Hex words: Difference between revisions
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13 such words found which contain 4 or more different digits. |
13 such words found which contain 4 or more different digits. |
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</pre> |
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{{omit from|6502 Assembly|unixdict.txt is much larger than the CPU's address space.}} |
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{{omit from|8080 Assembly|See 6502 Assembly.}} |
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{{omit from|Z80 Assembly|See 6502 Assembly.}} |
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Revision as of 03:11, 14 November 2021
Hex words is a draft programming task. It is not yet considered ready to be promoted as a complete task, for reasons that should be found in its talk page.
- Definition
For the purposes of this task a hex word means a word which (in lower case form) consists entirely of the letters a, b, c, d, e and f.
- Task
Using unixdict.txt, find all hex words with 4 letters or more.
Convert each such word to its decimal equivalent and compute its base 10 digital root.
Display all three in increasing order of digital root and show the total count of such words.
Also filter out all such words which contain at least 4 distinct letters and display the same statistics but in decreasing order of decimal equivalent together with their total count.
ALGOL 68
<lang algol68># find words that contain only hex digits a-f # IF FILE input file;
STRING file name = "unixdict.txt"; open( input file, file name, stand in channel ) /= 0
THEN
# failed to open the file # print( ( "Unable to open """ + file name + """", newline ) )
ELSE
# file opened OK #
BOOL at eof := FALSE;
# set the EOF handler for the file #
on logical file end( input file, ( REF FILE f )BOOL:
BEGIN
# note that we reached EOF on the #
# latest read #
at eof := TRUE;
# return TRUE so processing can continue #
TRUE
END
);
INT count := 0;
INT max words = 100; # guess at the maximum number of words #
MODE HEXWORD = STRUCT( STRING word, LONG INT value, INT root, INT len );
[ 1 : max words ]HEXWORD hw;
WHILE STRING word;
get( input file, ( word, newline ) );
NOT at eof
DO
# check the word contains only a-f and compute its decimal value #
IF INT word len = ( UPB word + 1 ) - LWB word;
word len >= 4
THEN
# the word is at least 4 characters long #
BOOL is hex word := word /= "";
LONG INT int word := 0;
FOR i FROM LWB word TO UPB word
WHILE is hex word := word[ i ] >= "a" AND word[ i ] <= "f"
DO
int word *:= 16;
int word +:= ( ABS word[ i ] - ABS "a" ) + 10
OD;
IF is hex word
THEN
# have a hex word #
count +:= 1;
# compute the digital root #
LONG INT r := int word;
WHILE r > 9 DO
LONG INT dr := r MOD 10;
WHILE ( r OVERAB 10 ) > 0 DO dr +:= r MOD 10 OD;
r := dr
OD;
word OF hw[ count ] := word;
value OF hw[ count ] := int word;
root OF hw[ count ] := SHORTEN r;
len OF hw[ count ] := word len
FI
FI
OD;
close( input file );
# prints the HEXWORD hw #
PROC show = ( HEXWORD hw )VOID:
BEGIN
STRING pad = IF len OF hw >= 12 THEN "" ELSE ( 12 - len OF hw ) * " " FI;
print( ( word OF hw, ": ", pad, whole( value OF hw, -10 ), " [ ", whole( root OF hw, 0 ), " ]", newline ) )
END # show # ;
# Quicksorts in-place the array of HEXWORDS a, from lb to ub on ascending value #
PROC quicksort = ( REF[]HEXWORD a, INT lb, ub )VOID:
IF ub > lb THEN
# more than one element, so must sort #
INT left := lb;
INT right := ub;
# choosing the middle element of the array as the pivot #
LONG INT pivot := value OF a[ left + ( ( right + 1 ) - left ) OVER 2 ];
WHILE
WHILE IF left <= ub THEN value OF a[ left ] < pivot ELSE FALSE FI DO left +:= 1 OD;
WHILE IF right >= lb THEN value OF a[ right ] > pivot ELSE FALSE FI DO right -:= 1 OD;
left <= right
DO
HEXWORD t := a[ left ];
a[ left ] := a[ right ];
a[ right ] := t;
left +:= 1;
right -:= 1
OD;
quicksort( a, lb, right );
quicksort( a, left, ub )
FI # quicksort # ;
# show the hex words in ascending order of digital root #
FOR r FROM 1 TO 9 DO
FOR i FROM 1 TO count DO
IF root OF hw[ i ] = r THEN show( hw[ i ] ) FI
OD
OD;
print( ( "Found ", whole( count, 0 ), " hex words", newline, newline ) );
# show the words in descending value order excluding those with less than 4 unique letters #
quicksort( hw, 1, count );
INT count 4 := 0;
FOR i FROM count BY -1 TO 1 DO
# check the word has at least four different digits #
INT a := 0, b := 0, c := 0, d := 0, e := 0, f := 0;
FOR c pos FROM LWB word OF hw[ i ] TO UPB word OF hw[ i ] DO
IF CHAR ch = ( word OF hw[ i ] )[ c pos ];
ch = "a"
THEN a := 1
ELIF ch = "b"
THEN b := 1
ELIF ch = "c"
THEN c := 1
ELIF ch = "d"
THEN d := 1
ELIF ch = "e"
THEN e := 1
ELSE f := 1
FI
OD;
IF a + b + c + d + e + f >= 4
THEN
# have a hex word with at least 4 different digits #
count 4 +:= 1;
show( hw[ i ] )
FI
OD;
print( ( "Found ", whole( count 4, 0 ), " hex words with 4 or more distinct digits", newline ) )
FI</lang>
- Output:
ababa: 703162 [ 1 ] abbe: 43966 [ 1 ] dada: 56026 [ 1 ] deaf: 57007 [ 1 ] decade: 14600926 [ 1 ] cede: 52958 [ 2 ] feed: 65261 [ 2 ] abed: 44013 [ 3 ] added: 712173 [ 3 ] bade: 47838 [ 3 ] beebe: 782014 [ 4 ] decca: 912586 [ 4 ] dade: 56030 [ 5 ] bead: 48813 [ 6 ] deface: 14613198 [ 6 ] babe: 47806 [ 7 ] fade: 64222 [ 7 ] dead: 57005 [ 8 ] efface: 15727310 [ 8 ] facade: 16435934 [ 8 ] accede: 11325150 [ 9 ] beef: 48879 [ 9 ] cafe: 51966 [ 9 ] dacca: 896202 [ 9 ] deed: 57069 [ 9 ] face: 64206 [ 9 ] Found 26 hex words facade: 16435934 [ 8 ] efface: 15727310 [ 8 ] deface: 14613198 [ 6 ] decade: 14600926 [ 1 ] accede: 11325150 [ 9 ] decca: 912586 [ 4 ] fade: 64222 [ 7 ] face: 64206 [ 9 ] deaf: 57007 [ 1 ] cafe: 51966 [ 9 ] bead: 48813 [ 6 ] bade: 47838 [ 3 ] abed: 44013 [ 3 ] Found 13 hex words with 4 or more distinct digits
Factor
<lang factor>USING: formatting io io.encodings.ascii io.files kernel literals math math.parser prettyprint sequences sets sorting ;
CONSTANT: words $[
"unixdict.txt" ascii file-lines [ length 3 > ] filter [ "abcdef" subset? ] filter
]
- droot ( m -- n ) 1 - 9 mod 1 + ;
- info. ( str -- ) dup hex> dup droot "%-8s-> %-10d-> %d\n" printf ;
- info-by ( quot ? -- )
[ sort-with ] [ inv-sort-with ] if [ length ] keep [ info. ] each pprint ; inline
words [ hex> droot ] t info-by " hex words with 4 or more letters found." print nl
words [ cardinality 3 > ] filter [ hex> ] f info-by " such words found which contain 4 or more different digits." print</lang>
- Output:
ababa -> 703162 -> 1 abbe -> 43966 -> 1 dada -> 56026 -> 1 deaf -> 57007 -> 1 decade -> 14600926 -> 1 cede -> 52958 -> 2 feed -> 65261 -> 2 abed -> 44013 -> 3 added -> 712173 -> 3 bade -> 47838 -> 3 beebe -> 782014 -> 4 decca -> 912586 -> 4 dade -> 56030 -> 5 bead -> 48813 -> 6 deface -> 14613198 -> 6 babe -> 47806 -> 7 fade -> 64222 -> 7 dead -> 57005 -> 8 efface -> 15727310 -> 8 facade -> 16435934 -> 8 accede -> 11325150 -> 9 beef -> 48879 -> 9 cafe -> 51966 -> 9 dacca -> 896202 -> 9 deed -> 57069 -> 9 face -> 64206 -> 9 26 hex words with 4 or more letters found. facade -> 16435934 -> 8 efface -> 15727310 -> 8 deface -> 14613198 -> 6 decade -> 14600926 -> 1 accede -> 11325150 -> 9 decca -> 912586 -> 4 fade -> 64222 -> 7 face -> 64206 -> 9 deaf -> 57007 -> 1 cafe -> 51966 -> 9 bead -> 48813 -> 6 bade -> 47838 -> 3 abed -> 44013 -> 3 13 such words found which contain 4 or more different digits.
Julia
<lang julia>digroot(n) = (while n > 9 n = sum(digits(n)) end; n)
function hexwords(wordfile = "unixdict.txt")
words = lowercase.(split(read(wordfile, String), r"\s+"))
filter!(w -> length(w) >= 4 && all(c -> c in "abcdef", w), words)
results = [[w, parse(Int, w, base = 16)] for w in words]
for a in results
pushfirst!(a, digroot(a[2]))
end
println("Hex words in $wordfile:\nRoot Word Base 10\n", "-"^30)
for a in sort!(results)
println(rpad(a[1], 6), rpad(a[2], 10), a[3])
end
println("Total count of these words: $(length(results)).")
println("\nHex words with > 3 distinct letters:\nRoot Word Base 10\n", "-"^30)
filter!(a -> length(unique(a[2])) > 3, results)
for a in results
println(rpad(a[1], 6), rpad(a[2], 10), a[3])
end
println("Total count of those words: $(length(results)).")
end
hexwords()
</lang>
- Output:
Hex words in unixdict.txt: Root Word Base 10 ------------------------------ 1 ababa 703162 1 abbe 43966 1 dada 56026 1 deaf 57007 1 decade 14600926 2 cede 52958 2 feed 65261 3 abed 44013 3 added 712173 3 bade 47838 4 beebe 782014 4 decca 912586 5 dade 56030 6 bead 48813 6 deface 14613198 7 babe 47806 7 fade 64222 8 dead 57005 8 efface 15727310 8 facade 16435934 9 accede 11325150 9 beef 48879 9 cafe 51966 9 dacca 896202 9 deed 57069 9 face 64206 Total count of these words: 26. Hex words with > 3 distinct letters: Root Word Base 10 ------------------------------ 1 deaf 57007 1 decade 14600926 3 abed 44013 3 bade 47838 4 decca 912586 6 bead 48813 6 deface 14613198 7 fade 64222 8 efface 15727310 8 facade 16435934 9 accede 11325150 9 cafe 51966 9 face 64206 Total count of those words: 13.
Perl
<lang perl>#!/usr/bin/perl
use strict; # https://rosettacode.org/wiki/Hex_words use warnings; use List::AllUtils qw( nsort_by uniq );
sub root
{
local $_ = shift;
$_ = eval while s/\B/+/g;
return $_;
}
my @bydecimal = grep +(uniq /[a-f]/g)[3],
my @byroot = map { sprintf "%10s %10d %3d\n", $_, hex $_, root hex $_
} do { local(@ARGV, $/) = 'unixdict.txt'; <> =~ /^[a-f]{4,}$/gm };
print +(nsort_by { (split ' ')[2] } @byroot),
"total count = @{[ scalar @byroot ]} and @{[ scalar @bydecimal
]} have at least 4 distinct digits\n",
reverse nsort_by { (split ' ')[1] } @bydecimal;</lang>
- Output:
ababa 703162 1
abbe 43966 1
dada 56026 1
deaf 57007 1
decade 14600926 1
cede 52958 2
feed 65261 2
abed 44013 3
added 712173 3
bade 47838 3
beebe 782014 4
decca 912586 4
dade 56030 5
bead 48813 6
deface 14613198 6
babe 47806 7
fade 64222 7
dead 57005 8
efface 15727310 8
facade 16435934 8
accede 11325150 9
beef 48879 9
cafe 51966 9
dacca 896202 9
deed 57069 9
face 64206 9
total count = 26 and 13 have at least 4 distinct digits
facade 16435934 8
efface 15727310 8
deface 14613198 6
decade 14600926 1
accede 11325150 9
decca 912586 4
fade 64222 7
face 64206 9
deaf 57007 1
cafe 51966 9
bead 48813 6
bade 47838 3
abed 44013 3
Phix
with javascript_semantics function af(string s) return max(s)<='f' and min(s)>='a' end function function digital_root(integer n) assert(n>=0) while n>9 do integer tot = 0 while n>0 do tot += remainder(n,10) n = floor(n/10) end while n = tot end while return n end function sequence words = filter(unix_dict(4),af), decml = apply(true,to_integer,{words,0,16}), roots = apply(decml,digital_root), tags = custom_sort(roots,tagset(length(roots))) function caejasp() -- columnize/apply/extract/join/apply/sprint(...) sequence s = columnize(apply(true,extract,{{words,decml,roots},{tags}})) return join(apply(true,sprintf,{{"%6s -> %8d -> %d\n"},s})) end function printf(1," %s\n %d hex words with 4 or more letters found,\n",{caejasp(),length(tags)}) function ge4(integer t) return length(unique(words[t]))>=4 end function tags = filter(tags,ge4) tags = extract(tags,reverse(custom_sort(extract(decml,tags),tagset(length(tags))))) printf(1," %d with 4 or more distinct characters:\n\n %s\n",{length(tags),caejasp()})
- Output:
ababa -> 703162 -> 1 abbe -> 43966 -> 1 dada -> 56026 -> 1 deaf -> 57007 -> 1 decade -> 14600926 -> 1 cede -> 52958 -> 2 feed -> 65261 -> 2 abed -> 44013 -> 3 added -> 712173 -> 3 bade -> 47838 -> 3 beebe -> 782014 -> 4 decca -> 912586 -> 4 dade -> 56030 -> 5 bead -> 48813 -> 6 deface -> 14613198 -> 6 babe -> 47806 -> 7 fade -> 64222 -> 7 dead -> 57005 -> 8 efface -> 15727310 -> 8 facade -> 16435934 -> 8 accede -> 11325150 -> 9 beef -> 48879 -> 9 cafe -> 51966 -> 9 dacca -> 896202 -> 9 deed -> 57069 -> 9 face -> 64206 -> 9 26 hex words with 4 or more letters found, 13 with 4 or more distinct characters: facade -> 16435934 -> 8 efface -> 15727310 -> 8 deface -> 14613198 -> 6 decade -> 14600926 -> 1 accede -> 11325150 -> 9 decca -> 912586 -> 4 fade -> 64222 -> 7 face -> 64206 -> 9 deaf -> 57007 -> 1 cafe -> 51966 -> 9 bead -> 48813 -> 6 bade -> 47838 -> 3 abed -> 44013 -> 3
Python
<lang python>def digroot(n):
while n > 9:
n = sum([int(d) for d in str(n)])
return n
with open('unixdict.txt') as f:
lines = [w.strip() for w in f.readlines()]
words = [w for w in lines if len(w) >= 4 and all(c in 'abcdef' for c in w)]
results = [[w, int(w, 16)] for w in words]
for a in results:
a.append(digroot(a[1]))
print(f"Hex words in unixdict.txt:\nRoot Word Base 10\n", "-"*22)
for a in sorted(results, key=lambda x:x[2]):
print(f"{a[2]} {a[0]:6}{a[1]:10}")
print("Total count of these words:", len(results))
print("\nHex words with > 3 distinct letters:\nRoot Word Base 10\n", "-"*22)
results = [a for a in results if len(set(str(a[0]))) > 3]
for a in sorted(results, key=lambda x:x[2]):
print(f"{a[2]} {a[0]:6}{a[1]:10}")
print("Total count of those words:", len(results))
</lang>
- Output:
Hex words in unixdict.txt: Root Word Base 10 ---------------------- 1 ababa 703162 1 abbe 43966 1 dada 56026 1 deaf 57007 1 decade 14600926 2 cede 52958 2 feed 65261 3 abed 44013 3 added 712173 3 bade 47838 4 beebe 782014 4 decca 912586 5 dade 56030 6 bead 48813 6 deface 14613198 7 babe 47806 7 fade 64222 8 dead 57005 8 efface 15727310 8 facade 16435934 9 accede 11325150 9 beef 48879 9 cafe 51966 9 dacca 896202 9 deed 57069 9 face 64206 Total count of these words: 26 Hex words with > 3 distinct letters: Root Word Base 10 ---------------------- 1 deaf 57007 1 decade 14600926 3 abed 44013 3 bade 47838 4 decca 912586 6 bead 48813 6 deface 14613198 7 fade 64222 8 efface 15727310 8 facade 16435934 9 accede 11325150 9 cafe 51966 9 face 64206 Total count of those words: 13
Raku
Sorted by digital root with a secondary alphabetical sort. <lang perl6>sub dr (Int $_ is copy) { $_ = dr(.comb.sum) while .chars > 1; $_ }
my %hex = './unixdict.txt'.IO.slurp.words.grep( *.chars > 3 )\
.grep({ not / <-[abcdef]> / }).map: { $_ => dr :16($_).comb.sum }
say "{+%hex} hex words longer than 3 characters found in unixdict.txt:"; printf "%6s ➡ %8d ➡ %d\n", .key, :16(.key), .value for %hex.sort: { .value, .key }
my %many = %hex.grep: +*.key.comb.Set > 3;
say "\nOf which {+%many} contain at least four distinct characters:"; printf "%6s ➡ %8d ➡ %d\n", .key, :16(.key), .value for %many.sort: { -:16(.key) }</lang>
- Output:
26 hex words longer than 3 characters found in unixdict.txt: ababa ➡ 703162 ➡ 1 abbe ➡ 43966 ➡ 1 dada ➡ 56026 ➡ 1 deaf ➡ 57007 ➡ 1 decade ➡ 14600926 ➡ 1 cede ➡ 52958 ➡ 2 feed ➡ 65261 ➡ 2 abed ➡ 44013 ➡ 3 added ➡ 712173 ➡ 3 bade ➡ 47838 ➡ 3 beebe ➡ 782014 ➡ 4 decca ➡ 912586 ➡ 4 dade ➡ 56030 ➡ 5 bead ➡ 48813 ➡ 6 deface ➡ 14613198 ➡ 6 babe ➡ 47806 ➡ 7 fade ➡ 64222 ➡ 7 dead ➡ 57005 ➡ 8 efface ➡ 15727310 ➡ 8 facade ➡ 16435934 ➡ 8 accede ➡ 11325150 ➡ 9 beef ➡ 48879 ➡ 9 cafe ➡ 51966 ➡ 9 dacca ➡ 896202 ➡ 9 deed ➡ 57069 ➡ 9 face ➡ 64206 ➡ 9 Of which 13 contain at least four distinct characters: facade ➡ 16435934 ➡ 8 efface ➡ 15727310 ➡ 8 deface ➡ 14613198 ➡ 6 decade ➡ 14600926 ➡ 1 accede ➡ 11325150 ➡ 9 decca ➡ 912586 ➡ 4 fade ➡ 64222 ➡ 7 face ➡ 64206 ➡ 9 deaf ➡ 57007 ➡ 1 cafe ➡ 51966 ➡ 9 bead ➡ 48813 ➡ 6 bade ➡ 47838 ➡ 3 abed ➡ 44013 ➡ 3
Wren
<lang ecmascript>import "./ioutil" for FileUtil import "./fmt" for Conv, Fmt import "./math" for Int import "./seq" for Lst
var words = FileUtil.readLines("unixdict.txt").where { |w| w.count > 0 && w[0].bytes[0] < 103 } var hexDigits = "abcdef" var lines = [] for (word in words) {
if (word.count < 4) continue
if (word.all { |c| hexDigits.contains(c) }) {
var num = Conv.atoi(word, 16)
var dr = Int.digitalRoot(num)[0]
lines.add(Fmt.swrite("$-7s -> $-9s -> $d", word, num, dr))
}
} lines.sort { |a, b| a[-1].bytes[0] < b[-1].bytes[0] } System.print(lines.join("\n")) System.print("\n%(lines.count) hex words with 4 or more letters found.\n") var digits4 = [] for (line in lines) {
var word = line.split("->")[0].trimEnd()
if (Lst.distinct(word.toList).count >= 4) digits4.add(line)
} digits4.sort { |a, b| Num.fromString(a.split("->")[1]) > Num.fromString(b.split("->")[1]) } System.print(digits4.join("\n")) System.print("\n%(digits4.count) such words found which contain 4 or more different digits.")</lang>
- Output:
decade -> 14600926 -> 1 ababa -> 703162 -> 1 abbe -> 43966 -> 1 dada -> 56026 -> 1 deaf -> 57007 -> 1 feed -> 65261 -> 2 cede -> 52958 -> 2 added -> 712173 -> 3 bade -> 47838 -> 3 abed -> 44013 -> 3 decca -> 912586 -> 4 beebe -> 782014 -> 4 dade -> 56030 -> 5 deface -> 14613198 -> 6 bead -> 48813 -> 6 babe -> 47806 -> 7 fade -> 64222 -> 7 dead -> 57005 -> 8 facade -> 16435934 -> 8 efface -> 15727310 -> 8 dacca -> 896202 -> 9 beef -> 48879 -> 9 cafe -> 51966 -> 9 deed -> 57069 -> 9 face -> 64206 -> 9 accede -> 11325150 -> 9 26 hex words with 4 or more letters found. facade -> 16435934 -> 8 efface -> 15727310 -> 8 deface -> 14613198 -> 6 decade -> 14600926 -> 1 accede -> 11325150 -> 9 decca -> 912586 -> 4 fade -> 64222 -> 7 face -> 64206 -> 9 deaf -> 57007 -> 1 cafe -> 51966 -> 9 bead -> 48813 -> 6 bade -> 47838 -> 3 abed -> 44013 -> 3 13 such words found which contain 4 or more different digits.