User input/Text

User input/Text
You are encouraged to solve this task according to the task description, using any language you may know.

In this task, the goal is to input a string and the integer 75000, from the text console.

See also: User Input - graphical

Ada

Works with: GCC version 4.1.2

<lang ada>

  function Get_String return String is
    Line : String (1 .. 1_000);
    Last : Natural;
  begin
    Get_Line (Line, Last);
    return Line (1 .. Last);
  end Get_String;
  function Get_Integer return Integer is
    S : constant String := Get_String;
  begin
    return Integer'Value (S);
    --  may raise exception Constraint_Error if value entered is not a well-formed integer
  end Get_Integer;
</lang>

The functions above may be called as shown below <lang ada>

  My_String  : String  := Get_String;
  My_Integer : Integer := Get_Integer;

</lang>

ALGOL 68

print("Enter a string: ");
STRING s := read string;
print("Enter a number: ");
INT i := read int;
~

AutoHotkey

Windows console

<lang AutoHotkey> DllCall("AllocConsole") FileAppend, please type something`n, CONOUT$ FileReadLine, line, CONIN$, 1 msgbox % line FileAppend, please type '75000'`n, CONOUT$ FileReadLine, line, CONIN$, 1 msgbox % line</lang>

Input Command

this one takes input regardless of which application has focus. <lang AutoHotkey>TrayTip, Input:, Type a string: Input(String) TrayTip, Input:, Type an int: Input(Int) TrayTip, Done!, Input was recieved. Msgbox, You entered "%String%" and "%Int%" ExitApp Return

Input(ByRef Output) {

 Loop
 {
   Input, Char, L1, {Enter}{Space}
   If ErrorLevel contains Enter 
     Break
   Else If ErrorLevel contains Space
     Output .= " "
   Else 
     Output .= Char
   TrayTip, Input:, %Output%
 }

}</lang>

AWK

This demo shows a same-line prompt, and that the integer i becomes 0 if the line did not parse as an integer. <lang awk> ~/src/opt/run $ awk 'BEGIN{printf "enter a string: "}{s=$0;i=$0+0;print "ok,"s"/"i}' enter a string: hello world ok,hello world/0 75000 ok,75000/75000 </lang>

BASIC

Works with: QuickBasic version 4.5

 INPUT "Enter a string: ", s$
 INPUT "Enter a number: ", i%

Works with: FreeBASIC

 dim s as string
 dim i as integer
 
 input "Enter a string: ", s
 input "Enter the integer 75000: ", i

Befunge

This prompts for a string and pushes it to the stack a character at a time (~) until end of input (-1).

<>:v:"Enter a string: "
 ^,_ >~:1+v
     ^    _@

Numeric input is easier, using the & command.

<>:v:"Enter a number: "
 ^,_ & @

C

Works with: gcc

<lang c> #include <stdio.h>

int main(int argc, char* argv[])
{
        int input;
        if((scanf("%d", &input))==1)
        {
                printf("Read in %d\n", input);
                return 1;
        }
        return 0;
}</lang>

C++

Works with: g++

<lang cpp> #include <iostream>

#include <string>
using namespace std;

int main()
{
     // while probably all current implementations have int wide enough for 75000, the C++ standard
     // only guarantees this for long int.
     long int integer_input;
     string string_input;
     cout << "Enter an integer:  ";
     cin >> integer_input;
     cout << "Enter a string:  ";
     cin >> string_input;
     return 0;
}</lang>

Note: The program as written above only reads the string up to the first whitespace character. To get a complete line into the string, replace <lang cpp> cin >> string_input;</lang> with <lang cpp> getline(cin, string_input);</lang>

Note: if a numeric input operation fails, the value is not stored for that operation, plus the fail bit is set, which causes all future stream operations to be ignored (e.g. if a non-integer is entered for the first input above, then nothing will be stored in either the integer and the string). A more complete program would test for an error in the input (with if (!cin) // handle error) after the first input, and then clear the error (with cin.clear()) if we want to get further input.

Alternatively, we could read the input into a string first, and then parse that into an int later.

C#

<lang csharp> using System;

 namespace C_Sharp_Console {
 
     class example {
 
         static void Main() {
             string word;
             int num;
             
             Console.Write("Enter an integer: ");
             num = Console.Read();
             Console.Write("Enter a String: ");
             word = Console.ReadLine();
         }
     }
 }</lang>

Clojure

<lang clojure>(import '(java.util Scanner)) (def scan (Scanner. *in*)) (def s (.nextLine scan)) (def n (.nextInt scan)) </lang>

Common Lisp

<lang lisp>(format t "Enter some text: ") (let ((s (read-line)))

   (format t "You entered ~s~%" s))

(format t "Enter a number: ") (let ((n (read)))

   (if (numberp n)
       (format t "You entered ~d.~%" n)
     (format t "That was not a number.")))</lang>

D

<lang D>import tango.io.Console; import Integer = tango.text.convert.Integer;

void main() {

 int num;
 char[] word;
 Cout("Enter an integer:")();
 num = Integer.parse(Cin.get());
 Cout("Enter a string:")();
 word = Cin.get();
}</lang>

Erlang

<lang erlang> {ok, [String]} = io:fread("Enter a string: ","~s").

{ok, [Number]} = io:fread("Enter a number: ","~d").</lang>

Alternatively, you could use io:get_line to get a string: <lang erlang> String = io:get_line("Enter a string: ").</lang>

FALSE

FALSE has neither a string type nor numeric input. Shown instead are routines to parse and echo a word and to parse and interpret a number using the character input command (^).

[[^$' =~][,]#,]w:
[0[^'0-$$9>0@>|~][\10*+]#%]d:
w;! d;!.

Forth

Input a string

<lang forth> : INPUT$ ( n -- addr n )

   PAD SWAP ACCEPT
   PAD SWAP ;</lang>

Input a number

The only ANS standard number interpretation word is >NUMBER ( ud str len -- ud str len ), which is meant to be the base factor for more convenient (but non-standard) parsing words. <lang forth> : INPUT# ( -- u true | false )

  0. 16 INPUT$ DUP >R
  >NUMBER NIP NIP 
  R> <> DUP 0= IF NIP THEN ;</lang>

Works with: GNU Forth

<lang forth> : INPUT# ( -- n true | d 1 | false )

   16 INPUT$ SNUMBER? ;</lang>

Works with: Win32Forth

<lang forth> : INPUT# ( -- n true | false )

   16 INPUT$ NUMBER? NIP
   DUP 0= IF NIP THEN ;</lang>

Note that NUMBER? always leaves a double result on the stack. INPUT# returns a single precision number. If you desire a double precision result, remove the NIP.

Here is an example that puts it all together:

<lang forth> : TEST

  ." Enter your name: " 80 INPUT$ CR
  ." Hello there, " TYPE CR
  ." Enter a number: " INPUT# CR
  IF   ." Your number is " .
  ELSE ." That's not a number!" THEN CR ;</lang>

Fortran

Works with: Fortran version 90 and later

<lang fortran> character(20) :: s integer :: i

print*, "Enter a string (max 20 characters)" read*, s print*, "Enter the integer 75000" read*, i </lang>

Groovy

<lang groovy> word = System.in.readLine()

num = System.in.readLine().toInteger()</lang>

Haskell

<lang haskell>

import System.IO (hFlush, stdout)
main = do
    putStr "Enter a string: "
    hFlush stdout
    str <- getLine
    putStr "Enter an integer: "
    hFlush stdout
    num <- readLn :: IO Int 
    putStrLn $ str ++ (show num)</lang>

Note: :: IO Int is only there to disambiguate what type we wanted from read. If num were used in a numerical context, its type would have been inferred by the interpreter/compiler. Note also: Haskell doesn't automatically flush stdout when doing input, so explicit flushes are necessary.

Java

<lang java> import java.io.BufferedReader;

import java.io.InputStreamReader;

public class GetInput {
    public static void main(String[] args) throws Exception {
        BufferedReader sysin = new BufferedReader(new InputStreamReader(System.in));
        int number = Integer.parseInt(sysin.readLine());
        String string = sysin.readLine();
    }
}</lang>

or

Works with: Java version 1.5/5.0+

<lang java> import java.util.Scanner;

Scanner stdin = new Scanner(System.in);
String string = stdin.nextLine();
int number = stdin.nextInt();</lang>

Logo

Logo literals may be read from a line of input from stdin as either a list or a single word. <lang logo> make "input readlist  ; in: string 75000

show map "number? :input  ; [false true]

make "input readword   ; in: 75000
show :input + 123       ; 75123 
make "input readword   ; in: string 75000
show :input             ; string 75000</lang>

Mathematica

<lang Mathematica>

mystring = InputString["give me a string please"];
myinteger = Input["give me an integer please"];

</lang>

Metafont

<lang metafont>string s; message "write a string: "; s := readstring; message s; message "write a number now: "; b := scantokens readstring; if b = 750:

 message "You've got it!"

else:

 message "Sorry..."

fi; end</lang>

If we do not provide a number in the second input, Metafont will complain. (The number 75000 was reduced to 750 since Metafont biggest number is near 4096).

mIRC Scripting Language

alias askmesomething {
  echo -a You answered: $input(What's your name?, e)
}

Modula-3

<lang modula3>MODULE Input EXPORTS Main;

IMPORT IO, Fmt;

VAR string: TEXT;

   number: INTEGER;

BEGIN

 IO.Put("Enter a string: ");
 string := IO.GetLine();
 IO.Put("Enter a number: ");
 number := IO.GetInt();
 IO.Put("You entered: " & string & " and " & Fmt.Int(number) & "\n");

END Input. </lang>

newLISP

Works with: newLISP version 9.0

(print "Enter an integer: ")
(set 'x (read-line))
(print "Enter a string: ")
(set 'y (read-line))

OCaml

<lang ocaml>print_string "Enter a string: "; let str = read_line () in

 print_string "Enter an integer: ";
 let num = read_int () in
   Printf.printf "%s%d\n" str num</lang>

Octave

<lang octave>% read a string ("s") s = input("Enter a string: ", "s");

% read a GNU Octave expression, which is evaluated; e.g. % 5/7 gives 0.71429 i = input("Enter an expression: ");

% parse the input for an integer printf("Enter an integer: "); ri = scanf("%d");

% show the values disp(s); disp(i); disp(ri);</lang>

Pascal

<lang pascal> program UserInput(input, output);

var i : Integer;
    s : String;
begin
 write('Enter an integer: ');
 readln(i);
 write('Enter a string: ');
 readln(s)
end.</lang>

Perl

Works with: Perl version 5.8.8

<lang perl> #!/usr/bin/perl

my $string = <>; # equivalent to readline(*STDIN)
my $integer = <>;</lang>

PHP

Works with: CLI SAPI

<lang php> #!/usr/bin/php

<?php
$string = fgets(STDIN);
$integer = (int) fgets(STDIN);</lang>

Pop11

<lang pop11> ;;; Setup item reader

lvars itemrep = incharitem(charin);
lvars s, c, j = 0;
;;; read chars up to a newline and put them on the stack
while (charin() ->> c) /= `\n` do j + 1 -> j ; c endwhile;
;;; build the string
consstring(j) -> s;
;;; read the integer
lvars i = itemrep();</lang>

PostScript

Works with: PostScript version level-2

<lang postscript> %open stdin for reading (and name the channel "kbd"):

/kbd (%stdin) (r) file def
%make ten-char buffer to read string into:
/buf (..........) def
%read string into buffer:
kbd buf readline</lang>

At this point there will be two items on the stack: a boolean which is "true" if the read was successful and the string that was read from the kbd (input terminates on a <return>). If the length of the string exceeds the buffer length, an error condition occurs (rangecheck). For the second part, the above could be followed by this:

<lang postscript> %if the read was successful, convert the string to integer:

{cvi} if</lang>

which will read the conversion operator 'cvi' (convert to integer) and the boolean and execute the former if the latter is true.

PowerShell

<lang powershell> $string = Read-Host "Input a string"

$number = Read-Host "Input a number"</lang>

Python

Input a string

<lang python> string = raw_input("Input a string: ")</lang> In Python 3.0, raw_input will be renamed to input(). The Python 3.0 equivalent would be <lang python> string = input("Input a string: ")</lang>

Input a number

While input() gets a string in Python 3.0, in 2.x it is the equivalent of eval(raw_input(...)). Because this runs arbitrary code, and just isn't nice, it is being removed in Python 3.0. raw_input() is being changed to input() because there will be no other kind of input function in Python 3.0. <lang python> number = input("Input a number: ") # Deprecated, please don't use.</lang> Python 3.0 equivalent: <lang python> number = eval(input("Input a number: ")) # Evil, please don't use.</lang> The preferred way of getting numbers from the user is to take the input as a string, and pass it to any one of the numeric types to create an instance of the appropriate number. <lang python> number = float(raw_input("Input a number: "))</lang> Python 3.0 equivalent: <lang python> number = float(input("Input a number: "))</lang> float may be replaced by any numeric type, such as int, complex, or decimal.Decimal. Each one varies in expected input.

R

Works with: R version 2.81

<lang R> stringval <- readline("String: ") intval <- as.integer(readline("Integer: ")) </lang>

Raven

<lang raven> 'Input a string: ' print expect as str

'Input an integer: ' print expect 0 prefer as num</lang>

REXX

<lang rexx>do until i = 75000

 say "Input 75000"
 pull i

end</lang>

Ruby

Works with: Ruby version 1.8.4

<lang ruby> print "Enter a string: "

s = gets
print "Enter an integer: "
i = gets.to_i   # If string entered, will return zero
puts "String  = " + s
puts "Integer = " + i.to_s</lang>

Scheme

The read procedure is R5RS standard, inputs a scheme representation so, in order to read a string, one must enter "hello world" <lang scheme> (define str (read))

 (define num (read))
 (display "String = ") (display str)
 (display "Integer = ") (display num)</lang>

Slate

<lang slate> print: (query: 'Enter a String: '). [| n |

 n: (Integer readFrom: (query: 'Enter an Integer: ')).
 (n is: Integer)
   ifTrue: [print: n]
   ifFalse: [inform: 'Not an integer: ' ; n printString]

] do. </lang>

Standard ML

<lang sml>print "Enter a string: "; let val str = valOf (TextIO.inputLine TextIO.stdIn) in (* note: this keeps the trailing newline *)

 print "Enter an integer: ";
 let val num = valOf (TextIO.scanStream (Int.scan StringCvt.DEC) TextIO.stdIn) in
   print (str ^ Int.toString num ^ "\n")
 end

end</lang>

Tcl

Like LISP, there is no concept of a "number" in TCL - the only real variable type is a string (whether a string might represent a number is a matter of interpretation of the string in a mathematical expression at some later time). Thus the input is the same for both tasks:

<lang tcl>set str [gets stdin] set num [gets stdin]</lang>

possibly followed by something like

<lang tcl>if {![string is integer -strict $num]} then { ...do something here...}</lang>

If the requirement is to prompt until the user enters the integer 75000, then: <lang tcl>set input 0 while {$input != 75000} {

   puts -nonewline "enter the number '75000': "
   flush stdout
   set input [gets stdin]

}</lang>

Of course, it's nicer to wrap the primitives in a procedure: <lang tcl>proc question {var message} {

   upvar 1 $var v
   puts -nonewline "$message: "
   flush stdout
   gets stdin $v

} question name "What is your name" question task "What is your quest" question doom "What is the air-speed velocity of an unladen swallow"</lang>

Toka

needs readline
." Enter a string: " readline is-data the-string
." Enter a number: " readline >number [ ." Not a number!" drop 0 ] ifFalse is-data the-number

the-string type cr
the-number . cr

UNIX Shell

Works with: Debian Almquish SHell

#!/bin/sh

read STRING
read INTEGER

Works with: Bourne Again SHell

#!/bin/bash

read STRING
read INTEGER

Vedit macro language

Get_Input(1, "Enter a string: ")
#2 = Get_Num("Enter a number: ")

Visual Basic .NET

Platform: .NET

Works with: Visual Basic .NET version 9.0+

Input an Integer

<lang vbnet>Dim i As Integer Console.WriteLine("Enter an Integer") i = Console.ReadLine()</lang>

Input an Integer With Error Handling

<lang vbnet>Dim i As Integer Dim iString As String Console.WriteLine("Enter an Integer") iString = Console.ReadLine() Try

   i = Convert.ToInt32(iString)

Catch ex As Exception

   Console.WriteLine("This is not an Integer")

End Try</lang>

Input a String

<lang vbnet>Dim i As String Console.WriteLine("Enter a String") i = Console.ReadLine()</lang>