Talk:Frobenius numbers: Difference between revisions

Content added Content deleted

Inline

Revision as of 23:49, 1 April 2021

title of this task

These are not Frobenius primes. Indeed, some numbers of this series aren't prime.

According to OEIS, they are known as the Frobenius number of the numerical semi-group generated by prime(n) and prime(n+1) (as noted in the OEIS entry A037165 by Victoria A. Sapko). They are also known as Frobenius numbers. -- Gerard Schildberger (talk) 22:57, 1 April 2021 (UTC)

task clarification

It appears that when the task's author stated:

      a(n) = prime(n)*prime(n+1) - prime(n) - prime(n+1), where prime(n) < 10,000

it was meant to mean:

      a(n) = prime(n)*prime(n+1) - prime(n) - prime(n+1), where a(n)     < 10,000

This is based on the output for the Ring example's output. -- Gerard Schildberger (talk) 23:33, 1 April 2021 (UTC)

task wording

I think that the task description would read better with:

     FrobeniusNumber(n)  =  prime(n)*prime(n+1) - prime(n) - prime(n+1), where FrobeniusNumber(n) < 10,000

instead of using a(n). -- Gerard Schildberger (talk) 23:48, 1 April 2021 (UTC)

@@ Line 7: / Line 7: @@
 It appears that when the task's author stated:
-      <big> a(n) = prime(n)*prime(n+1) - prime(n) - prime(n+1), where '''prime(n) < 10,000''' </big>
+      <big> a(n) = prime(n)*prime(n+1) - prime(n) - prime(n+1), where '''prime(n) &lt; 10,000''' </big>
 it was meant to mean:
-      <big> a(n) = prime(n)*prime(n+1) - prime(n) - prime(n+1), where '''a(n) < 10,000'''       </big>
+      <big> a(n) = prime(n)*prime(n+1) - prime(n) - prime(n+1), where '''a(n)     &lt; 10,000''' </big>
 This is based on the output for the &nbsp; '''Ring''' &nbsp; example's output. &nbsp; &nbsp; -- [[User:Gerard Schildberger|Gerard Schildberger]] ([[User talk:Gerard Schildberger|talk]]) 23:33, 1 April 2021 (UTC)
+== task wording ==
+I think that the task description would read better with:
+     <big> FrobeniusNumber(n)  =  prime(n)*prime(n+1) - prime(n) - prime(n+1), where '''FrobeniusNumber(n) &lt; 10,000''' </big>
+instead of using &nbsp; '''a(n)'''. &nbsp; &nbsp; -- [[User:Gerard Schildberger|Gerard Schildberger]] ([[User talk:Gerard Schildberger|talk]]) 23:48, 1 April 2021 (UTC)