Text processing/Max licenses in use: Difference between revisions

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Revision as of 22:06, 5 October 2008

A company currently pays a fixed sum for the use of a particular licensed software package. In determining if it has a good deal it decides to calculate its maximum use of the software from its license management log file.

Assume the softwares file faithfully records a checkout event when a copy of the software starts and a checkin event when the software finishes. An example of checkout and checkin events are:

 License OUT @ 2008/10/03_23:51:05 for job 4974
 ...
 License IN  @ 2008/10/04_00:18:22 for job 4974

Save the 10,000 line log file from here into a local file then write a program to scan the file extracting both the maximum licenses that were out at any time, and the time(s) at which this occurs.

Fortran

Works with: Fortran version 90 and later

PROGRAM MAX_LICENSES
  IMPLICIT NONE

  INTEGER :: out=0, maxout=0, maxcount=0, err
  CHARACTER(50) :: line
  CHARACTER(19) :: maxtime(100)

  OPEN (UNIT=5, FILE="Licenses.txt", STATUS="OLD", IOSTAT=err)
  IF (err > 0) THEN
    WRITE(*,*) "Error opening file Licenses.txt"
    STOP
  END IF

  DO 
    READ(5, "(A)", IOSTAT=err) line
    IF (err == -1) EXIT          ! EOF detected
    IF (line(9:9) == "O") THEN
      out = out + 1
    ELSE IF (line(9:9) == "I") THEN
      out = out - 1
    END IF
    IF (out > maxout ) THEN
      maxout = maxout + 1
      maxcount = 1
      maxtime(maxcount) = line(15:33)
    ELSE IF (out == maxout) THEN
      maxcount = maxcount + 1
      maxtime(maxcount) = line(15:33)
    END IF
  END DO
 
  CLOSE(5)
 
  WRITE(*,"(A,I4,A)") "Maximum simultaneous license use is", maxout, " at the following times:"
  WRITE(*,"(A)") maxtime(1:maxcount)
 
END PROGRAM MAX_LICENSES

Output

Maximum simultaneous license use is  99 at the following times:
2008/10/03_08:39:34                                           
2008/10/03_08:40:40

J

   NB.  Parse data, select columns
   'I D' =: (8 ; 14+i.19) { ::]"1 L:0 ];._2 ] 1!:1 ::(''"_) <'licenses.txt'
   
   NB.  Calculate number of licenses used at any given time
   lu    =:  +/\ _1 ^ 'OI' i. I
   
   NB.  Find the maxima
   mx    =:  (I.@:= >./) lu
  
   NB.  Output results
   (mx { D) ,~ 'Maximum simultaneous license use is ' , ' at the following times:' ,~ ": {. ,mx { lu
Maximum simultaneous license use is 99 at the following times:
2008/10/03_08:39:34                                           
2008/10/03_08:40:40

Python

Python 2.6 <python>def max_out(logfile):

   maxout = 0
   maxouttimes = []
   out = 0
   for line in logfile:
       direction = line[8]
       time = line[14:33]
       if direction == 'O':
           out += 1
           if out > maxout:
               maxout = out
               maxouttimes = [time]
           elif out == maxout:
               maxouttimes.append(time)
       else:
           out -=1
   return maxout, maxouttimes

if __name__ == '__main__':

   log = file('license_example_log.txt')
   maxout, maxouttimes = max_out(log)
   log.close()
   print "Maximum simultaneous license use is %i at the following times:\n %s" % (
       maxout, '\n '.join(maxouttimes))</python>

Example output:

Maximum simultaneous license use is 99 at the following times:
 2008/10/03_08:39:34
 2008/10/03_08:40:40

@@ Line 8: / Line 8: @@
-Save the 10,000 line log file from [http://docs.google.com/View?docid=dxbvd2v_4fg4pr8dg here]* into a local file then write a program to scan the file extracting both the maximum licenses that were out at any time, and the time(s) at which this occurs.
+Save the 10,000 line log file from [http://rosettacode.org/mlijobs.txt here] into a local file then write a program to scan the file extracting both the maximum licenses that were out at any time, and the time(s) at which this occurs.
-*Note: The page uses javascript to display a text file, so it may be best to cut-n-paste from a browser to a text file rather than downloading the URL.
 == {{header|Fortran}} ==