Eertree: Difference between revisions
SqrtNegInf (talk | contribs) m (→{{header|Perl}}: Fix link: Perl 6 --> Raku) |
SqrtNegInf (talk | contribs) m (→{{header|Raku}}: Fix code: Perl 6 --> Raku) |
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(formerly Perl 6) |
(formerly Perl 6) |
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{{trans|Ring}} |
{{trans|Ring}} |
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<lang perl6> |
<lang perl6>my $str = "eertree"; |
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use v6; |
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my $str = "eertree"; |
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my @pal = (); |
my @pal = (); |
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my ($strrev,$strpal); |
my ($strrev,$strpal); |
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Revision as of 00:22, 19 March 2020
You are encouraged to solve this task according to the task description, using any language you may know.
An eertree is a data structure designed for efficient processing of certain palindrome tasks, for instance counting the number of sub-palindromes in an input string.
The data structure has commonalities to both tries and suffix trees. See links below.
- Task
Construct an eertree for the string "eertree", then output all sub-palindromes by traversing the tree.
- See also
- Wikipedia entry: trie.
- Wikipedia entry: suffix tree
- Cornell University Library, Computer Science, Data Structures and Algorithms ───► EERTREE: An Efficient Data Structure for Processing Palindromes in Strings.
C#
<lang csharp>using System; using System.Collections.Generic;
namespace Eertree {
class Node {
public Node(int length) {
this.Length = length;
// empty or
this.Edges = new Dictionary<char, int>();
}
public Node(int length, Dictionary<char, int> edges, int suffix) {
this.Length = length;
this.Edges = edges;
this.Suffix = suffix;
}
public int Length { get; set; }
public Dictionary<char, int> Edges { get; set; }
public int Suffix { get; set; }
}
class Program {
const int EVEN_ROOT = 0;
const int ODD_ROOT = 1;
static List<Node> Eertree(string s) {
List<Node> tree = new List<Node> {
//new Node(0, null, ODD_ROOT), or
new Node(0, new Dictionary<char, int>(), ODD_ROOT),
//new Node(-1, null, ODD_ROOT) or
new Node(-1, new Dictionary<char, int>(), ODD_ROOT)
};
int suffix = ODD_ROOT;
int n, k;
for (int i = 0; i < s.Length; i++) {
char c = s[i];
for (n = suffix; ; n = tree[n].Suffix) {
k = tree[n].Length;
int b = i - k - 1;
if (b >= 0 && s[b] == c) {
break;
}
}
if (tree[n].Edges.ContainsKey(c)) {
suffix = tree[n].Edges[c];
continue;
}
suffix = tree.Count;
tree.Add(new Node(k + 2));
tree[n].Edges[c] = suffix;
if (tree[suffix].Length == 1) {
tree[suffix].Suffix = 0;
continue;
}
while (true) {
n = tree[n].Suffix;
int b = i - tree[n].Length - 1;
if (b >= 0 && s[b] == c) {
break;
}
}
tree[suffix].Suffix = tree[n].Edges[c];
}
return tree;
}
static List<string> SubPalindromes(List<Node> tree) {
List<string> s = new List<string>();
SubPalindromes_children(0, "", tree, s);
foreach (var c in tree[1].Edges.Keys) {
int m = tree[1].Edges[c];
string ct = c.ToString();
s.Add(ct);
SubPalindromes_children(m, ct, tree, s);
}
return s;
}
static void SubPalindromes_children(int n, string p, List<Node> tree, List<string> s) {
foreach (var c in tree[n].Edges.Keys) {
int m = tree[n].Edges[c];
string p1 = c + p + c;
s.Add(p1);
SubPalindromes_children(m, p1, tree, s);
}
}
static void Main(string[] args) {
List<Node> tree = Eertree("eertree");
List<string> result = SubPalindromes(tree);
string listStr = string.Join(", ", result);
Console.WriteLine("[{0}]", listStr);
}
}
}</lang>
- Output:
[ee, e, r, t, rtr, ertre, eertree]
C++
<lang cpp>#include <iostream>
- include <functional>
- include <map>
- include <vector>
struct Node {
int length; std::map<char, int> edges; int suffix;
Node(int l) : length(l), suffix(0) {
/* empty */
}
Node(int l, const std::map<char, int>& m, int s) : length(l), edges(m), suffix(s) {
/* empty */
}
};
constexpr int evenRoot = 0; constexpr int oddRoot = 1;
std::vector<Node> eertree(const std::string& s) {
std::vector<Node> tree = {
Node(0, {}, oddRoot),
Node(-1, {}, oddRoot)
};
int suffix = oddRoot;
int n, k;
for (size_t i = 0; i < s.length(); ++i) {
char c = s[i];
for (n = suffix; ; n = tree[n].suffix) {
k = tree[n].length;
int b = i - k - 1;
if (b >= 0 && s[b] == c) {
break;
}
}
auto it = tree[n].edges.find(c);
auto end = tree[n].edges.end();
if (it != end) {
suffix = it->second;
continue;
}
suffix = tree.size();
tree.push_back(Node(k + 2));
tree[n].edges[c] = suffix;
if (tree[suffix].length == 1) {
tree[suffix].suffix = 0;
continue;
}
while (true) {
n = tree[n].suffix;
int b = i - tree[n].length - 1;
if (b >= 0 && s[b] == c) {
break;
}
}
tree[suffix].suffix = tree[n].edges[c];
}
return tree;
}
std::vector<std::string> subPalindromes(const std::vector<Node>& tree) {
std::vector<std::string> s;
std::function<void(int, std::string)> children;
children = [&children, &tree, &s](int n, std::string p) {
auto it = tree[n].edges.cbegin();
auto end = tree[n].edges.cend();
for (; it != end; it = std::next(it)) {
auto c = it->first;
auto m = it->second;
std::string pl = c + p + c;
s.push_back(pl);
children(m, pl);
}
};
children(0, "");
auto it = tree[1].edges.cbegin();
auto end = tree[1].edges.cend();
for (; it != end; it = std::next(it)) {
auto c = it->first;
auto n = it->second;
std::string ct(1, c);
s.push_back(ct);
children(n, ct); }
return s;
}
int main() {
using namespace std;
auto tree = eertree("eertree");
auto pal = subPalindromes(tree);
auto it = pal.cbegin(); auto end = pal.cend();
cout << "[";
if (it != end) {
cout << it->c_str();
it++;
}
while (it != end) {
cout << ", " << it->c_str();
it++;
}
cout << "]" << endl;
return 0;
}</lang>
- Output:
[ee, e, r, t, rtr, ertre, eertree]
D
<lang D>import std.array; import std.stdio;
void main() {
auto tree = eertree("eertree");
writeln(subPalindromes(tree));
}
struct Node {
int length; int[char] edges; int suffix;
}
const evenRoot = 0; const oddRoot = 1;
Node[] eertree(string s) {
Node[] tree = [
Node(0, null, oddRoot),
Node(-1, null, oddRoot),
];
int suffix = oddRoot;
int n, k;
foreach (i, c; s) {
for (n=suffix; ; n=tree[n].suffix) {
k = tree[n].length;
int b = i-k-1;
if (b>=0 && s[b]==c) {
break;
}
}
if (c in tree[n].edges) {
suffix = tree[n].edges[c];
continue;
}
suffix = tree.length;
tree ~= Node(k+2);
tree[n].edges[c] = suffix;
if (tree[suffix].length == 1) {
tree[suffix].suffix = 0;
continue;
}
while (true) {
n = tree[n].suffix;
int b = i-tree[n].length-1;
if (b>=0 && s[b]==c) {
break;
}
}
tree[suffix].suffix = tree[n].edges[c];
}
return tree;
}
auto subPalindromes(Node[] tree) {
auto s = appender!(string[]);
void children(int n, string p) {
foreach (c, n; tree[n].edges) {
p = c ~ p ~ c;
s ~= p;
children(n, p);
}
}
children(0, "");
foreach (c, n; tree[1].edges) {
string ct = [c].idup;
s ~= ct;
children(n, ct);
}
return s.data;
}</lang>
- Output:
["ee", "e", "r", "t", "rtr", "ertre", "eertree"]
Go
<lang go>package main
import "fmt"
func main() {
tree := eertree([]byte("eertree"))
fmt.Println(subPalindromes(tree))
}
type edges map[byte]int
type node struct {
length int edges suffix int
}
const evenRoot = 0 const oddRoot = 1
func eertree(s []byte) []node {
tree := []node{
evenRoot: {length: 0, suffix: oddRoot, edges: edges{}},
oddRoot: {length: -1, suffix: oddRoot, edges: edges{}},
}
suffix := oddRoot
var n, k int
for i, c := range s {
for n = suffix; ; n = tree[n].suffix {
k = tree[n].length
if b := i - k - 1; b >= 0 && s[b] == c {
break
}
}
if e, ok := tree[n].edges[c]; ok {
suffix = e
continue
}
suffix = len(tree)
tree = append(tree, node{length: k + 2, edges: edges{}})
tree[n].edges[c] = suffix
if tree[suffix].length == 1 {
tree[suffix].suffix = 0
continue
}
for {
n = tree[n].suffix
if b := i - tree[n].length - 1; b >= 0 && s[b] == c {
break
}
}
tree[suffix].suffix = tree[n].edges[c]
}
return tree
}
func subPalindromes(tree []node) (s []string) {
var children func(int, string)
children = func(n int, p string) {
for c, n := range tree[n].edges {
c := string(c)
p := c + p + c
s = append(s, p)
children(n, p)
}
}
children(0, "")
for c, n := range tree[1].edges {
c := string(c)
s = append(s, c)
children(n, c)
}
return
}</lang>
- Output:
[ee e r t rtr ertre eertree]
Java
<lang Java>import java.util.ArrayList; import java.util.HashMap; import java.util.List; import java.util.Map;
public class Eertree {
public static void main(String[] args) {
List<Node> tree = eertree("eertree");
List<String> result = subPalindromes(tree);
System.out.println(result);
}
private static class Node {
int length;
Map<Character, Integer> edges = new HashMap<>();
int suffix;
public Node(int length) {
this.length = length;
}
public Node(int length, Map<Character, Integer> edges, int suffix) {
this.length = length;
this.edges = edges != null ? edges : new HashMap<>();
this.suffix = suffix;
}
}
private static final int EVEN_ROOT = 0; private static final int ODD_ROOT = 1;
private static List<Node> eertree(String s) {
List<Node> tree = new ArrayList<>();
tree.add(new Node(0, null, ODD_ROOT));
tree.add(new Node(-1, null, ODD_ROOT));
int suffix = ODD_ROOT;
int n, k;
for (int i = 0; i < s.length(); ++i) {
char c = s.charAt(i);
for (n = suffix; ; n = tree.get(n).suffix) {
k = tree.get(n).length;
int b = i - k - 1;
if (b >= 0 && s.charAt(b) == c) {
break;
}
}
if (tree.get(n).edges.containsKey(c)) {
suffix = tree.get(n).edges.get(c);
continue;
}
suffix = tree.size();
tree.add(new Node(k + 2));
tree.get(n).edges.put(c, suffix);
if (tree.get(suffix).length == 1) {
tree.get(suffix).suffix = 0;
continue;
}
while (true) {
n = tree.get(n).suffix;
int b = i - tree.get(n).length - 1;
if (b >= 0 && s.charAt(b) == c) {
break;
}
}
tree.get(suffix).suffix = tree.get(n).edges.get(c);
}
return tree;
}
private static List<String> subPalindromes(List<Node> tree) {
List<String> s = new ArrayList<>();
subPalindromes_children(0, "", tree, s);
for (Map.Entry<Character, Integer> cm : tree.get(1).edges.entrySet()) {
String ct = String.valueOf(cm.getKey());
s.add(ct);
subPalindromes_children(cm.getValue(), ct, tree, s);
}
return s;
}
// nested methods are a pain, even if lambdas make that possible for Java
private static void subPalindromes_children(final int n, final String p, final List<Node> tree, List<String> s) {
for (Map.Entry<Character, Integer> cm : tree.get(n).edges.entrySet()) {
Character c = cm.getKey();
Integer m = cm.getValue();
String pl = c + p + c;
s.add(pl);
subPalindromes_children(m, pl, tree, s);
}
}
}</lang>
- Output:
[ee, r, t, rtr, ertre, eertree, e]
Julia
<lang julia>mutable struct Node
edges::Dict{Char, Node}
link::Union{Node, Missing}
sz::Int
Node() = new(Dict(), missing, 0)
end
sizednode(x) = (n = Node(); n.sz = x; n)
function eertree(str)
nodes = Vector{Node}()
oddroot = sizednode(-1)
evenroot = sizednode(0)
oddroot.link = evenroot
evenroot.link = oddroot
S = "0"
maxsuffix = evenroot
function maxsuffixpal(startnode,a::Char)
# Traverse the suffix-palindromes of tree looking for equality with a
u = startnode
i = length(S)
k = u.sz
while u !== oddroot && S[i - k] != a
if u === u.link
throw("circular reference above oddroot")
end
u = u.link
k = u.sz
end
u
end
function addchar(a::Char)
Q = maxsuffixpal(maxsuffix, a)
creatednode = !haskey(Q.edges, a)
if creatednode
P = sizednode(Q.sz + 2)
push!(nodes, P)
if P.sz == 1
P.link = evenroot
else
P.link = maxsuffixpal(Q.link, a).edges[a]
end
Q.edges[a] = P # adds edge (Q, P)
end
maxsuffix = Q.edges[a] # P becomes the new maxsuffix
S *= string(a)
creatednode
end
function getsubpalindromes()
result = Vector{String}()
getsubpalindromes(oddroot, [oddroot], "", result)
getsubpalindromes(evenroot, [evenroot], "", result)
result
end
function getsubpalindromes(nd, nodestohere, charstohere, result)
for (lnkname, nd2) in nd.edges
getsubpalindromes(nd2, vcat(nodestohere, nd2), charstohere * lnkname, result)
end
if nd !== oddroot && nd !== evenroot
assembled = reverse(charstohere) *
(nodestohere[1] === evenroot ? charstohere : charstohere[2:end])
push!(result, assembled)
end
end
println("Results of processing string \"$str\":")
for c in str
addchar(c)
end
println("Number of sub-palindromes: ", length(nodes))
println("Sub-palindromes: ", getsubpalindromes())
end
eertree("eertree")
</lang>
- Output:
Results of processing string "eertree": Number of sub-palindromes: 7 Sub-palindromes: ["e", "r", "eertree", "ertre", "rtr", "t", "ee"]
Kotlin
<lang scala>// version 1.1.4
class Node {
val edges = mutableMapOf<Char, Node>() // edges (or forward links) var link: Node? = null // suffix link (backward links) var len = 0 // the length of the node
}
class Eertree(str: String) {
val nodes = mutableListOf<Node>()
private val rto = Node() // odd length root node, or node -1
private val rte = Node() // even length root node, or node 0
private val s = StringBuilder("0") // accumulated input string, T = S[1..i]
private var maxSufT = rte // maximum suffix of tree T
init {
// Initialize and build the tree
rte.link = rto
rto.link = rte
rto.len = -1
rte.len = 0
for (ch in str) add(ch)
}
private fun getMaxSuffixPal(startNode: Node, a: Char): Node {
// We traverse the suffix-palindromes of T in the order of decreasing length.
// For each palindrome we read its length k and compare T[i-k] against a
// until we get an equality or arrive at the -1 node.
var u = startNode
val i = s.length
var k = u.len
while (u !== rto && s[i - k - 1] != a) {
if (u === u.link!!) throw RuntimeException("Infinite loop detected")
u = u.link!!
k = u.len
}
return u
}
private fun add(a: Char): Boolean {
// We need to find the maximum suffix-palindrome P of Ta
// Start by finding maximum suffix-palindrome Q of T.
// To do this, we traverse the suffix-palindromes of T
// in the order of decreasing length, starting with maxSuf(T)
val q = getMaxSuffixPal(maxSufT, a)
// We check Q to see whether it has an outgoing edge labeled by a.
val createANewNode = a !in q.edges.keys
if (createANewNode) {
// We create the node P of length Q + 2
val p = Node()
nodes.add(p)
p.len = q.len + 2
if (p.len == 1) {
// if P = a, create the suffix link (P, 0)
p.link = rte
}
else {
// It remains to create the suffix link from P if |P|>1. Just
// continue traversing suffix-palindromes of T starting with the
// the suffix link of Q.
p.link = getMaxSuffixPal(q.link!!, a).edges[a]
}
// create the edge (Q, P)
q.edges[a] = p
}
// P becomes the new maxSufT
maxSufT = q.edges[a]!!
// Store accumulated input string
s.append(a)
return createANewNode }
fun getSubPalindromes(): List<String> {
// Traverse tree to find sub-palindromes
val result = mutableListOf<String>()
// Odd length words
getSubPalindromes(rto, listOf(rto), "", result)
// Even length words
getSubPalindromes(rte, listOf(rte), "", result)
return result
}
private fun getSubPalindromes(nd: Node, nodesToHere: List<Node>,
charsToHere: String, result: MutableList<String>) {
// Each node represents a palindrome, which can be reconstructed
// by the path from the root node to each non-root node.
// Traverse all edges, since they represent other palindromes
for ((lnkName, nd2) in nd.edges) {
getSubPalindromes(nd2, nodesToHere + nd2, charsToHere + lnkName, result)
}
// Reconstruct based on charsToHere characters.
if (nd !== rto && nd !== rte) { // Don't print for root nodes
val assembled = charsToHere.reversed() +
if (nodesToHere[0] === rte) // Even string
charsToHere
else // Odd string
charsToHere.drop(1)
result.add(assembled)
}
}
}
fun main(args: Array<String>) {
val str = "eertree"
println("Processing string '$str'")
val eertree = Eertree(str)
println("Number of sub-palindromes: ${eertree.nodes.size}")
val result = eertree.getSubPalindromes()
println("Sub-palindromes: $result")
}</lang>
- Output:
Processing string 'eertree' Number of sub-palindromes: 7 Sub-palindromes: [e, r, eertree, ertre, rtr, t, ee]
M2000 Interpreter
<lang M2000 Interpreter> If Version<9.5 Then exit If Version=9.5 And Revision<2 Then Exit Class Node {
inventory myedges
length, suffix=0
Function edges(s$) {
=-1 : if exist(.myedges, s$) then =eval(.myedges)
}
Module edges_append (a$, where) {
Append .myedges, a$:=where
}
Class:
Module Node(.length) {
Read ? .suffix, .myedges
}
} function eertree(s$) {
Const evenRoot=0, oddRoot=1
Inventory Tree= oddRoot:=Node(-1,1),evenRoot:=Node(0,1)
k=0
suffix=oddRoot
for i=0 to len(s$)-1 {
c$=mid$(s$,i+1,1)
n=suffix
Do {
k=tree(n).length
b=i-k-1
if b>=0 then if mid$(s$,b+1,1)=c$ Then exit
n =tree(n).suffix
} Always
e=tree(n).edges(c$)
if e>=0 then suffix=e :continue
suffix=len(Tree)
Append Tree, len(Tree):=Node(k+2)
Tree(n).edges_append c$, suffix
If tree(suffix).length=1 then tree(suffix).suffix=0 : continue
Do {
n=tree(n).suffix
b=i-tree(n).length-1
if b>0 Then If mid$(s$, b+1,1)=c$ then exit
} Always
e=tree(n).edges(c$)
if e>=0 then tree(suffix).suffix=e
}
=tree
} children=lambda (s, tree, n, root$="")->{
L=Len(tree(n).myEdges)
if L=0 then =s : exit
L--
For i=0 to L {
c=tree(n).myEdges
c$=Eval$(c, i) ' read keys at position i
nxt=c(i!) ' read value using position
p$ = if$(n=1 -> c$, c$+root$+c$)
append s, (p$,)
\\ better use lambda() and not children()
\\ for recursion when we copy this lambda to other identifier.
s = lambda(s, tree, nxt, p$)
}
= s
}
aString=Lambda ->{
Push Quote$(Letter$)
} aLine=Lambda ->{
Shift 2 ' swap two top stack items
if stackitem$()="" then { Drop} Else Push letter$+", "+Letter$
} Palindromes$=Lambda$ children, aString, aLine (Tree)-> {
="("+children(children((,), Tree, 0), Tree, 1)#Map(aString)#Fold$(aline,"")+")"
}
Print Palindromes$(eertree("eertree")) </lang>
- Output:
("ee", "e", "r", "t", "rtr", "ertre", "eertree")
Objeck
<lang objeck>use Collection.Generic;
class Eertree {
function : Main(args : String[]) ~ Nil {
tree := GetEertree("eertree");
Show(SubPalindromes(tree));
}
function : GetEertree(s : String) ~ Vector<Node> {
tree := Vector->New()<Node>;
tree->AddBack(Node->New(0, Nil, 1));
tree->AddBack(Node->New(-1, Nil, 1));
suffix := 1;
n : Int; k : Int;
for(i := 0; i < s->Size(); ++i;) {
c := s->Get(i);
done := false;
for (j := suffix; <>done; j := tree->Get(j)->GetSuffix();) {
k := tree->Get(j)->GetLength();
b := i - k - 1;
if (b >= 0 & s->Get(b) = c) {
n := j;
done := true;
};
};
skip := false;
if (tree->Get(n)->GetEdges()->Has(c)) {
suffix := tree->Get(n)->GetEdges()->Find(c)->Get();
skip := true;
};
if(<>skip) {
suffix := tree->Size();
tree->AddBack(Node->New(k + 2));
tree->Get(n)->GetEdges()->Insert(c, suffix);
if (tree->Get(suffix)->GetLength() = 1) {
tree->Get(suffix)->SetSuffix(0);
skip := true;
};
if(<>skip) {
done := false;
while (<>done) {
n := tree->Get(n)->GetSuffix();
b := i - tree->Get(n)->GetLength() - 1;
if (b >= 0 & s->Get(b) = c) {
done := true;
};
};
tree->Get(suffix)->SetSuffix(tree->Get(n)->GetEdges()->Find(c)->Get());
};
};
};
return tree; }
function : SubPalindromes(tree : Vector<Node>) ~ Vector<String> {
s := Vector->New()<String>;
SubPalindromesChildren(0, "", tree, s);
keys := tree->Get(1)->GetEdges()->GetKeys()<CharHolder>;
each(k : keys) {
key := keys->Get(k);
str := key->Get()->ToString();
s->AddBack(str);
value := tree->Get(1)->GetEdges()->Find(key)->As(IntHolder)->Get();
SubPalindromesChildren(value, str, tree, s);
};
return s; }
function : SubPalindromesChildren(n : Int, p : String, tree : Vector<Node>, s : Vector<String>) ~ Nil {
keys := tree->Get(n)->GetEdges()->GetKeys()<CharHolder>;
each(k : keys) {
key := keys->Get(k);
c := key->Get();
value := tree->Get(n)->GetEdges()->Find(key)->As(IntHolder)->Get();
str := ""; str += c; str += p; str += c;
s->AddBack(str);
SubPalindromesChildren(value, str, tree, s);
};
}
function : Show(result : Vector<String>) ~ Nil {
out := "[";
each(i : result) {
out += result->Get(i);
if(i + 1 < result->Size()) {
out += ", ";
};
};
out += "]";
out->PrintLine();
}
}
class Node {
@length : Int; @edges : Map<CharHolder, IntHolder>; @suffix : Int;
New(length : Int, edges : Map<CharHolder, IntHolder>, suffix : Int) {
@length := length;
@edges := edges <> Nil ? edges : Map->New()<CharHolder, IntHolder>;
@suffix := suffix;
}
New(length : Int) {
@length := length;
@edges := Map->New()<CharHolder, IntHolder>;
}
method : public : GetLength() ~ Int {
return @length;
}
method : public : GetSuffix() ~ Int {
return @suffix;
}
method : public : SetSuffix(suffix : Int) ~ Nil {
@suffix := suffix;
}
method : public : GetEdges() ~ Map<CharHolder, IntHolder> {
return @edges;
}
}</lang>
- Output:
[ee, e, r, t, rtr, ertre, eertree]
Perl
<lang perl>$str = "eertree";
for $n (1 .. length($str)) {
for $m (1 .. length($str)) {
$strrev = "";
$strpal = substr($str, $n-1, $m);
if ($strpal ne "") {
for $p (reverse 1 .. length($strpal)) {
$strrev .= substr($strpal, $p-1, 1);
}
($strpal eq $strrev) and push @pal, $strpal;
}
}
}
print join ' ', grep {not $seen{$_}++} @pal, "\n";</lang>
- Output:
e ee eertree ertre r rtr t
Phix
If you use this in anger it may be wise to replace {string chars, sequence next} with a dictionary, which can obviously be either a new dictionary for each node, or perhaps better a single/per tree dictionary keyed on {n,ch}. <lang Phix>enum LEN,SUFF,CHARS,NEXT
function node(integer len, suffix=1, string chars="", sequence next={})
return {len,suffix,chars,next} -- must match above enum!
end function
function eertree(string s) sequence tree = {node(-1), -- odd lengths
node(0)} -- even lengths
integer suff = 2 -- max suffix palindrome
for i=1 to length(s) do
integer cur = suff, curlen, ch = s[i], k
while (true) do
curlen = tree[cur][LEN]
k = i-1-curlen
if k>=1 and s[k]==ch then
exit
end if
cur = tree[cur][SUFF]
end while
k = find(ch,tree[cur][CHARS])
if k then
suff = tree[cur][NEXT][k]
else
tree = append(tree,node(curlen+2))
suff = length(tree)
tree[cur][CHARS] &= ch
tree[cur][NEXT] &= suff
if tree[suff][LEN]==1 then
tree[suff][SUFF] = 2
else
while (true) do
cur = tree[cur][SUFF]
curlen = tree[cur][LEN]
k = i-1-curlen
if k>=0 and s[k]==ch then
k = find(ch,tree[cur][CHARS])
if k then
tree[suff][SUFF] = tree[cur][NEXT][k]
end if
exit
end if
end while
end if
end if
end for
return tree
end function
function children(sequence s, tree, integer n, string root="")
for i=1 to length(tree[n][CHARS]) do
integer c = tree[n][CHARS][i],
nxt = tree[n][NEXT][i]
string p = iff(n=1 ? c&""
: c&root&c)
s = append(s, p)
s = children(s, tree, nxt, p)
end for
return s
end function
procedure main()
sequence tree = eertree("eertree")
puts(1,"tree:\n")
for i=1 to length(tree) do
sequence ti = tree[i]
ti[NEXT] = sprint(ti[NEXT])
printf(1,"[%d]: len:%2d suffix:%d chars:%-5s next:%s\n",i&ti)
end for
puts(1,"\n")
-- odd then even lengths: ?children(children(s,tree,1), tree, 2)
end procedure main()</lang>
- Output:
The tree matches Fig 1 in the pdf linked above.
tree:
[1]: len:-1 suffix:1 chars:ert next:{3,5,6}
[2]: len: 0 suffix:1 chars:e next:{4}
[3]: len: 1 suffix:2 chars: next:{}
[4]: len: 2 suffix:3 chars: next:{}
[5]: len: 1 suffix:2 chars: next:{}
[6]: len: 1 suffix:2 chars:r next:{7}
[7]: len: 3 suffix:5 chars:e next:{8}
[8]: len: 5 suffix:3 chars:e next:{9}
[9]: len: 7 suffix:4 chars: next:{}
{"e","r","t","rtr","ertre","eertree","ee"}
Python
<lang python>#!/bin/python from __future__ import print_function
class Node(object): def __init__(self): self.edges = {} # edges (or forward links) self.link = None # suffix link (backward links) self.len = 0 # the length of the node
class Eertree(object): def __init__(self): self.nodes = [] # two initial root nodes self.rto = Node() #odd length root node, or node -1 self.rte = Node() #even length root node, or node 0
# Initialize empty tree self.rto.link = self.rte.link = self.rto; self.rto.len = -1 self.rte.len = 0 self.S = [0] # accumulated input string, T=S[1..i] self.maxSufT = self.rte # maximum suffix of tree T
def get_max_suffix_pal(self, startNode, a): # We traverse the suffix-palindromes of T in the order of decreasing length. # For each palindrome we read its length k and compare T[i-k] against a # until we get an equality or arrive at the -1 node. u = startNode i = len(self.S) k = u.len while id(u) != id(self.rto) and self.S[i - k - 1] != a: assert id(u) != id(u.link) #Prevent infinte loop u = u.link k = u.len
return u
def add(self, a):
# We need to find the maximum suffix-palindrome P of Ta # Start by finding maximum suffix-palindrome Q of T. # To do this, we traverse the suffix-palindromes of T # in the order of decreasing length, starting with maxSuf(T) Q = self.get_max_suffix_pal(self.maxSufT, a)
# We check Q to see whether it has an outgoing edge labeled by a. createANewNode = not a in Q.edges
if createANewNode: # We create the node P of length Q+2 P = Node() self.nodes.append(P) P.len = Q.len + 2 if P.len == 1: # if P = a, create the suffix link (P,0) P.link = self.rte else: # It remains to create the suffix link from P if |P|>1. Just # continue traversing suffix-palindromes of T starting with the suffix # link of Q. P.link = self.get_max_suffix_pal(Q.link, a).edges[a]
# create the edge (Q,P) Q.edges[a] = P
#P becomes the new maxSufT self.maxSufT = Q.edges[a]
#Store accumulated input string self.S.append(a)
return createANewNode
def get_sub_palindromes(self, nd, nodesToHere, charsToHere, result): #Each node represents a palindrome, which can be reconstructed #by the path from the root node to each non-root node.
#Traverse all edges, since they represent other palindromes for lnkName in nd.edges: nd2 = nd.edges[lnkName] #The lnkName is the character used for this edge self.get_sub_palindromes(nd2, nodesToHere+[nd2], charsToHere+[lnkName], result)
#Reconstruct based on charsToHere characters. if id(nd) != id(self.rto) and id(nd) != id(self.rte): #Don't print for root nodes tmp = "".join(charsToHere) if id(nodesToHere[0]) == id(self.rte): #Even string assembled = tmp[::-1] + tmp else: #Odd string assembled = tmp[::-1] + tmp[1:] result.append(assembled)
if __name__=="__main__": st = "eertree" print ("Processing string", st) eertree = Eertree() for ch in st: eertree.add(ch)
print ("Number of sub-palindromes:", len(eertree.nodes))
#Traverse tree to find sub-palindromes result = [] eertree.get_sub_palindromes(eertree.rto, [eertree.rto], [], result) #Odd length words eertree.get_sub_palindromes(eertree.rte, [eertree.rte], [], result) #Even length words print ("Sub-palindromes:", result)</lang>
- Output:
Processing string eertree Number of sub-palindromes: 7 Sub-palindromes: ['r', 'e', 'eertree', 'ertre', 'rtr', 't', 'ee']
Racket
<lang racket>#lang racket (struct node (edges ; edges (or forward links)
link ; suffix link (backward links)
len) ; the length of the node
#:mutable)
(define (new-node link len) (node (make-hash) link len))
(struct eertree (nodes
rto ; odd length root node, or node -1
rte ; even length root node, or node 0
S ; accumulated input string, T=S[1..i]
max-suf-t) ; maximum suffix of tree T
#:mutable)
(define (new-eertree)
(let* ((rto (new-node #f -1))
(rte (new-node rto 0)))
(eertree null rto rte (list 0) rte)))
(define (eertree-get-max-suffix-pal et start-node a)
#| We traverse the suffix-palindromes of T in the order of decreasing length.
For each palindrome we read its length k and compare T[i-k] against a
until we get an equality or arrive at the -1 node. |#
(match et
[(eertree nodes rto rte (and S (app length i)) max-suf-t)
(let loop ((u start-node))
(let ((k (node-len u)))
(if (or (eq? u rto) (= (list-ref S (- i k 1)) a))
u
(let ((u→ (node-link u)))
(when (eq? u u→) (error 'eertree-get-max-suffix-pal "infinite loop"))
(loop u→)))))]))
(define (eertree-add! et a)
#| We need to find the maximum suffix-palindrome P of Ta
Start by finding maximum suffix-palindrome Q of T.
To do this, we traverse the suffix-palindromes of T
in the order of decreasing length, starting with maxSuf(T) |#
(match (eertree-get-max-suffix-pal et (eertree-max-suf-t et) a)
[(node Q.edges Q.→ Q.len)
;; We check Q to see whether it has an outgoing edge labeled by a.
(define new-node? (not (hash-has-key? Q.edges a)))
(when new-node?
(define P (new-node #f (+ Q.len 2))) ; We create the node P of length Q+2
(set-eertree-nodes! et (append (eertree-nodes et) (list P)))
(define P→
(if (= (node-len P) 1)
(eertree-rte et) ; if P = a, create the suffix link (P,0)
;; It remains to c reate the suffix link from P if |P|>1.
;; Just continue traversing suffix-palindromes of T starting with the suffix link of Q.
(hash-ref (node-edges (eertree-get-max-suffix-pal et Q.→ a)) a)))
(set-node-link! P P→)
(hash-set! Q.edges a P)) ; create the edge (Q,P)
(set-eertree-max-suf-t! et (hash-ref Q.edges a)) ; P becomes the new maxSufT
(set-eertree-S! et (append (eertree-S et) (list a))) ; Store accumulated input string
new-node?]))
(define (eertree-get-sub-palindromes et)
(define (inr nd (node-path (list nd)) (char-path/rev null))
;; Each node represents a palindrome, which can be reconstructed by the path from the root node to
;; each non-root node.
(let ((deeper ; Traverse all edges, since they represent other palindromes
(for/fold ((result null)) (([→-name nd2] (in-hash (node-edges nd))))
; The lnk-name is the character used for this edge
(append result (inr nd2 (append node-path (list nd2)) (cons →-name char-path/rev)))))
(root-node? (or (eq? (eertree-rto et) nd) (eq? (eertree-rte et) nd))))
(if root-node? ; Don't add root nodes
deeper
(let ((even-string? (eq? (car node-path) (eertree-rte et)))
(char-path (reverse char-path/rev)))
(cons (append char-path/rev (if even-string? char-path (cdr char-path))) deeper)))))
inr)
(define (eertree-get-palindromes et)
(define sub (eertree-get-sub-palindromes et))
(append (sub (eertree-rto et))
(sub (eertree-rte et))))
(module+ main
(define et (new-eertree)) ;; eertree works in integer space, so we'll map to/from char space here (for ((c "eertree")) (eertree-add! et (char->integer c))) (map (compose list->string (curry map integer->char)) (eertree-get-palindromes et)))
</lang>
- Output:
'("t" "rtr" "ertre" "eertree" "r" "e" "ee")
Raku
(formerly Perl 6)
<lang perl6>my $str = "eertree"; my @pal = (); my ($strrev,$strpal);
for (1 .. $str.chars) -> $n {
for (1 .. $str.chars) -> $m {
$strrev = "";
$strpal = $str.substr($n-1, $m);
if ($strpal ne "") {
for ($strpal.chars ... 1) -> $p {
$strrev ~= $strpal.substr($p-1,1);
}
($strpal eq $strrev) and @pal.push($strpal);
}
}
}
say @pal.unique; </lang>
- Output:
(e ee eertree ertre r rtr t)
REXX
This REXX program is modeled after the Ring example. <lang rexx>/*REXX program creates a list of (unique) sub─palindromes that exist in an input string.*/ parse arg x . /*obtain optional input string from CL.*/ if x== | x=="," then x= 'eertree' /*Not specified? Then use the default.*/ L= length(x) /*the length (in chars) of input string*/ @.= . /*@ tree indicates uniqueness of pals. */ $= /*list of unsorted & unique palindromes*/
do j=1 for L /*start at the left side of the string.*/
do k=1 for L /*traverse from left to right of string*/
parse var x =(j) y +(k) /*extract a substring from the string. */
if reverse(y)\==y | @.y\==. then iterate /*Partial string a palindrome? Skip it*/
@.y= y /*indicate a sub─palindrome was found. */
$= $' ' y /*append the sub─palindrome to the list*/
end /*k*/ /* [↑] an extra blank is inserted. */
end /*j*/
say '──────── The input string that is being used: ' space(x) say '──────── The number of sub─palindromes found: ' words($) say '──────── The list of sub─palindromes found: ' strip($)
/*stick a fork in it, we're all done. */</lang>
- output when using the default input:
──────── The input string that is being used: eertree ──────── The number of sub─palindromes found: 7 ──────── The list of sub─palindromes found: e ee eertree ertre r rtr t
Ring
<lang ring>
- Project : Eertree
str = "eertree" pal = [] for n=1 to len(str)
for m=1 to len(str)
strrev = ""
strpal = substr(str, n, m)
if strpal != ""
for p=len(strpal) to 1 step -1
strrev = strrev + strpal[p]
next
if strpal = strrev
add(pal, strpal)
ok
ok
next
next sortpal = sort(pal) for n=len(sortpal) to 2 step -1
if sortpal[n] = sortpal[n-1]
del(sortpal, n)
ok
next see sortpal + nl </lang> Output:
e ee eertree ertre r rtr t
Visual Basic .NET
<lang vbnet>Module Module1
Class Node
Public Sub New(Len As Integer)
Length = Len
Edges = New Dictionary(Of Char, Integer)
End Sub
Public Sub New(len As Integer, edg As Dictionary(Of Char, Integer), suf As Integer)
Length = len
Edges = If(IsNothing(edg), New Dictionary(Of Char, Integer), edg)
Suffix = suf
End Sub
Property Edges As Dictionary(Of Char, Integer)
Property Length As Integer
Property Suffix As Integer
End Class
ReadOnly EVEN_ROOT As Integer = 0 ReadOnly ODD_ROOT As Integer = 1
Function Eertree(s As String) As List(Of Node)
Dim tree As New List(Of Node) From {
New Node(0, New Dictionary(Of Char, Integer), ODD_ROOT),
New Node(-1, New Dictionary(Of Char, Integer), ODD_ROOT)
}
Dim suffix = ODD_ROOT
Dim n As Integer
Dim k As Integer
For i = 1 To s.Length
Dim c = s(i - 1)
n = suffix
While True
k = tree(n).Length
Dim b = i - k - 2
If b >= 0 AndAlso s(b) = c Then
Exit While
End If
n = tree(n).Suffix
End While
If tree(n).Edges.ContainsKey(c) Then
suffix = tree(n).Edges(c)
Continue For
End If
suffix = tree.Count
tree.Add(New Node(k + 2))
tree(n).Edges(c) = suffix
If tree(suffix).Length = 1 Then
tree(suffix).Suffix = 0
Continue For
End If
While True
n = tree(n).Suffix
Dim b = i - tree(n).Length - 2
If b >= 0 AndAlso s(b) = c Then
Exit While
End If
End While
Dim a = tree(n)
Dim d = a.Edges(c)
Dim e = tree(suffix)
e.Suffix = d
Next
Return tree End Function
Function SubPalindromes(tree As List(Of Node)) As List(Of String)
Dim s As New List(Of String)
Dim children As Action(Of Integer, String) = Sub(n As Integer, p As String)
For Each c In tree(n).Edges.Keys
Dim m = tree(n).Edges(c)
Dim p1 = c + p + c
s.Add(p1)
children(m, p1)
Next
End Sub
children(0, "")
For Each c In tree(1).Edges.Keys
Dim m = tree(1).Edges(c)
Dim ct = c.ToString()
s.Add(ct)
children(m, ct)
Next
Return s
End Function
Sub Main()
Dim tree = Eertree("eertree")
Dim result = SubPalindromes(tree)
Dim listStr = String.Join(", ", result)
Console.WriteLine("[{0}]", listStr)
End Sub
End Module</lang>
- Output:
[ee, e, r, t, rtr, ertre, eertree]
zkl
<lang zkl>class Node{
fcn init(length){
var edges=Dictionary(), # edges (or forward links). (char:Node)
link=Void, # suffix link (backward links)
sz =length; # node length.
}
} class Eertree{
fcn init(string=Void){
var nodes=List(),
# two initial root nodes rto=Node(-1), # odd length root node, or node -1 rte=Node(0); # even length root node, or node 0
rto.link=rte.link=rto; # Initialize empty tree
var S =Data(Void,0), # accumulated input string, T=S[1..i], byte buffer
maxSufT=rte; # maximum suffix of tree T
if(string) string.pump(addChar); // go ahead and build the tree
}
fcn get_max_suffix_pal(startNode,a){
# We traverse the suffix-palindromes of T in the order of decreasing length.
# For each palindrome we read its length k and compare T[i-k] against a
# until we get an equality or arrive at the -1 node.
u,i,k := startNode, S.len(), u.sz;
while(u.id!=rto.id and S.charAt(i - k - 1)!=a){
_assert_(u.id!=u.link.id); # Prevent infinte loop u,k = u.link,u.sz;
}
return(u);
}
fcn addChar(a){
# We need to find the maximum suffix-palindrome P of Ta # Start by finding maximum suffix-palindrome Q of T. # To do this, we traverse the suffix-palindromes of T # in the order of decreasing length, starting with maxSuf(T)
Q:=get_max_suffix_pal(maxSufT,a);
# We check Q to see whether it has an outgoing edge labeled by a.
createANewNode:=(not Q.edges.holds(a));
if(createANewNode){
P:=Node(Q.sz + 2); nodes.append(P); if(P.sz==1) P.link=rte; # if P = a, create the suffix link (P,0) else # It remains to create the suffix link from P if |P|>1. Just # continue traversing suffix-palindromes of T starting with the suffix # link of Q. P.link=get_max_suffix_pal(Q.link,a).edges[a]; Q.edges[a]=P; # create the edge (Q,P)
}
maxSufT=Q.edges[a]; # P becomes the new maxSufT
S.append(a); # Store accumulated input string
return(createANewNode); // in case anyone wants to know a is new edge
}
fcn get_sub_palindromes{
result:=List();
sub_palindromes(rto, T(rto),"", result); # Odd length words
sub_palindromes(rte, T(rte),"", result); # Even length words
result
}
fcn [private] sub_palindromes(nd, nodesToHere, charsToHere, result){
// nodesToHere needs to be read only
# Each node represents a palindrome, which can be reconstructed # by the path from the root node to each non-root node.
# Traverse all edges, since they represent other palindromes
nd.edges.pump(Void,'wrap([(lnkName,nd2)]){
sub_palindromes(nd2, nodesToHere+nd2, charsToHere+lnkName, result);
});
# Reconstruct based on charsToHere characters.
if(nd.id!=rto.id and nd.id!=rte.id){ # Don't print for root nodes
if(nodesToHere[0].id==rte.id) # Even string assembled:=charsToHere.reverse() + charsToHere; else assembled:=charsToHere.reverse() + charsToHere[1,*]; # Odd string result.append(assembled);
} }
}</lang> <lang zkl>st:="eertree"; println("Processing string \"", st,"\""); eertree:=Eertree(st); println("Number of sub-palindromes: ", eertree.nodes.len()); println("Sub-palindromes: ", eertree.get_sub_palindromes());</lang>
- Output:
Processing string "eertree"
Number of sub-palindromes: 7
Sub-palindromes: L("e","r","eertree","ertre","rtr","t","ee")