Talk:Monty Hall problem: Difference between revisions
(Monty Hall problem is FALSE yo) |
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alright, now lets say each O is a door- |
alright, now lets say each O is a door- |
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door #'s: 1 2 3 |
door #'s: 1 2 3 |
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doors: O O O |
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probability: 1/3 1/3 1/3 |
probability: 1/3 1/3 1/3 |
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okay each door has a 1/3 chance; but the two on the left have 66% chance.correct, |
okay each door has a 1/3 chance; but the two on the left have 66% chance.correct, |
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and I was looking at this and they were using larger numbers to try and explain it, this is what I think: |
and I was looking at this and they were using larger numbers to try and explain it, this is what I think: |
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door #'s: 1 2 3 4 5 6 7 8 9 10 |
door #'s: 1 2 3 4 5 6 7 8 9 10 |
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doors: O O O O O O O O O O |
doors: O O O O O O O O O O |
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So each door has a 10% chance |
So each door has a 10% chance |
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lets say we open all the doors except for door 7 and door 9. Now you would think it's in door 7, BUT thats not true now we just have two doors and TWO doors only not 10 but Two: |
lets say we open all the doors except for door 7 and door 9. Now you would think it's in door 7, BUT thats not true now we just have two doors and TWO doors only not 10 but Two: |
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door #'s: 7 9 |
door #'s: 7 9 |
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Doors: O O |
Doors: O O |
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okay and now they both have a 50/50 chance. PROBLEM? |
okay and now they both have a 50/50 chance. PROBLEM? |
Revision as of 05:44, 13 April 2011
I dont beleive everyone else, This is my theory:
alright, now lets say each O is a door-
door #'s: 1 2 3 doors: O O O probability: 1/3 1/3 1/3
okay each door has a 1/3 chance; but the two on the left have 66% chance.correct, So now say we pick one for example, door 3; awesome possum, so we say that it has a 33% chance of it being a car. So now we open door 2 and it's a goat. Now some think that door one still has a 66% chance and door 3 has 33% chance, but thats not true because now we only have 2 numbers; therefore it's 50/50 chance between the two
and I was looking at this and they were using larger numbers to try and explain it, this is what I think:
door #'s: 1 2 3 4 5 6 7 8 9 10 doors: O O O O O O O O O O
So each door has a 10% chance now say we predict door 9; at this point, you only have a 1 in 10 chance of getting it right. now next step:
lets say we open all the doors except for door 7 and door 9. Now you would think it's in door 7, BUT thats not true now we just have two doors and TWO doors only not 10 but Two:
door #'s: 7 9 Doors: O O
okay and now they both have a 50/50 chance. PROBLEM?
Well then,This is what I think, my friend tells me I'm crazy but I just don't know.