Digital root/Multiplicative digital root

Digital root/Multiplicative digital root
You are encouraged to solve this task according to the task description, using any language you may know.

The multiplicative digital root (MDR) and multiplicative persistence (MP) of a number, ${\displaystyle n}$, is calculated rather like the Digital root except digits are multiplied instead of being added:

1. Set ${\displaystyle m}$ to ${\displaystyle n}$ and ${\displaystyle i}$ to ${\displaystyle 0}$.
2. While ${\displaystyle m}$ has more than one digit:
• Find a replacement ${\displaystyle m}$ as the multiplication of the digits of the current value of ${\displaystyle m}$.
• Increment ${\displaystyle i}$.
3. Return ${\displaystyle i}$ (= MP) and ${\displaystyle m}$ (= MDR)

• Tabulate the MP and MDR of the numbers 123321, 7739, 893, 899998
• Tabulate MDR versus the first five numbers having that MDR, something like:
```MDR: [n0..n4]
===  ========
0: [0, 10, 20, 25, 30]
1: [1, 11, 111, 1111, 11111]
2: [2, 12, 21, 26, 34]
3: [3, 13, 31, 113, 131]
4: [4, 14, 22, 27, 39]
5: [5, 15, 35, 51, 53]
6: [6, 16, 23, 28, 32]
7: [7, 17, 71, 117, 171]
8: [8, 18, 24, 29, 36]
9: [9, 19, 33, 91, 119]
```

References

The solution uses the Package "Generic_Root" from the additive digital roots [[1]].

`with Ada.Text_IO, Generic_Root;   use Generic_Root; procedure Multiplicative_Root is    procedure Compute is new Compute_Root("*"); -- "*" for multiplicative roots    package TIO renames Ada.Text_IO;   package NIO is new TIO.Integer_IO(Number);    procedure Print_Numbers(Target_Root: Number; How_Many: Natural) is      Current: Number := 0;      Root, Pers: Number;   begin       for I in 1 .. How_Many loop	  loop 	     Compute(Current, Root, Pers);	     exit when Root = Target_Root;	     Current := Current + 1;	  end loop;	  NIO.Put(Current, Width => 6);	  if I < How_Many then	     TIO.Put(",");	  end if;	  Current := Current + 1;       end loop;   end Print_Numbers;    Inputs: Number_Array := (123321, 7739, 893, 899998);   Root, Pers: Number;begin   TIO.Put_Line("  Number   MDR    MP");   for I in Inputs'Range loop       Compute(Inputs(I), Root, Pers);       NIO.Put(Inputs(I), Width => 8);       NIO.Put(Root, Width => 6);       NIO.Put(Pers, Width => 6);       TIO.New_Line;   end loop;   TIO.New_Line;    TIO.Put_Line(" MDR    first_five_numbers_with_that_MDR");   for I in 0 .. 9 loop      TIO.Put("  " & Integer'Image(I) & "  ");      Print_Numbers(Target_Root => Number(I), How_Many => 5);      TIO.New_Line;   end loop;end Multiplicative_Root;`
Output:
```  Number   MDR    MP
123321     8     3
7739     8     3
893     2     3
899998     0     2

MDR    first_five_numbers_with_that_MDR
0       0,    10,    20,    25,    30
1       1,    11,   111,  1111, 11111
2       2,    12,    21,    26,    34
3       3,    13,    31,   113,   131
4       4,    14,    22,    27,    39
5       5,    15,    35,    51,    53
6       6,    16,    23,    28,    32
7       7,    17,    71,   117,   171
8       8,    18,    24,    29,    36
9       9,    19,    33,    91,   119
```

ALGOL 68

Works with: ALGOL 68G version Any - tested with release 2.8.win32
`# Multiplicative Digital Roots                                                # # structure to hold the results of calculating the digital root & persistence #MODE DR = STRUCT( INT root, INT persistence ); # calculate the multiplicative digital root and persistence of a number       #PROC md root = ( INT number )DR:BEGIN     # calculate the product of the digits of a number                         #    PROC digit product = ( INT number )INT:    BEGIN         INT    result := 1;        INT    rest   := number;         WHILE            result TIMESAB ( rest MOD 10 );            rest   OVERAB  10;            rest > 0        DO           SKIP        OD;         result    END; # digit product #     INT mp  := 0;    INT mdr := ABS number;     WHILE mdr > 9    DO        mp +:= 1;        mdr := digit product( mdr )    OD;     ( mdr, mp )END; # md root # # prints a number and its MDR and MP                                          #PROC print md root = ( INT number )VOID:BEGIN    DR mdr = md root( number );    print( ( whole( number, -6 )           , ": MDR: ", whole( root        OF mdr,  0 )           , ", MP: ",  whole( persistence OF mdr, -2 )           , newline           )         )END; # print md root # # prints the first few numbers with each possible Multiplicative Digital      ## Root. The number of values to print is specified as a parameter             #PROC tabulate mdr = ( INT number of values )VOID:BEGIN     [ 0 : 9, 1 : number of values ]INT mdr values;    [ 0 : 9                       ]INT mdr counts;    mdr counts[ AT 1 ] := ( 0, 0, 0, 0, 0, 0, 0, 0, 0, 0 );     # find the first few numbers with each possible mdr                       #     INT values found    := 0;    INT required values := 10 * number of values;     FOR value FROM 0 WHILE values found < required values    DO        DR mdr = md root( value );        IF mdr counts[ root OF mdr ] < number of values        THEN            # need more values with this multiplicative digital root          #            values found              +:= 1;            mdr counts[ root OF mdr ] +:= 1;            mdr values[ root OF mdr, mdr counts[ root OF mdr ] ] := value        FI    OD;     # print the values #     print( ( "MDR: [n0..n" + whole( number of values - 1, 0 ) + "]", newline ) );    print( ( "===  ========", newline ) );    FOR mdr pos FROM 1 LWB mdr values TO 1 UPB mdr values    DO        STRING separator := ": [";        print( ( whole( mdr pos, -3 ) ) );        FOR val pos FROM 2 LWB mdr values TO 2 UPB mdr values        DO            print( ( separator + whole( mdr values[ mdr pos, val pos ], 0 ) ) );            separator := ", "        OD;        print( ( "]", newline ) )    OD END; # tabulate mdr # main:(    print md root( 123321 );    print md root(   7739 );    print md root(    893 );    print md root( 899998 );    tabulate mdr( 5 ))`
Output:
```123321: MDR: 8, MP:  3
7739: MDR: 8, MP:  3
893: MDR: 2, MP:  3
899998: MDR: 0, MP:  2
MDR: [n0..n4]
===  ========
0: [0, 10, 20, 25, 30]
1: [1, 11, 111, 1111, 11111]
2: [2, 12, 21, 26, 34]
3: [3, 13, 31, 113, 131]
4: [4, 14, 22, 27, 39]
5: [5, 15, 35, 51, 53]
6: [6, 16, 23, 28, 32]
7: [7, 17, 71, 117, 171]
8: [8, 18, 24, 29, 36]
9: [9, 19, 33, 91, 119]
```

ALGOL W

`begin    % calculate the Multiplicative Digital Root (mdr) and Multiplicative Persistence (mp) of n %    procedure getMDR ( integer value  n                     ; integer result mdr, mp                     ) ;    begin        mp  := 0;        mdr := abs n;        while mdr > 9 do begin           integer v;           v   := mdr;           mdr := 1;           while begin               mdr := mdr * ( v rem 10 );               v   := v div 10;               v > 0           end do begin end;           mp := mp + 1;        end while_mdr_gt_9 ;    end getMDR ;     % task test cases %    write( "       N MDR MP" );    for n := 123321, 7739, 893, 899998 do begin        integer mdr, mp;        getMDR( n, mdr, mp );        write( s_w := 1, i_w := 8, n, i_w := 3, mdr, i_w := 2, mp )    end for_n ;     begin % find the first 5 numbers with each possible MDR %        integer requiredMdrs;        requiredMdrs := 5;        begin            integer array firstFew ( 0 :: 9, 1 :: requiredMdrs );            integer array mdrFOund ( 0 :: 9 );            integer       totalFound, requiredTotal, n;            for i := 0 until 9 do mdrFound( i ) := 0;            totalFound    := 0;            requiredTotal := 10 * requiredMdrs;            n             := -1;            while totalFound < requiredTotal do begin                integer mdr, mp;                n := n + 1;                getMDR( n, mdr, mp );                if mdrFound( mdr ) < requiredMdrs then begin                    % found another number with this MDR and haven't found enough yet %                    totalFound                       := totalFound + 1;                    mdrFound( mdr )                  := mdrFound( mdr ) + 1;                    firstFew( mdr, mdrFound( mdr ) ) := n                end if_found_another_MDR            end while_totalFound_lt_requiredTotal ;            % print the table of MDRs andnumbers %            write( "MDR: [n0..n4]" );            write( "===  ========" );            for v := 0 until 9 do begin                write( i_w := 3, s_w := 0, v, ": [" );                for foundPos := 1 until requiredMdrs do begin                    if foundPos > 1 then writeon( s_w := 0, ", " );                    writeon( i_w := 1, s_w := 0, firstFew( v, foundPos ) )                end for_foundPos ;                writeon( s_w := 0, "]" )            end for_v        end    end end.`
Output:
```       N MDR MP
123321   8  3
7739   8  3
893   2  3
899998   0  2
MDR: [n0..n4]
===  ========
0: [0, 10, 20, 25, 30]
1: [1, 11, 111, 1111, 11111]
2: [2, 12, 21, 26, 34]
3: [3, 13, 31, 113, 131]
4: [4, 14, 22, 27, 39]
5: [5, 15, 35, 51, 53]
6: [6, 16, 23, 28, 32]
7: [7, 17, 71, 117, 171]
8: [8, 18, 24, 29, 36]
9: [9, 19, 33, 91, 119]
```

AWK

`# Multiplicative Digital Roots BEGIN {     printMdrAndMp( 123321 );    printMdrAndMp(   7739 );    printMdrAndMp(    893 );    printMdrAndMp( 899998 );     tabulateMdr( 5 ); } # BEGIN function printMdrAndMp( n ){    calculateMdrAndMp( n );    printf( "%6d: MDR: %d, MP: %2d\n", n, MDR, MP );} # printMdrAndMp function calculateMdrAndMp( n,                     mdrStr, digit ){     MP  = 0;                     # global Multiplicative Persistence    MDR = ( n < 0 ? -n : n );    # global Multiplicative Digital Root     while( MDR > 9 )    {        MP ++;        mdrStr = "" MDR;        MDR    = 1;        for( digit = 1; digit <= length( mdrStr ); digit ++ )        {            MDR *= ( substr( mdrStr, digit, 1 ) * 1 );        } # for digit    } # while MDR > 9 } # calculateMdrAndMp function tabulateMdr( n,                  rqdValues, valueCount, value, pos ){     # generate a table of the first n numbers with each possible MDR     rqdValues  = n * 10;    valueCount = 0;     for( value = 0; valueCount < rqdValues; value ++ )    {        calculateMdrAndMp( value );        if( mdrCount[ MDR ] < n )        {            # still need another value with this MDR            valueCount ++;            mdrCount[ MDR ] ++;            mdrValues[ MDR ":" mdrCount[ MDR ] ] = value;        } # if mdrCount[ MDR ] < n    } # for value     # print the table     printf( "MDR: [n0..n%d]\n", n - 1 );    printf( "===  ========\n" );     for( pos = 0; pos < 10; pos ++ )    {        printf( "%3d:", pos );        separator = " [";        for( value = 1; value <= n; value ++ )        {            printf( "%s%d", separator, mdrValues[ pos ":" value ] );            separator = ", "        } # for value        printf( "]\n" );    } # for pos } # tabulateMdr`
Output:
```123321: MDR: 8, MP:  3
7739: MDR: 8, MP:  3
893: MDR: 2, MP:  3
899998: MDR: 0, MP:  2
MDR: [n0..n4]
===  ========
0: [0, 10, 20, 25, 30]
1: [1, 11, 111, 1111, 11111]
2: [2, 12, 21, 26, 34]
3: [3, 13, 31, 113, 131]
4: [4, 14, 22, 27, 39]
5: [5, 15, 35, 51, 53]
6: [6, 16, 23, 28, 32]
7: [7, 17, 71, 117, 171]
8: [8, 18, 24, 29, 36]
9: [9, 19, 33, 91, 119]
```

Bracmat

`(& ( MP/MDR  =   prod L n    .   ( prod        =   d          .   @(!arg:%@?d ?arg)&!d*prod\$!arg            | 1        )      & !arg:?L      &   whl        ' ( @(!arg:? [>1)          & (prod\$!arg:?arg) !L:?L          )      & !L:? [?n      & (!n+-1.!arg)  )& ( test  =   n    .     !arg:%?n ?arg        & out\$(!n "\t:" MP/MDR\$!n)        & test\$!arg      |   )& test\$(123321 7739 893 899998)& 0:?i& 1:?collecting:?done&   whl  ' ( !i+1:?i    & MP/MDR\$!i:(?MP.?MDR)    & ( !done:?*(!MDR.)^((?.)+?)*?      |   (!MDR.)^(!i.)*!collecting:?collecting        & (   !collecting:?A*(!MDR.)^(?is+[5)*?Z            & !A*!Z:?collecting            & (!MDR.)^!is*!done:?done          |           )      )    & !collecting:~1    )&   whl  ' ( !done:(?MDR.)^?is*?done    & put\$(!MDR ":")    & whl'(!is:(?i.)+?is&put\$(!i " "))    & put\$\n    ));`
Output:
```123321  : (3.8)
7739    : (3.8)
893     : (3.2)
899998  : (2.0)
0 :10  20  25  30  40
1 :1  11  111  1111  11111
2 :2  12  21  26  34
3 :3  13  31  113  131
4 :4  14  22  27  39
5 :5  15  35  51  53
6 :6  16  23  28  32
7 :7  17  71  117  171
8 :8  18  24  29  36
9 :9  19  33  91  119```

C

` #include <stdio.h> #define twidth 5#define mdr(rmdr, rmp, n)\    do { *rmp = 0; _mdr(rmdr, rmp, n); } while (0) void _mdr(int *rmdr, int *rmp, long long n){    /* Adjust r if 0 case, so we don't return 1 */    int r = n ? 1 : 0;    while (n) {         r *= (n % 10);        n /= 10;     }     (*rmp)++;    if (r >= 10)        _mdr(rmdr, rmp, r);    else        *rmdr = r;} int main(void){    int i, j, vmdr, vmp;    const int values[] = { 123321, 7739, 893, 899998 };    const int vsize    = sizeof(values) / sizeof(values[0]);     /* Initial test values */    printf("Number    MDR    MP\n");    for (i = 0; i < vsize; ++i) {        mdr(&vmdr, &vmp, values[i]);        printf("%6d   %3d   %3d\n", values[i], vmdr, vmp);    }     /* Determine table values */    int table[10][twidth] = { 0 };    int tfill[10]         = { 0 };    int total             = 0;    for (i = 0; total < 10 * twidth; ++i) {        mdr(&vmdr, &vmp, i);        if (tfill[vmdr] < twidth) {            table[vmdr][tfill[vmdr]++] = i;            total++;        }    }     /* Print calculated table values */    printf("\nMDR: [n0..n4]\n");    for (i = 0; i < 10; ++i) {        printf("%3d: [", i);        for (j = 0; j < twidth; ++j)            printf("%d%s", table[i][j], j != twidth - 1 ? ", " : "");         printf("]\n");    }     return 0;} `
Output:
```Number    MDR    MP
123321     8     3
7739     8     3
893     2     3
899998     0     2

MDR: [n0..n4]
0: [0, 10, 20, 25, 30]
1: [1, 11, 111, 1111, 11111]
2: [2, 12, 21, 26, 34]
3: [3, 13, 31, 113, 131]
4: [4, 14, 22, 27, 39]
5: [5, 15, 35, 51, 53]
6: [6, 16, 23, 28, 32]
7: [7, 17, 71, 117, 171]
8: [8, 18, 24, 29, 36]
9: [9, 19, 33, 91, 119]
```

C#

`using System;using System.Collections.Generic;using System.Linq; class Program{    static Tuple<int, int> DigitalRoot(long num)    {        int mp = 0;        while (num > 9)        {            num = num.ToString().ToCharArray().Select(x => x - '0').Aggregate((a, b) => a * b);            mp++;        }        return new Tuple<int, int>(mp, (int)num);    }    static void Main(string[] args)    {        foreach (long num in new long[] { 123321, 7739, 893, 899998 })        {            var t = DigitalRoot(num);            Console.WriteLine("{0} has multiplicative persistence {1} and multiplicative digital root {2}", num, t.Item1, t.Item2);        }         const int twidth = 5;        List<long>[] table = new List<long>[10];        for (int i = 0; i < 10; i++)            table[i] = new List<long>();        long number = -1;        while (table.Any(x => x.Count < twidth))         {            var t = DigitalRoot(++number);            if (table[t.Item2].Count < twidth)                table[t.Item2].Add(number);        }        for (int i = 0; i < 10; i++)            Console.WriteLine(" {0} : [{1}]", i, string.Join(", ", table[i]));    }}`
Output:
```123321 has multiplicative persistence 3 and multiplicative digital root 8
7739 has multiplicative persistence 3 and multiplicative digital root 8
893 has multiplicative persistence 3 and multiplicative digital root 2
899998 has multiplicative persistence 2 and multiplicative digital root 0
0 : [0, 10, 20, 25, 30]
1 : [1, 11, 111, 1111, 11111]
2 : [2, 12, 21, 26, 34]
3 : [3, 13, 31, 113, 131]
4 : [4, 14, 22, 27, 39]
5 : [5, 15, 35, 51, 53]
6 : [6, 16, 23, 28, 32]
7 : [7, 17, 71, 117, 171]
8 : [8, 18, 24, 29, 36]
9 : [9, 19, 33, 91, 119]```

C++

` #include <iomanip>#include <map>#include <vector>#include <iostream>using namespace std; void calcMDR( int n, int c, int& a, int& b ){    int m = n % 10; n /= 10;    while( n )    {	m *= ( n % 10 );	n /= 10;    }    if( m >= 10 ) calcMDR( m, ++c, a, b );    else { a = m; b = c; }} void table(){    map<int, vector<int> > mp;    int n = 0, a, b;    bool f = true;    while( f )    {	f = false;	calcMDR( n, 1, a, b );	mp[a].push_back( n );	n++;	for( int x = 0; x < 10; x++ )	    if( mp[x].size() < 5 )	    { f = true; break; }    }     cout << "|  MDR  |  [n0..n4]\n+-------+------------------------------------+\n";    for( int x = 0; x < 10; x++ )    {	cout << right << "| " << setw( 6 ) << x << "| ";	for( vector<int>::iterator i = mp[x].begin(); i != mp[x].begin() + 5; i++ )	    cout << setw( 6 ) << *i << " ";	cout << "|\n";    }    cout << "+-------+------------------------------------+\n\n";} int main( int argc, char* argv[] ){    cout << "|  NUMBER  |   MDR    |    MP    |\n+----------+----------+----------+\n";    int numbers[] = { 123321, 7739, 893, 899998 }, a, b;    for( int x = 0; x < 4; x++ )    {	cout << right << "| "  << setw( 9 ) << numbers[x] << "| ";	calcMDR( numbers[x], 1, a, b );	cout << setw( 9 ) << a  << "| " << setw( 9 ) << b << "|\n";    }    cout << "+----------+----------+----------+\n\n";    table();    return system( "pause" );} `
Output:
```|  NUMBER  |   MDR    |    MP    |
+----------+----------+----------+
|    123321|         8|         3|
|      7739|         8|         3|
|       893|         2|         3|
|    899998|         0|         2|
+----------+----------+----------+

|  MDR  |  [n0..n4]
+-------+------------------------------------+
|      0|      0     10     20     25     30 |
|      1|      1     11    111   1111  11111 |
|      2|      2     12     21     26     34 |
|      3|      3     13     31    113    131 |
|      4|      4     14     22     27     39 |
|      5|      5     15     35     51     53 |
|      6|      6     16     23     28     32 |
|      7|      7     17     71    117    171 |
|      8|      8     18     24     29     36 |
|      9|      9     19     33     91    119 |
+-------+------------------------------------+
```

Common Lisp

` (defun mdr/p (n)  "Return a list with MDR and MP of n"  (if (< n 10)     (list n 0)    (mdr/p-aux n 1 1))) (defun mdr/p-aux (n a c)  (cond ((and (zerop n) (< a 10)) (list a c))	((zerop n) (mdr/p-aux a 1 (+ c 1)))	(t (mdr/p-aux (floor n 10) (* (rem n 10) a) c)))) (defun first-n-number-for-each-root (n &optional (r 0) (lst nil) (c 0))  "Return the first m number with MDR = 0 to 9"  (cond ((and (= (length lst) n) (= r 9)) (format t "[email protected]: ~a~%" r (reverse lst)))	((= (length lst) n) (format t "[email protected]: ~a~%" r (reverse lst))	                    (first-n-number-for-each-root n (+ r 1) nil 0))	((= (first (mdr/p c)) r) (first-n-number-for-each-root n r (cons c lst) (+ c 1)))	(t (first-n-number-for-each-root n r lst (+ c 1))))) (defun start ()  (format t "Number: MDR  MD~%")  (loop for el in '(123321 7739 893 899998)        do (format t "[email protected]: ~{[email protected] ~}~%" el (mdr/p el)))  (format t "~%MDR: [n0..n4]~%")  (first-n-number-for-each-root 5))`
Output:
```Number: MDR  MD
123321:   8   3
7739:   8   3
893:   2   3
899998:   0   2

MDR: [n0..n4]
0: (0 10 20 25 30)
1: (1 11 111 1111 11111)
2: (2 12 21 26 34)
3: (3 13 31 113 131)
4: (4 14 22 27 39)
5: (5 15 35 51 53)
6: (6 16 23 28 32)
7: (7 17 71 117 171)
8: (8 18 24 29 36)
9: (9 19 33 91 119)```

Component Pascal

` MODULE MDR;IMPORT StdLog, Strings, TextMappers, DevCommanders; PROCEDURE CalcMDR(x: LONGINT; OUT mdr, mp: LONGINT);VAR	str: ARRAY 64 OF CHAR;	i: INTEGER;BEGIN	mdr := 1; mp := 0;	LOOP		Strings.IntToString(x,str);		IF LEN(str\$) = 1 THEN mdr := x; EXIT END;		i := 0;mdr := 1;		WHILE i < LEN(str\$) DO			mdr := mdr * (ORD(str[i]) - ORD('0'));			INC(i)		END;		INC(mp);		x := mdr	ENDEND CalcMDR; PROCEDURE Do*;VAR	mdr,mp: LONGINT;	s: TextMappers.Scanner;BEGIN	s.ConnectTo(DevCommanders.par.text);	s.SetPos(DevCommanders.par.beg);	REPEAT		s.Scan;		IF (s.type = TextMappers.int) OR (s.type = TextMappers.lint) THEN			CalcMDR(s.int,mdr,mp);			StdLog.Int(s.int);			StdLog.String(" MDR: ");StdLog.Int(mdr);			StdLog.String(" MP: ");StdLog.Int(mp);StdLog.Ln		END	UNTIL s.rider.eot;END Do; PROCEDURE Show(i: INTEGER; x: ARRAY OF LONGINT);VAR	k: INTEGER;BEGIN	StdLog.Int(i);StdLog.String(": ");	FOR k := 0 TO LEN(x) - 1 DO		StdLog.Int(x[k])	END;	StdLog.LnEND Show; PROCEDURE FirstFive*;VAR	i,j: INTEGER;	five: ARRAY 5 OF LONGINT;	x,mdr,mp: LONGINT;BEGIN	FOR i := 0 TO 9 DO		j := 0;x := 0;		WHILE (j < LEN(five)) DO			CalcMDR(x,mdr,mp);			IF mdr = i THEN five[j] := x; INC(j) END;			INC(x)		END;		Show(i,five)	ENDEND FirstFive; END MDR. `

Execute: ^Q MDR.Do 123321 7739 893 899998 ~

Output:
``` 123321 MDR:  8 MP:  3
7739 MDR:  8 MP:  3
893 MDR:  2 MP:  3
899998 MDR:  0 MP:  2
```

Execute: ^Q MDR.FirstFive

Output:
``` 0:  0 10 20 25 30
1:  1 11 111 1111 11111
2:  2 12 21 26 34
3:  3 13 31 113 131
4:  4 14 22 27 39
5:  5 15 35 51 53
6:  6 16 23 28 32
7:  7 17 71 117 171
8:  8 18 24 29 36
9:  9 19 33 91 119
```

D

Translation of: Python
`import std.stdio, std.algorithm, std.typecons, std.range, std.conv; /// Multiplicative digital root.auto mdRoot(in int n) pure /*nothrow*/ {    auto mdr = [n];    while (mdr.back > 9)        mdr ~= reduce!q{a * b}(1, mdr.back.text.map!(d => d - '0'));        //mdr ~= mdr.back.text.map!(d => d - '0').mul;        //mdr ~= mdr.back.reverseDigits.mul;    return tuple(mdr.length - 1, mdr.back);} void main() {    "Number: (MP, MDR)\n======  =========".writeln;    foreach (immutable n; [123321, 7739, 893, 899998])        writefln("%6d: (%s, %s)", n, n.mdRoot[]);     auto table = (int[]).init.repeat.enumerate!int.take(10).assocArray;    auto n = 0;    while (table.byValue.map!walkLength.reduce!min < 5) {        table[n.mdRoot[1]] ~= n;        n++;    }    "\nMP: [n0..n4]\n==  ========".writeln;    foreach (const mp; table.byKey.array.sort())        writefln("%2d: %s", mp, table[mp].take(5));}`
Output:
```Number: (MP, MDR)
======  =========
123321: (3, 8)
7739: (3, 8)
893: (3, 2)
899998: (2, 0)

MP: [n0..n4]
==  ========
0: [0, 10, 20, 25, 30]
1: [1, 11, 111, 1111, 11111]
2: [2, 12, 21, 26, 34]
3: [3, 13, 31, 113, 131]
4: [4, 14, 22, 27, 39]
5: [5, 15, 35, 51, 53]
6: [6, 16, 23, 28, 32]
7: [7, 17, 71, 117, 171]
8: [8, 18, 24, 29, 36]
9: [9, 19, 33, 91, 119]```

Alternative Version

`import std.stdio, std.algorithm, std.typecons, std.range; uint digitsProduct(uint n) pure nothrow @nogc {    typeof(return) result = !!n;    while (n) {        result *= n % 10;        n /= 10;    }    return result;} /// Multiplicative digital root.Tuple!(size_t, uint) mdRoot(uint m) pure nothrow {    auto mdr = m               .recurrence!((a, n) => a[n - 1].digitsProduct)               .until!q{ a <= 9 }(OpenRight.no).array;    return tuple(mdr.length - 1, mdr.back);} void main() {    "Number: (MP, MDR)\n======  =========".writeln;    foreach (immutable n; [123321, 7739, 893, 899998])        writefln("%6d: (%s, %s)", n, n.mdRoot[]);     auto table = (int[]).init.repeat.enumerate!int.take(10).assocArray;    auto n = 0;    while (table.byValue.map!walkLength.reduce!min < 5) {        table[n.mdRoot[1]] ~= n;        n++;    }    "\nMP: [n0..n4]\n==  ========".writeln;    foreach (const mp; table.byKey.array.sort())        writefln("%2d: %s", mp, table[mp].take(5));}`

More Efficient Version

`import std.stdio, std.algorithm, std.range; /// Multiplicative digital root.uint[2] mdRoot(in uint n) pure nothrow @nogc {    uint mdr = n;    uint count = 0;     while (mdr > 9) {        uint m = mdr;        uint digitsMul = !!m;        while (m) {            digitsMul *= m % 10;            m /= 10;        }        mdr = digitsMul;        count++;    }     return [count, mdr];} void main() {    "Number: [MP, MDR]\n======  =========".writeln;    foreach (immutable n; [123321, 7739, 893, 899998])        writefln("%6d: %s", n, n.mdRoot);     auto table = (int[]).init.repeat.enumerate!int.take(10).assocArray;    auto n = 0;    while (table.byValue.map!walkLength.reduce!min < 5) {        table[n.mdRoot[1]] ~= n;        n++;    }    "\nMP: [n0..n4]\n==  ========".writeln;    foreach (const mp; table.byKey.array.sort())        writefln("%2d: %s", mp, table[mp].take(5));}`

The output is similar.

Elixir

`defmodule Digital do  def mdroot(n), do: mdroot(n, 0)   defp mdroot(n, persist) when n < 10, do: {n, persist}  defp mdroot(n, persist), do: mdroot(product(n, 1), persist+1)   defp product(0, prod), do: prod  defp product(n, prod), do: product(div(n, 10), prod*rem(n, 10))   def task1(data) do    IO.puts "Number: MDR  MP\n======  ===  =="    Enum.each(data, fn n ->      {mdr, persist} = mdroot(n)      :io.format "~6w:   ~w  ~2w~n", [n, mdr, persist]    end)  end   def task2(m \\ 5) do    IO.puts "\nMDR: [n0..n#{m-1}]\n===  ========"    map = add_map(0, m, Map.new)    Enum.each(0..9, fn i ->      first = map[i] |> Enum.reverse |> Enum.take(m)      IO.puts "  #{i}: #{inspect first}"    end)  end   defp add_map(n, m, map) do    {mdr, _persist} = mdroot(n)    new_map = Map.update(map, mdr, [n], fn vals -> [n | vals] end)    min_len = Map.values(new_map) |> Enum.map(&length(&1)) |> Enum.min    if min_len < m, do: add_map(n+1, m, new_map),                  else: new_map  endend Digital.task1([123321, 7739, 893, 899998])Digital.task2`
Output:
```Number: MDR  MP
======  ===  ==
123321:   8   3
7739:   8   3
893:   2   3
899998:   0   2

MDR: [n0..n4]
===  ========
0: [0, 10, 20, 25, 30]
1: [1, 11, 111, 1111, 11111]
2: [2, 12, 21, 26, 34]
3: [3, 13, 31, 113, 131]
4: [4, 14, 22, 27, 39]
5: [5, 15, 35, 51, 53]
6: [6, 16, 23, 28, 32]
7: [7, 17, 71, 117, 171]
8: [8, 18, 24, 29, 36]
9: [9, 19, 33, 91, 119]
```

Factor

`USING: arrays formatting fry io kernel lists lists.lazy mathmath.text.utils prettyprint sequences ;IN: rosetta-code.multiplicative-digital-root : mdr ( n -- {persistence,root} )    0 swap    [ 1 digit-groups dup length 1 > ] [ product [ 1 + ] dip ] while    dup empty? [ drop { 0 } ] when first 2array ; : print-mdr ( n -- )    dup [ 1array ] dip mdr append    "%-12d has multiplicative persistence %d and MDR %d.\n"    vprintf ; : first5 ( n -- seq ) ! first 5 numbers with MDR of n    0 lfrom swap '[ mdr second _ = ] lfilter 5 swap ltake list>array ; : print-first5 ( i n -- )    "%-5d" printf bl first5 [ "%-5d " printf ] each nl ; : header ( -- )    "MDR | First five numbers with that MDR" print    "--------------------------------------" print ; : first5-table ( -- )    header 10 iota [ print-first5 ] each-index ; : main ( -- )    { 123321 7739 893 899998 } [ print-mdr ] each nl first5-table ; MAIN: main`
Output:
```123321       has multiplicative persistence 3 and MDR 8.
7739         has multiplicative persistence 3 and MDR 8.
893          has multiplicative persistence 3 and MDR 2.
899998       has multiplicative persistence 2 and MDR 0.

MDR | First five numbers with that MDR
--------------------------------------
0     0     10    20    25    30
1     1     11    111   1111  11111
2     2     12    21    26    34
3     3     13    31    113   131
4     4     14    22    27    39
5     5     15    35    51    53
6     6     16    23    28    32
7     7     17    71    117   171
8     8     18    24    29    36
9     9     19    33    91    119
```

Fortran

` !Implemented by Anant Dixit (Oct, 2014)program mdrimplicit noneinteger :: i, mdr, mp, n, jcharacter(len=*), parameter :: hfmt = '(A18)', nfmt = '(I6)'character(len=*), parameter :: cfmt = '(A3)', rfmt = '(I3)', ffmt = '(I9)' write(*,hfmt) 'Number   MDR   MP 'write(*,*) '------------------' i = 123321call root_pers(i,mdr,mp)write(*,nfmt,advance='no') iwrite(*,cfmt,advance='no') '   'write(*,rfmt,advance='no') mdrwrite(*,cfmt,advance='no') '   'write(*,rfmt) mp i = 3939call root_pers(i,mdr,mp)write(*,nfmt,advance='no') iwrite(*,cfmt,advance='no') '   'write(*,rfmt,advance='no') mdrwrite(*,cfmt,advance='no') '   'write(*,rfmt) mp i = 8822call root_pers(i,mdr,mp)write(*,nfmt,advance='no') iwrite(*,cfmt,advance='no') '   'write(*,rfmt,advance='no') mdrwrite(*,cfmt,advance='no') '   'write(*,rfmt) mp i = 39398call root_pers(i,mdr,mp)write(*,nfmt,advance='no') iwrite(*,cfmt,advance='no') '   'write(*,rfmt,advance='no') mdrwrite(*,cfmt,advance='no') '   'write(*,rfmt) mp write(*,*)write(*,*)write(*,*) 'First five numbers with MDR in first column: 'write(*,*) '---------------------------------------------' do i = 0,9  n = 0  j = 0  write(*,rfmt,advance='no') i  do    call root_pers(j,mdr,mp)    if(mdr.eq.i) then      n = n+1      if(n.eq.5) then        write(*,ffmt) j        exit      else        write(*,ffmt,advance='no') j      end if    end if    j = j+1  end doend do end program subroutine root_pers(i,mdr,mp)implicit noneinteger :: N, s, a, i, mdr, mpn = ia = 0if(n.lt.10) then  mdr = n  mp = 0  returnend ifdo while(n.ge.10)  a = a + 1  s = 1  do while(n.gt.0)    s = s * mod(n,10)    n = int(real(n)/10.0D0)  end do  n = send domdr = smp = aend subroutine  `
```Number   MDR   MP
------------------
123321     8     3
3939     2     4
8822     0     3
39398     0     3

First five numbers with MDR in first column:
---------------------------------------------
0        0       10       20       25       30
1        1       11      111     1111    11111
2        2       12       21       26       34
3        3       13       31      113      131
4        4       14       22       27       39
5        5       15       35       51       53
6        6       16       23       28       32
7        7       17       71      117      171
8        8       18       24       29       36
9        9       19       33       91      119

```

FreeBASIC

`' FB 1.05.0 Win64 Function multDigitalRoot(n As UInteger, ByRef mp As Integer, base_ As Integer = 10) As Integer  Dim mdr As Integer  mp = 0  Do     mdr = IIf(n > 0, 1, 0)     While n > 0      mdr *= n Mod base_      n = n \ base_    Wend    mp += 1    n = mdr  Loop until mdr < base_  Return mdrEnd Function Dim As Integer mdr, mpDim a(3) As UInteger = {123321, 7739, 893, 899998}For i As UInteger = 0 To 3 mp = 0 mdr = multDigitalRoot(a(i), mp) Print a(i); Tab(10); "MDR ="; mdr; Tab(20); "MP ="; mp PrintNextPrintPrint "MDR    1     2     3     4     5"Print "===  ==========================="PrintDim num(0 To 9, 0 To 5) As UInteger '' all zero by defaultDim As UInteger n = 0, count = 0Do  mdr = multDigitalRoot(n, mp)  If num(mdr, 0) < 5 Then    num(mdr, 0) += 1    num(mdr, num(mdr, 0)) = n    count += 1  End If  n += 1Loop Until count = 50 For i As UInteger = 0 To 9  Print i; ":" ;  For j As UInteger = 1 To 5    Print Using "######"; num(i, j);  Next j  PrintNext i PrintPrint "Press any key to quit"Sleep`
Output:
```123321   MDR = 8   MP = 3

7739     MDR = 8   MP = 3

893      MDR = 2   MP = 3

899998   MDR = 0   MP = 2

MDR    1     2     3     4     5
===  ===========================

0:     0    10    20    25    30
1:     1    11   111  1111 11111
2:     2    12    21    26    34
3:     3    13    31   113   131
4:     4    14    22    27    39
5:     5    15    35    51    53
6:     6    16    23    28    32
7:     7    17    71   117   171
8:     8    18    24    29    36
9:     9    19    33    91   119
```

Go

`package main import "fmt" // Only valid for n > 0 && base >= 2func mult(n uint64, base int) (mult uint64) {	for mult = 1; mult > 0 && n > 0; n /= uint64(base) {		mult *= n % uint64(base)	}	return} // Only valid for n >= 0 && base >= 2func MultDigitalRoot(n uint64, base int) (mp, mdr int) {	var m uint64	for m = n; m >= uint64(base); mp++ {		m = mult(m, base)	}	return mp, int(m)} func main() {	const base = 10	const size = 5 	const testFmt = "%20v %3v %3v\n"	fmt.Printf(testFmt, "Number", "MDR", "MP")	for _, n := range [...]uint64{		123321, 7739, 893, 899998,		18446743999999999999,		// From http://mathworld.wolfram.com/MultiplicativePersistence.html		3778888999, 277777788888899,	} {		mp, mdr := MultDigitalRoot(n, base)		fmt.Printf(testFmt, n, mdr, mp)	}	fmt.Println() 	var list [base][]uint64	for i := range list {		list[i] = make([]uint64, 0, size)	}	for cnt, n := size*base, uint64(0); cnt > 0; n++ {		_, mdr := MultDigitalRoot(n, base)		if len(list[mdr]) < size {			list[mdr] = append(list[mdr], n)			cnt--		}	}	const tableFmt = "%3v: %v\n"	fmt.Printf(tableFmt, "MDR", "First")	for i, l := range list {		fmt.Printf(tableFmt, i, l)	}}`
Output:
```              Number MDR  MP
123321   8   3
7739   8   3
893   2   3
899998   0   2
18446743999999999999   0   2
3778888999   0  10
277777788888899   0  11

MDR: First
0: [0 10 20 25 30]
1: [1 11 111 1111 11111]
2: [2 12 21 26 34]
3: [3 13 31 113 131]
4: [4 14 22 27 39]
5: [5 15 35 51 53]
6: [6 16 23 28 32]
7: [7 17 71 117 171]
8: [8 18 24 29 36]
9: [9 19 33 91 119]
```

Note that in the function `mdrNums` we don't know in advance how many numbers we'll need to examine to find the first 5 associated with all the MDRs. Using a lazy array to accumulate these numbers allows us to keep the function simple.

`import Control.Arrowimport Data.Arrayimport Data.LazyArrayimport Data.List (unfoldr)import Data.Tupleimport Text.Printf -- The multiplicative persistence (MP) and multiplicative digital root (MDR) of-- the argument.mpmdr :: Integer -> (Int, Integer)mpmdr = (length *** head) . span (> 9) . iterate (product . digits) -- Pairs (mdr, ns) where mdr is a multiplicative digital root and ns are the-- first k numbers having that root.mdrNums :: Int -> [(Integer, [Integer])]mdrNums k = assocs \$ lArrayMap (take k) (0,9) [(snd \$ mpmdr n, n) | n <- [0..]] digits :: Integral t => t -> [t]digits 0 = [0]digits n = unfoldr step n  where step 0 = Nothing        step k = Just (swap \$ quotRem k 10) printMpMdrs :: [Integer] -> IO ()printMpMdrs ns = do  putStrLn "Number MP MDR"  putStrLn "====== == ==="  sequence_ [printf "%6d %2d %2d\n" n p r | n <- ns, let (p,r) = mpmdr n] printMdrNums:: Int -> IO ()printMdrNums k = do  putStrLn "MDR Numbers"  putStrLn "=== ======="  let showNums = unwords . map show  sequence_ [printf "%2d  %s\n" mdr \$ showNums ns | (mdr,ns) <- mdrNums k] main :: IO ()main = do  printMpMdrs [123321, 7739, 893, 899998]  putStrLn ""  printMdrNums 5`
Output:

Note that the values in the first column of the table are MDRs, as shown in the task's sample output, not MP as incorrectly stated in the task statement and column header.

```Number MP MDR
====== == ===
123321  3  8
7739  3  8
893  3  2
899998  2  0

MDR Numbers
=== =======
0  0 10 20 25 30
1  1 11 111 1111 11111
2  2 12 21 26 34
3  3 13 31 113 131
4  4 14 22 27 39
5  5 15 35 51 53
6  6 16 23 28 32
7  7 17 71 117 171
8  8 18 24 29 36
9  9 19 33 91 119```

Icon and Unicon

Works in both languages:

`procedure main(A)    write(right("n",8)," ",right("MP",8),right("MDR",5))    every r := mdr(n := 123321|7739|893|899998) do        write(right(n,8),":",right(r[1],8),right(r[2],5))    write()    write(right("MDR",5),"  ","[n0..n4]")    every m := 0 to 9 do {        writes(right(m,5),": [")        every writes(right((m = mdr(n := seq(m))[2],.n)\5,6))        write("]")        }end procedure mdr(m)    i := 0    while (.m > 10, m := multd(m), i+:=1)    return [i,m]end procedure multd(m)    c := 1    while m > 0 do c *:= 1(m%10, m/:=10)    return cend`
Output:
```->drmdr
n       MP  MDR
123321:       3    8
7739:       3    8
893:       3    2
899998:       2    0

MDR  [n0..n4]
0: [     0    20    30    40    45]
1: [     1    11   111  1111 11111]
2: [     2    12    21    26    34]
3: [     3    13    31   113   131]
4: [     4    14    22    27    39]
5: [     5    15    35    51    53]
6: [     6    16    23    28    32]
7: [     7    17    71   117   171]
8: [     8    18    24    29    36]
9: [     9    19    33    91   119]
->
```

J

First, we need something to split a number into digits:

`   10&#.inv 1233211 2 3 3 2 1`

Second, we need to find their product:

`   */@(10&#.inv) 12332136`

Then we use this inductively until it converges:

`   */@(10&#.inv)^:a: 123321123321 36 18 8`

MP is one less than the length of this list, and MDR is the last element of this list:

`   (<:@#,{:) */@(10&#.inv)^:a: 1233213 8   (<:@#,{:) */@(10&#.inv)^:a: 77393 8   (<:@#,{:) */@(10&#.inv)^:a: 8933 2   (<:@#,{:) */@(10&#.inv)^:a: 8999982 0`

For the table, we don't need that whole list, we only need the final value. Then use these values to classify the original argument (taking the first five from each group):

`   (5&{./.~ (*/@(10&#.inv)^:_)"0) i.200000 10  20   25    301 11 111 1111 111112 12  21   26    343 13  31  113   1314 14  22   27    395 15  35   51    536 16  23   28    327 17  71  117   1718 18  24   29    369 19  33   91   119`

Note that since the first 10 non-negative integers are single digit values, the first column here doubles as a label (representing the corresponding multiplicative digital root).

Java

Works with: Java version 8
`import java.util.*; public class MultiplicativeDigitalRoot {     public static void main(String[] args) {         System.out.println("NUMBER  MDR   MP");        for (long n : new long[]{123321, 7739, 893, 899998}) {            long[] a = multiplicativeDigitalRoot(n);            System.out.printf("%6d %4d %4d%n", a[0], a[1], a[2]);        }         System.out.println();         Map<Long, List<Long>> table = new HashMap<>();        for (long i = 0; i < 10; i++)            table.put(i, new ArrayList<>());         for (long cnt = 0, n = 0; cnt < 10;) {            long[] res = multiplicativeDigitalRoot(n++);            List<Long> list = table.get(res[1]);            if (list.size() < 5) {                list.add(res[0]);                cnt = list.size() == 5 ? cnt + 1 : cnt;            }        }         System.out.println("MDR: first five numbers with same MDR");        table.forEach((key, lst) -> {            System.out.printf("%3d: ", key);            lst.forEach(e -> System.out.printf("%6s ", e));            System.out.println();        });    }     public static long[] multiplicativeDigitalRoot(long n) {        int mp = 0;        long mdr = n;        while (mdr > 9) {            long m = mdr;            long total = 1;            while (m > 0) {                total *= m % 10;                m /= 10;            }            mdr = total;            mp++;        }        return new long[]{n, mdr, mp};    }}`
```NUMBER  MDR   MP
123321    8    3
7739    8    3
893    2    3
899998    0    2

MDR: first five numbers with same MDR
0:      0     10     20     25     30
1:      1     11    111   1111  11111
2:      2     12     21     26     34
3:      3     13     31    113    131
4:      4     14     22     27     39
5:      5     15     35     51     53
6:      6     16     23     28     32
7:      7     17     71    117    171
8:      8     18     24     29     36
9:      9     19     33     91    119 ```

jq

`def do_until(condition; next):  def u: if condition then . else (next|u) end;  u; def mdroot(n):  def multiply: reduce .[] as \$i (1; .*\$i);  # state: [mdr, persist]  [n, 0]  | do_until( .[0] < 10;              [(.[0] | tostring | explode | map(.-48) | multiply), .[1] + 1]            ); # Produce a table with 10 rows (numbered from 0),# showing the first n numbers having the row-number as the mdrdef tabulate(n):  # state: [answer_matrix, next_i]  def tab:    def minlength: map(length) | min;    .[0] as \$matrix    | .[1] as \$i    | if (.[0]|minlength) == n then .[0]      else (mdroot(\$i) | .[0]) as \$mdr      | if \$matrix[\$mdr]|length < n then           (\$matrix[\$mdr] + [\$i]) as \$row          | \$matrix | setpath([\$mdr]; \$row)        else \$matrix        end      | [ ., \$i + 1 ]      | tab      end;   [[], 0]  | tab;`
Example:
` def neatly:  . as \$in  | range(0;length)   | "\(.): \(\$in[.])"; def rjust(n): tostring | (n-length)*" " + .; # The task:"  i   : [MDR, MP]",((123321, 7739, 893, 899998) as \$i | "\(\$i|rjust(6)): \(mdroot(\$i))"),"","Tabulation","MDR: [n0..n4]",(tabulate(5) | neatly)`
Output:
`\$ jq -n -r -c -f mdr.jq   i   : [MDR, MP]123321: [8,3]  7739: [8,3]   893: [2,3]899998: [0,2] TabulationMDR: [n0..n4]0: [0,10,20,25,30]1: [1,11,111,1111,11111]2: [2,12,21,26,34]3: [3,13,31,113,131]4: [4,14,22,27,39]5: [5,15,35,51,53]6: [6,16,23,28,32]7: [7,17,71,117,171]8: [8,18,24,29,36]9: [9,19,33,91,119]`

Julia

Function

` function digitalmultroot{S<:Integer,T<:Integer}(n::S, bs::T=10)    -1 < n && 1 < bs || throw(DomainError())    ds = n    pers = 0    while bs <= ds        ds = prod(digits(ds, bs))        pers += 1    end    return (pers, ds)end `

Main

` const bs = 10const excnt = 5 println("Testing Multiplicative Digital Root.\n")for i in [123321, 7739, 893, 899998]    (pers, ds) = digitalmultroot(i, bs)    print(@sprintf("%8d", i))    print(" has persistence ", pers)    println(" and digital root ", ds)end dmr = zeros(Int, bs, excnt)hasroom = trues(bs)dex = ones(Int, bs) i = 0while any(hasroom)    (pers, ds) = digitalmultroot(i, bs)    ds += 1    if hasroom[ds]        dmr[ds, dex[ds]] = i        dex[ds] += 1        if dex[ds] > excnt            hasroom[ds] = false        end    end    i += 1end println("\n MDR:    First ", excnt, " numbers having this MDR")for (i, d) in enumerate(0:(bs-1))    print(@sprintf("%4d: ", d))    println(join([@sprintf("%6d", dmr[i, j]) for j in 1:excnt], ","))end `
Output:
```Testing Multiplicative Digital Root.

123321 has persistence 3 and digital root 8
7739 has persistence 3 and digital root 8
893 has persistence 3 and digital root 2
899998 has persistence 2 and digital root 0

MDR:    First 5 numbers having this MDR
0:      0,    10,    20,    25,    30
1:      1,    11,   111,  1111, 11111
2:      2,    12,    21,    26,    34
3:      3,    13,    31,   113,   131
4:      4,    14,    22,    27,    39
5:      5,    15,    35,    51,    53
6:      6,    16,    23,    28,    32
7:      7,    17,    71,   117,   171
8:      8,    18,    24,    29,    36
9:      9,    19,    33,    91,   119
```

Kotlin

Translation of: FreeBASIC
`// version 1.1.2 fun multDigitalRoot(n: Int): Pair<Int, Int> = when {        n < 0   -> throw IllegalArgumentException("Negative numbers not allowed")        else    -> {            var mdr: Int            var mp = 0            var nn = n            do {                mdr = if (nn > 0) 1 else 0                while (nn > 0) {                    mdr *= nn % 10                    nn /= 10                }                mp++                nn = mdr            }            while (mdr >= 10)            Pair(mdr, mp)        }    } fun main(args: Array<String>) {    val ia = intArrayOf(123321, 7739, 893, 899998)    for (i in ia) {        val (mdr, mp) = multDigitalRoot(i)        println("\${i.toString().padEnd(9)} MDR = \$mdr  MP = \$mp")    }    println()    println("MDR   n0    n1    n2    n3    n4")    println("===  ===========================")    val ia2 = Array(10) { IntArray(6) } // all zero by default    var n = 0    var count = 0    do {        val (mdr, _) = multDigitalRoot(n)        if (ia2[mdr][0] < 5) {            ia2[mdr][0]++            ia2[mdr][ia2[mdr][0]] = n            count++        }        n++    }    while (count < 50)     for (i in 0..9) {        print("\$i:")        for (j in 1..5) print("%6d".format(ia2[i][j]))        println()    }}`
Output:
```123321    MDR = 8  MP = 3
7739      MDR = 8  MP = 3
893       MDR = 2  MP = 3
899998    MDR = 0  MP = 2

MDR   n0    n1    n2    n3    n4
===  ===========================
0:     0    10    20    25    30
1:     1    11   111  1111 11111
2:     2    12    21    26    34
3:     3    13    31   113   131
4:     4    14    22    27    39
5:     5    15    35    51    53
6:     6    16    23    28    32
7:     7    17    71   117   171
8:     8    18    24    29    36
9:     9    19    33    91   119
```

Mathematica / Wolfram Language

` ClearAll[mdr, mp, nums];mdr[n_] := NestWhile[Times @@ IntegerDigits[#] &, n, # > 9 &];mp[n_] := [email protected][Times @@ IntegerDigits[#] &, n, # > 9 &] - 1;TableForm[{#, mdr[#], mp[#]} & /@ {123321, 7739, 893, 899998},  TableHeadings -> {None, {"Number", "MDR", "MP"}}]nums = ConstantArray[{}, 10];For[i = 0, Min[Length /@ nums] < 5, i++,  AppendTo[nums[[mdr[i] + 1]], i]];TableForm[Table[{i, Take[nums[[i + 1]], 5]}, {i, 0, 9}],  TableHeadings -> {None, {"MDR", "First 5"}}, TableDepth -> 2] `
Output:
```Number   MDR   MP
-----------------
123321   8     3
7739     8     3
893      2     3
899998   0     2

MDR   First 5
-----------------------------
0   {0, 10, 20, 25, 30}
1   {1, 11, 111, 1111, 11111}
2   {2, 12, 21, 26, 34}
3   {3, 13, 31, 113, 131}
4   {4, 14, 22, 27, 39}
5   {5, 15, 35, 51, 53}
6   {6, 16, 23, 28, 32}
7   {7, 17, 71, 117, 171}
8   {8, 18, 24, 29, 36}
9   {9, 19, 33, 91, 119}
```

Nim

Translation of: Python
`import strutils, future template newSeqWith(len: int, init: expr): expr =  var result {.gensym.} = newSeq[type(init)](len)  for i in 0 .. <len:    result[i] = init  result proc mdroot(n): tuple[mp, mdr: int] =  var mdr = @[n]  while mdr[mdr.high] > 9:    var n = 1    for dig in \$mdr[mdr.high]:      n *= parseInt(\$dig)    mdr.add n  (mdr.high, mdr[mdr.high]) for n in [123321, 7739, 893, 899998]:  echo align(\$n, 6)," ",mdroot(n)echo "" var table = newSeqWith(10, newSeq[int]())for n in 0..int.high:  if table.map((x: seq[int]) => x.len).min >= 5: break  table[mdroot(n).mdr].add n for mp, val in table:  echo mp,": ",val[0..4]`
Output:
```123321 (mp: 3, mdr: 8)
7739 (mp: 3, mdr: 8)
893 (mp: 3, mdr: 2)
899998 (mp: 2, mdr: 0)

0: @[0, 10, 20, 25, 30]
1: @[1, 11, 111, 1111, 11111]
2: @[2, 12, 21, 26, 34]
3: @[3, 13, 31, 113, 131]
4: @[4, 14, 22, 27, 39]
5: @[5, 15, 35, 51, 53]
6: @[6, 16, 23, 28, 32]
7: @[7, 17, 71, 117, 171]
8: @[8, 18, 24, 29, 36]
9: @[9, 19, 33, 91, 119]```

PARI/GP

`a(n)=my(i);while(n>9,n=factorback(digits(n));i++);[i,n];apply(a, [123321, 7739, 893, 899998])v=vector(10,i,[]); forstep(n=0,oo,1, t=a(n)[2]+1; if(#v[t]<5,v[t]=concat(v[t],n); if(vecmin(apply(length,v))>4, return(v))))`
Output:
```%1 = [[3, 8], [3, 8], [3, 2], [2, 0]]
%2 = [[0, 10, 20, 25, 30], [1, 11, 111, 1111, 11111], [2, 12, 21, 26, 34], [3, 13, 31, 113, 131], [4, 14, 22, 27, 39], [5, 15, 35, 51, 53], [6, 16, 23, 28, 32], [7, 17, 71, 117, 171], [8, 18, 24, 29, 36], [9, 19, 33, 91, 119]]```

Perl

Translation of: D
`use warnings;use strict; sub mdr {  my \$n = shift;  my(\$count, \$mdr) = (0, \$n);  while (\$mdr > 9) {    my(\$m, \$dm) = (\$mdr, 1);    while (\$m) {      \$dm *= \$m % 10;      \$m = int(\$m/10);    }    \$mdr = \$dm;    \$count++;  }  (\$count, \$mdr);} print "Number: (MP, MDR)\n======  =========\n";foreach my \$n (123321, 7739, 893, 899998) {  printf "%6d: (%d, %d)\n", \$n, mdr(\$n);}print "\nMP: [n0..n4]\n==  ========\n";foreach my \$target (0..9) {  my \$i = 0;  my @n = map { \$i++ while (mdr(\$i))[1] != \$target; \$i++; } 1..5;  print " \$target: [", join(", ", @n), "]\n";}`
Output:
```Number: (MP, MDR)
======  =========
123321: (3, 8)
7739: (3, 8)
893: (3, 2)
899998: (2, 0)

MP: [n0..n4]
==  ========
0: [0, 10, 20, 25, 30]
1: [1, 11, 111, 1111, 11111]
2: [2, 12, 21, 26, 34]
3: [3, 13, 31, 113, 131]
4: [4, 14, 22, 27, 39]
5: [5, 15, 35, 51, 53]
6: [6, 16, 23, 28, 32]
7: [7, 17, 71, 117, 171]
8: [8, 18, 24, 29, 36]
9: [9, 19, 33, 91, 119]```

Perl 6

`sub multiplicative-digital-root(Int \$n) {    return .elems - 1, .[.end]        given cache(\$n, {[*] .comb} ... *.chars == 1)} for 123321, 7739, 893, 899998 {    say "\$_: ", .&multiplicative-digital-root;} for ^10 -> \$d {    say "\$d : ", .[^5]        given (1..*).grep: *.&multiplicative-digital-root[1] == \$d;}`
Output:
```123321: 3 8
7739: 3 8
893: 3 2
899998: 2 0
0 : 10 20 25 30 40
1 : 1 11 111 1111 11111
2 : 2 12 21 26 34
3 : 3 13 31 113 131
4 : 4 14 22 27 39
5 : 5 15 35 51 53
6 : 6 16 23 28 32
7 : 7 17 71 117 171
8 : 8 18 24 29 36
9 : 9 19 33 91 119```

Phix

`function mdr_mp(integer m)integer mp = 0    while m>9 do        integer newm = 1        while m do            newm *= remainder(m,10)            m = floor(m/10)        end while        m = newm        mp += 1    end while    return {m,mp}end function constant tests = {123321, 7739, 893, 899998}printf(1,"Number     MDR     MP\n")printf(1,"======     ===     ==\n")for i=1 to length(tests) do    integer ti = tests[i]    printf(1,"%6d %6d %6d\n",ti&mdr_mp(ti))end for integer i=0, found = 0sequence res = repeat({},10)while found<50 do    integer {mdr,mp} = mdr_mp(i)    if length(res[mdr+1])<5 then        res[mdr+1] &= i        found += 1    end if    i += 1end while printf(1,"\nMDR    1     2     3     4     5")printf(1,"\n===  ===========================\n") for i=1 to 10 do    printf(1,"%2d %5d %5d %5d %5d %5d\n",prepend(res[i],i-1))end for`
Output:
```Number     MDR     MP
======     ===     ==
123321      8      3
7739      8      3
893      2      3
899998      0      2

MDR    1     2     3     4     5
===  ===========================
0     0    10    20    25    30
1     1    11   111  1111 11111
2     2    12    21    26    34
3     3    13    31   113   131
4     4    14    22    27    39
5     5    15    35    51    53
6     6    16    23    28    32
7     7    17    71   117   171
8     8    18    24    29    36
9     9    19    33    91   119
```

PL/I

version 1

 This example is incomplete. Missing second half of task! Please ensure that it meets all task requirements and remove this message.
`multiple: procedure options (main);  /* 29 April 2014 */    declare n fixed binary (31); find_mdr: procedure;   declare (mdr, mp, p) fixed binary (31);    mdr = n;   do mp = 1 by 1 until (p <= 9);      p = 1;      do until (mdr = 0); /* Form product of the digits in mdr. */         p = mod(mdr, 10) * p;         mdr= mdr/10;      end;      mdr = p;   end;   put skip data (n, mdr, mp);end find_mdr;    do n = 123321, 7739, 893, 899998;      call find_mdr;   end; end multiple;`
Output:
```N=        123321        MDR=             8      MP=             3;
N=          7739        MDR=             8      MP=             3;
N=           893        MDR=             2      MP=             3;
N=        899998        MDR=             0      MP=             2;```

version 2

` mdrt: Proc Options(main); Dcl (x,p,r) Bin Fixed(31); Put Edit('number   persistence   multiplicative digital root')(Skip,a); Put Edit('-------  -----------   ---------------------------')(Skip,a); Call task1(123321); Call task1(  7739); Call task1(   893); Call task1(899998);  task1: Procedure(x); Dcl x Bin Fixed(31); Call mdr(x,p,r); Put Edit(x,p,r)(Skip,f(8),f(8),f(22)); End;  Dcl zn(0:9) Bin Fixed(31); Dcl z(0:9,5) Bin Fixed(31); zn=0; zn(0)=1; z(0,1)=0; Do x=1 To 11111;   Call mdr(x,p,r);   If zn(r)<5 Then Do;     zn(r)+=1;     z(r,zn(r))=x;     End;   End; Put Edit(' ')(Skip,a); Put Edit('MDR  first 5 numbers that have a matching MDR')(Skip,a); Put Edit('---  ----------------------------------------')(Skip,a);  Do r=0 To 9;   Put Edit(r,'  ')(Skip,f(3),a);   Do i=1 To 5;     Put Edit(z(r,i))(f(6));     End;   End;  mdr: Procedure(y,p,r); Dcl (y,p,r) Bin Fixed(31); Dcl (k,yy) Bin Fixed(31); Dcl pic Pic'(10)9'; Dcl d   Pic'9'; pic=abs(y); Do p=1 By 1 Until(pic<10);   Do k=1 To 10 Until(substr(pic,k,1)>'0');     End;   r=1;   Do k=k To 10;     d=substr(pic,k,1);     r=r*d;     End;   pic=r;   End; End; End;`
Output:
```number   persistence   multiplicative digital root
-------  -----------   ---------------------------
123321       3                     8
7739       3                     8
893       3                     2
899998       2                     0

MDR  first 5 numbers that have a matching MDR
---  ----------------------------------------
0       0    10    20    25    30
1       1    11   111  1111 11111
2       2    12    21    26    34
3       3    13    31   113   131
4       4    14    22    27    39
5       5    15    35    51    53
6       6    16    23    28    32
7       7    17    71   117   171
8       8    18    24    29    36
9       9    19    33    91   119```

Python

Python: Inspired by the solution to the Digital root task

`try:    from functools import reduceexcept:    pass def mdroot(n):    'Multiplicative digital root'    mdr = [n]    while mdr[-1] > 9:        mdr.append(reduce(int.__mul__, (int(dig) for dig in str(mdr[-1])), 1))    return len(mdr) - 1, mdr[-1] if __name__ == '__main__':    print('Number: (MP, MDR)\n======  =========')    for n in (123321, 7739, 893, 899998):        print('%6i: %r' % (n, mdroot(n)))     table, n = {i: [] for i in range(10)}, 0    while min(len(row) for row in table.values()) < 5:        mpersistence, mdr = mdroot(n)        table[mdr].append(n)        n += 1    print('\nMP: [n0..n4]\n==  ========')    for mp, val in sorted(table.items()):        print('%2i: %r' % (mp, val[:5]))`
Output:
```Number: (MP, MDR)
======  =========
123321: (3, 8)
7739: (3, 8)
893: (3, 2)
899998: (2, 0)

MP: [n0..n4]
==  ========
0: [0, 10, 20, 25, 30]
1: [1, 11, 111, 1111, 11111]
2: [2, 12, 21, 26, 34]
3: [3, 13, 31, 113, 131]
4: [4, 14, 22, 27, 39]
5: [5, 15, 35, 51, 53]
6: [6, 16, 23, 28, 32]
7: [7, 17, 71, 117, 171]
8: [8, 18, 24, 29, 36]
9: [9, 19, 33, 91, 119]```

Python: Inspired by the more efficient version of D.

Substitute the following function to run twice as fast when calculating mdroot(n) with n in range(1000000).

`def mdroot(n):    count, mdr = 0, n     while mdr > 9:        m, digitsMul = mdr, 1        while m:            m, md = divmod(m, 10)            digitsMul *= md        mdr = digitsMul        count += 1    return count, mdr`
Output:

(Exactly the same as before).

Racket

`#lang racket(define (digital-product n)  (define (inr-d-p m rv)    (cond      [(zero? m) rv]      [else (define-values (q r) (quotient/remainder m 10))            (if (zero? r) 0 (inr-d-p q (* rv r)))])) ; lazy on zero  (inr-d-p n 1)) (define (mdr/mp n)  (define (inr-mdr/mp m i)    (if (< m 10) (values m i) (inr-mdr/mp (digital-product m) (add1 i))))  (inr-mdr/mp n 0)) (printf "Number\tMDR\tmp~%======\t===\t==~%")(for ((n (in-list '(123321 7739 893 899998))))  (define-values (mdr mp) (mdr/mp n))  (printf "~a\t~a\t~a~%" n mdr mp)) (printf "~%MDR\t[n0..n4]~%===\t========~%")(for ((MDR (in-range 10)))  (define (has-mdr? n) (define-values (mdr mp) (mdr/mp n)) (= mdr MDR))  (printf "~a\t~a~%" MDR (for/list ((_ 5) (n (sequence-filter has-mdr? (in-naturals)))) n)))`
Output:
```Number	MDR	mp
======	===	==
123321	8	3
7739	8	3
893	2	3
899998	0	2

MDR	[n0..n4]
===	========
0	(0 10 20 25 30)
1	(1 11 111 1111 11111)
2	(2 12 21 26 34)
3	(3 13 31 113 131)
4	(4 14 22 27 39)
5	(5 15 35 51 53)
6	(6 16 23 28 32)
7	(7 17 71 117 171)
8	(8 18 24 29 36)
9	(9 19 33 91 119)```

REXX

idomatic version

`/*REXX program finds the  persistence and multiplicative  digital root  of some numbers.*/numeric digits 100                               /*increase the number of decimal digits*/parse arg x                                      /*obtain optional arguments from the CL*/if x='' | x=","  then x=123321 7739 893 899998   /*Not specified?  Then use the default.*/say center('number', 8)      ' persistence   multiplicative digital root'say copies('─'     , 8)      ' ───────────   ───────────────────────────'                                                 /* [↑]  the title  and  separator.     */     do j=1  for words(x);        n=word(x, j)   /*process each number in the   X  list.*/     parse value  MDR(n)   with   mp mdr         /*obtain the persistence and the  MDR. */     say right(n,8) center(mp,13) center(mdr,30) /*display a number,  persistence,  MDR.*/     end   /*j*/                                 /* [↑]  show MP & MDR for each number. */say;                     target=5say 'MDR        first '  target  " numbers that have a matching MDR"say '═══   ═══════════════════════════════════════════════════'      do k=0  for 10; hits=0;   _=                /*show numbers that have an MDR of  K. */       do m=k  until hits==target                /*find target numbers with an MDR of K.*/       if word( MDR(m), 2)\==k  then iterate     /*is this the  MDR  that's wanted?     */       hits=hits + 1;       _=space(_ m',')      /*yes, we got a hit,  add to the list. */       end   /*m*/                               /* [↑]  built a list of MDRs that = K. */     say " "k':     ['strip(_, , ',')"]"         /*display the  K  (MDR)  and the list. */     end     /*k*/                               /* [↑]  done with the   K   MDR list.  */exit                                             /*stick a fork in it,  we're all done. *//*──────────────────────────────────────────────────────────────────────────────────────*/MDR: procedure; parse arg y; y=abs(y)            /*get the number and determine the MDR.*/                   do p=1      until  y<10;    parse var  y  r  2                       do k=2  to length(y);   r=r * substr(y, k, 1)                       end   /*k*/                   y=r                   end       /*p*/               /* [↑]  wash, rinse, and repeat ···    */                return p r                       /*return the persistence and the  MDR. */`
output   when using the default inputs:
``` number   persistence   multiplicative digital root
────────  ───────────   ───────────────────────────
123321       3                     8
7739       3                     8
893       3                     2
899998       2                     0

MDR        first  5  numbers that have a matching MDR
═══   ═══════════════════════════════════════════════════
0:     [0, 10, 20, 25, 30]
1:     [1, 11, 111, 1111, 11111]
2:     [2, 12, 21, 26, 34]
3:     [3, 13, 31, 113, 131]
4:     [4, 14, 22, 27, 39]
5:     [5, 15, 35, 51, 53]
6:     [6, 16, 23, 28, 32]
7:     [7, 17, 71, 117, 171]
8:     [8, 18, 24, 29, 36]
9:     [9, 19, 33, 91, 119]
```

ultra-fast version

This fast version can handle a target of five hundred numbers with ease for the 2nd part of the task's requirement.

`/*REXX program finds the  persistence and multiplicative  digital root  of some numbers.*/numeric digits 2000                              /*increase the number of decimal digits*/parse arg target x                               /*obtain optional arguments from the CL*/if \datatype(target, 'W')  then target=25        /*Not specified?  Then use the default.*/if x='' | x=","  then x=123321 7739 893 899998   /* "      "         "   "   "      "   */say center('number',8)  ' persistence   multiplicative digital root'say copies('─'     ,8)  ' ───────────   ───────────────────────────'                                                 /* [↑]  the title  and  the separator. */     do j=1  for words(x);  n=abs( word(x, j) )  /*process each number in the list.     */     parse value  MDR(n)   with   mp mdr         /*obtain the persistence and the MDR.  */     say right(n,8) center(mp,13) center(mdr,30) /*display the number, persistence, MDR.*/     end   /*j*/                                 /* [↑] show MP and MDR for each number.*/say                                              /* [↓] show a blank and the title line.*/say 'MDR       first '  target  " numbers that have a matching MDR"say '═══  ' copies("═",(target+(target+1)**2)%2) /*display a separator line (for title).*/     do k=0  for 9;              hits=0           /*show numbers that have an MDR of  K. */    _=    if k==7  then [email protected]                           /*handle the special case of  seven.   */             else do m=k  until hits==target     /*find target numbers with an MDR of K.*/                  parse var  m  ''  -1  ?        /*obtain the right─most digit of  M.   */                  if k\==0  then if ?==0           then iterate                  if k==5   then if ?//2==0        then iterate                  if k==1   then m=copies(1, hits+1)                            else if MDR(m, 1)\==k  then iterate                  hits=hits+1                               /*got a hit, add to the list*/                  _=space(_ m)                              /*elide superfluous blanks. */                  if k==3  then do;      o=strip(m, 'T', 1) /*strip trailing ones from M*/                                if o==3  then m=copies(1, length(m))3   /*make a new  M.*/                                         else do;   t=pos(3, m) - 1     /*position of 3 */                                              m=overlay(3, translate(m, 1, 3), t)                                              end     /* [↑] shift the "3" 1 place left.*/                                m=m - 1               /*adjust for  DO  index increment.*/                                end                   /* [↑]  a shortcut to adj DO index*/                  end   /*m*/                         /* [↑]  built a list of MDRs = K  */     say " "k':    ['_"]"                         /*display the  K  (MDR)  and the list. */    if k==3  then @7=translate(_, 7, k)          /*save for later, a special  "7"  case.*/    end   /*k*/                                  /* [↑]  done with the  K  MDR list.    */ @.=                                              /* [↓]  handle MDR of  "9"  special.   */_=translate(@7, 9, 7)                            /*translate string for MDR  of nine.   */@9=translate(_, , ',')                           /*remove trailing commas from numbers. */@3=                                              /*assign null string before building.  */    do j=1  for words(@9)                         /*process each number for  MDR 9  case.*/   _=space( translate( word(@9, j), , 9),  0)    /*elide all  "9"s   using   SPACE(x,0).*/   L=length(_) + 1                               /*use a "fudged" length of the number. */   new=                                          /*these are the new numbers  (so far). */         do k=0 for L;       q=insert(3, _, k)    /*insert the  1st  "3"  into the number*/          do i=k  to L;     z=insert(3, q, i)    /*   "    "   2nd  "3"    "   "     "  */          if @.z\==''  then iterate              /*if already define, ignore the number.*/          @.z=z;            new=z new            /*define it,  and then add to the list.*/          end   /*i*/                            /* [↑]  end of  2nd  insertion of  "3".*/        end     /*k*/                            /* [↑]   "  "   1st      "      "   "  */    @3=space(@3 new)                              /*remove blanks,  then add to the list.*/   end          /*j*/                            /* [↑]  end of insertion of the  "3"s. */ [email protected];  [email protected]                                    /*define some strings for the merge.   */@=                                               /* [↓]  merge two lists,  3s  and  9s. */      do  while  a1\==''  &  a2\==''             /*process while the lists aren't empty.*/      x=word(a1, 1);   y=word(a2, 1)             /*obtain the 1st word in A1 & A2 lists.*/      if x=='' | y=='' then leave                /*are   X   or   Y   empty?            */      if x<y  then do;   @[email protected] x;   a1=delword(a1, 1, 1);   end   /*add  X  to the @ list.*/              else do;   @[email protected] y;   a2=delword(a2, 1, 1);   end   /* "   Y   "  "  "   "  */      end   /*while*/                            /* [↑]  only process just enough nums. */ @=subword(@, 1, target)                          /*elide the last trailing comma in list*/say " "9':     ['@"]"                            /*display the  "9" (MDR)  and the list.*/exit                                             /*stick a fork in it,  we're all done. *//*──────────────────────────────────────────────────────────────────────────────────────*/MDR: procedure; parse arg y,s;        y=abs(y)   /*get the number and determine the MDR.*/                   do p=1      until  y<10;    parse var  y  r  2                       do k=2  to length(y);   r=r * substr(y, k, 1)                       end   /*k*/                   y=r                   end       /*p*/               /* [↑]  wash, rinse, and repeat ···    */                if s==1  then return r           /*return multiplicative digital root.  */                return p r                       /*return the persistence and the  MDR. */`
output   when using the input of:   34
``` number   persistence   multiplicative digital root
────────  ───────────   ───────────────────────────
123321       3                     8
7739       3                     8
893       3                     2
899998       2                     0

MDR       first  34  numbers that have a matching MDR
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0:     [0 10 20 25 30 40 45 50 52 54 55 56 58 59 60 65 69 70 78 80 85 87 90 95 96 100 101 102 103 104 105 106 107 108]
1:     [1 11 111 1111 11111 111111 1111111 11111111 111111111 1111111111 11111111111 111111111111 1111111111111 11111111111111 111111111111111 1111111111111111 11111111111111111 111111111111111111 1111111111111111111 11111111111111111111 111111111111111111111 1111111111111111111111 11111111111111111111111 111111111111111111111111 1111111111111111111111111 11111111111111111111111111 111111111111111111111111111 1111111111111111111111111111 11111111111111111111111111111 111111111111111111111111111111 1111111111111111111111111111111 11111111111111111111111111111111 111111111111111111111111111111111 1111111111111111111111111111111111]
2:     [2 12 21 26 34 37 43 62 73 112 121 126 134 137 143 162 173 211 216 223 232 261 278 279 287 297 299 314 317 322 341 367 369 371]
3:     [3 13 31 113 131 311 1113 1131 1311 3111 11113 11131 11311 13111 31111 111113 111131 111311 113111 131111 311111 1111113 1111131 1111311 1113111 1131111 1311111 3111111 11111113 11111131 11111311 11113111 11131111 11311111]
4:     [4 14 22 27 39 41 72 89 93 98 114 122 127 139 141 172 189 193 198 212 217 221 249 266 271 277 294 319 333 338 346 364 379 383]
5:     [5 15 35 51 53 57 75 115 135 151 153 157 175 315 351 355 359 395 511 513 517 531 535 539 553 557 571 575 579 593 597 715 751 755]
6:     [6 16 23 28 32 44 47 48 61 68 74 82 84 86 116 123 128 132 144 147 148 161 168 174 182 184 186 213 218 224 227 228 231 238]
7:     [7 17 71 117 171 711 1117 1171 1711 7111 11117 11171 11711 17111 71111 111117 111171 111711 117111 171111 711111 1111117 1111171 1111711 1117111 1171111 1711111 7111111 11111117 11111171 11111711 11117111 11171111 11711111]
8:     [8 18 24 29 36 38 42 46 49 63 64 66 67 76 77 79 81 83 88 92 94 97 99 118 124 129 136 138 142 146 149 163 164 166]
9:     [9 19 33 91 119 133 191 313 331 911 1119 1133 1191 1313 1331 1911 3113 3131 3311 9111 11119 11133 11191 11313 11331 11911 13113 13131 13311 19111 31113 31131 31311 33111]
```

Ring

` # Project : Digital root/Multiplicative digital root load "stdlib.ring"root = newlist(10, 5)for r = 1 to 10     for x = 1 to 5          root[r][x] = 0     nextnextroot2 = list(10)for y = 1 to 10     root2[y] = 0nextsee "Number  MDR   MP" + nlnum = [123321, 7739, 893, 899998]digroot(num)see nlnum = 0:12000digroot(num)see "First five numbers with MDR in first column:" + nlfor n1 = 1 to 10     see "" + (n1-1) + " => "     for n2 = 1 to 5         see "" + root[n1][n2] + "  "     next     see nlnext func digroot(num)        for n = 1 to len(num)            sum = 0            numold = num[n]            while true                    pro = 1                    strnum = string(numold)                    for nr = 1 to len(strnum)                        pro = pro * number(strnum[nr])                    next                    sum = sum + 1                    numold = pro                    numn = string(num[n])                    sp = 6 - len(string(num[n]))                     if sp > 0                       for p = 1 to sp + 2                           numn = " " + numn                       next                    ok                    if len(string(numold)) = 1 and len(num) < 5                       see "" + numn + "     " + numold + "       " + sum + nl                       exit                    ok                    if len(string(numold)) = 1 and len(num) > 4                       root2[numold+1] = root2[numold+1] + 1                       if root2[numold+1] < 6                          root[numold+1][root2[numold+1]] = num[n]                       ok                       exit                    ok              end        next `

Output:

```Number  MDR   MP
123321   8     3
7739     8     3
893      2     3
899998   0     2

First five numbers with MDR in first column:
0 => 0  10  20  25  30
1 => 1  11  111  1111  11111
2 => 2  12  21  26  34
3 => 3  13  31  113  131
4 => 4  14  22  27  39
5 => 5  15  35  51  53
6 => 6  16  23  28  32
7 => 7  17  71  117  171
8 => 8  18  24  29  36
9 => 9  19  33  91  119
```

Ruby

Works with: Ruby version 2.1
`def mdroot(n)  mdr, persist = n, 0  until mdr < 10 do    mdr = mdr.to_s.each_char.map(&:to_i).inject(:*)    persist += 1  end  [mdr, persist]end puts "Number: MDR  MP", "======  ===  =="[123321, 7739, 893, 899998].each{|n| puts "%6d:   %d  %2d" % [n, *mdroot(n)]} counter = Hash.new{|h,k| h[k]=[]}0.step do |i|  counter[mdroot(i).first] << i  break if counter.values.all?{|v| v.size >= 5 }endputs "", "MDR: [n0..n4]", "===  ========"10.times{|i| puts "%3d: %p" % [i, counter[i].first(5)]}`
Output:
```Number: MDR  MP
======  ===  ==
123321:   8   3
7739:   8   3
893:   2   3
899998:   0   2

MDR: [n0..n4]
===  ========
0: [0, 10, 20, 25, 30]
1: [1, 11, 111, 1111, 11111]
2: [2, 12, 21, 26, 34]
3: [3, 13, 31, 113, 131]
4: [4, 14, 22, 27, 39]
5: [5, 15, 35, 51, 53]
6: [6, 16, 23, 28, 32]
7: [7, 17, 71, 117, 171]
8: [8, 18, 24, 29, 36]
9: [9, 19, 33, 91, 119]
```

Scala

Works with: Scala version 2.9.x
`import Stream._ object MDR extends App {   def mdr(x: BigInt, base: Int = 10): (BigInt, Long) = {    def multiplyDigits(x: BigInt): BigInt = ((x.toString(base) map (_.asDigit)) :\ BigInt(1))(_*_)    def loop(p: BigInt, c: Long): (BigInt, Long) = if (p < base) (p, c) else loop(multiplyDigits(p), c+1)    loop(multiplyDigits(x), 1)  }   printf("%15s\t%10s\t%s\n","Number","MDR","MP")  printf("%15s\t%10s\t%s\n","======","===","==")  Seq[BigInt](123321, 7739, 893, 899998, BigInt("393900588225"), BigInt("999999999999")) foreach {x =>    val (s, c) = mdr(x)    printf("%15s\t%10s\t%2s\n",x,s,c)  }  println   val mdrs: Stream[Int] => Stream[(Int, BigInt)] = i => i map (x => (x, mdr(x)._1))   println("MDR: [n0..n4]")  println("==== ========")  ((for {i <- 0 to 9} yield (mdrs(from(0)) take 11112 toList) filter {_._2 == i})    .map {_ take 5} map {xs => xs map {_._1}}).zipWithIndex    .foreach{p => printf("%3s: [%s]\n",p._2,p._1.mkString(", "))} }`
Output:
```         Number        MDR      MP
======        ===      ==
123321          8       3
7739          8       3
893          2       3
899998          0       2
393900588225          0       1
999999999999          0       3

MDR: [n0..n4]
==== ========
0: [0, 10, 20, 25, 30]
1: [1, 11, 111, 1111, 11111]
2: [2, 12, 21, 26, 34]
3: [3, 13, 31, 113, 131]
4: [4, 14, 22, 27, 39]
5: [5, 15, 35, 51, 53]
6: [6, 16, 23, 28, 32]
7: [7, 17, 71, 117, 171]
8: [8, 18, 24, 29, 36]
9: [9, 19, 33, 91, 119]```

Sidef

Translation of: Ruby
`func mdroot(n) {  var (mdr, persist) = (n, 0)  while (mdr >= 10) {    mdr = mdr.digits.prod    ++persist  }  [mdr, persist]} say "Number: MDR  MP\n======  ===  =="[123321, 7739, 893, 899998].each{|n| "%6d: %3d %3d\n" \                           .printf(n, mdroot(n)...) } var counter = Hash() Inf.times { |j|  counter{mdroot(j).first} := [] << j  break if counter.values.all {|v| v.len >= 5 }} say "\nMDR: [n0..n4]\n===  ========"10.times {|i| "%3d: %s\n".printf(i, counter{i}.first(5)) }`
Output:
```Number: MDR  MP
======  ===  ==
123321:   8   3
7739:   8   3
893:   2   3
899998:   0   2

MDR: [n0..n4]
===  ========
0: [0, 10, 20, 25, 30]
1: [1, 11, 111, 1111, 11111]
2: [2, 12, 21, 26, 34]
3: [3, 13, 31, 113, 131]
4: [4, 14, 22, 27, 39]
5: [5, 15, 35, 51, 53]
6: [6, 16, 23, 28, 32]
7: [7, 17, 71, 117, 171]
8: [8, 18, 24, 29, 36]
9: [9, 19, 33, 91, 119]
```

Tcl

`proc mdr {n} {    if {\$n < 0 || ![string is integer \$n]} {	error "must be an integer"    }    for {set i 0} {\$n > 9} {incr i} {	set n [tcl::mathop::* {*}[split \$n ""]]    }    return [list \$i \$n]}`

Demonstrating:

`puts "Number: MP MDR"puts [regsub -all . "Number: MP MDR" -]foreach n {123321 7739 893 899998} {    puts [format "%6d: %2d %3d" \$n {*}[mdr \$n]]}puts ""# The longEnough variable counts how many roots have at least 5 values accumulated for themfor {set i [set longEnough 0]} {\$longEnough < 10} {incr i} {    set root [lindex [mdr \$i] 1]    if {[llength [lappend accum(\$root) \$i]] == 5} {incr longEnough}}puts "MDR: \[n\u2080\u2026n\u2084\]"puts [regsub -all . "MDR: \[n\u2080\u2026n\u2084\]" -]for {set i 0} {\$i < 10} {incr i} {    puts [format "%3d: (%s)" \$i [join [lrange \$accum(\$i) 0 4] ", "]]}`
Output:
```Number: MP MDR
--------------
123321:  3   8
7739:  3   8
893:  3   2
899998:  2   0

MDR: [n₀…n₄]
------------
0: (0, 10, 20, 25, 30)
1: (1, 11, 111, 1111, 11111)
2: (2, 12, 21, 26, 34)
3: (3, 13, 31, 113, 131)
4: (4, 14, 22, 27, 39)
5: (5, 15, 35, 51, 53)
6: (6, 16, 23, 28, 32)
7: (7, 17, 71, 117, 171)
8: (8, 18, 24, 29, 36)
9: (9, 19, 33, 91, 119)
```

zkl

Translation of: Python
`fcn mdroot(n){ // Multiplicative digital root   mdr := List(n);   while (mdr[-1] > 9){      mdr.append(mdr[-1].split().reduce('*,1));   }   return(mdr.len() - 1, mdr[-1]);}`
`fcn mdroot(n){   count:=0; mdr:=n;   while(mdr > 9){      m:=mdr; digitsMul:=1;      while(m){	 reg md;	 m,md=m.divr(10);	 digitsMul *= md;      }      mdr = digitsMul;      count += 1;   }   return(count, mdr);}`
`println("Number:  (MP, MDR)\n=======  =========");foreach n in (T(123321, 7739, 893, 899998))  { println("%7,d: %s".fmt(n, mdroot(n))) } table:=D([0..9].zip(fcn{List()}).walk());  // dictionary(0:List, 1:List, ...)n    :=0;while(table.values.filter(fcn(r){r.len()<5})){ // until each entry has >=5 values   mpersistence, mdr := mdroot(n);   table[mdr].append(n);   n += 1;}println("\nMP: [n0..n4]\n==  ========");foreach mp in (table.keys.sort()){   println("%2d: %s".fmt(mp, table[mp][0,5])); //print first five values }`
Output:
```Number:  (MP, MDR)
=======  =========
123,321: L(3,8)
7,739: L(3,8)
893: L(3,2)
899,998: L(2,0)

MP: [n0..n4]
==  ========
0: L(0,10,20,25,30)
1: L(1,11,111,1111,11111)
2: L(2,12,21,26,34)
3: L(3,13,31,113,131)
4: L(4,14,22,27,39)
5: L(5,15,35,51,53)
6: L(6,16,23,28,32)
7: L(7,17,71,117,171)
8: L(8,18,24,29,36)
9: L(9,19,33,91,119)
```