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Talk:Roots of a quadratic function: Difference between revisions
Talk:Roots of a quadratic function (view source)
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I clearly see come of programs (Ada, and some marked as "translation of Ada") use
(b^2-4ac)/2*a,
there correct way is
(b^2-4ac)/(2*a).
I wonder why noone spotted this earlier!
<cite>Forsythe, Michael Malcolm and Cleve Mole suggest to try it on a=1, b=-10<sup>5</sup>, c=1</cite>, but Ada sample code uses -10e5, which is indeed -1e6 (-10<sup>6</sup>), if I was not wrong since I knew the "e" notation... --[[User:ShinTakezou|ShinTakezou]] 21:24, 22 June 2009 (UTC)
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