Amicable pairs

From Rosetta Code
Task
Amicable pairs
You are encouraged to solve this task according to the task description, using any language you may know.

Two integers and are said to be amicable pairs if and the sum of the proper divisors of () as well as .


Example

1184 and 1210 are an amicable pair, with proper divisors:

  •   1, 2, 4, 8, 16, 32, 37, 74, 148, 296, 592   and
  •   1, 2, 5, 10, 11, 22, 55, 110, 121, 242, 605   respectively.


Task

Calculate and show here the Amicable pairs below 20,000; (there are eight).


Related tasks



11l

<lang 11l>F sum_proper_divisors(n)

  R I n < 2 {0} E sum((1 .. n I/ 2).filter(it -> (@n % it) == 0))

L(n) 1..20000

  V m = sum_proper_divisors(n)
  I m > n & sum_proper_divisors(m) == n
     print(n"\t"m)</lang>

8080 Assembly

<lang 8080asm> org 100h ;;; Calculate proper divisors of 2..20000 lxi h,pdiv + 4 ; 2 bytes per entry lxi d,19999 ; [2 .. 20000] means 19999 entries lxi b,1 ; Initialize each entry to 1 init: mov m,c inx h mov m,b inx h dcx d mov a,d ora e jnz init lxi b,1 ; BC = outer loop variable iouter: inx b lxi h,-10001 ; Are we there yet? dad b jc idone ; If so, we've calculated all of them mov h,b mov l,c dad h xchg ; DE = inner loop variable iinner: push d ; save DE xchg dad h ; calculate *pdiv[DE] lxi d,pdiv dad d mov e,m ; DE = pdiv[DE] inx h mov d,m xchg ; pdiv[DE] += BC dad b xchg ; store it back mov m,d dcx h mov m,e pop h ; restore DE (into HL) dad b ; add BC lxi d,-20001 ; are we there yet? dad d jc iouter ; then continue with outer loop lxi d,20001 ; otherwise continue with inner loop dad d xchg jmp iinner idone: lxi b,1 ; BC = outer loop variable touter: inx b lxi h,-20001 ; Are we there yet? dad b rc ; If so, stop mov d,b ; DE = outer loop variable mov e,c tinner: inx d lxi h,-20001 ; Are we there yet? dad d jc touter ; If so continue with outer loop push d ; Store the variables push b mov h,b ; find *pdiv[BC] mov l,c dad b lxi b,pdiv dad b mov a,m ; Compare low byte (to E) cmp e jnz tnext1 ; Not equal = not amicable inx h mov a,m cmp d ; Compare high byte (to B) jnz tnext1 ; Not equal = not amicable pop b ; Restore BC xchg ; find *pdiv[DE] dad h lxi d,pdiv dad d mov a,m ; Compare low byte (to C) cmp c jnz tnext2 ; Not equal = not amicable inx h mov a,m ; Compare high byte (to B) cmp b jnz tnext2 ; Not equal = not amicable pop d ; Restore DE push d ; Save them both on the stack again push b push d mov h,b ; Print the first number mov l,c call prhl pop h ; And the second number call prhl lxi d,nl ; And a newline mvi c,9 call 5 tnext1: pop b ; Restore B tnext2: pop d ; Restore D jmp tinner ; Continue ;;; Print the number in HL prhl: lxi d,nbuf ; Store buffer pointer on stack push d lxi b,-10 ; Divisor pdgt: lxi d,-1 ; Quotient pdivlp: inx d dad b jc pdivlp mvi a,'0'+10 ; Make ASCII digit add l pop h ; Store in output buffer dcx h mov m,a push h xchg ; Keep going with rest of number mov a,h ; if not zero ora l jnz pdgt mvi c,9 ; CP/M call to print string pop d ; Get buffer pointer jmp 5 db '*****' nbuf: db ' $' nl: db 13,10,'$' pdiv: equ $ ; base</lang>

Output:
220 284
1184 1210
2620 2924
5020 5564
6232 6368
10744 10856
12285 14595
17296 18416

8086 Assembly

<lang asm>LIMIT: equ 20000 ; Maximum value cpu 8086 org 100h section .text mov ax,final ; Set DS and ES to point just beyond the mov cl,4 ; program. We're just going to assume MS-DOS shr ax,cl ; gave us enough memory. (Generally the case, inc ax ; a .COM gets a 64K segment and we need ~40K.) mov cx,cs add ax,cx mov ds,ax mov es,ax calc: mov ax,1 ; Calculate proper divisors for 2..20000 mov di,4 ; Initially, set each entry to 1. mov cx,LIMIT-1 ; 2 to 20000 inclusive = 19999 entries rep stosw mov ax,2 ; AX = outer loop counter mov cl,2 mov dx,LIMIT*2 ; Keep inner loop limit ready in DX mov bp,LIMIT/2 ; And outer loop limit in BP .outer: mov bx,ax ; BX = inner loop counter (multiplied by two) shl bx,cl ; Each entry is 2 bytes wide .inner: add [bx],ax ; divsum[BX/2] += AX add bx,ax ; Advance to next entry add bx,ax ; Twice, because each entry is 2 bytes wide cmp bx,dx ; Are we there yet? jbe .inner ; If not, keep going inc ax cmp ax,bp ; Is the outer loop done yet? jbe .outer ; If not, keep going show: mov dx,LIMIT ; Keep limit ready in DX mov ax,2 ; AX = outer loop counter mov si,4 ; SI = address for outer loop .outer: mov cx,ax ; CX = inner loop counter inc cx mov di,cx ; DI = address for inner loop shl di,1 mov bx,[si] ; Preload divsum[AX] .inner: cmp cx,bx ; CX == divsum[AX]? jne .next ; If not, the pair is not amicable cmp ax,[di] ; AX == divsum[CX]? jne .next ; If not, the pair is not amicable push ax ; Keep the registers push bx push cx push dx push cx ; And CX twice because we need to print it call prax ; Print the first number pop ax call prax ; And the second number mov dx,nl ; And a newline call pstr pop dx ; Restore the registers pop cx pop bx pop ax .next: inc di ; Increment inner loop variable and address inc di ; Address twice because each entry has 2 bytes inc cx cmp cx,dx ; Are we done yet? jbe .inner ; If not, keep going inc si ; Increment outer loop variable and address inc si ; Address twice because each entry has 2 bytes inc ax cmp ax,dx ; Are we done yet? jbe .outer ; If not, keep going. ret ;;; Print the number in AX. Destroys AX, BX, CX, DX. prax: mov cx,10 ; Divisor mov bx,nbuf ; Buffer pointer .digit: xor dx,dx div cx ; Divide by 10 and extract digit add dl,'0' ; Add ASCII 0 to digit dec bx mov [cs:bx],dl ; Store in string test ax,ax ; Any more? jnz .digit ; If so, keep going mov dx,bx ; If not, print the result ;;; Print string from CS. pstr: push ds ; Save DS mov ax,cs ; Set DS to CS mov ds,ax mov ah,9 ; Print string using MS-DOS int 21h pop ds ; Restore DS ret db '*****' nbuf: db ' $' nl: db 13,10,'$' final: equ $</lang>

Output:
220 284
1184 1210
2620 2924
5020 5564
6232 6368
10744 10856
12285 14595
17296 18416

AArch64 Assembly

Works with: as version Raspberry Pi 3B version Buster 64 bits
or android 64 bits with application Termux

<lang AArch64 Assembly> /* ARM assembly AARCH64 Raspberry PI 3B */ /* program amicable64.s */

/*******************************************/ /* Constantes file */ /*******************************************/ /* for this file see task include a file in language AArch64 assembly*/ .include "../includeConstantesARM64.inc"

.equ NMAXI, 20000 .equ TABMAXI, 100

/*********************************/ /* Initialized data */ /*********************************/ .data sMessResult: .asciz " @ : @\n" szCarriageReturn: .asciz "\n" szMessErr1: .asciz "Array too small !!" /*********************************/ /* UnInitialized data */ /*********************************/ .bss sZoneConv: .skip 24 tResult: .skip 8 * TABMAXI /*********************************/ /* code section */ /*********************************/ .text .global main main: // entry of program

   ldr x3,qNMaxi                 // load limit
   mov x4,#2                     // number begin

1:

   mov x0,x4                     // number
   bl decFactor                  // compute sum factors
   cmp x0,x4                     // equal ?
   beq 2f 
   mov x2,x0                     // factor sum 1
   bl decFactor
   cmp x0,x4                     // equal number ?
   bne 2f
   mov x0,x4                     // yes -> search in array 
   mov x1,x2                     // and store sum
   bl searchRes
   cmp x0,#0                     // find ?
   bne 2f                        // yes
   mov x0,x4                     // no -> display number ans sum
   mov x1,x2
   bl displayResult

2:

   add x4,x4,#1                     // increment number
   cmp x4,x3                     // end ?
   ble 1b

100: // standard end of the program

   mov x0, #0                    // return code
   mov x8, #EXIT                 // request to exit program
   svc #0                        // perform the system call

qAdrszCarriageReturn: .quad szCarriageReturn qNMaxi: .quad NMAXI /***************************************************/ /* display message number */ /***************************************************/ /* x0 contains number 1 */ /* x1 contains number 2 */ displayResult:

   stp x1,lr,[sp,-16]!           // save  registers
   stp x2,x3,[sp,-16]!           // save  registers
   mov x2,x1
   ldr x1,qAdrsZoneConv
   bl conversion10               // call décimal conversion
   ldr x0,qAdrsMessResult
   ldr x1,qAdrsZoneConv          // insert conversion in message
   bl strInsertAtCharInc
   mov x3,x0
   mov x0,x2
   ldr x1,qAdrsZoneConv
   bl conversion10               // call décimal conversion
   mov x0,x3
   ldr x1,qAdrsZoneConv          // insert conversion in message
   bl strInsertAtCharInc
   
   bl affichageMess              // display message
   ldp x2,x3,[sp],16              // restaur  2 registers
   ldp x1,lr,[sp],16              // restaur  2 registers
   ret                            // return to address lr x30

qAdrsMessResult: .quad sMessResult qAdrsZoneConv: .quad sZoneConv /***************************************************/ /* compute factors sum */ /***************************************************/ /* x0 contains the number */ decFactor:

   stp x1,lr,[sp,-16]!       // save  registers
   stp x2,x3,[sp,-16]!       // save  registers
   stp x4,x5,[sp,-16]!       // save  registers
   mov x4,#1                 // init sum
   mov x1,#2                 // start factor -> divisor

1:

   udiv x2,x0,x1
   msub x3,x2,x1,x0          // remainder
   cmp x1,x2                 // divisor > quotient ?
   bgt 3f
   cmp x3,#0                 // remainder = 0 ?
   bne 2f
   add x4,x4,x1              // add divisor to sum
   cmp x1,x2                 // divisor = quotient ?
   beq 3f                    // yes -> end
   add x4,x4,x2              // no -> add quotient to sum

2:

   add x1,x1,#1              // increment factor
   b 1b                      // and loop

3:

   mov x0,x4                 // return sum
   ldp x4,x5,[sp],16         // restaur  2 registers
   ldp x2,x3,[sp],16         // restaur  2 registers
   ldp x1,lr,[sp],16         // restaur  2 registers
   ret                       // return to address lr x30

/***************************************************/ /* search and store result in array */ /***************************************************/ /* x0 contains the number */ /* x1 contains factors sum */ /* x0 return 1 if find 0 else -1 if error */ searchRes:

   stp x1,lr,[sp,-16]!       // save  registers
   stp x2,x3,[sp,-16]!       // save  registers
   stp x4,x5,[sp,-16]!       // save  registers
   ldr x4,qAdrtResult        // array address
   mov x2,#0                 // indice begin

1:

   ldr x3,[x4,x2,lsl #3]     // load one result array
   cmp x3,#0                 // if 0 store new result
   beq 2f
   cmp x3,x0                 // equal ?
   beq 3f                    // find -> return 1
   add x2,x2,#1              // increment indice
   cmp x2,#TABMAXI           // maxi array ?
   blt 1b
   ldr x0,qAdrszMessErr1     // error
   bl affichageMess
   mov x0,#-1
   b 100f

2:

   str x1,[x4,x2,lsl #3]
   mov x0,#0                 // not find -> store and retun 0
   b 100f

3:

   mov x0,#1

100:

   ldp x4,x5,[sp],16         // restaur  2 registers
   ldp x2,x3,[sp],16         // restaur  2 registers
   ldp x1,lr,[sp],16         // restaur  2 registers
   ret                       // return to address lr x30

qAdrtResult: .quad tResult qAdrszMessErr1: .quad szMessErr1 /********************************************************/ /* File Include fonctions */ /********************************************************/ /* for this file see task include a file in language AArch64 assembly */ .include "../includeARM64.inc" </lang>

 220 : 284
 1184 : 1210
 2620 : 2924
 5020 : 5564
 6232 : 6368
 10744 : 10856
 12285 : 14595
 17296 : 18416

Action!

Calculations on a real Atari 8-bit computer take quite long time. It is recommended to use an emulator capable with increasing speed of Atari CPU.

<lang Action!>INCLUDE "H6:SIEVE.ACT"

CARD FUNC SumDivisors(CARD x)

 CARD i,max,sum
 sum=1 i=2 max=x
 WHILE i<max
 DO
   IF x MOD i=0 THEN
     max=x/i
     IF i<max THEN
       sum==+i+max
     ELSEIF i=max THEN
       sum==+i
     FI
   FI
   i==+1
 OD

RETURN (sum)

PROC Main()

 DEFINE MAXNUM="20000"
 BYTE ARRAY primes(MAXNUM+1)
 CARD m,n
 Put(125) PutE() ;clear the screen
 Sieve(primes,MAXNUM+1)
 FOR m=1 TO MAXNUM-1
 DO
   IF primes(m)=0 THEN
     n=SumDivisors(m)
     IF n<MAXNUM AND primes(n)=0 AND n>m THEN
       IF m=SumDivisors(n) THEN
         PrintF("%U %U%E",m,n)
       FI
     FI
   FI
 OD

RETURN</lang>

Output:

Screenshot from Atari 8-bit computer

220 284
1184 1210
2620 2924
5020 5564
6232 6368
10744 10856
12285 14595
17296 18416

Ada

This solution uses the package Generic_Divisors from the Proper Divisors task [[1]].

<lang Ada>with Ada.Text_IO, Generic_Divisors; use Ada.Text_IO;

procedure Amicable_Pairs is

  function Same(P: Positive) return Positive is (P);
  
  package Divisor_Sum is new Generic_Divisors
    (Result_Type => Natural, None => 0, One => Same, Add =>  "+");
  
  Num2 : Integer;

begin

  for Num1 in 4 .. 20_000 loop
     Num2 := Divisor_Sum.Process(Num1);
     if Num1 < Num2 then

if Num1 = Divisor_Sum.Process(Num2) then Put_Line(Integer'Image(Num1) & "," & Integer'Image(Num2)); end if;

     end if;
  end loop;

end Amicable_Pairs;</lang>

Output:
 220, 284
 1184, 1210
 2620, 2924
 5020, 5564
 6232, 6368
 10744, 10856
 12285, 14595
 17296, 18416

ALGOL 60

Works with: A60

<lang algol60> begin

comment - return n mod m; integer procedure mod(n, m);

 value n, q; integer n, m;

begin

 mod := n - m * entier(n / m);

end;

comment - return sum of the proper divisors of n; integer procedure sumf(n);

 value n; integer n;

begin

 integer sum, f1, f2;
 sum := 1;
 f1 := 2;
 for f1 := f1 while (f1 * f1) <= n do
   begin
     if mod(n, f1) = 0 then
       begin
          sum := sum + f1;
          f2 := n / f1;
          if f2 > f1 then sum := sum + f2;
       end;
     f1 := f1 + 1;
 end;
 sumf := sum;

end;

comment - main program begins here; integer a, b, found; outstring(1,"Searching up to 20000 for amicable pairs\n"); found := 0; for a := 2 step 1 until 20000 do

 begin
   b := sumf(a);
   if b > a then
      begin
        if a = sumf(b) then
           begin
             found := found + 1;
             outinteger(1,a);
             outinteger(1,b);
             outstring(1,"\n");
           end;
      end;
 end;

outinteger(1,found); outstring(1,"pairs were found");

end </lang>

Output:
Searching up to 20000 for amicable pairs
 220  284
 1184  1210
 2620  2924
 5020  5564
 6232  6368
 10744  10856
 12285  14595
 17296  18416
 8 pairs were found

ALGOL 68

<lang algol68># returns the sum of the proper divisors of n #

  1. if n = 1, 0 or -1, we return 0 #

PROC sum proper divisors = ( INT n )INT:

    BEGIN
        INT result := 0;
        INT abs n = ABS n;
        IF abs n > 1 THEN
            FOR d FROM ENTIER sqrt( abs n ) BY -1 TO 2 DO
                IF abs n MOD d = 0 THEN
                    # found another divisor                      #
                    result +:= d;
                    IF d * d /= n THEN
                        # include the other divisor              #
                        result +:= n OVER d
                    FI
                FI
            OD;
            # 1 is always a proper divisor of numbers > 1        #
            result +:= 1
        FI;
        result
    END # sum proper divisors # ;
  1. construct a table of the sum of the proper divisors of numbers #
  2. up to 20 000 #

INT max number = 20 000; [ 1 : max number ]INT proper divisor sum; FOR n TO UPB proper divisor sum DO proper divisor sum[ n ] := sum proper divisors( n ) OD;

  1. returns TRUE if n1 and n2 are an amicable pair FALSE otherwise #
  2. n1 and n2 are amicable if the sum of the proper diviors #
  3. n1 = n2 and the sum of the proper divisors of n2 = n1 #

PROC is an amicable pair = ( INT n1, n2 )BOOL:

    ( proper divisor sum[ n1 ] = n2 AND proper divisor sum[ n2 ] = n1 );
  1. find the amicable pairs up to 20 000 #

FOR p1 TO max number DO

   FOR p2 FROM p1 + 1 TO max number DO
       IF is an amicable pair( p1, p2 ) THEN
           print( ( whole( p1, -6 ), " and ", whole( p2, -6 ), " are an amicable pair", newline ) )
       FI
   OD

OD</lang>

Output:
   220 and    284 are an amicable pair
  1184 and   1210 are an amicable pair
  2620 and   2924 are an amicable pair
  5020 and   5564 are an amicable pair
  6232 and   6368 are an amicable pair
 10744 and  10856 are an amicable pair
 12285 and  14595 are an amicable pair
 17296 and  18416 are an amicable pair

ANSI Standard BASIC

Translation of: GFA Basic

<lang ANSI Standard BASIC>100 DECLARE EXTERNAL FUNCTION sum_proper_divisors 110 CLEAR 120 ! 130 DIM f(20001)  ! sum of proper factors for each n 140 FOR i=1 TO 20000 150 LET f(i)=sum_proper_divisors(i) 160 NEXT i 170 ! look for pairs 180 FOR i=1 TO 20000 190 FOR j=i+1 TO 20000 200 IF f(i)=j AND i=f(j) THEN 210 PRINT "Amicable pair ";i;" ";j 220 END IF 230 NEXT j 240 NEXT i 250 ! 260 PRINT 270 PRINT "-- found all amicable pairs" 280 END 290 ! 300 ! Compute the sum of proper divisors of given number 310 ! 320 EXTERNAL FUNCTION sum_proper_divisors(n) 330 ! 340 IF n>1 THEN ! n must be 2 or larger 350 LET sum=1 ! start with 1 360 LET root=SQR(n)  ! note that root is an integer 370  ! check possible factors, up to sqrt 380 FOR i=2 TO root 390 IF MOD(n,i)=0 THEN 400 LET sum=sum+i  ! i is a factor 410 IF i*i<>n THEN  ! check i is not actual square root of n 420 LET sum=sum+n/i  ! so n/i will also be a factor 430 END IF 440 END IF 450 NEXT i 460 END IF 470 LET sum_proper_divisors = sum 480 END FUNCTION</lang>

AppleScript

Translation of: JavaScript

<lang AppleScript>-- AMICABLE PAIRS ------------------------------------------------------------

-- amicablePairsUpTo :: Int -> Int on amicablePairsUpTo(max)

   -- amicable :: [Int] -> Int -> Int -> [Int] -> [Int]
   script amicable
       on |λ|(a, m, n, lstSums)
           if (m > n) and (m ≤ max) and ((item m of lstSums) = n) then
               a & n, m
           else
               a
           end if
       end |λ|
   end script
   
   -- divisorsSummed :: Int -> Int
   script divisorsSummed
       -- sum :: Int -> Int -> Int
       script sum
           on |λ|(a, b)
               a + b
           end |λ|
       end script
       
       on |λ|(n)
           foldl(sum, 0, properDivisors(n))
       end |λ|
   end script
   
   foldl(amicable, {}, ¬
       map(divisorsSummed, enumFromTo(1, max)))

end amicablePairsUpTo


-- TEST ---------------------------------------------------------------------- on run

   amicablePairsUpTo(20000)
   

end run


-- PROPER DIVISORS -----------------------------------------------------------

-- properDivisors :: Int -> [Int] on properDivisors(n)

   -- isFactor :: Int -> Bool 
   script isFactor
       on |λ|(x)
           n mod x = 0
       end |λ|
   end script
   
   -- integerQuotient :: Int -> Int
   script integerQuotient
       on |λ|(x)
           (n / x) as integer
       end |λ|
   end script
   
   if n = 1 then
       {1}
   else
       set realRoot to n ^ (1 / 2)
       set intRoot to realRoot as integer
       set blnPerfectSquare to intRoot = realRoot
       
       -- Factors up to square root of n,
       set lows to filter(isFactor, enumFromTo(1, intRoot))
       
       -- and quotients of these factors beyond the square root,
       -- excluding n itself (last item)
       items 1 thru -2 of (lows & map(integerQuotient, ¬
           items (1 + (blnPerfectSquare as integer)) thru -1 of reverse of lows))
   end if

end properDivisors

-- GENERIC FUNCTIONS ---------------------------------------------------------

-- enumFromTo :: Int -> Int -> [Int] on enumFromTo(m, n)

   if m > n then
       set d to -1
   else
       set d to 1
   end if
   set lst to {}
   repeat with i from m to n by d
       set end of lst to i
   end repeat
   return lst

end enumFromTo

-- filter :: (a -> Bool) -> [a] -> [a] on filter(f, xs)

   tell mReturn(f)
       set lst to {}
       set lng to length of xs
       repeat with i from 1 to lng
           set v to item i of xs
           if |λ|(v, i, xs) then set end of lst to v
       end repeat
       return lst
   end tell

end filter

-- foldl :: (a -> b -> a) -> a -> [b] -> a on foldl(f, startValue, xs)

   tell mReturn(f)
       set v to startValue
       set lng to length of xs
       repeat with i from 1 to lng
           set v to |λ|(v, item i of xs, i, xs)
       end repeat
       return v
   end tell

end foldl

-- map :: (a -> b) -> [a] -> [b] on map(f, xs)

   tell mReturn(f)
       set lng to length of xs
       set lst to {}
       repeat with i from 1 to lng
           set end of lst to |λ|(item i of xs, i, xs)
       end repeat
       return lst
   end tell

end map

-- Lift 2nd class handler function into 1st class script wrapper -- mReturn :: Handler -> Script on mReturn(f)

   if class of f is script then
       f
   else
       script
           property |λ| : f
       end script
   end if

end mReturn</lang>

Output:

<lang AppleScript>{{220, 284}, {1184, 1210}, {2620, 2924}, {5020, 5564}, {6232, 6368}, {10744, 10856}, {12285, 14595}, {17296, 18416}}</lang>

ARM Assembly

Works with: as version Raspberry Pi
or android 32 bits with application Termux

<lang ARM Assembly> /* ARM assembly Raspberry PI or android with termux */ /* program amicable.s */

/* REMARK 1 : this program use routines in a include file 
  see task Include a file language arm assembly 
  for the routine affichageMess conversion10 
  see at end of this program the instruction include */

/* for constantes see task include a file in arm assembly */ /************************************/ /* Constantes */ /************************************/ .include "../constantes.inc"

.equ NMAXI, 20000 .equ TABMAXI, 100

/*********************************/ /* Initialized data */ /*********************************/ .data sMessResult: .asciz " @ : @\n" szCarriageReturn: .asciz "\n" szMessErr1: .asciz "Array too small !!" /*********************************/ /* UnInitialized data */ /*********************************/ .bss sZoneConv: .skip 24 tResult: .skip 4 * TABMAXI /*********************************/ /* code section */ /*********************************/ .text .global main main: @ entry of program

   ldr r3,iNMaxi                 @ load limit
   mov r4,#2                     @ number begin

1:

   mov r0,r4                     @ number
   bl decFactor                  @ compute sum factors
   cmp r0,r4                     @ equal ?
   beq 2f 
   mov r2,r0                     @ factor sum 1
   bl decFactor
   cmp r0,r4                     @ equal number ?
   bne 2f
   mov r0,r4                     @ yes -> search in array 
   mov r1,r2                     @ and store sum
   bl searchRes
   cmp r0,#0                     @ find ?
   bne 2f                        @ yes
   mov r0,r4                     @ no -> display number ans sum
   mov r1,r2
   bl displayResult

2:

   add r4,#1                     @ increment number
   cmp r4,r3                     @ end ?
   ble 1b

100: @ standard end of the program

   mov r0, #0                    @ return code
   mov r7, #EXIT                 @ request to exit program
   svc #0                        @ perform the system call

iAdrszCarriageReturn: .int szCarriageReturn iNMaxi: .int NMAXI /***************************************************/ /* display message number */ /***************************************************/ /* r0 contains number 1 */ /* r1 contains number 2 */ displayResult:

   push {r1-r3,lr}               @ save registers 
   mov r2,r1
   ldr r1,iAdrsZoneConv
   bl conversion10               @ call décimal conversion
   ldr r0,iAdrsMessResult
   ldr r1,iAdrsZoneConv          @ insert conversion in message
   bl strInsertAtCharInc
   mov r3,r0
   mov r0,r2
   ldr r1,iAdrsZoneConv
   bl conversion10               @ call décimal conversion
   mov r0,r3
   ldr r1,iAdrsZoneConv          @ insert conversion in message
   bl strInsertAtCharInc
   
   bl affichageMess              @ display message
   pop {r1-r3,pc}                @ restaur des registres

iAdrsMessResult: .int sMessResult iAdrsZoneConv: .int sZoneConv /***************************************************/ /* compute factors sum */ /***************************************************/ /* r0 contains the number */ decFactor:

   push {r1-r5,lr}           @ save registers 
   mov r5,#1                 @ init sum
   mov r4,r0                 @ save number
   mov r1,#2                 @ start factor -> divisor

1:

   mov r0,r4                 @ dividende
   bl division
   cmp r1,r2                 @ divisor > quotient ?
   bgt 3f
   cmp r3,#0                 @ remainder = 0 ?
   bne 2f
   add r5,r5,r1              @ add divisor to sum
   cmp r1,r2                 @ divisor = quotient ?
   beq 3f                    @ yes -> end
   add r5,r5,r2              @ no -> add quotient to sum

2:

   add r1,r1,#1              @ increment factor
   b 1b                      @ and loop

3:

   mov r0,r5                 @ return sum
   pop {r1-r5,pc}            @ restaur registers

/***************************************************/ /* search and store result in array */ /***************************************************/ /* r0 contains the number */ /* r1 contains factors sum */ /* r0 return 1 if find 0 else -1 if error */ searchRes:

   push {r1-r4,lr}              @ save registers 
   ldr r4,iAdrtResult           @ array address
   mov r2,#0                    @ indice begin

1:

   ldr r3,[r4,r2,lsl #2]        @ load one result array
   cmp r3,#0                    @ if 0 store new result
   beq 2f
   cmp r3,r0                    @ equal ?
   moveq r0,#1                  @ find -> return 1
   beq 100f
   add r2,r2,#1                 @ increment indice
   cmp r2,#TABMAXI              @ maxi array ?
   blt 1b
   ldr r0,iAdrszMessErr1        @ error
   bl affichageMess
   mov r0,#-1
   b 100f

2:

   str r1,[r4,r2,lsl #2]
   mov r0,#0                   @ not find -> store and retun 0

100:

   pop {r1-r4,pc}              @ restaur registers

iAdrtResult: .int tResult iAdrszMessErr1: .int szMessErr1 /***************************************************/ /* ROUTINES INCLUDE */ /***************************************************/ .include "../affichage.inc" </lang>

 220         : 284
 1184        : 1210
 2620        : 2924
 5020        : 5564
 6232        : 6368
 10744       : 10856
 12285       : 14595
 17296       : 18416

Arturo

<lang rebol>properDivs: function [x] ->

   (factors x) -- x

amicable: function [x][

   y: sum properDivs x 
   if and? x = sum properDivs y 
           x <> y 
       -> return @[x,y]
   return ø

]

amicables: []

loop 1..20000 'n [

   am: amicable n
   if am <> ø 
       -> 'amicables ++ @[sort am]

]

print unique amicables</lang>

Output:
[220 284] [1184 1210] [2620 2924] [5020 5564] [6232 6368] [10744 10856] [12285 14595] [17296 18416]

ATS

<lang ATS> (* ****** ****** *) //

  1. include

"share/atspre_staload.hats"

  1. include

"share/HATS/atspre_staload_libats_ML.hats" // (* ****** ****** *) // fun sum_list_vt

 (xs: List_vt(int)): int =

(

 case+ xs of
 | ~list_vt_nil() => 0
 | ~list_vt_cons(x, xs) => x + sum_list_vt(xs)

) // (* ****** ****** *)

fun propDivs (

 x0: int

) : List0_vt(int) =

 loop(x0, 2, list_vt_sing(1)) where

{ // fun loop ( x0: int, i: int, res: List0_vt(int) ) : List0_vt(int) = ( if (i * i) > x0 then list_vt_reverse(res) else (

 if x0 % i != 0
   then
     loop(x0, i+1, res)
   // end of [then]
   else let
     val res =
       cons_vt(i, res)
     // end of [val]
     val res =
     (
       if i * i = x0 then res else cons_vt(x0 / i, res)
     ) : List0_vt(int) // end of [val]
   in
     loop(x0, i+1, res)
   end // end of [else]
 // end of [if]

) ) (* end of [loop] *) // } // end of [propDivs]

(* ****** ****** *)

fun sum_propDivs(x: int): int = sum_list_vt(propDivs(x))

(* ****** ****** *)

val theNat2 = auxmain(2) where { fun auxmain (

n: int

) : stream_vt(int) = $ldelay(stream_vt_cons(n, auxmain(n+1))) }

(* ****** ****** *) // val theAmicable = ( stream_vt_takeLte(theNat2, 20000) ).filter() ( lam x => let

 val x2 = sum_propDivs(x)

in x < x2 && x = sum_propDivs(x2) end ) // (* ****** ****** *)

val () = theAmicable.foreach() (

 lam x => println! ("(", x, ", ", sum_propDivs(x), ")")

)

(* ****** ****** *)

implement main0 () = ()

(* ****** ****** *) </lang>

Output:
(220, 284)
(1184, 1210)
(2620, 2924)
(5020, 5564)
(6232, 6368)
(10744, 10856)
(12285, 14595)
(17296, 18416)

AutoHotkey

<lang d>SetBatchLines -1 Loop, 20000 { m := A_index

; Getting factors loop % floor(sqrt(m)) { if ( mod(m, A_index) = 0 ) { if ( A_index ** 2 == m ) { sum += A_index continue } else if ( A_index != 1 ) { sum += A_index + m//A_index } else if ( A_index = 1 ) { sum += A_index } } } ; Factors obtained

; Checking factors of sum if ( sum > 1 ) { loop % floor(sqrt(sum)) { if ( mod(sum, A_index) = 0 ) { if ( A_index ** 2 == sum ) { sum2 += A_index continue } else if ( A_index != 1 ) { sum2 += A_index + sum//A_index } else if ( A_index = 1 ) { sum2 += A_index } } } if ( m = sum2 ) && ( m != sum ) && ( m < sum ) final .= m . ":" . sum . "`n" } ; Checked

sum := 0 sum2 := 0 } MsgBox % final ExitApp</lang>

Output:
220:284
1184:1210
2620:2924
5020:5564
6232:6368
10744:10856
12285:14595
17296:18416

AWK

<lang awk>

  1. !/bin/awk -f

function sumprop(num, i,sum,root) { if (num < 2) return 0 sum=1 root=sqrt(num) for ( i=2; i < root; i++) {

   if (num % i == 0 )
       { 
         sum = sum + i + num/i
         }
    }
    if (num % root == 0) 
       {
        sum = sum + root
        }    
return sum
}
                             

BEGIN{ limit=20000 print "Amicable pairs < ",limit for (n=1; n < limit+1; n++)

   {
   m=sumprop(n)
   if (n == sumprop(m) && n < m) print n,m
   }

} }</lang>

Output:
# ./amicable 
Amicable pairs < 20000
220 284
1184 1210
2620 2924
5020 5564
6232 6368
10744 10856
12285 14595
17296 18416


BASIC256

Translation of: FreeBASIC

<lang BASIC256>function SumProperDivisors(number) if number < 2 then return 0 sum = 0 for i = 1 to number \ 2 if number mod i = 0 then sum += i next i return sum end function

dim sum(20000) for n = 1 to 19999 sum[n] = SumProperDivisors(n) next n

print "The pairs of amicable numbers below 20,000 are :" print

for n = 1 to 19998 f = sum[n] if f <= n or f < 1 or f > 19999 then continue for if f = sum[n] and n = sum[f] then print rjust(string(n), 5); " and "; sum[n] end if next n end</lang>

Output:
The pairs of amicable numbers below 20,000 are :

  220 and 284
 1184 and 1210
 2620 and 2924
 5020 and 5564
 6232 and 6368
10744 and 10856
12285 and 14595
17296 and 18416


BCPL

<lang bcpl>get "libhdr"

manifest $(

   MAXIMUM = 20000

$)

// Calculate proper divisors for 1..N let propDivSums(n) = valof $( let v = getvec(n)

   for i = 1 to n do v!i := 1
   for i = 2 to n/2 do
   $(  let j = i*2
       while j < n do
       $(  v!j := v!j + i
           j := j + i
       $)
   $)
   resultis v

$)

// Are A and B an amicable pair, given the list of sums of proper divisors? let amicable(pdiv, a, b) = a = pdiv!b & b = pdiv!a

let start() be $( let pds = propDivSums(MAXIMUM)

   for x = 1 to MAXIMUM do
       for y = x+1 to MAXIMUM do
           if amicable(pds, x, y) do
               writef("%N, %N*N", x, y)

$)</lang>

Output:
220, 284
1184, 1210
2620, 2924
5020, 5564
6232, 6368
10744, 10856
12285, 14595
17296, 18416

Befunge

<lang befunge>v_@#-*8*:"2":$_:#!2#*8#g*#6:#0*#!:#-*#<v>*/.55+, 1>$$:28*:*:*%\28*:*:*/`06p28*:*:*/\2v %%^:*:<>*v +|!:-1g60/*:*:*82::+**:*:<<>:#**#8:#<*^>.28*^8 :

v>>*:*%/\28*:*:*%+\v>8+#$^#_+#`\:#0<:\`1/*:*2#<

2v^:*82\/*:*:*82:::_v#!%%*:*:*82\/*:*:*82::<_^#< >>06p:28*:*:**1+01-\>1+::28*:*:*/\28*:*:*%:*\`!^</lang>

Output:
220 284
1184 1210
2620 2924
5020 5564
6232 6368
10744 10856
12285 14595
17296 18416

C

Remark: Look at Pascal Alternative [[2]].You are using the same principle, so here too both numbers of the pair must be < top.

The program will overflow and error in all sorts of ways when given a commandline argument >= UINT_MAX/2 (generally 2^31) <lang c>#include <stdio.h>

  1. include <stdlib.h>

typedef unsigned int uint;

int main(int argc, char **argv) {

 uint top = atoi(argv[1]);
 uint *divsum = malloc((top + 1) * sizeof(*divsum));
 uint pows[32] = {1, 0};
 for (uint i = 0; i <= top; i++) divsum[i] = 1;
 // sieve
 // only sieve within lower half , the modification starts at 2*p
 for (uint p = 2; p+p <= top; p++) {
   if (divsum[p] > 1) {
     divsum[p] -= p;// subtract number itself from divisor sum ('proper')
     continue;}     // p not prime
   uint x; // highest power of p we need
   //checking x <= top/y instead of x*y <= top to avoid overflow
   for (x = 1; pows[x - 1] <= top/p; x++)
     pows[x] = p*pows[x - 1];
   //counter where n is not a*p with a = ?*p, useful for most p.
   //think of p>31 seldom divisions or p>sqrt(top) than no division is needed
   //n = 2*p, so the prime itself is left unchanged => k=p-1
   uint k= p-1;
   for (uint n = p+p; n <= top; n += p) {
     uint s=1+pows[1];
     k--;
     // search the right power only if needed
     if ( k==0) {
       for (uint i = 2; i < x && !(n%pows[i]); s += pows[i++]);
       k = p; }
     divsum[n] *= s;
   }
 }
 //now correct the upper half
 for (uint p = (top >> 1)+1; p <= top; p++) {
   if (divsum[p] > 1){
     divsum[p] -= p;}
 }
 uint cnt = 0;
 for (uint a = 1; a <= top; a++) {
   uint b = divsum[a];
   if (b > a && b <= top && divsum[b] == a){
     printf("%u %u\n", a, b);
     cnt++;}
 }
 printf("\nTop %u count : %u\n",top,cnt);
 return 0;

}</lang>

Output:
% ./a.out 20000
220 284
1184 1210
2620 2924
5020 5564
6232 6368
10744 10856
12285 14595
17296 18416

Top 20000 count : 8


% ./a.out 524000000
..
475838415 514823985
491373104 511419856
509379344 523679536

Top 524000000 count : 442

real  0m16.285s
user  0m16.156s

C#

<lang csharp>using System; using System.Collections.Generic; using System.Linq;

namespace RosettaCode.AmicablePairs {

   internal static class Program {
       private const int Limit = 20000;        
       private static void Main()
       {
           foreach (var pair in GetPairs(Limit))
           {
               Console.WriteLine("{0} {1}", pair.Item1, pair.Item2);
           }
       }
       private static IEnumerable<Tuple<int, int>> GetPairs(int max)
       {
           List<int> divsums =
               Enumerable.Range(0, max + 1).Select(i => ProperDivisors(i).Sum()).ToList();
           for(int i=1; i<divsums.Count; i++) {
               int sum = divsums[i];
               if(i < sum && sum <= divsums.Count && divsums[sum] == i) {
                   yield return new Tuple<int, int>(i, sum);
               }
           }
       }
       private static IEnumerable<int> ProperDivisors(int number)
       {
           return
               Enumerable.Range(1, number / 2)
                   .Where(divisor => number % divisor == 0);
       }
   }

}</lang>

Output:
220 284
1184 1210
2620 2924
5020 5564
6232 6368
10744 10856
12285 14595
17296 18416

C++

<lang cpp>

  1. include <vector>
  2. include <unordered_map>
  3. include <iostream>

int main() {

   std::vector<int> alreadyDiscovered;
   std::unordered_map<int, int> divsumMap; 
   int count = 0;
   for (int N = 1; N <= 20000; ++N)
   {      
       int divSumN = 0;
       for (int i = 1; i <= N / 2; ++i)
       {
           if (fmod(N, i) == 0)
           {
               divSumN += i;
           }
       }
       
       // populate map of integers to the sum of their proper divisors
       if (divSumN != 1) // do not include primes
           divsumMap[N] = divSumN;
       for (std::unordered_map<int, int>::iterator it = divsumMap.begin(); it != divsumMap.end(); ++it)
       {
           int M = it->first;
           int divSumM = it->second;
           int divSumN = divsumMap[N];
           if (N != M && divSumM == N && divSumN == M)
           {
               // do not print duplicate pairs
               if (std::find(alreadyDiscovered.begin(), alreadyDiscovered.end(), N) != alreadyDiscovered.end())
                   break;
               std::cout << "[" << M << ", " << N << "]" << std::endl;
               alreadyDiscovered.push_back(M);
               alreadyDiscovered.push_back(N);
               count++;
           }
       }
   }
   std::cout << count << " amicable pairs discovered" << std::endl;

} </lang>

Output:
[220, 284]
[1184, 1210]
[2620, 2924]
[5020, 5564]
[6232, 6368]
[10744, 10856]
[12285, 14595]
[17296, 18416]
8 amicable pairs discovered

Clojure

<lang lisp> (ns example

 (:gen-class))

(defn factors [n]

 " Find the proper factors of a number "
 (into (sorted-set)
       (mapcat (fn [x] (if (= x 1) [x] [x (/ n x)]))
               (filter #(zero? (rem n %)) (range 1 (inc (Math/sqrt n)))) )))


(def find-pairs (into #{}

              (for [n (range  2 20000)
                 :let [f (factors n)     ; Factors of n
                       M (apply + f)     ; Sum of factors
                       g (factors M)     ; Factors of sum
                       N (apply + g)]    ; Sum of Factors of sum
                 :when (= n N)           ; (sum(proDivs(N)) = M and sum(propDivs(M)) = N
                 :when (not= M N)]       ; N not-equal M
                (sorted-set n M))))      ; Found pair
Output Results

(doseq [q find-pairs]

 (println q))

</lang>

Output:
#{220 284}
#{6232 6368}
#{1184 1210}
#{5020 5564}
#{2620 2924}
#{12285 14595}
#{17296 18416}
#{10744 10856}

CLU

<lang clu>% Generate proper divisors from 1 to max proper_divisors = proc (max: int) returns (array[int])

   divs: array[int] := array[int]$fill(1, max, 0)
   for i: int in int$from_to(1, max/2) do
       for j: int in int$from_to_by(i*2, max, i) do
           divs[j] := divs[j] + i
       end
   end
   return(divs)

end proper_divisors

% Are A and B and amicable pair, given the proper divisors? amicable = proc (divs: array[int], a, b: int) returns (bool)

   return(divs[a] = b & divs[b] = a)

end amicable

% Find all amicable pairs up to 20 000 start_up = proc ()

   max = 20000
   po: stream := stream$primary_output()
   divs: array[int] := proper_divisors(max)
   
   for a: int in int$from_to(1, max) do
       for b: int in int$from_to(a+1, max) do
           if amicable(divs, a, b) then
               stream$putl(po, int$unparse(a) || ", " || int$unparse(b))
           end
       end
   end

end start_up</lang>

Output:
220, 284
1184, 1210
2620, 2924
5020, 5564
6232, 6368
10744, 10856
12285, 14595
17296, 18416

Common Lisp

<lang lisp>(let ((cache (make-hash-table)))

 (defun sum-proper-divisors (n)
   (or (gethash n cache)
       (setf (gethash n cache)
             (loop for x from 1 to (/ n 2)
                   when (zerop (rem n x))
                     sum x)))))

(defun amicable-pairs-up-to (n)

 (loop for x from 1 to n
       for sum-divs = (sum-proper-divisors x)
       when (and (< x sum-divs) (= x (sum-proper-divisors sum-divs)))
         collect (list x sum-divs)))

(amicable-pairs-up-to 20000)</lang>

Output:
((220 284) (1184 1210) (2620 2924) (5020 5564) (6232 6368) (10744 10856)
 (12285 14595) (17296 18416))

Cowgol

<lang cowgol>include "cowgol.coh";

const LIMIT := 20000;

  1. Calculate sums of proper divisors

var divSum: uint16[LIMIT + 1]; var i: @indexof divSum; var j: @indexof divSum;

i := 2; while i <= LIMIT loop

   divSum[i] := 1;
   i := i + 1;

end loop;

i := 2; while i <= LIMIT/2 loop

   j := i * 2;
   while j <= LIMIT loop
       divSum[j] := divSum[j] + i;
       j := j + i;
   end loop;
   i := i + 1;

end loop;

  1. Test each pair

i := 2; while i <= LIMIT loop

   j := i + 1;
   while j <= LIMIT loop
       if divSum[i] == j and divSum[j] == i then
           print_i32(i as uint32);
           print(", ");
           print_i32(j as uint32);
           print_nl();
       end if;
       j := j + 1;
   end loop;
   i := i + 1;

end loop;</lang>

Output:
220, 284
1184, 1210
2620, 2924
5020, 5564
6232, 6368
10744, 10856
12285, 14595
17296, 18416

Crystal

<lang Crystal> MX = 524_000_000 N = Math.sqrt(MX).to_u32 x = Array(Int32).new(MX+1, 1)

(2..N).each { |i|

   p = i*i
   x[p] += i
   k = i+i+1
   (p+i..MX).step(i) { |j|
       x[j] += k
       k += 1
   }

}

(4..MX).each { |m|

   n = x[m]
   if n < m && n != 0 && m == x[n]
       puts "#{n} #{m}"
   end

} </lang>

Output:
220 284
1184 1210
2620 2924
5020 5564
6232 6368
10744 10856
12285 14595
17296 18416
...... ......
....... .......
426191535 514780497
475838415 514823985
509379344 523679536

D

Translation of: Python

<lang d>void main() @safe /*@nogc*/ {

   import std.stdio, std.algorithm, std.range, std.typecons, std.array;
   immutable properDivs = (in uint n) pure nothrow @safe /*@nogc*/ =>
       iota(1, (n + 1) / 2 + 1).filter!(x => n % x == 0);
   enum rangeMax = 20_000;
   auto n2d = iota(1, rangeMax + 1).map!(n => properDivs(n).sum);
   foreach (immutable n, immutable divSum; n2d.enumerate(1))
       if (n < divSum && divSum <= rangeMax && n2d[divSum - 1] == n)
           writefln("Amicable pair: %d and %d with proper divisors:\n    %s\n    %s",
                    n, divSum, properDivs(n), properDivs(divSum));

}</lang>

Output:
Amicable pair: 220 and 284 with proper divisors:
    [1, 2, 4, 5, 10, 11, 20, 22, 44, 55, 110]
    [1, 2, 4, 71, 142]
Amicable pair: 1184 and 1210 with proper divisors:
    [1, 2, 4, 8, 16, 32, 37, 74, 148, 296, 592]
    [1, 2, 5, 10, 11, 22, 55, 110, 121, 242, 605]
Amicable pair: 2620 and 2924 with proper divisors:
    [1, 2, 4, 5, 10, 20, 131, 262, 524, 655, 1310]
    [1, 2, 4, 17, 34, 43, 68, 86, 172, 731, 1462]
Amicable pair: 5020 and 5564 with proper divisors:
    [1, 2, 4, 5, 10, 20, 251, 502, 1004, 1255, 2510]
    [1, 2, 4, 13, 26, 52, 107, 214, 428, 1391, 2782]
Amicable pair: 6232 and 6368 with proper divisors:
    [1, 2, 4, 8, 19, 38, 41, 76, 82, 152, 164, 328, 779, 1558, 3116]
    [1, 2, 4, 8, 16, 32, 199, 398, 796, 1592, 3184]
Amicable pair: 10744 and 10856 with proper divisors:
    [1, 2, 4, 8, 17, 34, 68, 79, 136, 158, 316, 632, 1343, 2686, 5372]
    [1, 2, 4, 8, 23, 46, 59, 92, 118, 184, 236, 472, 1357, 2714, 5428]
Amicable pair: 12285 and 14595 with proper divisors:
    [1, 3, 5, 7, 9, 13, 15, 21, 27, 35, 39, 45, 63, 65, 91, 105, 117, 135, 189, 195, 273, 315, 351, 455, 585, 819, 945, 1365, 1755, 2457, 4095]
    [1, 3, 5, 7, 15, 21, 35, 105, 139, 417, 695, 973, 2085, 2919, 4865]
Amicable pair: 17296 and 18416 with proper divisors:
    [1, 2, 4, 8, 16, 23, 46, 47, 92, 94, 184, 188, 368, 376, 752, 1081, 2162, 4324, 8648]
    [1, 2, 4, 8, 16, 1151, 2302, 4604, 9208]

Delphi

See Pascal.

Draco

<lang draco>/* Fill a given array such that for each N,

* P[n] is the sum of proper divisors of N */

proc nonrec propdivs([*] word p) void:

   word i, j, max;
   max := dim(p,1)-1;
   for i from 0 upto max do p[i] := 0 od;
   for i from 1 upto max/2 do
       for j from i*2 by i upto max do
           p[j] := p[j] + i
       od
   od

corp

/* Find all amicable pairs between 0 and 20,000 */ proc nonrec main() void:

   word MAX = 20000;
   word i, j;
   [MAX] word p;
   propdivs(p);
   
   for i from 1 upto MAX-1 do
       for j from i+1 upto MAX-1 do
           if p[i]=j and p[j]=i then 
               writeln(i:5, ", ", j:5)
           fi
       od
   od

corp</lang>

Output:
  220,   284
 1184,  1210
 2620,  2924
 5020,  5564
 6232,  6368
10744, 10856
12285, 14595
17296, 18416

EchoLisp

<lang scheme>

using (sum-divisors) from math.lib

(lib 'math) (define (amicable N) (define n 0) (for/list ((m (in-range 2 N))) (set! n (sum-divisors m)) #:continue (>= n (* 1.5 m))  ;; assume n/m < 1.5 #:continue (<= n m) ;; prevent perfect numbers #:continue (!= (sum-divisors n) m) (cons m n)))

(amicable 20000)

   → ((220 . 284) (1184 . 1210) (2620 . 2924) (5020 . 5564) (6232 . 6368) (10744 . 10856) (12285 . 14595) (17296 . 18416))

(amicable 1_000_000) ;; 42 pairs

  → (... (802725 . 863835) (879712 . 901424) (898216 . 980984) (947835 . 1125765) (998104 . 1043096))

</lang>

Ela

Translation of: Haskell

<lang ela>open monad io number list

divisors n = filter ((0 ==) << (n `mod`)) [1..(n `div` 2)] range = [1 .. 20000] divs = zip range $ map (sum << divisors) range pairs = [(n, m) \\ (n, nd) <- divs, (m, md) <- divs | n < m && nd == m && md == n]

do putLn pairs ::: IO</lang>

Output:
[(220,284),(1184,1210),(2620,2924),(5020,5564),(6232,6368),(10744,10856),(12285,14595),(17296,18416)]

Elena

Translation of: C#

ELENA 5.0 : <lang elena>import extensions; import system'routines;

const int N = 20000;

extension op {

   ProperDivisors
       = Range.new(1,self / 2).filterBy:(n => self.mod:n == 0);

   get AmicablePairs()
   {
       var divsums := Range
                        .new(0, self + 1)
                        .selectBy:(i => i.ProperDivisors.summarize(Integer.new()))
                        .toArray();

       ^ 1.repeatTill(divsums.Length) 
           .filterBy:(i)
           {
               var ii := i; 

               var sum := divsums[i];
               ^ (i < sum) && (sum < divsums.Length) && (divsums[sum] == i)
           } 
           .selectBy:(i => new { Item1 = i; Item2 = divsums[i]; })
   }

}

public program() {

   N.AmicablePairs.forEach:(pair)
   {
       console.printLine(pair.Item1, " ", pair.Item2)
   }

}</lang>

Output:
220 284
1184 1210
2620 2924
5020 5564
6232 6368
10744 10856
12285 14595
17296 18416

Alternative variant using strong-typed closures

<lang elena>import extensions; import system'routines'stex; import system'collections;

const int N = 20000;

extension op : IntNumber {

   Enumerator<int> ProperDivisors
       = new Range(1,self / 2).filterBy:(int n => self.mod:n == 0);

   get AmicablePairs()
   {
       auto divsums := new List<int>(
           cast Enumerator<int>(
               new Range(0, self).selectBy:(int i => i.ProperDivisors.summarize(0))));

       ^ new Range(0, divsums.Length)
           .filterBy:(int i)
           {
               auto sum := divsums[i];
               ^ (i < sum) && (sum < divsums.Length) && (divsums[sum] == i)
           }
           .selectBy:(int i => new Tuple<int,int>(i,divsums[i]));
   }

}

public program() {

   N.AmicablePairs.forEach:(var Tuple<int,int> pair)
   {
       console.printLine(pair.Item1, " ", pair.Item2)
   }

}</lang>

Alternative variant using yield enumerator

<lang elena>import extensions; import system'routines'stex; import system'collections;

const int Limit = 20000;

singleton ProperDivisors {

   Enumerator<int> function(int number)
       = Range.new(1, number / 2).filterBy:(int n => number.mod:n == 0);

}

public sealed AmicablePairs {

   int max;
   
   constructor(int max)
   {
       this max := max
   }
   
   yieldable Tuple<int, int> next()
   {
       List<int> divsums := Range.new(0, max + 1).selectBy:(int i => ProperDivisors(i).summarize(0));
       
       for (int i := 1, i < divsums.Length, i += 1)
       {
           int sum := divsums[i];
           if(i < sum && sum <= divsums.Length && divsums[sum] == i) {
               yield:new Tuple<int, int>(i, sum);
           }            
       };
       
       ^ nil
   }   

}

public program() {

   auto e := new AmicablePairs(Limit);
   for(auto pair := e.next(), pair != nil)
   {
       console.printLine(pair.Item1, " ", pair.Item2)
   }

}</lang>

Output:
220 284
1184 1210
2620 2924
5020 5564
6232 6368
10744 10856
12285 14595
17296 18416

Elixir

Works with: Elixir version 1.2

With proper_divisors#Elixir in place: <lang elixir>defmodule Proper do

 def divisors(1), do: []
 def divisors(n), do: [1 | divisors(2,n,:math.sqrt(n))] |> Enum.sort
 
 defp divisors(k,_n,q) when k>q, do: []
 defp divisors(k,n,q) when rem(n,k)>0, do: divisors(k+1,n,q)
 defp divisors(k,n,q) when k * k == n, do: [k | divisors(k+1,n,q)]
 defp divisors(k,n,q)                , do: [k,div(n,k) | divisors(k+1,n,q)]

end

map = Map.new(1..20000, fn n -> {n, Proper.divisors(n) |> Enum.sum} end) Enum.filter(map, fn {n,sum} -> map[sum] == n and n < sum end) |> Enum.sort |> Enum.each(fn {i,j} -> IO.puts "#{i} and #{j}" end)</lang>

Output:
220 and 284
1184 and 1210
2620 and 2924
5020 and 5564
6232 and 6368
10744 and 10856
12285 and 14595
17296 and 18416

Erlang

Erlang, slow

Very slow solution. Same functions by and large as in proper divisors and co.

<lang erlang> -module(properdivs). -export([amicable/1,divs/1,sumdivs/1]).

amicable(Limit) -> amicable(Limit,[],3,2).

amicable(Limit,List,_Current,Acc) when Acc >= Limit -> List; amicable(Limit,List,Current,Acc) when Current =< Acc/2 ->

   amicable(Limit,List,Acc,Acc+1);                                          

amicable(Limit,List,Current,Acc) ->

   CS = sumdivs(Current),                                                         
   AS = sumdivs(Acc),                                                             
   if                                                                             
       CS == Acc andalso AS == Current andalso Acc =/= Current ->                 
         io:format("A: ~w, B: ~w, ~nL: ~w~w~n",  [Current,Acc,divs(Current),divs(Acc)]),                                                                                
         NL = List ++ [{Current,Acc}],                                            
         amicable(Limit,NL,Acc+1,Acc+1);                                          
       true -> 
         amicable(Limit,List,Current-1,Acc) end.                            
                                                                                                                                          

divs(0) -> []; divs(1) -> []; divs(N) -> lists:sort(divisors(1,N)).

divisors(1,N) ->

    [1] ++ divisors(2,N,math:sqrt(N)).                                         
                                                                               

divisors(K,_N,Q) when K > Q -> []; divisors(K,N,_Q) when N rem K =/= 0 ->

   [] ++ divisors(K+1,N,math:sqrt(N));                                         

divisors(K,N,_Q) when K * K == N ->

   [K] ++ divisors(K+1,N,math:sqrt(N));                                        

divisors(K,N,_Q) ->

   [K, N div K] ++ divisors(K+1,N,math:sqrt(N)).                               
                                                                               

sumdivs(N) -> lists:sum(divs(N)). </lang>

Output:
3> properdivs:amicable(20000).
A: 220, B: 284, 
L: [1,2,4,5,10,11,20,22,44,55,110][1,2,4,71,142]
A: 1184, B: 1210, 
L: [1,2,4,8,16,32,37,74,148,296,592][1,2,5,10,11,22,55,110,121,242,605]
A: 2620, B: 2924, 
L: [1,2,4,5,10,20,131,262,524,655,1310][1,2,4,17,34,43,68,86,172,731,1462]
A: 5020, B: 5564, 
L: [1,2,4,5,10,20,251,502,1004,1255,2510][1,2,4,13,26,52,107,214,428,1391,2782]
A: 6232, B: 6368, 
L: [1,2,4,8,19,38,41,76,82,152,164,328,779,1558,3116][1,2,4,8,16,32,199,398,796,1592,3184]
A: 10744, B: 10856, 
L: [1,2,4,8,17,34,68,79,136,158,316,632,1343,2686,5372][1,2,4,8,23,46,59,92,118,184,236,472,1357,2714,5428]
A: 12285, B: 14595, 
L: [1,3,5,7,9,13,15,21,27,35,39,45,63,65,91,105,117,135,189,195,273,315,351,455,585,819,945,1365,1755,2457,4095][1,3,5,7,15,21,35,105,139,417,695,973,2085,2919,4865]
A: 17296, B: 18416, 
L: [1,2,4,8,16,23,46,47,92,94,184,188,368,376,752,1081,2162,4324,8648][1,2,4,8,16,1151,2302,4604,9208]
[{220,284},
 {1184,1210},
 {2620,2924},
 {5020,5564},
 {6232,6368},
 {10744,10856},
 {12285,14595},
 {17296,18416}]

Erlang, faster

This is lazy AND depends on the fun fact that we're not really identifying pairs. They just happen to order. Probably, this answer is false in some sense. But a good deal faster :) As above with the additional function.

[See the talk section   amicable pairs, out of order   for this Rosetta Code task.]

<lang erlang> friendly(Limit) ->

   List = [{X,properdivs:sumdivs(X)} || X <- lists:seq(3,Limit)],
   Final = [ X || 
       X <- lists:seq(3,Limit), 
       X == properdivs:sumdivs(proplists:get_value(X,List)) 
       andalso X =/= proplists:get_value(X,List)],
   io:format("L: ~w~n", [Final]).                                                   

</lang>

Output:
45> properdivs:friendly(20000).
L: [220,284,1184,1210,2620,2924,5020,5564,6232,6368,10744,10856,12285,14595,17296,18416]
ok

We might answer a challenge by saying: <lang erlang> friendly(Limit) ->

   List = [{X,properdivs:sumdivs(X)} || X <- lists:seq(3,Limit)],                 
   Final = [ X || X <- lists:seq(3,Limit), X == properdivs:sumdivs(proplists:get_value(X,List)) 
           andalso X =/= proplists:get_value(X,List)],
   findfriendlies(Final,[]).
                                                                                  
                                                                                  

findfriendlies(List,Acc) when length(List) =< 0 -> Acc; findfriendlies(List,Acc) ->

   A = lists:nth(1,List),                                                         
   AS = sumdivs(A),                                                               
   B = lists:nth(2,List),                                                         
   BS = sumdivs(B),                                                               
   if                                                                             
       AS == B andalso BS == A ->                                                 
         {_,BL} = lists:split(2,List),                                            
         findfriendlies(BL,Acc++[{A,B}]);                                         
       true -> false                                                              
   end.                                                                           
                                                                                  

</lang>

Output:
94>  properdivs:friendly(20000).
[{220,284},
 {1184,1210},
 {2620,2924},
 {5020,5564},
 {6232,6368},
 {10744,10856},
 {12285,14595},
 {17296,18416}]

In either case, it's a lot faster than the recursion in my first example.

ERRE

<lang ERRE>PROGRAM AMICABLE

CONST LIMIT=20000

PROCEDURE SUMPROP(NUM->M)

 IF NUM<2 THEN M=0 EXIT PROCEDURE
 SUM=1
 ROOT=SQR(NUM)
 FOR I=2 TO ROOT-1 DO
    IF (NUM=I*INT(NUM/I)) THEN
        SUM=SUM+I+NUM/I
    END IF
    IF (NUM=ROOT*INT(NUM/ROOT)) THEN
        SUM=SUM+ROOT
    END IF
 END FOR
 M=SUM

END PROCEDURE

BEGIN

 PRINT(CHR$(12);) ! CLS
 PRINT("Amicable pairs < ";LIMIT)
 FOR N=1 TO LIMIT DO
   SUMPROP(N->M1)
   SUMPROP(M1->M2)
   IF (N=M2 AND N<M1) THEN PRINT(N,M1)
 END FOR

END PROGRAM</lang>

Output:
Amicable pairs <  20000
 220           284
 1184          1210
 2620          2924
 5020          5564
 6232          6368
 10744         10856
 12285         14595
 17296         18416

F#

<lang fsharp> [2..20000 - 1] |> List.map (fun n-> n, ([1..n/2] |> List.filter (fun x->n % x = 0) |> List.sum)) |> List.map (fun (a,b) ->if a List.groupBy id |> List.map snd |> List.filter (List.length >> ((=) 2)) |> List.map List.head |> List.iter (printfn "%A") </lang>

Output:
(220, 284)
(1184, 1210)
(2620, 2924)
(5020, 5564)
(6232, 6368)
(10744, 10856)
(12285, 14595)
(17296, 18416)

Factor

This solution focuses on the language's namesake: factoring code into small words which are subsequently composed to form more powerful — yet just as simple — words. Using this approach, the final word naturally arrives at the solution. This is often referred to as the bottom-up approach, which is a way in which Factor (and other concatenative languages) commonly differs from other languages.

<lang Factor> USING: grouping math.primes.factors math.ranges ;

pdivs ( n -- seq ) divisors but-last ;
dsum ( n -- sum ) pdivs sum ;
dsum= ( n m -- ? ) dsum = ;
both-dsum= ( n m -- ? ) [ dsum= ] [ swap dsum= ] 2bi and ;
amicable? ( n m -- ? ) [ both-dsum= ] [ = not ] 2bi and ;
drange ( -- seq ) 2 20000 [a,b) ;
dsums ( -- seq ) drange [ dsum ] map ;
is-am?-seq ( -- seq ) dsums drange [ amicable? ] 2map ;
am-nums ( -- seq ) t is-am?-seq indices ;
am-nums-c ( -- seq ) am-nums [ 2 + ] map ;
am-pairs ( -- seq ) am-nums-c 2 group ;
print-am ( -- ) am-pairs [ >array . ] each ;

print-am </lang>

Output:
{ 220 284 }
{ 1184 1210 }
{ 2620 2924 }
{ 5020 5564 }
{ 6232 6368 }
{ 10744 10856 }
{ 12285 14595 }
{ 17296 18416 }

Forth

Works with: gforth version 0.7.3

Direct approach

Calculate many times the divisors.

<lang forth>: proper-divisors ( n -- 1..n )

 dup 2 / 1+ 1 ?do
   dup i mod 0= if i swap then
 loop drop ;
divisors-sum ( 1..n -- n )
 dup 1 = if exit then
 begin over + swap
 1 = until ;
pair ( n -- n )
 dup 1 = if exit then
 proper-divisors divisors-sum ;
?paired ( n -- t | f )
 dup pair 2dup pair
 = >r < r> and ;
amicable-list
 1+ 1 do
   i ?paired if cr i . i pair . then
 loop ;

20000 amicable-list</lang>

Output:
220 284 
1184 1210 
2620 2924 
5020 5564 
6232 6368 
10744 10856 
12285 14595 
17296 18416  ok

Storage approach

Use memory to store sum of divisors, a little quicker.

<lang forth>variable amicable-table

proper-divisors ( n -- 1..n )
 dup 1 = if exit then ( not really but useful )
 dup 2 / 1+ 1 ?do
   dup i mod 0= if i swap then
 loop drop ;
divisors-sum ( 1..n -- n )
 dup 1 = if exit then
 begin over + swap
 1 = until ;
build-amicable-table
 here amicable-table !
 1+ dup ,
 1 do
   i proper-divisors divisors-sum ,
 loop ;
paired cells amicable-table @ + @ ;
.amicables
 amicable-table @ @ 1 do
   i paired paired i =
   i paired i > and
   if cr i . i paired . then
 loop ;
amicable-list
 build-amicable-table .amicables ;

20000 amicable-list</lang>

Output:
220 284 
1184 1210 
2620 2924 
5020 5564 
6232 6368 
10744 10856 
12285 14595 
17296 18416  ok

Fortran

This version uses some latter-day facilities such as array assignment that could be replaced by an ordinary DO-loop, as could the FOR ALL statement that for two adds two to every second element, for three adds three to every third, etc. Each FORALL statement applies its DO-given increment to all the selected array elements potentially in any order or even simultaneously. Likewise, the "MODULE" protocol could be abandoned, which would mean that the KNOWNSUM array would have to be declared COMMON for access across routines - or the whole re-written as a single mainline. And if the PARAMETER statements were replaced appropriately, this source could be compiled using Fortran 77.

Output:

Perfect!!           6
Perfect!!          28
Amicable!         220         284
Perfect!!         496
Amicable!        1184        1210
Amicable!        2620        2924
Amicable!        5020        5564
Amicable!        6232        6368
Perfect!!        8128
Amicable!       10744       10856
Amicable!       12285       14595
Amicable!       17296       18416

<lang FORTRAN>

     MODULE FACTORSTUFF	!This protocol evades the need for multiple parameters, or COMMON, or one shapeless main line...

Concocted by R.N.McLean, MMXV.

      INTEGER LOTS,ILIMIT		!Some bounds.
      PARAMETER (ILIMIT = 2147483647)	!Computer arithmetic is not with real numbers.
      PARAMETER (LOTS = 22000)	!Nor is computer storage infinite.
      INTEGER KNOWNSUM(LOTS)		!Calculate these once as multiple references are expected.
      CONTAINS			!Assistants.
       INTEGER FUNCTION SUMF(N)	!Sum of the proper divisors of N.
        INTEGER N			!The number in question.
        INTEGER S,F,F2,INC,BOOST	!Assistants.
         IF (N.LE.LOTS) THEN		!If we're within reach,
           SUMF = KNOWNSUM(N)			!The result is to hand.
          ELSE			!Otherwise, some on-the-spot effort ensues.

Could use SUMF in place of S, but some compilers have been confused by such usage.

           S = 1			!1 is always a factor of N, but N is deemed not.
           F = 1			!Prepare a crude search for factors.
           INC = 1			!One by plodding one.
           IF (MOD(N,2) .EQ. 1) INC = 2!Ah, but an odd number cannot have an even number as a divisor.
   1       F = F + INC			!So half the time we can doubleplod.
           F2 = F*F				!Up to F2 < N rather than F < SQRT(N) and worries over inexact arithmetic.
           IF (F2 .LT. N) THEN			!F2 = N handled below.
             IF (MOD(N,F) .EQ. 0) THEN		!Does F divide N?
               BOOST = F + N/F			!Yes. The divisor and its counterpart.
               IF (S .GT. ILIMIT - BOOST) GO TO 666	!Would their augmentation cause an overflow?
               S = S + BOOST			!No, so count in the two divisors just discovered.
             END IF				!So much for a divisor discovered.
             GO TO 1				!Try for another.
           END IF			!So much for the horde.
           IF (F2 .EQ. N) THEN	!Special case: N may be a perfect square, not necessarily of a prime number.
             IF (S .GT. ILIMIT - F) GO TO 666	!It is. And it too might cause overflow.
             S = S + F			!But if not, count F once only.
           END IF			!All done.
           SUMF = S			!This is the result.
         END IF			!Whichever way obtained,
        RETURN			!Done.

Cannot calculate the sum, because it exceeds the integer limit.

 666     SUMF = -666		!An expression of dismay that the caller will notice.
       END FUNCTION SUMF	!Alternatively, find the prime factors, and combine them...  
        SUBROUTINE PREPARESUMF	!Initialise the KNOWNSUM array.

Convert the Sieve of Eratoshenes to have each slot contain the sum of the proper divisors of its slot number. Changes to instead count the number of factors, or prime factors, etc. would be simple enough.

        INTEGER F		!A factor for numbers such as 2F, 3F, 4F, 5F, ...
         KNOWNSUM(1) = 0		!Proper divisors of N do not include N.
         KNOWNSUM(2:LOTS) = 1		!So, although 1 is a proper divisor of all N, 1 is excluded for itself.
         DO F = 2,LOTS/2		!Step through all the possible divisors of numbers not exceeding LOTS.
           FOR ALL(I = F + F:LOTS:F) KNOWNSUM(I) = KNOWNSUM(I) + F	!And augment each corresponding slot.
         END DO			!Different divisors can hit the same slot. For instance, 6 by 2 and also by 3.
       END SUBROUTINE PREPARESUMF	!Could alternatively generate all products of prime numbers.
     END MODULE FACTORSTUFF	!Enough assistants. 
      PROGRAM AMICABLE		!Seek N such that SumF(SumF(N)) = N, for N up to 20,000.
      USE FACTORSTUFF		!This should help.
      INTEGER I,N		!Steppers.
      INTEGER S1,S2		!Sums of factors.
       CALL PREPARESUMF		!Values for every N up to the search limit will be called for at least once.

c WRITE (6,66) (I,KNOWNSUM(I), I = 1,48) c 66 FORMAT (10(I3,":",I5,"|"))

       DO N = 2,20000		!Step through the specified search space.
         S1 = SUMF(N)			!Only even numbers appear in the results, but check every one anyway.
         IF (S1 .EQ. N) THEN		!Catch a tight loop.
           WRITE (6,*) "Perfect!!",N	!Self amicable! Would otherwise appear as Amicable! n,n.
         ELSE IF (S1 .GT. N) THEN	!Look for a pair going upwards only.
           S2 = SUMF(S1)		!Since otherwise each would appear twice.
           IF (S2.EQ.N) WRITE (6,*) "Amicable!",N,S1	!Aha!
         END IF			!So much for that candidate.
       END DO			!On to the next.
     END			!Done.

</lang>

FreeBASIC

using Mod

<lang freebasic> ' FreeBASIC v1.05.0 win64

Function SumProperDivisors(number As Integer) As Integer

 If number < 2 Then Return 0
 Dim sum As Integer = 0
 For i As Integer = 1 To number \ 2
   If number Mod i = 0 Then sum += i
 Next
 Return sum

End Function

Dim As Integer n, f Dim As Integer sum(19999)

For n = 1 To 19999

 sum(n) = SumProperDivisors(n)

Next

Print "The pairs of amicable numbers below 20,000 are :" Print

For n = 1 To 19998

 ' f = SumProperDivisors(n)
 f = sum(n)
 If f <= n OrElse f < 1 OrElse f > 19999 Then Continue For 
 If f = sum(n) AndAlso n = sum(f) Then
   Print Using "#####"; n;  
   Print " and "; Using "#####"; sum(n)
 End If

Next

Print Print "Press any key to exit the program" Sleep End </lang>

Output:
The pairs of amicable numbers below 20,000 are :

  220 and   284
 1184 and  1210
 2620 and  2924
 5020 and  5564
 6232 and  6368
10744 and 10856
12285 and 14595
17296 and 18416

using "Sieve of Erathosthenes" style

<lang freebasic>' version 04-10-2016 ' compile with: fbc -s console ' replaced the function with 2 FOR NEXT loops

  1. Define max 20000 ' test for pairs below max
  2. Define max_1 max -1

Dim As String u_str = String(Len(Str(max))+1,"#") Dim As UInteger n, f Dim Shared As UInteger sum(max_1)

For n = 2 To max_1

 sum(n) = 1

Next

For n = 2 To max_1 \ 2

 For f  = n * 2 To max_1 Step n
   sum(f) += n
 Next

Next

Print Print Using " The pairs of amicable numbers below" & u_str & ", are :"; max Print

For n = 1 To max_1 -1

 f = Sum(n)
 If f <= n OrElse f > max Then Continue For
 If f = sum(n) AndAlso n = sum(f) Then
   Print Using u_str & " and" & u_str ; n; f
 End If

Next

' empty keyboard buffer While Inkey <> "" : Wend Print : Print : Print " Hit any key to end program" Sleep End</lang>

 The pairs of amicable numbers below 20,000 are :

   220 and   284
  1184 and  1210
  2620 and  2924
  5020 and  5564
  6232 and  6368
 10744 and 10856
 12285 and 14595
 17296 and 18416

Frink

This example uses Frink's built-in efficient factorization algorithms. It can work for arbitrarily large numbers. <lang frink> n = 1 seen = new set

do {

  n = n + 1
  if seen.contains[n]
     next
  sum = sum[allFactors[n, true, false, false]]
  if sum != n and sum[allFactors[sum, true, false, false]] == n
  {
     println["$n, $sum"]
     seen.put[sum]
  }

} while n <= 20000 </lang>

Output:
220, 284
1184, 1210
2620, 2924
5020, 5564
6232, 6368
10744, 10856
12285, 14595
17296, 18416

Futhark

This example does not show the output mentioned in the task description on this page (or a page linked to from here). Please ensure that it meets all task requirements and remove this message.
Note that phrases in task descriptions such as "print and display" and "print and show" for example, indicate that (reasonable length) output be a part of a language's solution.


This program is much too parallel and manifests all the pairs, which requires a giant amount of memory.

<lang> fun divisors(n: int): []int =

 filter (fn x => n%x == 0) (map (1+) (iota (n/2)))

fun amicable((n: int, nd: int), (m: int, md: int)): bool =

 n < m && nd == m && md == n

fun getPair (divs: [upper](int, int)) (flat_i: int): ((int,int), (int,int)) =

 let i = flat_i / upper
 let j = flat_i % upper
 in unsafe (divs[i], divs[j])

fun main(upper: int): [][2]int =

 let range = map (1+) (iota upper)
 let divs = zip range (map (fn n => reduce (+) 0 (divisors n)) range)
 let amicable = filter amicable (map (getPair divs) (iota (upper*upper)))
 in map (fn (np,mp) => [#1 np, #1 mp]) amicable

</lang>

GFA Basic

<lang> OPENW 1 CLEARW 1 ' DIM f%(20001) ! sum of proper factors for each n FOR i%=1 TO 20000

 f%(i%)=@sum_proper_divisors(i%)

NEXT i% ' look for pairs FOR i%=1 TO 20000

 FOR j%=i%+1 TO 20000
   IF f%(i%)=j% AND i%=f%(j%)
     PRINT "Amicable pair ";i%;" ";j%
   ENDIF
 NEXT j%

NEXT i% ' PRINT PRINT "-- found all amicable pairs" ~INP(2) CLOSEW 1 ' ' Compute the sum of proper divisors of given number ' FUNCTION sum_proper_divisors(n%)

 LOCAL i%,sum%,root%
 '
 IF n%>1 ! n% must be 2 or larger
   sum%=1 ! start with 1
   root%=SQR(n%) ! note that root% is an integer
   ' check possible factors, up to sqrt
   FOR i%=2 TO root%
     IF n% MOD i%=0
       sum%=sum%+i% ! i% is a factor
       IF i%*i%<>n% ! check i% is not actual square root of n%
         sum%=sum%+n%/i% ! so n%/i% will also be a factor
       ENDIF
     ENDIF
   NEXT i%
 ENDIF
 RETURN sum%

ENDFUNC </lang>

Output is:

Amicable pair: 220 284
Amicable pair: 1184 1210
Amicable pair: 2620 2924
Amicable pair: 5020 5564
Amicable pair: 6232 6368
Amicable pair: 10744 10856
Amicable pair: 12285 14595
Amicable pair: 17296 18416

-- found all amicable pairs

Go

<lang Go>package main

import "fmt"

func pfacSum(i int) int {

   sum := 0
   for p := 1; p <= i/2; p++ {
       if i%p == 0 {
           sum += p
       }
   }
   return sum

}

func main() {

   var a[20000]int
   for i := 1; i < 20000; i++ {
       a[i] = pfacSum(i)
   }
   fmt.Println("The amicable pairs below 20,000 are:")
   for n := 2; n < 19999; n++ {
       m := a[n]
       if m > n && m < 20000 && n == a[m] {
           fmt.Printf("  %5d and %5d\n", n, m)
       } 
   }

}</lang>

Output:
The amicable pairs below 20,000 are:
    220 and   284
   1184 and  1210
   2620 and  2924
   5020 and  5564
   6232 and  6368
  10744 and 10856
  12285 and 14595
  17296 and 18416

Haskell

<lang Haskell>divisors :: (Integral a) => a -> [a] divisors n = filter ((0 ==) . (n `mod`)) [1 .. (n `div` 2)]

main :: IO () main = do

 let range = [1 .. 20000 :: Int]
     divs = zip range $ map (sum . divisors) range
     pairs = [(n, m) | (n, nd) <- divs, (m, md) <- divs,
              n < m, nd == m, md == n]
 print pairs</lang>
Output:
[(220,284),(1184,1210),(2620,2924),(5020,5564),(6232,6368),(10744,10856),(12285,14595),(17296,18416)]


Or, deriving proper divisors above the square root as cofactors (for better performance)

<lang Haskell>import Data.Bool (bool)

amicablePairsUpTo :: Int -> [(Int, Int)] amicablePairsUpTo n =

 let sigma = sum . properDivisors
 in [1 .. n] >>=
    (\x ->
        let y = sigma x
        in bool [] [(x, y)] (x < y && x == sigma y))

properDivisors

 :: Integral a
 => a -> [a]

properDivisors n =

 let root = (floor . sqrt) (fromIntegral n :: Double)
     lows = filter ((0 ==) . rem n) [1 .. root]
 in init $
    lows ++ drop (bool 0 1 (root * root == n)) (reverse (quot n <$> lows))

main :: IO () main = mapM_ print $ amicablePairsUpTo 20000</lang>

Output:
(220,284)
(1184,1210)
(2620,2924)
(5020,5564)
(6232,6368)
(10744,10856)
(12285,14595)
(17296,18416)

J

Proper Divisor implementation:

<lang J>factors=: [: /:~@, */&>@{@((^ i.@>:)&.>/)@q:~&__ properDivisors=: factors -. -.&1</lang>

Amicable pairs:

<lang J> 1 + 0 20000 #: I. ,(</~@i.@# * (* |:))(=/ +/@properDivisors@>) 1 + i.20000

 220   284
1184  1210
2620  2924
5020  5564
6232  6368

10744 10856 12285 14595 17296 18416</lang>

Java

Works with: Java version 8

<lang java>import java.util.Map; import java.util.function.Function; import java.util.stream.Collectors; import java.util.stream.LongStream;

public class AmicablePairs {

   public static void main(String[] args) {
       int limit = 20_000;
       Map<Long, Long> map = LongStream.rangeClosed(1, limit)
               .parallel()
               .boxed()
               .collect(Collectors.toMap(Function.identity(), AmicablePairs::properDivsSum));
       LongStream.rangeClosed(1, limit)
               .forEach(n -> {
                   long m = map.get(n);
                   if (m > n && m <= limit && map.get(m) == n)
                       System.out.printf("%s %s %n", n, m);
               });
   }
   public static Long properDivsSum(long n) {
       return LongStream.rangeClosed(1, (n + 1) / 2).filter(i -> n % i == 0).sum();
   }

}</lang>

220 284 
1184 1210 
2620 2924 
5020 5564 
6232 6368 
10744 10856 
12285 14595 
17296 18416 

JavaScript

ES5

<lang JavaScript>(function (max) {

   // Proper divisors
   function properDivisors(n) {
       if (n < 2) return [];
       else {
           var rRoot = Math.sqrt(n),
               intRoot = Math.floor(rRoot),

               lows = range(1, intRoot).filter(function (x) {
                   return (n % x) === 0;
               });

           return lows.concat(lows.slice(1).map(function (x) {
               return n / x;
           }).reverse().slice((rRoot === intRoot) | 0));
       }
   }

   // [m..n]
   function range(m, n) {
       var a = Array(n - m + 1),
           i = n + 1;
       while (i--) a[i - 1] = i;
       return a;
   }

   // Filter an array of proper divisor sums,
   // reading the array index as a function of N (N-1)
   // and the sum of proper divisors as a potential M

   var pairs = range(1, max).map(function (x) {
       return properDivisors(x).reduce(function (a, d) {
           return a + d;
       }, 0)
   }).reduce(function (a, m, i, lst) {
       var n = i + 1;

       return (m > n) && lst[m - 1] === n ? a.concat(n, m) : a;
   }, []);

   // a -> bool -> s -> s
   function wikiTable(lstRows, blnHeaderRow, strStyle) {
       return '{| class="wikitable" ' + (
           strStyle ? 'style="' + strStyle + '"' : 
       ) + lstRows.map(function (lstRow, iRow) {
           var strDelim = ((blnHeaderRow && !iRow) ? '!' : '|');

           return '\n|-\n' + strDelim + ' ' + lstRow.map(function (v) {
               return typeof v === 'undefined' ? ' ' : v;
           }).join(' ' + strDelim + strDelim + ' ');
       }).join() + '\n|}';
   }

   return wikiTable(
       'N', 'M'.concat(pairs),
       true,
       'text-align:center'
   ) + '\n\n' + JSON.stringify(pairs);

})(20000);</lang>

Output:
N M
220 284
1184 1210
2620 2924
5020 5564
6232 6368
10744 10856
12285 14595
17296 18416

<lang JavaScript>[[220,284],[1184,1210],[2620,2924],[5020,5564],

[6232,6368],[10744,10856],[12285,14595],[17296,18416]]</lang>

ES6

<lang JavaScript>(() => {

   'use strict';
   // amicablePairsUpTo :: Int -> [(Int, Int)]
   const amicablePairsUpTo = n => {
       const sigma = compose(sum, properDivisors);
       return enumFromTo(1)(n).flatMap(x => {
           const y = sigma(x);
           return x < y && x === sigma(y) ? ([
               [x, y]
           ]) : [];
       });
   };
   // properDivisors :: Int -> [Int]
   const properDivisors = n => {
       const
           rRoot = Math.sqrt(n),
           intRoot = Math.floor(rRoot),
           lows = enumFromTo(1)(intRoot)
           .filter(x => 0 === (n % x));
       return lows.concat(lows.map(x => n / x)
           .reverse()
           .slice((rRoot === intRoot) | 0, -1));
   };


   // TEST -----------------------------------------------
   // main :: IO ()
   const main = () =>
       console.log(unlines(
           amicablePairsUpTo(20000).map(JSON.stringify)
       ));


   // GENERIC FUNCTIONS ----------------------------------
   // compose (<<<) :: (b -> c) -> (a -> b) -> a -> c
   const compose = (...fs) =>
       x => fs.reduceRight((a, f) => f(a), x);


   // enumFromTo :: Int -> Int -> [Int]
   const enumFromTo = m => n =>
       Array.from({
           length: 1 + n - m
       }, (_, i) => m + i);


   // sum :: [Num] -> Num
   const sum = xs => xs.reduce((a, x) => a + x, 0);


   // unlines :: [String] -> String
   const unlines = xs => xs.join('\n');


   // MAIN ---
   return main();

})();</lang>

Output:
[220,284]
[1184,1210]
[2620,2924]
[5020,5564]
[6232,6368]
[10744,10856]
[12285,14595]
[17296,18416]

jq

<lang jq># unordered def proper_divisors:

 . as $n
 | if $n > 1 then 1,
     (sqrt|floor as $s
     | range(2; $s+1) as $i
     | if ($n % $i) == 0 then $i,
          (if $i * $i == $n then empty else ($n / $i) end)

else empty end)

   else empty
   end;

def addup(stream): reduce stream as $i (0; . + $i);

def task(n):

 (reduce range(0; n+1) as $n
   ( [];  . + [$n | addup(proper_divisors)] )) as $listing
 | range(1;n+1) as $j
 | range(1;$j) as $k
 | if $listing[$j] == $k and $listing[$k] == $j
   then "\($k) and \($j) are amicable"
   else empty
   end ;

task(20000)</lang>

Output:

<lang sh>$ jq -c -n -f amicable_pairs.jq 220 and 284 are amicable 1184 and 1210 are amicable 2620 and 2924 are amicable 5020 and 5564 are amicable 6232 and 6368 are amicable 10744 and 10856 are amicable 12285 and 14595 are amicable 17296 and 18416 are amicable</lang>

Julia

Given factor, it is not necessary to calculate the individual divisors to compute their sum. See Abundant, deficient and perfect number classifications for the details. It is safe to exclude primes from consideration; their proper divisor sum is always 1. This code also uses a minor trick to ensure that none of the numbers identified are above the limit. All numbers in the range are checked for an amicable partner, but the pair is cataloged only when the greater member is reached. <lang Julia>using Primes, Printf

function pcontrib(p::Int64, a::Int64)

   n = one(p)
   pcon = one(p)
   for i in 1:a
       n *= p
       pcon += n
   end
   return pcon

end

function divisorsum(n::Int64)

   dsum = one(n)
   for (p, a) in factor(n)
       dsum *= pcontrib(p, a)
   end
   dsum -= n

end

function amicables(L = 2*10^7)

   acnt = 0
   println("Amicable pairs not greater than ", L)
   for i in 2:L
       !isprime(i) || continue
       j = divisorsum(i)
       j < i && divisorsum(j) == i || continue
       acnt += 1
       println(@sprintf("%4d", acnt), " => ", j, ", ", i)
   end

end

amicables()

</lang>

Output:
Amicable pairs not greater than 20000000
   1 => 220, 284
   2 => 1184, 1210
   3 => 2620, 2924
   4 => 5020, 5564
   5 => 6232, 6368
   6 => 10744, 10856
   7 => 12285, 14595
   8 => 17296, 18416
   9 => 66928, 66992
  10 => 67095, 71145
  11 => 63020, 76084
  12 => 69615, 87633
  13 => 79750, 88730
  14 => 122368, 123152
  15 => 100485, 124155
  16 => 122265, 139815
  17 => 141664, 153176
  18 => 142310, 168730
  19 => 171856, 176336
  20 => 176272, 180848
  21 => 196724, 202444
  22 => 185368, 203432
  23 => 280540, 365084
  24 => 308620, 389924
  25 => 356408, 399592
  26 => 319550, 430402
  27 => 437456, 455344
  28 => 469028, 486178
  29 => 503056, 514736
  30 => 522405, 525915
  31 => 643336, 652664
  32 => 600392, 669688
  33 => 609928, 686072
  34 => 624184, 691256
  35 => 635624, 712216
  36 => 667964, 783556
  37 => 726104, 796696
  38 => 802725, 863835
  39 => 879712, 901424
  40 => 898216, 980984
  41 => 998104, 1043096
  42 => 1077890, 1099390
  43 => 947835, 1125765
  44 => 1154450, 1189150
  45 => 1185376, 1286744
  46 => 1156870, 1292570
  47 => 1280565, 1340235
  48 => 1175265, 1438983
  49 => 1392368, 1464592
  50 => 1328470, 1483850
  51 => 1358595, 1486845
  52 => 1511930, 1598470
  53 => 1466150, 1747930
  54 => 1468324, 1749212
  55 => 1798875, 1870245
  56 => 1669910, 2062570
  57 => 2082464, 2090656
  58 => 2236570, 2429030
  59 => 2723792, 2874064
  60 => 2739704, 2928136
  61 => 2652728, 2941672
  62 => 2802416, 2947216
  63 => 2728726, 3077354
  64 => 2803580, 3716164
  65 => 3276856, 3721544
  66 => 3606850, 3892670
  67 => 3805264, 4006736
  68 => 3786904, 4300136
  69 => 4238984, 4314616
  70 => 4259750, 4445050
  71 => 4246130, 4488910
  72 => 4482765, 5120595
  73 => 4604776, 5162744
  74 => 5459176, 5495264
  75 => 5123090, 5504110
  76 => 5357625, 5684679
  77 => 5232010, 5799542
  78 => 5385310, 5812130
  79 => 5147032, 5843048
  80 => 5730615, 6088905
  81 => 4532710, 6135962
  82 => 5726072, 6369928
  83 => 6329416, 6371384
  84 => 6377175, 6680025
  85 => 6993610, 7158710
  86 => 6955216, 7418864
  87 => 7275532, 7471508
  88 => 5864660, 7489324
  89 => 7489112, 7674088
  90 => 7677248, 7684672
  91 => 7800544, 7916696
  92 => 7850512, 8052488
  93 => 7288930, 8221598
  94 => 8262136, 8369864
  95 => 7577350, 8493050
  96 => 9363584, 9437056
  97 => 9071685, 9498555
  98 => 9199496, 9592504
  99 => 8619765, 9627915
 100 => 9339704, 9892936
 101 => 9660950, 10025290
 102 => 8826070, 10043690
 103 => 10254970, 10273670
 104 => 8666860, 10638356
 105 => 9206925, 10791795
 106 => 10572550, 10854650
 107 => 8754130, 10893230
 108 => 10533296, 10949704
 109 => 9491625, 10950615
 110 => 9478910, 11049730
 111 => 10596368, 11199112
 112 => 9773505, 11791935
 113 => 11498355, 12024045
 114 => 10992735, 12070305
 115 => 11252648, 12101272
 116 => 11545616, 12247504
 117 => 11693290, 12361622
 118 => 12397552, 13136528
 119 => 11173460, 13212076
 120 => 11905504, 13337336
 121 => 13921528, 13985672
 122 => 10634085, 14084763
 123 => 12707704, 14236136
 124 => 13813150, 14310050
 125 => 14311688, 14718712
 126 => 15002464, 15334304
 127 => 13671735, 15877065
 128 => 14443730, 15882670
 129 => 16137628, 16150628
 130 => 15363832, 16517768
 131 => 14654150, 16817050
 132 => 15938055, 17308665
 133 => 17257695, 17578785
 134 => 17908064, 18017056
 135 => 14426230, 18087818
 136 => 18056312, 18166888
 137 => 17041010, 19150222
 138 => 18655744, 19154336
 139 => 16871582, 19325698
 140 => 17844255, 19895265
 141 => 17754165, 19985355

K

<lang k>

 propdivs:{1+&0=x!'1+!x%2}
 (8,2)#v@&{(x=+/propdivs[a])&~x=a:+/propdivs[x]}' v:1+!20000

(220 284

1184 1210
2620 2924
5020 5564
6232 6368
10744 10856
12285 14595
17296 18416)

</lang>

Kotlin

<lang scala>// version 1.1

fun sumProperDivisors(n: Int): Int {

   if (n < 2) return 0
   return (1..n / 2).filter{ (n % it) == 0 }.sum()

}

fun main(args: Array<String>) {

   val sum = IntArray(20000, { sumProperDivisors(it) } )
   println("The pairs of amicable numbers below 20,000 are:\n")
   for(n in 2..19998) {
       val m = sum[n]
       if (m > n && m < 20000 && n == sum[m]) {
           println(n.toString().padStart(5) + " and " + m.toString().padStart(5))
       }
   }

}</lang>

Output:
The pairs of amicable numbers below 20,000 are:

  220 and   284
 1184 and  1210
 2620 and  2924
 5020 and  5564
 6232 and  6368
10744 and 10856
12285 and 14595
17296 and 18416

Lua

0.02 of a second in 16 lines of code. The vital trick is to just set m to the sum of n's proper divisors each time. That way you only have to test the reverse, dividing your run time by half the loop limit (ie. 10,000)! <lang lua>function sumDivs (n)

   local sum = 1
   for d = 2, math.sqrt(n) do
       if n % d == 0 then
           sum = sum + d
           sum = sum + n / d
       end
   end
   return sum

end

for n = 2, 20000 do

   m = sumDivs(n)
   if m > n then
       if sumDivs(m) == n then print(n, m) end
   end

end</lang>

Output:

220 284 1184 1210 2620 2924 5020 5564 6232 6368 10744 10856 12285 14595 17296 18416

MAD

<lang MAD> NORMAL MODE IS INTEGER

           DIMENSION DIVS(20000)
           PRINT COMMENT $ AMICABLE PAIRS$
           
         R CALCULATE SUM OF DIVISORS OF N
           INTERNAL FUNCTION(N)
           ENTRY TO DIVSUM.
           DS = 0
           THROUGH SUMMAT, FOR DIVC=1, 1, DIVC.GE.N

SUMMAT WHENEVER N/DIVC*DIVC.E.N, DS = DS+DIVC

           FUNCTION RETURN DS
           END OF FUNCTION
         
         R CALCULATE SUM OF DIVISORS FOR ALL NUMBERS 1..20000
           THROUGH MEMO, FOR I=1, 1, I.GE.20000

MEMO DIVS(I) = DIVSUM.(I)

         R FIND ALL MATCHING PAIRS
           THROUGH CHECK, FOR I=1, 1, I.GE.20000
           THROUGH CHECK, FOR J=1, 1, J.GE.I

CHECK WHENEVER DIVS(I).E.J .AND. DIVS(J).E.I,

         0     PRINT FORMAT AMI,I,J
         
           VECTOR VALUES AMI = $I6,I6*$
           END OF PROGRAM</lang>
Output:
AMICABLE PAIRS
   284   220
  1210  1184
  2924  2620
  5564  5020
  6368  6232
 10856 10744
 14595 12285
 18416 17296


Maple

This example does not show the output mentioned in the task description on this page (or a page linked to from here). Please ensure that it meets all task requirements and remove this message.
Note that phrases in task descriptions such as "print and display" and "print and show" for example, indicate that (reasonable length) output be a part of a language's solution.


<lang Maple> with(NumberTheory): pairs:=[]; for i from 1 to 20000 do for j from i+1 to 20000 do sum1:=SumOfDivisors(j)-j; sum2:=SumOfDivisors(i)-i; if sum1=i and sum2=j and i<>j then pairs:=[op(pairs),[i,j]]; printf("%a", pairs); end if; end do; end do; pairs; </lang>

Mathematica / Wolfram Language

<lang Mathematica>amicableQ[n_] :=

Module[{sum = Total[Most@Divisors@n]},
 sum != n && n == Total[Most@Divisors@sum]]

Grid@Partition[Cases[Range[4, 20000], _?(amicableQ@# &)], 2]</lang>

Output:

220 284 1184 1210 2620 2924 5020 5564 6232 6368 10744 10856 12285 14595 17296 18416

MATLAB

<lang Matlab>function amicable

   tic
   N=2:1:20000; aN=[];
   N(isprime(N))=[]; %erase prime numbers
   I=1;
   a=N(1); b=sum(pd(a));
   while length(N)>1
       if a==b %erase perfect numbers;
           N(N==a)=[]; a=N(1); b=sum(pd(a));
       elseif b<a %the first member of an amicable pair is abundant not defective
           N(N==a)=[]; a=N(1); b=sum(pd(a));
       elseif ~ismember(b,N) %the other member was previously erased
           N(N==a)=[]; a=N(1); b=sum(pd(a));
       else
           c=sum(pd(b));
           if a==c
               aN(I,:)=[I a b]; I=I+1;
               N(N==b)=[];
           else
               if ~ismember(c,N) %the other member was previously erased
                   N(N==b)=[];
               end
           end
           N(N==a)=[]; a=N(1); b=sum(pd(a));
           clear c
       end
   end
   disp(array2table(aN,'Variablenames',{'N','Amicable1','Amicable2'}))
   toc

end

function D=pd(x)

   K=1:ceil(x/2);
   D=K(~(rem(x, K)));

end</lang>

Output:
    N    Amicable1    Amicable2
    _    _________    _________

    1      220          284    
    2     1184         1210    
    3     2620         2924    
    4     5020         5564    
    5     6232         6368    
    6    10744        10856    
    7    12285        14595    
    8    17296        18416    

Elapsed time is 8.958720 seconds.

Nim

Being a novice, I submitted my code to the Nim community for review and received much feedback and advice. They were instrumental in fine-tuning this code for style and readability, I can't thank them enough. <lang Nim> from math import sqrt

const N = 524_000_000.int32

proc sumProperDivisors(someNum: int32, chk4less: bool): int32 =

   result = 1
   let maxPD = sqrt(someNum.float).int32
   let offset = someNum mod 2
   for divNum in countup(2 + offset, maxPD, 1 + offset):
       if someNum mod divNum == 0:
           result += divNum + someNum div divNum
           if chk4less and result >= someNum:
               return 0

for n in countdown(N, 2):

   let m = sumProperDivisors(n, true)
   if m != 0 and n == sumProperDivisors(m, false):
       echo $n, " ", $m

</lang>

Output:
523679536 509379344
511419856 491373104
514823985 475838415
...... ......
..... .....
18416 17296
14595 12285
10856 10744
6368 6232
5564 5020
2924 2620
1210 1184
284 220

Total number of pairs is 442, on my machine the code takes ~389 minutes to run.
Here's a second version that uses a large amount of memory but runs in 2m32seconds. Again, thanks to the Nim community <lang Nim> from math import sqrt

const N = 524_000_000.int32 var x = newSeq[int32](N+1)

for i in 2..sqrt(N.float).int32:

 var p = i*i
 x[p] += i
 var j = i + i
 while (p += i; p <= N):
   j.inc
   x[p] += j

for m in 4..N:

 let n = x[m] + 1
 if n < m and n != 0 and m == x[n] + 1:
     echo n, " ", m

</lang>

Output:
220 284
1184 1210
2620 2924
5020 5564
6232 6368
10744 10856
12285 14595
17296 18416
..... .....
...... ......
426191535 514780497
475838415 514823985
509379344 523679536

Oberon-2

<lang Oberon2> MODULE AmicablePairs; IMPORT

 Out;

CONST

 max = 20000;

VAR

 i,j: INTEGER;
 pd: ARRAY max + 1 OF LONGINT;

PROCEDURE ProperDivisorsSum(n: LONGINT): LONGINT; VAR

  i,sum: LONGINT;

BEGIN

 sum := 0;
 IF n > 1 THEN 
   INC(sum,1);i := 2;
   WHILE (i < n) DO
     IF (n MOD i) = 0 THEN INC(sum,i) END;
     INC(i)
   END
 END;
 RETURN sum

END ProperDivisorsSum;

BEGIN

 FOR i := 0 TO max DO
   pd[i] := ProperDivisorsSum(i)
 END;
 FOR i := 2 TO max DO
   FOR j := i + 1 TO max DO
     IF (pd[i] = j) & (pd[j] = i) THEN
        Out.Char('[');Out.Int(i,0);Out.Char(',');Out.Int(j,0);Out.Char("]");Out.Ln
     END
   END 
 END

END AmicablePairs. </lang>

Output:
[220,284]
[1184,1210]
[2620,2924]
[5020,5564]
[6232,6368]
[10744,10856]
[12285,14595]
[17296,18416]

Oforth

Using properDivs implementation tasks without optimization (calculating proper divisors sum without returning a list for instance) :

<lang Oforth>import: mapping

Integer method: properDivs -- []

  #[ self swap mod 0 == ] self 2 / seq filter ;

amicables

| i j |

  Array new
  20000 loop: i [
     i properDivs sum dup ->j i <= if continue then
     j properDivs sum i <> if continue then
     [ i, j ] over add
     ]
</lang>
Output:
amicables .
[[220, 284], [1184, 1210], [2620, 2924], [5020, 5564], [6232, 6368], [10744, 10856], [12285, 14595], [17296, 18416]]

OCaml

<lang ocaml>let rec isqrt n =

 if n = 1 then 1
 else let _n = isqrt (n - 1) in
   (_n + (n / _n)) / 2

let sum_divs n =

 let sum = ref 1 in
 for d = 2 to isqrt n do
   if (n mod d) = 0 then sum := !sum + (n / d + d);
 done;
 !sum

let () =

 for n = 2 to 20000 do
   let m = sum_divs n in
   if (m > n) then
     if (sum_divs m) = n then Printf.printf "%d %d\n" n m;
 done

</lang>

Output:
220 284
1184 1210
2620 2924
5020 5564
6232 6368
10744 10856
12285 14595
17296 18416

PARI/GP

<lang parigp>for(x=1,20000,my(y=sigma(x)-x); if(y>x && x == sigma(y)-y,print(x" "y)))</lang>

Output:
220 284
1184 1210
2620 2924
5020 5564
6232 6368
10744 10856
12285 14595
17296 18416

Pascal

Direct approach

Works with: Turbo Pascal
Works with: Free Pascal

This version mutates the Sieve of Eratoshenes from striking out factors into summing factors. The Pascal source compiles with Turbo Pascal (7, patched to avoid the zero divide problem for cpu speeds better than ~150MHz) except that the array limit is too large: 15,000 works but does not reach 20,000. The Free Pascal compiler however can handle an array of 20,000 elements. Because the sum of factors of N can exceed N an ad-hoc SumF procedure is provided, thus the search could continue past the table limit, but at a cost in calculation time.

Output is

Chasing Chains of Sums of Factors of Numbers.
Perfect!! 6,
Perfect!! 28,
Amicable! 220,284,
Perfect!! 496,
Amicable! 1184,1210,
Amicable! 2620,2924,
Amicable! 5020,5564,
Amicable! 6232,6368,
Perfect!! 8128,
Amicable! 10744,10856,
Amicable! 12285,14595,
Sociable: 12496,14288,15472,14536,14264,
Sociable: 14316,19116,31704,47616,83328,177792,295488,629072,589786,294896,358336,418904,366556,274924,275444,243760,376736,381028,285778,152990,122410,97946,48976,45946,22976,22744,19916,17716,
Amicable! 17296,18416,

Source file:<lang pascal>

Program SumOfFactors; uses crt; {Perpetrated by R.N.McLean, December MCMXCV}

//{$DEFINE ShowOverflow} {$IFDEF FPC}

 {$MODE DELPHI}//tested with lots = 524*1000*1000 takes 75 secs generating KnownSum

{$ENDIF}

 var outf: text;
 const Limit = 2147483647;
 const lots = 20000;       {This should be much bigger, but problems apply.}
 var KnownSum: array[1..lots] of longint;
 Function SumF(N: Longint): Longint;
  var f,f2,s,ulp: longint;
  Begin
   if n <= lots then SumF:=KnownSum[N] {Hurrah!}
    else
     begin      {This is really crude...}
      s:=1;     {1 is always a factor, but N is not.}
      f:=2;
      f2:=f*f;
      while f2 < N do
       begin
        if N mod f = 0 then
         begin  {We have a divisor, and its friend.}
          ulp:=f + (N div f);
          if s > Limit - ulp then begin SumF:=-666; exit; end;
          s:=s + ulp;
         end;
        f:=f + 1;
        f2:=f*f;
       end;
       if f2 = N then {A perfect square gets its factor in once only.}
        if s <= Limit - f then s:=s + f
         else begin SumF:=-667; exit; end;
      SumF:=s;
     end;
  End;
 var i,j,l,sf,fs: LongInt;
 const enuff = 666; {Only so much sociability.}
 var trail: array[0..enuff] of longint;
 BEGIN
  ClrScr;
  WriteLn('Chasing Chains of Sums of Factors of Numbers.');
  for i:=1 to lots do KnownSum[i]:=1; {Sigh. KnownSum:=1;}

{start summing every divisor }

  for i:=2 to lots do
   begin
    j:=i + i;
    While j <= lots do    {Sigh. For j:=i + i:Lots:i do KnownSum[j]:=KnownSum[j] + i;}
    begin
      KnownSum[j]:=KnownSum[j] + i;
      j:=j + i;
     end;
   end; 
{Enough preparation.}
  Assign(outf,'Factors.txt'); ReWrite(Outf);
  WriteLn(Outf,'Chasing Chains of Sums of Factors of Numbers.');
  for i:=2 to lots do    {Search.}
   begin
    l:=0;
    sf:=SumF(i);
    while (sf > i) and (l < enuff) do
     begin
      l:=l + 1;
      trail[l]:=sf;
      sf:=SumF(sf);
     end;
    if l >= enuff then writeln('Rope ran out! ',i);

{$IFDEF ShowOverflow}

    if sf < 0 then writeln('Overflow with ',i);

{$ENDIF}

    if i = sf then      {A loop?}
     begin              {Yes. Reveal its members.}
      trail[0]:=i;      {The first.}
      if l = 0 then write('Perfect!! ')
       else if l = 1 then write('Amicable! ')
        else write('Sociable: ');
      for j:=0 to l do Write(Trail[j],',');
      WriteLn;
      if l = 0 then write(outf,'Perfect!! ')
       else if l = 1 then write(outf,'Amicable! ')
        else write(outf,'Sociable: ');
      for j:=0 to l do write(outf,Trail[j],',');
      WriteLn(outf);
     end;
   end;
  Close (outf);
 END.</lang>

More expansive.

a "normal" Version. Nearly fast as perl using nTheory. <lang pascal>program AmicablePairs; {$IFDEF FPC}

  {$MODE DELPHI}
  {$H+}

{$ELSE}

 {$APPTYPE CONSOLE}

{$ENDIF} uses

 sysutils;

const

 MAX = 20000;

//MAX = 20*1000*1000; type

 tValue = LongWord;
 tpValue = ^tValue;
 tPower = array[0..31] of tValue;
 tIndex = record
            idxI,
            idxS : Uint64;
          end;

var

 Indices      : array[0..511] of tIndex;
 //primes up to 65536 enough until 2^32
 primes       : array[0..6542] of tValue;

procedure InitPrimes; // sieve of erathosthenes without multiples of 2 type

 tSieve = array[0..(65536-1) div 2] of ansichar;

var

 ESieve : ^tSieve;
 idx,i,j,p : LongINt;

Begin

 new(ESieve);
 fillchar(ESieve^[0],SizeOF(tSieve),#1);
 primes[0] := 2;
 idx := 1;
 //sieving
 j := 1;
 p := 2*j+1;
 repeat
   if Esieve^[j] = #1 then
   begin
     i := (2*j+2)*j;// i := (sqr(p) -1) div 2;
     if i > High(tSieve) then
       BREAK;
     repeat
       ESIeve^[i] := #0;
       inc(i,p);
     until i > High(tSieve);
   end;
   inc(j);
   inc(p,2);
 until j >High(tSieve);
 //collecting
 For i := 1 to High(tSieve) do
   IF Esieve^[i] = #1 then
   Begin
     primes[idx] := 2*i+1;
     inc(idx);
     IF idx>High(primes) then
       BREAK;
   end;
 dispose(Esieve);

end;

procedure Su_append(n,factor:tValue;var su:string); var

 q,p : tValue;

begin

 p := 0;
 repeat
   q := n div factor;
   IF q*factor<>n then
     Break;
   inc(p);
   n := q;
 until false;
 IF p > 0 then
   IF p= 1 then
     su:= su+IntToStr(factor)+'*'
   else
     su:= su+IntToStr(factor)+'^'+IntToStr(p)+'*';

end;

procedure ProperDivs(n: Uint64); //output of prime factorization var

 su : string;
 primNo : tValue;
 p:tValue;

begin

 str(n:8,su);
 su:= su +' [';
 primNo := 0;
 p := primes[0];
 repeat
   Su_Append(n,p,su);
   inc(primNo);
   p := primes[primNo];
 until (p=0) OR (p*p >= n);
 p := n;
 Su_Append(n,p,su);
 su[length(su)] := ']';
 writeln(su);

end;

procedure AmPairOutput(cnt:tValue); var

 i : tValue;
 r_max,r_min,r : double;

begin

 r_max := 1.0;
 r_min := 16.0;
 For i := 0 to cnt-1 do
   with Indices[i] do
   begin
     r := IdxS/IDxI;
     writeln(i+1:4,IdxI:16,IDxS:16,' ratio ',r:10:7);
     IF r < 1 then
     begin
       writeln(i);
       readln;
       halt;
     end;
     if r_max < r then
       r_max := r
     else
       if r_min > r then
         r_min := r;
   IF cnt < 20 then
     begin
       ProperDivs(IdxI);
       ProperDivs(IdxS);
     end;
   end;
 writeln(' min ratio ',r_min:12:10);  writeln(' max ratio ',r_max:12:10);

end;

procedure SumOFProperDiv(n: tValue;var SumOfProperDivs:tValue); // calculated by prime factorization var

 i,q, primNo, Prime,pot : tValue;
 SumOfDivs: tValue;

begin

 i := N;
 SumOfDivs := 1;
 primNo := 0;
 Prime := Primes[0];
 q := i DIV Prime;
 repeat
   if q*Prime = i then
   Begin
     pot := 1;
     repeat
       i := q;
       q := i div Prime;
       Pot := Pot * Prime+1;
     until q*Prime <> i;
     SumOfDivs := SumOfDivs * pot;
   end;
   Inc(primNo);
   Prime := Primes[primNo];
   q := i DIV Prime;
   {check if i already prime}
   if Prime > q then
   begin
     prime := i;
     q := 1;
   end;
 until i = 1;
 SumOfProperDivs := SumOfDivs - N;

end;

function Check:tValue; const

 //going backwards
 DIV23 : array[0..5] of byte =
          //== 5,4,3,2,1,0
              (1,0,0,0,1,0);

var

 i,s,k,n : tValue;
 idx : nativeInt;

begin

 n := 0;
 idx := 3;
 For i := 2 to MAX do
 begin
   //must be divisble by 2 or 3 ( n < High(tValue) < 1e14 )
   IF DIV23[idx] = 0 then
   begin
     SumOFProperDiv(i,s);
     //only 24.7...%
     IF s>i then
     Begin
       SumOFProperDiv(s,k);
       IF k = i then
       begin
         With indices[n] do
         begin
           idxI := i;
           idxS := s;
         end;
         inc(n);
       end;
     end;
   end;
   dec(idx);
   IF idx < 0 then
     idx := high(DIV23);
 end;
 result := n;

end;

var

 T2,T1: TDatetime;
 APcnt: tValue;

begin

 InitPrimes;
 T1:= time;
 APCnt:= Check;
 T2:= time;
 AmPairOutput(APCnt);
 writeln('Time to find amicable pairs ',FormatDateTime('HH:NN:SS.ZZZ' ,T2-T1));
 {$IFNDEF UNIX} readln;{$ENDIF}

end.</lang> Output

   1             220             284 ratio  1.2909091
     220 [2^2*5*11*220]
     284 [2^2*284]
   2            1184            1210 ratio  1.0219595
    1184 [2^5*1184]
    1210 [2*5*11^2*1210]
   3            2620            2924 ratio  1.1160305
    2620 [2^2*5*2620]
    2924 [2^2*17*43*2924]
   4            5020            5564 ratio  1.1083665
    5020 [2^2*5*5020]
    5564 [2^2*13*5564]
   5            6232            6368 ratio  1.0218228
    6232 [2^3*19*41*6232]
    6368 [2^5*6368]
   6           10744           10856 ratio  1.0104244
   10744 [2^3*17*79*10744]
   10856 [2^3*23*59*10856]
   7           12285           14595 ratio  1.1880342
   12285 [3^3*5*7*13*12285]
   14595 [3*5*7*14595]
   8           17296           18416 ratio  1.0647549
   17296 [2^4*23*47*17296]
   18416 [2^4*18416]

Alternative

about 25-times faster. This will not output the amicable number unless both! numbers are under the given limit.

So there will be differences to "Table of n, a(n) for n=1..39374" https://oeis.org/A002025/b002025.txt Up to 524'000'000 the pairs found are only correct by number up to no. 437 460122410 and only 442 out of 455 are found, because some pairs exceed the limit. The limits of the ratio between the numbers of the amicable pair up to 1E14 are, based on b002025.txt:

No.    lower            upper         
31447  52326552030976  52326637800704 ratio  1.0000016 
52326552030976 [2^8*563*6079*59723]
52326637800704 [2^8*797*1439*178223]

38336  92371445691525 154378742017851 ratio  1.6712821
 92371445691525 [3^2*5^2*7^2*11*13^2*23*29^2*233]
154378742017851 [3^2*13^2*53*337*5682671]


The distance check is being corrected, the lower number is now not limited. The used method is not useful for very high limits.

n = p[1]^a[1]*p[2]^a[2]*...p[l]^a[l]

sum of divisors(n) = s(n) = (p[1]^(a[1]+1) -1) / (p[1] -1) * ... * (p[l]^(a[l]+1) -1) / (p[l] -1) with

p[k]^(a[k]+1) -1) / (p[k] -1) = sum (i= [1..a[k]])(p[k]^i)

Using "Sieve of Erathosthenes"-style

<lang pascal>program AmicPair; {find amicable pairs in a limited region 2..MAX beware that >both< numbers must be smaller than MAX there are 455 amicable pairs up to 524*1000*1000 correct up to

  1. 437 460122410

} //optimized for freepascal 2.6.4 32-Bit {$IFDEF FPC}

  {$MODE DELPHI}
  {$OPTIMIZATION ON,peephole,cse,asmcse,regvar}
  {$CODEALIGN loop=1,proc=8}

{$ELSE}

 {$APPTYPE CONSOLE}

{$ENDIF}

uses

 sysutils;

type

 tValue = LongWord;
 tpValue = ^tValue;
 tDivSum = array[0..0] of tValue;// evil, but dynamic arrays are slower
 tpDivSum = ^tDivSum;
 tPower = array[0..31] of tValue;
 tIndex = record
            idxI,
            idxS : tValue;
          end;

var

 power,
 PowerFac     : tPower;
 ds           : array of tValue;
 Indices      : array[0..511] of tIndex;
 DivSumField  : tpDivSum;
 MAX : tValue;

procedure Init; var

 i : LongInt;

begin

 DivSumField[0]:= 0;
 For i := 1 to MAX do
   DivSumField[i]:= 1;

end;

procedure ProperDivs(n: tValue); //Only for output, normally a factorication would do var

 su,so : string;
 i,q : tValue;

begin

 su:= '1';
 so:= ;
 i := 2;
 while i*i <= n do
 begin
   q := n div i;
   IF q*i -n = 0 then
   begin
     su:= su+','+IntToStr(i);
     IF q <> i then
       so:= ','+IntToStr(q)+so;
   end;
   inc(i);
 end;
 writeln('  [',su+so,']');

end;

procedure AmPairOutput(cnt:tValue); var

 i : tValue;
 r : double;

begin

 r := 1.0;
 For i := 0 to cnt-1 do
 with Indices[i] do
 begin
   writeln(i+1:4,IdxI:12,IDxS:12,' ratio ',IdxS/IDxI:10:7);
   if r < IdxS/IDxI then
     r := IdxS/IDxI;
     IF cnt < 20 then
     begin
       ProperDivs(IdxI);
       ProperDivs(IdxS);
     end;
 end;
 writeln(' max ratio ',r:10:4);

end;

function Check:tValue; var

 i,s,n : tValue;

begin

 n := 0;
 For i := 1 to MAX do
 begin
   //s = sum of proper divs (I)  == sum of divs (I) - I
   s := DivSumField^[i];
   IF (s <=MAX) AND (s>i) AND (DivSumField^[s]= i)then
   begin
     With indices[n] do
     begin
       idxI := i;
       idxS := s;
     end;
     inc(n);
   end;
 end;
 result := n;

end;

Procedure CalcPotfactor(prim:tValue); //PowerFac[k] = (prim^(k+1)-1)/(prim-1) == Sum (i=0..k) prim^i var

 k: tValue;
 Pot,       //== prim^k
 PFac : Int64;

begin

 Pot := prim;
 PFac := 1;
 For k := 0 to High(PowerFac) do
 begin
   PFac := PFac+Pot;
   IF (POT > MAX) then
     BREAK;
   PowerFac[k] := PFac;
   Pot := Pot*prim;
 end;

end;

procedure InitPW(prim:tValue); begin

 fillchar(power,SizeOf(power),#0);
 CalcPotfactor(prim);

end;

function NextPotCnt(p: tValue):tValue; //return the first power <> 0 //power == n to base prim var

 i : tValue;

begin

 result := 0;
 repeat
   i := power[result];
   Inc(i);
   IF i < p then
     BREAK
   else
   begin
     i := 0;
     power[result]  := 0;
     inc(result);
   end;
 until false;
 power[result] := i;

end;

procedure Sieve(prim: tValue); var

 actNumber,idx : tValue;

begin

 //sieve with "small" primes
 while prim*prim <= MAX do
 begin
   InitPW(prim);
   Begin
     //actNumber = actual number = n*prim
     actNumber := prim;
     idx := prim;
     while actNumber <= MAX do
     begin
       dec(idx);
       IF idx > 0 then
         DivSumField^[actNumber] *= PowerFac[0]
       else
       Begin
         DivSumField^[actNumber] *= PowerFac[NextPotCnt(prim)+1];
         idx := Prim;
       end;
       inc(actNumber,prim);
     end;
   end;
   //next prime
   repeat
     inc(prim);
   until DivSumField^[prim]= 1;//(DivSumField[prim] = 1);
 end;
 //sieve with "big" primes, only one factor is possible
 while 2*prim <= MAX do
 begin
   InitPW(prim);
   Begin
     actNumber := prim;
     idx := PowerFac[0];
     while actNumber <= MAX do
     begin
       DivSumField^[actNumber] *= idx;
       inc(actNumber,prim);
     end;
   end;
   repeat
     inc(prim);
   until DivSumField^[prim]= 1;
 end;
 For idx := 2 to MAX do
   dec(DivSumField^[idx],idx);

end;

var

 T2,T1,T0: TDatetime;
 APcnt: tValue;
 i: NativeInt;

begin

 MAX := 20000;
 IF  ParamCount > 0 then
   MAX := StrToInt(ParamStr(1));
 setlength(ds,MAX);
 DivSumField := @ds[0];
 T0:= time;
 For i := 1 to 1 do
 Begin
   Init;
   Sieve(2);
 end;
 T1:= time;
 APCnt := Check;
 T2:= time;
 AmPairOutput(APCnt);
 writeln(APCnt,' amicable pairs til ',MAX);
 writeln('Time to calc sum of divs    ',FormatDateTime('HH:NN:SS.ZZZ' ,T1-T0));
 writeln('Time to find amicable pairs ',FormatDateTime('HH:NN:SS.ZZZ' ,T2-T1));
 setlength(ds,0);
 {$IFNDEF UNIX}
   readln;
 {$ENDIF}

end.</lang> output

       220       284
  [1,2,4,5,10,11,20,22,44,55,110]
  [1,2,4,71,142]

      1184      1210
  [1,2,4,8,16,32,37,74,148,296,592]
  [1,2,5,10,11,22,55,110,121,242,605]

      2620      2924
  [1,2,4,5,10,20,131,262,524,655,1310]
  [1,2,4,17,34,43,68,86,172,731,1462]

      5020      5564
  [1,2,4,5,10,20,251,502,1004,1255,2510]
  [1,2,4,13,26,52,107,214,428,1391,2782]

      6232      6368
  [1,2,4,8,19,38,41,76,82,152,164,328,779,1558,3116]
  [1,2,4,8,16,32,199,398,796,1592,3184]

     10744     10856
  [1,2,4,8,17,34,68,79,136,158,316,632,1343,2686,5372]
  [1,2,4,8,23,46,59,92,118,184,236,472,1357,2714,5428]

     12285     14595
  [1,3,5,7,9,13,15,21,27,35,39,45,63,65,91,105,117,135,189,195,273,315,351,455,585,819,945,1365,1755,2457,4095]
  [1,3,5,7,15,21,35,105,139,417,695,973,2085,2919,4865]

     17296     18416
  [1,2,4,8,16,23,46,47,92,94,184,188,368,376,752,1081,2162,4324,8648]
  [1,2,4,8,16,1151,2302,4604,9208]

8 amicable numbers up to 20000
00:00:00.000

.... Test with 524*1000*1000 Linux32, FPC 3.0.1, i4330 3.5 Ghz //Win32 swaps first to allocate 2 GB )
 440   475838415   514823985 ratio  1.0819303
 441   491373104   511419856 ratio  1.0407974
 442   509379344   523679536 ratio  1.0280738
 max ratio     1.3537
442 amicable pairs til 524000000
Time to calc sum of divs    00:00:12.601
Time to find amicable pairs 00:00:02.557

Perl

Not particularly clever, but instant for this example, and does up to 20 million in 11 seconds.

Library: ntheory

<lang perl>use ntheory qw/divisor_sum/; for my $x (1..20000) {

 my $y = divisor_sum($x)-$x;
 say "$x $y" if $y > $x && $x == divisor_sum($y)-$y;

}</lang>

Output:
220 284
1184 1210
2620 2924
5020 5564
6232 6368
10744 10856
12285 14595
17296 18416

Phix

integer n
for m=1 to 20000 do
    n = sum(factors(m,-1))
    if m<n and m=sum(factors(n,-1)) then ?{m,n} end if
end for
Output:
{220,284}
{1184,1210}
{2620,2924}
{5020,5564}
{6232,6368}
{10744,10856}
{12285,14595}
{17296,18416}

Phixmonti

<lang Phixmonti>def sumDivs

   var n
   1 var sum n sqrt
   2 swap 2 tolist
   for
       var d
       n d mod not if
           sum d + n d / + var sum
       endif
   endfor
   sum

enddef

2 20000 2 tolist for

   var i
   i sumDivs var m
   m i > if
       m sumDivs i == if i print "\t" print m print nl endif
   endif

endfor

nl msec print " s" print</lang>

PHP

<lang php><?php

function sumDivs ($n) {

   $sum = 1;
   for ($d = 2; $d <= sqrt($n); $d++) {
       if ($n % $d == 0) $sum += $n / $d + $d;
   }
   return $sum;

}

for ($n = 2; $n < 20000; $n++) {

   $m = sumDivs($n);
   if ($m > $n) {
       if (sumDivs($m) == $n) echo $n." ".$m."
"; }

}

?></lang>

Output:
220 284
1184 1210
2620 2924
5020 5564
6232 6368
10744 10856
12285 14595
17296 18416

Picat

Different approaches to solve this task:

 * foreach loop (two variants)
 * list comprehension
 * while loop. 

Also, the calculation of the sum of divisors is tabled (the table is cleared between each run). <lang Picat>go =>

 N = 20000,
 println(amicable1),
 time(amicable1(N)),
 % initialize_table is needed to clear the table cache
 % of sum_divisors/1 between each run.
 initialize_table,
 println(amicable2),
 time(amicable2(N)),
 initialize_table,
 println(amicable3),
 time(amicable3(N)),
 initialize_table,
 println(amicable4),
 time(amicable4(N)),
 
 nl.


% Foreach loop and a map (hash table) amicable1(N) =>

 Pairs = new_map(),
 foreach(A in 1..N) 
    B = sum_divisors(A),
    C = sum_divisors(B),
    if A != B, A == C then
       Pairs.put([A,B].sort(),1)
    end
 end,
 println(Pairs.keys().sort()).


% List comprehension amicable2(N) =>

 println([[A,B].sort() : A in 1..N, 
          B = sum_divisors(A), 
          C = sum_divisors(B),
          A != B, A == C].remove_dups()).


% While loop amicable3(N) =>

 A = 1,
 while(A <= N)
    B = sum_divisors(A),
    if A < B, A == sum_divisors(B) then
      print([A,B]), print(" ")
    end,
    A := A + 1
 end,
 nl.

% Foreach loop, everything in the condition amicable4(N) =>

 foreach(A in 1..N, B = sum_divisors(A), A < B, A == sum_divisors(B))
    print([A,B]), print(" ")
 end,
 nl.

% % Sum of divisors of N % table sum_divisors(N) = Sum =>

 sum_divisors(2,N,1,Sum).

% Base case: exceeding the limit sum_divisors(I,N,Sum0,Sum), I > floor(sqrt(N)) =>

  Sum = Sum0.

% I is a divisor of N sum_divisors(I,N,Sum0,Sum), N mod I == 0 =>

 Sum1 = Sum0 + I,
 (I != N div I -> 
   Sum2 = Sum1 + N div I 
   ; 
   Sum2 = Sum1
 ),
 sum_divisors(I+1,N,Sum2,Sum).

% I is not a divisor of N. sum_divisors(I,N,Sum0,Sum) =>

 sum_divisors(I+1,N,Sum0,Sum).

</lang>

Output:
amicable1
[[220,284],[1184,1210],[2620,2924],[5020,5564],[6232,6368],[10744,10856],[12285,14595],[17296,18416]]
CPU time 0.114 seconds.

amicable2
[[220,284],[1184,1210],[2620,2924],[5020,5564],[6232,6368],[10744,10856],[12285,14595],[17296,18416]]
CPU time 0.106 seconds.

amicable3
[220,284] [1184,1210] [2620,2924] [5020,5564] [6232,6368] [10744,10856] [12285,14595] [17296,18416] 
CPU time 0.111 seconds.

amicable4
[220,284] [1184,1210] [2620,2924] [5020,5564] [6232,6368] [10744,10856] [12285,14595] [17296,18416] 
CPU time 0.107 seconds.

PicoLisp

<lang PicoLisp>(de accud (Var Key)

  (if (assoc Key (val Var))
     (con @ (inc (cdr @)))
     (push Var (cons Key 1)) )
  Key )

(de **sum (L)

  (let S 1
     (for I (cdr L)
        (inc 'S (** (car L) I)) )
     S ) )

(de factor-sum (N)

  (if (=1 N)
     0
     (let
        (R NIL
           D 2
           L (1 2 2 . (4 2 4 2 4 6 2 6 .))
           M (sqrt N)
           N1 N
           S 1 )
        (while (>= M D)
           (if (=0 (% N1 D))
              (setq M
                 (sqrt (setq N1 (/ N1 (accud 'R D)))) )
              (inc 'D (pop 'L)) ) )
        (accud 'R N1)
        (for I R
           (setq S (* S (**sum I))) )
        (- S N) ) ) )

(bench

  (for I 20000
     (let X (factor-sum I)
        (and
           (< I X)
           (= I (factor-sum X))
           (println I X) ) ) ) )</lang>
Output:
220 284
1184 1210
2620 2924
5020 5564
6232 6368
10744 10856
12285 14595
17296 18416
0.101 sec

PL/I

Translation of: REXX

<lang pli>*process source xref;

ami: Proc Options(main);
p9a=time();
Dcl (p9a,p9b,p9c) Pic'(9)9';
Dcl sumpd(20000) Bin Fixed(31);
Dcl pd(300) Bin Fixed(31);
Dcl npd     Bin Fixed(31);
Dcl (x,y)   Bin Fixed(31);
Do x=1 To 20000;
  Call proper_divisors(x,pd,npd);
  sumpd(x)=sum(pd,npd);
  End;
p9b=time();
Put Edit('sum(pd) computed in',(p9b-p9a)/1000,' seconds elapsed')
        (Skip,col(7),a,f(6,3),a);
Do x=1 To 20000;
  Do y=x+1 To 20000;
    If y=sumpd(x) &
       x=sumpd(y) Then
      Put Edit(x,y,' found after ',elapsed(),' seconds')
              (Skip,2(f(6)),a,f(6,3),a);
    End;
  End;
Put Edit(elapsed(),' seconds total search time')(Skip,f(6,3),a);
proper_divisors: Proc(n,pd,npd);
Dcl (n,pd(300),npd) Bin Fixed(31);
Dcl (d,delta)       Bin Fixed(31);
npd=0;
If n>1 Then Do;
  If mod(n,2)=1 Then  /* odd number  */
    delta=2;
  Else                /* even number */
    delta=1;
  Do d=1 To n/2 By delta;
    If mod(n,d)=0 Then Do;
      npd+=1;
      pd(npd)=d;
      End;
    End;
  End;
End;
sum: Proc(pd,npd) Returns(Bin Fixed(31));
Dcl (pd(300),npd) Bin Fixed(31);
Dcl sum Bin Fixed(31) Init(0);
Dcl i   Bin Fixed(31);
Do i=1 To npd;
  sum+=pd(i);
  End;
Return(sum);
End;
elapsed: Proc Returns(Dec Fixed(6,3));
p9c=time();
Return((p9c-p9b)/1000);
End;
End;</lang>
Output:
      sum(pd) computed in 0.510 seconds elapsed
   220   284 found after  0.010 seconds
  1184  1210 found after  0.060 seconds
  2620  2924 found after  0.110 seconds
  5020  5564 found after  0.210 seconds
  6232  6368 found after  0.260 seconds
 10744 10856 found after  2.110 seconds
 12285 14595 found after  2.150 seconds
 17296 18416 found after  2.240 seconds
 2.250 seconds total search time

PL/I-80

Rather than populating an array with the sum of the proper divisors and then searching, the approach here performs an direct test, saving memory, and at a minimal penalty in execution speed, even though about 25% more calls are made to sumf() than would be required simply to initialize an array. <lang PL/I> amicable: procedure options (main);

   %replace 
     search_limit by 20000;
   dcl (a, b, found) fixed bin;
   put skip list ('Searching for amicable pairs up to ');
   put edit (search_limit) (f(5));
   found = 0;
   do a = 2 to search_limit;
     b = sumf(a);
     if (b > a) then
       do;
         if (sumf(b) = a) then
           do;
             found = found + 1;
             put skip edit (a,b) (f(7));
           end;
       end;
   end;
   put skip list (found, ' pairs were found');
   stop;


/* return sum of the proper divisors of n */ sumf:

   procedure(n) returns (fixed bin);
   
   dcl (n, sum, f1, f2) fixed bin;
   sum = 1;  /* 1 is a proper divisor of every number */
   f1 = 2;
   do while ((f1 * f1) < n);
     if mod(n, f1) = 0 then
       do;
         sum = sum + f1;
         f2 = n / f1;
         /* don't double count identical co-factors! */
         if f2 > f1 then sum = sum + f2;
       end;
     f1 = f1 + 1;
   end;
   return (sum);

end sumf;

end amicable; </lang>

Output:
Searching for amicable pairs up to 20000
    220    284
   1184   1210
   2620   2924
   5020   5564
   6232   6368
  10744  10856
  12285  14595
  17296  18416
        8  pairs were found

PL/M

<lang plm>100H: /* CP/M CALLS */ BDOS: PROCEDURE (FN, ARG); DECLARE FN BYTE, ARG ADDRESS; GO TO 5; END BDOS; EXIT: PROCEDURE; CALL BDOS(0,0); END EXIT; PRINT: PROCEDURE (S); DECLARE S ADDRESS; CALL BDOS(9,S); END PRINT;

/* PRINT A NUMBER */ PRINT$NUMBER: PROCEDURE (N);

   DECLARE S (6) BYTE INITIAL ('.....$');
   DECLARE (N, P) ADDRESS, C BASED P BYTE;
   P = .S(5);

DIGIT:

   P = P - 1;
   C = N MOD 10 + '0';
   N = N / 10;
   IF N > 0 THEN GO TO DIGIT;
   CALL PRINT(P);

END PRINT$NUMBER;

/* CALCULATE SUMS OF PROPER DIVISORS */ DECLARE DIV$SUM (20$001) ADDRESS; DECLARE (I, J) ADDRESS;

DO I=2 TO 20$000; DIV$SUM(I) = 1; END; DO I=2 TO 10$000;

   DO J = I*2 TO 20$000 BY I;
       DIV$SUM(J) = DIV$SUM(J) + I;
   END;

END;

/* TEST EACH PAIR */ DO I=2 TO 20$000;

   DO J=I+1 TO 20$000;
       IF DIV$SUM(I)=J AND DIV$SUM(J)=I THEN DO;
           CALL PRINT$NUMBER(I);
           CALL PRINT(.', $');
           CALL PRINT$NUMBER(J);
           CALL PRINT(.(13,10,'$'));
       END;
   END;

END;

CALL EXIT; EOF</lang>

Output:
220, 284
1184, 1210
2620, 2924
5020, 5564
6232, 6368
10744, 10856
12285, 14595
17296, 18416

PowerShell

Works with: PowerShell version 2

<lang PowerShell> function Get-ProperDivisorSum ( [int]$N )

   {
   $Sum = 1
   If ( $N -gt 3 )
       {
       $SqrtN = [math]::Sqrt( $N )
       ForEach ( $Divisor1 in 2..$SqrtN )
           {
           $Divisor2 = $N / $Divisor1
           If ( $Divisor2 -is [int] ) { $Sum += $Divisor1 + $Divisor2 }
           }
       If ( $SqrtN -is [int] ) { $Sum -= $SqrtN }
       }
   return $Sum
   }

function Get-AmicablePairs ( $N = 300 )

   {
   ForEach ( $X in 1..$N )
       {
       $Sum = Get-ProperDivisorSum $X
       If ( $Sum -gt $X -and $X -eq ( Get-ProperDivisorSum $Sum ) )
           {
           "$X, $Sum"
           }
       }
   }

Get-AmicablePairs 20000 </lang>

Output:
220, 284
1184, 1210
2620, 2924
5020, 5564
6232, 6368
10744, 10856
12285, 14595
17296, 18416

Prolog

Works with: SWI-Prolog 7

With some guidance from other solutions here:

<lang prolog>divisor(N, Divisor) :-

   UpperBound is round(sqrt(N)),
   between(1, UpperBound, D),
   0 is N mod D,
   (
       Divisor = D
   ;
       LargerDivisor is N/D,
       LargerDivisor =\= D,
       Divisor = LargerDivisor
   ).

proper_divisor(N, D) :-

   divisor(N, D),
   D =\= N.

assoc_num_divsSum_in_range(Low, High, Assoc) :-

   findall( Num-DivSum,
            ( between(Low, High, Num),
              aggregate_all( sum(D),
                             proper_divisor(Num, D),
                             DivSum )),
            Pairs ),
   list_to_assoc(Pairs, Assoc).

get_amicable_pair(Assoc, M-N) :-

   gen_assoc(M, Assoc, N),
   M < N,
   get_assoc(N, Assoc, M).

amicable_pairs_under_20000(Pairs) :-

   assoc_num_divsSum_in_range(1,20000, Assoc),
   findall(P, get_amicable_pair(Assoc, P), Pairs).</lang>

Output:

<lang prolog>?- amicable_pairs_under_20000(R). R = [220-284, 1184-1210, 2620-2924, 5020-5564, 6232-6368, 10744-10856, 12285-14595, 17296-18416].</lang>

PureBasic

<lang PureBasic> EnableExplicit

Procedure.i SumProperDivisors(Number)

 If Number < 2 : ProcedureReturn 0 : EndIf
 Protected i, sum = 0
 For i = 1 To Number / 2
   If Number % i = 0
     sum + i
   EndIf
 Next
 ProcedureReturn sum

EndProcedure

Define n, f Define Dim sum(19999)

If OpenConsole()

 For n = 1 To 19999
   sum(n) = SumProperDivisors(n)
 Next
 PrintN("The pairs of amicable numbers below 20,000 are : ")
 PrintN("")
 For n = 1 To 19998
   f = sum(n)
   If f <= n Or f < 1 Or f > 19999 : Continue : EndIf
   If f = sum(n) And n = sum(f)
     PrintN(RSet(Str(n),5) + " and " + RSet(Str(sum(n)), 5))
   EndIf
 Next
 PrintN("")
 PrintN("Press any key to close the console")
 Repeat: Delay(10) : Until Inkey() <> ""
 CloseConsole()

EndIf </lang>

Output:
The pairs of amicable numbers below 20,000 are :

  220 and   284
 1184 and  1210
 2620 and  2924
 5020 and  5564
 6232 and  6368
10744 and 10856
12285 and 14595
17296 and 18416

Python

Importing Proper divisors from prime factors: <lang python>from proper_divisors import proper_divs

def amicable(rangemax=20000):

   n2divsum = {n: sum(proper_divs(n)) for n in range(1, rangemax + 1)}
   for num, divsum in n2divsum.items():
       if num < divsum and divsum <= rangemax and n2divsum[divsum] == num:
           yield num, divsum

if __name__ == '__main__':

   for num, divsum in amicable():
       print('Amicable pair: %i and %i With proper divisors:\n    %r\n    %r'
             % (num, divsum, sorted(proper_divs(num)), sorted(proper_divs(divsum))))</lang>
Output:
Amicable pair: 220 and 284 With proper divisors:
    [1, 2, 4, 5, 10, 11, 20, 22, 44, 55, 110]
    [1, 2, 4, 71, 142]
Amicable pair: 1184 and 1210 With proper divisors:
    [1, 2, 4, 8, 16, 32, 37, 74, 148, 296, 592]
    [1, 2, 5, 10, 11, 22, 55, 110, 121, 242, 605]
Amicable pair: 2620 and 2924 With proper divisors:
    [1, 2, 4, 5, 10, 20, 131, 262, 524, 655, 1310]
    [1, 2, 4, 17, 34, 43, 68, 86, 172, 731, 1462]
Amicable pair: 5020 and 5564 With proper divisors:
    [1, 2, 4, 5, 10, 20, 251, 502, 1004, 1255, 2510]
    [1, 2, 4, 13, 26, 52, 107, 214, 428, 1391, 2782]
Amicable pair: 6232 and 6368 With proper divisors:
    [1, 2, 4, 8, 19, 38, 41, 76, 82, 152, 164, 328, 779, 1558, 3116]
    [1, 2, 4, 8, 16, 32, 199, 398, 796, 1592, 3184]
Amicable pair: 10744 and 10856 With proper divisors:
    [1, 2, 4, 8, 17, 34, 68, 79, 136, 158, 316, 632, 1343, 2686, 5372]
    [1, 2, 4, 8, 23, 46, 59, 92, 118, 184, 236, 472, 1357, 2714, 5428]
Amicable pair: 12285 and 14595 With proper divisors:
    [1, 3, 5, 7, 9, 13, 15, 21, 27, 35, 39, 45, 63, 65, 91, 105, 117, 135, 189, 195, 273, 315, 351, 455, 585, 819, 945, 1365, 1755, 2457, 4095]
    [1, 3, 5, 7, 15, 21, 35, 105, 139, 417, 695, 973, 2085, 2919, 4865]
Amicable pair: 17296 and 18416 With proper divisors:
    [1, 2, 4, 8, 16, 23, 46, 47, 92, 94, 184, 188, 368, 376, 752, 1081, 2162, 4324, 8648]
    [1, 2, 4, 8, 16, 1151, 2302, 4604, 9208]


Or, supplying our own properDivisors function, and defining the harvest in terms of a generic concatMap:

<lang python>Amicable pairs

from itertools import chain from math import sqrt


  1. amicablePairsUpTo :: Int -> [(Int, Int)]

def amicablePairsUpTo(n):

   List of all amicable pairs
      of integers below n.
   
   sigma = compose(sum)(properDivisors)
   def amicable(x):
       y = sigma(x)
       return [(x, y)] if (x < y and x == sigma(y)) else []
   return concatMap(amicable)(
       enumFromTo(1)(n)
   )


  1. TEST ----------------------------------------------------
  2. main :: IO ()

def main():

   Amicable pairs of integers up to 20000
   for x in amicablePairsUpTo(20000):
       print(x)


  1. GENERIC -------------------------------------------------
  1. compose (<<<) :: (b -> c) -> (a -> b) -> a -> c

def compose(g):

   Right to left function composition.
   return lambda f: lambda x: g(f(x))


  1. concatMap :: (a -> [b]) -> [a] -> [b]

def concatMap(f):

   A concatenated list or string over which a function f
      has been mapped.
      The list monad can be derived by using an (a -> [b])
      function which wraps its output in a list (using an
      empty list to represent computational failure).
   
   return lambda xs: (.join if isinstance(xs, str) else list)(
       chain.from_iterable(map(f, xs))
   )


  1. enumFromTo :: Int -> Int -> [Int]

def enumFromTo(m):

   Enumeration of integer values [m..n]
   def go(n):
       return list(range(m, 1 + n))
   return lambda n: go(n)


  1. properDivisors :: Int -> [Int]

def properDivisors(n):

   Positive divisors of n, excluding n itself
   root_ = sqrt(n)
   intRoot = int(root_)
   blnSqr = root_ == intRoot
   lows = [x for x in range(1, 1 + intRoot) if 0 == n % x]
   return lows + [
       n // x for x in reversed(
           lows[1:-1] if blnSqr else lows[1:]
       )
   ]


  1. MAIN ---

if __name__ == '__main__':

   main()</lang>
Output:
(220, 284)
(1184, 1210)
(2620, 2924)
(5020, 5564)
(6232, 6368)
(10744, 10856)
(12285, 14595)
(17296, 18416)

Quackery

properdivisors is defined at Proper divisors#Quackery.

<lang Quackery> [ properdivisors

   dup size 0 = iff
     [ drop 0 ] done 
   behead swap witheach + ] is spd           ( n --> n )
   
 [ dup dup spd dup spd 
   rot = unrot > and ]      is largeamicable ( n --> b )
   
 [ [] swap times
     [ i^ largeamicable if
       [ i^ dup spd
         swap join 
         nested join ] ] ]  is amicables     ( n --> [ )
         
 20000 amicables witheach [ witheach [ echo sp ] cr ]</lang>
Output:
220 284 
1184 1210 
2620 2924 
5020 5564 
6232 6368 
10744 10856 
12285 14595 
17296 18416 


R

<lang R> divisors <- function (n) {

 Filter( function (m) 0 == n %% m, 1:(n/2) )

}

table = sapply(1:19999, function (n) sum(divisors(n)) )

for (n in 1:19999) {

 m = table[n]
 if ((m > n) && (m < 20000) && (n == table[m]))
   cat(n, " ", m, "\n")

} </lang>

Output:
220   284
1184   1210
2620   2924
5020   5564
6232   6368
10744   10856
12285   14595
17296   18416

Racket

With Proper_divisors#Racket in place: <lang racket>#lang racket (require "proper-divisors.rkt") (define SCOPE 20000)

(define P

 (let ((P-v (vector)))
   (λ (n)
     (set! P-v (fold-divisors P-v n 0 +))
     (vector-ref P-v n))))
returns #f if not an amicable number, amicable pairing otherwise

(define (amicable? n)

 (define m (P n))
 (define m-sod (P m))
 (and (= m-sod n)
      (< m n) ; each pair exactly once, also eliminates perfect numbers
      m))

(void (amicable? SCOPE)) ; prime the memoisation

(for* ((n (in-range 1 (add1 SCOPE)))

      (m (in-value (amicable? n)))
      #:when m)
 (printf #<<EOS

amicable pair: ~a, ~a

 ~a: divisors: ~a
 ~a: divisors: ~a


EOS

         n m n (proper-divisors n)  m (proper-divisors m)))

</lang>

Output:
amicable pair: 284, 220
  284: divisors: (1 2 4 71 142)
  220: divisors: (1 2 4 5 10 11 20 22 44 55 110)

amicable pair: 1210, 1184
  1210: divisors: (1 2 5 10 11 22 55 110 121 242 605)
  1184: divisors: (1 2 4 8 16 32 37 74 148 296 592)

amicable pair: 2924, 2620
  2924: divisors: (1 2 4 17 34 43 68 86 172 731 1462)
  2620: divisors: (1 2 4 5 10 20 131 262 524 655 1310)

amicable pair: 5564, 5020
  5564: divisors: (1 2 4 13 26 52 107 214 428 1391 2782)
  5020: divisors: (1 2 4 5 10 20 251 502 1004 1255 2510)

amicable pair: 6368, 6232
  6368: divisors: (1 2 4 8 16 32 199 398 796 1592 3184)
  6232: divisors: (1 2 4 8 19 38 41 76 82 152 164 328 779 1558 3116)

amicable pair: 10856, 10744
  10856: divisors: (1 2 4 8 23 46 59 92 118 184 236 472 1357 2714 5428)
  10744: divisors: (1 2 4 8 17 34 68 79 136 158 316 632 1343 2686 5372)

amicable pair: 14595, 12285
  14595: divisors: (1 3 5 7 15 21 35 105 139 417 695 973 2085 2919 4865)
  12285: divisors: (1 3 5 7 9 13 15 21 27 35 39 45 63 65 91 105 117 135 189 195 273 315 351 455 585 819 945 1365 1755 2457 4095)

amicable pair: 18416, 17296
  18416: divisors: (1 2 4 8 16 1151 2302 4604 9208)
  17296: divisors: (1 2 4 8 16 23 46 47 92 94 184 188 368 376 752 1081 2162 4324 8648)

Raku

(formerly Perl 6)

Works with: Rakudo version 2019.03.1

<lang perl6>sub propdivsum (\x) {

   my @l = 1 if x > 1;
   (2 .. x.sqrt.floor).map: -> \d {
       unless x % d { @l.push: d; my \y = x div d; @l.push: y if y != d }
   }
   sum @l

}

(1..20000).race.map: -> $i {

   my $j = propdivsum($i);
   say "$i $j" if $j > $i and $i == propdivsum($j);

}</lang>

Output:
220 284
1184 1210
2620 2924
5020 5564
6232 6368
10744 10856
12285 14595
17296 18416

REBOL

<lang REBOL>;- based on Lua code ;-)

sum-of-divisors: func[n /local sum][

   sum: 1
   ; using `to-integer` for compatibility with Rebol2
   for d 2 (to-integer square-root n) 1 [
       if 0 = remainder n d [ sum: n / d + sum + d ]
   ]
   sum

]

for n 2 20000 1 [

   if n < m: sum-of-divisors n [
       if n = sum-of-divisors m [ print [n tab m] ]
   ]

]</lang>

Output:
220      284
1184     1210
2620     2924
5020     5564
6232     6368
10744    10856
12285    14595
17296    18416

ReScript

<lang rescript>let isqrt = (v) => {

 Belt.Float.toInt(
   sqrt(Belt.Int.toFloat(v)))

}

let sum_divs = (n) => {

 let sum = ref(1)
 for d in 2 to isqrt(n) {
   if mod(n, d) == 0 {
     sum.contents = sum.contents + (n / d + d)
   }
 }
 sum.contents

}

{

 for n in 2 to 20000 {
   let m = sum_divs(n)
   if (m > n) {
     if sum_divs(m) == n {
       Printf.printf("%d %d\n", n, m)
     }
   }
 }

} </lang>

Output:
$ bsc ampairs.res > ampairs.bs.js
$ node ampairs.bs.js
220 284
1184 1210
2620 2924
5020 5564
6232 6368
10744 10856
12285 14595
17296 18416

REXX

version 1, with factoring

<lang rexx> /*REXX*/

Call time 'R' Do x=1 To 20000

 pd=proper_divisors(x)
 sumpd.x=sum(pd)
 End

Say 'sum(pd) computed in' time('E') 'seconds' Call time 'R' Do x=1 To 20000

 /* If x//1000=0 Then Say x time() */
 Do y=x+1 To 20000
   If y=sumpd.x &,
      x=sumpd.y Then
   Say x y 'found after' time('E') 'seconds'
   End
 End

Say time('E') 'seconds total search time' Exit

proper_divisors: Procedure Parse Arg n Pd= If n=1 Then Return If n//2=1 Then /* odd number */

 delta=2

Else /* even number */

 delta=1

Do d=1 To n%2 By delta

 If n//d=0 Then
   pd=pd d
 End

Return space(pd)

sum: Procedure Parse Arg list sum=0 Do i=1 To words(list)

 sum=sum+word(list,i)
 End

Return sum</lang>

Output:
sum(pd) computed in 48.502000 seconds
220 284 found after 3.775000 seconds
1184 1210 found after 21.611000 seconds
2620 2924 found after 46.817000 seconds
5020 5564 found after 84.296000 seconds
6232 6368 found after 100.918000 seconds
10744 10856 found after 150.126000 seconds
12285 14595 found after 162.124000 seconds
17296 18416 found after 185.600000 seconds
188.836000 seconds total search time 

version 2, using SIGMA function

This REXX version allows the specification of the upper limit (for the searching of amicable pairs).

Some optimization was incorporated by using a   sigma   function,   which was a re-coded   proper divisors   (Pdivs)   function,
which was taken from the REXX language entry for Rosetta Code task   integer factors.

Other optimizations were incorporated which took advantage of several well-known generalizations about amicable pairs.

The generation/summation is about   5,000%   times faster than the 1st REXX version;   searching is about   10,000%   times faster.

CPU time consumption note:   for every doubling of   H   (the upper limit for searches),   the CPU time consumed triples. <lang rexx>/*REXX program calculates and displays all amicable pairs up to a given number. */ parse arg H .; if H== | H=="," then H= 20000 /*get optional arguments (high limit).*/ w= length(H) ; low= 220 /*W: used for columnar output alignment*/ @.=. /* [↑] LOW is lowest amicable number. */

    do k=low  for H-low;     _= sigma(k)        /*generate sigma sums for a range of #s*/
    if _>=low  then @.k= _                      /*only keep the pertinent sigma sums.  */
    end   /*k*/                                 /* [↑]   process a range of integers.  */
  1. = 0 /*number of amicable pairs found so far*/
    do   m=low  to  H;       n= @.m             /*start the search at the lowest number*/
    if m==@.n  then do                          /*If equal, might be an amicable number*/
                    if m==n  then iterate       /*Is this a perfect number?  Then skip.*/
                    #= # + 1                    /*bump the  amicable pair  counter.    */
                    say right(m,w)    ' and '     right(n,w)     " are an amicable pair."
                    m= n                        /*start   M   (DO index)  from  N.     */
                    end
    end    /*m*/

say say # ' amicable pairs found up to ' H /*display count of the amicable pairs. */ exit /*stick a fork in it, we're all done. */ /*──────────────────────────────────────────────────────────────────────────────────────*/ sigma: procedure; parse arg x; od= x // 2 /*use either EVEN or ODD integers. */

      s= 1                                      /*set initial sigma sum to unity.   ___*/
              do j=2+od  by 1+od  while  j*j<x  /*divide by all integers up to the √ X */
              if x//j==0  then  s= s + j + x%j  /*add the two divisors to the sum.     */
              end   /*j*/                       /* [↑]  %  is REXX integer division.   */
                                                /*                                 ___ */
      if j*j==x  then  return s + j             /*Was  X  a square?   If so, add  √ X  */
                       return s                 /*return (sigma) sum of the divisors.  */</lang>
output   when using the default input:
  220  and    284  are an amicable pair.
 1184  and   1210  are an amicable pair.
 2620  and   2924  are an amicable pair.
 5020  and   5564  are an amicable pair.
 6232  and   6368  are an amicable pair.
10744  and  10856  are an amicable pair.
12285  and  14595  are an amicable pair.
17296  and  18416  are an amicable pair.

8  amicable pairs found up to  20000

version 3, SIGMA with limited searches

This REXX version is optimized to take advantage of the lowest ending-single-digit amicable number,   and
also incorporates the search of amicable numbers into the generation of the sigmas of the integers.

The optimization makes it about another   30%   faster when searching for amicable numbers up to one million. <lang rexx>/*REXX program calculates and displays all amicable pairs up to a given number. */ parse arg H .; if H== | H=="," then H=20000 /*get optional arguments (high limit).*/ w=length(H)  ; low=220 /*W: used for columnar output alignment*/ x= 220 34765731 6232 87633 284 12285 10856 36939357 6368 5684679 /*S minimums.*/

  do i=0 for 10;   $.i= word(x, i + 1);   end   /*minimum amicable #s for last dec dig.*/

@.= /* [↑] LOW is lowest amicable number. */

  1. = 0 /*number of amicable pairs found so far*/
    do k=low  for H-low                         /*generate sigma sums for a range of #s*/
    parse var k    -1  D                      /*obtain last decimal digit of   K.    */
    if k<$.D    then iterate                    /*if no need to compute, then skip it. */
         _= sigma(k)                            /*generate sigma sum for the number  K.*/
    @.k= _                                      /*only keep the pertinent sigma sums.  */
    if k==@._  then do                          /*is it a possible amicable number ?   */
                    if _==k  then iterate       /*Is it a perfect number?  Then skip it*/
                    #= # + 1                    /*bump the amicable pair counter.      */
                    say right(_, w)    ' and '     right(k, w)   " are an amicable pair."
                    end
    end   /*k*/                                 /* [↑]   process a range of integers.  */

say say # 'amicable pairs found up to' H /*display the count of amicable pairs. */ exit /*stick a fork in it, we're all done. */ /*──────────────────────────────────────────────────────────────────────────────────────*/ sigma: procedure; parse arg x; od= x // 2 /*use either EVEN or ODD integers. */

      s= 1                                      /*set initial sigma sum to unity.   ___*/
            do j=2+od  by 1+od  while  j*j<x    /*divide by all integers up to the √ x */
            if x//j==0  then  s= s + j + x%j    /*add the two divisors to the sum.     */
            end   /*j*/                         /* [↑]  %  is REXX integer division.   */
                                                /*                                 ___ */
      if j*j==x  then  return s + j             /*Was  X  a square?   If so, add  √ X  */
                       return s                 /*return (sigma) sum of the divisors.  */</lang>
output   is identical to the 2nd REXX version.



version 4, SIGMA using integer SQRT

This REXX version is optimized to use the   integer square root of X   in the   sigma   function   (instead of
computing the square of   J   to see if that value exceeds   X).

The optimization makes it about another   20%   faster when searching for amicable numbers up to one million. <lang rexx>/*REXX program calculates and displays all amicable pairs up to a given number. */ parse arg H .; if H== | H=="," then H=20000 /*get optional arguments (high limit).*/ w= length(H)  ; low= 220 /*W: used for columnar output alignment*/ x= 220 34765731 6232 87633 284 12285 10856 36939357 6368 5684679 /*S minimums.*/

  do i=0  for 10;   $.i= word(x, i + 1);   end  /*minimum amicable #s for last dec dig.*/

@.= /* [↑] LOW is lowest amicable number. */

  1. = 0 /*number of amicable pairs found so far*/
    do k=low  for H-low                         /*generate sigma sums for a range of #s*/
    parse var k    -1  D                      /*obtain last decimal digit of   K.    */
    if k<$.D    then iterate                    /*if no need to compute, then skip it. */
         _= sigma(k)                            /*generate sigma sum for the number  K.*/
    @.k= _                                      /*only keep the pertinent sigma sums.  */
    if k==@._  then do                          /*is it a possible amicable number ?   */
                    if _==k  then iterate       /*Is it a perfect number?  Then skip it*/
                    #= # + 1                    /*bump the amicable pair counter.      */
                    say right(_, w)    ' and '    right(k, w)    " are an amicable pair."
                    end
    end   /*k*/                                 /* [↑]   process a range of integers.  */

say say # 'amicable pairs found up to' H /*display the count of amicable pairs. */ exit /*stick a fork in it, we're all done. */ /*──────────────────────────────────────────────────────────────────────────────────────*/ iSqrt: procedure; parse arg x; r= 0; q= 1; do while q<=x; q= q * 4; end

                 do while q>1; q=q%4; _=x-r-q; r=r%2; if _>=0 then do;x=_;r=r+q; end; end
      return r

/*──────────────────────────────────────────────────────────────────────────────────────*/ sigma: procedure; parse arg x; od= x // 2 /*use either EVEN or ODD integers. */

      s= 1                                      /*set initial sigma sum to unity.   ___*/
               do j=2+od  by 1+od  to iSqrt(x)  /*divide by all integers up to the √ x */
               if x//j==0  then  s= s + j + x%j /*add the two divisors to the sum.     */
               end   /*j*/                      /* [↑]  % is the REXX integer division.*/
                                                /*                                 ___ */
      if j*j==x  then  return s + j             /*Was  X  a square?   If so, add  √ X  */
                       return s                 /*return (sigma) sum of the divisors.  */</lang>
output   is identical to the 2nd REXX version.



version 5, SIGMA (in-line code)

This REXX version is optimized by bringing the functions in-line   (which minimizes the overhead of invoking two
internal functions),   and it also pre-computes the powers of four   (for the integer square root code).

This method of coding has the disadvantage in that the code (logic) is less idiomatic and therefore less readable.

The optimization makes it about another   15%   faster when searching for amicable numbers up to one million. <lang rexx>/*REXX program calculates and displays all amicable pairs up to a given number. */ parse arg H .; if H== | H=="," then H=20000 /*get optional arguments (high limit).*/ w= length(H)  ; low= 220 /*W: used for columnar output alignment*/ x= 220 34765731 6232 87633 284 12285 10856 36939357 6368 5684679 /*S minimums.*/

  do i=0  for 10;   $.i= word(x, i + 1);   end  /*minimum amicable #s for last dec dig.*/

@.= /* [↑] LOW is lowest amicable number. */

  1. = 0 /*number of amicable pairs found so far*/
    do k=low  for H-low                         /*generate sigma sums for a range of #s*/
    parse var k    -1  D                      /*obtain last decimal digit of   K.    */
    if k<$.D    then iterate                    /*if no need to compute, then skip it. */
         _= sigma(k)                            /*generate sigma sum for the number  K.*/
    @.k= _                                      /*only keep the pertinent sigma sums.  */
    if k==@._  then do                          /*is it a possible amicable number ?   */
                    if _==k  then iterate       /*Is it a perfect number?  Then skip it*/
                    #= # + 1                    /*bump the amicable pair counter.      */
                    say right(_, w)    ' and '    right(k, w)    " are an amicable pair."
                    end
    end   /*k*/                                 /* [↑]   process a range of integers.  */

say say # 'amicable pairs found up to' H /*display the count of amicable pairs. */ exit /*stick a fork in it, we're all done. */ /*──────────────────────────────────────────────────────────────────────────────────────*/ iSqrt: procedure; parse arg x; r= 0; q= 1; do while q<=x; q= q * 4; end

                 do while q>1; q=q%4; _=x-r-q; r=r%2; if _>=0 then do;x=_;r=r+q; end; end
      return r

/*──────────────────────────────────────────────────────────────────────────────────────*/ sigma: procedure; parse arg x; od= x // 2 /*use either EVEN or ODD integers. */

      s= 1                                      /*set initial sigma sum to unity.   ___*/
               do j=2+od  by 1+od  to iSqrt(x)  /*divide by all integers up to the √ x */
               if x//j==0  then  s= s + j + x%j /*add the two divisors to the sum.     */
               end   /*j*/                      /* [↑]  % is the REXX integer division.*/
                                                /*                                 ___ */
      if j*j==x  then  return s + j             /*Was  X  a square?   If so, add  √ X  */
                       return s                 /*return (sigma) sum of the divisors.  */</lang>
output   is identical to the 2nd REXX version.



Ring

<lang ring> size = 18500 for n = 1 to size

   m = amicable(n)
   if m>n and amicable(m)=n
      see "" + n + " and " + m + nl ok

next see "OK" + nl

func amicable nr

    sum = 1
    for d = 2 to sqrt(nr)
        if nr % d = 0 
           sum = sum + d
           sum = sum + nr / d ok
    next
    return sum

</lang>

Ruby

With proper_divisors#Ruby in place: <lang ruby>h = {} (1..20_000).each{|n| h[n] = n.proper_divisors.sum } h.select{|k,v| h[v] == k && k < v}.each do |key,val| # k<v filters out doubles and perfects

 puts "#{key} and #{val}"

end </lang>

Output:

220 and 284 1184 and 1210 2620 and 2924 5020 and 5564 6232 and 6368 10744 and 10856 12285 and 14595 17296 and 18416

Run BASIC

<lang Runbasic>size = 18500 for n = 1 to size

   m = amicable(n)
   if m > n and amicable(m) = n then print  n ; " and " ; m

next

function amicable(nr)

    amicable = 1
    for d = 2 to sqr(nr)
        if nr mod d = 0 then amicable = amicable + d + nr / d
    next
end function</lang>
220 and 284
1184 and 1210
2620 and 2924
5020 and 5564
6232 and 6368
10744 and 10856
12285 and 14595
17296 and 18416

Rust

<lang rust>fn sum_of_divisors(val: u32) -> u32 {

   (1..val/2+1).filter(|n| val % n == 0)
               .fold(0, |sum, n| sum + n)

}

fn main() {

   let iter = (1..20_000).map(|i| (i, sum_of_divisors(i)))
                         .filter(|&(i, div_sum)| i > div_sum);
   for (i, sum1) in iter {
       if sum_of_divisors(sum1) == i {
          println!("{} {}", i, sum1);
       }
   }

}</lang>

Output:
284 220
1210 1184
2924 2620
5564 5020
6368 6232
10856 10744
14595 12285
18416 17296

Scala

<lang Scala>def properDivisors(n: Int) = (1 to n/2).filter(i => n % i == 0) val divisorsSum = (1 to 20000).map(i => i -> properDivisors(i).sum).toMap val result = divisorsSum.filter(v => v._1 < v._2 && divisorsSum.get(v._2) == Some(v._1))

println( result mkString ", " )</lang>

Output:
5020 -> 5564, 220 -> 284, 6232 -> 6368, 17296 -> 18416, 2620 -> 2924, 10744 -> 10856, 12285 -> 14595, 1184 -> 1210

Scheme

<lang scheme> (import (scheme base)

       (scheme inexact)
       (scheme write)
       (only (srfi 1) fold))
return a list of the proper-divisors of n

(define (proper-divisors n)

 (let ((root (sqrt n)))
   (let loop ((divisors (list 1))
              (i 2))
     (if (> i root)
       divisors
       (loop (if (zero? (modulo n i)) 
               (if (= (square i) n)
                 (cons i divisors)
                 (append (list i (quotient n i)) divisors))
               divisors)
             (+ 1 i))))))

(define (sum-proper-divisors n)

 (if (< n 2)
   0
   (fold + 0 (proper-divisors n))))

(define *max-n* 20000)

hold sums of proper divisors in a cache, to avoid recalculating

(define *cache* (make-vector (+ 1 *max-n*))) (for-each (lambda (i) (vector-set! *cache* i (sum-proper-divisors i)))

         (iota *max-n* 1))

(define (amicable-pair? i j)

 (and (not (= i j))
      (= i (vector-ref *cache* j))
      (= j (vector-ref *cache* i))))
double loop to *max-n*, displaying all amicable pairs

(let loop-i ((i 1))

 (when (<= i *max-n*)
   (let loop-j ((j i))
     (when (<= j *max-n*)
       (when (amicable-pair? i j)
         (display (string-append "Amicable pair: "
                                 (number->string i)
                                 " "
                                 (number->string j)))
         (newline))
       (loop-j (+ 1 j))))
   (loop-i (+ 1 i))))

</lang>

Output:
Amicable pair: 220 284
Amicable pair: 1184 1210
Amicable pair: 2620 2924
Amicable pair: 5020 5564
Amicable pair: 6232 6368
Amicable pair: 10744 10856
Amicable pair: 12285 14595
Amicable pair: 17296 18416

Sidef

<lang ruby>func propdivsum(n) {

   n.sigma - n

}

for i in (1..20000) {

   var j = propdivsum(i)
   say "#{i} #{j}" if (j>i && i==propdivsum(j))

}</lang>

Output:
220 284
1184 1210
2620 2924
5020 5564
6232 6368
10744 10856
12285 14595
17296 18416

Swift

<lang Swift>import func Darwin.sqrt

func sqrt(x:Int) -> Int { return Int(sqrt(Double(x))) }

func properDivs(n: Int) -> [Int] {

   if n == 1 { return [] }
   
   var result = [Int]()
   
   for div in filter (1...sqrt(n), { n % $0 == 0 }) {
       
       result.append(div)
       if n/div != div && n/div != n { result.append(n/div) }
   }
   
   return sorted(result)
   

}


func sumDivs(n:Int) -> Int {

   struct Cache { static var sum = [Int:Int]() }
   
   if let sum = Cache.sum[n] { return sum }
   
   let sum = properDivs(n).reduce(0) { $0 + $1 }
   
   Cache.sum[n] = sum
   
   return sum

}

func amicable(n:Int, m:Int) -> Bool {

   if n == m { return false }
   
   if sumDivs(n) != m || sumDivs(m) != n { return false }
   
   return true

}

var pairs = [(Int, Int)]()

for n in 1 ..< 20_000 {

   for m in n+1 ... 20_000 {
       if amicable(n, m) {
           pairs.append(n, m)
           println("\(n, m)")
       }
   }

}</lang>

Alternative

about 800 times faster.<lang Swift>import func Darwin.sqrt

func sqrt(x:Int) -> Int { return Int(sqrt(Double(x))) }

func sigma(n: Int) -> Int {

   if n == 1 { return 0 }          // definition of aliquot sum
   
   var result = 1
   let root = sqrt(n)
   
   for var div = 2; div <= root; ++div {
       if n % div == 0 {
           result += div + n/div
       }
       
   }
   if root*root == n { result -= root }
   
   return (result)

}

func amicables (upTo: Int) -> () {

   var aliquot = Array(count: upTo+1, repeatedValue: 0)
   for i in 1 ... upTo {           // fill lookup array
       aliquot[i] = sigma(i)
   }
   
for i in 1 ... upTo {
       let a = aliquot[i]
       if a > upTo {continue}      //second part of pair out-of-bounds
       if a == i {continue}        //skip perfect numbers
       
       if i == aliquot[a] {
           print("\(i, a)")
           aliquot[a] = upTo+1     //prevent second display of pair
       }
   }

}

amicables(20_000)</lang>

Output:
(220, 284)
(1184, 1210)
(2620, 2924)
(5020, 5564)
(6232, 6368)
(10744, 10856)
(12285, 14595)
(17296, 18416)

tbas

<lang vb> dim sums(20000)

sub sum_proper_divisors(n) dim sum = 0 dim i if n > 1 then for i = 1 to (n \ 2) if n %% i = 0 then sum = sum + i end if next end if return sum end sub

dim i, j for i = 1 to 20000 sums(i) = sum_proper_divisors(i) for j = i-1 to 2 by -1 if sums(i) = j and sums(j) = i then print "Amicable pair:";sums(i);"-";sums(j) exit for end if next next </lang>

>tbas amicable_pairs.bas
Amicable pair: 220 - 284
Amicable pair: 1184 - 1210
Amicable pair: 2620 - 2924
Amicable pair: 5020 - 5564
Amicable pair: 6232 - 6368
Amicable pair: 10744 - 10856
Amicable pair: 12285 - 14595
Amicable pair: 17296 - 18416

Tcl

<lang tcl>proc properDivisors {n} {

   if {$n == 1} return
   set divs 1
   set sum 1
   for {set i 2} {$i*$i <= $n} {incr i} {

if {!($n % $i)} { lappend divs $i incr sum $i if {$i*$i < $n} { lappend divs [set d [expr {$n / $i}]] incr sum $d } }

   }
   return [list $sum $divs]

}

proc amicablePairs {limit} {

   set result {}
   set sums [set divs {{}}]
   for {set n 1} {$n < $limit} {incr n} {

lassign [properDivisors $n] sum d lappend sums $sum lappend divs [lsort -integer $d]

   }
   for {set n 1} {$n < $limit} {incr n} {

set nsum [lindex $sums $n] for {set m 1} {$m < $n} {incr m} { if {$n==[lindex $sums $m] && $m==$nsum} { lappend result $m $n [lindex $divs $m] [lindex $divs $n] } }

   }
   return $result

}

foreach {m n md nd} [amicablePairs 20000] {

   puts "$m and $n are an amicable pair with these proper divisors"
   puts "\t$m : $md"
   puts "\t$n : $nd"

}</lang>

Output:
220 and 284 are an amicable pair with these proper divisors
	220 : 1 2 4 5 10 11 20 22 44 55 110
	284 : 1 2 4 71 142
1184 and 1210 are an amicable pair with these proper divisors
	1184 : 1 2 4 8 16 32 37 74 148 296 592
	1210 : 1 2 5 10 11 22 55 110 121 242 605
2620 and 2924 are an amicable pair with these proper divisors
	2620 : 1 2 4 5 10 20 131 262 524 655 1310
	2924 : 1 2 4 17 34 43 68 86 172 731 1462
5020 and 5564 are an amicable pair with these proper divisors
	5020 : 1 2 4 5 10 20 251 502 1004 1255 2510
	5564 : 1 2 4 13 26 52 107 214 428 1391 2782
6232 and 6368 are an amicable pair with these proper divisors
	6232 : 1 2 4 8 19 38 41 76 82 152 164 328 779 1558 3116
	6368 : 1 2 4 8 16 32 199 398 796 1592 3184
10744 and 10856 are an amicable pair with these proper divisors
	10744 : 1 2 4 8 17 34 68 79 136 158 316 632 1343 2686 5372
	10856 : 1 2 4 8 23 46 59 92 118 184 236 472 1357 2714 5428
12285 and 14595 are an amicable pair with these proper divisors
	12285 : 1 3 5 7 9 13 15 21 27 35 39 45 63 65 91 105 117 135 189 195 273 315 351 455 585 819 945 1365 1755 2457 4095
	14595 : 1 3 5 7 15 21 35 105 139 417 695 973 2085 2919 4865
17296 and 18416 are an amicable pair with these proper divisors
	17296 : 1 2 4 8 16 23 46 47 92 94 184 188 368 376 752 1081 2162 4324 8648
	18416 : 1 2 4 8 16 1151 2302 4604 9208

Transd

<lang scheme>

  1. lang transd

MainModule : {

   _start: (lambda
       (with sum 0 d 0 f Filter( from: 1 to: 20000 apply: (lambda
               (= sum 1)
               (for i in Range(2 (to-Int (sqrt @it))) do 
                   (if (not (mod @it i)) 
                       (= d (/ @it i)) (+= sum i)
                       (if (neq d i) (+= sum d))))
               (ret sum)))
           (with v (to-vector f)
               (for i in v do
                   (if (and (< i (size v)) 
                            (eq (+ @idx 1) (get v (- i 1))) 
                            (< i (get v (- i 1))))
                       (textout (+ @idx 1) ", " i "\n")
                   )))))

}</lang>

Output:
284, 220
1210, 1184
2924, 2620
5564, 5020
6368, 6232
10856, 10744
14595, 12285
18416, 17296

uBasic/4tH

<lang>Input "Limit: ";l Print "Amicable pairs < ";l

For n = 1 To l

 m = FUNC(_SumDivisors (n))-n
 If m = 0 Then Continue               ' No division by zero, please
 p = FUNC(_SumDivisors (m))-m
 If (n=p) * (n<m) Then Print n;" and ";m

Next

End

_LeastPower Param(2)

 Local(1)
 c@ = a@
 Do While (b@ % c@) = 0
   c@ = c@ * a@
 Loop

Return (c@)


' Return the sum of the proper divisors of a@

_SumDivisors Param(1)

 Local(4)
 b@ = a@
 c@ = 1
 ' Handle two specially
 d@ = FUNC(_LeastPower (2,b@))
 c@ = c@ * (d@ - 1)
 b@ = b@ / (d@ / 2)
 ' Handle odd factors
 For e@ = 3 Step 2 While (e@*e@) < (b@+1)
   d@ = FUNC(_LeastPower (e@,b@))
   c@ = c@ * ((d@ - 1) / (e@ - 1))
   b@ = b@ / (d@ / e@)
 Loop
 ' At this point, t must be one or prime
 If (b@ > 1) c@ = c@ * (b@+1)

Return (c@)</lang>

Output:
Limit: 20000
Amicable pairs < 20000
220 and 284
1184 and 1210
2620 and 2924
5020 and 5564
6232 and 6368
10744 and 10856
12285 and 14595
17296 and 18416

0 OK, 0:238

UTFool

<lang UTFool> ··· http://rosettacode.org/wiki/Amicable_pairs ··· ■ AmicablePairs

 § static
   ▶ main
   • args⦂ String[]
     ∀ n ∈ 1…20000
       m⦂ int: sumPropDivs n
       if m < n = sumPropDivs m
          System.out.println "⸨m⸩ ; ⸨n⸩"
   ▶ sumPropDivs⦂ int
   • n⦂ int
     m⦂ int: 1
     ∀ i ∈ √n ⋯> 1
       m +: n \ i = 0 ? i + (i = n / i ? 0 ! n / i) ! 0
     ⏎ m

</lang>

VBA

<lang vb>Option Explicit

Public Sub AmicablePairs() Dim a(2 To 20000) As Long, c As New Collection, i As Long, j As Long, t#

   t = Timer
   For i = LBound(a) To UBound(a)
       'collect the sum of the proper divisors
       'of each numbers between 2 and 20000
       a(i) = S(i)
   Next
   'Double Loops to test the amicable
   For i = LBound(a) To UBound(a)
       For j = i + 1 To UBound(a)
           If i = a(j) Then
               If a(i) = j Then
                    On Error Resume Next
                    c.Add i & " : " & j, CStr(i * j)
                    On Error GoTo 0
                    Exit For
               End If
           End If
       Next
   Next
   'End. Return :
   Debug.Print "Execution Time : " & Timer - t & " seconds."
   Debug.Print "Amicable pairs below 20 000 are : "
   For i = 1 To c.Count
       Debug.Print c.Item(i)
   Next i

End Sub

Private Function S(n As Long) As Long 'returns the sum of the proper divisors of n Dim j As Long

   For j = 1 To n \ 2
       If n Mod j = 0 Then S = j + S
   Next

End Function</lang>

Output:
Execution Time : 7,95703125 seconds.
Amicable pairs below 20 000 are : 
220 : 284
1184 : 1210
2620 : 2924
5020 : 5564
6232 : 6368
10744 : 10856
12285 : 14595
17296 : 18416

VBScript

Not at all optimal. :-( <lang VBScript>start = Now Set nlookup = CreateObject("Scripting.Dictionary") Set uniquepair = CreateObject("Scripting.Dictionary")

For i = 1 To 20000 sum = 0 For n = 1 To 20000 If n < i Then If i Mod n = 0 Then sum = sum + n End If End If Next nlookup.Add i,sum Next

For j = 1 To 20000 sum = 0 For m = 1 To 20000 If m < j Then If j Mod m = 0 Then sum = sum + m End If End If Next If nlookup.Exists(sum) And nlookup.Item(sum) = j And j <> sum _ And uniquepair.Exists(sum) = False Then uniquepair.Add j,sum End If Next

For Each key In uniquepair.Keys WScript.Echo key & ":" & uniquepair.Item(key) Next

WScript.Echo "Execution Time: " & DateDiff("s",Start,Now) & " seconds"</lang>

Output:
220:284
1184:1210
2620:2924
5020:5564
6232:6368
10744:10856
12285:14595
17296:18416
Execution Time: 162 seconds

Vlang

Translation of: Go

<lang Go>fn pfac_sum(i int) int {

   mut sum := 0
   for p := 1;p <= i/2;p++{
       if i%p == 0 {
           sum += p
       }
   }
   return sum

}

fn main(){

   a := []int{len: 20000, init:pfac_sum(it)}
   println('The amicable pairs below 20,000 are:')
   for n in 2 .. a.len {
       m := a[n]
       if m > n && m < 20000 && n == a[m] {
           println('${n:5} and ${m:5}')
       }
   }

}</lang>

Output:
The amicable pairs below 20,000 are:
  220 and   284
 1184 and  1210
 2620 and  2924
 5020 and  5564
 6232 and  6368
10744 and 10856
12285 and 14595
17296 and 18416


Wren

Library: Wren-fmt
Library: Wren-math

<lang ecmascript>import "/fmt" for Fmt import "/math" for Int, Nums

var a = List.filled(20000, 0) for (i in 1...20000) a[i] = Nums.sum(Int.properDivisors(i)) System.print("The amicable pairs below 20,000 are:") for (n in 2...19999) {

   var m = a[n]
   if (m > n && m < 20000 && n == a[m]) {
       System.print("  %(Fmt.d(5, n)) and %(Fmt.d(5, m))")
   }

}</lang>

Output:
The amicable pairs below 20,000 are:
    220 and   284
   1184 and  1210
   2620 and  2924
   5020 and  5564
   6232 and  6368
  10744 and 10856
  12285 and 14595
  17296 and 18416

XPL0

<lang XPL0>func SumDiv(Num); \Return sum of proper divisors of Num int Num, Div, Sum, Quot; [Div:= 2; Sum:= 0; loop [Quot:= Num/Div;

       if Div > Quot then quit;
       if rem(0) = 0 then
           [Sum:= Sum + Div;
           if Div # Quot then Sum:= Sum + Quot;
           ];
       Div:= Div+1;
       ];

return Sum+1; ];

def Limit = 20000; int Tbl(Limit), N, M; [for N:= 0 to Limit-1 do

   Tbl(N):= SumDiv(N);

for N:= 1 to Limit-1 do

   [M:= Tbl(N);
   if M<Limit & N=Tbl(M) & M>N then
       [IntOut(0, N);  ChOut(0, 9\tab\);
        IntOut(0, M);  CrLf(0);
       ];
   ];

]</lang>

Output:
220     284
1184    1210
2620    2924
5020    5564
6232    6368
10744   10856
12285   14595
17296   18416

Yabasic

Translation of: Lua

<lang Yabasic>sub sumDivs(n)

   local sum, d
   
   sum = 1
   
   for d = 2 to sqrt(n)
       if not mod(n, d) then
           sum = sum + d
           sum = sum + n / d
       end if
   next
   return sum

end sub

for n = 2 to 20000

   m = sumDivs(n)
   if m > n then
       if sumDivs(m) = n print n, "\t", m
   end if

next

print : print peek("millisrunning"), " ms"</lang>

zkl

Slooooow <lang zkl>fcn properDivs(n){ [1.. (n + 1)/2 + 1].filter('wrap(x){ n%x==0 and n!=x }) } const N=20000; sums:=[1..N].pump(T(-1),fcn(n){ properDivs(n).sum(0) }); [0..].zip(sums).filter('wrap([(n,s)]){ (n<s<=N) and sums[s]==n }).println();</lang>

Output:
L(L(220,284),L(1184,1210),L(2620,2924),L(5020,5564),L(6232,6368),L(10744,10856),L(12285,14595),L(17296,18416))

Zig

<lang zig>const MAXIMUM: u32 = 20_000;

// Fill up a given array with arr[n] = sum(propDivs(n)) pub fn calcPropDivs(divs: []u32) void {

   for (divs) |*d| d.* = 1;
   var i: u32 = 2;
   while (i <= divs.len/2) : (i += 1) {
       var j = i * 2;
       while (j < divs.len) : (j += i)
           divs[j] += i;
   }

}

// Are (A, B) an amicable pair? pub fn amicable(divs: []const u32, a: u32, b: u32) bool {

   return divs[a] == b and a == divs[b];

}

pub fn main() !void {

   const stdout = @import("std").io.getStdOut().writer();
   var divs: [MAXIMUM + 1]u32 = undefined;
   calcPropDivs(divs[0..]);
   
   var a: u32 = 1;
   while (a < divs.len) : (a += 1) {
       var b = a+1;
       while (b < divs.len) : (b += 1) {
           if (amicable(divs[0..], a, b))
               try stdout.print("{d}, {d}\n", .{a, b});
       }
   }

}</lang>

Output:
220, 284
1184, 1210
2620, 2924
5020, 5564
6232, 6368
10744, 10856
12285, 14595
17296, 18416

ZX Spectrum Basic

Translation of: AWK

<lang zxbasic>10 LET limit=20000 20 PRINT "Amicable pairs < ";limit 30 FOR n=1 TO limit 40 LET num=n: GO SUB 1000 50 LET m=num 60 GO SUB 1000 70 IF n=num AND n<m THEN PRINT n;" ";m 80 NEXT n 90 STOP 1000 REM sumprop 1010 IF num<2 THEN LET num=0: RETURN 1020 LET sum=1 1030 LET root=SQR num 1040 FOR i=2 TO root-.01 1050 IF num/i=INT (num/i) THEN LET sum=sum+i+num/i 1060 NEXT i 1070 IF num/root=INT (num/root) THEN LET sum=sum+root 1080 LET num=sum 1090 RETURN</lang>

Output:
Amicable pairs < 20000
220 284
1184 1210
2620 2924
5020 5564
6232 6368
10744 10856
12285 14595
17296 18416