# Input/Output for Pairs of Numbers

Input/Output for Pairs of Numbers is a draft programming task. It is not yet considered ready to be promoted as a complete task, for reasons that should be found in its talk page.

From lines of input starting with a line containing the numbers of pairs to follows, followed by that number of pairs of integers separated by a space on separate lines from STDIN, output the sum of each pair to STDOUT.

Sample input with corresponding output

Input

```5
1 2
10 20
-3 5
100 2
5 5```

Output

```3
30
2
102
10```

## ALGOL 68

Simple version - there can be newlines before or between the numbers

`# read a number from stand in then read and add that many pairs of numbers from stand in      ## and write the sum to stand out. If non integer data is supplied, a runtime error will occur #TO ( INT n; read( ( n, newline ) ); n ) DO    INT a, b;    read( ( a, b, newline ) );    print( ( a + b, newline ) )OD `

Strict version - the pairs of numbers must appear on the same line.

` # read a number from stand in then read and add that many pairs of numbers from stand in      ## and write the sum to stand out. If non integer data is supplied, a runtime error will occur ## This version does not allow the pairs of numbers to be spread over several lines            #STRING line;FILE   numbers;associate( numbers, line );TO ( INT n   ; read( ( line, newline ) )   ; reset( numbers )   ; get( numbers, ( n ) )   ; n   )DO    INT a, b;    read( ( line, newline ) );    reset( numbers );    get( numbers, ( a, b ) );    print( ( a + b, newline ) )OD`
Output:
```         +3
+30
+2
+102
+10
```

## AWK

`NR == 1 {n=\$1; next} NR > n+1 {exit} {print \$1+\$2}`

## Batch File

` @echo offsetlocal enabledelayedexpansion set /p pairs= for /l %%i in (1,1,%pairs%) do set /p pair%%i=for /l %%i in (1,1,%pairs%) do (  for %%j in (!pair%%i!) do (    set /a sum%%i+=%%j  )) for /l %%i in (1,1,%pairs%) do echo !sum%%i!pause>nul `
Input:
```5
10 10
5 6
-3 2
-6 -8
111 2
```
Output:
```20
11
-1
-14
113
```

## BBC BASIC

The specification is a bit ambiguous, but I understood it as wanting us to read all the numbers in first and then print all the sums. This program does that. It could be a couple of lines shorter if we were allowed to use a comma instead of a space as separator.

`INPUT n%DIM pairs%(n% - 1, 1)FOR i% = 0 TO n% - 1  INPUT s\$  pairs%(i%, 0) = VAL(LEFT\$(s\$, INSTR(s\$, " ")))  pairs%(i%, 1) = VAL(MID\$(s\$, INSTR(s\$, " ")))NEXTFOR i% = 0 TO n% - 1  PRINT pairs%(i%, 0) + pairs%(i%, 1)NEXT`

With the sample inputs:

```?5
?1 2
?10 20
?-3 5
?100 2
?5 5
3
30
2
102
10```

## C

`#include <stdio.h>#include <stdlib.h> int main(void){	int i, n, a, b, *f;	scanf("%d", &n);	f = malloc(sizeof(*f) * n); 	for (i = 0; i < n; i++) {		if (2 != scanf("%d %d", &a, &b))			abort();		f[i] = a + b;	} 	for (i = 0; i < n; i++)		printf("%d\n", f[i]); 	return 0;}`

Output for example input

```3
30
2
102
10
```

## C++

Modified in order to take in all inputs and then give the output, the original gave the output for each pair immediately.

` #include <iostream>using namespace std; int doStuff(int a, int b) {    return a + b;} int main() { 	int t, **list; 	cin >> t; 	list = new int*[t]; 	for(int j=0; j<t; j++){ 		list[j] = new int[2];		cin >> list[j][0]>> list[j][1]; 	} 	cout << endl; 	for(int j=0;j<t;j++){		cout << doStuff(list[j][0], list[j][1]) << endl;;	}	return 0;} `

Run as per given input

```5
1 2
10 20
-3 5
100 2
5 5

3
30
2
102
10
```

## D

This works with any number of integers on lines.

`void main() {    import std.stdio, std.string, std.conv, std.algorithm;     foreach (immutable _; 0 .. readln.strip.to!uint)        readln.split.to!(int[]).sum.writeln;}`

## Factor

` USING: io math.parser prettyprint sequences splitting ;IN: rosetta-code.pair-output : process-line ( str -- n )    " " split [ string>number ] map-sum ;: main ( -- ) lines 1 tail [ process-line ] map [ . ] each ; MAIN: main `
Output:
```3
30
2
102
10
```

## Fortran

Works with: Fortran version 95 and later
`program i_o_pairs  implicit none   integer :: npairs  integer :: i  integer, allocatable :: pairs(:,:)   read(*,*) npairs  allocate(pairs(npairs,2))   do i = 1, npairs    read(*,*) pairs(i,:)  end do  write(*, "(i0)") sum(pairs, 2) end program`

## FreeBASIC

`' FB 1.05.0 Win64 Dim As UInteger n Dim As Integer x, yInput "", nDim sums(1 To n) As IntegerFor i As Integer = 1 To  n  Input "", x, y  sums(i) =  x + yNext PrintFor i As Integer = 1 To n  Print Str(sums(i))Next Sleep`
Output:
```5
1 2
10 20
-3 5
100 2
5 5

3
30
2
102
10
```

This solution will actually add any number of integers placed on each line. Additionally, after removing the bits of code that cut out the specified number of lines, the solution will sum any number of lines of integers.

`main = do    contents <- getContents    let numberOfLines  =  read.head.lines\$ contents        nums  =  map (map read.words).take numberOfLines.tail.lines\$ contents        sums  =  map sum nums    mapM_ print sums`

## Go

`package main import (	"fmt"	"log") func main() {	var lines int	n, err := fmt.Scanln(&lines)	if n != 1 || err != nil {		log.Fatal(err)	} 	var a, b int	for ; lines > 0; lines-- {		n, err = fmt.Scanln(&a, &b)		if n != 2 || err != nil {			log.Fatal(err)		}		fmt.Println(a + b)	}}`

## J

` \$ cat <<EOF | jconsole -js '([: exit 0: [: smoutput [: ,. [: ({. {. }.) [: (+/"1) [: (0&".;._2) (1!:1)) 3'> 5> 1 2> 10 20> -3 5> 100 2> 5 5> EOF  3 30  2102 10 `

Considerably simpler than [explanation] output for lines of text, this sentence is a single fork. J pads the numeric arrays of 0&".;._2 (numbers cut) with 0 . We form the +/"1 (row sums), then take the sum of the first row of the beheaded sums ({. {. }.) for display. ,. (raveled items) reshapes the vector into a column-vector shaped matrix. And the [: (cap) causes the monadic form of the verb to cap's right.

## Java

`import java.util.Scanner; public class Main { 	public static int doStuff(int a, int b){	    int sum = a+b;	    return sum;	} 	public static void main(String[] args) {		Scanner in = new Scanner(System.in); 		int n = in.nextInt();		for(int i=0; i<n; i++){			int a = in.nextInt();			int b= in.nextInt();			int result = doStuff(a, b);			System.out.println(result);		}	}}`

## Kotlin

`// version 1.0.6 import java.util.Scanner fun main(args: Array<String>) {    val sc = Scanner(System.`in`)  // note: backticks required as 'in' is a Kotlin keyword    val n = sc.nextInt()    val x = IntArray(n)    val y = IntArray(n)    for (i in 0 until n) {        x[i] = sc.nextInt()        y[i] = sc.nextInt()      }    println()    for (i in 0 until n) println(x[i] + y[i])}`

Sample input/output:

Output:
```5
1 2
10 20
-3 5
100 2
5 5

3
30
2
102
10
```

## Lua

This solution will sum any number of space-separated numbers per input line, assuming the user won't input too many to store in the available RAM.

`local intTab, numLines, sum = {}, io.read()for i = 1, numLines do    sum = 0    for number in io.read():gmatch("%S+") do sum = sum + number end    table.insert(intTab, sum)endfor _, result in pairs(intTab) do print(result) end`

## PARI/GP

Interestingly, this task is not possible to implement directly in GP, since `input()`, like the gp REPL itself, ignores spaces. One must use PARI:

`#include <stdio.h>#include <stdlib.h>#include <pari/pari.h> int main(void); intmain(){  int i, n, a, b;  GEN f, sum;  pari_sp ltop;   // 1 MB stack, not using prime table  pari_init(1000000, 0);   scanf("%d", &n);  GEN f = cgetg(n+1, t_VEC);   for (i = 1; i <= n; i++) {    if (2 != scanf("%d %d", &a, &b)) abort();     ltop = avma; 	// Add a and b in PARI	sum = addii(stoi(a), stoi(b)); 	// Store the sum in a vector, collecting garbage as you go.	gel(f, i) = gerepileupto(ltop, sum);  }   pari_printf("%Ps", f);  return 0;}`

Of course for such a simple task this has very little advantage over C, but it does demonstrate the general principle.

## Perl

`\$n = scalar <>; for (1..\$n) {    (\$a,\$b) = split ' ', <>;    print \$a + \$b . "\n";}`

## Perl 6

`for ^get() { say [+] get.words }`

This does more than the task asks. It will sum as many numbers as you care to put on each line, and the numbers need not be integers, but may also be a mix of rational, floating-point, or complex numbers. More subtly, get can read from a file specified as a command-line argument, but defaults to taking STDIN if no filename is specified.

## Phix

`string line = gets(0)sequence r = scanf(trim(line),"%d"), s = {}if length(r)!=1 then    puts(1,"input not a number\n")    abort(0)end ifputs(1,"\n")for i=1 to r[1][1] do    line = gets(0)    r = scanf(trim(line),"%d %d")    if length(r)!=1 then        puts(1,"input not a pair of numbers\n")        abort(0)    end if    s &= sum(r[1])    puts(1,"\n")end forputs(1,"===\n")?s`
Output:

(or more accurately the final state of the console)

```5
1 2
10 20
-3 5
100 2
5 5
===
{3,30,2,102,10}
```

## PowerShell

` # script.ps1 \$in, \$line = (Get-Content \$args[0]), 0\$nb = \$in[\$line++]1..\$nb | foreach {    \$sum = 0    \$in[\$line++].Split() | foreach{ \$sum += \$_}     \$sum} # ./script file.txt `

## Python

`def do_stuff(a, b):	return a + b t = input()for x in range(0, t):	a, b = raw_input().strip().split()	print do_stuff(int(a), int(b))`

### Python: Alternative

Or without the function do_stuff() and that works for Python 3 and Python 2:

`>>> try: raw_inputexcept NameError: raw_input = input >>> for i in range(int(raw_input())):	print(sum(int(numberstring)		  for numberstring		  in raw_input().strip().split()))  51 2310 2030-3 52100 21025 510>>> `

(All but the first line of single numbers, (the 5), is output from the program).

### Python: With prompts

More than is asked for by the task, but if working interactively then the following version adds prompts.

`>>> for i in range(int(raw_input('lines: '))):	print(sum(int(numberstring)                   for numberstring in raw_input('two numbers: ').strip().split()))  lines: 5two numbers: 1 23two numbers: 10 2030two numbers: -3 52two numbers: 100 2102two numbers: 5 510>>> `

## Racket

`#lang racket;(define line-number (read)) ;reads all kind of things ;(for ([i (in-range line-number)]);  (displayln (+ (read) (read)))) (define line-count (string->number ;only reads numbers                    (string-trim (read-line))))  (for ([i (in-range line-count)])  (displayln (apply +                     (map string->number                          (string-split (read-line))))))`

## REXX

This version isn't limited to summing integers, any form of number that REXX supports can be used.

`/*REXX pgm reads a number (from the CL), reads that number of pairs, & writes their sum.*/                                                 /*all input is from the  Command Line. */     do  linein()                                /*read the number of pairs to be add*ed*/     \$=linein()                                  /*read a line (a record) from the C.L. */     say word(\$, 1)   +   word(\$, 2)             /*display the sum of a pair of numbers.*/     end   /*linein() */                                                 /*stick a fork in it,  we're all done. */`

## Ring

` # Project : Input/Output for Pairs of Numbers pairs = ["5", "1 2", "10 20", "-3 5", "100 2", "5 5"]for n = 1 to len(pairs)    nr = 0    for p = 1 to len(pairs[n])        if substr(pairs[n], p, 1) = " "           nr = p        ok    next    if nr > 0       n1 = number(left(pairs[n], nr - 1))       n2 = number(right(pairs[n], len(pairs[n]) - nr + 1))       n3 = n1 + n2       see n3 + nl    oknext `

Output:

```3
30
2
102
10
```

### Ring: Alternative

` # Project : Input/Output for Pairs of Numbers (Alternative) pairs = ["5", "1 2", "10 20", "5 -3", "100 2", "5 5"]for n = 1 to len(pairs)    nr = 0    for p = 1 to len(pairs[n])        if substr(pairs[n], p, 1) = " "           pairs[n] = substr(pairs[n], " ", "+")           nr = p        ok    next    if nr > 0       eval("ev = " + pairs[n])       see ev + nl    oknext>>> `
```3
30
2
102
10
```

## Ruby

`n = gets.to_in.times do  a, b = gets.split.map(&:to_i)  puts a + bend`

## Scala

`object IOPairs extends App {  private val in = scala.io.StdIn  private val n = in.readInt()   for (_ <- 0 until n) {    val Array(a, b) = in.readLine().split(" ").map(_.toInt)     def doStuff(a: Long, b: Long): Long = a + b     println(doStuff(a, b))  } } `

## Tcl

`gets stdin nwhile {\$n > 0} {    if {[scan [gets stdin] "%d %d" a b] == 2} {        puts [expr {\$a + \$b}]    }    incr n -1}`

## UNIX Shell

Works with: Bourne Again SHell
`read nwhile (( n > 0 )); do    read a b    echo \$((a+b))    ((n--))done`

## Ursa

`decl int amountset amount (in int console) decl int<> intsfor (decl int i) (< i amount) (inc i)        decl string input        set input (in string console)        append (int (split input " ")<0>) (int (split input " ")<1>) intsend for out endl console for (set i 0) (< i (size ints)) (set i (int (+ 2 i)))        out (int (+ ints<i> ints<(int (+ i 1))>)) endl consoleend for`

Networked version. Runs on port 20000.

`decl serverport spdecl port psp.attach 20000set p (sp.getconn) decl int amountset amount (in int p) decl int<> intsfor (decl int i) (< i amount) (inc i)        decl string input        set input (in string p)        append (int (split input " ")<0>) (int (split input " ")<1>) intsend for out endl p for (set i 0) (< i (size ints)) (set i (int (+ 2 i)))        out (int (+ ints<i> ints<(int (+ i 1))>)) endl pend for`

## zkl

Using the console as the input stream:

`fcn pairs{   n:=ask("num pairs: ").toInt();    do(n){ask("1 pair: ").split(" ").sum().println()}}`
Output:
```pairs()
num pairs: 5
1 pair: 1 2
3
1 pair: 10 20
30
1 pair: -3 5
2
1 pair: 100 2
102
1 pair: 5 5
10
```