Riordan numbers: Difference between revisions

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;Stretch
;Stretch
* Find and display the '''digit count''' of the 1000th Riordan number.
* Find and display the '''digit count''' of the 1,000th Riordan number.
* Find and display the '''digit count''' of the 10,000th Riordan number.




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my $upto = 32;
my $upto = 32;
say "First {$upto.&cardinal} Riordan numbers:\n" ~ @riordan[^$upto]».&comma».fmt("%17s").batch(4).join("\n") ~ "\n";
say "First {$upto.&cardinal} Riordan numbers:\n" ~ @riordan[^$upto]».&comma».fmt("%17s").batch(4).join("\n") ~ "\n";

say "The 1000th has {@riordan[9999].chars} digits";
sub abr ($_) { .chars < 41 ?? $_ !! .substr(0,20) ~ '..' ~ .substr(*-20) ~ " ({.chars} digits)" }
</lang>

say "The {.Int.&ordinal}: " ~ abr @riordan[$_ - 1] for 1e3, 1e4</lang>
{{out}}
{{out}}
<pre>First thirty-two Riordan numbers:
<pre>First thirty-two Riordan numbers:
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54,022,715,451 154,000,562,758 439,742,222,071 1,257,643,249,140
54,022,715,451 154,000,562,758 439,742,222,071 1,257,643,249,140


The one thousandth: 51077756867821111314..79942013897484633052 (472 digits)
The 1000th has 4765 digits</pre>
The ten thousandth: 19927418577260688844..71395322020211157137 (4765 digits)</pre>

Revision as of 18:29, 18 August 2022

Riordan numbers is a draft programming task. It is not yet considered ready to be promoted as a complete task, for reasons that should be found in its talk page.

Riordan numbers show up in several places in set theory. They are closely related to Motzkin numbers, and may be derived from them.

Riordan numbers comprise the sequence a where:

   a(0) = 1, a(1) = 0, for subsequent terms, a(n) = (n-1)*(2*a(n-1) + 3*a(n-2))/(n+1)

There are other generating functions, and you are free to use one most convenient for your language.


Task
  • Find and display the first 32 Riordan numbers.


Stretch
  • Find and display the digit count of the 1,000th Riordan number.
  • Find and display the digit count of the 10,000th Riordan number.


See also



Raku

<lang perl6>use Lingua::EN::Numbers;

my @riordan = 1, 0, { state $n = 1; (++$n - 1) / ($n + 1) × (3 × $^a + 2 × $^b) } … *;

my $upto = 32; say "First {$upto.&cardinal} Riordan numbers:\n" ~ @riordan[^$upto]».&comma».fmt("%17s").batch(4).join("\n") ~ "\n";

sub abr ($_) { .chars < 41 ?? $_ !! .substr(0,20) ~ '..' ~ .substr(*-20) ~ " ({.chars} digits)" }

say "The {.Int.&ordinal}: " ~ abr @riordan[$_ - 1] for 1e3, 1e4</lang>

Output:
First thirty-two Riordan numbers:
                1                 0                 1                 1
                3                 6                15                36
               91               232               603             1,585
            4,213            11,298            30,537            83,097
          227,475           625,992         1,730,787         4,805,595
       13,393,689        37,458,330       105,089,229       295,673,994
      834,086,421     2,358,641,376     6,684,761,125    18,985,057,351
   54,022,715,451   154,000,562,758   439,742,222,071 1,257,643,249,140

The one thousandth: 51077756867821111314..79942013897484633052 (472 digits)
The ten thousandth: 19927418577260688844..71395322020211157137 (4765 digits)