn(start,stop, i) {
printf("%d-%d: ",start,stop)
for (i=start; i<=stop; i++) {
printf("%d%s ",i,nth(i))
}
printf("\n")
} function nth(yearday, nthday) {
if (yearday ~ /1[1-3]$/) { # 11th,12th,13th
nthday = "th"
}
else if (yearday ~ /1$/) { # 1st,21st,31st,etc.
nthday = "st"
}
else if (yearday ~ /2$/) { # 2nd,22nd,32nd,etc.
nthday = "nd"
}
else if (yearday ~ /3$/) { # 3rd,23rd,33rd,etc.
nthday = "rd"
}
else if (yearday ~ /[0456789]$/) { # 4th-10th,20th,24th-30th,etc.
nthday = "th"
}
return(nthday)
} </lang>
- Output:
0-25: 0th 1st 2nd 3rd 4th 5th 6th 7th 8th 9th 10th 11th 12th 13th 14th 15th 16th 17th 18th 19th 20th 21st 22nd 23rd 24th 25th 250-265: 250th 251st 252nd 253rd 254th 255th 256th 257th 258th 259th 260th 261st 262nd 263rd 264th 265th 1000-1025: 1000th 1001st 1002nd 1003rd 1004th 1005th 1006th 1007th 1008th 1009th 1010th 1011th 1012th 1013th 1014th 1015th 1016th 1017th 1018th 1019th 1020th 1021st 1022nd 1023rd 1024th 1025th
Babel
<lang babel>((irregular ("st" "nd" "rd"))
(main
{(0 250 1000)
{ test ! "\n" << }
each})
(test {
<-
{iter 1 - -> dup <- + ordinalify ! <<
{iter 10 %} {" "} {"\n"} ifte << }
26 times})
(ordinalify {
<-
{{ -> dup <- 100 % 10 cugt } !
{ -> dup <- 100 % 14 cult } !
and not
{ -> dup <- 10 % 0 cugt } !
{ -> dup <- 10 % 4 cult } !
and
and}
{ -> dup
<- %d "'"
irregular -> 10 % 1 - ith
. . }
{ -> %d "'th" . }
ifte }))</lang>
- Output:
25'th 24'th 23'rd 22'nd 21'st 20'th 19'th 18'th 17'th 16'th 15'th 14'th 13'th 12'th 11'th 10'th 9'th 8'th 7'th 6'th 5'th 4'th 3'rd 2'nd 1'st 0'th 275'th 274'th 273'rd 272'nd 271'st 270'th 269'th 268'th 267'th 266'th 265'th 264'th 263'rd 262'nd 261'st 260'th 259'th 258'th 257'th 256'th 255'th 254'th 253'rd 252'nd 251'st 250'th 1025'th 1024'th 1023'rd 1022'nd 1021'st 1020'th 1019'th 1018'th 1017'th 1016'th 1015'th 1014'th 1013'th 1012'th 1011'th 1010'th 1009'th 1008'th 1007'th 1006'th 1005'th 1004'th 1003'rd 1002'nd 1001'st 1000'th
BaCon
<lang freebasic>' Nth (sans apostrophes) FUNCTION nth$(NUMBER n) TYPE STRING
LOCAL suffix
IF n < 0 THEN RETURN STR$(n)
IF MOD(n, 100) >= 11 AND MOD(n, 100) <= 13 THEN
suffix = "th"
ELSE
suffix = MID$("thstndrdthththththth", MOD(n, 10) * 2 + 1, 2)
ENDIF
RETURN CONCAT$(STR$(n), suffix)
END FUNCTION
' Test a few ranges FOR i = 1 TO 4
READ first, last
per = 1
FOR n = first TO last
PRINT nth$(n) FORMAT "%s "
' limit to 10 entries per line
IF per = 10 OR n = last THEN
per = 1
PRINT
ELSE
INCR per
ENDIF
NEXT
NEXT DATA 0, 25, 250, 265, 1000, 1025, -20, -11</lang>
- Output:
prompt$ ./nth 0th 1st 2nd 3rd 4th 5th 6th 7th 8th 9th 10th 11th 12th 13th 14th 15th 16th 17th 18th 19th 20th 21st 22nd 23rd 24th 25th 250th 251st 252nd 253rd 254th 255th 256th 257th 258th 259th 260th 261st 262nd 263rd 264th 265th 1000th 1001st 1002nd 1003rd 1004th 1005th 1006th 1007th 1008th 1009th 1010th 1011th 1012th 1013th 1014th 1015th 1016th 1017th 1018th 1019th 1020th 1021st 1022nd 1023rd 1024th 1025th -20 -19 -18 -17 -16 -15 -14 -13 -12 -11
BASIC
BASIC256
<lang BASIC256> function ordinal(n) ns$ = string(n) begin case case right(ns$, 1) = "1" if right(ns$, 2) = "11" then return ns$ + "th" return ns$ + "st" case right(ns$, 1) = "2" if right(ns$, 2) = "12" then return ns$ + "th" return ns$ + "nd" case right(ns$, 1) = "3" if right(ns$, 2) = "13" then return ns$ + "th" return ns$ + "rd" else return ns$ + "th" end case end function
subroutine imprimeOrdinal(a, b) for i = a to b print ordinal(i); " "; next i print end subroutine
call imprimeOrdinal (0, 25) call imprimeOrdinal (250, 265) call imprimeOrdinal (1000, 1025) end </lang>
Commodore BASIC
<lang basic> 0 REM ROSETTACODE.ORG 1 REM N'TH 2 REM WRITE A FUNCTION/METHOD/SUBROUTINE/... THAT WHEN GIVEN AN INTEGER GREATER 3 REM THAN OR EQUAL TO ZERO RETURNS A STRING OF THE NUMBER FOLLOWED BY 4 REM AN APOSTROPHE THEN THE ORDINAL SUFFIX. 5 REM BASED ON APPLESOFT BASIC VERSION @ ROSETTACODE.ORG 6 REM 7 REM ************************* 8 PRINT CHR$(14): REM CHANGE TO LOWER/UPPER CASE CHAR SET 9 OP = 1 10 FOR N = 0 TO 25 : GOSUB 100 : NEXT : PRINT 20 FOR N = 250 TO 265 : GOSUB 100 : NEXT : PRINT 30 FOR N = 1000 TO 1025 : GOSUB 100 : NEXT : PRINT 40 END 50 REM ************************* 100 GOSUB 200 110 PRINT NTH$ " "; 120 RETURN 130 REM ************************ 200 M1 = N - INT(N / 10) * 10 210 M2 = N - INT(N / 100) * 100 220 NTH$ = "TH" 230 IF M1 = 1 AND M2 <> 11 THEN NTH$ = "ST" 240 IF M1 = 2 AND M2 <> 12 THEN NTH$ = "ND" 250 IF M1 = 3 AND M2 <> 13 THEN NTH$ = "RD" 260 IF NOT OP THEN NTH$ = "'" + NTH$ 270 NTH$ = STR$(N) + NTH$ 280 RETURN </lang>
- Output:
Commodore 64 (40 column text)
0'th 1'st 2'nd 3'rd 4'th 5'th 6't h 7'th 8'th 9'th 10'th 11'th 12'th 13'th 14'th 15'th 16'th 17'th 18' th 19'th 20'th 21'st 22'nd 23'rd 2 4'th 25'th 250'th 251'st 252'nd 253'rd 254'th 255'th 256'th 257'th 258'th 259'th 260'th 261'st 262'nd 263'rd 264'th 265'th 1000'th 1001'st 1002'nd 1003'rd 100 4'th 1005'th 1006'th 1007'th 1008'th 1009'th 1010'th 1011'th 1012'th 10 13'th 1014'th 1015'th 1016'th 1017't h 1018'th 1019'th 1020'th 1021'st 1 022'nd 1023'rd 1024'th 1025'th
Nascom BASIC
<lang basic> 10 REM N'th 20 LOLIM=0 30 HILIM=25 40 GOSUB 1000 50 LOLIM=250 60 HILIM=265 70 GOSUB 1000 80 LOLIM=1000 90 HILIM=1025 100 GOSUB 1000 110 END 995 REM ** Print images 1000 FOR I=LOLIM TO HILIM 1010 NR=I 1020 GOSUB 1500 1030 SI$=STR$(I) 1040 PRINT RIGHT$(SI$,LEN(SI$)-1);SUF$;" "; 1050 NEXT I 1060 PRINT 1070 RETURN 1495 REM ** Get suffix 1500 LA=NR-INT(NR/10)*10:NLA=NR-INT(NR/100)*100 1510 IF LA=1 AND NLA<>11 THEN SUF$="st":RETURN 1520 IF LA=2 AND NLA<>12 THEN SUF$="nd":RETURN 1530 IF LA=3 AND NLA<>13 THEN SUF$="rd":RETURN 1540 SUF$="th" 1550 RETURN </lang>
- Output:
0th 1st 2nd 3rd 4th 5th 6th 7th 8th 9th 10th 11th 12th 13th 14th 15th 16th 17th 18th 19th 20th 21st 22nd 23rd 24th 25th 250th 251st 252nd 253rd 254th 255th 256th 257th 258th 259th 260th 261st 262nd 263rd 264th 265th 1000th 1001st 1002nd 1003rd 1004th 1005th 1006th 1007th 1008th 1009th 1010th 1011th 1012th 1013th 1014th 1015th 1016th 1017th 1018th 1019th 1020th 1021st 1022nd 1023rd 1024th 1025th
QBasic
<lang basic> DECLARE FUNCTION sufijo$ (n%) DECLARE SUB imprimeOrdinal (loLim%, hiLim%)
imprimeOrdinal 0, 25 imprimeOrdinal 250, 265 imprimeOrdinal 1000, 1025 END
DEFINT A-Z SUB imprimeOrdinal (loLim, hiLim)
loLim = INT(loLim) hiLim = INT(hiLim) FOR i = loLim TO hiLim PRINT STR$(i) + sufijo$(i) + " "; NEXT i PRINT
END SUB
FUNCTION sufijo$ (n)
n = INT(n)
NMod10 = n MOD 10
NMod100 = n MOD 100
IF (NMod10 = 1) AND (NMod100 <> 11) THEN
sufijo$ = "st"
ELSE
IF (NMod10 = 2) AND (NMod100 <> 12) THEN
sufijo$ = "nd"
ELSE
IF (NMod10 = 3) AND (NMod100 <> 13) THEN
sufijo$ = "rd"
ELSE
sufijo$ = "th"
END IF
END IF
END IF
END FUNCTION </lang>
Batch File
<lang dos>@echo off
- Main thing...
call :Nth 0 25 call :Nth 250 265 call :Nth 1000 1025 pause exit /b
- The subroutine
- Nth <lbound> <ubound>
setlocal enabledelayedexpansion for /l %%n in (%~1,1,%~2) do ( set curr_num=%%n set "out=%%nth" if !curr_num:~-1!==1 (set "out=%%nst") if !curr_num:~-1!==2 (set "out=%%nnd") if !curr_num:~-1!==3 (set "out=%%nrd") set "range_output=!range_output! !out!" ) echo."!range_output:~1!" goto :EOF</lang>
- Output:
"0th 1st 2nd 3rd 4th 5th 6th 7th 8th 9th 10th 11st 12nd 13rd 14th 15th 16th 17th 18th 19th 20th 21st 22nd 23rd 24th 25th" "250th 251st 252nd 253rd 254th 255th 256th 257th 258th 259th 260th 261st 262nd 263rd 264th 265th" "1000th 1001st 1002nd 1003rd 1004th 1005th 1006th 1007th 1008th 1009th 1010th 1011st 1012nd 1013rd 1014th 1015th 1016th 1017th 1018th 1019th 1020th 1021st 1022nd 1023rd 1024th 1025th" Press any key to continue . . .
BBC BASIC
<lang bbcbasic> PROCNth( 0, 25)
PROCNth( 250, 265)
PROCNth(1000,1025)
END
DEF PROCNth(s%,e%)
LOCAL i%,suff$
FOR i%=s% TO e%
suff$="th"
IF i% MOD 10 = 1 AND i% MOD 100 <> 11 suff$="st"
IF i% MOD 10 = 2 AND i% MOD 100 <> 12 suff$="nd"
IF i% MOD 10 = 3 AND i% MOD 100 <> 13 suff$="rd"
PRINT STR$i%+suff$+" ";
NEXT
PRINT
ENDPROC</lang>
- Output:
0th 1st 2nd 3rd 4th 5th 6th 7th 8th 9th 10th 11th 12th 13th 14th 15th 16th 17th 18th 19th 20th 21st 22nd 23rd 24th 25th 250th 251st 252nd 253rd 254th 255th 256th 257th 258th 259th 260th 261st 262nd 263rd 264th 265th 1000th 1001st 1002nd 1003rd 1004th 1005th 1006th 1007th 1008th 1009th 1010th 1011th 1012th 1013th 1014th 1015th 1016th 1017th 1018th 1019th 1020th 1021st 1022nd 1023rd 1024th 1025th
BCPL
<lang bcpl>get "libhdr"
// Generate ASCII string of number n with ordinal suffix // The string is stored at v. let nth(n, v) = valof $( let sfx = "thstndrd"
let c, s = 0, ?
// Generate digits
$( c := c + 1
v%c := n rem 10 + '0'
n := n / 10
$) repeatuntil n = 0
// Put digits in correct order
for i = 1 to c/2 do
$( let d = v%i
v%i := v%(c+1-i)
v%(c+1-i) := d
$)
// The length of the string is the amount of digits + 2
v%0 := c+2;
// Figure out the proper suffix from the last two digits
test v%(c-1)='1' | v%c>'3'
then s := 0
else s := 2*(v%c - '0')
v%(c+1) := sfx%(s+1)
v%(c+2) := sfx%(s+2)
resultis v
$)
let start() be $( let buf = vec 10
for i = 0 to 25 do writef("%S*N", nth(i, buf))
for i = 250 to 265 do writef("%S*N", nth(i, buf))
for i = 1000 to 1025 do writef("%S*N", nth(i, buf))
$)</lang>
- Output:
0th 1st 2nd 3rd 4th 5th 6th 7th 8th 9th 10th 11th 12th 13th 14th 15th 16th 17th 18th 19th 20th 21st 22nd 23rd 24th 25th 250th 251st 252nd 253rd 254th 255th 256th 257th 258th 259th 260th 261st 262nd 263rd 264th 265th 1000th 1001st 1002nd 1003rd 1004th 1005th 1006th 1007th 1008th 1009th 1010th 1011th 1012th 1013th 1014th 1015th 1016th 1017th 1018th 1019th 1020th 1021st 1022nd 1023rd 1024th 1025th
Befunge
The bottom section of code contains the "subroutine" that calculates the ordinal of a given number; the top section generates the list of values to test.
<lang befunge>0>55*:>1-\:0\`!v
- v$#$<^:\+*8"}"_
>35*:>1-\:0\`!v
- v$#$<^:\+*2"}"_
5< v$_v#!::-<0*5 @v <,*>#81#4^# _
>>:0\>:55+%68*v: tsnr |:/+ 55\+<, htdd >$>:#,_$:vg v"d"\*!`3:%+55<9 >%55+/1-!!*:8g,^</lang>
- Output:
0th 1st 2nd 3rd 4th 5th 6th 7th 8th 9th 10th 11th 12th 13th 14th 15th 16th 17th 18th 19th 20th 21st 22nd 23rd 24th 25th 250th 251st 252nd 253rd 254th 255th 256th 257th 258th 259th 260th 261st 262nd 263rd 264th 265th 1000th 1001st 1002nd 1003rd 1004th 1005th 1006th 1007th 1008th 1009th 1010th 1011th 1012th 1013th 1014th 1015th 1016th 1017th 1018th 1019th 1020th 1021st 1022nd 1023rd 1024th 1025th
BQN
<lang bqn>Nth ← {
sfx ← ⟨"th","st","nd","rd"⟩ (•Fmt 𝕩)∾sfx⊑˜ (1≠10|⌊𝕩÷10)×(3≥10|𝕩)×10|𝕩
}
∘‿4⥊ Nth¨ (↕26) ∾ (250+↕16) ∾ (1000+↕26)</lang>
- Output:
┌─
╵ "0th" "1st" "2nd" "3rd"
"4th" "5th" "6th" "7th"
"8th" "9th" "10th" "11th"
"12th" "13th" "14th" "15th"
"16th" "17th" "18th" "19th"
"20th" "21st" "22nd" "23rd"
"24th" "25th" "250th" "251st"
"252nd" "253rd" "254th" "255th"
"256th" "257th" "258th" "259th"
"260th" "261st" "262nd" "263rd"
"264th" "265th" "1000th" "1001st"
"1002nd" "1003rd" "1004th" "1005th"
"1006th" "1007th" "1008th" "1009th"
"1010th" "1011th" "1012th" "1013th"
"1014th" "1015th" "1016th" "1017th"
"1018th" "1019th" "1020th" "1021st"
"1022nd" "1023rd" "1024th" "1025th"
┘
C
<lang c>#include <stdio.h>
char* addSuffix(int num, char* buf, size_t len) {
char *suffixes[4] = { "th", "st", "nd", "rd" };
int i;
switch (num % 10)
{
case 1 : i = (num % 100 == 11) ? 0 : 1;
break;
case 2 : i = (num % 100 == 12) ? 0 : 2;
break;
case 3 : i = (num % 100 == 13) ? 0 : 3;
break;
default: i = 0;
};
snprintf(buf, len, "%d%s", num, suffixes[i]);
return buf;
}
int main(void) {
int i;
printf("Set [0,25]:\n");
for (i = 0; i < 26; i++)
{
char s[5];
printf("%s ", addSuffix(i, s, 5));
}
putchar('\n');
printf("Set [250,265]:\n");
for (i = 250; i < 266; i++)
{
char s[6];
printf("%s ", addSuffix(i, s, 6));
}
putchar('\n');
printf("Set [1000,1025]:\n");
for (i = 1000; i < 1026; i++)
{
char s[7];
printf("%s ", addSuffix(i, s, 7));
}
putchar('\n');
return 0;
}</lang> Another method with dynamic memory allocation <lang c>#include <stdlib.h>
- include <stdio.h>
static int digits(const int x) {
if (x / 10 == 0) return 1; return 1 + digits(x / 10);
}
static char * get_ordinal(const int i) {
const int string_size = digits(i) + 3; char * o_number = malloc(string_size); char * ordinal; if(i % 100 >= 11 && i % 100 <= 13) ordinal = "th"; else ordinal = i/10==1?"th":i%10==1?"st":i%10==2?"nd":i%10==3?"rd":"th"; sprintf_s(o_number, string_size, "%d%s", i, ordinal); return o_number;
}
static void print_range(const int begin, const int end) {
printf("Set [%d,%d]:\n", begin, end);
for (int i = begin; i <= end; i++) {
char * o_number = get_ordinal(i);
printf("%s ", o_number);
free(o_number);
}
printf("\n");
}
int main(void) {
print_range(0, 25); print_range(250, 265); print_range(1000, 1025);
}</lang>
- Output:
Set [0,25] : 0th 1st 2nd 3rd 4th 5th 6th 7th 8th 9th 10th 11th 12th 13th 14th 15th 16th 17th 18th 19th 20th 21st 22nd 23rd 24th 25th Set [250,265] : 250th 251st 252nd 253rd 254th 255th 256th 257th 258th 259th 260th 261st 262nd 263rd 264th 265th Set [1000,1025] : 1000th 1001st 1002nd 1003rd 1004th 1005th 1006th 1007th 1008th 1009th 1010th 1011th 1012th 1013th 1014th 1015th 1016th 1017th 1018th 1019th 1020th 1021st 1022nd 1023rd 1024th 1025th
C#
<lang csharp>using System; using System.Linq;
class Program {
private static string Ordinalize(int i)
{
i = Math.Abs(i);
if (new[] {11, 12, 13}.Contains(i%100))
return i + "th";
switch (i%10)
{
case 1:
return i + "st";
case 2:
return i + "nd";
case 3:
return i + "rd";
default:
return i + "th";
}
}
static void Main()
{
Console.WriteLine(string.Join(" ", Enumerable.Range(0, 26).Select(Ordinalize)));
Console.WriteLine(string.Join(" ", Enumerable.Range(250, 16).Select(Ordinalize)));
Console.WriteLine(string.Join(" ", Enumerable.Range(1000, 26).Select(Ordinalize)));
}
}</lang> Dotnet 5 version without LINQ <lang csharp>using System;
static string Ordinalize(int i) {
return i + (
i % 100 is >= 11 and <= 13 ? "th" :
i % 10 == 1 ? "st" :
i % 10 == 2 ? "nd" :
i % 10 == 3 ? "rd" :
"th");
}
static void PrintRange(int begin, int end) {
for(var i = begin; i <= end; i++)
Console.Write(Ordinalize(i) + (i == end ? "" : " "));
Console.WriteLine();
}
PrintRange(0, 25); PrintRange(250, 265); PrintRange(1000, 1025);</lang>
- Output:
0th 1st 2nd 3rd 4th 5th 6th 7th 8th 9th 10th 11th 12th 13th 14th 15th 16th 17th 18th 19th 20th 21st 22nd 23rd 24th 25th 250th 251st 252nd 253rd 254th 255th 256th 257th 258th 259th 260th 261st 262nd 263rd 264th 265th 1000th 1001st 1002nd 1003rd 1004th 1005th 1006th 1007th 1008th 1009th 1010th 1011th 1012th 1013th 1014th 1015th 1016th 1017th 1018th 1019th 1020th 1021st 1022nd 1023rd 1024th 1025th
C++
<lang cpp>#include <string>
- include <iostream>
using namespace std;
string Suffix(int num) {
switch (num % 10)
{
case 1 : if(num % 100 != 11) return "st";
break;
case 2 : if(num % 100 != 12) return "nd";
break;
case 3 : if(num % 100 != 13) return "rd";
}
return "th";
}
int main() {
cout << "Set [0,25]:" << endl;
for (int i = 0; i < 26; i++)
cout << i << Suffix(i) << " ";
cout << endl;
cout << "Set [250,265]:" << endl;
for (int i = 250; i < 266; i++)
cout << i << Suffix(i) << " ";
cout << endl;
cout << "Set [1000,1025]:" << endl;
for (int i = 1000; i < 1026; i++)
cout << i << Suffix(i) << " ";
cout << endl;
return 0;
}</lang>
- Output:
Set [0,25] : 0th 1st 2nd 3rd 4th 5th 6th 7th 8th 9th 10th 11th 12th 13th 14th 15th 16th 17th 18th 19th 20th 21st 22nd 23rd 24th 25th Set [250,265] : 250th 251st 252nd 253rd 254th 255th 256th 257th 258th 259th 260th 261st 262nd 263rd 264th 265th Set [1000,1025] : 1000th 1001st 1002nd 1003rd 1004th 1005th 1006th 1007th 1008th 1009th 1010th 1011th 1012th 1013th 1014th 1015th 1016th 1017th 1018th 1019th 1020th 1021st 1022nd 1023rd 1024th 1025th
Clojure
<lang clojure> (defn n-th [n]
(str n
(let [rem (mod n 100)]
(if (and (>= rem 11) (<= rem 13))
"th"
(condp = (mod n 10)
1 "st"
2 "nd"
3 "rd"
"th")))))
(apply str (interpose " " (map n-th (range 0 26)))) (apply str (interpose " " (map n-th (range 250 266)))) (apply str (interpose " " (map n-th (range 1000 1026)))) </lang>
- Output:
"0th 1st 2nd 3rd 4th 5th 6th 7th 8th 9th 10th 11th 12th 13th 14th 15th 16th 17th 18th 19th 20th 21st 22nd 23rd 24th 25th" "250th 251st 252nd 253rd 254th 255th 256th 257th 258th 259th 260th 261st 262nd 263rd 264th 265th" "1000th 1001st 1002nd 1003rd 1004th 1005th 1006th 1007th 1008th 1009th 1010th 1011th 1012th 1013th 1014th 1015th 1016th 1017th 1018th 1019th 1020th 1021st 1022nd 1023rd 1024th 1025th"
Alternatively, if you want to print the full ordinal English, it becomes trivial with pprint: <lang clojure> (apply str (interpose " " (map #(clojure.pprint/cl-format nil "~:R" %) (range 0 26)))) </lang>
- Output:
"zeroth first second third fourth fifth sixth seventh eighth ninth tenth eleventh twelfth thirteenth fourteenth fifteenth sixteenth seventeenth eighteenth nineteenth twentieth twenty-first twenty-second twenty-third twenty-fourth twenty-fifth"
CLU
<lang clu>nth = proc (n: int) returns (string)
num: string := int$unparse(n) sfx: array[string] := array[string]$[0: "th", "st", "nd", "rd"]
if n / 10 // 10 = 1 cor n // 10 > 3 then
return(num || sfx[0])
else
return(num || sfx[n // 10])
end
end nth
do_range = proc (from, to: int)
po: stream := stream$primary_output()
col: int := 0
for i: int in int$from_to(from,to) do
stream$putleft(po, nth(i), 7)
col := col + 1
if col = 10 then
stream$putc(po, '\n')
col := 0
end
end
stream$putl(po, "\n")
end do_range
start_up = proc ()
do_range(0,25) do_range(250,265) do_range(1000,1025)
end start_up</lang>
- Output:
0th 1st 2nd 3rd 4th 5th 6th 7th 8th 9th 10th 11th 12th 13th 14th 15th 16th 17th 18th 19th 20th 21st 22nd 23rd 24th 25th 250th 251st 252nd 253rd 254th 255th 256th 257th 258th 259th 260th 261st 262nd 263rd 264th 265th 1000th 1001st 1002nd 1003rd 1004th 1005th 1006th 1007th 1008th 1009th 1010th 1011th 1012th 1013th 1014th 1015th 1016th 1017th 1018th 1019th 1020th 1021st 1022nd 1023rd 1024th 1025th
COBOL
COBOL stores numbers in decimal form, so there is no need to use a modulo function: the last digit or the last two digits can be extracted directly. <lang cobol>IDENTIFICATION DIVISION. PROGRAM-ID. NTH-PROGRAM. DATA DIVISION. WORKING-STORAGE SECTION. 01 WS-NUMBER.
05 N PIC 9(8). 05 LAST-TWO-DIGITS PIC 99. 05 LAST-DIGIT PIC 9. 05 N-TO-OUTPUT PIC Z(7)9. 05 SUFFIX PIC AA.
PROCEDURE DIVISION. TEST-PARAGRAPH.
PERFORM NTH-PARAGRAPH VARYING N FROM 0 BY 1 UNTIL N IS GREATER THAN 25. PERFORM NTH-PARAGRAPH VARYING N FROM 250 BY 1 UNTIL N IS GREATER THAN 265. PERFORM NTH-PARAGRAPH VARYING N FROM 1000 BY 1 UNTIL N IS GREATER THAN 1025. STOP RUN.
NTH-PARAGRAPH.
MOVE 'TH' TO SUFFIX. MOVE N (7:2) TO LAST-TWO-DIGITS. IF LAST-TWO-DIGITS IS LESS THAN 4, OR LAST-TWO-DIGITS IS GREATER THAN 20, THEN PERFORM DECISION-PARAGRAPH. MOVE N TO N-TO-OUTPUT. DISPLAY N-TO-OUTPUT WITH NO ADVANCING. DISPLAY SUFFIX WITH NO ADVANCING. DISPLAY SPACE WITH NO ADVANCING.
DECISION-PARAGRAPH.
MOVE N (8:1) TO LAST-DIGIT. IF LAST-DIGIT IS EQUAL TO 1 THEN MOVE 'ST' TO SUFFIX. IF LAST-DIGIT IS EQUAL TO 2 THEN MOVE 'ND' TO SUFFIX. IF LAST-DIGIT IS EQUAL TO 3 THEN MOVE 'RD' TO SUFFIX.</lang>
Output:
0TH 1ST 2ND 3RD 4TH 5TH 6TH 7TH 8TH 9TH 10TH 11TH 12TH 13TH 14TH 15TH 16TH 17TH 18TH 19TH 20TH 21ST 22ND 23RD 24TH 25TH 250TH 251ST 252ND 253RD 254TH 255TH 256TH 257TH 258TH 259TH 260TH 261ST 262ND 263RD 264TH 265TH 1000TH 1001ST 1002ND 1003RD 1004TH 1005TH 1006TH 1007TH 1008TH 1009TH 1010TH 1011TH 1012TH 1013TH 1014TH 1015TH 1016TH 1017TH 1018TH 1019TH 1020TH 1021ST 1022ND 1023RD 1024TH 1025TH
Common Lisp
<lang lisp>(defun add-suffix (number)
(let* ((suffixes #10("th" "st" "nd" "rd" "th"))
(last2 (mod number 100))
(last-digit (mod number 10))
(suffix (if (< 10 last2 20)
"th"
(svref suffixes last-digit))))
(format nil "~a~a" number suffix)))
</lang>
A more concise, albeit less readable version:
<lang lisp>(defun add-suffix (n)
(format nil "~d'~:[~[th~;st~;nd~;rd~:;th~]~;th~]" n (< (mod (- n 10) 100) 10) (mod n 10)))
</lang>
Display the results:
<lang lisp>(loop for (low high) in '((0 25) (250 265) (1000 1025))
do (progn
(format t "~a to ~a: " low high)
(loop for n from low to high
do (format t "~a " (add-suffix n))
finally (terpri))))</lang>
- Output:
0 to 25: 0th 1st 2nd 3rd 4th 5th 6th 7th 8th 9th 10th 11th 12th 13th 14th 15th 16th 17th 18th 19th 20th 21st 22nd 23rd 24th 25th 250 to 265: 250th 251st 252nd 253rd 254th 255th 256th 257th 258th 259th 260th 261st 262nd 263rd 264th 265th 1000 to 1025: 1000th 1001st 1002nd 1003rd 1004th 1005th 1006th 1007th 1008th 1009th 1010th 1011th 1012th 1013th 1014th 1015th 1016th 1017th 1018th 1019th 1020th 1021st 1022nd 1023rd 1024th 1025th
Cowgol
<lang cowgol>include "cowgol.coh"; include "strings.coh";
- Given an int32, return decimal string and add an ordinal suffix
sub ordsfx(n: int32, buf: [uint8]): (out: [uint8]) is
var sfx: [uint8][] := {"th", "st", "nd", "rd"};
out := buf;
buf := IToA(n, 10, buf); # IToA is included in standard library
# Since we now already have the digits, we can make the decision
# without doing any more work.
if (n > 10 and [@prev @prev buf] == '1')
or ([@prev buf] > '3') then
CopyString(sfx[0], buf);
else
CopyString(sfx[[@prev buf]-'0'], buf);
end if;
end sub;
- Print suffixed numerals from start to end inclusive
sub test(start: int32, end_: int32) is
var buf: uint8[16]; # buffer
var n: uint8 := 10;
while start <= end_ loop
print(ordsfx(start, &buf[0]));
print_char(' ');
start := start + 1;
n := n - 1;
if n == 0 then
print_nl();
n := 10;
end if;
end loop;
print_nl();
end sub;
test(0, 25); test(250,265); test(1000,1025);</lang>
- Output:
0th 1st 2nd 3rd 4th 5th 6th 7th 8th 9th 10th 11th 12th 13th 14th 15th 16th 17th 18th 19th 20th 21st 22nd 23rd 24th 25th 250th 251st 252nd 253rd 254th 255th 256th 257th 258th 259th 260th 261st 262nd 263rd 264th 265th 1000th 1001st 1002nd 1003rd 1004th 1005th 1006th 1007th 1008th 1009th 1010th 1011th 1012th 1013th 1014th 1015th 1016th 1017th 1018th 1019th 1020th 1021st 1022nd 1023rd 1024th 1025th
Crystal
<lang ruby>struct Int
def ordinalize
num = self.abs
ordinal = if (11..13).includes?(num % 100)
"th"
else
case num % 10
when 1; "st"
when 2; "nd"
when 3; "rd"
else "th"
end
end
"#{self}#{ordinal}"
end
end
[(0..25),(250..265),(1000..1025)].each{|r| puts r.map{ |n| n.ordinalize }.join(", "); puts} </lang>
- Output:
0th, 1st, 2nd, 3rd, 4th, 5th, 6th, 7th, 8th, 9th, 10th, 11th, 12th, 13th, 14th, 15th, 16th, 17th, 18th, 19th, 20th, 21st, 22nd, 23rd, 24th, 25th 250th, 251st, 252nd, 253rd, 254th, 255th, 256th, 257th, 258th, 259th, 260th, 261st, 262nd, 263rd, 264th, 265th 1000th, 1001st, 1002nd, 1003rd, 1004th, 1005th, 1006th, 1007th, 1008th, 1009th, 1010th, 1011th, 1012th, 1013th, 1014th, 1015th, 1016th, 1017th, 1018th, 1019th, 1020th, 1021st, 1022nd, 1023rd, 1024th, 1025th
D
<lang d>import std.stdio, std.string, std.range, std.algorithm;
string nth(in uint n) pure {
static immutable suffix = "th st nd rd th th th th th th".split;
return "%d'%s".format(n, (n % 100 <= 10 || n % 100 > 20) ?
suffix[n % 10] : "th");
}
void main() {
foreach (r; [iota(26), iota(250, 266), iota(1000, 1026)])
writefln("%-(%s %)", r.map!nth);
}</lang>
- Output:
0'th 1'st 2'nd 3'rd 4'th 5'th 6'th 7'th 8'th 9'th 10'th 11'th 12'th 13'th 14'th 15'th 16'th 17'th 18'th 19'th 20'th 21'st 22'nd 23'rd 24'th 25'th 250'th 251'st 252'nd 253'rd 254'th 255'th 256'th 257'th 258'th 259'th 260'th 261'st 262'nd 263'rd 264'th 265'th 1000'th 1001'st 1002'nd 1003'rd 1004'th 1005'th 1006'th 1007'th 1008'th 1009'th 1010'th 1011'th 1012'th 1013'th 1014'th 1015'th 1016'th 1017'th 1018'th 1019'th 1020'th 1021'st 1022'nd 1023'rd 1024'th 1025'th
Delphi
See Pascal.
Draco
<lang draco>proc nonrec nth(word n; *char buf) *char:
channel output text ch;
open(ch, buf);
write(ch; n,
if (n/10)%10=1 then "th"
elif n%10=1 then "st"
elif n%10=2 then "nd"
elif n%10=3 then "rd"
else "th"
fi
);
close(ch);
buf
corp;
proc nonrec print_range(word start, stop) void:
[8] char buf;
word col, n;
col := 0;
for n from start upto stop do
write(nth(n, &buf[0]));
col := col + 1;
if col%10=0 then writeln() else write('\t') fi
od;
writeln()
corp
proc nonrec main() void:
print_range(0, 25); print_range(250, 265); print_range(1000, 1025)
corp</lang>
- Output:
0th 1st 2nd 3rd 4th 5th 6th 7th 8th 9th 10th 11th 12th 13th 14th 15th 16th 17th 18th 19th 20th 21st 22nd 23rd 24th 25th 250th 251st 252nd 253rd 254th 255th 256th 257th 258th 259th 260th 261st 262nd 263rd 264th 265th 1000th 1001st 1002nd 1003rd 1004th 1005th 1006th 1007th 1008th 1009th 1010th 1011th 1012th 1013th 1014th 1015th 1016th 1017th 1018th 1019th 1020th 1021st 1022nd 1023rd 1024th 1025th
Elena
ELENA 5.0 : <lang elena>import extensions; import system'math; import system'routines;
extension op {
ordinalize()
{
int i := self.Absolute;
if (new int[]{11,12,13}.ifExists(i.mod:100))
{
^ i.toPrintable() + "th"
};
(i.mod(10)) =>
1 { ^ i.toPrintable() + "st" }
2 { ^ i.toPrintable() + "nd" }
3 { ^ i.toPrintable() + "rd" };
^ i.toPrintable() + "th"
}
}
public program() {
console.printLine(new Range(0,26).selectBy(mssgconst ordinalize<op>[1])); console.printLine(new Range(250,26).selectBy(mssgconst ordinalize<op>[1])); console.printLine(new Range(1000,26).selectBy(mssgconst ordinalize<op>[1]))
}</lang>
- Output:
0th,1st,2nd,3rd,4th,5th,6th,7th,8th,9th,10th,11th,12th,13th,14th,15th,16th,17th,18th,19th,20th,21st,22nd,23rd,24th,25th 250th,251st,252nd,253rd,254th,255th,256th,257th,258th,259th,260th,261st,262nd,263rd,264th,265th,266th,267th,268th,269th,270th,271st,272nd,273rd,274th,275th 1000th,1001st,1002nd,1003rd,1004th,1005th,1006th,1007th,1008th,1009th,1010th,1011th,1012th,1013th,1014th,1015th,1016th,1017th,1018th,1019th,1020th,1021st,1022nd,1023rd,1024th,1025th
Elixir
<lang elixir>defmodule RC do
def ordinalize(n) do
num = abs(n)
ordinal = if rem(num, 100) in 4..20 do
"th"
else
case rem(num, 10) do
1 -> "st"
2 -> "nd"
3 -> "rd"
_ -> "th"
end
end
"#{n}#{ordinal}"
end
end
Enum.each([0..25, 250..265, 1000..1025], fn range ->
Enum.map(range, fn n -> RC.ordinalize(n) end) |> Enum.join(" ") |> IO.puts
end)</lang>
- Output:
0th 1st 2nd 3rd 4th 5th 6th 7th 8th 9th 10th 11th 12th 13th 14th 15th 16th 17th 18th 19th 20th 21st 22nd 23rd 24th 25th 250th 251st 252nd 253rd 254th 255th 256th 257th 258th 259th 260th 261st 262nd 263rd 264th 265th 1000th 1001st 1002nd 1003rd 1004th 1005th 1006th 1007th 1008th 1009th 1010th 1011th 1012th 1013th 1014th 1015th 1016th 1017th 1018th 1019th 1020th 1021st 1022nd 1023rd 1024th 1025th
ERRE
<lang ERRE> PROGRAM NTH_SOLVE
! ! for rosettacode.org !
PROCEDURE NTH(S%,E%)
LOCAL I%,SUFF$
FOR I%=S% TO E% DO
SUFF$="th"
IF I% MOD 10=1 AND I% MOD 100<>11 THEN SUFF$="st" END IF
IF I% MOD 10=2 AND I% MOD 100<>12 THEN SUFF$="nd" END IF
IF I% MOD 10=3 AND I% MOD 100<>13 THEN SUFF$="rd" END IF
PRINT(STR$(I%)+SUFF$+" ";)
END FOR
PRINT
END PROCEDURE
BEGIN
NTH(0,25) NTH(250,265) NTH(1000,1025)
END PROGRAM </lang>
- Output:
0th 1st 2nd 3rd 4th 5th 6th 7th 8th 9th 10th 11th 12th 13th 14th 15th 16th 17th 18th 19th 20th 21st 22nd 23rd 24th 25th 250th 251st 252nd 253rd 254th 255th 256th 257th 258th 259th 260th 261st 262nd 263rd 264th 265th 1000th 1001st 1002nd 1003rd 1004th 1005th 1006th 1007th 1008th 1009th 1010th 1011th 1012th 1013th 1014th 1015th 1016th 1017th 1018th 1019th 1020th 1021st 1022nd 1023rd 1024th 1025th
F#
<lang fsharp>open System
let ordinalsuffix n =
let suffixstrings = [|"th"; "st"; "nd"; "rd"|] let (d, r) = Math.DivRem(n, 10) n.ToString() + suffixstrings.[ if r < 4 && (d &&& 1) = 0 then r else 0 ]
[<EntryPoint>] let main argv =
let show = (Seq.iter (ordinalsuffix >> (printf " %s"))) >> (Console.WriteLine) [0..25] |> show [250..265] |> show [1000..1025] |> show 0
</lang>
- Output:
0th 1st 2nd 3rd 4th 5th 6th 7th 8th 9th 10th 11th 12th 13th 14th 15th 16th 17th 18th 19th 20th 21st 22nd 23rd 24th 25th 250th 251th 252th 253th 254th 255th 256th 257th 258th 259th 260th 261st 262nd 263rd 264th 265th 1000th 1001st 1002nd 1003rd 1004th 1005th 1006th 1007th 1008th 1009th 1010th 1011th 1012th 1013th 1014th 1015th 1016th 1017th 1018th 1019th 1020th 1021st 1022nd 1023rd 1024th 1025th
Factor
<lang factor>USING: io kernel math math.order math.parser math.ranges qw sequences ; IN: rosetta-code.nth
- n'th ( n -- str )
dup 10 /mod swap 1 = [ drop 0 ] when
[ number>string ]
[ 4 min qw{ th st nd rd th } nth ] bi* append ;
- n'th-demo ( -- )
0 25 250 265 1000 1025 [ [a,b] ] 2tri@ [ [ n'th write bl ] each nl ] tri@ ;
MAIN: n'th-demo</lang>
- Output:
0th 1st 2nd 3rd 4th 5th 6th 7th 8th 9th 10th 11th 12th 13th 14th 15th 16th 17th 18th 19th 20th 21st 22nd 23rd 24th 25th 250th 251st 252nd 253rd 254th 255th 256th 257th 258th 259th 260th 261st 262nd 263rd 264th 265th 1000th 1001st 1002nd 1003rd 1004th 1005th 1006th 1007th 1008th 1009th 1010th 1011th 1012th 1013th 1014th 1015th 1016th 1017th 1018th 1019th 1020th 1021st 1022nd 1023rd 1024th 1025th
Forth
<lang forth>: 'nth ( -- c-addr ) s" th st nd rd th th th th th th " drop ;
- .nth ( n -- )
dup 10 20 within if 0 .r ." th " exit then dup 0 .r 10 mod 3 * 'nth + 3 type ;
- test ( n n -- ) cr do i 5 mod 0= if cr then i .nth loop ;
- tests ( -- )
26 0 test 266 250 test 1026 1000 test ;
tests</lang>
- Output:
0th 1st 2nd 3rd 4th 5th 6th 7th 8th 9th 10th 11th 12th 13th 14th 15th 16th 17th 18th 19th 20th 21st 22nd 23rd 24th 25th 250th 251st 252nd 253rd 254th 255th 256th 257th 258th 259th 260th 261st 262nd 263rd 264th 265th 1000th 1001st 1002nd 1003rd 1004th 1005th 1006th 1007th 1008th 1009th 1010th 1011st 1012nd 1013rd 1014th 1015th 1016th 1017th 1018th 1019th 1020th 1021st 1022nd 1023rd 1024th 1024th ok
Fortran
THE INSTRUCTIONS! Write a function/method/subroutine/... that when given an integer greater than or equal to zero returns a string of the number followed by an apostrophe then the ordinal suffix. Example returns would include 1'st 2'nd 3'rd 11'th 111'th 1001'st 1012'th
Please find the compilation instructions and examples in comments at the start of the source. <lang Fortran>!-*- mode: compilation; default-directory: "/tmp/" -*- !Compilation started at Fri Jun 6 15:40:18 ! !a=./f && make -k $a && echo 0 25 | $a && echo 250 265 | $a && echo 1000 1025 | $a !gfortran -std=f2008 -Wall -fopenmp -ffree-form -fall-intrinsics -fimplicit-none -g f.f08 -o f ! 0'th 1'st 2'nd ! 3'rd 4'th 5'th ! 6'th 7'th 8'th ! 9'th 10'th 11'th ! 12'th 13'th 14'th ! 15'th 16'th 17'th ! 18'th 19'th 20'th ! 21'st 22'nd 23'rd ! 24'th 25'th ! 250'th 251'st ! 252'nd 253'rd 254'th ! 255'th 256'th 257'th ! 258'th 259'th 260'th ! 261'st 262'nd 263'rd ! 264'th 265'th ! 1000th 1001st ! 1002nd 1003rd 1004th ! 1005th 1006th 1007th ! 1008th 1009th 1010th ! 1011th 1012th 1013th ! 1014th 1015th 1016th ! 1017th 1018th 1019th ! 1020th 1021st 1022nd ! 1023rd 1024th 1025th ! !Compilation finished at Fri Jun 6 15:40:18
program nth
implicit none
logical :: need
integer :: here, there, n, i, iostat
read(5,*,iostat=iostat) here, there
if (iostat .ne. 0) then
write(6,*)'such bad input never before seen.'
write(6,*)'I AYE EYE QUIT!'
call exit(1)
end if
need = .false.
n = abs(there - here) + 1
i = 0
do while (0 /= mod(3+mod(here-i, 3), 3))
write(6,'(a22)',advance='no')
i = i+1
end do
do i = here, there, sign(1, there-here)
write(6,'(a22)',advance='no') ordinate(i)
if (2 /= mod(i,3)) then
need = .true.
else
write(6,'(a)')
need = .false.
end if
end do
if (need) write(6,'(a)')
contains
character(len=22) function ordinate(n)
character(len=19) :: a
character(len=20), parameter :: &
&a09 = "thstndrdthththththth",&
&ateen = "thththththththththth"
integer :: ones, tens, ones_index
integer, intent(in) :: n
write(a,'(i19)') n
ones = mod(n,10)
tens = mod(n,100)
ones_index = ones*2+1
if (n < 1000) then
if ((10 .le. tens) .and. (tens .lt. 20)) then
ordinate = a // "'" // ateen(ones_index:ones_index+1)
! ^^^^^^ remove these characters to remove the important '
else
ordinate = a // "'" // a09(ones_index:ones_index+1)
! ^^^^^^ remove these characters to remove the important '
end if
else
if ((10 .le. tens) .and. (tens .lt. 20)) then
ordinate = a // ateen(ones_index:ones_index+1)
else
ordinate = a // a09(ones_index:ones_index+1)
end if
end if
end function ordinate
end program nth</lang>
FreeBASIC
<lang freebasic>' FB 1.05.0 Win64
' Apostrophes NOT used as incorrect English
Function ordinal(n As UInteger) As String
Dim ns As String = Str(n)
Select Case Right(ns, 1)
Case "0", "4" To "9"
Return ns + "th"
Case "1"
If Right(ns, 2) = "11" Then Return ns + "th"
Return ns + "st"
Case "2"
If Right(ns, 2) = "12" Then Return ns + "th"
Return ns + "nd"
Case "3"
If Right(ns, 2) = "13" Then Return ns + "th"
Return ns + "rd"
End Select
End Function
Dim i As Integer For i = 0 To 25
Print ordinal(i); " ";
Next Print : Print
For i = 250 To 265
Print ordinal(i); " ";
Next Print : Print
For i = 1000 To 1025
Print ordinal(i); " ";
Next Print : Print
Print "Press any key to quit" Sleep</lang>
- Output:
0th 1st 2nd 3rd 4th 5th 6th 7th 8th 9th 10th 11th 12th 13th 14th 15th 16th 17th 18th 19th 20th 21st 22nd 23rd 24th 25th 250th 251st 252nd 253rd 254th 255th 256th 257th 258th 259th 260th 261st 262nd 263rd 264th 265th 1000th 1001st 1002nd 1003rd 1004th 1005th 1006th 1007th 1008th 1009th 1010th 1011th 1012th 1013th 1014th 1015th 1016th 1017th 1018th 1019th 1020th 1021st 1022nd 1023rd 1024th 1025th
Gambas
Click this link to run this code <lang gambas>Public Sub Main() Dim siNums As Short[] = [0, 25, 250, 265, 1000, 1025] Dim siCount, siNumbers As Short Dim sOrdinal As String
For siNumbers = 0 To 4 Step 2
For siCount = siNums[siNumbers] To siNums[siNumbers + 1] sOrdinal = "th" If Right(Str(siCount), 1) = "1" And Right(Str(siCount), 2) <> "11" Then sOrdinal = "st" If Right(Str(siCount), 1) = "2" And Right(Str(siCount), 2) <> "12" Then sOrdinal = "nd" If Right(Str(siCount), 1) = "3" And Right(Str(siCount), 2) <> "13" Then sOrdinal = "rd" Print siCount & sOrdinal;; Next Print gb.NewLine
Next
End </lang> Output:
0th 1st 2nd 3rd 4th 5th 6th 7th 8th 9th 10th 11th 12th 13th 14th 15th 16th 17th 18th 19th 20th 21st 22nd 23rd 24th 25th 250th 251st 252nd 253rd 254th 255th 256th 257th 258th 259th 260th 261st 262nd 263rd 264th 265th 1000th 1001st 1002nd 1003rd 1004th 1005th 1006th 1007th 1008th 1009th 1010th 1011th 1012th 1013th 1014th 1015th 1016th 1017th 1018th 1019th 1020th 1021st 1022nd 1023rd 1024th 1025th
Go
<lang go>package main
import "fmt"
func ord(n int) string {
s := "th"
switch c := n % 10; c {
case 1, 2, 3:
if n%100/10 == 1 {
break
}
switch c {
case 1:
s = "st"
case 2:
s = "nd"
case 3:
s = "rd"
}
}
return fmt.Sprintf("%d%s", n, s)
}
func main() {
for n := 0; n <= 25; n++ {
fmt.Printf("%s ", ord(n))
}
fmt.Println()
for n := 250; n <= 265; n++ {
fmt.Printf("%s ", ord(n))
}
fmt.Println()
for n := 1000; n <= 1025; n++ {
fmt.Printf("%s ", ord(n))
}
fmt.Println()
}</lang>
- Output:
0th 1st 2nd 3rd 4th 5th 6th 7th 8th 9th 10th 11th 12th 13th 14th 15th 16th 17th 18th 19th 20th 21st 22nd 23rd 24th 25th 250th 251st 252nd 253rd 254th 255th 256th 257th 258th 259th 260th 261st 262nd 263rd 264th 265th 1000th 1001st 1002nd 1003rd 1004th 1005th 1006th 1007th 1008th 1009th 1010th 1011th 1012th 1013th 1014th 1015th 1016th 1017th 1018th 1019th 1020th 1021st 1022nd 1023rd 1024th 1025th
GW-BASIC
<lang qbasic> 10 ' N'th 20 LET LOLIM% = 0 30 LET HILIM% = 25 40 GOSUB 1000 50 LET LOLIM% = 250 60 LET HILIM% = 265 70 GOSUB 1000 80 LET LOLIM% = 1000 90 LET HILIM% = 1025 100 GOSUB 1000 110 END
995 ' Print images 1000 FOR I% = LOLIM% TO HILIM% 1010 LET NR% = I% 1020 GOSUB 1500 1030 LET SI$ = STR$(I%) 1040 PRINT RIGHT$(SI$, LEN(SI$) - 1); SUF$; " "; 1050 NEXT I% 1060 PRINT 1070 RETURN
1495 ' Get suffix 1500 IF (NR% MOD 10 = 1) AND (NR% MOD 100 <> 11) THEN LET SUF$ = "st": GOTO 2000 1600 IF (NR% MOD 10 = 2) AND (NR% MOD 100 <> 12) THEN LET SUF$ = "nd": GOTO 2000 1700 IF (NR% MOD 10 = 3) AND (NR% MOD 100 <> 13) THEN LET SUF$ = "rd": GOTO 2000 1800 LET SUF$ = "th" 2000 RETURN </lang>
- Output:
0th 1st 2nd 3rd 4th 5th 6th 7th 8th 9th 10th 11th 12th 13th 14th 15th 16th 17th 18th 19th 20th 21st 22nd 23rd 24th 25th 250th 251st 252nd 253rd 254th 255th 256th 257th 258th 259th 260th 261st 262nd 263rd 264th 265th 1000th 1001st 1002nd 1003rd 1004th 1005th 1006th 1007th 1008th 1009th 1010th 1011th 1012th 1013th 1014th 1015th 1016th 1017th 1018th 1019th 1020th 1021st 1022nd 1023rd 1024th 1025th
Haskell
<lang haskell>import Data.Array
ordSuffs :: Array Integer String ordSuffs = listArray (0,9) ["th", "st", "nd", "rd", "th",
"th", "th", "th", "th", "th"]
ordSuff :: Integer -> String ordSuff n = show n ++ suff n
where suff m | (m `rem` 100) >= 11 && (m `rem` 100) <= 13 = "th"
| otherwise = ordSuffs ! (m `rem` 10)
printOrdSuffs :: [Integer] -> IO () printOrdSuffs = putStrLn . unwords . map ordSuff
main :: IO () main = do
printOrdSuffs [ 0.. 25] printOrdSuffs [ 250.. 265] printOrdSuffs [1000..1025]</lang>
- Output:
0th 1st 2nd 3rd 4th 5th 6th 7th 8th 9th 10th 11th 12th 13th 14th 15th 16th 17th 18th 19th 20th 21st 22nd 23rd 24th 25th 250th 251st 252nd 253rd 254th 255th 256th 257th 258th 259th 260th 261st 262nd 263rd 264th 265th 1000th 1001st 1002nd 1003rd 1004th 1005th 1006th 1007th 1008th 1009th 1010th 1011th 1012th 1013th 1014th 1015th 1016th 1017th 1018th 1019th 1020th 1021st 1022nd 1023rd 1024th 1025th
Icon and Unicon
The following works in both languages. <lang unicon>procedure main(A)
every writes(" ",nth(0 to 25) | "\n")
every writes(" ",nth(250 to 265) | "\n")
every writes(" ",nth(1000 to 1025) | "\n")
end
procedure nth(n)
return n || ((n%10 = 1, n%100 ~= 11, "st") |
(n%10 = 2, n%100 ~= 12, "nd") |
(n%10 = 3, n%100 ~= 13, "rd") | "th")
end</lang>
- Output:
->nth 0th 1st 2nd 3rd 4th 5th 6th 7th 8th 9th 10th 11th 12th 13h 14th 15th 16th 17th 18th 19th 20th 21st 22nd 23rd 24th 25th 250th 251st 252nd 253rd 254th 255th 256th 257th 258th 259th 260th 261st 262nd 263rd 264th 265th 1000th 1001st 1002nd 1003rd 1004th 1005th 1006th 1007th 1008th 1009th 1010th 1011th 1012th 1013h 1014th 1015th 1016th 1017th 1018th 1019th 1020th 1021st 1022nd 1023rd 1024th 1025th ->
J
Implementation:
<lang J>suf=: (;:'th st nd rd th') {::~ 4 <. 10 10 (* 1&~:)~/@#: ] nth=: [: ;:inv (": , suf)each</lang>
Task:
<lang J> thru=: <./ + i.@(+ *)@-~
nth 0 thru 25
0th 1st 2nd 3rd 4th 5th 6th 7th 8th 9th 10th 11th 12th 13th 14th 15th 16th 17th 18th 19th 20th 21st 22nd 23rd 24th 25th
nth 250 thru 265
250th 251st 252nd 253rd 254th 255th 256th 257th 258th 259th 260th 261st 262nd 263rd 264th 265th
nth 1000 thru 1025
1000th 1001st 1002nd 1003rd 1004th 1005th 1006th 1007th 1008th 1009th 1010th 1011th 1012th 1013th 1014th 1015th 1016th 1017th 1018th 1019th 1020th 1021st 1022nd 1023rd 1024th 1025th</lang>
Java
<lang java>public class Nth { public static String ordinalAbbrev(int n){ String ans = "th"; //most of the time it should be "th" if(n % 100 / 10 == 1) return ans; //teens are all "th" switch(n % 10){ case 1: ans = "st"; break; case 2: ans = "nd"; break; case 3: ans = "rd"; break; } return ans; }
public static void main(String[] args){ for(int i = 0; i <= 25;i++){ System.out.print(i + ordinalAbbrev(i) + " "); } System.out.println(); for(int i = 250; i <= 265;i++){ System.out.print(i + ordinalAbbrev(i) + " "); } System.out.println(); for(int i = 1000; i <= 1025;i++){ System.out.print(i + ordinalAbbrev(i) + " "); } } }</lang>
<lang java>package nth;
import java.util.stream.IntStream; import java.util.stream.Stream;
public interface Nth {
public static String suffix(int n){
if(n % 100 / 10 == 1){
return "th"; //teens are all "th"
}
switch(n % 10){
case 1: return "st";
case 2: return "nd";
case 3: return "rd";
default: return "th"; //most of the time it should be "th"
}
}
public static void print(int start, int end) {
IntStream.rangeClosed(start, end)
.parallel()
.mapToObj(i -> i + suffix(i) + " ")
.reduce(String::concat)
.ifPresent(System.out::println)
;
}
public static void print(int[] startAndEnd) {
print(startAndEnd[0], startAndEnd[1]);
}
public static int[] startAndEnd(int start, int end) {
return new int[] {
start,
end
};
}
public static void main(String... arguments){
Stream.of(
startAndEnd(0, 25),
startAndEnd(250, 265),
startAndEnd(1000, 1025)
)
.forEach(Nth::print)
;
}
}</lang>
- Output:
0th 1st 2nd 3rd 4th 5th 6th 7th 8th 9th 10th 11th 12th 13th 14th 15th 16th 17th 18th 19th 20th 21st 22nd 23rd 24th 25th 250th 251st 252nd 253rd 254th 255th 256th 257th 258th 259th 260th 261st 262nd 263rd 264th 265th 1000th 1001st 1002nd 1003rd 1004th 1005th 1006th 1007th 1008th 1009th 1010th 1011th 1012th 1013th 1014th 1015th 1016th 1017th 1018th 1019th 1020th 1021st 1022nd 1023rd 1024th 1025th
JavaScript
ES5
<lang JavaScript>console.log(function () {
var lstSuffix = 'th st nd rd th th th th th th'.split(' '),
fnOrdinalForm = function (n) {
return n.toString() + (
11 <= n % 100 && 13 >= n % 100 ?
"th" : lstSuffix[n % 10]
);
},
range = function (m, n) {
return Array.apply(
null, Array(n - m + 1)
).map(function (x, i) {
return m + i;
});
};
return [[0, 25], [250, 265], [1000, 1025]].map(function (tpl) {
return range.apply(null, tpl).map(fnOrdinalForm).join(' ');
}).join('\n\n');
}());</lang>
- Output:
<lang JavaScript>0th 1st 2nd 3rd 4th 5th 6th 7th 8th 9th 10th 11th 12th 13th 14th 15th 16th 17th 18th 19th 20th 21st 22nd 23rd 24th 25th
250th 251st 252nd 253rd 254th 255th 256th 257th 258th 259th 260th 261st 262nd 263rd 264th 265th
1000th 1001st 1002nd 1003rd 1004th 1005th 1006th 1007th 1008th 1009th 1010th 1011th 1012th 1013th 1014th 1015th 1016th 1017th 1018th 1019th 1020th 1021st 1022nd 1023rd 1024th 1025th</lang>
ES6
<lang JavaScript>(function (lstTestRanges) {
'use strict'
let lstSuffix = 'th st nd rd th th th th th th'.split(' '),
// ordinalString :: Int -> String
ordinalString = n =>
n.toString() + (
11 <= n % 100 && 13 >= n % 100 ?
"th" : lstSuffix[n % 10]
),
// range :: Int -> Int -> [Int]
range = (m, n) =>
Array.from({
length: (n - m) + 1
}, (_, i) => m + i);
return lstTestRanges
.map(tpl => range
.apply(null, tpl)
.map(ordinalString)
);
})([[0, 25], [250, 265], [1000, 1025]]);</lang>
- Output:
[["0th", "1st", "2nd", "3rd", "4th", "5th", "6th", "7th", "8th", "9th", "10th", "11th", "12th", "13th", "14th", "15th", "16th", "17th", "18th", "19th", "20th", "21st", "22nd", "23rd", "24th", "25th"], ["250th", "251st", "252nd", "253rd", "254th", "255th", "256th", "257th", "258th", "259th", "260th", "261st", "262nd", "263rd", "264th", "265th"], ["1000th", "1001st", "1002nd", "1003rd", "1004th", "1005th", "1006th", "1007th", "1008th", "1009th", "1010th", "1011th", "1012th", "1013th", "1014th", "1015th", "1016th", "1017th", "1018th", "1019th", "1020th", "1021st", "1022nd", "1023rd", "1024th", "1025th"]]
jq
<lang jq>
- ordinalize an integer input, positive or negative
def ordinalize:
(if . < 0 then -(.) else . end) as $num
| ($num % 100) as $small
| (if 11 <= $small and $small <= 13 then "th"
else
( $num % 10)
| (if . == 1 then "st"
elif . == 2 then "nd"
elif . == 3 then "rd"
else "th"
end)
end) as $ordinal
| "\(.)\($ordinal)" ;
([range(-5; -1)], [range(0;26)], [range(250;266)], [range(1000;1026)])
| map(ordinalize)
</lang>
- Output:
["-5th","-4th","-3rd","-2nd"] ["0th","1st","2nd","3rd","4th","5th","6th","7th","8th","9th","10th","11th","12th","13th","14th","15th","16th","17th","18th","19th","20th","21st","22nd","23rd","24th","25th"] ["250th","251st","252nd","253rd","254th","255th","256th","257th","258th","259th","260th","261st","262nd","263rd","264th","265th"] ["1000th","1001st","1002nd","1003rd","1004th","1005th","1006th","1007th","1008th","1009th","1010th","1011th","1012th","1013th","1014th","1015th","1016th","1017th","1018th","1019th","1020th","1021st","1022nd","1023rd","1024th","1025th"]
Julia
<lang julia>using Printf</lang> Function: <lang julia>function ordinal(n::Integer)
n < 0 && throw(DomainError())
suffixes = ("st", "nd", "rd")
u = n % 10
t = n ÷ 10 % 10
if u > 3 || u == 0 || t == 1
suf = "th"
else
suf = suffixes[u]
end
return string(n, suf)
end</lang>
Main: <lang julia>println("Tests of ordinal formatting of integers.") for (i, n) in enumerate(0:25)
(i - 1) % 10 == 0 && println()
@printf("%7s", ordinal(n))
end
println() for (i, n) in enumerate(250:265)
(i - 1) % 10 == 0 && println()
@printf("%7s", ordinal(n))
end
println() for (i, n) in enumerate(1000:1025)
(i - 1) % 10 == 0 && println()
@printf("%7s", ordinal(n))
end</lang> Main2: <lang julia>Nth(x::Integer) = if x % 100 ∈ [11, 12, 13] "th" else ["th", "st", "nd", "rd", "th"][min(x % 10 + 1, 5)] end NthA(x::Integer) = "$(x)'$(Nth(x)) " [0:25..., 250:265..., 1000:1025...] .|> NthA .|> print;</lang>
- Output:
Tests of ordinal formatting of integers.
0th 1st 2nd 3rd 4th 5th 6th 7th 8th 9th
10th 11th 12th 13th 14th 15th 16th 17th 18th 19th
20th 21st 22nd 23rd 24th 25th
250th 251st 252nd 253rd 254th 255th 256th 257th 258th 259th
260th 261st 262nd 263rd 264th 265th
1000th 1001st 1002nd 1003rd 1004th 1005th 1006th 1007th 1008th 1009th
1010th 1011th 1012th 1013th 1014th 1015th 1016th 1017th 1018th 1019th
1020th 1021st 1022nd 1023rd 1024th 1025th
Kotlin
<lang scala>fun Int.ordinalAbbrev() =
if (this % 100 / 10 == 1) "th"
else when (this % 10) { 1 -> "st" 2 -> "nd" 3 -> "rd" else -> "th" }
fun IntRange.ordinalAbbrev() = map { "$it" + it.ordinalAbbrev() }.joinToString(" ")
fun main(args: Array<String>) {
listOf((0..25), (250..265), (1000..1025)).forEach { println(it.ordinalAbbrev()) }
}</lang>
Lambdatalk
Translation from the javascript entry <lang scheme> {def fnOrdinalForm
{lambda {:n}
{if {and {<= 11 {% :n 100}} {>= 13 {% :n 100}}}
then :nth
else :n{A.get {% :n 10} th st nd rd th th th th th th}}}}
-> fnOrdinalForm
{S.map fnOrdinalForm {S.serie 0 25}} -> 0th 1st 2nd 3rd 4th 5th 6th 7th 8th 9th 10th 11th 12th 13th 14th 15th
16th 17th 18th 19th 20th 21st 22nd 23rd 24th 25th
{S.map fnOrdinalForm {S.serie 250 265}} -> 250th 251st 252nd 253rd 254th 255th 256th 257th 258th 259th 260th 261st 262nd 263rd 264th 265th
{S.map fnOrdinalForm {S.serie 1000 1025}} -> 1000th 1001st 1002nd 1003rd 1004th 1005th 1006th 1007th 1008th 1009th 1010th 1011th 1012th 1013th 1014th 1015th 1016th 1017th 1018th 1019th 1020th 1021st 1022nd 1023rd 1024th 1025th </lang>
Liberty BASIC
<lang lb> call printImages 0, 25 call printImages 250, 265 call printImages 1000, 1025 end
sub printImages loLim, hiLim
loLim = int(loLim) hiLIm = int(hiLim) for i = loLim to hiLim print str$(i) + suffix$(i) + " "; next i print
end sub
function suffix$(n)
n = int(n)
nMod10 = n mod 10
nMod100 = n mod 100
if (nMod10 = 1) and (nMod100 <> 11) then
suffix$ = "st"
else
if (nMod10 = 2) and (nMod100 <> 12) then
suffix$ = "nd"
else
if (NMod10 = 3) and (NMod100 <> 13) then
suffix$ = "rd"
else
suffix$ = "th"
end if
end if
end if
end function </lang>
- Output:
0th 1st 2nd 3th 4th 5th 6th 7th 8th 9th 10th 11th 12th 13th 14th 15th 16th 17th 18th 19th 20th 21st 22nd 23th 24th 25th 250th 251st 252nd 253th 254th 255th 256th 257th 258th 259th 260th 261st 262nd 263th 264th 265th 1000th 1001st 1002nd 1003th 1004th 1005th 1006th 1007th 1008th 1009th 1010th 1011th 1012th 1013th 1014th 1015th 1016th 1017th 1018th 1019th 1020th 1021st 1022nd 1023th 1024th 1025th
Lua
The apostrophe just looks weird if you ask me. No one did, obviously. <lang Lua>function getSuffix (n)
local lastTwo, lastOne = n % 100, n % 10 if lastTwo > 3 and lastTwo < 21 then return "th" end if lastOne == 1 then return "st" end if lastOne == 2 then return "nd" end if lastOne == 3 then return "rd" end return "th"
end
function Nth (n) return n .. "'" .. getSuffix(n) end
for i = 0, 25 do print(Nth(i), Nth(i + 250), Nth(i + 1000)) end</lang>
- Output:
0'th 250'th 1000'th 1'st 251'st 1001'st 2'nd 252'nd 1002'nd 3'rd 253'rd 1003'rd 4'th 254'th 1004'th 5'th 255'th 1005'th 6'th 256'th 1006'th 7'th 257'th 1007'th 8'th 258'th 1008'th 9'th 259'th 1009'th 10'th 260'th 1010'th 11'th 261'st 1011'th 12'th 262'nd 1012'th 13'th 263'rd 1013'th 14'th 264'th 1014'th 15'th 265'th 1015'th 16'th 266'th 1016'th 17'th 267'th 1017'th 18'th 268'th 1018'th 19'th 269'th 1019'th 20'th 270'th 1020'th 21'st 271'st 1021'st 22'nd 272'nd 1022'nd 23'rd 273'rd 1023'rd 24'th 274'th 1024'th 25'th 275'th 1025'th
Maple
<lang maple>toOrdinal := proc(n:: nonnegint) if 1 <= n and n <= 10 then if n >= 4 then printf("%ath", n); elif n = 3 then printf("%ard", n); elif n = 2 then printf("%and", n); else printf("%ast", n); end if: else printf(convert(n, 'ordinal')); end if: return NULL; end proc:
a := [[0, 25], [250, 265], [1000, 1025]]: for i in a do for j from i[1] to i[2] do toOrdinal(j); printf(" "); end do; printf("\n\n"); end do;</lang>
- Output:
0th 1st 2nd 3rd 4th 5th 6th 7th 8th 9th 10th 11th 12th 13th 14th 15th 16th 17th 18th 19th 20th 21st 22nd 23rd 24th 25th 250th 251st 252nd 253rd 254th 255th 256th 257th 258th 259th 260th 261st 262nd 263rd 264th 265th 1000th 1001st 1002nd 1003rd 1004th 1005th 1006th 1007th 1008th 1009th 1010th 1011th 1012th 1013th 1014th 1015th 1016th 1017th 1018th 1019th 1020th 1021st 1022nd 1023rd 1024th 1025th
Mathematica/Wolfram Language
I borrowed the logic from the Python code. <lang Mathematica>suffixlist = {"th", "st", "nd", "rd", "th", "th", "th", "th", "th","th"}; addsuffix[n_] := Module[{suffix},
suffix = Which[ Mod[n, 100] <= 10, suffixlist[[Mod[n, 10] + 1]], Mod[n, 100] > 20, suffixlist[[Mod[n, 10] + 1]], True, "th" ]; ToString[n] <> suffix ]
addsuffix[#] & /@ Range[0, 25] (* test 1 *) addsuffix[#] & /@ Range[250, 265] (* test 2 *) addsuffix[#] & /@ Range[1000, 1025] (* test 3 *)</lang>
- Output:
{"0th", "1st", "2nd", "3rd", "4th", "5th", "6th", "7th", "8th", "9th", "10th", "11th", "12th", "13th", "14th", "15th", "16th", "17th", "18th", "19th", "20th", "21st", "22nd", "23rd", "24th", "25th"}
{"250th", "251st", "252nd", "253rd", "254th", "255th", "256th", "257th", "258th", "259th", "260th", "261st", "262nd", "263rd", "264th", "265th"}
{"1000th", "1001st", "1002nd", "1003rd", "1004th", "1005th", "1006th", "1007th", "1008th", "1009th", "1010th", "1011th", "1012th", "1013th", "1014th", "1015th", "1016th", "1017th", "1018th", "1019th", "1020th", "1021st", "1022nd", "1023rd", "1024th", "1025th"}
MATLAB
<lang MATLAB>function s = nth(n)
tens = mod(n, 100);
if tens > 9 && tens < 20
suf = 'th';
else
switch mod(n, 10)
case 1
suf = 'st';
case 2
suf = 'nd';
case 3
suf = 'rd';
otherwise
suf = 'th';
end
end
s = sprintf('%d%s', n, suf);
end</lang>
- Output:
0th 1st 2nd 3rd 4th 5th 6th 7th 8th 9th 10th 11th 12th 13th 14th 15th 16th 17th 18th 19th 20th 21st 22nd 23rd 24th 25th 250th 251st 252nd 253rd 254th 255th 256th 257th 258th 259th 260th 261st 262nd 263rd 264th 265th 1000th 1001st 1002nd 1003rd 1004th 1005th 1006th 1007th 1008th 1009th 1010th 1011th 1012th 1013th 1014th 1015th 1016th 1017th 1018th 1019th 1020th 1021st 1022nd 1023rd 1024th 1025th
Microsoft Small Basic
<lang microsoftsmallbasic> loLim = 0 hiLim = 25 PrintImages() loLim = 250 hiLim = 265 PrintImages() loLim = 1000 hiLim = 1025 PrintImages()
Sub PrintImages
For i = loLim To hiLim
nr = i
GetSuffix()
TextWindow.Write(i + suffix + " ")
EndFor
TextWindow.WriteLine("")
EndSub
Sub GetSuffix
rem10 = Math.Remainder(nr, 10) rem100 = Math.Remainder(nr, 100) If rem10 = 1 And rem100 <> 11 Then suffix = "st" ElseIf rem10 = 2 And rem100 <> 12 Then suffix = "nd" ElseIf rem10 = 3 And rem100 <> 13 Then suffix = "rd" Else suffix = "th" EndIf
EndSub </lang>
MiniScript
To get the output all on one line, we append it to a list as we go, and then print the list all at once at the end.
<lang MiniScript>ordinal = function(n)
if n > 3 and n < 20 then return n + "th" if n % 10 == 1 then return n + "st" if n % 10 == 2 then return n + "nd" if n % 10 == 3 then return n + "rd" return n + "th"
end function
out = [] test = function(from, to)
for i in range(from, to)
out.push ordinal(i)
end for
end function
test 0, 25 test 250, 265 test 1000, 1025 print out.join</lang>
- Output:
0th 1st 2nd 3rd 4th 5th 6th 7th 8th 9th 10th 11th 12th 13th 14th 15th 16th 17th 18th 19th 20th 21st 22nd 23rd 24th 25th 250th 251st 252nd 253rd 254th 255th 256th 257th 258th 259th 260th 261st 262nd 263rd 264th 265th 1000th 1001st 1002nd 1003rd 1004th 1005th 1006th 1007th 1008th 1009th 1010th 1011st 1012nd 1013rd 1014th 1015th 1016th 1017th 1018th 1019th 1020th 1021st 1022nd 1023rd 1024th 1025th
Modula-2
<lang modula2> MODULE Nth;
FROM STextIO IMPORT
WriteString, WriteLn;
FROM WholeStr IMPORT
IntToStr;
PROCEDURE Suffix(N: CARDINAL; VAR OUT Destination: ARRAY OF CHAR); VAR
NMod10, NMod100: CARDINAL;
BEGIN
NMod10 := N MOD 10; NMod100 := N MOD 100; IF (NMod10 = 1) AND (NMod100 <> 11) THEN Destination := "st"; ELSIF (NMod10 = 2) AND (NMod100 <> 12) THEN Destination := "nd"; ELSIF (NMod10 = 3) AND (NMod100 <> 13) THEN Destination := "rd"; ELSE Destination := "th"; END;
END Suffix;
PROCEDURE PrintImages(LoLim, HiLim: CARDINAL); VAR
I: CARDINAL; IString: ARRAY [0 .. 15] OF CHAR; ISuff: ARRAY [0 .. 1] OF CHAR;
BEGIN
FOR I := LoLim TO HiLim DO
IntToStr(I, IString);
Suffix(I, ISuff);
WriteString(IString);
WriteString(ISuff);
WriteString(" ");
END;
WriteLn;
END PrintImages;
BEGIN
PrintImages( 0, 25); PrintImages( 250, 265); PrintImages(1000, 1025);
END Nth. </lang>
Nanoquery
<lang nanoquery>def ordinalAbbrev(n)
if int(n % 100 / 10) = 1
return "th"
end
if n % 10 = 1
return "st"
else if n % 10 = 2
return "nd"
else if n % 10 = 3
return "rd"
else
return "th"
end
end
for i in range(0, 25)
print (i + "'" + ordinalAbbrev(i) + " ")
end println
for i in range(250, 265)
print (i + "'" + ordinalAbbrev(i) + " ")
end println
for i in range(1000, 1025)
print (i + "'" + ordinalAbbrev(i) + " ")
end println</lang>
- Output:
0'th 1'st 2'nd 3'rd 4'th 5'th 6'th 7'th 8'th 9'th 10'th 11'th 12'th 13'th 14'th 15'th 16'th 17'th 18'th 19'th 20'th 21'st 22'nd 23'rd 24'th 25'th 250'th 251'st 252'nd 253'rd 254'th 255'th 256'th 257'th 258'th 259'th 260'th 261'st 262'nd 263'rd 264'th 265'th 1000'th 1001'st 1002'nd 1003'rd 1004'th 1005'th 1006'th 1007'th 1008'th 1009'th 1010'th 1011'th 1012'th 1013'th 1014'th 1015'th 1016'th 1017'th 1018'th 1019'th 1020'th 1021'st 1022'nd 1023'rd 1024'th 1025'th
Nim
<lang nim>const Suffix = ["th", "st", "nd", "rd", "th", "th", "th", "th", "th", "th"]
proc nth(n: Natural): string =
$n & "'" & (if n mod 100 in 11..20: "th" else: Suffix[n mod 10])
for j in countup(0, 1000, 250):
for i in j..j+24: stdout.write nth(i), " " echo ""</lang>
- Output:
0'th 1'st 2'nd 3'rd 4'th 5'th 6'th 7'th 8'th 9'th 10'th 11'th 12'th 13'th 14'th 15'th 16'th 17'th 18'th 19'th 20'th 21'st 22'nd 23'rd 24'th 250'th 251'st 252'nd 253'rd 254'th 255'th 256'th 257'th 258'th 259'th 260'th 261'st 262'nd 263'rd 264'th 265'th 266'th 267'th 268'th 269'th 270'th 271'st 272'nd 273'rd 274'th 500'th 501'st 502'nd 503'rd 504'th 505'th 506'th 507'th 508'th 509'th 510'th 511'th 512'th 513'th 514'th 515'th 516'th 517'th 518'th 519'th 520'th 521'st 522'nd 523'rd 524'th 750'th 751'st 752'nd 753'rd 754'th 755'th 756'th 757'th 758'th 759'th 760'th 761'st 762'nd 763'rd 764'th 765'th 766'th 767'th 768'th 769'th 770'th 771'st 772'nd 773'rd 774'th 1000'th 1001'st 1002'nd 1003'rd 1004'th 1005'th 1006'th 1007'th 1008'th 1009'th 1010'th 1011'th 1012'th 1013'th 1014'th 1015'th 1016'th 1017'th 1018'th 1019'th 1020'th 1021'st 1022'nd 1023'rd 1024'th
Objeck
<lang objeck>class Nth {
function : OrdinalAbbrev(n : Int ) ~ String {
ans := "th"; # most of the time it should be "th"
if(n % 100 / 10 = 1) {
return ans; # teens are all "th"
};
select(n % 10){
label 1: { ans := "st"; }
label 2: { ans := "nd"; }
label 3: { ans := "rd"; }
};
return ans;
}
function : Main(args : String[]) ~ Nil {
for(i := 0; i <= 25; i+=1;) {
abbr := OrdinalAbbrev(i);
"{$i}{$abbr} "->Print();
};
""->PrintLine();
for(i := 250; i <= 265; i+=1;) {
abbr := OrdinalAbbrev(i);
"{$i}{$abbr} "->Print();
};
""->PrintLine();
for(i := 1000; i <= 1025; i+=1;) {
abbr := OrdinalAbbrev(i);
"{$i}{$abbr} "->Print();
};
}
}</lang>
- Output:
0th 1st 2nd 3rd 4th 5th 6th 7th 8th 9th 10th 11th 12th 13th 14th 15th 16th 17th 18th 19th 20th 21st 22nd 23rd 24th 25th 250th 251st 252nd 253rd 254th 255th 256th 257th 258th 259th 260th 261st 262nd 263rd 264th 265th 1000th 1001st 1002nd 1003rd 1004th 1005th 1006th 1007th 1008th 1009th 1010th 1011th 1012th 1013th 1014th 1015th 1016th 1017th 1018th 1019th 1020th 1021st 1022nd 1023rd 1024th 1025th
OCaml
<lang Ocaml> let show_nth n =
if (n mod 10 = 1) && (n mod 100 <> 11) then "st" else if (n mod 10 = 2) && (n mod 100 <> 12) then "nd" else if (n mod 10 = 3) && (n mod 100 <> 13) then "rd" else "th"
let () =
let show_ordinals (min, max) =
for i=min to max do
Printf.printf "%d%s " i (show_nth i)
done;
print_newline() in
List.iter show_ordinals [ (0,25); (250,265); (1000,1025) ]
</lang>
- Output:
0th 1st 2nd 3rd 4th 5th 6th 7th 8th 9th 10th 11th 12th 13th 14th 15th 16th 17th 18th 19th 20th 21st 22nd 23rd 24th 25th 250th 251st 252nd 253rd 254th 255th 256th 257th 258th 259th 260th 261st 262nd 263rd 264th 265th 1000th 1001st 1002nd 1003rd 1004th 1005th 1006th 1007th 1008th 1009th 1010th 1011th 1012th 1013th 1014th 1015th 1016th 1017th 1018th 1019th 1020th 1021st 1022nd 1023rd 1024th 1025th
Oforth
<lang Oforth>: nth(n) | r |
n "th" over 10 mod ->r r 1 == ifTrue: [ n 100 mod 11 == ifFalse: [ drop "st" ] ] r 2 == ifTrue: [ n 100 mod 12 == ifFalse: [ drop "nd" ] ] r 3 == ifTrue: [ n 100 mod 13 == ifFalse: [ drop "rd" ] ] + ;</lang>
- Output:
seqFrom(0, 25) map(#nth) println [0th, 1st, 2nd, 3rd, 4th, 5th, 6th, 7th, 8th, 9th, 10th, 11th, 12th, 13th, 14th, 15th, 16t h, 17th, 18th, 19th, 20th, 21st, 22nd, 23rd, 24th, 25th] seqFrom(250, 265) map(#nth) println [250th, 251st, 252nd, 253rd, 254th, 255th, 256th, 257th, 258th, 259th, 260th, 261st, 262nd , 263rd, 264th, 265th] seqFrom(1000, 1025) map(#nth) println [1000th, 1001st, 1002nd, 1003rd, 1004th, 1005th, 1006th, 1007th, 1008th, 1009th, 1010th, 1 011th, 1012th, 1013th, 1014th, 1015th, 1016th, 1017th, 1018th, 1019th, 1020th, 1021st, 102 2nd, 1023rd, 1024th, 1025th]
PARI/GP
(Spurious apostrophes intentionally omitted, following Raku.)
<lang parigp>ordinal(n)=my(k=n%10,m=n%100); Str(n,if(m<21&&m>3,"th",k==1,"st",k==2,"nd",k==3,"rd","th")); apply(ordinal, [0..25]) apply(ordinal, [250..265]) apply(ordinal, [1000..1025]) apply(ordinal, [111, 1012])</lang>
- Output:
%1 = ["0th", "1st", "2nd", "3rd", "4th", "5th", "6th", "7th", "8th", "9th", "10th", "11th", "12th", "13th", "14th", "15th", "16th", "17th", "18th", "19th", "20th", "21st", "22nd", "23rd", "24th", "25th"] %2 = ["250th", "251st", "252nd", "253rd", "254th", "255th", "256th", "257th", "258th", "259th", "260th", "261st", "262nd", "263rd", "264th", "265th"] %3 = ["1000th", "1001st", "1002nd", "1003rd", "1004th", "1005th", "1006th", "1007th", "1008th", "1009th", "1010th", "1011th", "1012th", "1013th", "1014th", "1015th", "1016th", "1017th", "1018th", "1019th", "1020th", "1021st", "1022nd", "1023rd", "1024th", "1025th"] %4 = ["111th", "1012th"]
Pascal
nearly copy of Ada <lang pascal>Program n_th;
function Suffix(N: NativeInt):AnsiString; var
res: AnsiString;
begin
res:= 'th';
case N mod 10 of
1:IF N mod 100 <> 11 then
res:= 'st';
2:IF N mod 100 <> 12 then
res:= 'nd';
3:IF N mod 100 <> 13 then
res:= 'rd';
else
end;
Suffix := res;
end;
procedure Print_Images(loLim, HiLim: NativeInt); var
i : NativeUint;
begin
for I := LoLim to HiLim do write(i,Suffix(i),' '); writeln;
end;
begin
Print_Images( 0, 25); Print_Images( 250, 265); Print_Images(1000, 1025);
end.</lang>
- Output:
shortened
0th 1st 2nd 3rd 4th ... 11th 12th 13th ..20th 21st 22nd 23rd 24th 25th 250th 251st 252nd 253rd 254th ..261st 262nd 263rd 264th 265th ..1001st 1002nd 1003rd 1004th..1011th..1013th..1021st 1022nd 1023rd 1024th
Perl
Requires Perl 5.10 or newer for the Defined OR operator (//). <lang perl>use 5.10.0; my %irregulars = ( 1 => 'st',
2 => 'nd',
3 => 'rd',
11 => 'th',
12 => 'th',
13 => 'th');
sub nth {
my $n = shift;
$n . # q(') . # Uncomment this to add apostrophes to output
($irregulars{$n % 100} // $irregulars{$n % 10} // 'th');
}
sub range { join ' ', map { nth($_) } @{$_[0]} } print range($_), "\n" for ([0..25], [250..265], [1000..1025]);</lang>
- Output:
0th 1st 2nd 3rd 4th 5th 6th 7th 8th 9th 10th 11th 12th 13th 14th 15th 16th 17th 18th 19th 20th 21st 22nd 23rd 24th 25th 250th 251st 252nd 253rd 254th 255th 256th 257th 258th 259th 260th 261st 262nd 263rd 264th 265th 1000th 1001st 1002nd 1003rd 1004th 1005th 1006th 1007th 1008th 1009th 1010th 1011th 1012th 1013th 1014th 1015th 1016th 1017th 1018th 1019th 1020th 1021st 1022nd 1023rd 1024th 1025th
Alternatively, can use a library.
<lang perl>use Lingua::EN::Numbers::Ordinate 'ordinate'; foreach my $i (0..25, 250..265, 1000..1025) {
print ordinate($i),"\n";
}</lang>
Phix
constant ordinals = {"th","st","nd","rd"} function Nth(integer n, bool apostrophe=false) integer mod10 = mod(n,10)+1 if mod10>4 or mod(n,100)=mod10+9 then mod10 = 1 end if return sprintf("%d%s",{n,repeat('\'',apostrophe)&ordinals[mod10]}) end function constant ranges = {{0,25},{250,265},{1000,1025}} for i=1 to length(ranges) do for j=ranges[i][1] to ranges[i][2] do if mod(j,10)=0 then puts(1,"\n") end if printf(1," %6s",{Nth(j,i=2)}) end for puts(1,"\n") end for
- Output:
0th 1st 2nd 3rd 4th 5th 6th 7th 8th 9th 10th 11th 12th 13th 14th 15th 16th 17th 18th 19th 20th 21st 22nd 23rd 24th 25th 250'th 251'st 252'nd 253'rd 254'th 255'th 256'th 257'th 258'th 259'th 260'th 261'st 262'nd 263'rd 264'th 265'th 1000th 1001st 1002nd 1003rd 1004th 1005th 1006th 1007th 1008th 1009th 1010th 1011th 1012th 1013th 1014th 1015th 1016th 1017th 1018th 1019th 1020th 1021st 1022nd 1023rd 1024th 1025th
Alternatively you can use the builtin ord(), and a more functional style, as follows (same output)
function do_one(integer n, string apostrophe) return pad_head(sprintf("%d%s%s",{n,apostrophe,ord(n)}),7) end function procedure do_set(sequence s, bool bApostrophe=false) puts(1,join_by(apply(true,do_one,{s,{repeat('`',bApostrophe)}}),1,10,"")&"\n") end procedure constant {rs,re} = columnize({{0,25},{250,265},{1000,1025}}) papply(true,do_set,{apply(true,tagset,{re,rs}),{false,true,false}})
PHP
<lang PHP>function nth($num) {
$os = "th";
if ($num % 100 <= 10 or $num % 100 > 20) {
switch ($num % 10) {
case 1:
$os = "st";
break;
case 2:
$os = "nd";
break;
case 3:
$os = "rd";
break;
}
}
return $num . $os;
}
foreach ([[0,25], [250,265], [1000,1025]] as $i) {
while ($i[0] <= $i[1]) {
echo nth($i[0]) . " ";
$i[0]++;
}
echo "\n";
}</lang>
- Output:
0th 1st 2nd 3rd 4th 5th 6th 7th 8th 9th 10th 11th 12th 13th 14th 15th 16th 17th 18th 19th 20th 21st 22nd 23rd 24th 25th 250th 251st 252nd 253rd 254th 255th 256th 257th 258th 259th 260th 261st 262nd 263rd 264th 265th 1000th 1001st 1002nd 1003rd 1004th 1005th 1006th 1007th 1008th 1009th 1010th 1011th 1012th 1013th 1014th 1015th 1016th 1017th 1018th 1019th 1020th 1021st 1022nd 1023rd 1024th 1025th
Picat
nth/3 is a built-in predicate in Picat, so let's call the functions nth2/1 and onward.
Prolog style
<lang Picat>nth2(N) = N.to_string() ++ Th =>
( tween(N) -> Th = "th" ; 1 = N mod 10 -> Th = "st" ; 2 = N mod 10 -> Th = "nd" ; 3 = N mod 10 -> Th = "rd" ; Th = "th" ).
tween(N) => Tween = N mod 100, between(11, 13, Tween).</lang>
Function with explicit conditions
<lang Picat>nth3(N) = cc(N,"th"), tween(N) => true. nth3(N) = cc(N,"st"), N mod 10 = 1 => true. nth3(N) = cc(N,"nd"), N mod 10 = 2 => true. nth3(N) = cc(N,"rd"), N mod 10 = 3 => true. nth3(N) = cc(N,"th") => true. % helper function cc(N,Th) = N.to_string() ++ Th.</lang>
List of suffixes
<lang Picat>nth4(N) = Nth =>
Suffix = ["th","st","nd","rd","th","th","th","th","th","th"], Nth = N.to_string() ++ cond((N mod 100 <= 10; N mod 100 > 20), Suffix[1 + N mod 10], "th").</lang>
Test
<lang Picat>go =>
Ranges = [ 0..25, 250..265, 1000..1025], foreach(Range in Ranges) println([nth2(I) : I in Range]) end, nl.</lang>
- Output:
[0th,1st,2nd,3rd,4th,5th,6th,7th,8th,9th,10th,11th,12th,13th,14th,15th,16th,17th,18th,19th,20th,21st,22nd,23rd,24th,25th] [250th,251st,252nd,253rd,254th,255th,256th,257th,258th,259th,260th,261st,262nd,263rd,264th,265th] [1000th,1001st,1002nd,1003rd,1004th,1005th,1006th,1007th,1008th,1009th,1010th,1011th,1012th,1013th,1014th,1015th,1016th,1017th,1018th,1019th,1020th,1021st,1022nd,1023rd,1024th,1025th]
PicoLisp
<lang PicoLisp>(de rangeth (A B)
(mapcar
'((I)
(pack I
(if (member (% I 100) (11 12 13))
'th
(case (% I 10)
(1 'st)
(2 'nd)
(3 'rd)
(T 'th) ) ) ) )
(range A B) ) )
(prinl (glue " " (rangeth 0 25))) (prinl (glue " " (rangeth 250 265))) (prinl (glue " " (rangeth 1000 1025)))
(bye)</lang>
- Output:
0th 1st 2nd 3rd 4th 5th 6th 7th 8th 9th 10th 11th 12th 13th 14th 15th 16th 17th 18th 19th 20th 21st 22nd 23rd 24th 25th 250th 251st 252nd 253rd 254th 255th 256th 257th 258th 259th 260th 261st 262nd 263rd 264th 265th 1000th 1001st 1002nd 1003rd 1004th 1005th 1006th 1007th 1008th 1009th 1010th 1011th 1012th 1013th 1014th 1015th 1016th 1017th 1018th 1019th 1020th 1021st 1022nd 1023rd 1024th 1025th
PL/I
<lang>Nth: procedure options (main); /* 1 June 2014 */
declare i fixed (10);
do i = 0 to 25, 250 to 265, 1000 to 1025;
if i = 250 | i = 1000 then put skip (2);
put edit (enth(i)) (x(1), a);
end;
enth: procedure (i) returns (character (25) varying);
declare i fixed (10); declare suffix character (2);
select (mod(i, 10));
when (1) suffix = 'st';
when (2) suffix = 'nd';
when (3) suffix = 'rd';
otherwise suffix = 'th';
end;
select (mod(i, 100));
when (11, 12, 13) suffix = 'th';
otherwise ;
end;
return ( trim(i) || suffix );
end enth;
end Nth;</lang>
- Output:
0th 1st 2nd 3rd 4th 5th 6th 7th 8th 9th 10th 11th 12th 13th 14th 15th 16th 17th 18th 19th 20th 21st 22nd 23rd 24th 25th 250th 251st 252nd 253rd 254th 255th 256th 257th 258th 259th 260th 261st 262nd 263rd 264th 265th 1000th 1001st 1002nd 1003rd 1004th 1005th 1006th 1007th 1008th 1009th 1010th 1011th 1012th 1013th 1014th 1015th 1016th 1017th 1018th 1019th 1020th 1021st 1022nd 1023rd 1024th 1025th
PowerShell
<lang powershell>function nth($inp){ $suffix = "th"
switch($inp % 10){ 1{$suffix="st"} 2{$suffix="nd"} 3{$suffix="rd"} } return "$inp$suffix " }
0..25 | %{Write-host -nonewline (nth "$_")};"" 250..265 | %{Write-host -nonewline (nth "$_")};"" 1000..1025 | %{Write-host -nonewline (nth "$_")};""</lang>
- Output:
0th 1st 2nd 3rd 4th 5th 6th 7th 8th 9th 10th 11st 12nd 13rd 14th 15th 16th 17th 18th 19th 20th 21st 22nd 23rd 24th 25th 250th 251st 252nd 253rd 254th 255th 256th 257th 258th 259th 260th 261st 262nd 263rd 264th 265th 1000th 1001st 1002nd 1003rd 1004th 1005th 1006th 1007th 1008th 1009th 1010th 1011st 1012nd 1013rd 1014th 1015th 1016th 1017th 1018th 1019th 1020th 1021st 1022nd 1023rd 1024th 1025th
An Alternate Version
This is, I think, is a more "PowerShelly" way: <lang PowerShell> function Get-Nth ([int]$Number) {
$suffix = "th"
switch ($Number % 10)
{
1 {$suffix = "st"}
2 {$suffix = "nd"}
3 {$suffix = "rd"}
}
"$Number$suffix"
}
1..25 | ForEach-Object {Get-Nth $_} | Format-Wide {$_} -Column 5 -Force 251..265 | ForEach-Object {Get-Nth $_} | Format-Wide {$_} -Column 5 -Force 1001..1025 | ForEach-Object {Get-Nth $_} | Format-Wide {$_} -Column 5 -Force </lang>
- Output:
1st 2nd 3rd 4th 5th 6th 7th 8th 9th 10th 11st 12nd 13rd 14th 15th 16th 17th 18th 19th 20th 21st 22nd 23rd 24th 25th 251st 252nd 253rd 254th 255th 256th 257th 258th 259th 260th 261st 262nd 263rd 264th 265th 1001st 1002nd 1003rd 1004th 1005th 1006th 1007th 1008th 1009th 1010th 1011st 1012nd 1013rd 1014th 1015th 1016th 1017th 1018th 1019th 1020th 1021st 1022nd 1023rd 1024th 1025th
Prolog
Following Icon:
<lang prolog>nth(N, N_Th) :-
( tween(N) -> Th = "th" ; 1 is N mod 10 -> Th = "st" ; 2 is N mod 10 -> Th = "nd" ; 3 is N mod 10 -> Th = "rd" ; Th = "th" ), string_concat(N, Th, N_Th).
tween(N) :- Tween is N mod 100, between(11, 13, Tween).
test :-
forall( between(0,25, N), (nth(N, N_Th), format('~w, ', N_Th)) ),
nl, nl,
forall( between(250,265,N), (nth(N, N_Th), format('~w, ', N_Th)) ),
nl, nl,
forall( between(1000,1025,N), (nth(N, N_Th), format('~w, ', N_Th)) ).
</lang>
- Output:
of `test/0`
?- test. 0th, 1st, 2nd, 3rd, 4th, 5th, 6th, 7th, 8th, 9th, 10th, 11th, 12th, 13th, 14th, 15th, 16th, 17th, 18th, 19th, 20th, 21st, 22nd, 23rd, 24th, 25th, 250th, 251st, 252nd, 253rd, 254th, 255th, 256th, 257th, 258th, 259th, 260th, 261st, 262nd, 263rd, 264th, 265th, 1000th, 1001st, 1002nd, 1003rd, 1004th, 1005th, 1006th, 1007th, 1008th, 1009th, 1010th, 1011th, 1012th, 1013th, 1014th, 1015th, 1016th, 1017th, 1018th, 1019th, 1020th, 1021st, 1022nd, 1023rd, 1024th, 1025th, true.
PureBasic
<lang PureBasic>Procedure.s Suffix(n.i)
Select n%10 Case 1 : If n%100<>11 : ProcedureReturn "st" : EndIf Case 2 : If n%100<>12 : ProcedureReturn "nd" : EndIf Case 3 : If n%100<>13 : ProcedureReturn "rd" : EndIf EndSelect ProcedureReturn "th"
EndProcedure
Procedure put(a.i,b.i)
For i=a To b : Print(Str(i)+Suffix(i)+" ") : Next
PrintN("")
EndProcedure
If OpenConsole()=0 : End 1 : EndIf put(0,25) put(250,265) put(1000,1025) Input()</lang>
- Output:
0th 1st 2nd 3rd 4th 5th 6th 7th 8th 9th 10th 11th 12th 13th 14th 15th 16th 17th 18th 19th 20th 21st 22nd 23rd 24th 25th 250th 251st 252nd 253rd 254th 255th 256th 257th 258th 259th 260th 261st 262nd 263rd 264th 265th 1000th 1001st 1002nd 1003rd 1004th 1005th 1006th 1007th 1008th 1009th 1010th 1011th 1012th 1013th 1014th 1015th 1016th 1017th 1018th 1019th 1020th 1021st 1022nd 1023rd 1024th 1025th
Python
<lang python>_suffix = ['th', 'st', 'nd', 'rd', 'th', 'th', 'th', 'th', 'th', 'th']
def nth(n):
return "%i'%s" % (n, _suffix[n%10] if n % 100 <= 10 or n % 100 > 20 else 'th')
if __name__ == '__main__':
for j in range(0,1001, 250):
print(' '.join(nth(i) for i in list(range(j, j+25))))</lang>
- Output:
0'th 1'st 2'nd 3'rd 4'th 5'th 6'th 7'th 8'th 9'th 10'th 11'th 12'th 13'th 14'th 15'th 16'th 17'th 18'th 19'th 20'th 21'st 22'nd 23'rd 24'th 250'th 251'st 252'nd 253'rd 254'th 255'th 256'th 257'th 258'th 259'th 260'th 261'st 262'nd 263'rd 264'th 265'th 266'th 267'th 268'th 269'th 270'th 271'st 272'nd 273'rd 274'th 500'th 501'st 502'nd 503'rd 504'th 505'th 506'th 507'th 508'th 509'th 510'th 511'th 512'th 513'th 514'th 515'th 516'th 517'th 518'th 519'th 520'th 521'st 522'nd 523'rd 524'th 750'th 751'st 752'nd 753'rd 754'th 755'th 756'th 757'th 758'th 759'th 760'th 761'st 762'nd 763'rd 764'th 765'th 766'th 767'th 768'th 769'th 770'th 771'st 772'nd 773'rd 774'th 1000'th 1001'st 1002'nd 1003'rd 1004'th 1005'th 1006'th 1007'th 1008'th 1009'th 1010'th 1011'th 1012'th 1013'th 1014'th 1015'th 1016'th 1017'th 1018'th 1019'th 1020'th 1021'st 1022'nd 1023'rd 1024'th
Alternate version <lang python>#!/usr/bin/env python3
def ord(n):
try:
s = ['st', 'nd', 'rd'][(n-1)%10]
if (n-10)%100//10:
return str(n)+s
except IndexError:
pass
return str(n)+'th'
if __name__ == '__main__':
print(*(ord(n) for n in range(26))) print(*(ord(n) for n in range(250,266))) print(*(ord(n) for n in range(1000,1026)))</lang>
- Output:
0th 1st 2nd 3rd 4th 5th 6th 7th 8th 9th 10th 11th 12th 13th 14th 15th 16th 17th 18th 19th 20th 21st 22nd 23rd 24th 25th 250th 251st 252nd 253rd 254th 255th 256th 257th 258th 259th 260th 261st 262nd 263rd 264th 265th 1000th 1001st 1002nd 1003rd 1004th 1005th 1006th 1007th 1008th 1009th 1010th 1011th 1012th 1013th 1014th 1015th 1016th 1017th 1018th 1019th 1020th 1021st 1022nd 1023rd 1024th 1025th
Quackery
<lang Quackery> [ table ] is suffix ( n --> $ )
$ "th st nd rd th th th th th th" nest$ witheach [ ' suffix put ]
[ dup number$
swap dup 100 mod
10 21 within iff
[ drop $ "th" join ]
else
[ 10 mod
suffix join ] ] is ordinal$ ( n --> $ )
[ over - 1+
[] swap times
[ over i^ + ordinal$
nested join ]
nip 50 wrap$ ] is test ( n n --> )
0 25 test cr 250 265 test cr 1000 1025 test</lang>
- Output:
0th 1st 2nd 3rd 4th 5th 6th 7th 8th 9th 10th 11th 12th 13th 14th 15th 16th 17th 18th 19th 20th 21st 22nd 23rd 24th 25th 250th 251st 252nd 253rd 254th 255th 256th 257th 258th 259th 260th 261st 262nd 263rd 264th 265th 1000th 1001st 1002nd 1003rd 1004th 1005th 1006th 1007th 1008th 1009th 1010th 1011th 1012th 1013th 1014th 1015th 1016th 1017th 1018th 1019th 1020th 1021st 1022nd 1023rd 1024th 1025th
R
Note that R vectors are 1-indexed. <lang rsplus>nth <- function(n) {
if (length(n) > 1) return(sapply(n, nth))
mod <- function(m, n) ifelse(!(m%%n), n, m%%n)
suffices <- c("th", "st", "nd", "rd", "th", "th", "th", "th", "th", "th")
if (n %% 100 <= 10 || n %% 100 > 20)
suffix <- suffices[mod(n+1, 10)]
else
suffix <- 'th'
paste(n, "'", suffix, sep="")
}
range <- list(0:25, 250:275, 500:525, 750:775, 1000:1025)
sapply(range, nth)</lang>
- Output:
[,1] [,2] [,3] [,4] [,5] [1,] "0'th" "250'th" "500'th" "750'th" "1000'th" [2,] "1'st" "251'st" "501'st" "751'st" "1001'st" [3,] "2'nd" "252'nd" "502'nd" "752'nd" "1002'nd" [4,] "3'rd" "253'rd" "503'rd" "753'rd" "1003'rd" [5,] "4'th" "254'th" "504'th" "754'th" "1004'th" [6,] "5'th" "255'th" "505'th" "755'th" "1005'th" [7,] "6'th" "256'th" "506'th" "756'th" "1006'th" [8,] "7'th" "257'th" "507'th" "757'th" "1007'th" [9,] "8'th" "258'th" "508'th" "758'th" "1008'th" [10,] "9'th" "259'th" "509'th" "759'th" "1009'th" [11,] "10'th" "260'th" "510'th" "760'th" "1010'th" [12,] "11'th" "261'st" "511'th" "761'st" "1011'th" [13,] "12'th" "262'nd" "512'th" "762'nd" "1012'th" [14,] "13'th" "263'rd" "513'th" "763'rd" "1013'th" [15,] "14'th" "264'th" "514'th" "764'th" "1014'th" [16,] "15'th" "265'th" "515'th" "765'th" "1015'th" [17,] "16'th" "266'th" "516'th" "766'th" "1016'th" [18,] "17'th" "267'th" "517'th" "767'th" "1017'th" [19,] "18'th" "268'th" "518'th" "768'th" "1018'th" [20,] "19'th" "269'th" "519'th" "769'th" "1019'th" [21,] "20'th" "270'th" "520'th" "770'th" "1020'th" [22,] "21'st" "271'st" "521'st" "771'st" "1021'st" [23,] "22'nd" "272'nd" "522'nd" "772'nd" "1022'nd" [24,] "23'rd" "273'rd" "523'rd" "773'rd" "1023'rd" [25,] "24'th" "274'th" "524'th" "774'th" "1024'th" [26,] "25'th" "275'th" "525'th" "775'th" "1025'th"
Racket
<lang racket>#lang racket (define (teen? n) (<= 11 (modulo n 100) 19)) (define (Nth n)
(format
"~a'~a" n
(match* ((modulo n 10) n)
[((or 1 2 3) (? teen?)) 'th] [(1 _) 'st] [(2 _) 'nd] [(3 _) 'rd] [(_ _) 'th])))
(for ((range (list (in-range 26) (in-range 250 266) (in-range 1000 1026))))
(displayln (string-join (for/list ((nth (sequence-map Nth range))) nth) " ")))</lang>
- Output:
0'th 1'st 2'nd 3'rd 4'th 5'th 6'th 7'th 8'th 9'th 10'th 11'th 12'th 13'th 14'th 15'th 16'th 17'th 18'th 19'th 20'th 21'st 22'nd 23'rd 24'th 25'th 250'th 251'st 252'nd 253'rd 254'th 255'th 256'th 257'th 258'th 259'th 260'th 261'st 262'nd 263'rd 264'th 265'th 1000'th 1001'st 1002'nd 1003'rd 1004'th 1005'th 1006'th 1007'th 1008'th 1009'th 1010'th 1011'th 1012'th 1013'th 1014'th 1015'th 1016'th 1017'th 1018'th 1019'th 1020'th 1021'st 1022'nd 1023'rd 1024'th 1025'th
Raku
(formerly Perl 6) (Spurious apostrophes intentionally omitted.) <lang perl6>my %irregulars = <1 st 2 nd 3 rd>, (11..13 X=> 'th');
sub nth ($n) { $n ~ ( %irregulars{$n % 100} // %irregulars{$n % 10} // 'th' ) }
say .list».&nth for [^26], [250..265], [1000..1025];</lang>
- Output:
0th 1st 2nd 3rd 4th 5th 6th 7th 8th 9th 10th 11th 12th 13th 14th 15th 16th 17th 18th 19th 20th 21st 22nd 23rd 24th 25th 250th 251st 252nd 253rd 254th 255th 256th 257th 258th 259th 260th 261st 262nd 263rd 264th 265th 1000th 1001st 1002nd 1003rd 1004th 1005th 1006th 1007th 1008th 1009th 1010th 1011th 1012th 1013th 1014th 1015th 1016th 1017th 1018th 1019th 1020th 1021st 1022nd 1023rd 1024th 1025th
If you want to get Unicodally fancy, use this version instead: <lang perl6>my %irregulars = <1 ˢᵗ 2 ⁿᵈ 3 ʳᵈ>, (11..13 X=> 'ᵗʰ');
sub nth ($n) { $n ~ ( %irregulars{$n % 100} // %irregulars{$n % 10} // 'ᵗʰ' ) }
say .list».&nth for [^26], [250..265], [1000..1025];</lang>
- Output:
0ᵗʰ 1ˢᵗ 2ⁿᵈ 3ʳᵈ 4ᵗʰ 5ᵗʰ 6ᵗʰ 7ᵗʰ 8ᵗʰ 9ᵗʰ 10ᵗʰ 11ᵗʰ 12ᵗʰ 13ᵗʰ 14ᵗʰ 15ᵗʰ 16ᵗʰ 17ᵗʰ 18ᵗʰ 19ᵗʰ 20ᵗʰ 21ˢᵗ 22ⁿᵈ 23ʳᵈ 24ᵗʰ 25ᵗʰ
250ᵗʰ 251ˢᵗ 252ⁿᵈ 253ʳᵈ 254ᵗʰ 255ᵗʰ 256ᵗʰ 257ᵗʰ 258ᵗʰ 259ᵗʰ 260ᵗʰ 261ˢᵗ 262ⁿᵈ 263ʳᵈ 264ᵗʰ 265ᵗʰ
1000ᵗʰ 1001ˢᵗ 1002ⁿᵈ 1003ʳᵈ 1004ᵗʰ 1005ᵗʰ 1006ᵗʰ 1007ᵗʰ 1008ᵗʰ 1009ᵗʰ 1010ᵗʰ 1011ᵗʰ 1012ᵗʰ 1013ᵗʰ 1014ᵗʰ 1015ᵗʰ 1016ᵗʰ 1017ᵗʰ 1018ᵗʰ 1019ᵗʰ 1020ᵗʰ 1021ˢᵗ 1022ⁿᵈ 1023ʳᵈ 1024ᵗʰ 1025ᵗʰ
Red
<lang rebol>Red[]
nth: function [n][
d: n % 10 suffix: either any [d < 1 d > 4 1 = to-integer n / 10] [4] [d] rejoin [n pick ["st" "nd" "rd" "th"] suffix]
]
test: function [low high][
repeat i high - low + 1 [
prin [nth i + low - 1 ""]
]
prin newline
]
test 0 25 test 250 265 test 1000 1025</lang>
- Output:
0th 1st 2nd 3rd 4th 5th 6th 7th 8th 9th 10th 11th 12th 13th 14th 15th 16th 17th 18th 19th 20th 21st 22nd 23rd 24th 25th 250th 251st 252nd 253rd 254th 255th 256th 257th 258th 259th 260th 261st 262nd 263rd 264th 265th 1000th 1001st 1002nd 1003rd 1004th 1005th 1006th 1007th 1008th 1009th 1010th 1011st 1012nd 1013rd 1014th 1015th 1016th 1017th 1018th 1019th 1020th 1021st 1022nd 1023rd 1024th 1025th
REXX
This version adds suffixes without apostrophes.
Negative numbers and fractions are also handled. <lang rexx>/*REXX program shows ranges of numbers with ordinal (st/nd/rd/th) suffixes attached.*/ call tell 0, 25 /*display the 1st range of numbers. */ call tell 250, 265 /* " " 2nd " " " */ call tell 1000, 1025 /* " " 3rd " " " */ exit /*stick a fork in it, we're all done. */ /*──────────────────────────────────────────────────────────────────────────────────────*/ tell: procedure; parse arg L,H,,$ /*get the Low and High #s, nullify list*/
do j=L to H; $=$ th(j); end /*process the range, from low ───► high*/
say 'numbers from ' L " to " H ' (inclusive):' /*display the title. */
say strip($); say; say /*display line; 2 sep*/
return /*return to invoker. */
/*──────────────────────────────────────────────────────────────────────────────────────*/ th: parse arg z; x=abs(z); return z||word('th st nd rd',1+x//10*(x//100%10\==1)*(x//10<4))</lang> output using the default inputs:
numbers from 0 to 25 (inclusive): 0th 1st 2nd 3rd 4th 5th 6th 7th 8th 9th 10th 11th 12th 13th 14th 15th 16th 17th 18th 19th 20th 21st 22nd 23rd 24th 25th numbers from 250 to 265 (inclusive): 250th 251st 252nd 253rd 254th 255th 256th 257th 258th 259th 260th 261st 262nd 263rd 264th 265th numbers from 1000 to 1025 (inclusive): 1000th 1001st 1002nd 1003rd 1004th 1005th 1006th 1007th 1008th 1009th 1010th 1011th 1012th 1013th 1014th 1015th 1016th 1017th 1018th 1019th 1020th 1021st 1022nd 1023rd 1024th 1025th
Ring
<lang ring> for nr = 0 to 25
see Nth(nr) + Nth(nr + 250) + Nth(nr + 1000) + nl
next
func getSuffix n
lastTwo = n % 100
lastOne = n % 10
if lastTwo > 3 and lastTwo < 21 "th" ok
if lastOne = 1 return "st" ok
if lastOne = 2 return "nd" ok
if lastOne = 3 return "rd" ok
return "th"
func Nth n
return "" + n + "'" + getSuffix(n) + " "
</lang>
Ruby
Code (slightly adapted) and methodname taken from ActiveSupport (Ruby on Rails). <lang ruby>class Integer
def ordinalize
num = self.abs
ordinal = if (11..13).include?(num % 100)
"th"
else
case num % 10
when 1; "st"
when 2; "nd"
when 3; "rd"
else "th"
end
end
"#{self}#{ordinal}"
end
end
[(0..25),(250..265),(1000..1025)].each{|r| puts r.map(&:ordinalize).join(", "); puts} </lang>
- Output:
0th, 1st, 2nd, 3rd, 4th, 5th, 6th, 7th, 8th, 9th, 10th, 11th, 12th, 13th, 14th, 15th, 16th, 17th, 18th, 19th, 20th, 21st, 22nd, 23rd, 24th, 25th 250th, 251st, 252nd, 253rd, 254th, 255th, 256th, 257th, 258th, 259th, 260th, 261st, 262nd, 263rd, 264th, 265th 1000th, 1001st, 1002nd, 1003rd, 1004th, 1005th, 1006th, 1007th, 1008th, 1009th, 1010th, 1011th, 1012th, 1013th, 1014th, 1015th, 1016th, 1017th, 1018th, 1019th, 1020th, 1021st, 1022nd, 1023rd, 1024th, 1025th
Rust
<lang rust>fn nth(num: isize) -> String {
format!("{}{}", num, match (num % 10, num % 100) {
(1, 11) | (2, 12) | (3, 13) => "th",
(1, _) => "st",
(2, _) => "nd",
(3, _) => "rd",
_ => "th",
})
}
fn main() {
let ranges = [(0, 26), (250, 266), (1000, 1026)];
for &(s, e) in &ranges {
println!("[{}, {}) :", s, e);
for i in s..e {
print!("{}, ", nth(i));
}
println!();
}
}</lang>
- Output:
[0, 26) : 0th, 1st, 2nd, 3rd, 4th, 5th, 6th, 7th, 8th, 9th, 10th, 11th, 12th, 13th, 14th, 15th, 16th, 17th, 18th, 19th, 20th, 21st, 22nd, 23rd, 24th, 25th, [250, 266) : 250th, 251st, 252nd, 253rd, 254th, 255th, 256th, 257th, 258th, 259th, 260th, 261st, 262nd, 263rd, 264th, 265th, [1000, 1026) : 1000th, 1001st, 1002nd, 1003rd, 1004th, 1005th, 1006th, 1007th, 1008th, 1009th, 1010th, 1011th, 1012th, 1013th, 1014th, 1015th, 1016th, 1017th, 1018th, 1019th, 1020th, 1021st, 1022nd, 1023rd, 1024th, 1025th,
Scala
<lang Scala>object Nth extends App {
def abbrevNumber(i: Int) = print(s"$i${ordinalAbbrev(i)} ")
def ordinalAbbrev(n: Int) = {
val ans = "th" //most of the time it should be "th"
if (n % 100 / 10 == 1) ans //teens are all "th"
else (n % 10) match {
case 1 => "st"
case 2 => "nd"
case 3 => "rd"
case _ => ans
}
}
(0 to 25).foreach(abbrevNumber) println() (250 to 265).foreach(abbrevNumber) println(); (1000 to 1025).foreach(abbrevNumber)
}</lang>
Seed7
<lang seed7>$ include "seed7_05.s7i";
const func string: suffix (in integer: num) is func
result var string: suffix is ""; begin if num rem 10 = 1 and num rem 100 <> 11 then suffix := "st"; elsif num rem 10 = 2 and num rem 100 <> 12 then suffix := "nd"; elsif num rem 10 = 3 and num rem 100 <> 13 then suffix := "rd"; else suffix := "th"; end if; end func;
const proc: printImages (in integer: start, in integer: stop) is func
local
var integer: num is 0;
begin
for num range start to stop do
write(num <& suffix(num) <& " ");
end for;
writeln;
end func;
const proc: main is func
begin printImages( 0, 25); printImages( 250, 265); printImages(1000, 1025); end func;</lang>
- Output:
0th 1st 2nd 3rd 4th 5th 6th 7th 8th 9th 10th 11th 12th 13th 14th 15th 16th 17th 18th 19th 20th 21st 22nd 23rd 24th 25th 250th 251st 252nd 253rd 254th 255th 256th 257th 258th 259th 260th 261st 262nd 263rd 264th 265th 1000th 1001st 1002nd 1003rd 1004th 1005th 1006th 1007th 1008th 1009th 1010th 1011th 1012th 1013th 1014th 1015th 1016th 1017th 1018th 1019th 1020th 1021st 1022nd 1023rd 1024th 1025th
Set lang
Due to the language's specification, the input can only contain one character. Therefore, the following code only works with 0-9. <lang set_lang>set o 49 set t 50 set h 51 set n ! set ! n set ! 39 [n=o] set ? 13 [n=t] set ? 16 [n=h] set ? 19 set ! T set ! H set ? 21 set ! S set ! T set ? 21 set ! N set ! D set ? 12 set ! R set ! D > EOF</lang> Input: I, Output: O
I: 1, O: 1'ST
I: 2, O: 2'ND
I: 3, O: 3'RD
I: 4, O: 4'TH
I: 5, O: 5'TH
...
Sidef
<lang ruby>func nth(n) {
static irregulars = Hash(<1 ˢᵗ 2 ⁿᵈ 3 ʳᵈ 11 ᵗʰ 12 ᵗʰ 13 ᵗʰ>...)
n.to_s + (irregulars{n % 100} \\ irregulars{n % 10} \\ 'ᵗʰ')
}
for r in [0..25, 250..265, 1000..1025] {
say r.map {|n| nth(n) }.join(" ")
}</lang>
- Output:
0ᵗʰ 1ˢᵗ 2ⁿᵈ 3ʳᵈ 4ᵗʰ 5ᵗʰ 6ᵗʰ 7ᵗʰ 8ᵗʰ 9ᵗʰ 10ᵗʰ 11ᵗʰ 12ᵗʰ 13ᵗʰ 14ᵗʰ 15ᵗʰ 16ᵗʰ 17ᵗʰ 18ᵗʰ 19ᵗʰ 20ᵗʰ 21ˢᵗ 22ⁿᵈ 23ʳᵈ 24ᵗʰ 25ᵗʰ 250ᵗʰ 251ˢᵗ 252ⁿᵈ 253ʳᵈ 254ᵗʰ 255ᵗʰ 256ᵗʰ 257ᵗʰ 258ᵗʰ 259ᵗʰ 260ᵗʰ 261ˢᵗ 262ⁿᵈ 263ʳᵈ 264ᵗʰ 265ᵗʰ 1000ᵗʰ 1001ˢᵗ 1002ⁿᵈ 1003ʳᵈ 1004ᵗʰ 1005ᵗʰ 1006ᵗʰ 1007ᵗʰ 1008ᵗʰ 1009ᵗʰ 1010ᵗʰ 1011ᵗʰ 1012ᵗʰ 1013ᵗʰ 1014ᵗʰ 1015ᵗʰ 1016ᵗʰ 1017ᵗʰ 1018ᵗʰ 1019ᵗʰ 1020ᵗʰ 1021ˢᵗ 1022ⁿᵈ 1023ʳᵈ 1024ᵗʰ 1025ᵗʰ
Sinclair ZX81 BASIC
Works flawlessly with 2k or more of RAM. With 1k, the subroutine itself works but you can't quite print all the tests: the program crashes with an 'out of memory' error code after 1017th. (A slightly less useful and readable version gets as far as 1023rd; 1025th is probably attainable, but might involve obfuscating the program more than is appropriate for this site.) <lang basic> 10 FOR N=0 TO 25
20 GOSUB 160 30 PRINT N$;" "; 40 NEXT N 50 PRINT 60 FOR N=250 TO 265 70 GOSUB 160 80 PRINT N$;" "; 90 NEXT N
100 PRINT 110 FOR N=1000 TO 1025 120 GOSUB 160 130 PRINT N$;" "; 140 NEXT N 150 STOP 160 LET N$=STR$ N 170 LET S$="TH" 180 IF LEN N$=1 THEN GOTO 200 190 IF N$(LEN N$-1)="1" THEN GOTO 230 200 IF N$(LEN N$)="1" THEN LET S$="ST" 210 IF N$(LEN N$)="2" THEN LET S$="ND" 220 IF N$(LEN N$)="3" THEN LET S$="RD" 230 LET N$=N$+S$ 240 RETURN</lang>
- Output:
0TH 1ST 2ND 3RD 4TH 5TH 6TH 7TH 8TH 9TH 10TH 11TH 12TH 13TH 14TH 15TH 16TH 17TH 18TH 19TH 20TH 21ST 22ND 23RD 24TH 25TH 250TH 251ST 252ND 253RD 254TH 255TH 256TH 257TH 258TH 259TH 260TH 261ST 262ND 263RD 264TH 265TH 1000TH 1001ST 1002ND 1003RD 1004TH 1005TH 1006TH 1007TH 1008TH 1009TH 1010TH 1011TH 1012TH 1013TH 1014TH 1015TH 1016TH 1017TH 1018TH 1019TH 1020TH 1021ST 1022ND 1023RD 1024TH 1025TH
SQL
Oracle <lang SQL> select level card,
to_char(to_date(level,'j'),'fmjth') ord
from dual connect by level <= 15;
select to_char(to_date(5373485,'j'),'fmjth') from dual; </lang>
CARD ORD
---------- ------------------------------
1 1st
2 2nd
3 3rd
4 4th
5 5th
6 6th
7 7th
8 8th
9 9th
10 10th
11 11th
12 12th
13 13th
14 14th
15 15th
15 rows selected.
select to_char(to_date(5373485,'j'),'fmjth')
*
ERROR at line 1:
ORA-01854: julian date must be between 1 and 5373484
Standard ML
<lang sml>local
val v = Vector.tabulate (10, fn 1 => "st" | 2 => "nd" | 3 => "rd" | _ => "th") fun getSuffix x = if 3 < x andalso x < 21 then "th" else Vector.sub (v, x mod 10)
in
fun nth n = Int.toString n ^ getSuffix (n mod 100)
end
(* some test ouput *) val () = (print o concat o List.tabulate)
(26, fn i => String.concatWith "\t" (map nth [i, i + 250, i + 1000]) ^ "\n")</lang>
- Output:
0th 250th 1000th 1st 251st 1001st 2nd 252nd 1002nd 3rd 253rd 1003rd 4th 254th 1004th 5th 255th 1005th 6th 256th 1006th 7th 257th 1007th 8th 258th 1008th 9th 259th 1009th 10th 260th 1010th 11th 261st 1011th 12th 262nd 1012th 13th 263rd 1013th 14th 264th 1014th 15th 265th 1015th 16th 266th 1016th 17th 267th 1017th 18th 268th 1018th 19th 269th 1019th 20th 270th 1020th 21st 271st 1021st 22nd 272nd 1022nd 23rd 273rd 1023rd 24th 274th 1024th 25th 275th 1025th
Stata
We reuse here the maps function defined in the task Apply a callback to an array.
<lang stata>mata function maps(f,a) { nr = rows(a) nc = cols(a) b = J(nr,nc,"") for (i=1;i<=nr;i++) { for (j=1;j<=nc;j++) b[i,j] = (*f)(a[i,j]) } return(b) }
function nth(n) { k = max((min((mod(n-1,10)+1,4)),4*(mod(n-10,100)<10))) return(strofreal(n)+("st","nd","rd","th")[k]) }
maps(&nth(),((0::25),(250::275),(1000::1025))) end</lang>
Output:
1 2 3
+----------------------------+
1 | 0th 250th 1000th |
2 | 1st 251st 1001st |
3 | 2nd 252nd 1002nd |
4 | 3rd 253rd 1003rd |
5 | 4th 254th 1004th |
6 | 5th 255th 1005th |
7 | 6th 256th 1006th |
8 | 7th 257th 1007th |
9 | 8th 258th 1008th |
10 | 9th 259th 1009th |
11 | 10th 260th 1010th |
12 | 11th 261st 1011th |
13 | 12th 262nd 1012th |
14 | 13th 263rd 1013th |
15 | 14th 264th 1014th |
16 | 15th 265th 1015th |
17 | 16th 266th 1016th |
18 | 17th 267th 1017th |
19 | 18th 268th 1018th |
20 | 19th 269th 1019th |
21 | 20th 270th 1020th |
22 | 21st 271st 1021st |
23 | 22nd 272nd 1022nd |
24 | 23rd 273rd 1023rd |
25 | 24th 274th 1024th |
26 | 25th 275th 1025th |
+----------------------------+
Swift
<lang Swift>func addSuffix(n:Int) -> String {
if n % 100 / 10 == 1 {
return "th"
}
switch n % 10 {
case 1:
return "st"
case 2:
return "nd"
case 3:
return "rd"
default:
return "th"
}
}
for i in 0...25 {
print("\(i)\(addSuffix(i)) ")
} println() for i in 250...265 {
print("\(i)\(addSuffix(i)) ")
} println() for i in 1000...1025 {
print("\(i)\(addSuffix(i)) ")
} println()</lang>
- Output:
0th 1st 2nd 3rd 4th 5th 6th 7th 8th 9th 10th 11th 12th 13th 14th 15th 16th 17th 18th 19th 20th 21st 22nd 23rd 24th 25th 250th 251st 252nd 253rd 254th 255th 256th 257th 258th 259th 260th 261st 262nd 263rd 264th 265th 1000th 1001st 1002nd 1003rd 1004th 1005th 1006th 1007th 1008th 1009th 1010th 1011th 1012th 1013th 1014th 1015th 1016th 1017th 1018th 1019th 1020th 1021st 1022nd 1023rd 1024th 1025th
Tcl
<lang tcl>proc ordinal {n} {
if {$n%100<10 || $n%100>20} {
set suff [lindex {th st nd rd th th th th th th} [expr {$n % 10}]]
} else {
set suff th
} return "$n'$suff"
}
foreach start {0 250 1000} {
for {set n $start; set l {}} {$n<=$start+25} {incr n} {
lappend l [ordinal $n]
} puts $l
}</lang>
- Output:
0'th 1'st 2'nd 3'rd 4'th 5'th 6'th 7'th 8'th 9'th 10'th 11'th 12'th 13'th 14'th 15'th 16'th 17'th 18'th 19'th 20'th 21'st 22'nd 23'rd 24'th 25'th 250'th 251'st 252'nd 253'rd 254'th 255'th 256'th 257'th 258'th 259'th 260'th 261'st 262'nd 263'rd 264'th 265'th 266'th 267'th 268'th 269'th 270'th 271'st 272'nd 273'rd 274'th 275'th 1000'th 1001'st 1002'nd 1003'rd 1004'th 1005'th 1006'th 1007'th 1008'th 1009'th 1010'th 1011'th 1012'th 1013'th 1014'th 1015'th 1016'th 1017'th 1018'th 1019'th 1020'th 1021'st 1022'nd 1023'rd 1024'th 1025'th
True BASIC
<lang basic> SUB sufijo (n)
LET n = INT(n)
LET NMod10 = MOD(n, 10)
LET NMod100 = MOD(n, 100)
IF (NMod10 = 1) AND (NMod100 <> 11) THEN
LET sufi$ = "st"
ELSE
IF (NMod10 = 2) AND (NMod100 <> 12) THEN
LET sufi$ = "nd"
ELSE
IF (NMod10 = 3) AND (NMod100 <> 13) THEN
LET sufi$ = "rd"
ELSE
LET sufi$ = "th"
END IF
END IF
END IF
PRINT sufi$;
END SUB
SUB imprimeOrdinal (loLim, hiLim)
LET loLim = INT(loLim)
LET hiLim = INT(hiLim)
FOR i = loLim TO hiLim
PRINT i;
CALL sufijo (i)
PRINT " ";
NEXT i
PRINT
END SUB
CALL imprimeOrdinal (0, 25) CALL imprimeOrdinal (250, 265) CALL imprimeOrdinal (1000, 1025) END </lang>
TypeScript
<lang javascript> // N'th function suffix(n: number): string {
var nMod10: number = n % 10; var nMod100: number = n % 100; if (nMod10 == 1 && nMod100 != 11) return "st"; else if (nMod10 == 2 && nMod100 != 12) return "nd"; else if (nMod10 == 3 && nMod100 != 13) return "rd"; else return "th";
}
function printImages(loLim: number, hiLim: number) {
for (i = loLim; i <= hiLim; i++)
process.stdout.write(`${i}` + suffix(i) + " ");
process.stdout.write("\n");
}
printImages( 0, 25); printImages( 250, 265); printImages(1000, 1025); </lang>
- Output:
0th 1st 2nd 3rd 4th 5th 6th 7th 8th 9th 10th 11th 12th 13th 14th 15th 16th 17th 18th 19th 20th 21st 22nd 23rd 24th 25th 250th 251st 252nd 253rd 254th 255th 256th 257th 258th 259th 260th 261st 262nd 263rd 264th 265th 1000th 1001st 1002nd 1003rd 1004th 1005th 1006th 1007th 1008th 1009th 1010th 1011th 1012th 1013th 1014th 1015th 1016th 1017th 1018th 1019th 1020th 1021st 1022nd 1023rd 1024th 1025th
uBasic/4tH
<lang>For x = 0 to 25 ' Test range 0..25
Push x : GoSub _PrintOrdinal
Next x : Print
For x = 250 to 265 ' Test range 250..265
Push x : GoSub _PrintOrdinal
Next x : Print
For x = 1000 to 1025 ' Test range 1000..1025
Push x : GoSub _PrintOrdinal
Next x : Print
End ' End test program
' ( n --)
_PrintOrdinal ' Ordinal subroutine
If Tos() > -1 Then ' If within range then
Print Using "____#";Tos();"'"; ' Print the number
' Take care of 11, 12 and 13
If (Tos()%100 > 10) * (Tos()%100 < 14) Then
Gosub (Pop() * 0) + 100 ' Clear stack and print "th"
Return ' We're done here
EndIf
Push Pop() % 10 ' Calculate n mod 10 GoSub 100 + 10 * ((Tos()>0) + (Tos()>1) + (Tos()>2) - (3 * (Pop()>3))) Else ' And decide which ordinal to use Print Pop();" is less than zero" ' Otherwise, it is an error EndIf
Return
' Select and print proper ordinal
100 Print "th"; : Return 110 Print "st"; : Return 120 Print "nd"; : Return 130 Print "rd"; : Return</lang>
- Output:
0'th 1'st 2'nd 3'rd 4'th 5'th 6'th 7'th 8'th 9'th 10'th 11'th 12'th 13'th 14'th 15'th 16'th 17'th 18'th 19'th 20'th 21'st 22'nd 23'rd 24'th 25'th 250'th 251'st 252'nd 253'rd 254'th 255'th 256'th 257'th 258'th 259'th 260'th 261'st 262'nd 263'rd 264'th 265'th 1000'th 1001'st 1002'nd 1003'rd 1004'th 1005'th 1006'th 1007'th 1008'th 1009'th 1010'th 1011'th 1012'th 1013'th 1014'th 1015'th 1016'th 1017'th 1018'th 1019'th 1020'th 1021'st 1022'nd 1023'rd 1024'th 1025'th
UNIX Shell
<lang sh>nth() {
local ordinals=(th st nd rd)
local -i n=$1 i
if (( n < 0 )); then
printf '%s%s\n' - "$(nth $(( -n )) )"
return 0
fi
case $(( n % 100 )) in
11|12|13) i=0;;
*) (( i= n%10 < 4 ? n%10 : 0 ));;
esac
printf '%d%s\n' "$n" "${ordinals[i]}"
} for n in {0..25} {250..265} {1000..1025}; do
nth $n
done | column</lang>
- Output:
0th 7th 14th 21st 252nd 259th 1000th 1007th 1014th 1021st 1st 8th 15th 22nd 253rd 260th 1001st 1008th 1015th 1022nd 2nd 9th 16th 23rd 254th 261st 1002nd 1009th 1016th 1023rd 3rd 10th 17th 24th 255th 262nd 1003rd 1010th 1017th 1024th 4th 11th 18th 25th 256th 263rd 1004th 1011th 1018th 1025th 5th 12th 19th 250th 257th 264th 1005th 1012th 1019th 6th 13th 20th 251st 258th 265th 1006th 1013th 1020th
VBA
<lang vb>Private Function ordinals() As Variant
ordinals = [{"th","st","nd","rd"}]
End Function
Private Function Nth(n As Variant, Optional apostrophe As Boolean = False) As String
Dim mod10 As Integer: mod10 = n Mod 10 + 1 If mod10 > 4 Or n Mod 100 = mod10 + 9 Then mod10 = 1 Nth = CStr(n) & String$(Val(-apostrophe), "'") & ordinals()(mod10)
End Function
Public Sub main()
Ranges = [{0,25;250,265;1000,1025}]
For i = 1 To UBound(Ranges)
For j = Ranges(i, 1) To Ranges(i, 2)
If j Mod 10 = 0 Then Debug.Print
Debug.Print Format(Nth(j, i = 2), "@@@@@@@");
Next j
Debug.Print
Next i
End Sub</lang>
- Output:
0th 1st 2nd 3rd 4th 5th 6th 7th 8th 9th 10th 11th 12th 13th 14th 15th 16th 17th 18th 19th 20th 21st 22nd 23rd 24th 25th 250'th 251'st 252'nd 253'rd 254'th 255'th 256'th 257'th 258'th 259'th 260'th 261'st 262'nd 263'rd 264'th 265'th 1000th 1001st 1002nd 1003rd 1004th 1005th 1006th 1007th 1008th 1009th 1010th 1011th 1012th 1013th 1014th 1015th 1016th 1017th 1018th 1019th 1020th 1021st 1022nd 1023rd 1024th 1025th
Vlang
<lang vlang>fn ord(n int) string {
mut s := "th"
c := n % 10
if c in [1,2,3] {
if n%100/10 == 1 {
return "$n$s"
}
match c {
1 {
s = 'st'
}
2 {
s = 'nd'
}
3 {
s = 'rd'
}
else{}
}
}
return "$n$s"
}
fn main() {
for n := 0; n <= 25; n++ {
print("${ord(n)} ")
}
println()
for n := 250; n <= 265; n++ {
print("${ord(n)} ")
}
println()
for n := 1000; n <= 1025; n++ {
print("${ord(n)} ")
}
println()
}</lang>
- Output:
0th 1st 2nd 3rd 4th 5th 6th 7th 8th 9th 10th 11th 12th 13th 14th 15th 16th 17th 18th 19th 20th 21st 22nd 23rd 24th 25th 250th 251st 252nd 253rd 254th 255th 256th 257th 258th 259th 260th 261st 262nd 263rd 264th 265th 1000th 1001st 1002nd 1003rd 1004th 1005th 1006th 1007th 1008th 1009th 1010th 1011th 1012th 1013th 1014th 1015th 1016th 1017th 1018th 1019th 1020th 1021st 1022nd 1023rd 1024th 1025th
Wren
<lang ecmascript>import "/fmt" for Conv
var ranges = [ 0..25, 250..265, 1000..1025 ] for (r in ranges) {
r.each { |i| System.write("%(Conv.ord(i)) ") }
System.print("\n")
}</lang>
- Output:
0th 1st 2nd 3rd 4th 5th 6th 7th 8th 9th 10th 11th 12th 13th 14th 15th 16th 17th 18th 19th 20th 21st 22nd 23rd 24th 25th 250th 251st 252nd 253rd 254th 255th 256th 257th 258th 259th 260th 261st 262nd 263rd 264th 265th 1000th 1001st 1002nd 1003rd 1004th 1005th 1006th 1007th 1008th 1009th 1010th 1011th 1012th 1013th 1014th 1015th 1016th 1017th 1018th 1019th 1020th 1021st 1022nd 1023rd 1024th 1025th
XBasic
<lang xbasic> PROGRAM "nth" VERSION "0.0002"
DECLARE FUNCTION Entry() INTERNAL FUNCTION Suffix$(n&&) INTERNAL FUNCTION PrintImages (loLim&&, hiLim&&)
FUNCTION Entry()
PrintImages( 0, 25) PrintImages( 250, 265) PrintImages(1000, 1025)
END FUNCTION
FUNCTION Suffix$(n&&)
nMod10@@ = n&& MOD 10
nMod100@@ = n&& MOD 100
SELECT CASE TRUE
CASE (nMod10@@ = 1) AND (nMod100@@ <> 11):
RETURN ("st")
CASE (nMod10@@ = 2) AND (nMod100@@ <> 12):
RETURN ("nd")
CASE (nMod10@@ = 3) AND (nMod100@@ <> 13):
RETURN ("rd")
CASE ELSE:
RETURN ("th")
END SELECT
END FUNCTION
FUNCTION PrintImages(loLim&&, hiLim&&)
FOR i&& = loLim&& TO hiLim&& PRINT TRIM$(STRING$(i&&)); Suffix$(i&&); " "; NEXT PRINT
END FUNCTION END PROGRAM </lang>
- Output:
0th 1st 2nd 3rd 4th 5th 6th 7th 8th 9th 10th 11th 12th 13th 14th 15th 16th 17th 18th 19th 20th 21st 22nd 23rd 24th 25th 250th 251st 252nd 253rd 254th 255th 256th 257th 258th 259th 260th 261st 262nd 263rd 264th 265th 1000th 1001st 1002nd 1003rd 1004th 1005th 1006th 1007th 1008th 1009th 1010th 1011th 1012th 1013th 1014th 1015th 1016th 1017th 1018th 1019th 1020th 1021st 1022nd 1023rd 1024th 1025th
XLISP
<lang xlisp>(DEFUN NTH (N)
(COND
((AND (> (MOD N 100) 3) (< (MOD N 100) 21)) `(,N TH))
((= (MOD N 10) 1) `(,N ST))
((= (MOD N 10) 2) `(,N ND))
((= (MOD N 10) 3) `(,N RD))
(T `(,N TH))))
(DEFUN RANGE (X Y)
(IF (<= X Y)
(CONS X (RANGE (+ X 1) Y))))
(DEFUN TEST-NTH ()
(DISPLAY (MAPCAR NTH (RANGE 1 25))) (NEWLINE) (DISPLAY (MAPCAR NTH (RANGE 250 265))) (NEWLINE) (DISPLAY (MAPCAR NTH (RANGE 1000 1025))))
(TEST-NTH)</lang>
- Output:
((1 ST) (2 ND) (3 RD) (4 TH) (5 TH) (6 TH) (7 TH) (8 TH) (9 TH) (10 TH) (11 TH) (12 TH) (13 TH) (14 TH) (15 TH) (16 TH) (17 TH) (18 TH) (19 TH) (20 TH) (21 ST) (22 ND) (23 RD) (24 TH) (25 TH)) ((250 TH) (251 ST) (252 ND) (253 RD) (254 TH) (255 TH) (256 TH) (257 TH) (258 TH) (259 TH) (260 TH) (261 ST) (262 ND) (263 RD) (264 TH) (265 TH)) ((1000 TH) (1001 ST) (1002 ND) (1003 RD) (1004 TH) (1005 TH) (1006 TH) (1007 TH) (1008 TH) (1009 TH) (1010 TH) (1011 TH) (1012 TH) (1013 TH) (1014 TH) (1015 TH) (1016 TH) (1017 TH) (1018 TH) (1019 TH) (1020 TH) (1021 ST) (1022 ND) (1023 RD) (1024 TH) (1025 TH))
XPL0
<lang xpl0> \N'th code Rem=2, CrLf=9, IntIn=10, IntOut=11, Text=12;
procedure Suf(N, S); integer N; character S; integer NMod10, NMod100; begin NMod10:= Rem(N/10); NMod100:= Rem(N/100); case of NMod10 = 1 & NMod100 # 11: S(0):= "st"; NMod10 = 2 & NMod100 # 12: S(0):= "nd"; NMod10 = 3 & NMod100 # 13: S(0):= "rd" other S(0):= "th"; end;
procedure PrintImages(LoLim, HiLim); integer LoLim, HiLim; integer I; character S; begin for I:= LoLim, HiLim do begin Suf(I, addr S); IntOut(0, I); Text(0, S); Text(0, " ") end; CrLf(0) end;
begin PrintImages(0, 25); PrintImages(250, 265); PrintImages(1000, 1025) end </lang>
- Output:
0th 1st 2nd 3rd 4th 5th 6th 7th 8th 9th 10th 11th 12th 13th 14th 15th 16th 17th 18th 19th 20th 21st 22nd 23rd 24th 25th 250th 251st 252nd 253rd 254th 255th 256th 257th 258th 259th 260th 261st 262nd 263rd 264th 265th 1000th 1001st 1002nd 1003rd 1004th 1005th 1006th 1007th 1008th 1009th 1010th 1011th 1012th 1013th 1014th 1015th 1016th 1017th 1018th 1019th 1020th 1021st 1022nd 1023rd 1024th 1025th
Yabasic
<lang xbasic> sub ordinal$ (n)
NMod10 = mod(n, 10)
NMod100 = mod(n, 100)
if (NMod10 = 1) and (NMod100 <> 11) then
return "st"
else
if (NMod10 = 2) and (NMod100 <> 12) then
return "nd"
else
if (NMod10 = 3) and (NMod100 <> 13) then
return "rd"
else
return "th"
end if
end if
end if
end sub
sub imprimeOrdinal(a, b)
for i = a to b
print i, ordinal$(i), " ";
next i
print
end sub
imprimeOrdinal (0, 25) imprimeOrdinal (250, 265) imprimeOrdinal (1000, 1025) end </lang>
zkl
Two versions, your choice <lang zkl>#if 0 fcn addSuffix(n){
z:=n.abs()%100; if(11<=z<=13) return(String(n,"th")); z=z%10; String(n,(z==1 and "st") or (z==2 and "nd") or (z==3 and "rd") or "th");
}
- else
fcn addSuffix(n){
var suffixes=T("th","st","nd","rd","th","th","th","th","th","th"); //0..10
z:=n.abs()%100;
String(n,(z<=10 or z>20) and suffixes[z%10] or "th");
}
- endif</lang>
<lang zkl>[0..25] .apply(addSuffix).concat(",").println(); [250..265] .apply(addSuffix).concat(",").println(); [1000..1025].apply(addSuffix).concat(",").println();</lang>
- Output:
0th,1st,2nd,3rd,4th,5th,6th,7th,8th,9th,10th,11th,12th,13th,14th,15th,16th,17th,18th,19th,20th,21st,22nd,23rd,24th,25th 250th,251st,252nd,253rd,254th,255th,256th,257th,258th,259th,260th,261st,262nd,263rd,264th,265th 1000th,1001st,1002nd,1003rd,1004th,1005th,1006th,1007th,1008th,1009th,1010th,1011th,1012th,1013th,1014th,1015th,1016th,1017th,1018th,1019th,1020th,1021st,1022nd,1023rd,1024th,1025th
ZX Spectrum Basic
<lang basic> 10 FOR n=0 TO 25
20 GO SUB 140 30 PRINT n$;" "; 40 NEXT n 50 FOR n=250 TO 265 60 GO SUB 140 70 PRINT n$;" "; 80 NEXT n 90 FOR n=1000 TO 1025
100 GO SUB 140 110 PRINT n$;" "; 120 NEXT n 130 STOP 140 LET s$="th" 150 LET n$=STR$ n 160 IF LEN n$=1 THEN GO TO 180 170 IF n$(LEN n$-1)="1" THEN GO TO 210 180 IF n$(LEN n$)="1" THEN LET s$="st" 190 IF n$(LEN n$)="2" THEN LET s$="nd" 200 IF n$(LEN n$)="3" THEN LET s$="rd" 210 LET n$=n$+s$ 220 RETURN</lang>
- Output:
0th 1st 2nd 3rd 4th 5th 6th 7th 8th 9th 10th 11th 12th 13th 14th 15th 16th 17th 18th 19th 20th 21st 22nd 23rd 24th 25th 250th 251st 252nd 253rd 254th 255th 256th 257th 258th 259th 260th 261st 262nd 263rd 264th 265th 1000th 1001st 1002nd 1003rd 1004th 1005th 1006th 1007th 1008th 1009th 1010th 1011th 1012th 1013th 1014th 1015th 1016th 1017th 1018th 1019th 1020th 1021st 1022nd 1023rd 1024th 1025th