Largest five adjacent number: Difference between revisions
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{{out|Sample output (it's random)}} |
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<pre>99625</pre> |
<pre>99625</pre> |
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=={{header|Julia}}== |
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<lang julia>dig = rand(0:9, 1000) |
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@show maximum(evalpoly(10, dig[i:i+4]) for i in 1:length(dig)-4) |
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</lang>{{out}} |
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<pre> |
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maximum((evalpoly(10, dig[i:i + 4]) for i = 1:length(dig) - 4)) = 99993 |
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</pre> |
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=={{header|Ring}}== |
=={{header|Ring}}== |
Revision as of 17:09, 27 September 2021
Largest five adjacent number is a draft programming task. It is not yet considered ready to be promoted as a complete task, for reasons that should be found in its talk page.
- Task
Generate random 1000-digit number.
Find the five adjacent digits in the 1000-digit number that is largest.
Raku
<lang perl6>say (^10).roll(1000).rotor(5 => -4)».join.max</lang>
- Sample output (it's random):
99625
Julia
<lang julia>dig = rand(0:9, 1000) @show maximum(evalpoly(10, dig[i:i+4]) for i in 1:length(dig)-4)
</lang>
- Output:
maximum((evalpoly(10, dig[i:i + 4]) for i = 1:length(dig) - 4)) = 99993
Ring
<lang ring> digit = "" max = 0 maxOld = 0 limit = 1000
for n = 1 to limit
rand = random(9) randStr = string(rand) digit += randStr
next
for n = 1 to len(digit)-5
res = substr(digit,n,5) resNum = number(res) if resNum > maxold max = resNum maxOld = max ok
next
see max + nl </lang>
- Output:
The largest number is: 99638
Wren
Very simple approach as there's little need for speed here. <lang ecmascript>import "random" for Random import "/fmt" for Fmt
var rand = Random.new() var digits = List.filled(1000, 0) for (i in 0...999) digits[i] = rand.int(10) var number = digits.join() for (i in 99999...0) {
var quintet = Fmt.swrite("$05d", i) if (number.contains(quintet)) { Fmt.print("The largest number formed from 5 adjacent digits is: $,d", i) return }
}</lang>
- Output:
Sample output:
The largest number formed from 5 adjacent digits is: 99,850