Apply a digital filter (direct form II transposed): Difference between revisions
Apply a digital filter (direct form II transposed) (view source)
Revision as of 01:11, 16 April 2020
, 4 years ago→{{header|Rust}}
SqrtNegInf (talk | contribs) m (→{{header|Sidef}}: Fix link: Perl 6 --> Raku) |
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20 0.651770838819
</pre>
=={{header|Ruby}}==
{{trans|C#}}
<lang ruby>def filter(a,b,signal)
result = Array.new(signal.length(), 0.0)
for i in 0..signal.length()-1 do
tmp = 0.0
for j in 0 .. b.length()-1 do
if i - j < 0 then next end
tmp += b[j] * signal[i - j]
end
for j in 1 .. a.length()-1 do
if i - j < 0 then next end
tmp -= a[j] * result[i - j]
end
tmp /= a[0]
result[i] = tmp
end
return result
end
def main
a = [1.00000000, -2.77555756e-16, 3.33333333e-01, -1.85037171e-17]
b = [0.16666667, 0.5, 0.5, 0.16666667]
signal = [
-0.917843918645, 0.141984778794, 1.20536903482, 0.190286794412,
-0.662370894973, -1.00700480494, -0.404707073677, 0.800482325044,
0.743500089861, 1.01090520172, 0.741527555207, 0.277841675195,
0.400833448236, -0.2085993586, -0.172842103641, -0.134316096293,
0.0259303398477, 0.490105989562, 0.549391221511, 0.9047198589
]
result = filter(a,b,signal)
for i in 0 .. result.length() - 1 do
print "%11.8f" % [result[i]]
if (i + 1) % 5 == 0 then
print "\n"
else
print ", "
end
end
end
main()</lang>
{{out}}
<pre>-0.15297399, -0.43525783, -0.13604340, 0.69750333, 0.65644469
-0.43548245, -1.08923946, -0.53767655, 0.51704999, 1.05224975
0.96185430, 0.69569009, 0.42435630, 0.19626223, -0.02783512
-0.21172192, -0.17474556, 0.06925841, 0.38544587, 0.65177084</pre>
=={{header|Rust}}==
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