Find words which contains more than 3 e vowels: Difference between revisions
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=={{header|Frink}}== |
=={{header|Frink}}== |
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{ |
{ |
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d = countToDict[charList[word]] |
d = countToDict[charList[word]] |
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if d.get["a",0] == 0 and d.get["e",0] > 3 and d.get["i",0] == 0 and d.get["o",0] == 0 and d.get["u",0] == 0 |
if d.get["a",0] == 0 and d.get["e",0] > 3 and d.get["i",0] == 0 and d.get["o",0] == 0 and d.get["u",0] == 0 |
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println[word] |
println[word] |
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} |
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</lang> |
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{{out}} |
{{out}} |
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<pre> |
<pre> |