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Talk:Roots of a quadratic function: Difference between revisions
Talk:Roots of a quadratic function (view source)
Revision as of 14:28, 16 September 2010
, 13 years ago"I wonder why noone spotted this earlier!" => Basically all the test cases had a = 1. :-)
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("I wonder why noone spotted this earlier!" => Basically all the test cases had a = 1. :-)) |
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<cite>Forsythe, Michael Malcolm and Cleve Mole suggest to try it on a=1, b=-10<sup>5</sup>, c=1</cite>, but Ada sample code uses -10e5, which is indeed -1e6 (-10<sup>6</sup>), if I was not wrong since I knew the "e" notation... --[[User:ShinTakezou|ShinTakezou]] 21:24, 22 June 2009 (UTC)
Basically all the test cases had a = 1, :-) So I added some test cases especially where a ≠ 1, hence 2*a ≠ 2/a.... [[User:NevilleDNZ|NevilleDNZ]] 14:28, 16 September 2010 (UTC)
== J example ==
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