Shoelace formula for polygonal area: Difference between revisions
Added 11l
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Show the answer here, on this page.
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=={{header|11l}}==
{{trans|Python}}
<lang 11l>F area_by_shoelace(x, y)
R abs(sum(zip(x, y[1..] [+] y[0.<1]).map((i, j) -> i * j))
-sum(zip(x[1..] [+] x[0.<1], y).map((i, j) -> i * j))) / 2
V points = [(3, 4), (5, 11), (12, 8), (9, 5), (5, 6)]
V x = points.map(p -> p[0])
V y = points.map(p -> p[1])
print(area_by_shoelace(x, y))</lang>
{{out}}
<pre>
30
</pre>
=={{header|360 Assembly}}==
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