Talk:Zeckendorf arithmetic: Difference between revisions
Content added Content deleted
mNo edit summary |
|||
| Line 7: | Line 7: | ||
My output matches the first test of the tcl entry, which obviously also disagrees with the Perl output. |
My output matches the first test of the tcl entry, which obviously also disagrees with the Perl output. |
||
In turn the next line is 100101 -z 100 = 100010 # subtraction, which I read as 17-3 = 15. |
In turn the next line is 100101 -z 100 = 100010 # subtraction, which I read as 17-3 = 15. |
||
Obviously, you can refer to [[Zeckendorf_number_representation#Perl_6]] to confirm or dispute my findings. |
|||
[[User:Petelomax|Pete Lomax]] ([[User talk:Petelomax|talk]]) 22:32, 21 August 2018 (UTC) |
|||
Revision as of 01:09, 22 August 2018
Spelling should be "arithmetic".
- Got it. --Mwn3d 14:45, 29 October 2012 (UTC)
Perl 6 error
I get 10100 + 1010 = 101000, aka 11 + 7 = 18 which contradicts the Perl 6 output of 10100 +z 1010 = 100101 # addition.
My output matches the first test of the tcl entry, which obviously also disagrees with the Perl output.
In turn the next line is 100101 -z 100 = 100010 # subtraction, which I read as 17-3 = 15.
Obviously, you can refer to Zeckendorf_number_representation#Perl_6 to confirm or dispute my findings.
Pete Lomax (talk) 22:32, 21 August 2018 (UTC)