Filter

Filter
You are encouraged to solve this task according to the task description, using any language you may know.

Select certain elements from an Array into a new Array in a generic way. E.g., select all even numbers from an Array

Ruby

 ary = [1,2,3,4,5,6]
 even_ary = ary.select{|el|el%2==0}
 # => [2, 4, 6]

Standard ML

 val ary = [1,2,3,4,5,6];
 List.filter (fn x => x mod 2 = 0) ary

Haskell

 ary = [1..10]
 evens = [ x | x <- ary, even x ]

Python

 values = range(10)
 [x for x in values if x % 2 == 0]

Perl

 my @list = (1, 2, 3, 4, 5, 6);
 my @even = grep { 0 == $_%2; } @list;

C

       int arr[5] = {1,2,3,4,5};
       int *result;
       int memoryReqd = 0,length = sizeof(arr)/sizeof(arr[0]), i,j;
       for (i=0; i<length; i++)
       {
               if(0 == arr[i]%2)
               {
                       memoryReqd++;
               }
       }
       result = (int*)malloc(memoryReqd*sizeof(int));
       for(i=0,j=0; i<length; i++)
       {
               if(0 == arr[i]%2)
               {
                       result[j++]=arr[i];
               }
       }

       // Test our resultant array
       for(i=0; i<memoryReqd; i++)
       {
               printf("%d\n",result[i]);
       }

C#

       // .NET 1.x solution
       ArrayList array = new ArrayList( new int[] { 1, 2, 3, 4, 5 } );
       ArrayList evens = new ArrayList();
       foreach( int i in array )
       {
               if( (i%2) == 0 )
                       evens.Add( i );
       }
       foreach( int i in evens )
              System.Console.WriteLine( i.ToString() );

       // .NET 2.0 solution
       List<int> array = new List<int>( new int[] { 1, 2, 3, 4, 5 } );
       List<int> evens = array.FindAll( delegate( int i ) { return (i%2)==0; } );
       foreach( int i in evens )
              System.Console.WriteLine( i.ToString() );