Sum of the digits of n is substring of n: Difference between revisions

Content added Content deleted
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<lang 11l>V count = 0
<lang 11l>V count = 0
L(n) 1000
L(n) 1000
I String(sum(String(n).map(d -> Int(d)))) C String(n)
I String(sum(String(n).map(Int))) C String(n)
count++
count++
print(f:‘{n:3}’, end' I count % 8 == 0 {"\n"} E ‘ ’)</lang>
print(f:‘{n:3}’, end' I count % 8 == 0 {"\n"} E ‘ ’)</lang>