Talk:Zumkeller numbers: Difference between revisions
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if (n % 2 || d.size() >= 24) |
if (n % 2 || d.size() >= 24) |
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return true;</pre> |
return true;</pre> |
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99504 has 28 divisors and is not a zumkeller number. |
99504 has 28 divisors and is not a zumkeller number.<BR> |
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Testet with GO version: |
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<lang go>func main() { |
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fmt.Println("The first 220 Zumkeller numbers are:") |
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for i, count := 99500, 0; count < 5; i++ { |
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if isZumkeller(i) { |
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fmt.Printf("%3d ", i)</lang> |
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<pre> |
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99500 99510 99512 99516 99520 </pre> |
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Testet with cpp version: |
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<lang cpp> |
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int main() { |
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cout << "First 220 Zumkeller numbers:" << endl; |
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vector<uint> zumz; |
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for (uint n = 99500; zumz.size() < 5; n++) |
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if (isZum(n)) |
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zumz.push_back(n); |
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cout << zumz << endl << endl; |
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... |
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// if we get here and n is odd or n has at least 24 divisors it's a zum! |
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if (n % 2 || d.size() >= 29) |
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return true;</lang> |
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<pre> |
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99500 99504 99510 99512 99516 </pre> |
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[[user horsth|Horsth]] 06:56, 9 May 2021 (UTC) |
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Revision as of 07:14, 9 May 2021
Why this limitation in c++
// if we get here and n is odd or n has at least 24 divisors it's a zum!
if (n % 2 || d.size() >= 24)
return true;
99504 has 28 divisors and is not a zumkeller number.
Testet with GO version:
<lang go>func main() {
fmt.Println("The first 220 Zumkeller numbers are:")
for i, count := 99500, 0; count < 5; i++ {
if isZumkeller(i) {
fmt.Printf("%3d ", i)</lang>
99500 99510 99512 99516 99520
Testet with cpp version: <lang cpp> int main() {
cout << "First 220 Zumkeller numbers:" << endl;
vector<uint> zumz;
for (uint n = 99500; zumz.size() < 5; n++)
if (isZum(n))
zumz.push_back(n);
cout << zumz << endl << endl;
...
// if we get here and n is odd or n has at least 24 divisors it's a zum!
if (n % 2 || d.size() >= 29)
return true;</lang>
99500 99504 99510 99512 99516
Horsth 06:56, 9 May 2021 (UTC)