Sorting Algorithms/Circle Sort
Sorting Algorithm
This is a sorting algorithm. It may be applied to a set of data in order to sort it.
For comparing various sorts, see compare sorts.
For other sorting algorithms, see sorting algorithms, or:
Heap sort | Merge sort | Patience sort | Quick sort
O(n log2n) sorts
Shell Sort
O(n2) sorts
Bubble sort |
Cocktail sort |
Cocktail sort with shifting bounds |
Comb sort |
Cycle sort |
Gnome sort |
Insertion sort |
Selection sort |
Strand sort
other sorts
Bead sort |
Bogo sort |
Common sorted list |
Composite structures sort |
Custom comparator sort |
Counting sort |
Disjoint sublist sort |
External sort |
Jort sort |
Lexicographical sort |
Natural sorting |
Order by pair comparisons |
Order disjoint list items |
Order two numerical lists |
Object identifier (OID) sort |
Pancake sort |
Quickselect |
Permutation sort |
Radix sort |
Ranking methods |
Remove duplicate elements |
Sleep sort |
Stooge sort |
[Sort letters of a string] |
Three variable sort |
Topological sort |
Tree sort
Sort an array of integers (of any convenient size) into ascending order using Circlesort. In short, compare the first element to the last element, then the second element to the second last element, etc. Then split the array in two and recurse until there is only one single element in the array, like this:
Before: 6 7 8 9 2 5 3 4 1 After: 1 4 3 5 2 9 8 7 6
Show both the initial, unsorted list and the final sorted list. (Intermediate steps during sorting are optional.) Optimizations (like doing 0.5 log2(n) iterations and then continue with an Insertion sort) are optional.
Pseudo code:
function circlesort (index lo, index hi, swaps) { if lo == hi return (swaps) high := hi low := lo mid := int((hi-lo)/2) while lo < hi { if (value at lo) > (value at hi) { swap.values (lo,hi) swaps++ } lo++ hi-- } if lo == hi if (value at lo) > (value at hi+1) { swap.values (lo,hi+1) swaps++ } swaps := circlesort(low,low+mid,swaps) swaps := circlesort(low+mid+1,high,swaps) return(swaps) } while circlesort (0, sizeof(array)-1, 0)
For more information on Circle sorting, see Sourceforge.
C
<lang c>#include <stdio.h>
int circle_sort_inner(int *start, int *end) { int *p, *q, t, swapped;
if (start == end) return 0;
// funny "||" on next line is for the center element of odd-lengthed array
for (swapped = 0, p = start, q = end; p *q)
t = *p, *p = *q, *q = t, swapped = 1;
// q == p-1 at this point return swapped | circle_sort_inner(start, q) | circle_sort_inner(p, end); }
//helper function to show arrays before each call void circle_sort(int *x, int n) { do { int i; for (i = 0; i < n; i++) printf("%d ", x[i]); putchar('\n'); } while (circle_sort_inner(x, x + (n - 1))); }
int main(void) { int x[] = {5, -1, 101, -4, 0, 1, 8, 6, 2, 3}; circle_sort(x, sizeof(x) / sizeof(*x));
return 0; }</lang>
- Output:
5 -1 101 -4 0 1 8 6 2 3 -4 -1 0 3 6 1 2 8 5 101 -4 -1 0 1 2 3 5 6 8 101
D
<lang d>import std.stdio, std.algorithm, std.array, std.traits;
void circlesort(T)(T[] items) if (isMutable!T) {
uint inner(size_t lo, size_t hi, uint swaps) { if (lo == hi) return swaps; auto high = hi; auto low = lo; immutable mid = (hi - lo) / 2;
while (lo < hi) { if (items[lo] > items[hi]) { swap(items[lo], items[hi]); swaps++; } lo++; hi--; }
if (lo == hi && items[lo] > items[hi + 1]) { swap(items[lo], items[hi + 1]); swaps++; } swaps = inner(low, low + mid, swaps); swaps = inner(low + mid + 1, high, swaps); return swaps; }
if (!items.empty) while (inner(0, items.length - 1, 0)) {}
}
void main() {
import std.random, std.conv;
auto a = [5, -1, 101, -4, 0, 1, 8, 6, 2, 3]; a.circlesort; a.writeln; assert(a.isSorted);
// Fuzzy test. int[30] items; foreach (immutable _; 0 .. 100_000) { auto data = items[0 .. uniform(0, items.length)]; foreach (ref x; data) x = uniform(-items.length.signed * 3, items.length.signed * 3); data.circlesort; assert(data.isSorted); }
}</lang>
- Output:
[-4, -1, 0, 1, 2, 3, 5, 6, 8, 101]
CoffeeScript
<lang>circlesort = (arr, lo, hi, swaps) ->
if lo == hi return (swaps)
high = hi low = lo mid = Math.floor((hi-lo)/2)
while lo < hi if arr[lo] > arr[hi] t = arr[lo] arr[lo] = arr[hi] arr[hi] = t swaps++ lo++ hi--
if lo == hi if arr[lo] > arr[hi+1] t = arr[lo] arr[lo] = arr[hi+1] arr[hi+1] = t swaps++
swaps = circlesort(arr,low,low+mid,swaps) swaps = circlesort(arr,low+mid+1,high,swaps)
return(swaps)
VA = [2,14,4,6,8,1,3,5,7,9,10,11,0,13,12,-1]
while circlesort(VA,0,VA.length-1,0)
console.log VA</lang>
Output:
console: -1,1,0,3,4,5,8,12,2,9,6,10,7,13,11,14 console: -1,0,1,3,2,5,4,8,6,7,9,12,10,11,13,14 console: -1,0,1,2,3,4,5,6,7,8,9,10,11,12,13,14
Forth
<lang>defer precedes ( addr addr -- flag ) variable (swaps) \ keeps track of swaps
[UNDEFINED] cell- [IF] : cell- 1 cells - ; [THEN]
- (compare) ( a1 a2 -- a1 a2)
over @ over @ precedes \ if swapped, increment (swaps) if over over over @ over @ swap rot ! swap ! 1 (swaps) +! then
- (circlesort) ( a n --)
dup 1 > if over over ( array len) 1- cells over + swap ( 'end 'begin) begin over over > \ if we didn't pass the middle while \ check and swap opposite elements (compare) swap cell- swap cell+ repeat \ check if there's a middle element over over = if cell- (compare) then drop drop over over 2/ recurse \ sort first partition dup 2/ cells rot + swap dup 2/ - recurse exit then \ sort second partition drop drop \ nothing to sort
- sort begin 0 (swaps) ! over over (circlesort) (swaps) @ 0= until drop drop ;
- noname < ; is precedes
10 constant /sample create sample 5 , -1 , 101 , -4 , 0 , 1 , 8 , 6 , 2 , 3 ,
- .sample sample /sample cells bounds do i ? 1 cells +loop ;
sample /sample sort .sample</lang>
J
Of more parsing and atomic data, or less parsing with large data groups the latter produces faster J programs. Consequently each iteration laminates the original with its reverse. It joins the recursive call to the pairwise minima of the left block to the recursive call of the pairwise maxima of the right block, repeating the operations while the output changes. This is sufficient for power of 2 length data. The pre verb adjusts the data length. And post recovers the original data. This implementation discards the "in place" property described at the sourceforge link.
<lang J> circle_sort =: post ([: power_of_2_length pre) NB. the main sorting verb power_of_2_length =: even_length_iteration^:_ NB. repeat while the answer changes even_length_iteration =: ((,: |.) (([: <./ ({.~ _&,)) ,&$: ([: >./ (}.~ 0&,))) (1r2 * #))^:(1 < #) pre =: , (([: (-~ >.&.(2&^.)) #) # >./) NB. extend data to next power of 2 length post =: ({.~ #)~ NB. remove the extra data </lang> Examples: <lang J>
show =: [ smoutput
8 ([: circle_sort&.>@show ;&(?~)) 13 NB. sort lists length 8 and 13
┌───────────────┬────────────────────────────┐ │0 6 7 3 4 5 2 1│3 10 1 4 7 8 5 6 2 0 9 11 12│ └───────────────┴────────────────────────────┘ ┌───────────────┬────────────────────────────┐ │0 1 2 3 4 5 6 7│0 1 2 3 4 5 6 7 8 9 10 11 12│ └───────────────┴────────────────────────────┘
8 ([: circle_sort&.>@show ;&(1 }. 2 # ?~)) 13 NB. data has repetition
┌─────────────────────────────┬──────────────────────────────────────────────────────┐ │2 3 3 5 5 1 1 7 7 6 6 4 4 0 0│12 11 11 4 4 3 3 9 9 7 7 10 10 6 6 2 2 1 1 5 5 8 8 0 0│ └─────────────────────────────┴──────────────────────────────────────────────────────┘ ┌─────────────────────────────┬──────────────────────────────────────────────────────┐ │0 0 1 1 2 3 3 4 4 5 5 6 6 7 7│0 0 1 1 2 2 3 3 4 4 5 5 6 6 7 7 8 8 9 9 10 10 11 11 12│ └─────────────────────────────┴──────────────────────────────────────────────────────┘ </lang>
Python
The doctest passes with odd and even length lists. As do the random tests. Please see circle_sort.__doc__ for example use and output. <lang python>
- python3
- tests: expect no output.
- doctest with python3 -m doctest thisfile.py
- additional tests: python3 thisfile.py
def circle_sort_backend(A:list, L:int, R:int)->'sort A in place, returning the number of swaps':
>>> L = [3, 2, 8, 28, 2,] >>> circle_sort(L) 3 >>> print(L) [2, 2, 3, 8, 28] >>> L = [3, 2, 8, 28,] >>> circle_sort(L) 1 >>> print(L) [2, 3, 8, 28] n = R-L if n < 2: return 0 swaps = 0 m = n//2 for i in range(m): if A[R-(i+1)] < A[L+i]: (A[R-(i+1)], A[L+i],) = (A[L+i], A[R-(i+1)],) swaps += 1 if (n & 1) and (A[L+m] < A[L+m-1]): (A[L+m-1], A[L+m],) = (A[L+m], A[L+m-1],) swaps += 1 return swaps + circle_sort_backend(A, L, L+m) + circle_sort_backend(A, L+m, R)
def circle_sort(L:list)->'sort A in place, returning the number of swaps':
swaps = 0 s = 1 while s: s = circle_sort_backend(L, 0, len(L)) swaps += s return swaps
- more tests!
if __name__ == '__main__':
from random import shuffle for i in range(309): L = list(range(i)) M = L[:] shuffle(L) N = L[:] circle_sort(L) if L != M: print(len(L)) print(N) print(L)
</lang>
REXX
This REXX version will work with any numbers that REXX supports, including negative and floating point numbers. <lang rexx>/*REXX program uses a circle sort to sort an array (or list) of numbers.*/ parse arg x; if x= then x=6 7 8 9 2 5 3 4 1 /*use the defaults ? */ call make@ 'before sort:' /*display the list, make an array*/ call circleSort # /*invoke circle sort subroutine. */ call makeY ' after sort:' /*make a list, display the list. */ exit /*stick a fork in it, we're done.*/ /*──────────────────────────────────CIRCLESORT subroutine───────────────*/ circleSort: do while .circleSrt(1,arg(1),0)\==0; end; return /*done.*/ .circleSrt: procedure expose @.; parse arg lo,hi,swaps /*get the args. */ if lo==hi then return swaps /*are we done ? */ high=hi; low=lo; mid=(hi-lo) % 2 /*assign indices*/
/* [↓] a section*/ do while lo<hi /*sort section. */ if @.lo>@.hi then call .swap lo,hi /*out of order ?*/ lo=lo+1; hi=hi-1 /*add; subtract.*/ end /*while lo<hi*/ /*just 1 section*/
hiP=hi+1 /*point to HI+1.*/ if lo==hi then if @.lo>@.hiP then call .swap lo,hiP /*out of order? */ swaps=.circleSrt(low, low+mid, swaps) /*sort lower. */ swaps=.circleSrt(low+mid+1, high, swaps) /* " higher, */ return swaps /*section done. */ /*──────────────────────────────────one─liner subroutines───────────────*/ .swap: arg a,b; parse value @.a @.b with @.b @.a; swaps=swaps+1; return make@: #=words(x); do i=1 for #; @.i=word(x,i); end; say arg(1) x; return makeY: y=@.1; do j=2 to #; y=y @.j; end; say arg(1) y; return</lang> output when using the default input:
before sort: 6 7 8 9 2 5 3 4 1 after sort: 1 2 3 4 5 6 7 8 9
output when using the input of: 2 3 3 5 5 1 1 7 7 6 6 4 4 0 0
before sort: 2 3 3 5 5 1 1 7 7 6 6 4 4 0 0 after sort: 0 0 1 1 2 3 3 4 4 5 5 6 6 7 7
output when using the input of: 2 3 44 44 5.77 +1 -12345 -3 -3.9 1e7 9
before sort: 2 3 44 44 5.77 +1 -12345 -3 -3.9 1e7 0 before sort: -12345 -3.9 -3 0 +1 2 3 5.77 44 44 1e7
uBasic/4tH
<lang>PRINT "Circle sort:"
n = FUNC (_InitArray) PROC _ShowArray (n) PROC _Circlesort (n) PROC _ShowArray (n)
END
_Circle PARAM (3)
IF a@ = b@ THEN RETURN (c@)
LOCAL (3) d@ = a@ e@ = b@ f@ = (b@-a@)/2
DO WHILE a@ < b@ IF @(a@) > @(b@) THEN PUSH @(a@) @(a@) = @(b@) @(b@) = POP() c@ = c@ + 1 ENDIF a@ = a@ + 1 b@ = b@ - 1 LOOP
IF a@ = b@ THEN IF @(a@) > @(b@+1) THEN PUSH @(a@) @(a@) = @(b@+1) @(b@+1) = POP() c@ = c@ + 1 ENDIF ENDIF
c@ = FUNC (_Circle (d@, d@+f@, c@)) c@ = FUNC (_Circle (d@+f@+1, e@, c@))
RETURN (c@)
_Circlesort PARAM(1) ' Circle sort
DO WHILE FUNC (_Circle (0, a@-1, 0)) LOOP
RETURN
_InitArray ' Init example array
PUSH 4, 65, 2, -31, 0, 99, 2, 83, 782, 1
FOR i = 0 TO 9 @(i) = POP() NEXT
RETURN (i)
_ShowArray PARAM (1) ' Show array subroutine
FOR i = 0 TO a@-1 PRINT @(i), NEXT
RETURN</lang>