Talk:Loops/N plus one half

I noticed that many implementations don't run the loop 9.5 times. Instead a check is made whether the comma has to be printed. This way the loop still runs exactly 10 times, with a different action taken depending on the loop variable.

This is pointed out in the description:

in the last iteration one executes only part of the loop body

Notice the quotes around n+1/2 showing that it's not literally n+1/2 times, but rather the last time through only part of the work is done. Running the loop 9.5 times isn't a requirement, but if you can get your language to do it then go for it. --Mwn3d 21:09, 4 November 2009 (UTC)

Task name doesn't make sense?

You are asked to print the numbers one to ten with separating commas. Surely n == 10. And so you want to go through a loop doing the same thing n minus one, i.e 9 times; then do something else the n'th time through the loop, as many of the examples do.

A more correct name might be "Loop/n minus one half", but even better might be "Looping with a different action on the last iteration" - its not as twee, but more accurate? --Paddy3118 06:10, 5 November 2009 (UTC)