ABC problem: Difference between revisions
Easylang
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"sQuAd" can be spelled with blocks.
"Confuse" can be spelled with blocks.</pre>
=={{header|EasyLang}}==
<syntaxhighlight lang="easylang">
b$[][] = [ [ "B" "O" ] [ "X" "K" ] [ "D" "Q" ] [ "C" "P" ] [ "N" "A" ] [ "G" "T" ] [ "R" "E" ] [ "T" "G" ] [ "Q" "D" ] [ "F" "S" ] [ "J" "W" ] [ "H" "U" ] [ "V" "I" ] [ "A" "N" ] [ "O" "B" ] [ "E" "R" ] [ "F" "S" ] [ "L" "Y" ] [ "P" "C" ] [ "Z" "M" ] ]
len b[] len b$[][]
global w$[] cnt .
#
proc backtr wi . .
if wi > len w$[]
cnt += 1
return
.
for i = 1 to len b$[][]
if b[i] = 0 and (b$[i][1] = w$[wi] or b$[i][2] = w$[wi])
b[i] = 1
backtr wi + 1
b[i] = 0
.
.
.
for s$ in [ "A" "BARK" "BOOK" "TREAT" "COMMON" "SQUAD" "CONFUSE" ]
w$[] = strchars s$
cnt = 0
backtr 1
print s$ & " can be spelled in " & cnt & " ways"
.
</syntaxhighlight>
{{out}}
<pre>
A can be spelled in 2 ways
BARK can be spelled in 8 ways
BOOK can be spelled in 0 ways
TREAT can be spelled in 8 ways
COMMON can be spelled in 0 ways
SQUAD can be spelled in 8 ways
CONFUSE can be spelled in 32 ways
</pre>
=={{header|EchoLisp}}==
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