Spelling of ordinal numbers
You are encouraged to solve this task according to the task description, using any language you may know.
Ordinal numbers (as used in this Rosetta Code task), are numbers that describe the position of something in a list.
It is this context that ordinal numbers will be used, using an English-spelled name of an ordinal number.
The ordinal numbers are (at least, one form of them):
1st 2nd 3rd 4th 5th 6th 7th ··· 99th 100th ··· 1000000000th ··· etc
sometimes expressed as:
1st 2nd 3rd 4th 5th 6th 7th ··· 99th 100th ··· 1000000000th ···
For this task, the following (English-spelled form) will be used:
first second third fourth fifth sixth seventh ninety-nineth one hundredth one billionth
Furthermore, the American version of numbers will be used here (as opposed to the British).
2,000,000,000 is two billion, not two milliard.
- Task
Write a driver and a function (subroutine/routine ···) that returns the English-spelled ordinal version of a specified number (a positive integer).
Optionally, try to support as many forms of an integer that can be expressed: 123 00123.0 1.23e2 all are forms of the same integer.
Show all output here.
- Test cases
Use (at least) the test cases of:
1 2 3 4 5 11 65 100 101 272 23456 8007006005004003
- Related tasks
AutoHotkey
Based on Number_names <lang AutoHotkey>OrdinalNumber(n){ OrdinalNumber := {"one":"first", "two":"second", "three":"third", "five":"fifth", "eight":"eighth", "nine":"ninth", "twelve": "twelfth"} RegExMatch(n, "\w+$", m) return (OrdinalNumber[m] ? RegExReplace(n, "\w+$", OrdinalNumber[m]) : n "th") }
Spell(n) { ; recursive function to spell out the name of a max 36 digit integer, after leading 0s removed
Static p1=" thousand ",p2=" million ",p3=" billion ",p4=" trillion ",p5=" quadrillion ",p6=" quintillion "
, p7=" sextillion ",p8=" septillion ",p9=" octillion ",p10=" nonillion ",p11=" decillion "
, t2="twenty",t3="thirty",t4="forty",t5="fifty",t6="sixty",t7="seventy",t8="eighty",t9="ninety"
, o0="zero",o1="one",o2="two",o3="three",o4="four",o5="five",o6="six",o7="seven",o8="eight"
, o9="nine",o10="ten",o11="eleven",o12="twelve",o13="thirteen",o14="fourteen",o15="fifteen"
, o16="sixteen",o17="seventeen",o18="eighteen",o19="nineteen"
n :=RegExReplace(n,"^0+(\d)","$1") ; remove leading 0s from n
If (11 < d := (StrLen(n)-1)//3) ; #of digit groups of 3
Return "Number too big"
If (d) ; more than 3 digits 1000+
Return Spell(SubStr(n,1,-3*d)) p%d% ((s:=SubStr(n,1-3*d)) ? ", " Spell(s) : "")
i := SubStr(n,1,1)
If (n > 99) ; 3 digits 100..999
Return o%i% " hundred" ((s:=SubStr(n,2)) ? " and " Spell(s) : "")
If (n > 19) ; n = 20..99
Return t%i% ((o:=SubStr(n,2)) ? "-" o%o% : "")
Return o%n% ; n = 0..19
}
PrettyNumber(n) { ; inserts thousands separators into a number string
Return RegExReplace( RegExReplace(n,"^0+(\d)","$1"), "\G\d+?(?=(\d{3})+(?:\D|$))", "$0,")
}</lang> Example:<lang AutoHotkey>for i, n in StrSplit("1 2 3 4 5 11 65 100 101 272 23456 8007006005004003", " ")
res .= PrettyNumber(n) "`t" Spell(n) "`t" OrdinalNumber(Spell(n)) "`n"
MsgBox % res </lang>
Outputs:
1 first 2 second 3 third 4 fourth 5 fifth 11 eleventh 65 sixty-fifth 100 one hundredth 101 one hundred and first 272 two hundred and seventy-second 23,456 twenty-three thousand , four hundred and fifty-sixth 8,007,006,005,004,003 eight quadrillion , seven trillion , six billion , five million , four thousand , third
C
<lang c>#include <stdbool.h>
- include <stdio.h>
- include <stdint.h>
- include <glib.h>
typedef uint64_t integer;
typedef struct number_names_tag {
const char* cardinal; const char* ordinal;
} number_names;
const number_names small[] = {
{ "zero", "zeroth" }, { "one", "first" }, { "two", "second" },
{ "three", "third" }, { "four", "fourth" }, { "five", "fifth" },
{ "six", "sixth" }, { "seven", "seventh" }, { "eight", "eighth" },
{ "nine", "ninth" }, { "ten", "tenth" }, { "eleven", "eleventh" },
{ "twelve", "twelfth" }, { "thirteen", "thirteenth" },
{ "fourteen", "fourteenth" }, { "fifteen", "fifteenth" },
{ "sixteen", "sixteenth" }, { "seventeen", "seventeenth" },
{ "eighteen", "eighteenth" }, { "nineteen", "nineteenth" }
};
const number_names tens[] = {
{ "twenty", "twentieth" }, { "thirty", "thirtieth" },
{ "forty", "fortieth" }, { "fifty", "fiftieth" },
{ "sixty", "sixtieth" }, { "seventy", "seventieth" },
{ "eighty", "eightieth" }, { "ninety", "ninetieth" }
};
typedef struct named_number_tag {
const char* cardinal; const char* ordinal; integer number;
} named_number;
const named_number named_numbers[] = {
{ "hundred", "hundredth", 100 },
{ "thousand", "thousandth", 1000 },
{ "million", "millionth", 1000000 },
{ "billion", "billionth", 1000000000 },
{ "trillion", "trillionth", 1000000000000 },
{ "quadrillion", "quadrillionth", 1000000000000000ULL },
{ "quintillion", "quintillionth", 1000000000000000000ULL }
};
const char* get_small_name(const number_names* n, bool ordinal) {
return ordinal ? n->ordinal : n->cardinal;
}
const char* get_big_name(const named_number* n, bool ordinal) {
return ordinal ? n->ordinal : n->cardinal;
}
const named_number* get_named_number(integer n) {
const size_t names_len = sizeof(named_numbers)/sizeof(named_numbers[0]);
for (size_t i = 0; i + 1 < names_len; ++i) {
if (n < named_numbers[i + 1].number)
return &named_numbers[i];
}
return &named_numbers[names_len - 1];
}
void append_number_name(GString* gstr, integer n, bool ordinal) {
if (n < 20)
g_string_append(gstr, get_small_name(&small[n], ordinal));
else if (n < 100) {
if (n % 10 == 0) {
g_string_append(gstr, get_small_name(&tens[n/10 - 2], ordinal));
} else {
g_string_append(gstr, get_small_name(&tens[n/10 - 2], false));
g_string_append_c(gstr, '-');
g_string_append(gstr, get_small_name(&small[n % 10], ordinal));
}
} else {
const named_number* num = get_named_number(n);
integer p = num->number;
append_number_name(gstr, n/p, false);
g_string_append_c(gstr, ' ');
if (n % p == 0) {
g_string_append(gstr, get_big_name(num, ordinal));
} else {
g_string_append(gstr, get_big_name(num, false));
g_string_append_c(gstr, ' ');
append_number_name(gstr, n % p, ordinal);
}
}
}
GString* number_name(integer n, bool ordinal) {
GString* result = g_string_sized_new(8); append_number_name(result, n, ordinal); return result;
}
void test_ordinal(integer n) {
GString* name = number_name(n, true);
printf("%llu: %s\n", n, name->str);
g_string_free(name, TRUE);
}
int main() {
test_ordinal(1); test_ordinal(2); test_ordinal(3); test_ordinal(4); test_ordinal(5); test_ordinal(11); test_ordinal(15); test_ordinal(21); test_ordinal(42); test_ordinal(65); test_ordinal(98); test_ordinal(100); test_ordinal(101); test_ordinal(272); test_ordinal(300); test_ordinal(750); test_ordinal(23456); test_ordinal(7891233); test_ordinal(8007006005004003LL); return 0;
}</lang>
- Output:
1: first 2: second 3: third 4: fourth 5: fifth 11: eleventh 15: fifteenth 21: twenty-first 42: forty-second 65: sixty-fifth 98: ninety-eighth 100: one hundredth 101: one hundred first 272: two hundred seventy-second 300: three hundredth 750: seven hundred fiftieth 23456: twenty-three thousand four hundred fifty-sixth 7891233: seven million eight hundred ninety-one thousand two hundred thirty-third 8007006005004003: eight quadrillion seven trillion six billion five million four thousand third
C++
<lang cpp>#include <iostream>
- include <string>
- include <cstdint>
typedef std::uint64_t integer;
struct number_names {
const char* cardinal; const char* ordinal;
};
const number_names small[] = {
{ "zero", "zeroth" }, { "one", "first" }, { "two", "second" },
{ "three", "third" }, { "four", "fourth" }, { "five", "fifth" },
{ "six", "sixth" }, { "seven", "seventh" }, { "eight", "eighth" },
{ "nine", "ninth" }, { "ten", "tenth" }, { "eleven", "eleventh" },
{ "twelve", "twelfth" }, { "thirteen", "thirteenth" },
{ "fourteen", "fourteenth" }, { "fifteen", "fifteenth" },
{ "sixteen", "sixteenth" }, { "seventeen", "seventeenth" },
{ "eighteen", "eighteenth" }, { "nineteen", "nineteenth" }
};
const number_names tens[] = {
{ "twenty", "twentieth" }, { "thirty", "thirtieth" },
{ "forty", "fortieth" }, { "fifty", "fiftieth" },
{ "sixty", "sixtieth" }, { "seventy", "seventieth" },
{ "eighty", "eightieth" }, { "ninety", "ninetieth" }
};
struct named_number {
const char* cardinal; const char* ordinal; integer number;
};
const named_number named_numbers[] = {
{ "hundred", "hundredth", 100 },
{ "thousand", "thousandth", 1000 },
{ "million", "millionth", 1000000 },
{ "billion", "billionth", 1000000000 },
{ "trillion", "trillionth", 1000000000000 },
{ "quadrillion", "quadrillionth", 1000000000000000ULL },
{ "quintillion", "quintillionth", 1000000000000000000ULL }
};
const char* get_name(const number_names& n, bool ordinal) {
return ordinal ? n.ordinal : n.cardinal;
}
const char* get_name(const named_number& n, bool ordinal) {
return ordinal ? n.ordinal : n.cardinal;
}
const named_number& get_named_number(integer n) {
constexpr size_t names_len = std::size(named_numbers);
for (size_t i = 0; i + 1 < names_len; ++i) {
if (n < named_numbers[i + 1].number)
return named_numbers[i];
}
return named_numbers[names_len - 1];
}
std::string number_name(integer n, bool ordinal) {
std::string result;
if (n < 20)
result = get_name(small[n], ordinal);
else if (n < 100) {
if (n % 10 == 0) {
result = get_name(tens[n/10 - 2], ordinal);
} else {
result = get_name(tens[n/10 - 2], false);
result += "-";
result += get_name(small[n % 10], ordinal);
}
} else {
const named_number& num = get_named_number(n);
integer p = num.number;
result = number_name(n/p, false);
result += " ";
if (n % p == 0) {
result += get_name(num, ordinal);
} else {
result += get_name(num, false);
result += " ";
result += number_name(n % p, ordinal);
}
}
return result;
}
void test_ordinal(integer n) {
std::cout << n << ": " << number_name(n, true) << '\n';
}
int main() {
test_ordinal(1); test_ordinal(2); test_ordinal(3); test_ordinal(4); test_ordinal(5); test_ordinal(11); test_ordinal(15); test_ordinal(21); test_ordinal(42); test_ordinal(65); test_ordinal(98); test_ordinal(100); test_ordinal(101); test_ordinal(272); test_ordinal(300); test_ordinal(750); test_ordinal(23456); test_ordinal(7891233); test_ordinal(8007006005004003LL); return 0;
}</lang>
- Output:
1: first 2: second 3: third 4: fourth 5: fifth 11: eleventh 15: fifteenth 21: twenty-first 42: forty-second 65: sixty-fifth 98: ninety-eighth 100: one hundredth 101: one hundred first 272: two hundred seventy-second 300: three hundredth 750: seven hundred fiftieth 23456: twenty-three thousand four hundred fifty-sixth 7891233: seven million eight hundred ninety-one thousand two hundred thirty-third 8007006005004003: eight quadrillion seven trillion six billion five million four thousand third
Clojure
<lang clojure>(def test-cases [1 2 3 4 5 11 65 100 101 272 23456 8007006005004003]) (pprint
(sort (zipmap test-cases (map #(clojure.pprint/cl-format nil "~:R" %) test-cases))))
</lang>
- Output:
([1 "first"] [2 "second"] [3 "third"] [4 "fourth"] [5 "fifth"] [11 "eleventh"] [65 "sixty-fifth"] [100 "one hundredth"] [101 "one hundred first"] [272 "two hundred seventy-second"] [23456 "twenty-three thousand, four hundred fifty-sixth"] [8007006005004003 "eight quadrillion, seven trillion, six billion, five million, four thousand, third"])
Common Lisp
Common Lisp's format is able to do this directly. Here's a short function wrapping it and a demonstration. <lang lisp>(defun ordinal-number (n)
(format nil "~:R" n))
- |
CL-USER> (loop for i in '(1 2 3 4 5 11 65 100 101 272 23456 8007006005004003)
do (format t "~a: ~a~%" i (ordinal-number i)))
1: first 2: second 3: third 4: fourth 5: fifth 11: eleventh 65: sixty-fifth 100: one hundredth 101: one hundred first 272: two hundred seventy-second 23456: twenty-three thousand four hundred fifty-sixth 8007006005004003: eight quadrillion seven trillion six billion five million four thousand third NIL |# </lang>
Factor
Factor's math.text.english vocabulary provides the number>text word for converting numbers to written English. It also provides the ordinal-suffix word for getting the suffix for a given number, such as th for 12. The bulk of this code deals with converting the output of number>text to ordinal format.
<lang factor>USING: assocs formatting grouping kernel literals locals math
math.parser math.text.english qw regexp sequences
splitting.extras ;
IN: rosetta-code.spelling-ordinal-numbers
<PRIVATE
! Factor supports the arbitrary use of commas in integer ! literals, as some number systems (e.g. Indian) don't solely ! break numbers up into triplets.
CONSTANT: test-cases qw{
1 2 3 4 5 11 65 100 101 272 23456 8007006005004003 123 00123.0 1.23e2 1,2,3 0b1111011 0o173 0x7B 2706/22
}
CONSTANT: replacements $[
qw{
one first
two second
three third
five fifth
eight eighth
nine ninth
twelve twelfth
} 2 group
]
- regular-ordinal ( n -- str )
[ number>text ] [ ordinal-suffix ] bi append ;
! Since Factor's number>text word contains commas and "and", ! strip them out with a regular expression.
- text>ordinal-text ( str -- str' ) R/ \sand|,/ "" re-replace ;
PRIVATE>
- number>ordinal-text ( n! -- str )
n >integer n! n number>text " ,-" split* dup last replacements at [ [ but-last ] dip suffix "" join ] [ drop n regular-ordinal ] if* text>ordinal-text ;
<PRIVATE
- print-ordinal-pair ( str x -- )
number>ordinal-text "%16s => %s\n" printf ;
PRIVATE>
- ordinal-text-demo ( -- )
test-cases [ dup string>number print-ordinal-pair ] each
"C{ 123 0 }" C{ 123 0 } print-ordinal-pair ;
MAIN: ordinal-text-demo</lang>
- Output:
1 => first
2 => second
3 => third
4 => fourth
5 => fifth
11 => eleventh
65 => sixty-fifth
100 => one hundredth
101 => one hundred first
272 => two hundred seventy-second
23456 => twenty-three thousand four hundred fifty-sixth
8007006005004003 => eight quadrillion seven trillion six billion five million four thousand third
123 => one hundred twenty-third
00123.0 => one hundred twenty-third
1.23e2 => one hundred twenty-third
1,2,3 => one hundred twenty-third
0b1111011 => one hundred twenty-third
0o173 => one hundred twenty-third
0x7B => one hundred twenty-third
2706/22 => one hundred twenty-third
C{ 123 0 } => one hundred twenty-third
Go
As with the Kotlin solution, this uses the output of say from the
Number_names task.
<lang Go>import (
"fmt"
"strings"
)
func main() { for _, n := range []int64{ 1, 2, 3, 4, 5, 11, 65, 100, 101, 272, 23456, 8007006005004003, } { fmt.Println(sayOrdinal(n)) } }
var irregularOrdinals = map[string]string{ "one": "first", "two": "second", "three": "third", "five": "fifth", "eight": "eighth", "nine": "ninth", "twelve": "twelfth", }
func sayOrdinal(n int64) string { s := say(n) i := strings.LastIndexAny(s, " -") i++ // Now s[:i] is everything upto and including the space or hyphen // and s[i:] is the last word; we modify s[i:] as required. // Since LastIndex returns -1 if there was no space/hyphen, // `i` will be zero and this will still be fine. if x, ok := irregularOrdinals[s[i:]]; ok { s = s[:i] + x } else if s[len(s)-1] == 'y' { s = s[:i] + s[i:len(s)-1] + "ieth" } else { s = s[:i] + s[i:] + "th" } return s }
// Below is a copy of https://rosettacode.org/wiki/Number_names#Go
var small = [...]string{"zero", "one", "two", "three", "four", "five", "six", "seven", "eight", "nine", "ten", "eleven", "twelve", "thirteen", "fourteen", "fifteen", "sixteen", "seventeen", "eighteen", "nineteen"} var tens = [...]string{"", "", "twenty", "thirty", "forty", "fifty", "sixty", "seventy", "eighty", "ninety"} var illions = [...]string{"", " thousand", " million", " billion", " trillion", " quadrillion", " quintillion"}
func say(n int64) string { var t string if n < 0 { t = "negative " // Note, for math.MinInt64 this leaves n negative. n = -n } switch { case n < 20: t += small[n] case n < 100: t += tens[n/10] s := n % 10 if s > 0 { t += "-" + small[s] } case n < 1000: t += small[n/100] + " hundred" s := n % 100 if s > 0 { t += " " + say(s) } default: // work right-to-left sx := "" for i := 0; n > 0; i++ { p := n % 1000 n /= 1000 if p > 0 { ix := say(p) + illions[i] if sx != "" { ix += " " + sx } sx = ix } } t += sx } return t }</lang>
- Output:
first second third fourth fifth eleventh sixty-fifth one hundredth one hundred first two hundred seventy-second twenty-three thousand four hundred fifty-sixth eight quadrillion seven trillion six billion five million four thousand third
Haskell
Uses solution of Number_names#Haskell
<lang haskell>spellOrdinal :: Integer -> String spellOrdinal n
| n <= 0 = "not ordinal"
| n < 20 = small n
| n < 100 = case divMod n 10 of
(k, 0) -> spellInteger (10*k) ++ "th"
(k, m) -> spellInteger (10*k) ++ "-" ++ spellOrdinal m
| n < 1000 = case divMod n 100 of
(k, 0) -> spellInteger (100*k) ++ "th"
(k, m) -> spellInteger (100*k) ++ " and " ++ spellOrdinal m
| otherwise = case divMod n 1000 of
(k, 0) -> spellInteger (1000*k) ++ "th"
(k, m) -> spellInteger (k*1000) ++ s ++ spellOrdinal m
where s = if m < 100 then " and " else ", "
where
small = ([ undefined, "first", "second", "third", "fourth", "fifth"
, "sixth", "seventh", "eighth", "nineth", "tenth", "eleventh"
, "twelveth", "thirteenth", "fourteenth", "fifteenth", "sixteenth"
, "seventeenth", "eighteenth", "nineteenth"] !!) . fromEnum</lang>
Testing
<lang haskell>main = mapM_ (\n -> putStrLn $ show n ++ "\t" ++ spellOrdinal n)
[1, 2, 3, 4, 5, 11, 65, 100, 101, 272, 23456, 8007006005004003]</lang>
λ> main 1 first 2 second 3 third 4 fourth 5 fifth 11 eleventh 65 sixty-fifth 100 one hundredth 101 one hundred and first 272 two hundred and seventy-second 23456 twenty-three thousand, four hundred and fifty-sixth 8007006005004003 eight quadrillion, seven trillion, six billion, five million, four thousand and third
Java
<lang java> import java.util.HashMap; import java.util.Map;
public class SpellingOfOrdinalNumbers {
public static void main(String[] args) {
for ( long test : new long[] {1, 2, 3, 4, 5, 11, 65, 100, 101, 272, 23456, 8007006005004003L} ) {
System.out.printf("%d = %s%n", test, toOrdinal(test));
}
}
private static Map<String,String> ordinalMap = new HashMap<>();
static {
ordinalMap.put("one", "first");
ordinalMap.put("two", "second");
ordinalMap.put("three", "third");
ordinalMap.put("five", "fifth");
ordinalMap.put("eight", "eighth");
ordinalMap.put("nine", "ninth");
ordinalMap.put("twelve", "twelfth");
}
private static String toOrdinal(long n) {
String spelling = numToString(n);
String[] split = spelling.split(" ");
String last = split[split.length - 1];
String replace = "";
if ( last.contains("-") ) {
String[] lastSplit = last.split("-");
String lastWithDash = lastSplit[1];
String lastReplace = "";
if ( ordinalMap.containsKey(lastWithDash) ) {
lastReplace = ordinalMap.get(lastWithDash);
}
else if ( lastWithDash.endsWith("y") ) {
lastReplace = lastWithDash.substring(0, lastWithDash.length() - 1) + "ieth";
}
else {
lastReplace = lastWithDash + "th";
}
replace = lastSplit[0] + "-" + lastReplace;
}
else {
if ( ordinalMap.containsKey(last) ) {
replace = ordinalMap.get(last);
}
else if ( last.endsWith("y") ) {
replace = last.substring(0, last.length() - 1) + "ieth";
}
else {
replace = last + "th";
}
}
split[split.length - 1] = replace;
return String.join(" ", split);
}
private static final String[] nums = new String[] {
"zero", "one", "two", "three", "four", "five", "six", "seven", "eight", "nine",
"ten", "eleven", "twelve", "thirteen", "fourteen", "fifteen", "sixteen", "seventeen", "eighteen", "nineteen"
};
private static final String[] tens = new String[] {"zero", "ten", "twenty", "thirty", "forty", "fifty", "sixty", "seventy", "eighty", "ninety"};
private static final String numToString(long n) {
return numToStringHelper(n);
}
private static final String numToStringHelper(long n) {
if ( n < 0 ) {
return "negative " + numToStringHelper(-n);
}
int index = (int) n;
if ( n <= 19 ) {
return nums[index];
}
if ( n <= 99 ) {
return tens[index/10] + (n % 10 > 0 ? "-" + numToStringHelper(n % 10) : "");
}
String label = null;
long factor = 0;
if ( n <= 999 ) {
label = "hundred";
factor = 100;
}
else if ( n <= 999999) {
label = "thousand";
factor = 1000;
}
else if ( n <= 999999999) {
label = "million";
factor = 1000000;
}
else if ( n <= 999999999999L) {
label = "billion";
factor = 1000000000;
}
else if ( n <= 999999999999999L) {
label = "trillion";
factor = 1000000000000L;
}
else if ( n <= 999999999999999999L) {
label = "quadrillion";
factor = 1000000000000000L;
}
else {
label = "quintillion";
factor = 1000000000000000000L;
}
return numToStringHelper(n / factor) + " " + label + (n % factor > 0 ? " " + numToStringHelper(n % factor ) : "");
}
} </lang>
- Output:
1 = first 2 = second 3 = third 4 = fourth 5 = fifth 11 = eleventh 65 = sixty-fifth 100 = one hundredth 101 = one hundred first 272 = two hundred seventy-second 23456 = twenty-three thousand four hundred fifty-sixth 8007006005004003 = eight quadrillion seven trillion six billion five million four thousand third
Julia
This makes use of code posted on this site by MichaeLeroy for a similar task at https://rosettacode.org/wiki/Number_names#Julia. The function num2text is used (but not included here) as posted from that location. <lang Julia> const irregular = Dict("one" => "first", "two" => "second", "three" => "third", "five" => "fifth",
"eight" => "eighth", "nine" => "ninth", "twelve" => "twelfth")
const suffix = "th" const ysuffix = "ieth"
function numtext2ordinal(s)
lastword = split(s)[end]
redolast = split(lastword, "-")[end]
if redolast != lastword
lastsplit = "-"
word = redolast
else
lastsplit = " "
word = lastword
end
firstpart = reverse(split(reverse(s), lastsplit, limit=2)[end])
firstpart = (firstpart == word) ? "": firstpart * lastsplit
if haskey(irregular, word)
word = irregular[word]
elseif word[end] == 'y'
word = word[1:end-1] * ysuffix
else
word = word * suffix
end
firstpart * word
end
const testcases = [1 2 3 4 5 11 65 100 101 272 23456 8007006005004003] for n in testcases
println("$n => $(numtext2ordinal(num2text(n)))")
end </lang>
- Output:
1 => first 2 => second 3 => third 4 => fourth 5 => fifth 11 => eleventh 65 => sixty-fifth 100 => one hundredth 101 => one hundred and first 272 => two hundred and seventy-second 23456 => twenty-three thousand four hundred and fifty-sixth 8007006005004003 => eight quadrillion seven trillion six billion five million four thousand and third
Kotlin
This makes use of the code at https://rosettacode.org/wiki/Number_names#Kotlin, which I also wrote, and adjusts it to output the corresponding ordinal. Although, for good measure, the program can deal with negative integers, zero and UK-style numbers (the insertion of 'and' at strategic places, no 'milliards' I promise!) none of these are actually tested in line with the task's requirements. <lang scala>// version 1.1.4-3
typealias IAE = IllegalArgumentException
val names = mapOf(
1 to "one", 2 to "two", 3 to "three", 4 to "four", 5 to "five", 6 to "six", 7 to "seven", 8 to "eight", 9 to "nine", 10 to "ten", 11 to "eleven", 12 to "twelve", 13 to "thirteen", 14 to "fourteen", 15 to "fifteen", 16 to "sixteen", 17 to "seventeen", 18 to "eighteen", 19 to "nineteen", 20 to "twenty", 30 to "thirty", 40 to "forty", 50 to "fifty", 60 to "sixty", 70 to "seventy", 80 to "eighty", 90 to "ninety"
) val bigNames = mapOf(
1_000L to "thousand", 1_000_000L to "million", 1_000_000_000L to "billion", 1_000_000_000_000L to "trillion", 1_000_000_000_000_000L to "quadrillion", 1_000_000_000_000_000_000L to "quintillion"
)
val irregOrdinals = mapOf(
"one" to "first", "two" to "second", "three" to "third", "five" to "fifth", "eight" to "eighth", "nine" to "ninth", "twelve" to "twelfth"
)
fun String.toOrdinal(): String {
val splits = this.split(' ', '-')
var last = splits[splits.lastIndex]
return if (irregOrdinals.containsKey(last)) this.dropLast(last.length) + irregOrdinals[last]!!
else if (last.endsWith("y")) this.dropLast(1) + "ieth"
else this + "th"
}
fun numToOrdinalText(n: Long, uk: Boolean = false): String {
if (n == 0L) return "zeroth" // or alternatively 'zeroeth'
val neg = n < 0L
val maxNeg = n == Long.MIN_VALUE
var nn = if (maxNeg) -(n + 1) else if (neg) -n else n
val digits3 = IntArray(7)
for (i in 0..6) { // split number into groups of 3 digits from the right
digits3[i] = (nn % 1000).toInt()
nn /= 1000
}
fun threeDigitsToText(number: Int) : String {
val sb = StringBuilder()
if (number == 0) return ""
val hundreds = number / 100
val remainder = number % 100
if (hundreds > 0) {
sb.append(names[hundreds], " hundred")
if (remainder > 0) sb.append(if (uk) " and " else " ")
}
if (remainder > 0) {
val tens = remainder / 10
val units = remainder % 10
if (tens > 1) {
sb.append(names[tens * 10])
if (units > 0) sb.append("-", names[units])
}
else sb.append(names[remainder])
}
return sb.toString()
}
val strings = Array<String>(7) { threeDigitsToText(digits3[it]) }
var text = strings[0]
var andNeeded = uk && digits3[0] in 1..99
var big = 1000L
for (i in 1..6) {
if (digits3[i] > 0) {
var text2 = strings[i] + " " + bigNames[big]
if (text.length > 0) {
text2 += if (andNeeded) " and " else ", "
andNeeded = false
}
else andNeeded = uk && digits3[i] in 1..99
text = text2 + text
}
big *= 1000
}
if (maxNeg) text = text.dropLast(5) + "eight"
if (neg) text = "minus " + text
return text.toOrdinal()
}
fun numToOrdinalText(s: String, uk: Boolean = false): String {
val d = s.toDoubleOrNull() ?: throw IAE("String is not numeric")
if (d !in Long.MIN_VALUE.toDouble() .. Long.MAX_VALUE.toDouble())
throw IAE("Double is outside the range of a Long Integer")
val n = d.toLong()
if (n.toDouble() != d) throw IAE("String does not represent a Long Integer")
return numToOrdinalText(n, uk)
}
fun main(args: Array<String>) {
val la = longArrayOf(1, 2, 3, 4, 5, 11, 65, 100, 101, 272, 23456, 8007006005004003)
println("Using US representation:")
for (i in la) println("${"%16d".format(i)} = ${numToOrdinalText(i)}")
val sa = arrayOf("123", "00123.0", "1.23e2")
for (s in sa) println("${"%16s".format(s)} = ${numToOrdinalText(s)}")
}</lang>
- Output:
Using US representation:
1 = first
2 = second
3 = third
4 = fourth
5 = fifth
11 = eleventh
65 = sixty-fifth
100 = one hundredth
101 = one hundred first
272 = two hundred seventy-second
23456 = twenty-three thousand, four hundred fifty-sixth
8007006005004003 = eight quadrillion, seven trillion, six billion, five million, four thousand, third
123 = one hundred twenty-third
00123.0 = one hundred twenty-third
1.23e2 = one hundred twenty-third
Nim
As in the Python solution, we reuse the output of spellInteger from the
Number_names task.
<lang Nim>import strutils, algorithm, tables
const irregularOrdinals = {"one": "first",
"two": "second",
"three": "third",
"five": "fifth",
"eight": "eighth",
"nine": "ninth",
"twelve": "twelfth"}.toTable
const
tens = ["", "", "twenty", "thirty", "forty", "fifty", "sixty", "seventy",
"eighty", "ninety"]
small = ["zero", "one", "two", "three", "four", "five", "six", "seven",
"eight", "nine", "ten", "eleven", "twelve", "thirteen", "fourteen",
"fifteen", "sixteen", "seventeen", "eighteen", "nineteen"]
huge = ["", "", "million", "billion", "trillion", "quadrillion",
"quintillion", "sextillion", "septillion", "octillion", "nonillion",
"decillion"]
- Forward reference.
proc spellInteger(n: int64): string
proc nonzero(c: string; n: int64; connect = ""): string =
if n == 0: "" else: connect & c & spellInteger(n)
proc lastAnd(num: string): string =
if ',' in num:
let pos = num.rfind(',')
var (pre, last) = if pos >= 0: (num[0 ..< pos], num[pos+1 .. num.high])
else: ("", num)
if " and " notin last: last = " and" & last
result = [pre, ",", last].join()
else:
result = num
proc big(e, n: int64): string =
if e == 0: spellInteger(n) elif e == 1: spellInteger(n) & " thousand" else: spellInteger(n) & " " & huge[e]
iterator base1000Rev(n: int64): int64 =
var n = n while n != 0: let r = n mod 1000 n = n div 1000 yield r
proc spellInteger(n: int64): string =
if n < 0:
"minus " & spellInteger(-n)
elif n < 20:
small[int(n)]
elif n < 100:
let a = n div 10
let b = n mod 10
tens[int(a)] & nonzero("-", b)
elif n < 1000:
let a = n div 100
let b = n mod 100
small[int(a)] & " hundred" & nonzero(" ", b, " and")
else:
var sq = newSeq[string]()
var e = 0
for x in base1000Rev(n):
if x > 0: sq.add big(e, x)
inc e
reverse sq
lastAnd(sq.join(", "))
proc num2ordinal(n: SomeInteger|SomeFloat): string =
let n = n.int64
var num = spellInteger(n)
let hyphen = num.rsplit('-', 1)
var number = num.rsplit(' ', 1)
var delim = ' '
if number[^1].len > hyphen[^1].len:
number = hyphen
delim = '-'
if number[^1] in irregularOrdinals:
number[^1] = delim & irregularOrdinals[number[^1]]
elif number[^1].endswith('y'):
number[^1] = delim & number[^1][0..^2] & "ieth"
else:
number[^1] = delim & number[^1] & "th"
result = number.join()
when isMainModule:
const tests1 = [int64 1, 2, 3, 4, 5, 11, 65, 100, 101, 272, 23456, 8007006005004003, 123] tests2 = [0123.0, 1.23e2]
for num in tests1: echo "$1 => $2".format(num, num2ordinal(num)) for num in tests2: echo "$1 => $2".format(num, num2ordinal(num))</lang>
- Output:
1 => first 2 => second 3 => third 4 => fourth 5 => fifth 11 => eleventh 65 => sixty-fifth 100 => one hundredth 101 => one hundred and first 272 => two hundred and seventy-second 23456 => twenty-three thousand, four hundred and fifty-sixth 8007006005004003 => eight quadrillion, seven trillion, six billion, five million, four thousand, and third 123 => one hundred and twenty-third 123.0 => one hundred and twenty-third 123.0 => one hundred and twenty-third
Perl
Adding zero to the input forces a numeric conversion (any identity operation would suffice). <lang perl>use Lingua::EN::Numbers 'num2en_ordinal';
printf "%16s : %s\n", $_, num2en_ordinal(0+$_) for
<1 2 3 4 5 11 65 100 101 272 23456 8007006005004003 123 00123.0 '00123.0' 1.23e2 '1.23e2'>;</lang>
- Output:
1 : first
2 : second
3 : third
4 : fourth
5 : fifth
11 : eleventh
65 : sixty-fifth
100 : one hundredth
101 : one hundred and first
272 : two hundred and seventy-second
23456 : twenty-three thousand four hundred and fifty-sixth
8007006005004003 : eight quadrillion, seven trillion, six billion, five million, four thousand and third
123 : one hundred and twenty-third
00123.0 : one hundred and twenty-third
00123.0 : one hundred and twenty-third
1.23e2 : one hundred and twenty-third
1.23e2 : one hundred and twenty-third
Phix
Standard builtin
constant tests = {1, 2, 3, 4, 5, 11, 65, 100, 101, 272, 23456, 8007006005004003, 123, 00123.0, 1.23e2, 0b1111011, 0o173, 0x7B, 861/7} for i=1 to length(tests) do puts(1,ordinal(tests[i])&'\n') end for
- Output:
first second third fourth fifth eleventh sixty-fifth one hundredth one hundred and first two hundred and seventy-second twenty-three thousand, four hundred and fifty-sixth eight quadrillion, seven trillion, six billion, five million, four thousand, and third one hundred and twenty-third one hundred and twenty-third one hundred and twenty-third one hundred and twenty-third one hundred and twenty-third one hundred and twenty-third one hundred and twenty-third
Prolog
<lang prolog>test_ordinal(Number):-
number_name(Number, ordinal, Name),
writef('%w: %w\n', [Number, Name]).
main:-
test_ordinal(1), test_ordinal(2), test_ordinal(3), test_ordinal(4), test_ordinal(5), test_ordinal(11), test_ordinal(15), test_ordinal(21), test_ordinal(42), test_ordinal(65), test_ordinal(98), test_ordinal(100), test_ordinal(101), test_ordinal(272), test_ordinal(300), test_ordinal(750), test_ordinal(23456), test_ordinal(7891233), test_ordinal(8007006005004003).</lang>
Module for spelling numbers in US English: <lang prolog>:- module(number_name, [number_name/3]).
small_name(0, zero, zeroth). small_name(1, one, first). small_name(2, two, second). small_name(3, three, third). small_name(4, four, fourth). small_name(5, five, fifth). small_name(6, six, sixth). small_name(7, seven, seventh). small_name(8, eight, eighth). small_name(9, nine, ninth). small_name(10, ten, tenth). small_name(11, eleven, eleventh). small_name(12, tewlve, twelfth). small_name(13, thirteen, thirteenth). small_name(14, fourteen, fourteenth). small_name(15, fifteen, fifteenth). small_name(16, sixteen, sixteenth). small_name(17, seventeen, seventeenth). small_name(18, eighteen, eighteenth). small_name(19, nineteen, nineteenth). small_name(20, twenty, twentieth). small_name(30, thirty, thirtieth). small_name(40, forty, fortieth). small_name(50, fifty, fiftieth). small_name(60, sixty, sixtieth). small_name(70, seventy, seventieth). small_name(80, eighty, eightieth). small_name(90, ninety, ninetieth).
big_names([big(100, hundred, hundredth),
big(1000, thousand, thousandth), big(1000000, million, millionth), big(1000000000, billion, billionth), big(1000000000000, trillion, trillionth), big(1000000000000000, quadrillion, quadrillionth), big(1000000000000000000, quintillion, quintillionth), big(1000000000000000000000, sextillion, sextillionth), big(1000000000000000000000000, septillion, septillionth)]).
big_name(Number, Big):-
big_names(Names), big_name(Names, Number, Big).
big_name([Big], _, Big):-
!.
big_name([Big1, Big2|_], Number, Big1):-
Big2 = big(N2, _, _), Number < N2, !.
big_name([_|Names], Number, Big):-
big_name(Names, Number, Big).
get_big_name(big(_, C, _), cardinal, C). get_big_name(big(_, _, O), ordinal, O).
get_small_name(Number, cardinal, Name):-
small_name(Number, Name, _), !.
get_small_name(Number, ordinal, Name):-
small_name(Number, _, Name).
number_name(Number, Type, Name):-
Number < 20, !, get_small_name(Number, Type, Name).
number_name(Number, Type, Name):-
Number < 100,
!,
N is Number mod 10,
(N = 0 ->
get_small_name(Number, Type, Name)
;
N1 is Number - N,
get_small_name(N1, cardinal, Name1),
get_small_name(N, Type, Name2),
atomic_list_concat([Name1, '-', Name2], Name)
).
number_name(Number, Type, Name):-
big_name(Number, big(P, C, O)),
N is Number // P,
number_name(N, cardinal, Name1),
M is Number mod P,
(M = 0 ->
get_big_name(big(P, C, O), Type, Name2)
;
number_name(M, Type, Name3),
atomic_list_concat([C, ' ', Name3], Name2)
),
atomic_list_concat([Name1, ' ', Name2], Name).</lang>
- Output:
1: first 2: second 3: third 4: fourth 5: fifth 11: eleventh 15: fifteenth 21: twenty-first 42: forty-second 65: sixty-fifth 98: ninety-eighth 100: one hundredth 101: one hundred first 272: two hundred seventy-second 300: three hundredth 750: seven hundred fiftieth 23456: twenty-three thousand four hundred fifty-sixth 7891233: seven million eight hundred ninety-one thousand two hundred thirty-third 8007006005004003: eight quadrillion seven trillion six billion five million four thousand third
Python
As with the Go solution, this uses the output of spell_integer from the
Number_names task.
<lang Python>irregularOrdinals = { "one": "first", "two": "second", "three": "third", "five": "fifth", "eight": "eighth", "nine": "ninth", "twelve": "twelfth", }
def num2ordinal(n):
conversion = int(float(n))
num = spell_integer(conversion)
hyphen = num.rsplit("-", 1)
num = num.rsplit(" ", 1)
delim = " "
if len(num[-1]) > len(hyphen[-1]):
num = hyphen
delim = "-"
if num[-1] in irregularOrdinals:
num[-1] = delim + irregularOrdinals[num[-1]]
elif num[-1].endswith("y"):
num[-1] = delim + num[-1][:-1] + "ieth"
else:
num[-1] = delim + num[-1] + "th"
return "".join(num)
if __name__ == "__main__":
tests = "1 2 3 4 5 11 65 100 101 272 23456 8007006005004003 123 00123.0 1.23e2".split()
for num in tests:
print("{} => {}".format(num, num2ordinal(num)))
- This is a copy of the code from https://rosettacode.org/wiki/Number_names#Python
TENS = [None, None, "twenty", "thirty", "forty",
"fifty", "sixty", "seventy", "eighty", "ninety"]
SMALL = ["zero", "one", "two", "three", "four", "five",
"six", "seven", "eight", "nine", "ten", "eleven",
"twelve", "thirteen", "fourteen", "fifteen",
"sixteen", "seventeen", "eighteen", "nineteen"]
HUGE = [None, None] + [h + "illion"
for h in ("m", "b", "tr", "quadr", "quint", "sext",
"sept", "oct", "non", "dec")]
def nonzero(c, n, connect=):
return "" if n == 0 else connect + c + spell_integer(n)
def last_and(num):
if ',' in num:
pre, last = num.rsplit(',', 1)
if ' and ' not in last:
last = ' and' + last
num = .join([pre, ',', last])
return num
def big(e, n):
if e == 0:
return spell_integer(n)
elif e == 1:
return spell_integer(n) + " thousand"
else:
return spell_integer(n) + " " + HUGE[e]
def base1000_rev(n):
# generates the value of the digits of n in base 1000
# (i.e. 3-digit chunks), in reverse.
while n != 0:
n, r = divmod(n, 1000)
yield r
def spell_integer(n):
if n < 0:
return "minus " + spell_integer(-n)
elif n < 20:
return SMALL[n]
elif n < 100:
a, b = divmod(n, 10)
return TENS[a] + nonzero("-", b)
elif n < 1000:
a, b = divmod(n, 100)
return SMALL[a] + " hundred" + nonzero(" ", b, ' and')
else:
num = ", ".join([big(e, x) for e, x in
enumerate(base1000_rev(n)) if x][::-1])
return last_and(num)</lang>
Output
1 => first 2 => second 3 => third 4 => fourth 5 => fifth 11 => eleventh 65 => sixty-fifth 100 => one hundredth 101 => one hundred and first 272 => two hundred and seventy-second 23456 => twenty-three thousand, four hundred and fifty-sixth 8007006005004003 => eight quadrillion, seven trillion, six billion, five million, four thousand, and third 123 => one hundred and twenty-third 00123.0 => one hundred and twenty-third 1.23e2 => one hundred and twenty-third
Raku
(formerly Perl 6)
Rakudo version 2019.07.1 is updated to Unicode version 12.1. Unicode version 12.0 introduced some new numeric digits, which changed the output here a bit. This will work with earlier versions of Rakudo, but will yield slightly different results.
This would be pretty simple to implement from scratch; it would be straightforward to do a minor modification of the Number names task code. Much simpler to just use the Lingua::EN::Numbers module from the Raku ecosystem though. It will easily handles ordinal number conversions.
We need to be slightly careful of terminology. In Raku, 123, 00123.0, & 1.23e2 are not all integers. They are respectively an Int (integer), a Rat (rational number) and a Num (floating point number). (The fourth numeric is a Complex) For this task it doesn't much matter as the ordinal routine coerces its argument to an Int, but to Raku they are different things. We can further abuse allomorphic and String types and role mixins for some somewhat non-intuitive results as well.
Note that the different allomorphic integer forms of 123 are evaluated on use, not on assignment. They can be passed around in parameters, but until they are used numerically, they retain their stringy characteristics and are distinctive, determinable through introspection. The numerics are evaluated on assignment, hence the stringified output not exactly matching the input format. The mixin role returns different things depending on what context you evaluate it under. When evaluated as a string it is 17, numerically, it is 123.
Raku uses Unicode natively. If a glyph has a Unicode 'Numeric Digit' (<:Nd>) property, it is treated as a numeric digit, and may be used as one.
It is not really clear what is meant by "Write a driver and a function...". Well, the function part is clear enough; driver not so much. Perhaps this will suffice.
<lang perl6>use Lingua::EN::Numbers;
- The task
+$_ ?? printf( "Type: \%-14s %16s : %s\n", .^name, $_, .&ordinal ) !! say "\n$_:" for
- Testing
'Required tests', 1, 2, 3, 4, 5, 11, 65, 100, 101, 272, 23456, 8007006005004003,
'Optional tests - different forms of 123', 'Numerics', 123, 00123.0, 1.23e2, 123+0i,
'Allomorphs', |<123 1_2_3 00123.0 1.23e2 123+0i 0b1111011 0o173 0x7B 861/7>,
'Numeric Strings', |'1_2_3 00123.0 1.23e2 123+0i 0b1111011 0o173 0x7B 861/7'.words,
'Unicode Numeric Strings',
- (Only using groups of digits from the same Unicode block. Technically,
- digits from any block could be combined with digits from any other block.)
|(^0x1FFFF).grep( { .chr ~~ /<:Nd>/ and .unival == 1|2|3 }).rotor(3)».chr».join,
'Role Mixin', '17' but 123;</lang>
- Output:
Required tests:
Type: Int 1 : first
Type: Int 2 : second
Type: Int 3 : third
Type: Int 4 : fourth
Type: Int 5 : fifth
Type: Int 11 : eleventh
Type: Int 65 : sixty-fifth
Type: Int 100 : one hundredth
Type: Int 101 : one hundred first
Type: Int 272 : two hundred seventy-second
Type: Int 23456 : twenty-three thousand, four hundred fifty-sixth
Type: Int 8007006005004003 : eight quadrillion, seven trillion, six billion, five million, four thousand third
Optional tests - different forms of 123:
Numerics:
Type: Int 123 : one hundred twenty-third
Type: Rat 123 : one hundred twenty-third
Type: Num 123 : one hundred twenty-third
Type: Complex 123+0i : one hundred twenty-third
Allomorphs:
Type: IntStr 123 : one hundred twenty-third
Type: IntStr 1_2_3 : one hundred twenty-third
Type: RatStr 00123.0 : one hundred twenty-third
Type: NumStr 1.23e2 : one hundred twenty-third
Type: ComplexStr 123+0i : one hundred twenty-third
Type: IntStr 0b1111011 : one hundred twenty-third
Type: IntStr 0o173 : one hundred twenty-third
Type: IntStr 0x7B : one hundred twenty-third
Type: RatStr 861/7 : one hundred twenty-third
Numeric Strings:
Type: Str 1_2_3 : one hundred twenty-third
Type: Str 00123.0 : one hundred twenty-third
Type: Str 1.23e2 : one hundred twenty-third
Type: Str 123+0i : one hundred twenty-third
Type: Str 0b1111011 : one hundred twenty-third
Type: Str 0o173 : one hundred twenty-third
Type: Str 0x7B : one hundred twenty-third
Type: Str 861/7 : one hundred twenty-third
Unicode Numeric Strings:
Type: Str 123 : one hundred twenty-third
Type: Str ١٢٣ : one hundred twenty-third
Type: Str ۱۲۳ : one hundred twenty-third
Type: Str ߁߂߃ : one hundred twenty-third
Type: Str १२३ : one hundred twenty-third
Type: Str ১২৩ : one hundred twenty-third
Type: Str ੧੨੩ : one hundred twenty-third
Type: Str ૧૨૩ : one hundred twenty-third
Type: Str ୧୨୩ : one hundred twenty-third
Type: Str ௧௨௩ : one hundred twenty-third
Type: Str ౧౨౩ : one hundred twenty-third
Type: Str ೧೨೩ : one hundred twenty-third
Type: Str ൧൨൩ : one hundred twenty-third
Type: Str ෧෨෩ : one hundred twenty-third
Type: Str ๑๒๓ : one hundred twenty-third
Type: Str ໑໒໓ : one hundred twenty-third
Type: Str ༡༢༣ : one hundred twenty-third
Type: Str ၁၂၃ : one hundred twenty-third
Type: Str ႑႒႓ : one hundred twenty-third
Type: Str ១២៣ : one hundred twenty-third
Type: Str ᠑᠒᠓ : one hundred twenty-third
Type: Str ᥇᥈᥉ : one hundred twenty-third
Type: Str ᧑᧒᧓ : one hundred twenty-third
Type: Str ᪁᪂᪃ : one hundred twenty-third
Type: Str ᪑᪒᪓ : one hundred twenty-third
Type: Str ᭑᭒᭓ : one hundred twenty-third
Type: Str ᮱᮲᮳ : one hundred twenty-third
Type: Str ᱁᱂᱃ : one hundred twenty-third
Type: Str ᱑᱒᱓ : one hundred twenty-third
Type: Str ꘡꘢꘣ : one hundred twenty-third
Type: Str ꣑꣒꣓ : one hundred twenty-third
Type: Str ꤁꤂꤃ : one hundred twenty-third
Type: Str ꧑꧒꧓ : one hundred twenty-third
Type: Str ꧱꧲꧳ : one hundred twenty-third
Type: Str ꩑꩒꩓ : one hundred twenty-third
Type: Str ꯱꯲꯳ : one hundred twenty-third
Type: Str １２３ : one hundred twenty-third
Type: Str 𐒡𐒢𐒣 : one hundred twenty-third
Type: Str 𐴱𐴲𐴳 : one hundred twenty-third
Type: Str 𑁧𑁨𑁩 : one hundred twenty-third
Type: Str 𑃱𑃲𑃳 : one hundred twenty-third
Type: Str 𑄷𑄸𑄹 : one hundred twenty-third
Type: Str 𑇑𑇒𑇓 : one hundred twenty-third
Type: Str 𑋱𑋲𑋳 : one hundred twenty-third
Type: Str 𑑑𑑒𑑓 : one hundred twenty-third
Type: Str 𑓑𑓒𑓓 : one hundred twenty-third
Type: Str 𑙑𑙒𑙓 : one hundred twenty-third
Type: Str 𑛁𑛂𑛃 : one hundred twenty-third
Type: Str 𑜱𑜲𑜳 : one hundred twenty-third
Type: Str 𑣡𑣢𑣣 : one hundred twenty-third
Type: Str 𑱑𑱒𑱓 : one hundred twenty-third
Type: Str 𑵑𑵒𑵓 : one hundred twenty-third
Type: Str 𑶡𑶢𑶣 : one hundred twenty-third
Type: Str 𖩡𖩢𖩣 : one hundred twenty-third
Type: Str 𖭑𖭒𖭓 : one hundred twenty-third
Type: Str 𝟏𝟐𝟑 : one hundred twenty-third
Type: Str 𝟙𝟚𝟛 : one hundred twenty-third
Type: Str 𝟣𝟤𝟥 : one hundred twenty-third
Type: Str 𝟭𝟮𝟯 : one hundred twenty-third
Type: Str 𝟷𝟸𝟹 : one hundred twenty-third
Type: Str 𞥑𞥒𞥓 : one hundred twenty-third
Role Mixin:
Type: Str+{<anon|1>} 17 : one hundred twenty-third
REXX
<lang REXX>/*REXX programs spells out ordinal numbers (in English, using the American system). */ numeric digits 3000 /*just in case the user uses gihugic #s*/ parse arg n /*obtain optional arguments from the CL*/
if n= | n="," then n= 1 2 3 4 5 11 65 100 101 272 23456 8007006005004003
pgmOpts= 'ordinal quiet' /*define options needed for $SPELL#.REX*/
do j=1 for words(n) /*process each of the specified numbers*/
x=word(n, j) /*obtain a number from the input list. */
os=$spell#(x pgmOpts) /*invoke REXX routine to spell ordinal#*/
say right(x, max(20, length(x) ) ) ' spelled ordinal number ───► ' os
end /*j*/</lang>
- output when using the default inputs:
1 spelled ordinal number ───► first
2 spelled ordinal number ───► second
3 spelled ordinal number ───► third
4 spelled ordinal number ───► fourth
5 spelled ordinal number ───► fifth
11 spelled ordinal number ───► eleventh
65 spelled ordinal number ───► sixty-fifth
100 spelled ordinal number ───► one hundredth
101 spelled ordinal number ───► one hundred first
272 spelled ordinal number ───► two hundred seventy-second
23456 spelled ordinal number ───► twenty-three thousand four hundred fifty-sixth
8007006005004003 spelled ordinal number ───► eight quadrillion seven trillion six billion five million four thousand third
The $SPELL#.REX routine can be found here ───► $SPELL#.REX.
Rust
<lang rust>struct NumberNames {
cardinal: &'static str, ordinal: &'static str,
}
impl NumberNames {
fn get_name(&self, ordinal: bool) -> &'static str {
if ordinal {
return self.ordinal;
}
self.cardinal
}
}
const SMALL_NAMES: [NumberNames; 20] = [
NumberNames {
cardinal: "zero",
ordinal: "zeroth",
},
NumberNames {
cardinal: "one",
ordinal: "first",
},
NumberNames {
cardinal: "two",
ordinal: "second",
},
NumberNames {
cardinal: "three",
ordinal: "third",
},
NumberNames {
cardinal: "four",
ordinal: "fourth",
},
NumberNames {
cardinal: "five",
ordinal: "fifth",
},
NumberNames {
cardinal: "six",
ordinal: "sixth",
},
NumberNames {
cardinal: "seven",
ordinal: "seventh",
},
NumberNames {
cardinal: "eight",
ordinal: "eighth",
},
NumberNames {
cardinal: "nine",
ordinal: "ninth",
},
NumberNames {
cardinal: "ten",
ordinal: "tenth",
},
NumberNames {
cardinal: "eleven",
ordinal: "eleventh",
},
NumberNames {
cardinal: "twelve",
ordinal: "twelfth",
},
NumberNames {
cardinal: "thirteen",
ordinal: "thirteenth",
},
NumberNames {
cardinal: "fourteen",
ordinal: "fourteenth",
},
NumberNames {
cardinal: "fifteen",
ordinal: "fifteenth",
},
NumberNames {
cardinal: "sixteen",
ordinal: "sixteenth",
},
NumberNames {
cardinal: "seventeen",
ordinal: "seventeenth",
},
NumberNames {
cardinal: "eighteen",
ordinal: "eighteenth",
},
NumberNames {
cardinal: "nineteen",
ordinal: "nineteenth",
},
];
const TENS: [NumberNames; 8] = [
NumberNames {
cardinal: "twenty",
ordinal: "twentieth",
},
NumberNames {
cardinal: "thirty",
ordinal: "thirtieth",
},
NumberNames {
cardinal: "forty",
ordinal: "fortieth",
},
NumberNames {
cardinal: "fifty",
ordinal: "fiftieth",
},
NumberNames {
cardinal: "sixty",
ordinal: "sixtieth",
},
NumberNames {
cardinal: "seventy",
ordinal: "seventieth",
},
NumberNames {
cardinal: "eighty",
ordinal: "eightieth",
},
NumberNames {
cardinal: "ninety",
ordinal: "ninetieth",
},
];
struct NamedNumber {
cardinal: &'static str, ordinal: &'static str, number: usize,
}
impl NamedNumber {
fn get_name(&self, ordinal: bool) -> &'static str {
if ordinal {
return self.ordinal;
}
self.cardinal
}
}
const N: usize = 7; const NAMED_NUMBERS: [NamedNumber; N] = [
NamedNumber {
cardinal: "hundred",
ordinal: "hundredth",
number: 100,
},
NamedNumber {
cardinal: "thousand",
ordinal: "thousandth",
number: 1000,
},
NamedNumber {
cardinal: "million",
ordinal: "millionth",
number: 1000000,
},
NamedNumber {
cardinal: "billion",
ordinal: "billionth",
number: 1000000000,
},
NamedNumber {
cardinal: "trillion",
ordinal: "trillionth",
number: 1000000000000,
},
NamedNumber {
cardinal: "quadrillion",
ordinal: "quadrillionth",
number: 1000000000000000,
},
NamedNumber {
cardinal: "quintillion",
ordinal: "quintillionth",
number: 1000000000000000000,
},
];
fn big_name(n: usize) -> &'static NamedNumber {
for i in 1..N {
if n < NAMED_NUMBERS[i].number {
return &NAMED_NUMBERS[i - 1];
}
}
&NAMED_NUMBERS[N - 1]
}
fn number_name(n: usize, ordinal: bool) -> String {
if n < 20 {
return String::from(SMALL_NAMES[n].get_name(ordinal));
} else if n < 100 {
if n % 10 == 0 {
return String::from(TENS[n / 10 - 2].get_name(ordinal));
}
let s1 = TENS[n / 10 - 2].get_name(false);
let s2 = SMALL_NAMES[n % 10].get_name(ordinal);
return format!("{}-{}", s1, s2);
}
let big = big_name(n);
let mut result = number_name(n / big.number, false);
result.push(' ');
if n % big.number == 0 {
result.push_str(big.get_name(ordinal));
} else {
result.push_str(big.get_name(false));
result.push(' ');
result.push_str(&number_name(n % big.number, ordinal));
}
result
}
fn test_ordinal(n: usize) {
println!("{}: {}", n, number_name(n, true));
}
fn main() {
test_ordinal(1); test_ordinal(2); test_ordinal(3); test_ordinal(4); test_ordinal(5); test_ordinal(11); test_ordinal(15); test_ordinal(21); test_ordinal(42); test_ordinal(65); test_ordinal(98); test_ordinal(100); test_ordinal(101); test_ordinal(272); test_ordinal(300); test_ordinal(750); test_ordinal(23456); test_ordinal(7891233); test_ordinal(8007006005004003);
}</lang>
- Output:
1: first 2: second 3: third 4: fourth 5: fifth 11: eleventh 15: fifteenth 21: twenty-first 42: forty-second 65: sixty-fifth 98: ninety-eighth 100: one hundredth 101: one hundred first 272: two hundred seventy-second 300: three hundredth 750: seven hundred fiftieth 23456: twenty-three thousand four hundred fifty-sixth 7891233: seven million eight hundred ninety-one thousand two hundred thirty-third 8007006005004003: eight quadrillion seven trillion six billion five million four thousand third
Sidef
<lang ruby>var lingua_en = frequire('Lingua::EN::Numbers') var tests = [1,2,3,4,5,11,65,100,101,272,23456,8007006005004003]
tests.each {|n|
printf("%16s : %s\n", n, lingua_en.num2en_ordinal(n))
}</lang>
- Output:
1 : first
2 : second
3 : third
4 : fourth
5 : fifth
11 : eleventh
65 : sixty-fifth
100 : one hundredth
101 : one hundred and first
272 : two hundred and seventy-second
23456 : twenty-three thousand four hundred and fifty-sixth
8007006005004003 : eight quadrillion, seven trillion, six billion, five million, four thousand and third
Swift
<lang swift>fileprivate class NumberNames {
let cardinal: String let ordinal: String
init(cardinal: String, ordinal: String) {
self.cardinal = cardinal
self.ordinal = ordinal
}
func getName(_ ordinal: Bool) -> String {
return ordinal ? self.ordinal : self.cardinal
}
class func numberName(number: Int, ordinal: Bool) -> String {
guard number < 100 else {
return ""
}
if number < 20 {
return smallNames[number].getName(ordinal)
}
if number % 10 == 0 {
return tens[number/10 - 2].getName(ordinal)
}
var result = tens[number/10 - 2].getName(false)
result += "-"
result += smallNames[number % 10].getName(ordinal)
return result
}
static let smallNames = [
NumberNames(cardinal: "zero", ordinal: "zeroth"),
NumberNames(cardinal: "one", ordinal: "first"),
NumberNames(cardinal: "two", ordinal: "second"),
NumberNames(cardinal: "three", ordinal: "third"),
NumberNames(cardinal: "four", ordinal: "fourth"),
NumberNames(cardinal: "five", ordinal: "fifth"),
NumberNames(cardinal: "six", ordinal: "sixth"),
NumberNames(cardinal: "seven", ordinal: "seventh"),
NumberNames(cardinal: "eight", ordinal: "eighth"),
NumberNames(cardinal: "nine", ordinal: "ninth"),
NumberNames(cardinal: "ten", ordinal: "tenth"),
NumberNames(cardinal: "eleven", ordinal: "eleventh"),
NumberNames(cardinal: "twelve", ordinal: "twelfth"),
NumberNames(cardinal: "thirteen", ordinal: "thirteenth"),
NumberNames(cardinal: "fourteen", ordinal: "fourteenth"),
NumberNames(cardinal: "fifteen", ordinal: "fifteenth"),
NumberNames(cardinal: "sixteen", ordinal: "sixteenth"),
NumberNames(cardinal: "seventeen", ordinal: "seventeenth"),
NumberNames(cardinal: "eighteen", ordinal: "eighteenth"),
NumberNames(cardinal: "nineteen", ordinal: "nineteenth")
]
static let tens = [
NumberNames(cardinal: "twenty", ordinal: "twentieth"),
NumberNames(cardinal: "thirty", ordinal: "thirtieth"),
NumberNames(cardinal: "forty", ordinal: "fortieth"),
NumberNames(cardinal: "fifty", ordinal: "fiftieth"),
NumberNames(cardinal: "sixty", ordinal: "sixtieth"),
NumberNames(cardinal: "seventy", ordinal: "seventieth"),
NumberNames(cardinal: "eighty", ordinal: "eightieth"),
NumberNames(cardinal: "ninety", ordinal: "ninetieth")
]
}
fileprivate class NamedPower {
let cardinal: String
let ordinal: String
let number: UInt64
init(cardinal: String, ordinal: String, number: UInt64) {
self.cardinal = cardinal
self.ordinal = ordinal
self.number = number
}
func getName(_ ordinal: Bool) -> String {
return ordinal ? self.ordinal : self.cardinal
}
class func getNamedPower(_ number: UInt64) -> NamedPower {
for i in 1..<namedPowers.count {
if number < namedPowers[i].number {
return namedPowers[i - 1]
}
}
return namedPowers[namedPowers.count - 1]
}
static let namedPowers = [
NamedPower(cardinal: "hundred", ordinal: "hundredth",
number: 100),
NamedPower(cardinal: "thousand", ordinal: "thousandth",
number: 1000),
NamedPower(cardinal: "million", ordinal: "millionth",
number: 1000000),
NamedPower(cardinal: "billion", ordinal: "billionth",
number: 1000000000),
NamedPower(cardinal: "trillion", ordinal: "trillionth",
number: 1000000000000),
NamedPower(cardinal: "quadrillion", ordinal: "quadrillionth",
number: 1000000000000000),
NamedPower(cardinal: "quintillion", ordinal: "quintillionth",
number: 1000000000000000000)
]
}
public func numberName(number: UInt64, ordinal: Bool) -> String {
if number < 100 {
return NumberNames.numberName(number: Int(truncatingIfNeeded: number),
ordinal: ordinal)
}
let p = NamedPower.getNamedPower(number)
var result = numberName(number: number/p.number, ordinal: false)
result += " "
if number % p.number == 0 {
result += p.getName(ordinal)
} else {
result += p.getName(false)
result += " "
result += numberName(number: number % p.number, ordinal: ordinal)
}
return result
}
func printOrdinal(_ number: UInt64) {
print("\(number): \(numberName(number: number, ordinal: true))")
}
printOrdinal(1) printOrdinal(2) printOrdinal(3) printOrdinal(4) printOrdinal(5) printOrdinal(11) printOrdinal(15) printOrdinal(21) printOrdinal(42) printOrdinal(65) printOrdinal(98) printOrdinal(100) printOrdinal(101) printOrdinal(272) printOrdinal(300) printOrdinal(750) printOrdinal(23456) printOrdinal(7891233) printOrdinal(8007006005004003)</lang>
- Output:
1: first 2: second 3: third 4: fourth 5: fifth 11: eleventh 15: fifteenth 21: twenty-first 42: forty-second 65: sixty-fifth 98: ninety-eighth 100: one hundredth 101: one hundred first 272: two hundred seventy-second 300: three hundredth 750: seven hundred fiftieth 23456: twenty-three thousand four hundred fifty-sixth 7891233: seven million eight hundred ninety-one thousand two hundred thirty-third 8007006005004003: eight quadrillion seven trillion six billion five million four thousand third
VBA
Inspired by the Phix solution. Uses Number names <lang vb>Private Function ordinal(s As String) As String
Dim irregs As New Collection
irregs.Add "first", "one"
irregs.Add "second", "two"
irregs.Add "third", "three"
irregs.Add "fifth", "five"
irregs.Add "eighth", "eight"
irregs.Add "ninth", "nine"
irregs.Add "twelfth", "twelve"
Dim i As Integer
For i = Len(s) To 1 Step -1
ch = Mid(s, i, 1)
If ch = " " Or ch = "-" Then Exit For
Next i
On Error GoTo 1
ord = irregs(Right(s, Len(s) - i))
ordinal = Left(s, i) & ord
Exit Function
1:
If Right(s, 1) = "y" Then
s = Left(s, Len(s) - 1) & "ieth"
Else
s = s & "th"
End If
ordinal = s
End Function Public Sub ordinals()
tests = [{1, 2, 3, 4, 5, 11, 65, 100, 101, 272, 23456, 8007006005004003, 123, 00123.0, 1.23E2}]
init
For i = 1 To UBound(tests)
Debug.Print ordinal(spell(tests(i)))
Next i
End Sub</lang>
- Output:
first second third fourth fifth eleventh sixty-fifth one hundredth one hundred and first two hundred and seventy-second twenty-three thousand, four hundred and fifty-sixth eight quadrillion, seven trillion, six billion, five million, four thousandth one hundred and twenty-third one hundred and twenty-third
Wren
This reuses the say function from the Number names task.
Note that it is not safe to use this script for numbers with an absolute magnitude >= 2^53 as integers cannot be expressed exactly by Wren's Num type beyond that limit. <lang ecmascript>var small = ["zero", "one", "two", "three", "four", "five", "six", "seven", "eight", "nine", "ten", "eleven",
"twelve", "thirteen", "fourteen", "fifteen", "sixteen", "seventeen", "eighteen", "nineteen"]
var tens = ["", "", "twenty", "thirty", "forty", "fifty", "sixty", "seventy", "eighty", "ninety"]
var illions = ["", " thousand", " million", " billion"," trillion", " quadrillion", " quintillion"]
var irregularOrdinals = {
"one": "first", "two": "second", "three": "third", "five": "fifth", "eight": "eighth", "nine": "ninth", "twelve": "twelfth"
}
var say say = Fn.new { |n|
var t = ""
if (n < 0) {
t = "negative "
n = -n
}
if (n < 20) {
t = t + small[n]
} else if (n < 100) {
t = t + tens[(n/10).floor]
var s = n % 10
if (s > 0) t = t + "-" + small[s]
} else if (n < 1000) {
t = t + small[(n/100).floor] + " hundred"
var s = n % 100
System.write("") // guards against VM recursion bug
if (s > 0) t = t + " " + say.call(s)
} else {
var sx = ""
var i = 0
while (n > 0) {
var p = n % 1000
n = (n/1000).floor
if (p > 0) {
System.write("") // guards against VM recursion bug
var ix = say.call(p) + illions[i]
if (sx != "") ix = ix + " " + sx
sx = ix
}
i = i + 1
}
t = t + sx
}
return t
}
var sayOrdinal = Fn.new { |n|
var s = say.call(n)
var r = s[-1..0]
var i1 = r.indexOf(" ")
if (i1 != -1) i1 = s.count - 1 - i1
var i2 = r.indexOf("-")
if (i2 != -1) i2 = s.count - 1 - i2
var i = (i1 > i2) ? i1 : i2
i = i + 1
// Now s[0...i] is everything up to and including the space or hyphen
// and s[i..-1] is the last word; we modify s[i..-1] as required. // Since indexOf returns -1 if there was no space/hyphen, // `i` will be zero and this will still be fine.
var x = irregularOrdinals[s[i..-1]]
if (x) {
return s[0...i] + x
} else if (s[-1] == "y") {
return s[0...i] + s[i..-2] + "ieth"
} else {
return s[0...i] + s[i..-1] + "th"
}
}
for (n in [1, 2, 3, 4, 5, 11, 65, 100, 101, 272, 23456, 9007199254740991]) {
System.print(sayOrdinal.call(n))
}</lang>
- Output:
first second third fourth fifth eleventh sixty-fifth one hundredth one hundred first two hundred seventy-second twenty-three thousand four hundred fifty-sixth nine quadrillion seven trillion one hundred ninety-nine billion two hundred fifty-four million seven hundred forty thousand nine hundred ninety-first
zkl
<lang zkl>fcn nth(n,th=True){
var [const]
nmsth=T("","first","second","third","fourth","fifth","sixth","seventh","eighth","ninth"),
nms1=T("","one","two","three","four","five","six","seven","eight","nine"),
nms10=T("ten","eleven","twelve","thirteen","fourteen","fifteen","sixteen","seventeen","eighteen","nineteen"),
nms10th=T("tenth","eleventh","twelfth","thirteenth","fourteenth","fifteenth","sixteenth","seventeenth","eighteenth","nineteenth"),
nms20=T("twenty","thirty","forty","fifty","sixty","seventy","eighty","ninety"),
nms1000=T("thousand","million","billion","trillion","quadrillion"); // 3,6,9,12,15
if (n<0) String("negative ",nth(-n,th));
else if(n<10) th and nmsth[n] or nms1[n];
else if(n<20) th and nms10th[n-10] or nms10[n-10];
else if(n<10) th and nmsth[n] or nms1[n];
else if(n<100){
m,txt := n%10,nms20[n/10-2];
if(m) String(txt,dash(n%10,"-",th));
else String(txt[0,-1],"ieth");
}
else if(n<1000) String(nms1[n/100]," hundred",dash(n%100," ",th));
else{
n=n.toInt(); // yuck, only here to handle floats, 1.23-->"first"
ds:=(n.numDigits()-1)/3*3; // 1e3->3, 1e4-->3, 1e5-->3, 1e6-->6, 1e7-->6
z:=(10).pow(ds); // 1234-->1000, 12345-->10000
thou:=ds/3 - 1; // 1000-->0, 10000-->0, 2,000,000-->1
nnn,ys := n/z, n%z;
String((if(nnn<10) nms1[nnn] else nth(nnn,False)),
" ",nms1000[thou], if(ys==0) "th" else String(" ",nth(ys,th)));
}
} fcn dash(n,d,th){ if(n) String(d,nth(n,th)) else (th and "th" or "") }</lang> <lang zkl>testNs:=L(1,2,3,4,5,11,65,100,101,272,23456,8007006005004003,
123,00123.0,1.23e2,);
foreach n in (testNs){
if(n.isType(Float)) println("%16.2f --> %s".fmt(n,nth(n)));
else println("%16d --> %s".fmt(n,nth(n)));
}</lang>
- Output:
1 --> first
2 --> second
3 --> third
4 --> fourth
5 --> fifth
11 --> eleventh
65 --> sixty-fifth
100 --> one hundredth
101 --> one hundred first
272 --> two hundred seventy-second
23456 --> twenty-three thousand four hundred fifty-sixth
8007006005004003 --> eight quadrillion seven trillion six billion five million four thousand third
123 --> one hundred twenty-third
123.00 --> one hundred twenty-third
123.00 --> one hundred twenty-third