Lagrange Interpolation: Difference between revisions
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var scalarMultiply = Fn.new { |poly, x| poly.map { |coef| coef * x }.toList } |
var scalarMultiply = Fn.new { |poly, x| poly.map { |coef| coef * x }.toList } |
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// Divide a |
// Divide a polynomial by a scalar. |
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var scalarDivide = Fn.new { |poly, x| scalarMultiply.call(poly, 1/x) } |
var scalarDivide = Fn.new { |poly, x| scalarMultiply.call(poly, 1/x) } |
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// Returns the Lagrange interpolating polynomial which passes through a list of points. |
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var lagrange = Fn.new { |pts| |
var lagrange = Fn.new { |pts| |
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var c = pts.count |
var c = pts.count |
Revision as of 18:20, 5 September 2023
Lagrange Interpolation is a draft programming task. It is not yet considered ready to be promoted as a complete task, for reasons that should be found in its talk page.
The task is to implement the Legrange Interpolation formula and use it to solve the example problem to find a polynomial P of degree<4 satisfying P(1)=1 P(2)=4 P(3)=1 P(4)=5 as described at [1]
- Related task Curve that touches three points
F#
// Lagrange Interpolation. Nigel Galloway: September 5th., 2023
let symbol=MathNet.Symbolics.SymbolicExpression.Variable
let qi=MathNet.Symbolics.SymbolicExpression.FromInt32
let eval (g:MathNet.Symbolics.SymbolicExpression) x=let n=Map["x",MathNet.Symbolics.FloatingPoint.Real x] in MathNet.Symbolics.Evaluate.evaluate n g.Expression
let fN g=let x=symbol "x" in g|>List.fold(fun z c->(x-c)*z)(qi 1)
let fG(n,g)=let n,g=n|>List.map qi,g|>List.map qi in List.map2(fun i g->i,g,n|>List.except [i]) n g
let LIF n=fG n|>List.sumBy(fun(ci,bi,c)->bi*(fN c)/(c|>List.fold(fun z c->(ci-c)*z)(qi 1)))
printfn $"%s{LIF([1;2;3;4],[1;4;1;5]).Expand().ToString()}"
- Output:
-21 + 215/6*x - 16*x^2 + 13/6*x^3
Wren
A polynomial is represented here by a list of coefficients from the lowest to the highest degree. However, the library methods which deal with polynomials expect the coefficients to be presented from highest to lowest degree so we therefore need to reverse the list before calling these methods.
import "./dynamic" for Tuple
import "./math" for Math
import "./fmt" for Fmt
var Point = Tuple.create("Point", ["x", "y"])
// Add two polynomials.
var add = Fn.new { |p1, p2|
var m = p1.count
var n = p2.count
var sum = List.filled(m.max(n), 0)
for (i in 0...m) sum[i] = p1[i]
for (i in 0...n) sum[i] = sum[i] + p2[i]
return sum
}
// Multiply two polynmials.
var multiply = Fn.new { |p1, p2|
var m = p1.count
var n = p2.count
var prod = List.filled(m + n - 1, 0)
for (i in 0...m) {
for (j in 0...n) prod[i+j] = prod[i+j] + p1[i] * p2[j]
}
return prod
}
// Multiply a polynomial by a scalar.
var scalarMultiply = Fn.new { |poly, x| poly.map { |coef| coef * x }.toList }
// Divide a polynomial by a scalar.
var scalarDivide = Fn.new { |poly, x| scalarMultiply.call(poly, 1/x) }
// Returns the Lagrange interpolating polynomial which passes through a list of points.
var lagrange = Fn.new { |pts|
var c = pts.count
var polys = List.filled(c, null)
for (i in 0...c) {
var poly = [1]
for (j in 0...c) {
if (i == j) continue
poly = multiply.call(poly, [-pts[j].x, 1])
}
var d = Math.evalPoly(poly[-1..0], pts[i].x)
polys[i] = scalarDivide.call(poly, d)
}
var sum = [0]
for (i in 0...c) {
polys[i] = scalarMultiply.call(polys[i], pts[i].y)
sum = add.call(sum, polys[i])
}
return sum
}
var pts = [
Point.new(1, 1),
Point.new(2, 4),
Point.new(3, 1),
Point.new(4, 5)
]
var lip = lagrange.call(pts)
Fmt.pprint("$f", lip[-1..0], "", "x")
- Output:
2.166667x³ - 16.000000x² + 35.833333x - 21.000000