Input/Output for pairs of numbers: Difference between revisions

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From lines of input starting with a line containing the numbers of pairs to follows, followed by that number of pairs of integers separated by a space on separate lines from STDIN, output the sum of each pair to STDOUT.

Sample input with corresponding output

Input

Output

ALGOL 68

Simple version - there can be newlines before or between the numbers <lang algol68># read a number from stand in then read and add that many pairs of numbers from stand in #

and write the sum to stand out. If non integer data is supplied, a runtime error will occur #

TO ( INT n; read( ( n, newline ) ); n ) DO

   INT a, b;
   read( ( a, b, newline ) );
   print( ( a + b, newline ) )

OD </lang> Strict version - the pairs of numbers must appear on the same line. <lang algol68>

read a number from stand in then read and add that many pairs of numbers from stand in #
and write the sum to stand out. If non integer data is supplied, a runtime error will occur #
This version does not allow the pairs of numbers to be spread over several lines #

STRING line; FILE numbers; associate( numbers, line ); TO ( INT n

  ; read( ( line, newline ) )
  ; reset( numbers )
  ; get( numbers, ( n ) )
  ; n
  )

DO

   INT a, b;
   read( ( line, newline ) );
   reset( numbers );
   get( numbers, ( a, b ) );
   print( ( a + b, newline ) )

OD</lang>

Output:

AWK

<lang awk>NR == 1 {n=$1; next} NR > n+1 {exit} {print $1+$2}</lang>

BBC BASIC

The specification is a bit ambiguous, but I understood it as wanting us to read all the numbers in first and then print all the sums. This program does that. It could be a couple of lines shorter if we were allowed to use a comma instead of a space as separator. <lang bbcbasic>INPUT n% DIM pairs%(n% - 1, 1) FOR i% = 0 TO n% - 1

 INPUT s$
 pairs%(i%, 0) = VAL(LEFT$(s$, INSTR(s$, " ")))
 pairs%(i%, 1) = VAL(MID$(s$, INSTR(s$, " ")))

NEXT FOR i% = 0 TO n% - 1

 PRINT pairs%(i%, 0) + pairs%(i%, 1)

NEXT</lang> With the sample inputs:

C

<lang C>#include <stdio.h>

include <stdlib.h>

int main(void) { int i, n, a, b, *f; scanf("%d", &n); f = malloc(sizeof(*f) * n);

for (i = 0; i < n; i++) { if (2 != scanf("%d %d", &a, &b)) abort(); f[i] = a + b; }

for (i = 0; i < n; i++) printf("%d\n", f[i]);

return 0; }</lang>

Output for example input

C++

Modified in order to take in all inputs and then give the output, the original gave the output for each pair immediately. <lang cpp> /*Modified by Abhishek Ghosh, 19th March 2014, Rotterdam*/

include <iostream>

using namespace std;

int doStuff(int a, int b) {

   return a + b;

}

int main() {

int t, **list;

cin >> t;

list = new int*[t];

for(int j=0; j<t; j++){

list[j] = new int[2]; cin >> list[j][0]>> list[j][1];

}

cout << endl;

for(int j=0;j<t;j++){ cout << doStuff(list[j][0], list[j][1]) << endl;; } return 0; } </lang>

Run as per given input

D

This works with any number of integers on lines. <lang d>void main() {

   import std.stdio, std.string, std.conv, std.algorithm;

   foreach (immutable _; 0 .. readln.strip.to!uint)
       readln.split.to!(int[]).sum.writeln;

}</lang>

Fortran

Works with: Fortran version 95 and later

<lang fortran>program i_o_pairs

 implicit none

 integer :: npairs
 integer :: i
 integer, allocatable :: pairs(:,:)

 read(*,*) npairs
 allocate(pairs(npairs,2))

 do i = 1, npairs
   read(*,*) pairs(i,:)
 end do
 write(*, "(i0)") sum(pairs, 2)

end program</lang>

FreeBASIC

<lang freebasic>' FB 1.05.0 Win64

Dim As UInteger n Dim As Integer x, y Input "", n Dim sums(1 To n) As Integer For i As Integer = 1 To n

 Input "", x, y
 sums(i) =  x + y

Next Print For i As Integer = 1 To n

 Print Str(sums(i))

Next Sleep</lang>

Output:

Haskell

This solution will actually add any number of integers placed on each line. Additionally, after removing the bits of code that cut out the specified number of lines, the solution will sum any number of lines of integers.

<lang Haskell>main = do

   contents <- getContents
   let numberOfLines  =  read.head.lines$ contents
       nums  =  map (map read.words).take numberOfLines.tail.lines$ contents
       sums  =  map sum nums
   mapM_ print sums</lang>

Go

<lang go>package main

import ( "fmt" "log" )

func main() { var lines int n, err := fmt.Scanln(&lines) if n != 1 || err != nil { log.Fatal(err) }

var a, b int for ; lines > 0; lines-- { n, err = fmt.Scanln(&a, &b) if n != 2 || err != nil { log.Fatal(err) } fmt.Println(a + b) } }</lang>

J

<lang J> $ cat <<EOF | jconsole -js '([: exit 0: [: smoutput [: ,. [: ({. {. }.) [: (+/"1) [: (0&".;._2) (1!:1)) 3' > 5 > 1 2 > 10 20 > -3 5 > 100 2 > 5 5 > EOF

 3
30
 2

102

</lang> Considerably simpler than [explanation] output for lines of text, this sentence is a single fork. J pads the numeric arrays of 0&".;._2 (numbers cut) with 0 . We form the +/"1 (row sums), then take the sum of the first row of the beheaded sums ({. {. }.) for display. ,. (raveled items) reshapes the vector into a column-vector shaped matrix. And the [: (cap) causes the monadic form of the verb to cap's right.

Java

<lang java>import java.util.Scanner;

public class Main {

public static int doStuff(int a, int b){ int sum = a+b; return sum; }

public static void main(String[] args) { Scanner in = new Scanner(System.in);

int n = in.nextInt(); for(int i=0; i<n; i++){ int a = in.nextInt(); int b= in.nextInt(); int result = doStuff(a, b); System.out.println(result); } } }</lang>

Kotlin

<lang scala>// version 1.0.6

import java.util.Scanner

fun main(args: Array<String>) {

   val sc = Scanner(System.`in`)  // note: backticks required as 'in' is a Kotlin keyword
   val n = sc.nextInt()
   val x = IntArray(n)
   val y = IntArray(n)
   for (i in 0 until n) {
       x[i] = sc.nextInt()
       y[i] = sc.nextInt()  
   }
   println()
   for (i in 0 until n) println(x[i] + y[i])

}</lang> Sample input/output:

Output:

Lua

This solution will sum any number of space-separated numbers per input line, assuming the user won't input too many to store in the available RAM. <lang Lua>local intTab, numLines, sum = {}, io.read() for i = 1, numLines do

   sum = 0
   for number in io.read():gmatch("%S+") do sum = sum + number end
   table.insert(intTab, sum)

end for _, result in pairs(intTab) do print(result) end</lang>

PARI/GP

Interestingly, this task is not possible to implement directly in GP, since input(), like the gp REPL itself, ignores spaces. One must use PARI: <lang c>#include <stdio.h>

include <stdlib.h>
include <pari/pari.h>

int main(void);

int main() {

 int i, n, a, b;
 GEN f, sum;
 pari_sp ltop;
 
 // 1 MB stack, not using prime table
 pari_init(1000000, 0);
 
 scanf("%d", &n);
 GEN f = cgetg(n+1, t_VEC);

 for (i = 1; i <= n; i++) {
   if (2 != scanf("%d %d", &a, &b)) abort();

   ltop = avma;

// Add a and b in PARI sum = addii(stoi(a), stoi(b));

// Store the sum in a vector, collecting garbage as you go. gel(f, i) = gerepileupto(ltop, sum);

 pari_printf("%Ps", f);
 return 0;

}</lang> Of course for such a simple task this has very little advantage over C, but it does demonstrate the general principle.

Perl 6

<lang perl6>for ^get() { say [+] get.words }</lang> This does more than the task asks. It will sum as many numbers as you care to put on each line, and the numbers need not be integers, but may also be a mix of rational, floating-point, or complex numbers. More subtly, get can read from a file specified as a command-line argument, but defaults to taking STDIN if no filename is specified.

Phix

<lang Phix>string line = gets(0) sequence r = scanf(trim(line),"%d"), s = {} if length(r)!=1 then

   puts(1,"input not a number\n")
   abort(0)

end if puts(1,"\n") for i=1 to r[1][1] do

   line = gets(0)
   r = scanf(trim(line),"%d %d")
   if length(r)!=1 then
       puts(1,"input not a pair of numbers\n")
       abort(0)
   end if
   s &= sum(r[1])
   puts(1,"\n")

end for puts(1,"===\n") ?s</lang>

Output:

(or more accurately the final state of the console)

5
1 2
10 20
-3 5
100 2
5 5
===
{3,30,2,102,10}

PowerShell

script.ps1

$in, $line = (Get-Content $args[0]), 0 $nb = $in[$line++] 1..$nb | foreach {

   $sum = 0
   $in[$line++].Split() | foreach{ $sum += $_} 
   $sum

}

./script file.txt

</lang>

Python

<lang python>def do_stuff(a, b): return a + b

t = input() for x in range(0, t): a, b = raw_input().strip().split() print do_stuff(int(a), int(b))</lang>

Python: Alternative

Or without the function do_stuff() and that works for Python 3 and Python 2: <lang python>>>> try: raw_input except NameError: raw_input = input

>>> for i in range(int(raw_input())): print(sum(int(numberstring) for numberstring in raw_input().strip().split()))

5 1 2 3 10 20 30 -3 5 2 100 2 102 5 5 10 >>> </lang> (All but the first line of single numbers, (the 5), is output from the program).

Python: With prompts

More than is asked for by the task, but if working interactively then the following version adds prompts. <lang python>>>> for i in range(int(raw_input('lines: '))): print(sum(int(numberstring)

                 for numberstring in raw_input('two numbers: ').strip().split()))

lines: 5 two numbers: 1 2 3 two numbers: 10 20 30 two numbers: -3 5 2 two numbers: 100 2 102 two numbers: 5 5 10 >>> </lang>

Racket

<lang Racket>#lang racket

(define line-number (read)) ;reads all kind of things
(for ([i (in-range line-number)])
(displayln (+ (read) (read))))

(define line-count (string->number ;only reads numbers

                   (string-trim (read-line))))

(for ([i (in-range line-count)])

 (displayln (apply + 
                   (map string->number 
                        (string-split (read-line))))))</lang>

REXX

This version isn't limited to summing integers, any form of number that REXX supports can be used. <lang rexx>/*REXX pgm reads a number (from C.L.), reads that # of pairs, writes their sum*/

    do  linein()                      /*read the number of pairs to be add*ed*/
    y=linein()                        /*read a line (a record) from the input*/
    say word(y,1) + word(y,2)         /*write the sum of a pair of numbers.  */
    end   /*linein() */               /*keep getting pairs of # (the 1st get)*/

                                      /*stick a fork in it,  we're all done. */</lang>

Ruby

<lang ruby>n = gets.to_i n.times do

 a, b = gets.split.map(&:to_i)
 puts a + b

end</lang>

Tcl

<lang tcl>gets stdin n while {$n > 0} {

   if {[scan [gets stdin] "%d %d" a b] == 2} {
       puts [expr {$a + $b}]
   }
   incr n -1

}</lang>

UNIX Shell

Works with: Bourne Again SHell

<lang bash>read n while (( n > 0 )); do

   read a b
   echo $((a+b))
   ((n--))

done</lang>

Ursa

<lang ursa>decl int amount set amount (in int console)

decl int<> ints for (decl int i) (< i amount) (inc i)

       decl string input
       set input (in string console)
       append (int (split input " ")<0>) (int (split input " ")<1>) ints

end for

out endl console

for (set i 0) (< i (size ints)) (set i (int (+ 2 i)))

       out (int (+ ints ints<(int (+ i 1))>)) endl console

end for</lang> Networked version. Runs on port 20000. <lang ursa>decl serverport sp decl port p sp.attach 20000 set p (sp.getconn)
decl int amount set amount (in int p)
decl int<> ints for (decl int i) (< i amount) (inc i)
decl string input set input (in string p) append (int (split input " ")<0>) (int (split input " ")<1>) ints
end for
out endl p
for (set i 0) (< i (size ints)) (set i (int (+ 2 i)))
out (int (+ ints ints<(int (+ i 1))>)) endl p
end for</lang>
zkl
Using the console as the input stream: <lang zkl>fcn pairs{
n:=ask("num pairs: ").toInt(); do(n){ask("1 pair: ").split(" ").sum().println()}
}</lang>

Output:
pairs() num pairs: 5 1 pair: 1 2 3 1 pair: 10 20 30 1 pair: -3 5 2 1 pair: 100 2 102 1 pair: 5 5 10