Talk:Euler's identity: Difference between revisions
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(Created page with "Euler's identity is actually e<sup>ix</sup>=cos(x)+i.sin(x). The example given is a special case when when x=π. cos π is -1 and sin π is 0. Thus e<sup>iπ</sup> is obviousl...") |
(Response to Nigel.) |
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Euler's identity is actually e<sup>ix</sup>=cos(x)+i.sin(x). The example given is a special case when when x=π. cos π is -1 and sin π is 0. Thus e<sup>iπ</sup> is obviously -1.--[[User:Nigel Galloway|Nigel Galloway]] ([[User talk:Nigel Galloway|talk]]) 14:31, 9 August 2021 (UTC) |
Euler's identity is actually e<sup>ix</sup>=cos(x)+i.sin(x). The example given is a special case when when x=π. cos π is -1 and sin π is 0. Thus e<sup>iπ</sup> is obviously -1.--[[User:Nigel Galloway|Nigel Galloway]] ([[User talk:Nigel Galloway|talk]]) 14:31, 9 August 2021 (UTC) |
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:FWIW, the [https://en.wikipedia.org/wiki/Euler%27s_identity Wikipedia article] on the subject describes e<sup>ix</sup>=cos(x)+i.sin(x) as ''Euler's formula'' and agrees with the task author that e<sup>iπ</sup> + 1 = 0 is called ''Euler's identity''. I have no idea whether this is correct terminology or not. --[[User:PureFox|PureFox]] ([[User talk:PureFox|talk]]) 14:48, 9 August 2021 (UTC) |
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Revision as of 14:49, 9 August 2021
Euler's identity is actually eix=cos(x)+i.sin(x). The example given is a special case when when x=π. cos π is -1 and sin π is 0. Thus eiπ is obviously -1.--Nigel Galloway (talk) 14:31, 9 August 2021 (UTC)
- FWIW, the Wikipedia article on the subject describes eix=cos(x)+i.sin(x) as Euler's formula and agrees with the task author that eiπ + 1 = 0 is called Euler's identity. I have no idea whether this is correct terminology or not. --PureFox (talk) 14:48, 9 August 2021 (UTC)