Minimum numbers of three lists: Difference between revisions
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(Created page with "{{Draft task}} ;Task:Let given three lists: <br>Numbers1 = [5,45,23,21,67] <br>Numbers2 = [43,22,78,46,38] <br>Numbers3 = [9,98,12,98,53] <br>Select the minimum of Numbers[n]...") |
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;Task:Let given three lists: |
;Task:Let given three lists: |
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Numbers1 = [5,45,23,21,67] |
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<br>Numbers2 = [43,22,78,46,38] |
<br>Numbers2 = [43,22,78,46,38] |
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<br>Numbers3 = [9,98,12,98,53] |
<br>Numbers3 = [9,98,12,98,53] |
Revision as of 08:56, 26 October 2021
Minimum numbers of three lists is a draft programming task. It is not yet considered ready to be promoted as a complete task, for reasons that should be found in its talk page.
- Task
- Let given three lists:
Numbers1 = [5,45,23,21,67]
Numbers2 = [43,22,78,46,38]
Numbers3 = [9,98,12,98,53]
Select the minimum of Numbers[n], Numbers2[n] and Numbers3[n], where n <= 5
Add minimum to a new list (Numbers)
Show Numbers on this page.
Ring
<lang ring> see "working..." + nl
Numbers = [] Numbers1 = [5,45,23,21,67] Numbers2 = [43,22,78,46,38] Numbers3 = [9,98,12,98,53]
for n = 1 to len(Numbers1)
Temp = [] add(Temp,Numbers1[n]) add(Temp,Numbers2[n]) add(Temp,Numbers3[n]) min = min(Temp) add(Numbers,min)
next
see "The minimum numbers of three lists = " see showArray(Numbers) see nl + "done..." + nl
func showArray(array)
txt = "" see "[" for n = 1 to len(array) txt = txt + array[n] + "," next txt = left(txt,len(txt)-1) txt = txt + "]" see txt
</lang>
- Output:
working... The minimum numbers of three lists = [5,22,12,21,38] done...