Talk:Euler's identity

Euler's identity is actually e^ix=cos(x)+i.sin(x). The example given is a special case when when x=π. cos π is -1 and sin π is 0. Thus e^iπ is obviously -1.--Nigel Galloway (talk) 14:31, 9 August 2021 (UTC)

FWIW, the Wikipedia article on the subject describes e^ix=cos(x)+i.sin(x) as Euler's formula and agrees with the task author that e^iπ + 1 = 0 is called Euler's identity. I have no idea whether this is correct terminology or not. --PureFox (talk) 14:48, 9 August 2021 (UTC)