Halt and catch fire: Difference between revisions
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=={{header|8086 Assembly}}== |
=={{header|8086 Assembly}}== |
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{{trans|Z80 Assembly}} |
{{trans|Z80 Assembly}} |
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These two lines will halt the processor: |
These two lines will halt the processor: |
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<lang asm>cli |
<lang asm>cli |
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hlt</lang> |
hlt</lang> |
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=={{header|68000 Assembly}}== |
=={{header|68000 Assembly}}== |
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The 68000 can only read words or longs at even addresses. Attempting to do so at an odd address will crash the CPU. |
The 68000 can only read words or longs at even addresses. Attempting to do so at an odd address will crash the CPU. |
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Revision as of 20:27, 12 September 2021
You are encouraged to solve this task according to the task description, using any language you may know.
- Task
Create a program that crashes as soon as possible, with as few lines of code as possible. Be smart and don't damage your computer, ok?
- References
6502 Assembly
Upon executing this byte as code, the processor will halt. No interrupts can occur either. This does not occur on 65c02-based hardware such as the Apple II or Atari Lynx. <lang 6502asm> db $02</lang>
8086 Assembly
These two lines will halt the processor: <lang asm>cli hlt</lang>
68000 Assembly
The 68000 can only read words or longs at even addresses. Attempting to do so at an odd address will crash the CPU. <lang 68000devpac>CrashBandicoot equ $100001 LEA CrashBandicoot,A0 MOVE.W (A0),D0</lang>
Z80 Assembly
The processor is permanently halted. Strangely enough, this does not work on the Game Boy. Rather, both the HALT instruction and the instruction after it are skipped.
<lang z80>di
halt</lang>