Truth table: Difference between revisions

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=={{header|Tcl}}==
=={{header|Tcl}}==
<lang tcl>package require Tcl 8.5
<lang tcl>package require Tcl 8.5

puts -nonewline "Enter a boolean expression: "
puts -nonewline "Enter a boolean expression: "
flush stdout
flush stdout
set exp [gets stdin]
set exp [gets stdin]

# Generate the nested loops as the body of a lambda term.
set vars [lsort -unique [regexp -inline -all {\$\w+} $exp]]
set vars [lsort -unique [regexp -inline -all {\$\w+} $exp]]
set cmd [list format [string repeat "%s\t" [llength $vars]]%s]
set cmd [list format [string repeat "%s\t" [llength $vars]]%s]
Line 360: Line 363:
set cmd [list foreach [string range $v 1 end] {0 1} $cmd]
set cmd [list foreach [string range $v 1 end] {0 1} $cmd]
}
}

puts [join $vars \t]\tResult
puts [join $vars \t]\tResult
apply [list {} $cmd]</lang>
apply [list {} $cmd]</lang>

Revision as of 15:48, 12 November 2011

Truth table is a draft programming task. It is not yet considered ready to be promoted as a complete task, for reasons that should be found in its talk page.

A truth table is a display of the inputs to, and the output of a Boolean equation organised as a table where each row gives one combination of input values and the corresponding value of the equation.

Task
  1. Input a Boolean equation from the user as a string then calculate and print a formatted truth table for the given equation.
    (One can assume that the user input is correct).
  2. Print and show output for Boolean equations of two and three input variables, but any program should not be limited to that many variables in the equation.
  3. Either reverse-polish or infix notation expressions are allowed.
Cf.
Ref.

Go

Variance: Runtime evaluation or code generation is not directly supported in Go. The function tt here does however accept functions with any number of arguments and produce the corresponding truth table. <lang go>package main

import (

   "fmt"
   "reflect"

)

func xor(a, b bool) bool {

   return a != b

}

func stu(s, t, u bool) bool {

   return s || xor(t, u)

}

func abcd(a, b, c, d bool) bool {

   return xor(a, xor(b, xor(c, d)))

}

func main() {

   tt(xor,  "A     B        A ^ B")
   tt(stu,  "S     T     U        S | ( T ^ U )")
   tt(abcd, "A     B     C     D        A ^ (B ^ (C ^ D))")

}

func tt(f interface{}, label string) {

   fmt.Println()
   fmt.Println(label)
   tv := []bool{false, true}
   v := reflect.ValueOf(f)
   n := reflect.TypeOf(f).NumIn()
   a := make([]reflect.Value, n)
   lines := 1 << uint(n)
   for l := 0; l < lines; l++ {
       s := "  "
       lBits := l
       for i := range a {
           ba := tv[lBits & 1]
           s = fmt.Sprintf("%-5t %s", ba, s)
           a[n-1-i] = reflect.ValueOf(ba)
           lBits >>= 1
       }
       fmt.Println(s, v.Call(a)[0].Bool())
   }

}</lang> Output:

A     B        A ^ B
false false    false
false true     true
true  false    true
true  true     false

S     T     U        S | ( T ^ U )
false false false    false
false false true     true
false true  false    true
false true  true     false
true  false false    true
true  false true     true
true  true  false    true
true  true  true     true

A     B     C     D        A ^ (B ^ (C ^ D))
false false false false    false
false false false true     true
false false true  false    true
false false true  true     false
false true  false false    true
false true  false true     false
false true  true  false    false
false true  true  true     true
true  false false false    true
true  false false true     false
true  false true  false    false
true  false true  true     true
true  true  false false    false
true  true  false true     true
true  true  true  false    true
true  true  true  true     false

J

Implementation:

<lang j>truthTable=:3 :0

 assert. -. 1 e. 'data expr names table' e.&;: y
 names=. ~. (#~ _1 <: nc) ;:expr=. y
 data=. #:i.2^#names
 (names)=. |:data
 (' ',;:inv names,<expr),(1+#@>names,<expr)":data,.".expr

)</lang>

The argument is expected to be a valid boolean J sentence which, among other things, does not use any of the words used within the implementation (but any single-character name is valid).

Example use:

<lang j> truthTable '-.b'

b -.b
0   1
1   0
  truthTable 'a*b'
a b a*b
0 0   0
0 1   0
1 0   0
1 1   1
  truthTable 'a+.b'
a b a+.b
0 0    0
0 1    1
1 0    1
1 1    1
  truthTable 'a<:b'
a b a<:b
0 0    1
0 1    1
1 0    0
1 1    1
  truthTable '(a*bc)+.d'
a bc d (a*bc)+.d
0  0 0         0
0  0 1         1
0  1 0         0
0  1 1         1
1  0 0         0
1  0 1         1
1  1 0         1
1  1 1         1</lang>

Java

Works with: Java version 1.5+

This example would require a system of pages that would be moderately complicated to set up and follow (or a really huge page that would also be hard to follow) since there is no eval in Java, so you can find information about it here. There is a link to an executable jar file with the required source files there. The program shows the expression and the truth table in a window. The expression must use prefix notation, single characters for input names (numerals, lowercase letters, and uppercase letters are the easiest to read), and the outputs can be shown as 1/0 or T/F. There is also a "Check" button which will make sure that the operators have enough operands. The window looks something like this:

PicoLisp

<lang PicoLisp>(de truthTable (Expr)

  (let Vars
     (uniq
        (make
           (setq Expr
              (recur (Expr)  # Convert infix to prefix notation
                 (cond
                    ((atom Expr) (link Expr))
                    ((== 'not (car Expr))
                       (list 'not (recurse (cadr Expr))) )
                    (T
                       (list
                          (cadr Expr)
                          (recurse (car Expr))
                          (recurse (caddr Expr)) ) ) ) ) ) ) )
     (for V Vars
        (prin (align -7 V)) )
     (prinl)
     (bind (mapcar cons Vars)
        (do (** 2 (length Vars))
           (for "V" Vars
              (space (if (print (val "V")) 6 4)) )
           (println (eval Expr))
           (find '(("V") (set "V" (not (val "V")))) Vars) ) ) ) )</lang>

Test: <lang PicoLisp>: (truthTable (str "A and (B or C)")) A B C NIL NIL NIL NIL T NIL NIL NIL NIL T NIL NIL T T NIL T NIL NIL T NIL T NIL T T NIL T T NIL T T T T

(truthTable (str "not (Foo and (Bar or Mumble))"))

Foo Bar Mumble NIL NIL NIL T T NIL NIL T NIL T NIL T T T NIL NIL NIL NIL T T T NIL T NIL NIL T T T T T T NIL

(truthTable (str "(A xor B) and (B or C)"))

A B C NIL NIL NIL NIL T NIL NIL NIL NIL T NIL T T T NIL NIL NIL NIL T NIL T NIL T T NIL T T T T T T NIL

(truthTable (str "(A xor B) and ((not B) or C)"))

A B C NIL NIL NIL NIL T NIL NIL T NIL T NIL NIL T T NIL NIL NIL NIL T NIL T NIL T T NIL T T T T T T NIL</lang>

Python

This accepts correctly formatted Python boolean expressions. <lang python>from itertools import product

while True:

   bexp = input('\nBoolean expression: ')
   bexp = bexp.strip()
   if not bexp:
       print("\nThank you")
       break
   code = compile(bexp, '<string>', 'eval')
   names = code.co_names
   print('\n' + ' '.join(names), ':', bexp)
   for values in product(range(2), repeat=len(names)):
       env = dict(zip(names, values))
       print(' '.join(str(v) for v in values), ':', eval(code, env))

</lang>

Sample output
Boolean expression: A ^ B

A B : A ^ B
0 0 : 0
0 1 : 1
1 0 : 1
1 1 : 0

Boolean expression: S | ( T ^ U )

S T U : S | ( T ^ U )
0 0 0 : 0
0 0 1 : 1
0 1 0 : 1
0 1 1 : 0
1 0 0 : 1
1 0 1 : 1
1 1 0 : 1
1 1 1 : 1

Boolean expression: A ^ (B ^ (C ^ D))

A B C D : A ^ (B ^ (C ^ D))
0 0 0 0 : 0
0 0 0 1 : 1
0 0 1 0 : 1
0 0 1 1 : 0
0 1 0 0 : 1
0 1 0 1 : 0
0 1 1 0 : 0
0 1 1 1 : 1
1 0 0 0 : 1
1 0 0 1 : 0
1 0 1 0 : 0
1 0 1 1 : 1
1 1 0 0 : 0
1 1 0 1 : 1
1 1 1 0 : 1
1 1 1 1 : 0

Boolean expression: 

Thank you

Ruby

Uses eval, so blindly trusts the user's input. The core true and false objects understand the methods & (and), | (or), ! (not) and ^ (xor) -- [1] <lang ruby>loop do

 print "\ninput a boolean expression (e.g. 'a & b'): "
 expr = gets.strip.downcase 
 break if expr.empty?
 vars = expr.scan(/\p{Alpha}+/)
 if vars.empty?
   puts "no variables detected in your boolean expression"
   next
 end
 vars.each {|v| print "#{v}\t"}
 puts "| #{expr}"
 prefix = []
 suffix = []
 vars.each do |v|
   prefix << "[false, true].each do |#{v}|"
   suffix << "end"
 end
 body = vars.inject("puts ") {|str, v| str + "#{v}.to_s + '\t' + "} 
 body += '"| " + eval(expr).to_s'
 eval (prefix + [body] + suffix).join("\n")

end</lang>

Example

input a boolean expression (e.g. 'a & b'): !a
a       | !a
false   | true
true    | false

input a boolean expression (e.g. 'a & b'): a|!b
a       b       | a|!b
false   false   | true
false   true    | false
true    false   | true
true    true    | true

input a boolean expression (e.g. 'a & b'): ((a^b)^c)^d
a       b       c       d       | ((a^b)^c)^d
false   false   false   false   | false
false   false   false   true    | true
false   false   true    false   | true
false   false   true    true    | false
false   true    false   false   | true
false   true    false   true    | false
false   true    true    false   | false
false   true    true    true    | true
true    false   false   false   | true
true    false   false   true    | false
true    false   true    false   | false
true    false   true    true    | true
true    true    false   false   | false
true    true    false   true    | true
true    true    true    false   | true
true    true    true    true    | false

Tcl

<lang tcl>package require Tcl 8.5

puts -nonewline "Enter a boolean expression: " flush stdout set exp [gets stdin]

  1. Generate the nested loops as the body of a lambda term.

set vars [lsort -unique [regexp -inline -all {\$\w+} $exp]] set cmd [list format [string repeat "%s\t" [llength $vars]]%s] append cmd " {*}\[[list subst $vars]\] \[[list expr $exp]\]" set cmd "puts \[$cmd\]" foreach v [lreverse $vars] {

   set cmd [list foreach [string range $v 1 end] {0 1} $cmd]

}

puts [join $vars \t]\tResult apply [list {} $cmd]</lang> Sample run:

Enter a boolean expression: ($a&&$b)||$c
$a	$b	$c	Result
0	0	0	0
0	0	1	1
0	1	0	0
0	1	1	1
1	0	0	0
1	0	1	1
1	1	0	1
1	1	1	1