Sum of the digits of n is substring of n: Difference between revisions

Content added Content deleted
(Added solution for Action!)
(Added 11l)
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{{Template:Strings}}
{{Template:Strings}}
<br><br>
<br><br>

=={{header|11l}}==
{{trans|Nim}}

<lang 11l>V count = 0
L(n) 1000
I String(sum(String(n).map(d -> Int(d)))) C String(n)
count++
print(f:‘{n:3}’, end' I count % 8 == 0 {"\n"} E ‘ ’)</lang>

{{out}}
<pre>
0 1 2 3 4 5 6 7
8 9 10 20 30 40 50 60
70 80 90 100 109 119 129 139
149 159 169 179 189 199 200 300
400 500 600 700 800 900 910 911
912 913 914 915 916 917 918 919
</pre>


=={{header|8080 Assembly}}==
=={{header|8080 Assembly}}==