Text processing/Max licenses in use: Difference between revisions
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=={{header|Python}}== |
=={{header|Python}}== |
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Python 2.4+ |
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<python> |
<python> |
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out = 0 |
out = 0 |
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max_out = -1 |
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max_times = [] |
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for job in open('mlijobs.txt'): |
for job in open('mlijobs.txt'): |
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if "OUT" in job: |
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out += 1 |
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else: |
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⚫ | |||
out -= 1 |
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if out |
if out > max_out: |
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max_out = out |
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⚫ | |||
if out == max_out: |
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max_times.append(job.split()[3]) |
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print "Maximum simultaneous license use is", |
print "Maximum simultaneous license use is", max_out, "at the following times:" |
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for time in |
for time in max_times: |
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print " ", time |
print " ", time</python> |
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</python> |
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Example output: |
Example output: |
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<pre>Maximum simultaneous license use is 99 at the following times: |
<pre>Maximum simultaneous license use is 99 at the following times: |
Revision as of 13:55, 17 November 2008
You are encouraged to solve this task according to the task description, using any language you may know.
A company currently pays a fixed sum for the use of a particular licensed software package. In determining if it has a good deal it decides to calculate its maximum use of the software from its license management log file.
Assume the softwares file faithfully records a checkout event when a copy of the software starts and a checkin event when the software finishes. An example of checkout and checkin events are:
License OUT @ 2008/10/03_23:51:05 for job 4974 ... License IN @ 2008/10/04_00:18:22 for job 4974
Save the 10,000 line log file from here into a local file then write a program to scan the file extracting both the maximum licenses that were out at any time, and the time(s) at which this occurs.
APL
⍝ Copy/paste file's contents into TXT (easiest), or TXT ← ⎕NREAD I ← TXT[;8+⎕IO] D ← TXT[;⎕IO+14+⍳19] lu ← +\ ¯1 * 'OI' ⍳ I mx ← (⎕IO+⍳⍴lu)/⍨lu= max ← ⌈/ lu ⎕ ← 'Maximum simultaneous license use is ' , ' at the following times:' ,⍨ ⍕max ⋄ ⎕←D[mx;] Maximum simultaneous license use is 99 at the following times: 2008/10/03_08:39:34 2008/10/03_08:40:40
Fortran
PROGRAM MAX_LICENSES IMPLICIT NONE INTEGER :: out=0, maxout=0, maxcount=0, err CHARACTER(50) :: line CHARACTER(19) :: maxtime(100) OPEN (UNIT=5, FILE="Licenses.txt", STATUS="OLD", IOSTAT=err) IF (err > 0) THEN WRITE(*,*) "Error opening file Licenses.txt" STOP END IF DO READ(5, "(A)", IOSTAT=err) line IF (err == -1) EXIT ! EOF detected IF (line(9:9) == "O") THEN out = out + 1 ELSE IF (line(9:9) == "I") THEN out = out - 1 END IF IF (out > maxout ) THEN maxout = maxout + 1 maxcount = 1 maxtime(maxcount) = line(15:33) ELSE IF (out == maxout) THEN maxcount = maxcount + 1 maxtime(maxcount) = line(15:33) END IF END DO CLOSE(5) WRITE(*,"(A,I4,A)") "Maximum simultaneous license use is", maxout, " at the following times:" WRITE(*,"(A)") maxtime(1:maxcount) END PROGRAM MAX_LICENSES
Output
Maximum simultaneous license use is 99 at the following times: 2008/10/03_08:39:34 2008/10/03_08:40:40
J
NB. Parse data, select columns 'I D' =: (8 ; 14+i.19) { ::]"1 L:0 ];._2 ] 1!:1 ::(''"_) <'licenses.txt' NB. Calculate number of licenses used at any given time lu =: +/\ _1 ^ 'OI' i. I NB. Find the maxima mx =: (I.@:= >./) lu NB. Output results (mx { D) ,~ 'Maximum simultaneous license use is ' , ' at the following times:' ,~ ": {. ,mx { lu Maximum simultaneous license use is 99 at the following times: 2008/10/03_08:39:34 2008/10/03_08:40:40
Python
<python> out = 0 max_out = -1 max_times = []
for job in open('mlijobs.txt'):
if "OUT" in job: out += 1 else: out -= 1 if out > max_out: max_out = out max_times = [] if out == max_out: max_times.append(job.split()[3])
print "Maximum simultaneous license use is", max_out, "at the following times:" for time in max_times:
print " ", time</python>
Example output:
Maximum simultaneous license use is 99 at the following times: 2008/10/03_08:39:34 2008/10/03_08:40:40