Runtime evaluation/In an environment

Runtime evaluation/In an environment
You are encouraged to solve this task according to the task description, using any language you may know.

Given a program in the language representing a function, evaluate it with the variable x (or another name if that is not valid) bound to a provided value, then evaluate it again with x bound to another provided value, then subtract the result of the first from the second and return or print it.

Preferably, do so in a way which does not involve string manipulation of source code, and is plausibly extensible to a runtime-chosen set of bindings.

For more general examples and language-specific details, see Eval.

Common Lisp

<lang lisp> (defun eval-with-x (program a b)

 (let ((at-a (eval `(let ((x ',a)) ,program)))
       (at-b (eval `(let ((x ',b)) ,program))))
   (- at-b at-a)))

</lang>

<lang lisp> (eval-with-x '(exp x) 0 1) => 1.7182817 </lang>

This version ensures that the program is compiled, once, for more efficient execution:

<lang lisp> (defun eval-with-x (program a b)

 (let* ((f (compile nil `(lambda (x) ,program)))
        (at-a (funcall f a))
        (at-b (funcall f b)))
   (- at-b at-a)))

</lang>

Perl

<lang perl>our $x;

 # Only necessary if "use strict" is in effect or a
 # lexical $x (declared with "my") exists in this scope.

sub eval_with_x

  {my $code = shift;
   local $x = shift;
   my $first = eval $code;
   local $x = shift;
   return eval($code) - $first;}

print eval_with_x('3 * $x', 5, 10), "\n"; # Prints "15\n".</lang>

Note that this is a dynamic, not lexical, binding of $x.

Python

<lang python>code = raw_input('f(x): ') x = [input('x[%i]: ' % i) for i in [0,1]] fx = [eval(code, {"x": xv}) for xv in x] print "f({x[0]}) = {f0}; f({x[1]}) = {f1}; f({x[1]}) - f({x[0]}) = {ans}".format(

   x=x, f0=fx[0], f1=fx[1], ans= fx[1] - fx[0] )</lang>

Typical use would be (user input is after the initial colon in a line): <lang python>f(x): 2**x x[0]: 3 x[1]: 5 f(3) = 8; f(5) = 32; f(5) - f(3) = 24</lang>

Ruby

<lang ruby>def getBinding(x)

 return binding

end

def eval_with_x(code, a, b)

 eval(code, getBinding(b)) - eval(code, getBinding(a))

end

puts eval_with_x('2 ** x', 3, 5) # Prints "24"</lang>

Scheme

Almost identical to the Common Lisp version above. <lang scheme>(define (eval-with-x prog a b)

 (let ((at-a (eval `(let ((x ',a)) ,prog)))
       (at-b (eval `(let ((x ',b)) ,prog))))
   (- at-b at-a)))</lang>